Sean, whose mass is 60 kg, is riding on a 5.0 kg sled initially traveling at 8.0 m/s. He brakes the sled with a constant force, bringing it to a stop in 4.0 s. What force does he apply?
Answer:
130NExplanation:
according to Newtons second law;
F = ma
F = m(v-u)/t
m is the mass = 60+5 = 65kg
v is the final velocity = 0m/s
initial velocity = 8m/s
time t = 4.0s
F = 65(8)/4
F = 65*2
F = 130N
Hence he applied a force of 130N
Full moon is located______
a. farthest from the Sun
b. at a 90 degree angle with the Sun and Earth
c. closest to the Sun
Answer:
Im going to take an educated guess and say its B.
Explanation:
A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
What is a Full moon?A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.
When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.
Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.
To learn more about the Full moon, refer to the link:
https://brainly.com/question/15032553
#SPJ2
Please help with this physics question
The correct answer is A continúe moving with constant velocity
It will be easier to lift a load in wheel barrow if the load is moved
towards the wheel.why
Answer:
the moment
Explanation:
the shorter the distance from the force, the lesser the torque acting on it
Can someone please help me with this problem. I’ve tried but I can’t seem to figure it out.
A box with weight of magnitude F_G = 2.00 N is lowered by a rope down a smooth plane that is inclined at an angle φ = 30.0 degrees about ve the horizontal. The normal force acting on the box has a magnitude n = 1.73 N, the tension force is 1.00 N, and the displacement Δr of the box is 1.80 m down the cloned plane.
What is the work W_G done on the box by the gravity?
Answer:
1.8 J
Explanation:
I had this exact question today and found someone who had solved it before, this was their response to the work done by gravity. They used the name "physicsmom"
Vertical distance = 1.8 sin 30 = .9 m
W = 2 N * .9 m = 1.8J
Good luck! I hope this helps!
The work done on the box by the gravity is 0.072 J.
The given parameters;
weight of the box, [tex]F_g[/tex] = 2 Ninclination of the rope, φ = 30⁰normal force acting on the box, n = 1.73 Ntension on the rope, T = 1 Ndisplacement of the box, Δr = 1.8 mThe work done on the box by gravity is calculated as follows;
W = FΔr
where;
F is the net horizontal force on the block
The net horizontal force on the box is calculated as follows;
[tex]\Sigma F_x = F_g sin(\theta ) - F_k\\\\ \Sigma F_x = F_g sin(\theta ) - \mu_k F_n \\\\ \Sigma F_x = 2 \times sin(30 ) - (tan \theta) \times F_n\\\\ \Sigma F_x = 1 - (tan\ 30) \times 1.73\\\\ \Sigma F_x = 0.04 \ N[/tex]
The work done on the box by gravity is calculated as;
W = 0.04 x 1.8
W = 0.072 J.
Thus, the work done on the box by the gravity is 0.072 J.
Learn more here: https://brainly.com/question/14945453
Find an expression for the center of mass of a solid hemisphere, given as the distance R from the center of the flat part of the hemisphere. Express your answer in terms of R. Express the coefficients using three significant figures.
Answer:
z_c = ⅜R
Explanation:
If we assume that the hemisphere has uniform density, we can express the centre of mass as;
z_c = (ρ/M)∫∫∫ z•dV
We know that density(ρ) = mass(M)/volume(V)
Thus, Vρ = M
And volume of hemisphere = 2πr³/3
Thus;
2Vρπr³/3 = M
So;
z_c = (ρ/(2Vρπr³/3))∫∫∫ z•dV
Where r = R in this case.
ρ will cancel out to give;
z_c = (3/(2πr³))∫∫∫_V (z•dV)
In spherical coordinates,
r is radius
Φ = angle between the point and the z − axis
θ = azimuthal angle
Therefore, the integral becomes what it is in the attached image.
I've completed the explanation as well in the attachment.
A car drives 150 km SE and then 50 km due N. What is the car's displacement?
