An object of mass 10 kg is moving along positive x- axis with velocity 5 m/s. At some point it breaks into two parts of 6 kg and 4 kg. 6 kg moves making 600 with x –axis and 4 kg moves making -300 with axis. What is velocity of their centre of mass after breaking?

Answers

Answer 1

Explanation:

Correct option is

B

−3m/s

2

Given,

m=10kg

u=10m/s

v=−2m/s

t=4sec

The acceleration is rate of change of velocity,

a=

t

v−u

a=

4

−2−10

a=

4

−12

=−3m/s

2

The correct option is B.


Related Questions

If the submarine intends to submerge to a depth of 150 m, what pressure must it be designed to withstand

Answers

Explanation:

Hydrostatic pressure, P = hdg where d is density if the liquid ( water)

P= 150m × 1000kgm-3 × 10ms-2

P= 1.5 ×10^6 Pa

Which of the following will require most developed countries to
decrease emissions of carbon dioxide and other greenhouse gases?
a. Montreal Protocol c. Emissions Reduction Act
b. Kyoto Protocol d. Reforestation Project

Answers

Answer:

Kyoto Protocol

Explanation:

please answer right please

Answers

Answer:

i think its A

Explanation:

I hope this helps :)

A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The work done in the given case is 0

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

For calculating the work done by an object we apply the formula, that is ~

[tex]f \times s \times \cos( \theta) [/tex]

where f represents force applied, and s represents displacement.

but here, the displacement is zero since the wall didn't move at all, Therefore If we plug it's value as 0, we get

[tex]f = 0 \times s \times \cos( \theta) [/tex]

hence,

[tex]work \: done = 0[/tex]

Solution:Here, though the man is applying force on the wall, the work done is zero. This is because work is said to be done only when a force acting on a body produces motion in it in the direction of the force applied. Here, the man is trying to push the wall with a great force. He might fell exhausted after some time and say that he has done a lot of work. But in terms of physics, he has done no work because the force applied by the person has not produced any displacement. We know, work done = force × displacement. If displacement is zero, then work done is zero.

So therefore, we can conclude that the man hasn't done any work.

Hope it helps.

Do comment if you have any query.

A fairly efficient steam turbine engine fired by coal is used to drive an electric generator. The generator operates between 2100°C and 385°C.

(a) Determine the maximum possible efficiency of the engine.


Answer: 72.3 %


Formula:

e = 1 - (Tc / Th) = 1 - (Qc / Qh) = ( W / Qh)


Explanation: Unsure??


(b) The engine absorbs 1.15 105 J from the hot reservoir every second. If the actual efficiency of the engine is 40.3%, determine the mechanical power the engine delivers.


Answer: 46 kW


Explanation:

Energy absorbed by the engine (J) * actual efficiency of the engine (%) = mechanical power the engine delivers (kW)


How does 1 - (385/2100) = 72.3 % ?
What do I Plug in to make e = 72.3 %

Answers

Use kelvin not celsius

C + 273 = K

This will fix my problem of the equation not making sense.

lonic Naming Practice
Write the name of the following chemical compound:
Na3Cl1

Answers

Answer:

sodium chloride. .....

Ionic naming practice: Na3Cl1= Sodium Chloride

Help me quick!!! please!!

Calculate the power of an engine which raises a mass of 1000 kg to a height of 40 m in 10 s.

Answers

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is [tex]w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J[/tex]

At this point we can simply apply the definition of power, that is [tex]P = \frac wt[/tex], to get the power of the engine is [tex]39.240 W[/tex]

Answer:

P=39200W

Explanation:

P=(mgh)/t

P=(40×9.8×1000)/10

P=39200W

This should be pretty easy i think.

Describe the components within the system involved in the collision between pilot and landing zone.

Answers

Answer:

its a sure for not but i think its a 192583

State a hypothesis about your estimated daily water use.

Answers

Answer

Estimates vary, but, on average, each person uses about 80-100 gallons of water per day, for indoor home uses.

