The object takes to move is 0.409s.
Calculaiton:
time period T = 4 s
Angular speed ω = 2π/T= 1.57 rad/s
SHM equation
x = A sin ωt
6 = 10 sin(1.57t)
sin(1.57t) = 0.6
1.57 t = 0.6435
t= 0.409s.
The amplitude of a periodic variable is a measure of its change over one period. The amplitude of an aperiodic signal is its magnitude relative to a reference value. Amplitude has various definitions, all of which are functions of the magnitude of the difference between extreme values of a variable. It refers to the maximum displacement from equilibrium exhibited by a body in periodic motion.
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a constriction in a pipe reduces its diameter from 4.0 cm to 2.0 cm. where the pipe is narrow the water speed is 8.0 m/s. where it is wide the water speed is:
The velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
How to find velocity ?To find the velocity of the water where the pipe is narrow, you can use the formula for the mass flow rate, which is given by:
Mass flow rate = Density * Flow rate
= Density * (Area * Velocity)
Where:
Density is the density of the fluid
Flow rate is the volume flow rate, or the rate at which volume flows through the pipe
Area is the cross-sectional area of the pipe
Velocity is the velocity of the fluid
The mass flow rate is constant, so you can set the mass flow rate on either side of the constriction equal to each other and solve for the velocity on the other side.
The cross-sectional area of the pipe on the narrow side is given by the formula for the area of a circle:
A = pi * r^2
Where:
A is the cross-sectional area of the pipe
r is the radius of the pipe
The radius of the pipe on the narrow side is 3 cm / 2 = 1.5 cm. Plugging this value into the formula for the cross-sectional area, you get:
A = pi * (1.5 cm)^2
= 7.07 cm^2
The cross-sectional area of the pipe on the wide side is given by the same formula, with a radius of 6 cm / 2 = 3 cm:
A = pi * (3 cm)^2
= 28.27 cm^2
Since the mass flow rate is constant, you can set the mass flow rates on either side of the constriction equal to each other and solve for the velocity on the other side:
(Density * 7.07 cm^2 * v) = (Density * 28.27 cm^2 * 8 m/s)
Solving for v, the velocity on the narrow side, you get:
v = (Density * 28.27 cm^2 * 8 m/s) / (Density * 7.07 cm^2)
= 11.6 m/s
The final value for the velocity on the narrow side is 11.6 m/s. This is the velocity of the water in the narrow part of the pipe.
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it’s actually 7th grade science no physics pls answer it’s a lot of points
What do the historical communication technologies in these photos have in common?
(pictures are shown below)
All the tools of communication such as the drum, telegraph et cetra were used for emergency communication.
What is communication?We know that communication has to do with the art of sending and receiving information between two people who may or may not be at the same place. We know that the dissemination of information is a very important aspect of life and we have always tried to invent means of communication especially at times when we have an emergency situation that needs a kind of an immediate remedy.
We can see that all the kinds of communication gadgets that have been show here are all from a period that is far behind the kind of civilization that we have to day and the kind of thge communication gadgets that are quite available to the people that are around today.
However, all the tools shown could be used to send information in times of emergency.
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Classify the type of reaction below.
C2H6 + O2
--> CO2 + H2O
a. Synthesis
b. Decomposition
c. Combustion
d. Single Replacement
e. Double Replacement
Answer: Synthesis
Explanation: You are combining multiple Elements
A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?
Answer:
5 m
Explanation:
Displacement is the straight-line distance from the starting point to the end point. Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).
d² = 3² + 4² = 25
d = [tex]\sqrt{25}[/tex] = 5 m
Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)
a point at an antinode of the standing wave on the wire travels from its maximum upward displacement to its maximum downward displacement in 8.40 msms . what is the wire'??s mass?
The relation between the time-period of the transverse wave for the third harmonic and the time between the maximum displacement and minimum displacement is [tex]=16.3 \mathrm{~g}[/tex]
[tex]$$T_3=2 t$$Substitute$8.40 \mathrm{~ms}$[/tex]
for t in the above expression.