Answer:
If the car travels 150 kilometers to the Southeast, and then 50 kilometers to the North, it is understood that the car does not travel the same way out as it does back. Therefore, the car's displacement will be the sum of both distances traveled, that is, 150 + 50, which is equal to 200. Therefore, the car traveled about 200 kilometers from its starting point.
What are the 6 basic machines, and what are they and what can the be, and look like.
Answer:
Pulleys, levers, inclined planes, wedges, screws, and wheel and axle.
Explanation:
A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance traveled by the biker?
100 m
80 m
30 m
48 m
PLZ heeeeelp
Answer:
48m
Explanation:
Given the following data;
Initial velocity = 0m/s
Final velocity = 6m/s
Time, t = 6 secs
Time, T2 = 5 secs
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
Substituting into the equation;
[tex]a = \frac{6 - 0}{6}[/tex]
[tex]a = \frac{6}{6}[/tex]
Acceleration, a = 1m/s²
To find the distance covered in the first phase;
Solving for distance, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting the values into the equation;
[tex] S = 0(6) + \frac {1}{2}*1*(6)^{2}[/tex]
[tex] S = 0 + \frac {1}{2}*1*36[/tex]
[tex] S = 0.5 *36[/tex]
Distance, S1 = 18m
For the second phase, time T2 = 5 secs;
Mathematically, speed is given by the equation;
[tex]Speed = \frac{distance}{time}[/tex]
Making distance the subject of formula, we have;
[tex]Distance, S = speed * time[/tex]
Substituting into the above equation;
[tex]Distance, S = 6 * 5[/tex]
Distance, S2 = 30m
Total distance = S1 + S2 = 18m + 30m = 48m
Total distance = 48m
Therefore, the total distance traveled by the biker is 48m.
If the jet is moving at a speed of 1140 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0 g's.
Answer:
The radius is [tex]r =1705.44 \ m[/tex]
Explanation:
From the question we are told that
The speed is [tex]v = 1140 \ km /h = \frac{1140 * 1000}{3600} = 316.67 \ m/s[/tex]
The centripetal acceleration is [tex]a = 6 g's = 6 * 9.8 = 58.8 \ m/s^2[/tex]
Generally the centripetal force acting on the jet is mathematically represented as
[tex]F_c = \frac{m * v^2 }{r}[/tex]
Generally this centripetal force is equal to the net force acting which according to Newton's third law is mathematically represented as
[tex]F = m * a[/tex]
So
[tex]\frac{m * v^2 }{r} = ma[/tex]
=> [tex]\frac{ v^2 }{r} = a[/tex]
=> [tex]r = \frac{v^2}{a}[/tex]
=> [tex]r = \frac{316.67^2}{58.8}[/tex]
=> [tex]r =1705.44 \ m[/tex]
what is a factor that scientists use to classify orders of soil?
b. Interpret Data Solution A has a pH of 1.6.
Solution B has a pH of 4. Which solution
has a greater concentration of hydrogen
ions? Explain.
Answer:
Solution A has a pH of 6 and solution B has a pH of 8. Which of the following is true regarding the concentration of hydrogen ions in each solution? A) A has 100 times greater H+ concentration than B. B) B has 100 times greater H+ concentration than A. C) A has 7/9 of the H+ concentration of B. D) A has 9/7 of the H+ concentration of B. E) none of these
Explanation:
Hey im super sorry if i get this wrong :)
Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.
Answer:
v₃ = 1.625 [m/s]
Explanation:
To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.
Since the collision is inelastic, the two bodies are joined after the collision.
P = m*v [kg*m/s]
m = mass [kg]
v = velocity [m/s]
where:
P = lineal momentum [kg*m/s]
Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.
