Answer:
25m/s
Explanation:
p=mv
75 = 3v
v = 75/3
v = 25 m/s
If you want to verify your answer, just insert the value of v to the equation.
A block with a mass of 6.0 kg is
held in equilibrium on an incline
of angle θ = 30.0° by a horizontal
force, F, as shown in the figure.
Find the magnitudes of the
normal force on the block and of F. (Ignore friction.)
(a) The normal force on the block is 50.92 N.
(b) The horizontal force on block keeping it in equilibrium is 29.4 N.
The given parameters;
mass of the block, m = 6 kgangle of inclination, θ = 30.0°The normal force on the block is calculated as follows;
[tex]F_n = W \times cos(\theta)[/tex]
where;
W is the weight of the block[tex]F_n = mg \times cos(\theta)\\\\F_n = 6 \times 9.8 \times cos(30)\\\\F_n = 50 .92 \ N[/tex]
The horizontal force on block keeping it in equilibrium is calculated as follows;
[tex]F- F_x = 0\\\\F-mgsin\theta= 0\\\\F = mgsin\theta\\\\F = 6 \times 9.8 \times sin(30)\\\\F = 29.4 \ N[/tex]
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Two electrons are separated by one cm. What is the ratio of the electric force to the gravitational force between them? (me = 9. 11 ´ 10-31 kg, ke = 8. 99 ´ 109 N×m2 /C2 , G = 6. 67 ´ 10-11 N×m2 /kg2 , and e = 1. 6 ´ 10-19 C) a. 2. 3 ´ 102 b. 1. 3 ´ 1020 c. 3. 1 ´ 1022 d. 4. 2 ´ 1042.
The ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
The given parameters;
Mass of the electron, [tex]m_e[/tex]= 9.11 x 10⁻¹¹ kgCoulomb's constant, k = 8.99 x 10⁹ Nm²/C²Gravitational constant, G = 6.67 x 10⁻¹¹ Nm²/kg²Charge of electron, q = 1.6 x 10⁻¹⁹ CDistance between the two electrons, r = 1 cmThe electrostatic force between the two electrons is calculated as follows;
[tex]F_c = \frac{kq^2}{r^2} \\\\[/tex]
The gravitational force between the two electrons is calculated as follows;
[tex]F_g = \frac{Gm_e^2}{r^2}[/tex]
The ratio of the electric force to the gravitational force between the two electrons is calculated as follows;
[tex]\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{1}{\frac{Gm^2}{r^2} } \\\\\frac{F_c}{F_g} = \frac{kq^2}{r^2} \times \frac{r^2}{Gm^2} \\\\\frac{F_c}{F_g} = \frac{kq^2}{Gm^2}\\\\[/tex]
[tex]\frac{F_c}{F_g} = \frac{(8.99 \times 10^9) \times (1.6 \times 10^{-19}))^2}{(6.67 \times 10^{-11} ) \times (9.11 \times 10^{-31})^2} \\\\\frac{F_c}{F_g} = 4.2 \times 10^{42}[/tex]
Thus, the ratio of the electric force to the gravitational force between the two electrons is [tex]4.2 \times 10^{42}[/tex].
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A fairly efficient steam turbine engine fired by coal is used to drive an electric generator. The generator operates between 2100°C and 385°C.
(a) Determine the maximum possible efficiency of the engine.
Answer: 72.3 %
Formula:
e = 1 - (Tc / Th) = 1 - (Qc / Qh) = ( W / Qh)
Explanation: Unsure??
(b) The engine absorbs 1.15 105 J from the hot reservoir every second. If the actual efficiency of the engine is 40.3%, determine the mechanical power the engine delivers.
Answer: 46 kW
Explanation:
Energy absorbed by the engine (J) * actual efficiency of the engine (%) = mechanical power the engine delivers (kW)
How does 1 - (385/2100) = 72.3 % ?
What do I Plug in to make e = 72.3 %
Use kelvin not celsius
C + 273 = K
This will fix my problem of the equation not making sense.
Rubies are used in electronics.
Please select the best answer from the choices provided
) Т
) F
A 0.14-MIN baseball is dropped from rest. It has a momentum of 0.90 kg⋅m/skg⋅m/s just before it lands on the ground.
For what amount of time was the ball in the air?
The time spent in the air by the ball at the given momentum is 6.43 s.
