The Total Work done by the gas = area under the graph on the volume axis.
Clearly, from the graph, we can see that area below the isotherm is less than the area under the straight line AB process.
On drawing multiple isotherms across AB, we can see that the temperature first increases and then decreases.
1. The work done by the gas in the process A to B exceeds the work that would be done by it if the system were taken from A to B along the isotherm.
2. In the T-V diagram, path AB becomes a part of the parabola.
3. Ongoing from A to B, the temperature T of the gas first increases to the highest value and then decreases.
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if you weight 100 pounds on earth,
what would you weight on the moon
Answer: 16 Pounds.
To figure out how much YOU would weigh on the moon, take your weight and divide it by 6. So, if you weighed 100 pounds on Earth, you would weigh only about 16 pounds on the moon.
Question
A rabbit moves a distance of 85 meters in 13 seconds.
What is the rabbits average speed?
7.26 m/s
0.15 m/s²
6.54 m/s
6.54 m/s²
Important Formula:
[tex]s=\dfrac{d}{t}[/tex]
__________________________________________________________
[tex]d=85m[/tex] (measured in meters)
[tex]t=13s[/tex] (measured in seconds)
[tex]s=?[/tex] (measured in meters per second; m/s)
__________________________________________________________
[tex]s=\dfrac{d}{t}[/tex]
[tex]s=\dfrac{85}{13}[/tex]
__________________________________________________________
[tex]\fbox{6.54 m/s},\fbox{Option C}[/tex]
an astronaut drops a rock from the top of a crater on the moon when the rock is halfwat down to the bottom of the crater its speed is what fraction of its cinal impact speed?A. 1/4–√2B.1/4C. 1/2–√2D. 1/–√2Answer:
The fraction of its final impact speed is 1/√2.
Impact speed is the speed of the vehicle at the time of impact or collision.
The rock has lost half of its gravitational potential energy, its kinetic energy at the halfway point is half of its kinetic energy at impact.
As we know kinetic energy is directly proportional to mass (m) and velocity square (v²),
KE ∝ v²
KE = (1/2)mv²
then K.E at halfway point is equal to 1/2 x K.E,
Then,
The K.E at impact, then the rock’s speed at the halfway point its speed at impact will be 1/√2 its impact speed.
Therefore option D is the correct answer, the fraction of its final impact speed is 1/√2.
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Emily and Henry were in the lab and graphed the heating of ice to 125°C. Emily and Brad made an observation that the graph contains three sloped and two level portions. Emily and Brad determined that the two level portions in the graph represented:
The two level portions in the graph represented phase changes.
What are phase changes?
The transition of matter from one state (solid, liquid, gas, or plasma) to another is referred to as a phase change. These changes also take place when the pressure on the system varies, as well as when the system receives enough energy or loses enough energy.
The slope of the line dividing two phases is determined by the relative densities of the two phases. The solid-liquid line, for instance, slopes up and to the right if the liquid is less dense than the solid, whereas up and to the left if the liquid is denser than the solid.
Therefore the two level portions in the graph represented phase changes.
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Earth satellite whose height is 35786 km then find its distance velocity ?
help me it's urgent i mark u brainlist
Earth satellite whose height is 35786 km them the distance velocity is 11,300 km/h.
What is satellite?Satellite is defined as a piece of technology that is launched into space and orbits the earth or another planet with a specific purpose. An object that orbits a larger object can be referred to as a satellite.
The equation for estimating the speed for the orbital velocity of a satellite is derived using the centripetal force and gravitation equations. The spacecraft would need to maintain a velocity of roughly 11,300 km/h in order to complete one orbit of the earth, which is located nearly 35,786 km above the surface of the planet.
Thus, earth satellite whose height is 35786 km them the distance velocity is 11,300 km/h.
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Which is the correct equation for calculating the kinetic energy of an object?