[tex]$$T_3=2(8.4 \mathrm{~ms})\left(\frac{10^{-3} \mathrm{~s}}{1 \mathrm{~ms}}\right)$$[/tex]
The wave velocity can be given by the following expression [tex]=0.0168 \mathrm{~s}[/tex]
[tex]v=\frac{\lambda_3}{T_3}[/tex]
Here,
[tex]$$\lambda_3$$[/tex]
is the frequency of third harmonics and
[tex]$$T_3$$[/tex]
is the time-period of third harmonics.
Substitute [tex]$0.1296 \mathrm{~m}$[/tex] for
[tex]$$\lambda_3$$[/tex]
and
[tex]$0.0168 \mathrm{~s}$ for$T_3$[/tex]
[tex]\begin{aligned}& v=\frac{0.1296 \mathrm{~m}}{0.0168 \mathrm{~m}} \\& =7.714 \mathrm{~m} / \mathrm{s}\end{aligned}[/tex]
The expression of the wave velocity is given by the following expression.
[tex]v=\sqrt{\frac{T}{m / L}}[/tex]
Rearrange the above expression for
[tex]$$m$$[/tex]
[tex]\text { Substitute } 5.00 \mathrm{~N} \text { for } T, 0.1944 \mathrm{~m} \text { for } L \text {, and } 7.714 \mathrm{~m} / \mathrm{s} \text { for } v \text { in the above expression. }[/tex]
[tex]\begin{gathered}m=\frac{(5.00 \mathrm{~N})(0.1944 \mathrm{~m})}{(7.714 \mathrm{~m} / \mathrm{s})^2} \\=(0.0163345 \mathrm{~kg})\left(\frac{1000 \mathrm{~g}}{1 \mathrm{~kg}}\right) \\=16.3 \mathrm{~g}\end{gathered}[/tex]
The anti-nodes in the standing waves are at a distance half a wavelength. The time-period is twice the time from maximum displacement to minimum displacement of the anti-node.
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one cannot peer all the way back and directly observe the big bang because the universe's density was so low. true false
True. The Big Bang Theory is the current scientific explanation for the origin and evolution of the universe. According to this theory, the universe was initially in a state of extremely high density and temperature, and it has been expanding and cooling since its inception.
One reason we cannot directly observe the Big Bang is that the universe's density was so low at that time that there were no solid particles, such as atoms or molecules, that could have formed into stars or galaxies. Instead, the universe was filled with a hot, ionized plasma that was too diffuse to be observed by telescopes. Another reason is that the expansion of the universe has caused the light and other electromagnetic radiation that was emitted during the Big Bang to become redshifted, or stretched out in wavelength, over time. This means that the light from the earliest moments of the universe has shifted into the microwave and radio frequency ranges, which are not visible to the human eye. Therefore, while we can infer some details about the conditions of the early universe based on observations of the cosmic microwave background radiation and the large-scale structure of the universe, we cannot directly observe the Big Bang itself.
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Uing two billiard ball and 3 to 4 entence decided experiment to demontrate the law of conervation of momentum. (4 point)
So let's talk about billiard balls and the law of conservation of momentum. For the purposes of this simplified discussion, momentum is always conserved for collisions between balls.
What is momentum?Momentum is a commonly used term in sports. A team that has the momentum is on the move and is going to take some effort to stop. A team that has a lot of momentum is really on the move and is going to be hard to stop. Momentum is a physics term; it refers to the quantity of motion that an object has. A sports team that is on the move has the momentum. If an object is in motion (on the move) then it has momentum.Momentum can be defined as "mass in motion." All objects have mass; so if an object is moving, then it has momentum - it has its mass in motion. The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving. Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.To learn more about velocity refer to:
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when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?
You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.
What three sorts of solar occurrences are there?Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.
How can I follow the cycle of solar activity the best?The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.
