amanda weighs about 600 n on earth, but would only weigh about 100 n on the moon. which best explains why amanda would weigh less on the moon than on earth? A. the mass of the moon is less than that of earth, therefore it has a weaker gravitational force. B. the circumference of the moon is smaller than earth, therefore it has less gravity. C. the pull from the gravity from earth decreases the pull of gravity from the moon. D. the lack of air pressure on the moon weakens the gravitational force of the moon.

Answer:

Explanation:

The energy conservation is equal to half of the product of the spring constant and the square of displacement of the spring, so option C is correct.

The correct option is A, the amplitude and period of the oscillations that result from this collision are 0.300 m in 1.26s.

The expression for Period of spring is,

[tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]

Here, m is the mass of the spring and k is the spring constant

Substitute 2 kg

for m

and 100N/m

for k

in equation [tex]T = 2\pi\sqrt{\frac{2m}{k} }[/tex]

and solve for T .

[tex]T = 2\pi\sqrt{\frac{(2)2 kg}{100 N/m} }[/tex]

T = 1.26s

In physics, amplitude refers to the maximum displacement or distance moved by a wave from its equilibrium or mean position. It is a measure of the intensity or strength of a wave, and it is usually represented as the height of the crest or depth of the trough of the wave.

The amplitude of a wave can be measured in various units, depending on the type of wave and the context in which it is being studied. For example, the amplitude of a sound wave is measured in decibels (dB), while the amplitude of an electromagnetic wave is measured in volts per meter (V/m). Amplitude plays an important role in the behavior of waves. It determines the energy carried by the wave and affects other properties such as frequency, wavelength, and phase.

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Complete Question: -

A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2.00-kg object traveling along the x-axis at 3.00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision

A) 0.300 m, 1.26 s

B) 0.300 m, 0.889 s

C) 0.424 m, 0.889 s

D) 0.424 m, 1.26 s

E) 0.424 m, 5.00 s

The angular acceleration of the fan is 0.740 rad/s^2,

Angular acceleration which represents the rate at which the angular velocity changes over time. The unit used to measure angular acceleration is radians per square second (rad/s2), according to the International System of Units. The Greek alphabet symbol alpha (α) is used to denote angular acceleration.

To calculate the angular acceleration of the fan, the formula α = Δω/Δt is used. Here, α represents angular acceleration, Δω represents the change in angular speed, and Δt represents the change in time.

In this scenario, Δω is equal to 10.0 - 6.30 = 3.70 rad/s, and Δt is equal to 5.00 s. By substituting these values into the formula, we obtain α = 3.70/5.00 = 0.740 rad/s^2.

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Isometric pushes against a wall made of concrete, Isotonic running up a hill. isotonic freestyle swimming, bicycle pedalling on a level surface: isotonic.

Static muscle contractions, in which the length of the muscle does not change during the workout, are called isometric exercises. This indicates that during the activity, there is no discernible movement or alteration in joint angle. Instead, the muscles are tense against a constant force or maintained still for a certain period of time. Exercises that are isometric include pushing against a wall, keeping a plank position, and tightening a hand grasp. Exercises that are isometric can help to increase joint stability and balance as well as muscular strength and endurance. They can also be incorporated into normal workout routines for general health and strength training. They are frequently used in physical therapy to aid patients in recovering from injuries or surgery.

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The angle measured from the horizontal is where we can be sure that we never detect an electron is 0.0485 rad.

The correct answer is C.

To find the angle at which we can be sure to never detect an electron, we will use the equation:

θ = λ/d

Where:

θ = angle at which we can be sure to never detect an electron

λ = de Broglie wavelength of the electron = h/p

where h = Planck's constant and p = momentum of electron (m*v)

We know that the velocity of the electron is 15.0 m/s. To find the momentum, we can use the mass of an electron (9.11 x 10⁻³¹ kg).

p = m*v = (9.11 x 10⁻³¹ kg) * (15.0 m/s)

p = 1.37 x 10⁻²⁹ kg m/s

Now we can find the de Broglie wavelength:

λ = h/p

λ = (6.626 x 10⁻³⁴ J s) / (1.37 x 10⁻²⁹ kg m/s)

λ = 4.83 x 10⁻⁵ m

Now we can substitute this into the equation for θ:

θ = λ/d

θ = (4.83 x 10⁻⁵ m)/(0.500 x 10⁻³ m)

θ = 0.0966 rad

However, this is the angle at which we would see destructive interference. To be sure we never detect an electron, we want the angle to be half of this, or:

θ = 0.0966/2

θ = 0.0483 rad, which rounds to 0.0485 rad (to 3 significant figures).