Answer:
Below
Explanation:
K.E. = 1/2 * m * v^2
4. For an ideal gas, the specific heat at constant pressure Cp is greater than the specific heat at constant volume CV because the A. pressure of the gas remains constant when its temperature remains constant B. gas does work on its environment when its pressure remains constant while its temperature is in creased C. increase in the gas's internal energy is greater when the pressure remains constant than when t he volume remains constant D. heat input per degree increase in temperature is the same in processes for which either the pressure or the volume is kept constant
Whenever the gases are heated at a fixed volume, no outside work is done as well as the heat energy given is simply used to make the gas more energetic internally.
Why is CP for just an ideal gas higher than Cv?The specific heat under constant pressure for an ideal gas, Cp, is higher than Cv.This is due to the fact that when the gas' temperature rises while the pressure stays constant, the gas must perform some finite work on its surroundings.
Does CP always exceed Cpk?When the goal value and the specification's average are equal, Cpk equals Cp.Never can Cpk go above Cp.With the creation of descriptive statistic displays and histograms, Cp and Cpk can both be determined.
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Suppose we observe a Cepheid variable in a distant galaxy. The Cepheid brightens and dims with a regular period of about 10 days. What can we learn from this observation?We can learn the distance to the galaxy.
We can find out how far away the galaxy is. By comparing the actual luminosity with the expected luminosity, which is affected by the inverse square law of light traveling through the great expanses of space.
How can the distance of Cepheid variables be determined from observations of those variables?
Astronomers have measured the distances to distant galaxies by observing Cepheid variables. They compare the apparent brightness with the intrinsic brightness of the Cepheid variable. The distance can be determined by comparing the observed and actual brightness.
How far can we measure in space using Cepheid variables?
Unlike Earth-based parallax measurements, which can only be made up to a maximum of 65 light years, cepheid variables can be observed and measured out to a distance of around 20 million light years.
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_______ drink(s) within a 4 hour time span, regardless of height and weight, can get you a BAC of .01% .
1
1 drink(s) within a 4-hour time span regardless of the height and weight can get you a BAC of .01%.
Even one drink of alcohol can impair your ability to drive. Having more than one drink in his bloodstream puts him in danger and could get him arrested. Failure to pay this will result in a fine of 10% of the service tax. No penalty if service tax and interest are paid within 30 days after the notice is served.
Usually, you can apply the one-drink-an-hour rule without hesitation. So if you have two glasses of wine, you have to wait two hours before going out. Drinking one cup for an hour will give your body time to overcome the other factors above and hopefully bring you to a safe enough alcohol level to drive.
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short 10g rope is used to pull a 50g toy across a horizontal surface without friction. if a force of 3.0 x 10 -2 n is applied horizontally to the free
0.025 N the force of the string on the toy, at the other end of the rope.
What is friction?Friction is a force that resists the relative motion of two objects that are in contact with each other. It is caused by the interaction of the surfaces of the two objects and the molecules that make them up. Friction can be either static or kinetic. Static friction occurs when the two surfaces are not moving relative to each other, while kinetic friction occurs when the two surfaces are moving relative to each other. Friction is a type of force that can be both beneficial and detrimental.
Mass of the string (m) = 10 grams or 10⁻² kg
Mass of the toy (M) = 50 g or 5 x10⁻² kg
Mass of the system = M + m
= 10⁻² + 5 x 10⁻²
= 6 x 10⁻² kg
Force applied (F) = 3.0 x 10⁻² N
Acceleration of toy + string = (0.03/6) x 10⁻²
= 0.5m/s²
Thus force on the toy = 5 x10⁻² x 0.5
= 0.025 N
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The complete question is as follows:
A short 10g string is used to pull a 50g toy across a frictionless horizontal surface. if a 0.03N force is applied horizontally to the free end, the force of the string on the toy, at the other end, is:
What quantity describes how long an object is moving for?
A 17,973 g object has an acceleration of 2m/s². What is the net force applied to the
object
Answer:
According to Newton's second law of motion, the acceleration of an object equals the net force acting on it divided by its mass, or a = F m .