Explanation:

A block with a mass of 6.0 kg is
held in equilibrium on an incline
of angle θ = 30.0° by a horizontal
force, F, as shown in the figure.
Find the magnitudes of the
normal force on the block and of F. (Ignore friction.)

Answers

(a) The normal force on the block is 50.92 N.

(b) The horizontal force on block keeping it in equilibrium is 29.4 N.

The given parameters;

mass of the block, m = 6 kgangle of inclination, θ = 30.0°

The normal force on the block is calculated as follows;

[tex]F_n = W \times cos(\theta)[/tex]

where;

W is the weight of the block

[tex]F_n = mg \times cos(\theta)\\\\F_n = 6 \times 9.8 \times cos(30)\\\\F_n = 50 .92 \ N[/tex]

The horizontal force on block keeping it in equilibrium is calculated as follows;

[tex]F- F_x = 0\\\\F-mgsin\theta= 0\\\\F = mgsin\theta\\\\F = 6 \times 9.8 \times sin(30)\\\\F = 29.4 \ N[/tex]

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Rubies are used in electronics.
Please select the best answer from the choices provided
) Т
) F

Answers

False, rubies are not used in electronics because they are bad conductors.

1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)

Answers

The force diagram on the desk consists of normal reaction and weight of the pencil.

The net force on the desk in vertical direction is 1 N.

The net force on the desk in horizontal direction is 0.

The given parameters;

weight of the pencil, W = 1 N

The force diagram of the desk is sketched as follows;

                                             ↑ N

                                             ⊕

                                              ↓ W

Where;

N is the normal reaction on the deskW is the weight of the ball

The net force on the desk in vertical direction = 1 N

The net force on the desk in horizontal direction = 0

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the primary factor in decreasing the kinetic energy of an object is to

Answers

Answer:

Decreasing the velocity

Explanation:

The primary factor in decreasing the kinetic energy of an object is to decrease the velocity of the object.

What is Kinetic energy?

The kinetic energy of an object is the energy which it possesses due to the motion of the object. Kinetic energy is defined as the work which is needed to accelerate an object of a given mass from the state of rest to its stated velocity and direction. Gain of the energy during the acceleration of an object, the body maintains this kinetic energy unless its speed changes and the object accelerates.

The kinetic energy is directly proportional to the mass and the velocity of the object. The primary factor which is responsible for the decrease in the kinetic energy of an object is to decrease the velocity of the object.

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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!


Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.


PLEASE NO LINKS OR I WILL REPORT YOU

Answers

Answer:

c

Explanation:

Prove that the two equations shown below are equivalent.​

F = ma and F = p/t​

Answers

Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]

F = ma is the formula of Newton’s Second Law of Motion.

To prove Newton's second law of motion,

Given Force F = Δp/Δt

What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.

Proof for F=ma

     Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,

For initial velocity u, p1 = m × u

The final velocity v, p2 = m × v

The change in momentum can be expressed as

p2 – p1 = (m × v) – (m × u)

p2 – p1 = m (v – u)

Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.

The applied force F,

F ∝ [m (v – u)]/t

F ∝ m × a

As acceleration (a) is the rate of change of velocity with respect to time.

F = k × m × a

F = ma

where k can be the constant.

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Suppose you were able to take measurements of current through the
resistor and voltage across the resistor. Your record of numerical values is written in a

tabular data below​

Answers

Answer:

  see attached

Explanation:

It will be easier to plot the data if you have grid lines to work with.

In the attached, we had to reverse the order of entries in the table, because the graphing program likes the independent variable listed first.

2. If Joe rides his bicycle in a straight line for 15 min with an average velocity of 12.5 km/h south, how far has he ridden?

Answers

Answer:

3.125 Kilometers

Explanation:

To answer this you just multiply 12.5 by .25 (since 15 minutes is a quarter of an hour) to get 3.125 kilometers ridden.

An "energy bar" contains 26 ggof carbohydrates.How much energy is this in joules?