Therefore, the correct answer is (c) 0.0485 rad.

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Answer: The motion of a body with constant speed in a circular path is said to be accelerated, because it is moving with uniform speed, but not with uniform velocity, as velocity is a vector quantity, it can be represented in magnitude as well the direction.

Explanation:

Of the three states of matter (solid, liquid, and gas), gas has the most kinetic energy. This is because the particles in a gas have the highest average speed compared to the particles in solids and liquids.

In a gas, the particles are in constant motion, colliding with each other and the walls of the container. This motion generates kinetic energy, which is proportional to the speed and mass of the particles. In contrast, solids have the lowest kinetic energy because their particles are tightly packed and have limited movement. The particles in a solid vibrate around a fixed position, and only experience small oscillations. Liquids have an intermediate amount of kinetic energy. The particles in a liquid are less tightly packed than in a solid, and can move more freely, resulting in more kinetic energy. However, liquids have more intermolecular forces between the particles compared to gases, which restricts their movement and reduces their average speed. Therefore, of the three states of matter, gases have the most kinetic energy, followed by liquids and then solids.

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Answer:B

Explanation:The ray above makes a 90 degree angle. The ray below makes a 60 degree angle.

The gauge pressure that a pump must produce to pump the water from the bottom of Grand Canyon to Indian Gardens is about 627080 pascals and 6.17 atm.

The difference in elevation of the two points = 1370 - 730 = 640m

Density of water, `ρ` = 1000 kg/m³

g = 9.8 m/s²

The gauge pressure must a pump produce to pump water from the bottom of Grand Canyon (elevation 730 m) to Indian Gardens (elevation 1370 m).

Formula used: `P = ρgh`

where, `P` is pressure, `ρ` is density of water, `g` is acceleration due to gravity, `h` is height difference between the two points.

The gauge pressure that must a pump produce to pump water from the bottom of Grand Canyon to Indian Gardens is 627080 Pa and 6.17 atm.

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The speed of the car at b if the normal force between the road and the tires at b is twice that at a is about 44.1 km/h.

Speed of the car at A = 50 km/h

Radius of curvature at A = 70 m

Radius of curvature at B = 70 m

Normal force between the road and the tires at B = 2 × Normal force between the road and the tires at A= 2N

Mass center of the car = 1.2 m

The speed of car at B be v km/h

From the conservation of energy at the point A and B, we get:

1/2 mv² + mgh = 1/2 m(50)² + mg(70 - r)

1/2 mv² + mg(70 + r) = 1/2 m(50²)

1/2 mv² = 1/2 m50² - mg(70 + r) …… equation (1)

From the conservation of energy at point B, we get:

1/2 mv² + mg(2r + 1.2) = 1/2 m(50)² + mg(70 - r)

2× Normal force between the road and the tires at A = Normal force between the road and the tires at B

Normal force between the road and the tires at B = 2 × Normal force between the road and the tires at A

Therefore, mg - 2 × N = mv²/rmg - N = mv²/2r

2mg - 4N = mv²/rmg - 2N = mv²/2r

Subtracting, we get:

N = mg/3

Normal force between the road and the tires at A = mg/3

Normal force between the road and the tires at B = 2mg/3

Normal force between the road and the tires at B = 2(mg/3) = mg/3

From the above equations, we get the value of v. Putting the values, we get:

1/2 mv² = 1/2 m(50)² - mg(70 + r) - mg(2r + 1.2) + mg(70 - r)1/2 v² = 1/2(50)² - g(70 + r) - g(2r + 1.2) + g(70 - r)v = 44.1 km/h

Therefore, the speed of the car at B is 44.1 km/h.