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5. if the star sirius emits 23 times more energy than the sun, why does the sun appear brighter in the sky? include the terms luminosity and apparent brightness in your response.
The star Sirius is indeed brighter but our Sun appears to be brighter because it is closer to us.
The intrinsic luminosity of Sirius is exactly 25.4 times more than the sun but if we compare the distances of these stars, Sirius is 8.6 light years away from us and the Sun is just 8 light minutes away from us. This marks the obvious reason why our Sun appears more bright.
Even mathematically, it can be justified as the apparent brightness of any luminous object depends on the inverse square of the distance of that luminous object. Therefore the sun's light energy dominates our sky and we can't see any traces of Sirius from the earth.
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Question 8 of 20
You heat a pot of water on a gas stove. Not all the energy from the
combustion of the gas is transformed into thermal energy. What happens to
the rest of the energy released when the gas burns?
OA. It is transformed into light energy.
OB. It is transformed into chemical energy.
C. It is transformed into electrical energy.
OD. It is transformed into nuclear energy.
SUBMIT
Answer:
None of the choices you provided are correct. When a gas burns, it releases energy in the form of heat and light. Some of this energy is transferred to the pot of water, increasing its temperature, but some of the energy is also released as light. However, the rest of the energy is not transformed into chemical, electrical, or nuclear energy. Instead, it is lost to the environment in the form of waste heat. This is why gas stoves can become hot to the touch - they are releasing excess energy in the form of heat that is not being used to heat the pot of water.
Explanation:
Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.
The volume of the toy is 80 ml.
To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.
In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.
The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.
It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.
Answer:
Volume of the toy: [tex]80\; {\rm mL}[/tex].
Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)
Explanation:
The graduated cylinder initially measures the volume of water in this cylinder:
[tex]V(\text{water}) = 70\; {\rm mL}[/tex].
Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:
[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].
Rearrange to find the volume of the toy:
[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].
To find the average density of this toy, divide mass by volume:
[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].
1. Find the force due to gravity if the mass of the object is 2300 kg
and the mass of the other object is 4000 kg. The distance
between the two objects is 0.150 m.
The force due to gravity will be 0.0272 Newtons.
What exactly does gravitational force signify?The force between two mass-containing objects that are drawn toward one another is referred to as the gravitational pull. There is gravity everywhere around us. For instance, it maintains the planets in our solar system in orbit around the Sun. Additionally, because to gravity, the Moon maintains its orbit around the Earth.
How to calculate gravitational force in the above question?Despite being weak and appealing, gravitational forces exist.
Given, mass of one object= 2300 kg
mass of another object= 4000 kg
distance between the two objects= 0.150 m
value of G is universal, [tex]G= 6.67[/tex]×[tex]10^{-11}[/tex] [tex]N m^{2} / kg^{2}[/tex]
the equation is, [tex]F=G\frac{M1 . M2}{d^{2} }[/tex]
[tex]F=0.0272 N[/tex]
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an increase in sound level from 30 db to 50 db requires an increase in sound intensity by a factor of:
Loudness increases by 10 dB for every dB increase in sound intensity. A 40-decibel light rainstorm is 100 times louder than a whisper, whereas a 30-decibel "silent" room is 10 times louder than a 20-decibel whisper. Loud noises can be harmful.
50 dB is how much louder than 20 dB?A 10 dB rise results in a two-fold increase in volume. The loudness will therefore rise by nearly 8 times with a 30 dB increase (from 20 dB to 50 dB).
Decibels are measured on a logarithmic scale using a power of ten, which might be perplexing. For those of you without advanced math degrees, this simply implies that the sound intensity doubles for every 10 decibel rise.
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if we have a system that uses 5 volts with a frequency of 1ghz and the power used is 3 watts, what is the power draw when we increase the frequency to 3ghz?
Processor-A uses 20 W of power components and 80 W cpu dynamic power 3 GHz.
Static power: What does that mean?When there is no design activity occurring, static power—also known as "leakage"—is used up. It closely relates to the transistor's idle current, which is based on the transistor's characteristics.