Pbefore = Pafter
(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃
where:
m₁ = mass one = 5 [kg]
v₁ = velocity of the mass one = 2 [m/s]
m₂ = mass two = 3 [kg]
v₂ = velocity of the mass two = 1 [m/s]
v₃ = velocity of the combined masses after the collision [m/s]
Now replacing we have:
(5*2) + (3*1) = (5 + 3)*v₃
10 + 3 = 8*v₃
v₃ = 13/8
v₃ = 1.625 [m/s]
A thin spherical shell has a radius of 0.70 m. An applied torque of 860 N m gives the shell an angular acceleration of 4.70 rad/s2 about an axis through the center of the shell. What is the rotational inertia of the shell about the axis of rotation
Answer:
[tex]I=182.97\ kg-m^2[/tex]
Explanation:
Given that,
Radius of a spherical shell, r = 0.7 m
Torque acting on the shell, [tex]\tau=860\ N[/tex]
Angular acceleration of the shell, [tex]\alpha =4.7\ m/s^2[/tex]
We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :
[tex]\tau=I\alpha[/tex]
I is the rotational inertia of the shell
[tex]I=\dfrac{\tau}{\alpha }\\\\I=\dfrac{860}{4.7}\\\\I=182.97\ kg-m^2[/tex]
So, the rotational inertia of the shell is [tex]182.97\ kg-m^2[/tex].
If you cannot exert enough force to loosen a bolt with a wrench, which of the following should you do?
Question 5 options:
1.) Tie a rope to the end of the wrench and pull on the rope.
2.) Use a wrench with a longer handle.
3.) You should exert a force on the wrench closer to the bolt.
4.) Use a wrench with a shorter handle.
Answer:
2.) Use a wrench with a longer handle.
Explanation:
It is suggested to use a wrench with longer handle if you cannot exert enough force to loosen a bolt with a wrench.
In doing this work, the torque which is the force that can turn the screw is not enough;
Torque = force x distance
If we increase the distance or the length of the handle, we can generate more torque to overcome the force needed.
The Amazon rainforest has millions of trees down in South America. Pantanal, the largest wetland, or swamp, on Earth sits directly below the Amazon on a map. Explain this phenomenon using processes from the water cycle.
The subject is science just to let you know.
Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.
Answer:
Nine, Brazil, Venezuela
Explanation:
Which form of energy has the most potential globally
a) Solar energy
b) Bio energy
c) Wind energy
d) Geothermal energy
Answer:
i think the answer is solar,
Explanation:
because it is a natural resource im sorry if im wrong
An electron (restricted to one dimension) is trapped between two rigid walls 1.40 nm apart. The electron's energy is approximately 19 eV. (a) What is the quantum number n for the energy state that the electron occupies? (b) Based on the quantum number you found in part (a), calculate a more precise value for the electron's energy in eV), expressed to at least three significant figures. (Use any physical constants or unit conversions to at least four significant figures in your calculations.) _________ eV
Answer:
a) n = 9.9 b) E₁₀ = 19.25 eV
Explanation:
Solving the Scrodinger equation for the electronegative box we get
Eₙ = (h² / 8m L²2) n²
where l is the distance L = 1.40 nm = 1.40 10⁻⁹ m and n the quantum number
In this case En = 19 eV let us reduce to the SI system
En = 19 eV (1.6 10⁻¹⁹ J / 1 eV) = 30.4 10⁻¹⁹ J
n = √ (In 8 m L² / h²)
let's calculate
n = √ (8 9.1 10⁻³¹ (1.4 10⁻⁹)² 30.4 10⁻¹⁹ / (6.63 10⁻³⁴)²
n = √ (98) n = 9.9
since n must be an integer, we approximate them to 10
b) We substitute for the calculation of energy
In = (h² / 8mL2² n²
In = (6.63 10⁻³⁴) 2 / (8 9.1 10⁻³¹ (1.4 10⁻⁹)² 10²
E₁₀ = 3.08 10⁻¹⁸ J
we reduce eV
E₁₀ = 3.08 10⁻¹⁸ j (1ev / 1.6 10⁻¹⁹J)
E₁₀ = 1.925 101 eV
E₁₀ = 19.25 eV
the result with significant figures is
E₁₀ = 19.25 eV
Moderate injuries are generally __________.