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The wavelength of the radio waves is approximately 0.579 m or 57.9 cm

Wavelength is the distance covered by an electromagnetic wave while propagating through space. The relationship between the wavelength and the frequency of an electromagnetic wave is given by the formula;

Wavelength = speed of light / frequency = c / f

where c is the speed of light and f is the frequency of the wave.

To calculate the wavelength of a VHF television station assigned to channel 22 that transmits its signal using radio waves with a frequency of 518 MHz, we substitute the known values into the equation above.

Wavelength = c / f = (3 x 10⁸ m/s) / (518 x 10⁶ Hz) = 0.579 m or 57.9 cm (rounded to three significant digits)

Therefore, the wavelength of the radio waves transmitted by the VHF television station assigned to channel 22 is 0.579 m or 57.9 cm (rounded to three significant digits).

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Force will become  2.25 x 10^N. because, According to Coulomb's Law, the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Thus, if the distance between two point charges is doubled, the force between them will decrease by a factor of 4. This is because the inverse square relationship means that the force decreases rapidly with distance. Therefore, if the force between two point charges is 9 x 10^N when they are 1 meter apart, when the distance is doubled to 2 meters, the force will become 9 x 10^N / 4 = 2.25 x 10^N.

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The maximum gain of an amplifier that produces an output voltage amplitude of 50 Vpp with an input voltage amplitude of 200 mVpp is 25. The formula to calculate gain is output voltage amplitude divided by input voltage amplitude.

In this case, we are given an input voltage of 200 mVpp, so the maximum gain of this amplifier can be calculated as follows:

Gain = Output Voltage/Input Voltage = Output Voltage/200 mVpp

Therefore, the maximum gain of this amplifier is equal to the output voltage. In other words, the maximum gain of this amplifier is equal to the voltage output of the amplifier.

To calculate the output voltage of the amplifier, we need to know the supply voltage and the resistance of the load. Assuming the supply voltage is 5V and the load resistance is 10k ohms, the output voltage can be calculated as follows:

Output Voltage = Supply Voltage * Load Resistance / (Load Resistance + Output Resistance) = 5V * 10k ohms / (10k ohms + 10k ohms) = 5V

Therefore, the maximum gain of this amplifier is 5V/200 mVpp = 25.

To summarize, the maximum gain of this amplifier is 25, calculated by dividing the output voltage by the input voltage. The output voltage can be calculated by knowing the supply voltage and load resistance.

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The geocentric model says that the earth is at the center of the cosmos or universe, and the planets, the sun and the moon, and the stars circles around it. The early heliocentric models consider the sun as the center, and the planets revolve around the sun.

Answer:

Explanation:

Using Kirchhoff's laws, we can solve for the current i:

At the node where the 2Ω and 4Ω resistors meet, the current is split into two branches, i and i1. Applying Kirchhoff's current law (KCL), we have:

i + i1 = 12/2 = 6 A

At the loop with the 2Ω, 4Ω, and 5Ω resistors, applying Kirchhoff's voltage law (KVL), we have:

-20 + 2i + 4i1 + 5i1 = 0

-20 + 6i1 + 2i = 0

6i1 + 2i = 20

3i1 + i = 10

We can solve this system of equations by substitution, which gives:

i = 2 A

Therefore, the current through the 2Ω resistor is 2 A. The answer is (A) 2 A.

In this case, the normal force exerted by the table on the book is the action force and the reaction force is the force that the book exerts on the table. This force is equal in magnitude to the normal force and acts in the opposite direction.

Newton's third law states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on another object, the second object exerts a force back on the first object that is equal in magnitude and opposite in direction.

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The maximum energy of photoelectrons from aluminium is 2.3 eV for radiation of 2000 Å and 0.90 eV for radiation of 3130 Å.

To calculate Planck's constant and the work function of aluminium, we need to use the equation:

 h = E2 - E1/ λ2 - λ1

Where h is Planck's constant, E1 and E2 are the maximum energy of photoelectrons for each wavelength, and λ1 and λ2 are the wavelengths.

Using the given data, we have:

h = (2.3 - 0.90) / (2000 - 3130)

Therefore, h = -1.4 eV / -930 Å, which simplifies to h = 0.0015 eVÅ.

The work function of aluminium is equal to the maximum energy of the photoelectrons for the longest wavelength, in this case, 0.90 eV. Therefore, the work function of aluminium is 0.90 eV.

