Analyze the problem and complete the statements.
t-7 = 8
I know this problem is an
because it has an equals sign.
The t is the
The negative sign is the
The 7 and the 8 are both

Answers

Answer 1

Answer:

I know this problem is an  

✔ equation

because it has an equals sign.

The t is the  

✔ variable

.

The negative sign is the  

✔ operation

.

The 7 and the 8 are both  

✔ constants

.

Step-by-step explanation: i took the test :( crying cuz im bouta fail


Related Questions

Parallelogram JKLM is shown. If KR=X+7, KM = 3x - 5. and JL = 4x - 10.
what is JR?
2 points
K
R
569
27°
72°
M

Answers

Answer:

Step-by-step explanation:

In a parallelogram, this one in particular:

KR = RM

JR = RL

We are looking in the end for the length of JR, but that means that we need to solve for x somehow to plug in the expression for JL, and then split that in half. Here's how we're going to go about it. I know that

KM = KR + RM, but since KR and RM are the same length, the equation becomes

KM = 2KR. Filling that in with the expressions I'm given for KM and KR:

3x - 5 = 2(x + 7) and

3x - 5 = 2x + 14 and

x = 19. Now I can find the length of JL:

JL = 4x - 10 so

JL = 4(19) - 10 and

JL = 66

Knowing that JR = RL and JL is 66 units long, JR = RL = 33 units each.

Two hikers are miles apart and walking toward each other. They meet in hours. Find the rate of each hiker if one hiker walks mph faster than the other.

Answers

Answer:

where are the numbers

Step-by-step explanation:

Beverly fpund a magic bean. If she puts it in the soil , every single day it will grow 4 cm. After how many days will it be 14.56 meters tall

Answers

Answer:

364 days

Step-by-step explanation:

Magic bean will take 364 days to grow 14.56 m tall.

What is Unit Conversion?

A conversion factor exists as a ratio that expresses how many of one unit stand equal to another unit. For example, there exist 12 in. in 1 ft, 1609 m in 1 mi, 100 cm in 1 m, 60 s in 1 min, and so on.

Unit conversion exists as a multi-step procedure that involves multiplication or division by a numerical factor, choosing the accurate number of significant digits, and rounding.

First we need to convert the height in m into cm.

14.56 m=14.56*100=1456 cm

If it grows 4 cm in one day then:

It will take 1456/4=364 days (a year) to grow completely.

To know more about unit conversion refer:

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(c) 63 divided by 3 = 21 , Show how you use this to work out 0.63 divided by 0.3.

Answers

Answer:

0.63 ÷ 0.3 = 63 x 10^-2 ÷ 3 x 10^-1 = 63 / 3  x 10^(-2--1) = 21 x 10^-1 = 2.1

Answer:

2.1.

Step-by-step explanation:

63/3 = 21

0.63 = 63 / 100

and 0.3 = 3 / 10

so 0.63/0.3 = 63 /100 / 3/10 = 63/100 * 10/3

= 63/3 / 10

So the answer is 21 / 10 = 2.1.

PLEASE HELP!!!

Find an equation for the straight line that passes through the point (2.3) and is parallel to
the line x = 4.

Answers

Answer:

Answer is x=1 inthe sentences

3/4 of the class walk to school while 1/5 ride bicycle. Find the ratio of those who walk to those who ride bicycles.

Answers

Answer:

15:4

Step-by-step explanation:

Multiply the fractions to get a common denominator. Multiply 3/4 by 5 and your get 15/20 and multiply 1/5 by 4 and you get 4/20. The numerators represent the ratio.

Is the domain of an arithmetic sequence discrete or continuous? Is the range of an arithmetic sequence discrete or continuous?

Answers

Answer:

continuous, continuous

Step-by-step explanation:

The discrete domain are set of input variables that have numbers in an interval. A continuous domain has all numbers in an interval. The point representing the solution of an equation are distinct. The range of sequence is the merely a set of defines the sequence and is represented as X1, X2, X3, or N = 1, 2, 3.

ESSENTIAL QUESTION How do graphs
and equations reveal information about a
relationship between two quantities?

Answers

Answer:

When you plot the graph, you may see a line or a curve. This presents the trend of the relationship of the two quantities when the independent variable changes.

Graphs visually depict patterns and trends, while equations provide precise mathematical descriptions, both revealing valuable information about the relationship between two quantities.

Graphs visually represent data and patterns, allowing us to identify the nature of the relationship between two quantities. The slope and intercepts of a graph provide information about the rate of change and the values when one quantity is zero.

