An airline charges the following baggage fees: $20 for the first bag and $40 for the second. Suppose 54% of passengers have no checked luggage, 25% have only one piece of checked luggage and 21% have two pieces. We suppose a negligible portion of people check more than two bags.
a) The average baggage-related revenue per passenger is: $___.
b) The standard deviation of baggage-related revenue is: $____.
c) About how much revenue should the airline expect for a flight of 120 passengers?

Answer:

You have to follow PEMDAS or parenthesis, exponents, multiplication, division, addition, and subtraction. It's an order to solve equations. I listed the steps and the answers for you below :) I have throughly checked them so they should be correct! yw :D

Step-by-step explanation:

1. 5x + 4x - 6x = 24

9x - 6x = 24

3x = 24

24/3 = 8

x = 8

2. 8y + 5 - 4y + 1 = 46

8y - 4y = 4y

5 + 1 = 6

4y + 6 = 46

4y = 46 - 6

4y = 40

40/4 = 10

y = 10

3. 33 = 5 ( x + 8 ) + 3

33 =  5x + 40 + 3 (because we distributed)

33 = 5x + 43

5x + 43 = 33 (just rewriting it to make it easier)

5x = 33 - 43

5x = -10

-10/5 = -2

so x = - 2

4. 2m + 3 ( m - 8 ) = 1

2m + 3m - 24 = 1

we got 3m - 24 because we distributed the 3

5m - 24 = 1

5m = 25

25/5 = 5

m = 5

5. p + p - 2p + 4p = - 48

2p - 2p + 4p = - 48

4p = - 48

- 48 / 4 = - 12

p = - 12

6. 2 ( y + 5 ) + 3y = 25

2y + 10 + 3y = 25

5y + 10 = 25

5y = 25 - 10

5y = 15

15/5 = 3

y = 3

7. 1/4 h + 3/4 h + 1/2 h + 2 = 5

1/4 h + 3/4 h + 1/2 = 3/2 h

3/2 h + 2 = 5

3/2 h = 5 - 2

3/2 h = 3

h = 2

8. 60 = 4 ( k + 3 ) + 2 ( k - 3 )

60 = 4k + 12 + 2k - 6

4k + 12 + 2k - 6 = 60

6k + 6 = 60

6k = 60 - 6

6k = 54

k = 9

9. - 2 ( d + 1.4 ) - 1.8 = 20.6

-2d + - 2.8 - 1.8 = 20.6

-2d - 2.8 = 22.4

-2d = 25.2

d = - 12.6

10. 8 - 2 ( w + 4 ) = 10

8 + - 2 w + - 8 = 10

-2w + 9 + - 8 = 10

-2w = 10

10 / -2 = -5

w = -5

Step-by-step explanation:

[tex]{ \bf{( \frac{ - 10 {a}^{3} {b}^{5} \times 6 {a}^{6} {b}^{2} }{ {12a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{( \frac{ - 60 {a}^{9} {b}^{7} }{12 {a}^{9} {b}^{5} } ) {}^{3} }} \\ \\ = { \sf{(5 {b}^{2}) {}^{3} }} \\ = { \sf{125 {b}^{5} }}[/tex]

Answer:

Differentiation is concerned with things like speeds and accelerations, slopes and curves ect. These are Rates of Change, they are things that are defined locally. The Fundamental Theorem of Calculus is that Integration and Differentiation are the inverse of each other.

Answer:

By the Sum Rule, the derivative of 1−sin(x) 1 - sin ( x ) with respect to x x is ddx[1]+ddx[−sin(x)] d d x [ 1 ] + d d x [ - sin ( x ) ] .

Answer:

A. [tex]\frac{5}{13}[/tex]

Step-by-step explanation:

Hi there!

We are given right triangle PQR, with PR=5, RQ=12, and PQ=13

We want to find the value of sin(Q)

Let's first recall that sine is [tex]\frac{opposite}{hypotenuse}[/tex]

In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse

So that means that sin(Q) would be [tex]\frac{PR}{PQ}[/tex]

Substituting the values of PR and PQ gives sin(Q) as [tex]\frac{5}{13}[/tex], which is A

Hope this helps!

The distance between each of the students' houses are:

Aakash & Bao Ying live 9 blocks away from each other

Aakash & Chris live 3 blocks away from each other

Aakash & Donna live 66 blocks away from each other

Bao Ying & Chris live 6 blocks away from each other

Bao Ying & Donna live 57 blocks away from each other

Chris & Donna live 63 blocks away from each other

To solve this question, we represent each with the first letter of their names.