Explanation:
The Sun's evolution from youngest to oldest stage is:
A) white dwarf, red giant, main-sequence, protostar
B) red giant, main-sequence, white dwarf, protostar
C) protostar, red giant, main-sequence, white dwarf
D) protostar, main-sequence, red giant, white dwarf
D) The Sun's evolution from youngest to the oldest stage is protostar, main-sequence, red giant, a white dwarf.
A protostar is the very beginning stage of a star's life. It is a cloud of gas and dust that starts to collapse due to its own gravitational pull. As it collapses, the gas and dust heat up, and eventually, nuclear fusion begins, creating a star.
The main-sequence stage is the longest and most stable period of a star's life. During this stage, the star is converting hydrogen into helium in its core, producing energy and light. This stage can last for billions of years.
Once a star has used up its hydrogen fuel, it enters the red giant phase. This is when the star expands, becoming much larger and much brighter. The star is now converting helium into other elements in its core, such as carbon and oxygen.
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During the collision, the car and truck exert forces on each other. Which of the following is a correct statement about these forces and gives evidence to support this statement? The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the truck changes. B The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the car changes. С The forces the truck and car exert on each other must be external to the truck-car system because the momentum of both the truck and car change. D The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same E The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system changes.
The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same. Option D
What is the Collison?We know that it is possible for an object to be able to bump into another object when this occurs, we would have to apply the law of the conservation of linear momentum. Recall that from the law of the conservation of linear momentum, momentum before collision is equal to the momentum after collision.
We would also have to consider the fact that the weight of the truck is much lager than the weight of the car. The forces that the two vehicles would exert on each other can not be the same. It is clear that the truck is going to exert more force than the car.
With that said, we must have in mind that the total momentum of the system does not change because we are going to approximate the system to function as a closed system.
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The reynolds number is an important number in fluid mechanics. it is the ratio of the intertial forces to viscous forces. T/F
True. A Reynolds number is an important number in fluid mechanics. it is the ratio of the inertial forces to viscous forces.
The Reynolds number is a dimensionless quantity that is used to determine whether the flow pattern in a pipe is laminar or turbulent. The ratio of inertial forces to viscous forces defines the Reynolds number.
If the value of Nr is between 0 and 2000, the liquid flow is streamlined or laminar. The flow is turbulent above 4000, and the flow of the liquid is unstable between 2000 and 3000, alternating between the laminar and turbulent flow.
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a long, straight, thin-walled cylindrical shell of radius r carries a current i. find the magnetic field outside the cylinder (r > r) and inside the cylinder (r < r).
The magnetic field inside the cylinder is zero and outside the cylinder is
B = μ₀ I/(2*π*r)
The circulation of the magnetic field along a circular path of radius, r , is given by:
⇒ B cosθ (2* π* r)
where, cos θ is 1 if the field forms circles. Now that the Amperian loop is closed, we may analyze the current inside of it. The net current that travels across the surface defined by the Amperian loop determines the enclosed current. The enclosed current is denoted by the letter I since the loop completely encloses the wire. Making use of Ampere's Law,
B cosθ (2* π* r) = μ₀ I
Since, the right-hand side of the equation is not zero at this moment, it is obvious that cos cannot be zero. As a result, we can draw the conclusion that, as we had previously predicted, the magnetic field must form concentric rings. The magnetic field's strength is determined by:
B = μ₀ I/(2*π*r)
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Sorrow, hurt, anger, guilt, confusion, and other feelings that arise after suffering a loss are reflected in: a. grief. b. acceptance. c. mourning. d. distancing.
Correct answer:- (a) grief
Sorrow, hurt, anger, guilt, confusion, and other feelings that arise after suffering a loss are reflected in grief.
What does grief mean?Regardless of whether someone's sadness is caused by the loss of a loved one or by receiving a terminal illness, grief is a powerful, perhaps overwhelming feeling for people.