Equations, on the other hand, offer precise mathematical descriptions of the relationship. The form of the equation reveals the nature of the relationship, while coefficients and constants provide specific information. Solving equations yields solutions that satisfy the relationship.

Both graphs and equations work together to provide a comprehensive understanding of the relationship between two quantities, with graphs offering visual insights and equations providing precise mathematical information.

Learn more about equations here;

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(a/b)^x-1 = (b/a)^x-3​

Answers

Answer:

x = 2

Step-by-step explanation:

After a 20% reduction, you purchase a tv for $336. What was the price of the tv before the reduction?

Answers

Answer:

$420

.8 x = 336

x = 336/.8

X=$420

Step-by-step explanation:

Which expression is the simplified form of -10 + 3x - x - 7x + 5x + 7 + 2x?
A. 4x-3
B. 2x - 3
C. -18x - 17
D. -X​

Answers

Answer:

B

Step-by-step explanation:

-10 + 3x - x - 7x + 5x + 7 + 2x

combine like terms

-10 + 3x - x - 7x + 5x + 7 + 2x

-3 + 3x - x - 7x + 5x + 2x

the -7x and the 5x + 2x cancel out to 0, so for the x terms we are left with 3x -x to get 2x

= 2x - 3

Find the missing length of the following with midsegment drawn

Answers

Answer:

18

Step-by-step explanation:

RQ = (22+14)/2 = 36/2 = 18

Answer:

QR = 18

Step-by-step explanation:

The midsegment QR is half the sum of the parallel bases, that is

QR = [tex]\frac{JM+KL}{2}[/tex] = [tex]\frac{22+14}{2}[/tex] = [tex]\frac{36}{2}[/tex] = 18

write each number as a reduced fraction or mixed number. A. 16/24 B. 15/24. C. 4%​

Answers

Answer:

A.1/3 B.5/8 C.1/25

Step-by-step explanation:

just simplify it down to the lowest

Answer:

Ä. 16/24 as reduced fraction = 2/3

B. 15/24 as reduced fraction= 5/8


Three adults are picked at random from those with a mass of 70 kg or less.
Calculate the probability that one of them has a mass of 35 kg or less and the other two each have a
mass greater than 35 kg.

Answers

Answer is Indians only answers super simple questions

ALGEBRA 2

Name the property of real numbers illustrated by each equation.

#21

Answers

Answer:

The property showed in the number 21 is the distributive property

Se desea pintar un cuadrado inscrito en una circunferencia de radio R=3cm como se muestra en la figura. Calcular el área del cuadrado

Answers

El área del cuadrado es de 3 centímetros cuadrados.

Dado que se desea pintar un cuadrado inscrito en una circunferencia de radio R=3cm como se muestra en la figura, para calcular el área del cuadrado se debe realizar el siguiente cálculo:

Radio = diámetro / 2 3 = X/2 X = 6Hipotenusa del triángulo interno: 6 cm

Aplicando teorema pitagórico: lado al cuadrado mas lado al cuadrado es igual a hipotenusa al cuadrado.

L^2 + L^2 = 62L^2 = 6L^2 = 6/2L = √ 3L = 1.732Área de un cuadrado = L x L = L^2 = 3

Por lo tanto, el área del cuadrado es de 3 centímetros cuadrados.

Aprende más en https://brainly.com/question/16405529

El área del cuadrado es de 18 centímetros cuadrados.  

El procedimiento de resolución se basa en conocer que la Medida de la Diagonal de un Cuadrado inscrito es igual a la Medida del Radio del Círculo, lo cual permite determinar el valor de la medida del Cuadrado en función del Radio del Círculo. Finalmente, determinamos el Área del Cuadrado mediante su fórmula conocida.

Dado que existe un cuadrado inscrito en un círculo, la medida de la diagonal del cuadrado es igual a la medida del radio del círculo. Además, conocemos que un cuadrado está formado por 4 triángulos rectángulos con configuración angular 45-45-90. Entonces, la medida del lado del cuadrado se calcula mediante la siguiente relación geométrica:

[tex]l = \sqrt{2}\cdot R[/tex] (1)

Donde:

[tex]R[/tex] - Radio del círculo, en centímetros.

[tex]l[/tex] - Longitud del lado del cuadrado, en centímetros.

Por otra parte, la ecuación de área del cuadrado es igual a:

[tex]A = l^{2}[/tex] (2)

Donde [tex]A[/tex] es el área del cuadrado, en centímetros cuadrados.