So, we have:

[tex]A= 5\ west[/tex] --- Aakash

[tex]B= 4\ east[/tex] ---- Bao Ying

[tex]C = 2\ west[/tex] --- Chris

[tex]D = 61\ east[/tex] ---- Donna

I've added the picture and the number line that represent the scenario as an attachment.

To calculate how far each lives from each other's, we start by representing west as negative and east as positive.

So, the representations become:

[tex]A = -5[/tex]

[tex]B = 4[/tex]

[tex]C = -2[/tex]

[tex]D = 61[/tex]

The absolute difference of each represents how far they live from one another.

Aakash & Bao Ying         Aakash & Chris                 Aakash & Donna

[tex]AB = |-5 -4| =9[/tex]          [tex]AC = |-5 --2| =3[/tex]         [tex]AD = |-5 -61| =66[/tex]

Bao Ying & Chris                 Bao Ying & Donna

[tex]BC = |4 --2| =6[/tex]                [tex]BD = |4 -61| =57[/tex]

Chris & Donna

[tex]CD = |-2 -61| =63[/tex]

This means that

Aakash & Bao Ying live 9 blocks away from each other

Aakash & Chris live 3 blocks away from each other

Aakash & Donna live 66 blocks away from each other

Bao Ying & Chris live 6 blocks away from each other

Bao Ying & Donna live 57 blocks away from each other

Chris & Donna live 63 blocks away from each other

To carry out the above computations from the number line, we simply count the numbers from one to the other.

For instance:

There are 3 numbers from Akash to Chris.

This means that: Aakash & Chris live 3 blocks away from each other

Learn more about number line at:

https://brainly.com/question/13189025

9514 1404 393

Answer:

  38.1% decrease

Step-by-step explanation:

A percentage change is found from ...

  % change = (change)/(original amount) × 100%

  = (new value - original amount)/(original amount) × 100%

  = (13 -21)/21 × 100% = -8/21 × 100% ≈ -38.1%

Frazer's speed decreased by 38.1% during the second part.

_____

Additional comment

A negative % change represents a decrease; a positive % change represents an increase.

Answer:

The 95% confidence interval for the mean of mid-upper arm circumference based on your sample is between 139.29 mm and 160.71 mm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 4 - 1 = 3

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 3.1824

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 3.1824\frac{6.73}{\sqrt{4}} = 10.71[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 150 - 10.71 = 139.29 mm

The upper end of the interval is the sample mean added to M. So it is 150 + 10.71 = 160.71 mm

The 95% confidence interval for the mean of mid-upper arm circumference based on your sample is between 139.29 mm and 160.71 mm.

Answer: About 63 in²

Step-by-step explanation:

Area of circle = π · r²

Area of large pizza:

[tex]\pi *r^{2} =3.14*6^{2} =3.14*36=113.04[/tex]

Area of small pizza:

[tex]\pi *r^{2} =3.14*4^{2} =3.14*16=50.24[/tex]

Difference in area:

[tex]113.04-50.24=62.8[/tex]

Answer:

You’ve worked 7 hours and 30 minutes

Step-by-step explanation:

Answer:

3.2 hours

Step-by-step explanation:

12 workers * 4 hours = 48 worker hours

15 workers  * x hours = 48 worker hours

48 /15 =3.2 hours

Answer:

3 hours and 12 minutes.

Step-by-step explanation:

12 Workers complete a job in 4 hours

1 worker complete a job 12 × 4 = 48

15 workers complete a job = 48/15 = 3³/¹⁵ = 3¹/⁵

= 3 hours + 1/5 × 60  minutes = 3 hours 12 minutes.

G(x)=5x+3

[tex]\\ \sf\longmapsto G(2)[/tex]

[tex]\\ \sf\longmapsto 5(2)+3[/tex]

[tex]\\ \sf\longmapsto 10+3[/tex]

[tex]\\ \sf\longmapsto 13[/tex]

Option c is correct

Answer: 4,989,600 different ways

Step-by-step explanation:

Answer:

39/250

Step-by-step explanation:

15 3/5 = 78/5 and percent means per 100, so

(78/5)/100 = (78/5)(1/100)

=78/500 = 39/250

Answer:

The student took the numbers for the factors 5, -4 for the zeros  instead of solving the equation

The zeros are -5, 4

Step-by-step explanation:

x^2 +x - 20=0

What 2 number multiply to -20 and add to 1

5*-4 = -20

5+-4 = 1

(x+5)(x-4) =0

Using the zero product property

x+5 = 0  x-4 =0

x=-5  x=4

Answer:

Solution given:

equation is:

x²+x-20=0

doing middle term factorisation

note:we need to get 1 while subtracting factor of the product of constant and coefficient of x².