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Ceteris paribus, a decrease in capital productivity is the event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. The correct answer is option C.

Ceteris paribus is a Latin expression that means "all other things being equal." Ceteris paribus is a model in which economists use to analyze the effect of one independent variable on a dependent variable while keeping all other independent variables constant. This implies that only one variable is allowed to change while all other variables are held constant at their current level or position.

Therefore, Ceteris paribus, an increase in investor confidence, an increase in cosmetic income and wealth, and a strength of time preference will not cause both the equilibrium interest rate and the equilibrium quantity of investment to fall. However, a decrease in capital productivity is an event that would cause both the equilibrium interest rate and the equilibrium quantity of investment to fall.

When capital productivity is low, firms are unable to produce goods and services efficiently, and as a result, the demand for investment falls. When the demand for investment falls, the equilibrium quantity of investment will also decrease, leading to a decrease in the equilibrium interest rate.

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Unproven theories ultimately cannot be regarded as scientific facts or principles and are not generally recognised by the scientific community.

A well-supported explanation of a natural occurrence in science that has passed rigorous examination and is backed by empirical data is referred to as a theory. A hypothesis, however, cannot be regarded as a scientific fact or principle if it is not backed up by empirical data or if it has not undergone extensive testing and verification. The scientific community frequently rejects unproven notions with scant empirical backing and may even label them as pseudoscientific or non-scientific. This is so that scientific theories and findings may be evaluated and verified frequently. Science does this by using evidence-based reasoning and critical thinking. Unproven theories are therefore eventually not regarded as being a part of the corpus of scientific knowledge.

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The Periodic Table of Elements served as the inspiration for this scavenger hunt. The exercise consists of two sets of questions, each of which has 28 questions that must be answered using the Periodic Table.

Students are tasked with identifying elements in the first set of questions using information from their attributes, such as the element's position on the periodic table, atomic mass, or quantity of electrons, protons, or neutrons. The objectives of the questions are to familiarise students with the properties of various elements and the structure of the Periodic Table. The second series of questions is comparable to the first, but more difficult because it asks students to identify components using less obvious cues, like their chemical symbol or a chemical formula. In order to succeed in their future studies of chemistry and other related sciences, students will benefit from being more familiar with the structure of the periodic table and the characteristics of various elements.

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In the case where the car is traveling in the -x direction and decreasing in speed, it has a negative velocity and a positive acceleration. Therefore, option D is the correct answer. In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration.

Let's discuss the given options one by one:

(A) In this case, the car is traveling in the -x direction at a constant speed. Therefore, it has a negative velocity and zero acceleration. This option is incorrect.

(B) In this case, the car is traveling in the - direction and increasing its speed. Therefore, it has a negative velocity and a positive acceleration. However, the given direction is not specified, and thus this option is not accurate.

(C) In this case, the car is traveling in the +x direction and increasing in speed. Therefore, it has a positive velocity and a positive acceleration. This option is incorrect.

(D) In this case, the car is traveling in the - direction and decreasing in speed. Therefore, it has a negative velocity and a positive acceleration. This option is correct.

(E) In this case, the car is traveling in the +x direction and decreasing in speed. Therefore, it has a positive velocity and a negative acceleration. This option is incorrect.

Therefore, Option D ( - direction decreasing in speed) is correct.

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Answer:

The four planets were approximately aligned on one side of the Sun and we used the gravity of each planet to speed up the spacecraft to get to the next one in its path

Explanation:

All the Options 1, 2, 3, 4  are true about the Voyager 2 spacecraft to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's.

The Voyager 2 spacecraft was able to make a "tour" of all four of the jovian planets in the late 1970's and the 1980's due to the following:

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The battery has to supply more power when two resistors are connected in series than when only one resistor is connected. This is because the power dissipated in a series circuit is equal to the sum of the power dissipated in each resistor.

When two identical resistors are connected in series to a battery, the battery has to supply more power than when only one of the resistors is connected. This is because the resistors offer resistance, which results in the dissipation of energy as heat. The higher the resistance of a resistor, the more power it requires to operate.Resistors consume energy as they offer resistance to the flow of current. The power supplied by the battery is converted to heat energy in the resistor, and the amount of heat energy dissipated is determined by the resistance of the resistor. The greater the resistance of the resistor, the more power it requires to function.