Answers

I’m it’s about 3.4878 energy in joules

Why is wrestling ring floor always softThis is physics

Answers

Answer:

So the people in the ring don't get hurt or break anything on impact once they hit the floor

help -----------------------------------------

Answers

Answer:

H,G,E,D,C,B,A,I,F

Explanation:

F is an ignious intrusion and I cross cuts H to A so it must be newer.

Inertia causes bodies to slow in their motion, unless they’re pushed by a force.
Inertia resists changes to the state of motion of a body.
Inertia decelerates a body.
Inertia is due to friction.

Answers

Answer:

ill go with B

Explanation:

inertia is the ability of a body to remain at rest or in a constant speed in a constant direction when no force is acting on it

I'll give brainliest​

Answers

Good luck dude hahaha

Answer: figuratively speaking both the lines for the force Q and force P is equal.

Solve 100N up 90N down for net force

Answers

Answer:

10 Newtons up

Hope this helps!

A 0.14-MIN baseball is dropped from rest. It has a momentum of 0.90 kg⋅m/skg⋅m/s just before it lands on the ground.
For what amount of time was the ball in the air?

Answers

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

momentum of the ball, P = 0.9 kgm/sweight of the ball, W = 0.14 N

The impulse experienced by the ball is calculated as follows;

[tex]Ft = \Delta P[/tex]

where;

[tex]Ft[/tex] is impulse

[tex]\Delta P[/tex] is change in momentum

The time of motion of the ball is calculated as follows;

[tex]t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s[/tex]

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

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given. force of 88N and an acceleration of 4 m/s 2 what is the mass?

Answers

Mass, m=22 kg
It is given that Force, F = 88N
Acceleration, a=4 m/s 2

What quantity is represented by the mass number minus the atomic number?.

Answers

Answer:

Mass = mass of nucleus

Atomic Number = number of protons (charge) of nucleus

Mass - Atomic Number = number of neutrons

Da 6.0 kg wooden crate slides across a wooden floor
at a speed of 2.4 m/s, it it takes an applica force
of 25 N to keep it going at a steady speed. What is the
coe of kinetic friction between the floor and crate?

Answers

Answer:coe?

Explanation:

which term is most applicable to a discussion of angular momentum in the context of black holes?


A: Photon

B: Curvature

C: Spin

D: Time

Answers

Answer:

c:   spin

Explanation:

it's not curvature

The most applicable term to a discussion of angular momentum in the context of black holes is Spin. Thus, the correct option is C.

What is angular momentum of black holes?

Angular Momentum is defined as the property of any rotating object which is given by the product of the moment of inertia of an object and the angular velocity of the rotating object. Angular momentum is a vector quantity and it has both the magnitude and direction. The examples of angular momentum are the rotation and revolution of the Earth.

When the astronomers claim that they have estimated the spin of a black hole, this means they have measured its angular momentum. This is the total angular momentum of all the materials on the Universe that ever crossed the event horizon and got trapped inside it.

Therefore, the correct option is C.

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The product of pressure and volume of any gas equals a constant, k. What variable(s) must not change in order for the value of k to remain constant

Answers

The variable is temperature

Study the three pieces of evidence for the Big Bang in this activity carefully. What is common to all these pieces of observable evidence and why does this make them much more powerful than if they did not have this common feature?

Answers

Answer:

Explanation:

the measured abundances of elementsthe observed expansion of spacethe discovery of cosmic wave background

The common observable evidence are:

the measured abundances of elementsthe expansion of spacethe cosmic wave background

What is big bang?

The big bang is the theory which explains that how the universe began. It says that the universe began with just a single point. It went on expanding and stretched to grow as large as possible. It is still now expanding.

The big bang consist of fully dark matter, interstellar gases or dust. The big bang is increasing just because in universe there is abundant of hydrogen and helium.

The radiations come from the big bang. These rays are also called as cosmic wave. This big bang is still on it way of expanding more.

Thus, the observational evidence are the measured abundances of element, the expansion of space and the cosmic wave background.

Learn more about big bang.

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