20*1=20=2*5*2*1

we get 1 while subtracting 5-2*2=5-4

now substitute value 5-4 at coefficient of x

we get

x²+(5-4)x-20=0

now

distribute

x²+5x-4x-20=0

taking common from each two term

x(x+5)-4(x+5)=0

again taking common (x+5) and keeping remaining at another bracket

(x+5)(x-4)=0

either

x+5=0

x=-5

or

x-4=0

x=4

Error is:

x= 4 not -4

x=-5 not 5.

9514 1404 393

Answer:

Step-by-step explanation:

The result each should have obtained is ...

  a +10 = 17

  a = 7

Braulio's mistake was in using 1 as his divisor instead of -1. His bottom row should have been 1, 4, a-4, 1-a, a +10.

Zahra's mistake was improperly evaluating higher powers of -1. Her evaluation should have been 1 -5 +a +3 +11 = a +10.

Answer:

The answer is 1,000

SInce the beginning number is 3 and there are ten possible numbers to put in the remaining three slots, there are exactly 1,000 possible combinations for a 3-digit code. The answer is 1,000. There are 3 rows of 10 digits. The number of combinations 10 to the thid power which is 1000 (10 * 10 * 10)

Answer:

C

Step-by-step explanation:

one line is

y = 3x/7 + 11

its slope is 3/7

the y-intercept is, of course, when x=0. there y=11

the other is

-3x + 7y = 13

7y = 3x + 13

y = 3x/7 + 13/7

its slope is 3/7 (the same as the other line)

the y-intercept (x=0) is y = 13/7 (different to the other line)

Answer:

C. Yes, since the slopes are the same and the y-intercepts are different.

Step-by-step explanation:

[tex]y=\frac{3}{7} x+11[/tex]  and [tex]-3x+7y=13[/tex]

→ Rearrange the second equation to make y the subject

7y = 3x + 13

→ Divide everything by 7

[tex]y=\frac{3}{7} x+\frac{13}{7}[/tex]

Answer:

how did not orderstan that

Answer:

[tex]{ \sf{ \underline{ {x}^{2} + 5x - 6 }}}[/tex]

Step-by-step explanation:

[tex](x + 6)(x - 1) \\ = {x}^{2} - x + 6x - 6 \\ = {x}^{2} + 5x - 6[/tex]

Answer:

y = 48x + 36

Step-by-step explanation:

m = 48

y = 48x +36

Answer:

2x^5-10x^4-8x^3

Step-by-step explanation:

2x^3 ( x^2 - 5x-4)

Distribute

2x^3 * x^2  - 2x^3 -5x  -2x^3 *4

2 x^(3+2) - 10 x^(3+1) - 8x^3

2x^5-10x^4-8x^3

Answer:

Step-by-step explanation:

Answer:

y =6

Step-by-step explanation:

We can write a ratio to solve

3           y

----- = ----------

4            8

Using cross products

3*8 = 4y

24 = 4y

Divide by 4

24/4 = 4y/4

6 = y

let the line between 2 tria be y

sin 60/8√2 = sin 90/y

y=13.06

sin 45/13.06 = sin 90/x

x=18.46

Answer:

First, find the hypotenuse of the right triangle with the 60° & 30°.

[tex]sin(60) = \frac{8\sqrt{2}}{h} \\\\sin(60)h=8\sqrt{2}\\\\\frac{\sqrt{3}}{2} h=8\sqrt{2}\\\\h=\frac{8\sqrt{2}}{\frac{\sqrt{3}}{2}}=8\sqrt{2}*\frac{2}{\sqrt{3}} =\frac{16\sqrt{2} }{\sqrt{3}} =\frac{16\sqrt{2}(\sqrt{3}) }{\sqrt{3}(\sqrt{3})} =\frac{16\sqrt{6} }{3}[/tex]

Use that side length to find x.

[tex]sin(45)=\frac{\frac{16\sqrt{6}}{3}}{x}\\\\sin(45)x=\frac{16\sqrt{6}}{3} \\\\\frac{\sqrt{2}}{2}x=\frac{16\sqrt{6}}{3} \\\\x=\frac{\frac{16\sqrt{6}}{3}}{\frac{\sqrt{2}}{2}}=\frac{16\sqrt{6}}{3}*\frac{2}{\sqrt{2}}=\frac{16\sqrt{2}\sqrt{3}(2)}{3\sqrt{2} }=\frac{32\sqrt{3} }{3}[/tex]

Answer:

z -2 = 10

Step-by-step explanation:

11z-9-10z+7 = 10

Combine like terms on the left side

11z -10z     -9+7  =10

z -2 = 10

Answer: z=12

Step-by-step explanation:

[tex]11z-9-10z+7=10\\z-9+7=10\\z-2=10\\z=12[/tex]