Power is it static or is it dynamic?While leakage, or the current that passes through a transistor while there is no activity, makes up static power, switching or short-circuit power are components of dynamic power. Any of the following things may influence each power component's value: Activity. Frequency.
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disregarding friction, how far will the cart move in 3.2 s, starting from rest? answer in units of m.
If the cart moves in 3.2 seconds from rest, then the distance traveled by cart is 2 meters.
Which definition of distance suits you best?How do you define distance? Regardless of direction, distance measures an object's overall movement. Distance is defined as the amount of ground covered by an object, regardless of its starting or stopping position.
Horizontal force acting on the cart, F = 11 N
Mass of the cart, m = 35 kg
To find,
Distance covered by the cart in 3.5 seconds if it starts from rest.
Solution,
Let x is the distance moved by the cart. It can be calculated using the second equation of motion as :
s = 1.925 meters
What is the definition of a distance?In terms of "how much land an object is covered" while traveling, distance—a scalar quantity—describes this. Displacement is a vector number that expresses the overall change in the object's location, and it is related to the phrase "how far from place the thing is."
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I NEED HELP ASAP PLSS
Answer:
C.) The United States would become less dependent on energies that emit greenhouse gases.
Explanation:
If nuclear energy increased, it would occupy a larger piece of the pie chart. The prompt states that the usage of non-fossil fuel-based forms of energy would remain constant. This condition means that nuclear energy would decrease the percentage of fossil fuel-based energy used. Energy production through the use of fossil fuels necessarily produces greenhouse gases such as CO2. An increase in nuclear energy would mean a corresponding decrease in dependence on greenhouse gas-producing fossil fuels.
John walks to the pizza place for lunch. He walks 2 km north, then 1 km east. To get home, he walks 2 km west and 1 km south. What distance did he travel? What is his displacement?
Answer:
The total distance covered is 3 km and the displacement is 2.24 km.
Explanation:
For the total distance covered by Anthony, we just add all of the distances.
1 km (going east) + 1 km (going east again) + 1 km (going south) = 3 km
Hence, the his total distance covered when he went to the pizza place is 3 km.
Solving for the displacement is a different matter. We cannot just add all of the distances. From analysis of the problem, Anthony traveled and formed a right triangle. He traveled 1 km east twice, making it 2 km east in total, then he traveled 1 km south.
When dealing with a right triangle with 2 sides given (for this problem the two sides are the 2 km east and the 1 km south), we use the Pythagorean Theorem.
Solution:
c² = a² + b² (Pythagorean Theorem)
c will be the longest side of the right triangle
a and b will be the other sides of the right triangle
c = √ (a² + b²)
c = √ (2² km + 1² km)
c = √5 km
c = 2.2361 km ≈ 2.24 km
Therefore, the displacement of Anthony is 2.24 km.
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1. a 1.4 x 103 kg car is westbound at a velocity of 37.0 km/h when it collides with a 2.0 x 103 kg truck northbound at a velocity of 35 km/h. if these two vehicles lock together upon collision, what is the initial velocity of the vehicles after collision? (7.2 m/s 37o w of n) 2. a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision? (2.4 m/s 56o w of n) 3. a 4.0 x 104 n truck moving west at a velocity of 8.0 m/s collides with a 3.0x104 n truck heading south at a velocity of 5.0 m/s. if these two vehicles lock together upon impact, what is their velocity?(5.0 m/s 25o s of w)
The velocity of vehicles after the collision is 15.82m/sec if car mass is 1.4 × 10³kg and truck mass is 2×10³kg
We know that we need to conserve the momentum of watermelon in a certain direction. Also,we know that initial momentum of watermelon is zero,it means that according to law of conservation of momentum final momentum should be zero.