Si sabemos que [tex]R = 3\,cm[/tex], entonces el área del cuadrado es:

[tex]l = \sqrt{2}\cdot (3\,cm)[/tex]

[tex]l = 3\sqrt{2}\,cm[/tex]

[tex]A = (3\sqrt{2}\,cm)^{2}[/tex]

[tex]A = 18\,cm^{2}[/tex]

El área del cuadrado es de 18 centímetros cuadrados.  

He aquí una pregunta relacionada sobre el área del cuadrado: https://brainly.com/question/23915250

In the figure shown, line AB is parallel to line CD. What is the measure of angle x? Explain your answer.

Answers

Answer:

x = 53°

Step-by-step explanation:

The angle 115° and the angle formed by the sum of x+62° are external alternates angles, so it means they have the same measure, and you can find the value of x doing:

115°- 62° = 53°

(a-√a/√a-1) - (√a+1/a+√a) : √a+1/a. solve a

Answers

Answer:

Step-by-step explanation:

[tex]\displaystyle \ \Large \boldsymbol{} \frac{a-\sqrt{a} }{\sqrt{a}-1 } -\frac{\sqrt{a}+1 }{a+\sqrt{a} } :\frac{\sqrt{a}+1 }{a} = \\\\\\\frac{\sqrt{a}(\sqrt{a} -1 ) }{(\sqrt{a}-1) } -\frac{\sqrt{a}+1 }{\sqrt{a}(\sqrt{a}+1 )}\cdot \frac{\sqrt{a}\cdot \sqrt{a} }{\sqrt{a}+1 } = \\\\\\\sqrt{a} -\frac{\sqrt{a} }{1+\sqrt{a} } =\frac{a+\sqrt{a}-\sqrt{a} }{1+\sqrt{a} } = \\\\\\\frac{a}{\sqrt{a}+1 } \cdot \frac{\sqrt{a}-1 }{\sqrt{a}-1} } =\boxed{\frac{a\sqrt{a} -a}{a-1} }[/tex]

Point A(8,4) is reflected over point (6,−2) and its image is point B. What are the coordinates of point BB?

Answers

Answer:

If Point A (8,4) is reflected over point (6,−2), then that point becomes (4, -8).

Let me know if this helps!

Durning Saturday’s thunderstorms a total of 500 mm of rain fell in fell in 20 minutes.How many mm fell per minute

Answers

Answer

25mm of rain fell each second

Step-by-step explanation:

we know that 500 mm fell in 20 minutes

so, we have to divide 500 by 20 giving us the amount of rain that fell each minute:

500/20 = 25

therefore, 25mm of rain fell each minute

hope this helped:)

Answer:

25 mm per minute

Step-by-step explanation:

Take the amount of rain and divide by the number of minutes

500/20

25 mm per minute

How can this quadrilateral be classified?
Select each correct answer.
O trapezoid
O square
O rhombus
O parallelogram

Answers

Answer:

Rhombus, Square, Parallelogram :)

Step-by-step explanation:

I just did this question and I got the three answers above right. I hope this helps!

What is the value of the expression below when x=3
10x²- 7x + 10

Answers

Answer: 79

Concept:

Here, we need to understand the idea of evaluation.  

When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.

Solve:

Given information

10x² - 7x + 10

x = 3

Substitute the value into the expression

= 10 (3)² - 7 (3) + 10

Simplify by multiplication

= 10 (9) - 21 + 10

= 90 - 21 + 10

Simplify by subtraction

= 69 + 10

Simplify by addition

= 79

Hope this helps!! :)

Please let me know if you have any questions

Answer:

92

Step-by-step explanation:

The variable 'x' shows up twice in this expression.  Replace each instance of 'x' with 3:

10(3)^2 - 7(3) + 10  =  10(9) - 21 + 19  =  92

Need help on #7 , #8 Asap

Answers

b and b,

first one 100-51= 49 so b

second one think of a big angle with a line through it, so it would be AB would be a combination of AC and BC


Answer:

7.b

8.b

Answers................ ​

Answers

Answer:

x=1

Step-by-step explanation:

log2( x^2 -x+2) = 1+2log2(x)

Rewriting 1 as log2(2)

log2( x^2 -x+2) = log2(2)+2log2(x)

We know that a log b = log a^b

log2( x^2 -x+2) = log2(2)+log2(x^2)

we know log a + log b = log (ab)

log2( x^2 -x+2) = log2(2*x^2)

Since the bases are the same the terms inside must be equal

x^2 -x+2 = 2x^2

Subtract 2x^2 from each side

-x^2 -x+2 = 0

Multiply by -1

x^2 +x-2 = 0

Factor

(x+2)(x-1)=0

Using the zero product property

x+2 = 0  x-1=0

x=-2  x=1

Checking the solutions

log2( x^2 -x+2) = 1+2log2(x)