What is the duration of grief?
Grieving typically lasts for a year or longer. The individual in grieving must deal with the emotional and life changes brought on by the loss of a loved one. It's normal to feel emotionally attached to the deceased for a very long time after they have passed away, even though the anguish may eventually lessen.
How much time does grief last?Grieving typically lasts for a year or longer. The individual in grieving must deal with the emotional and life changes brought on by the loss of a loved one. It's normal to feel emotionally attached to the deceased for a very long time after they have passed away, even though the anguish may eventually lessen.
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A small box of mass m is kicked up an inclined plane with an initial velocity v, and slides up the incline a distance L before it stops. The inclined plane makes an angle a with the horizontal, and the friction coefficient is u. What is the distance L the box slides up the ramp before it stops? (Hint: The known quantities are the mass, the initial speed, the angle, the coefficient of friction, and the acceleration of gravity:{m, Vo, a,u,9). Solve for the distance L in terms of these quantities.)
Main Answer:
The distance of L is [tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]
Explanation:
if the block will slide a distance 'L' then syoped;
The initial velocity given to the block is V m/s
So, Total K.E given will goes to gain in potential energy and work done by friction .
K.E=1/2mv^2
P.E at hight (Lsin[tex]\alpha[/tex]) will be = mgh
And work done by the Friction Force is given as = w.r = force*displacement= - uNL= -uMgGcos[tex]\alpha[/tex]L
so,
KE+WD by friction = gain in P.E
[tex]1/2mv^{2} +(-uMgGcos\alpha L)=MgLsin\alpha \\1/2V^{2} =glsin\alpha +uglcso\alpha \\v^{2} /2= Gl(sin\alpha +ucos\alpha )[/tex]
Hence by solving we get :
[tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]=L
So the distance = L
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A 2.0-m-long string vibrates at its second-harmonic frequency with a maximum amplitude of 2.0 cm. One end of the string is at x = 0 cm. Find the oscillation amplitude at x = 10, 20, 30, 40, and 50 cm.
At x = 10, 20, 30, 40, & 50 cm, the oscillation's amplitude is 8.83 mm.The length of time required for a motion to complete one cycle.
How do you define oscillatory amplitude?The greatest deviation from the mean position is the magnitude of oscillation for a body that oscillates. It is the length between peak or trough of the wave and its mean position. The loudness of a sound will increase with increasing sound wave amplitude.
In an oscillating pendulum, what is amplitude?Amplitude: The distance between the motion's center and either extremity. Period: The length of time required for a motion to complete one cycle.
A(x)=A(max)sin(2pix/L)
A(x)=0.015sin(2pix/2)
A(x) =0.015sin (pix)
where x=20cm = 0.2m
A(x)=0.015sin(pi*0.2)
8.83 mm or A(x)=8,82*10-3 m
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if your answer is a vector, give answer in the form ai bj ck with no spaces between symbols.if your answer is a scalar, then give your scalar answer.
scalar, any physical quantity whose magnitude serves as its sole description.Volume, density, velocity, energy, weight, and time are a few examples of scalars.Other quantities, like as velocity and force are referred to as vectors since they have both direction and magnitude.
How can you recognize a scalar?While vector quantities have had both magnitude and direction, scalar values simply have magnitude.Time is a scalar that is entirely independent of direction.It lacks direction and just possesses magnitude.Acceleration, displacement, and force all happen in a specific direction.
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Two frequency generators are creating sounds of frequencies 460 and 471 Hz simultaneously. Randomized Variables f1 = 460 Hz f2 = 471 Hz Part (a) What average frequency will you hear in Hz?
The average frequency will be 465.5 Hz.
The frequency of light can be described as the number of waves passing through a point in a medium (or vacuum) per second.