We know that momentum =mass × velocity
So,initial momentum of car is =1.4 × 10³kg × 37km/hr
Similarly,,initial momentum of truck=2×10³kg × 35km/hr
Now,it is given that both vehicles lock together,so total mass of both vehicles is =1.4 × 10³kg + 2×10³kg=3.4 ×10³kg
Assume final velocity of both vehicle is v
So,following the law of conservation,we get
=>1.4 × 10³kg × 37 + 2×10³kg × 35 = 3.4 ×10³ ×v
=>51.8 ×10³ + 2×10³=3.4×10³ ×v
=>53.8 ×10³ kg-m/sec = 3.4×10³ ×v
=>v = 53.8/3.4
=>v=15.82m/sec
Hence,final velocity of both vehicle after collision is 15.82m/sec.
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two planets are identical, except planet x has an atmosphere of mostly nitrogen and planet y has an atmosphere of mostly carbon dioxide. what can you determine about the planets
Two planets are identical, except planet x has an atmosphere of mostly nitrogen and planet y has an atmosphere of mostly carbon dioxide therefore what we can determine about the planets is that x is Earth while y is Venus.
What is Atmosphere?This is referred to as the envelope of gases surrounding the earth or another planet and it makes life possible by providing different organisms with air to breathe
In the atmosphere of the planet Venus there is a high concentration of carbon dioxide as it is made up of it is made of 96.5% of CO₂ and a 3% of nitrogen.
On the other hand in the atmosphere of the planet Earth, there is a high concentration of nitrogen which is about 78% and is therefore the reason why they were chosen as the correct choices.
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a vertical spring scale can measure weights up to 210 n . the scale extends by an amount of 13.5 cm from its equilibrium position at 0 n to the 210 n mark. a fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.15 hz . part a ignoring the mass of the spring, what is the mass m of the fish?
sheesh sheesh
Explanation:
The diagram below represents a wave.
What is the speed of the wave if its wavelength is 3.0 m?
The speed of the wave is determined as 18 m/s.
option D is the correct answer.
What is the speed of the wave?
The speed of the wave is the rate of change of wave's displacement with time.
The speed of the wave is calculated by applying the formula relating speed, wavelength and frequency of the wave as shown below.
v = fλ
where;
v is the speed of the wavef is the frequency of the waveλ is the wavelength of the waveThe frequency of the wave is calculated as follows;
f = 1 / T
where;
T is the period of the waveThe period of a wave is the time taken for the wave to complete one cycle.
In the picture given, 3 cycles of the wave = 0.5 s
1 cycle of the wave = ?
= 0.5 s / 3
= 0.16667 s
f = 1 / T
f = 1 / 0.16667
f = 6 Hz
The speed of the wave is calculated as follows;
v = fλ
v = 6 Hz x 3 m
v = 18 m/s
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1. A car moving 11 m/s accelerates at 1.5 m/s². How fast is it moving after it accelerates for 50
seconds?
Type a response (show work please)
We may be aware that, for example, a car leaving a stop sign would move farther in a given amount of time the faster it accelerates.
what an acceleration is?acceleration is the rate of change in both speed of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated. So because direction is always shifting, motion on a circle accelerates even while the speed is constant.
What prompts accelerating?An object's velocity is altered by a net force, and acceleration increases with net force. To accelerate at the same rate as less massive objects, more massive objects need greater net forces.
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WILL GIVE BRAINLY IF RIGHT
what would happen if you dropped, at the same time, particles of different shapes from a boat into still water
Explanation:
If you dropped particles of different shapes from a boat into still water, they would fall straight down due to the force of gravity. The speed at which they fall would depend on their mass and the shape of the particles could affect how they move through the water, but ultimately they would all sink to the bottom of the water body. If the particles are buoyant, they may float instead of sinking.
the force between between two objects increases by what factor if the distance between them is changed 4.5 times the original separation?
The new gravitational force between the object will be 1/20.25 times of the original force.
The gravitational force between any two object is defined as the product of the masses of the object and it is inversely proportional to the square of the distance between them which is given by,
F = GMm/R²
Here,
G is the universal gravitational constant, M and m are the mass of the body and R is the distance between them.