The given parameters;
momentum of the ball, P = 0.9 kgm/sweight of the ball, W = 0.14 NThe impulse experienced by the ball is calculated as follows;
[tex]Ft = \Delta P[/tex]
where;
[tex]Ft[/tex] is impulse
[tex]\Delta P[/tex] is change in momentum
The time of motion of the ball is calculated as follows;
[tex]t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s[/tex]
Thus, the time spent in the air by the ball at the given momentum is 6.43 s.
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A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
The work done in the given case is 0
[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]
For calculating the work done by an object we apply the formula, that is ~
[tex]f \times s \times \cos( \theta) [/tex]where f represents force applied, and s represents displacement.
but here, the displacement is zero since the wall didn't move at all, Therefore If we plug it's value as 0, we get
[tex]f = 0 \times s \times \cos( \theta) [/tex]hence,
[tex]work \: done = 0[/tex]So therefore, we can conclude that the man hasn't done any work.
Hope it helps.
Do comment if you have any query.
Inertia causes bodies to slow in their motion, unless they’re pushed by a force.
Inertia resists changes to the state of motion of a body.
Inertia decelerates a body.
Inertia is due to friction.
Answer:
ill go with B
Explanation:
inertia is the ability of a body to remain at rest or in a constant speed in a constant direction when no force is acting on it
The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
c
Explanation:
State a hypothesis about your estimated daily water use.
Answer
Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.
Explanation:
Study the three pieces of evidence for the Big Bang in this activity carefully. What is common to all these pieces of observable evidence and why does this make them much more powerful than if they did not have this common feature?
Answer:
Explanation:
the measured abundances of elementsthe observed expansion of spacethe discovery of cosmic wave backgroundThe common observable evidence are:
the measured abundances of elementsthe expansion of spacethe cosmic wave backgroundWhat is big bang?The big bang is the theory which explains that how the universe began. It says that the universe began with just a single point. It went on expanding and stretched to grow as large as possible. It is still now expanding.
The big bang consist of fully dark matter, interstellar gases or dust. The big bang is increasing just because in universe there is abundant of hydrogen and helium.
The radiations come from the big bang. These rays are also called as cosmic wave. This big bang is still on it way of expanding more.
Thus, the observational evidence are the measured abundances of element, the expansion of space and the cosmic wave background.
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Describe the changes that occur inside a helium balloon as it rises from sea level
Answer:
The balloon expands in the number of particles per cubic centimeter decreases. This happens because as it expands there is a decrease in the density of area. The Dead Sea is a solution that is so dense that you easily float on it.
Which of the following will require most developed countries to
decrease emissions of carbon dioxide and other greenhouse gases?
a. Montreal Protocol c. Emissions Reduction Act
b. Kyoto Protocol d. Reforestation Project
Answer:
Kyoto Protocol
Explanation:
given. force of 88N and an acceleration of 4 m/s 2 what is the mass?
You throw a can of cranberry sauce straight up in the air with an initial velocity of 12 m/s. What is the maximum height the baseball reaches above your head.
Answer:
Δx=7.35m
Explanation:
This is a free fall problem (g= -9.8 m/s²).
Displacement: ? <--- what you're trying to find (max height)
Initial Velocity: 12 m/s
Final Velocity: 0 m/s <-- since the can will land back in your hands
Time: Missing <-- not needed to solve
Acceleration: -9.8 m/s²
The equation that you will use is vf²=vi²+2aΔx
Now plug the information into the equation!
(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx
Multiply the 2 with the acceleration (-9.8m/s²)
(0m/s)²=(12m/s)²-19.6m/s²Δx
Now you need to square the final and initial velocity
0m/s=144m/s-19.6m/s²Δx
Move 144 to the other side of the equal sign
-144m/s=-19.6m/s²Δx
Divide both sides by -19.6m/s²
7.346m=Δx
You can round it to the tenth or hundreth place, up to you!
For this example, I'll round to the hundredth...
Δx=7.35m
I would double check this answer or review it yourself to see if it's correct.
Good luck with your studies!
Suppose you were able to take measurements of current through the
resistor and voltage across the resistor. Your record of numerical values is written in a
tabular data below
Answer:
see attached
Explanation:
It will be easier to plot the data if you have grid lines to work with.
In the attached, we had to reverse the order of entries in the table, because the graphing program likes the independent variable listed first.
the primary factor in decreasing the kinetic energy of an object is to
Answer:
Decreasing the velocity
Explanation:
The primary factor in decreasing the kinetic energy of an object is to decrease the velocity of the object.
What is Kinetic energy?The kinetic energy of an object is the energy which it possesses due to the motion of the object. Kinetic energy is defined as the work which is needed to accelerate an object of a given mass from the state of rest to its stated velocity and direction. Gain of the energy during the acceleration of an object, the body maintains this kinetic energy unless its speed changes and the object accelerates.