X cannot be negative because 2 log2(x) cannot be negative

log2( 1^2 -1+2) = 1+2log2(1)

x=1

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=1+2log_2x[/tex]

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=log_22+2log_2x[/tex]

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=2log_2(2x)[/tex]

[tex]\\ \rm\Rrightarrow log_2(x^2-x+2)=log_2(2x^2)[/tex]

[tex]\\ \rm\Rrightarrow x^2-x+2=2x^2[/tex]

[tex]\\ \rm\Rrightarrow x^2+x-2=0[/tex]

[tex]\\ \rm\Rrightarrow (x+2)(x-1)=0[/tex]

x=-2,1

log is always positive so x=1

Laws used

log_a(a)=1loga^m=mlogalog(ab)=loga+logb

What is the measure of n

Answers

Answer:

Step-by-step explanation:

This is a geometric means problem. Namely, n is the geometric mean between the 2 smaller triangles within that larger one. Set up the problem accordingly:

[tex]\frac{28}{n}=\frac{n}{7}[/tex] and cross multiply:

[tex]n^2=196[/tex] so

n = 14

If the blue radius below is perpendicular to the chord AC which is. 14 units long, what is the length of the segment AB?

Answers

Answer:

C. 7 units

Step-by-step explanation:

The given parameters are;

The length of the chord of the circle, [tex]\overline{AC}[/tex] = 14 units

The orientation of the radius and the chord = The radius is perpendicular to the chord

We have in ΔAOC, [tex]\overline{AO}[/tex] = [tex]\overline{OC}[/tex] = The radius of the circle

[tex]\overline{OB}[/tex] ≅ [tex]\overline{OB}[/tex]  by reflexive property

The angle at point B = 90° by angle formed by the radius which is perpendiclar to the chord [tex]\overline{AC}[/tex]

ΔAOB and ΔCOB are right triangles (triangles having one 90° angle)

[tex]\overline{AO}[/tex] and [tex]\overline{OC}[/tex] are hypotenuse sides of ΔAOB and ΔCOB respectively and [tex]\overline{OB}[/tex] is a leg to ΔAOB and ΔCOB

Therefore;

ΔAOB ≅ ΔCOB, by Hypotenuse Leg rule of congruency

Therefore;

[tex]\overline{AB}[/tex] ≅ [tex]\overline{BC}[/tex] by Congruent Parts of Congruent Triangles are Congruent, CPCTC

[tex]\overline{AB}[/tex] = [tex]\overline{BC}[/tex] by definition of congruency

[tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] by segment addition postulate

∴ [tex]\overline{AC}[/tex] = [tex]\overline{AB}[/tex] + [tex]\overline{BC}[/tex] =  [tex]\overline{AB}[/tex] + [tex]\overline{AB}[/tex] = 2 ×  [tex]\overline{AB}[/tex]

∴  [tex]\overline{AB}[/tex] = [tex]\overline{AC}[/tex]/2

[tex]\overline{AB}[/tex] = 14/2 = 7

[tex]\overline{AB}[/tex] = 7 units.

Answer:

7 units

Step-by-step explanation:

Question 16 of 17
Which of the following best describes the graph below?

A. Independent variable
0 o a
B. A relation that is a function
C. A relation that is not a function
D. Dependent variable

Answers

The answer is B. It is a relation and also a function at the same time because it satisfies a specific domain

Un alambre de longitud x s3. E dobla en forma de cuadrado exprese su área en términos de la ingitud x

Answers

Respuesta:

A = 1/16 × x²

Explicación paso a paso:

Un alambre de longitud x se dobla en forma de cuadrado. Como un cuadrado tiene 4 lados iguales la longitud de cada lado (l) será:

l = 1/4 × x

Para calcular el área de un cuadrado (A) usaremos la siguiente fórmula.

A = l²

A = (1/4 × x)²

A = 1/16 × x²

Can someone verify if this is correct?

I used cosec because the others didn’t work

Answers

Yes that’s correct. I’m doing flvs too!

58°
X Х
jsut give a quick

Answers

Answer:

32

Step-by-step explanation:

The sum of the angles of a triangle is 180

58+90+x = 180

148+x = 180

x = 180-148

x=32

Concept

The angle sum property of a triangle:

The total measure of the three angles of a triangle is 180°

Solution

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: + \: 58 \degree \: + \: 90 \degree \: = \: 180 \degree}}}[/tex]

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: + \: 148 \: = \: 180 \degree}}}[/tex]

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: = \: 180 \degree \: - \: 148 \degree}}}[/tex]

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: = \: 32 \degree}}}[/tex]

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