It is measured in units of Hertz (Hz). Electromagnetic radiation propagates through space as a wave, and one type of radiation differs from another in the frequency of this wave. Electromagnetic radiation is categorized using the electromagnetic spectrum, which is usually organized by frequency.Frequency generated by generator 1 = f1 = 460 Hz
Frequency produced by generator 2 = f2 = 471 Hz
the average frequency will be (f1 + f2) / 2
f1 + f2 = 460 + 471
f1 + f2 = 931 Hz
Average frequency = A = 931/2
A = 465.5 Hz
The average frequency we hear will be 465.5 Hz.
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a 5 kg block is suspended from the pulley system as shown. pulley a has a mass of 15 kg, a radius of 103 mm, and radius of gyration of 77 mm. pulley b has a mass of 3 kg, a radius of 32 mm, and a radius of gyration of 31 mm. determine the speed of the block after it has decended 3 meters. give your answer rounded to 2 decimal places.
The speed of the block after it has descended is 3 meters is 3.54 m/s.
To determine the speed of the block after it has descended 3 meters, we need to consider the energy conservation principle. The initial potential energy of the block is equal to the final kinetic energy of the block plus the work done on the block by the pulleys.
The initial potential energy of the block is given by:
U = mgh
where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the block.
The final kinetic energy of the block is given by:
K = (1/2) × m × v²
where m is the mass of the block and v is the velocity of the block.
The work done on the block by the pulleys is given by:
W = F × d
where F is the force exerted on the block by the pulleys and d is the distance traveled by the block.
The force exerted on the block by the pulleys is equal to the tension in the rope. The tension in the rope can be calculated using the following formula:
T = (m × g) / (1 + (Ia/Ib))
where T is the tension in the rope, m is the mass of the block, g is the acceleration due to gravity, Ia is the moment of inertia of pulley A, and Ib.
where I is the moment of inertia, m is the mass of the pulley, and r is the radius of the pulley.
Substituting the given values into the formulas above, we get:
U = 5 × 9.81 × 3 = 146.1 J.
Ia = (1/2) × 15 × (77)² = 70,245 [tex]mm^4[/tex]
Ib = (1/2) × 3 × (31)² = 2,871 [tex]mm^4[/tex]
T = (5 × 9.81) / (1 + (70,245/2,871)) = 33.4 N
W = T × 3 = 100.2 J
K = (1/2) × 5 × v²
Substituting the values for U, W, and K into the energy conservation equation, we get:
146.1 J = 100.2 J + (1/2) × 5 × v²
v² = (146.1 J - 100.2 J) / (1/2) × 5
v² = 45.9 J / 2.5
v = √(45.9 J / 2.5) = 3.54 m/s
Therefore, the speed of the block after it has descended 3 meters is approximately 3.54 m/s, rounded to two decimal places.
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how does the final temperature of the gas compare with its initial temperature? express your answer using two significant figures. tcta
Step 1: Calculate the ratio of the final and beginning temperatures using the ideal gas law solved for temperature.
Step 2: Calculate the ratio after eliminating any constant values.
Step 3:Solve for the final temperature after substituting the beginning temperature into the ratio.
Perfect Gas Law: According to the ideal gas law, a gas's pressure, P, is inversely proportional to its volume, V, temperature, T, and the number of moles it contains, n, in the sample. The equivalent statement is: For these issues, we'll use the ratio of two temperatures. Because the ratio of starting to end volume and pressure will be the same regardless of the units used to express them, the volume and pressure can be expressed in any form. exhibited in (as long as the initial and final of each are expressed in the same units).PV= nRT
However, for this method to work properly, the temperature must be stated in Kelvin. This is true because Kelvin's zero point is absolute zero. Theoretically, molecules are entirely immobile at 0 Kelvin.
T = PV/nR
The ideal gas law equivalency is used to compute the final temperature in the next two issues.
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(a) A Carnot engine working in a forward direction (i.e. taking heat from a hot body and rejecting remaining heat after work to a cold body) is a heat engine. Therefore the engine to be used as a heat engine operates in a direction. as it is in contact with the heat reservoir during this segment; and, as its is in contact with cold sink.