A.
life-threatening
B.
soft tissue injuries
C.
bumps and bruises
D.
too serious for first aid
Please select the best answer from the choices provided.
A
B
C
D
Answer:
B. soft tissue injuries
Explanation:
i took the test on edge and its really the only one that would make sense if you payed attention to the lesson :)
Bicyclist travels at an average velocity of 11.2 km/h [W]. How far will the bicyclist travel in 175 minutes?
Answer:
32.67km
Explanation:
~= round off
11.2km/h~3.11m/s
175minutes=10500s
10500*3.11~32, 666.67m
=32.66667km
~ 32.67km
The first group of planets that are made of rock and closest to the sun
Answer:
A terrestrial planet, telluric planet, or rocky planet is a planet that is composed primarily of silicate rocks or metals. Within the Solar System, the terrestrial planets are the inner planets closest to the Sun
A batter hits a foul ball. The 0.140-kg baseball that was approaching him at 40.0 m/s leaves the bat at 30.0 m/s in a direction perpendicular to the line between the batter and the pitcher. What is the magnitude of the impulse delivered to the baseball?
A) 9.80 Ns
B) 3.50 Ns
C) 7.00 Ns
D) 5.60 Ns
E) 1.40 Ns
Answer:
The magnitude of the impulse delivered to the baseball is 7.0 Ns
Explanation:
Given;
mass of the foul ball, m = 0.14 kg
initial velocity, u = 40 m/s
final velocity, v = 30 m/s in perpendicular direction
Impulse is given as change in momentum;
initial momentum in horizontal direction, Pi = mu
Pi = 0.14 x 40 = 5.6 Ns
final momentum in perpendicular direction, Pf = mv
Pf = 0.14 x 30
Pf = 4.2 Ns
The resultant impulse is given by;
J² = 5.6² + 4.2²
J² = 49
J = √49
J = 7.0 Ns
Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns
HELP ASAP!!!!!!!!!
Mark and Steven were conducting an investigation where they were measuring the energy of a glass marble as it rolled down a ramp. According to their calculations, the total energy of the marble decreased. Which statement below is the best explanation for the decrease in total energy?
A) It decreased because it was destroyed by the interaction with the ramp
B) The total energy always decreases in an energy conversion
C) They were incorrect; the energy totals should have been the same
D) The energy decreased because heat resulted from friction between the marble and the ramp
How many bonds can antimony form?
Answer:
An antimony can form 3 bonds
Let me know if this helps
Thanks!
:)
Explanation:
An artery with cross sectional area of 1 cm2 branches into 20 smaller arteries each with 0.5 cm2 cross sectional area. If the velocity of blood in the thicker artery is v, what is the velocity of the blood in the thinner arteries
Answer:
The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.
Explanation:
To find the velocity of the blood we need to use the continuity equation:
[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex] (1)
Where:
n: is the number of branches
A: is the cross-sectional area
v: is the velocity
For artery 1, we have:
n₁ = 1, A₁ = 1 cm², v₁ = v
For the 20 arteries (2), we have:
n₂ = 20, A₂ = 0.5 cm², v₂ =?
By using equation (1):
[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]
[tex] 1 cm^{2}*v = 20*0.5 cm^{2}*v_{2} [/tex]
[tex] v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v [/tex]
Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.
I hope it helps you!
What is the momentum of 100 kg running at 4m/s north?
how can voltage be produced by magnetism and motion?
Answer:
Electromagnetic Induction by a Moving Magnet
Then the action of moving a coil or loop of wire through a magnetic field induces a voltage in the coil with the magnitude of this induced voltage being proportional to the speed or velocity of the movement.
Explanation:
things that affects the demand for electricity
How long would it take a 500. W electric motor to do 15010 J of work?