As per the given question the distance between the object is increased 4.5 times the original separation.
R' = 4.5R.
The new force of attraction between the object will be,
F' = GMm/(R')²
F' = GMm/(4.5R)²
F' = GMm/20.25R²
F' = F/20.25
So, the new force of attraction between the two objects will become 1/20.25 times of original force.
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7. What is the weight of a ball with a mass of 0.77 kg? (hint: how fast is gravity?)
Answer:
While on the earth, any object with a mass of 0.77 kg weighs 7.546 newtons (1.698 pounds).
On the moon, the same 0.77-kg object would weigh 1.232 newtons (0.277 pound)
Explanation:
what force must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2500 kg car (a big car) resting on the slave cylinder? the master cylinder has a 1.93 cm diameter, while the slave's is 24.9 cm. 1900 n 150 n 15 n 4.1e 06 n 74 n
The force that must be exerted on the master cylinder of the hydraulic lift to support the weight of car is 147.2 N .
The Pascal's Law states that the relation between the pressure , force and area is given as :
Pressure = Force/Area ;
given that the diameter of the master cylinder is = 1.93 cm ;
so radius of master cylinder = 1.93/2 = 0.965 cm = 0.00965 m ;
the diameter of slave cylinder is = 24.9 cm ;
the radius of the slave cylinder = 24.9/2 = 12.45 m = 0.1245 m ;
Area of slave cylinder (A₁)= π(0.1245)² = 0.0486 m²
Area of the master cylinder (A₂) = π(0.00965)² = 0.000292 m² ;
given mass of the car = 2500 Kg ,
the force exerted will be : F = m*a
F₁ = 2500*9.8 = 24500 N ;
F₁/A₁ = F₂/A₂
So , 24500/0.0486 = F₂/0.000292
F₂ = (24500/0.0486)×0.000292
F₂ = 147.2 N
Therefore , the force exerted on the master cylinder is 147.2 N .
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a dad pushes tangentially on a small hand-driven merry-go-round and is able to accelerate it from rest to a frequency of 15 rpm in 10.0 s. assume the merry-go-round is a uniform disk of radius 2.5 m and has a mass of 330 kg, and two children (each with a mass of 25 kg) sit opposite each other on the edge. calculate the torque required to produce the acceleration, neglecting frictional torque. what force is required at the edge?
Refer to the photo taken.
a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. How much work was done by the dog ?
The work done by the dog is 0.81J.
What is work done?Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.
It is said that no work is done if the object does not move.
The work done on an object is the amount of energy transferred to an object through work.
According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:
Force = mass × acceleration
Force = 0.75kg × 9.8m/s²
Force = 7.35N
Work done = 7.35N × 0.11m = 0.81J
Therefore, 0.81J is the work done by the dog.
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a car accelerates uniformly from rest to 25 m/s over a distance of 30 meters. what is the acceleration of the car?
Answer:
a=25/24 m/s^2
Explanation:
I’m going to assume you mean the final velocity is 25m/s.
v^2=u^2+2as
625=0+2a300
a=25/24 m/s^2 or 1.0416^_ (period 1) ^m
a 40cm diameter wheel accelerates uniformly from 240 rpm to 360 rpm in 6.5 seconds. how far will a point on the edge of the wheel have traveled in this time
Answer:
S = V1 t + 1/2 a t^2 distance traveled for linear acceleration
θ = ω1 t + 1/2 α t^2 equivalent angle for rotational acceleration
ω1 = 240 / min * 2 π * 240 / (60 s/min) = 8 π / s
ω2 = 360 rpm = 12 π / s
α = 4 π/ 6.5 s^2 = .62 π / s^2 angular acceleration
θ = 8 π / s 6.5 s + .62 π / 2 * 6.5^2
θ = 52 π + 13 π = 65 π = 65 * π / (2 π / rev) = 32.5 rev
1 rev = 2 * π * R = 2 * π * .4 m = 2.51 m / rev
S = 32.5 rev * 2.5 m/rev = 81 m