A heat engine, symbolized by a circle in this illustration, uses some of the heat transfer to produce work.
The most effective heat engine that is theoretically possible—i.e., any machine that can transform thermal energy (heating) into mechanical energy—is the Carnot engine (work).The heat and cold reservoirs are the names given to the hot and cold items. Only the hot temperatures' absolute values affect efficiency. A portion of the heat QH that is extracted from the high-temperature source TH in the case of a heat engine is transformed into work. The ratio of net work completed to heat absorbed throughout one full cycle is known as a heat engine's thermal efficiency.
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A mass m is suspended by a massless string forming a simple pendulum of length 2.0 m. The string of the pendulum is initially at an angle of 60° with the vertically downward direction when the mass is released from rest.
The centripetal acceleration of the mass m when it is at the lowest position is 10 m/s². The correct option is A.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any object moving in a circle with an acceleration vector pointing in the direction of the circle's center.
A projectile is an object that is launched into the air and then moves only in response to the acceleration of gravity. The trajectory of the object is referred to as the projectile's trajectory.
The equation of projectile motion is:
[tex]V = \sqrt{2gh}\\\\\\V = \sqrt{2 \times 10 \times \dfrac{1}{2} } \\\\V = \sqrt{20}[/tex]
a² = v² / l = 20 / 2 = 10 m/s²
Therefore, the correct option is A, 10 m/s².
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The question is incomplete. Your most probably complete question is given below:
The centripetal acceleration of the mass m when it is at the lowest position is:
10 m/s²
5 m/s²
20 m/s²
25 m/s²
All the following statements are true. Which one makes it possible to learn of the existence of extrasolar planets without seeing the planets themselves?Planets exert gravitational tugs on their stars that cause stars to orbit around the center of mass of their planetary systems.
Planets exert gravitational tugs on their stars that cause stars to orbit around the center of mass of their planetary systems. is true
What does the term "extrasolar planet" mean?Extrasolar planets, often known as exoplanets, are any planetary bodies outside of the solar system that typically circle stars other than the Sun.A planet beyond the Solar System is referred to as an exoplanet or extrasolar planet. In 1917, the first potential sign of an exoplanet was observed, but it was not taken seriously. In 1992, the first detection confirmation took place. 1988 saw the discovery of a different planet, which was verified in 2003. Telescopes have photographed a small number of exoplanets directly, but the great majority have been discovered via indirect techniques like the transit method and the radial-velocity approach. There are 5,284 confirmed exoplanets in 3,899 planetary systems as of December 1, 2022.The complete questio is Which one makes it possible to learn of the existence of extrasolar planets without seeing the planets themselves?
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What is the internal energy of 4moles of oxygen molecules at 25degree
The internal energy of n moles of a gas is u= 1/2nFRT
where F = number of degrees of freedom.
The internal energy of 4 moles of oxygen at temperature T is =
u = 1/2 × 4 × 5RT = 10RT (F=5 for oxygen molecule)
T (temperature) given = 25 degree
u = 10 * R * 25 = 250 R
R = 8.314
Thus, total internal energy = 250 * 8.314 = 2078.5 Joules
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supply drop design proposal
What is the Force of Gravity acting on the object in the diagram?
The force of gravity acting on the 23 Kg object in the diagram is 225.4 N
How do I determine the force of gravity?The force of gravity is defined as follow:
Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Using the above formula, we can easily obtain the force gravity acting on the 23 Kg object. This is shown below:
Mass (m) = 23 KilogramsAcceleration due to gravity (g) = 9.8 m/s²Force of gravity (F) =?Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Force of gravity = 23 Kg × 9.8 m/s²
Force of gravity = 225.4 N
Thus, from the calculation made above, we can conclude that the gravitaional force is 225.4 N
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compare the time it takes for light to travel 1000 m on the surface of the earth and in outer space.
Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.
Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.
The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.
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