The kinetic energy is directly proportional to the mass and the velocity of the object. The primary factor which is responsible for the decrease in the kinetic energy of an object is to decrease the velocity of the object.
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If you eat cheese are you 1 percent cheese?
Answer:
No. Exactly what you eat doesn’t make up your internal structure.
:)
Answer:
Explanation:
Light cheeses are less than 20 %, low fat cheeses are 20 to 30%, fat cheeses are 50 to 60%, double-cream cheeses are at least 60% and triple-cream cheeses are at least 75 %.
3. Would prudent to do an observatory M 82 for this class?
Answer: Yes,
If you need any other thing let me know, I'll still be on
Explanation:
2. If Joe rides his bicycle in a straight line for 15 min with an average velocity of 12.5 km/h south, how far has he ridden?
Answer:
3.125 Kilometers
Explanation:
To answer this you just multiply 12.5 by .25 (since 15 minutes is a quarter of an hour) to get 3.125 kilometers ridden.
Why is wrestling ring floor always softThis is physics
Answer:
So the people in the ring don't get hurt or break anything on impact once they hit the floor
An "energy bar" contains 26 ggof carbohydrates.How much energy is this in joules?
an electric charge (Q=-230nc) located at origin generate an electric field at point P located at (2 , 6)m(meter) find the electric filed at P *
1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)
The force diagram on the desk consists of normal reaction and weight of the pencil.
The net force on the desk in vertical direction is 1 N.
The net force on the desk in horizontal direction is 0.
The given parameters;
weight of the pencil, W = 1 NThe force diagram of the desk is sketched as follows;
↑ N
⊕
↓ W
Where;
N is the normal reaction on the deskW is the weight of the ballThe net force on the desk in vertical direction = 1 N
The net force on the desk in horizontal direction = 0
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What quantity is represented by the mass number minus the atomic number?.
Answer:
Mass = mass of nucleus
Atomic Number = number of protons (charge) of nucleus
Mass - Atomic Number = number of neutrons
lonic Naming Practice
Write the name of the following chemical compound:
Na3Cl1
Answer:
sodium chloride. .....
which term is most applicable to a discussion of angular momentum in the context of black holes?
A: Photon
B: Curvature
C: Spin
D: Time
Answer:
c: spin
Explanation:
it's not curvature
The most applicable term to a discussion of angular momentum in the context of black holes is Spin. Thus, the correct option is C.
What is angular momentum of black holes?
Angular Momentum is defined as the property of any rotating object which is given by the product of the moment of inertia of an object and the angular velocity of the rotating object. Angular momentum is a vector quantity and it has both the magnitude and direction. The examples of angular momentum are the rotation and revolution of the Earth.
When the astronomers claim that they have estimated the spin of a black hole, this means they have measured its angular momentum. This is the total angular momentum of all the materials on the Universe that ever crossed the event horizon and got trapped inside it.
Therefore, the correct option is C.
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Help me quick!!! please!!
Calculate the power of an engine which raises a mass of 1000 kg to a height of 40 m in 10 s.
Answer:
39.240 W
Explanation:
Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]
At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]
Answer:
P=39200W
Explanation:
P=(mgh)/t
P=(40×9.8×1000)/10
P=39200W
A bullet of mass 6.00 gg is fired horizontally into a wooden block of mass 1.20 kgkg resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.190. The bullet remains embedded in the block, which is observed to slide a distance 0.270 mm along the surface before stopping.
(a) What was teh initial speed of the bullet?(b) What kind of collision took place between the bullet and the block? Explain your answer comparing the values of the kinetic energy before and after the collision.(c) Calculate the impulse of the block from the moment just after the impact to his final position. Analyze the result.
Answer:
A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.230 m along the surface before stopping.
Explanation:
Prove that the two equations shown below are equivalent.
F = ma and F = p/t
Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]
F = ma is the formula of Newton’s Second Law of Motion.
To prove Newton's second law of motion,
Given Force F = Δp/Δt
What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.Proof for F=ma
Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,
For initial velocity u, p1 = m × u
The final velocity v, p2 = m × v
The change in momentum can be expressed as
p2 – p1 = (m × v) – (m × u)
p2 – p1 = m (v – u)
Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.
The applied force F,
F ∝ [m (v – u)]/t
F ∝ m × a
As acceleration (a) is the rate of change of velocity with respect to time.
F = k × m × a
F = ma
where k can be the constant.
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