As a result, when two identical resistors are connected in series to a battery, the battery has to supply more power than when only one of the resistors is connected, to produce the same current through the circuit. Therefore, if two resistors of equal value are connected in series, the total power dissipated is twice that of when a single resistor is connected.

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When a light bulb used in a slide projector draws a current of 6 amperes while operating on 120 volts, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb in ohms is 20. Thus, the correct option is B.

When we know that the current drawn by a light bulb is 6 amperes and the voltage applied to it is 120 volts, we can easily calculate the resistance of the light bulb, as follows:

Resistance (R) = Voltage (V) / Current (I)

here, V = 120V and I = 6A

Therefore, the resistance of the light bulb is:

R = V/I = 120/6 = 20 Ohms

The formula used to calculate the power (P) consumed by a light bulb is:

P = V × I

Here, the voltage (V) applied to the light bulb is 120 volts and the current (I) drawn by the light bulb is 6 amperes. So, the power consumed by the light bulb is:

P = 120 × 6 = 720 watts

Hence, the power consumed by the light bulb in watts is 720, and the resistance of the light bulb is 20 ohms.

Therefore, the correct option is B.

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The translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.

We can use conservation of energy to solve this problem. The initial energy of the cylinder is all potential energy, and the final energy is all kinetic energy. The potential energy at the bottom of the incline is zero.

The potential energy of the cylinder at the top of the incline is given by:

PE = mgh

where m is the mass of the cylinder, g is the acceleration due to gravity, and h is the height of the incline. Substituting the given values, we get:

PE = (mass of cylinder) x (acceleration due to gravity) x (height of incline) = mgh

The kinetic energy of the cylinder at the bottom of the incline is given by:

KE = (1/2)mv^2

where v is the translational speed of the cylinder at the bottom of the incline.

According to the conservation of energy, the initial potential energy is equal to the final kinetic energy, so we can set these two expressions equal to each other:

mgh = (1/2)mv^2

We can cancel the mass of the cylinder from both sides, and solve for v:

v = sqrt(2gh)

Substituting the given values, we get:

v = sqrt(2 x 9.81 m/s^2 x 7.20 m) ≈ 9.43 m/s

Therefore, the translational speed of the cylinder when it reaches the foot of the incline is approximately 9.43 m/s.

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The final expression for the charge Q(t) at any time t is given as:Q(t) = CV(t) = 2.5 × 10^-11 e- t/RC

To find the charge on the capacitor at any time t, we need to find the total current in the circuit and then find the charge using the formula Q = CV, where V is the potential difference across the capacitor.Let's find the total current in the circuit using the formula:

I = (1/LC)½ x (e- Rt/2L) sin(wt - φ)

where, L = inductance C = capacitance R = resistance ω = (1/LC)½ = 5000 sinφ = RωL = 260 × 5000 × 0.2 = 2600

Let's now substitute the given values into the formula and simplify:I = (1/(0.2 × 1.25 × 10^-5))½ x (e- 260t/2 × 0.2) sin(5000t - φ)I = 10^5 x (e- 130t) sin(5000t - φ). Let's now find the charge Q on the capacitor using the formula:

Q = CV where, C = capacitance V = potential difference across the capacitor. To find the potential difference across the capacitor, we need to find the current passing through it, which is given as the total current minus the current passing through the inductor. Let's find the current passing through the inductor using the formula:

I L = I x sin(wt - φ)IL = I x sin(5000t - φ).The potential difference across the capacitor can be calculated using the formula:V C = V 0 × e- t/RC where, V0 = initial potential difference across the capacitor R = resistance of the circuit C = capacitance of the circuit. Let's now find the current passing through the capacitor:I C = (I - I L)I C = I - I L

Now we have all the necessary formulas to find the charge Q(t) at any time t. Let's substitute the given values into the formulas and simplify:

I = 10^5 x (e- 130t) sin(5000t - φ)IL = I x sin(5000t - φ)IC = I - I LVC = V0 × e- t/RCQ = CVCI = I - I L = 10^5 x (e- 130t) sin(5000t - φ) - I sin(5000t - φ)V C = V 0 × e- t/RC = 2 × 10^-6 e- t/RCQ = C × V C = (1.25 × 10^-5) × (2 × 10^-6) e- t/RC = 2.5 × 10^-11 e- t/RC

Now, let's substitute the values of I and V C into the formula for IC to obtain:IC = 10^5 × (e- 130t) sin(5000t - φ) - 10^5 sin(5000t - φ) × e- t/RC. Therefore final expression for the charge Q(t) at any time t is given as:Q(t) = CV(t) = 2.5 × 10^-11 e- t/RC

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We can use the equation [tex]q(t) = C.V(t)[/tex] to calculate the charge q (t) on the capacitor at any time t: [tex]q(t) = 1,25 . 10-5 Farad.V(t)[/tex].

The charge on a capacitor in a series circuit at any time t is given by the equation [tex]q(t) = C.V(t)[/tex], where C is the capacitance of the capacitor and V(t) is the voltage across the capacitor at time t.

In the given circuit, the capacitance of the capacitor is 1.25 x 10-5 Farad, and the initial charge on the capacitor is 2 x 10-6 Coulomb. Therefore, to find the charge q(t) on the capacitor at any time t, we need to find the voltage V(t) across the capacitor at time t.

To do this, we must first calculate the total inductance and resistance in the circuit. The total inductance is the sum of the inductances of each inductor, so the total inductance in this circuit is 0.2 Henry. The total resistance is the sum of the resistances of each resistor, so the total resistance in this circuit is 260 Ohms.

We can now use Ohm's Law (V = IR) to calculate the voltage V(t) across the capacitor at time t:[tex]V(t) = I(t).R[/tex], where I (t) is the current at time t and R is the total resistance in the circuit. Since the inductance of the circuit is 0.2 Henry, we can use the equation L*di/dt = V to calculate the current at time t, I [tex](t) = V(t)/R[/tex].

Substituting this into Ohm's Law, we get: V(t) = (V(t)/R)*R. Solving for V(t), we get V(t) = V(t). Therefore, the voltage V(t) across the capacitor at any time t is equal to the voltage at time t.

Finally, we can use the equation [tex]q(t) = C.V(t)[/tex]to calculate the charge q(t) on the capacitor at any time t: [tex]q(t) = 1,25 . 10-5 Farad.V(t)[/tex].

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Polar stratospheric clouds are high-altitude clouds made of tiny ice crystals that form in the lower stratosphere at very cold temperatures. They exhibit vivid iridescent colors and are associated with ozone depletion.

High-altitude clouds comprised of microscopic ice crystals are referred to as polar stratospheric clouds, nacreous clouds, or mother-of-pearl clouds. At heights of around 15,000 to 25,000 meters and extremely low temperatures of minus 80 to minus 85 degrees Celsius, they occur in the lower stratosphere. The refraction of sunlight as it passes through the ice crystals gives these clouds their distinctive dazzling and vibrant iridescent colors. Polar stratospheric clouds, which are linked to the ozone layer's thinning, are most frequently seen during the winter in polar locations like the Arctic and Antarctic.

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The density of the metal in grams per milliliter is 7.87 g/mL.

Given data:The weight of metal, W = 187.6 g,Volume of water, V₁ = 225.2 mL.

The combined volume of solid and liquid, V₂ = 250.3 mL

Volume of the metal can be calculated as:Volume of metal = V₂ - V₁= 250.3 - 225.2= 25.1 mL

The density of the metal can be calculated as:Density = Weight of metal / Volume of metal

Density = W / V= 187.6 g / 25.1 mL= 7.87 g/mL

Thus, the density, in grams per milliliter, of the metal is therefore calculated and found to be 7.87 g/mL.

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Yes, the values found in parts (a) and (b) are consistent with the fact that tidal effects with earth have caused the moon to rotate with one side always facing earth.

This is because part (a) states that the moon rotates on its axis in the same amount of time it takes to complete one orbit around the Earth, which is a phenomenon known as tidal locking. Part (b) further indicates that the same side of the moon always faces the Earth, further supporting the notion that tidal effects have caused the moon to rotate with one side always facing Earth.

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