(Algebra ll) Given the function below

Answer:

She should have included an exponent of 2 on the 3

Step-by-step explanation:

The factor tree can be presented as follows;

                [tex]{}[/tex]                                90

[tex]{}[/tex]                                                  ↓

[tex]{}[/tex]                                     9          ↔            10

[tex]{}[/tex]                                     ↓                           ↓

[tex]{}[/tex]                                3  ↔  3                  2  ↔  5

Therefore, the prime factorization of 90 is equal to 90 = 3 × 3 × 2 × 5

She should have wrote, 90 = 3² × 2 × 5

Therefore, the error is that she should have included an exponent of 2 on the 3.

Answer:

B

✔ She should have included an exponent of 2 on the 3.

Step-by-step explanation:

E2021

Answer:

first option

Step-by-step explanation:

the graph has a point of (8,2)

so see which option proves this point

2=0.25(8)

2=2

so first option is correct

Answer:

p = 4/7c

p = 36 cups when c = 63 cups

Step-by-step explanation:

Cups of pineapple juice, p = 8

Cups of cranberry juice, c = 14

equation that describes the proportional relationship between cups of pineapple juice (p) and cups of cranberry juice (c)

p = k * c

Where,

k = constant of proportionality

p = k * c

8 = k * 14

8 = 14k

k = 8/14

k = 4/7

Therefore,

p = 4/7c

How many cups of pineapple juice are needed for 63 cups of cranberry juice?

p = 4/7c

p = 4/7 * 63

= (4 * 63) / 7

= 252/7

= 36

p = 36

p = 36 cups when c = 63 cups

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

[tex]Q_1=\dfrac{11+13}{2}[/tex]

[tex]Q_1=\dfrac{24}{2}[/tex]

[tex]Q_1=12[/tex]

And

[tex]Q_3=\dfrac{16+16}{2}[/tex]

[tex]Q_3=\dfrac{32}{2}[/tex]

[tex]Q_3=16[/tex]

The interquartile range is:

[tex]IQR=Q_3-Q_1[/tex]

[tex]IQR=16-12[/tex]

[tex]IQR=4[/tex]

The data values lies outside the interval [tex][Q_1-1.5IQR,Q_3+1.5IQR][/tex] are known as outliers.

[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)][/tex]

[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6][/tex]

[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[6,22][/tex]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

Answer:

Step-by-step explanation:

Step-by-step explanation:

.hhx cvs Gunther b but kcm

Answer:

the answer is A

Step-by-step explanation:

Answer:

[tex]\underline{\underline{ -10x +2}}[/tex]

Step-by-step explanation:

A expression is given to us and we need to simplify out the expression . The given expression is ,

[tex]\implies 2(-3x +1)-4x [/tex]

Open the brackets .

[tex]\implies -6x +2-4x [/tex]

Simplify the like terms .

[tex]\underline{\underline{ -10x +2}}[/tex]

Hence the correct option is (4) .

Answer:

Lateral surface area of pentagonal prism = 750 cm²

Step-by-step explanation:

Given information:

Height of pentagonal prism = 15 cm

Length of edge = 10 cm

Length of apothem = 16.8 cm

Find:

Lateral surface area of pentagonal prism

Computation:

Lateral surface area of pentagonal prism = 5(a)(h)

Lateral surface area of pentagonal prism = 5(10)(15)

Lateral surface area of pentagonal prism = 750 cm²

Answer:

15 ten thousands

Step-by-step explanation:

15,000 ones is 15,000 * 1 = 15,000

1,500 tens is 1,500 * 10 = 15,000

15 thousands is 15 * 1000 = 15,000

15,000 is 15,000 '-'

15 TEN thousands is 15 * 10,000 = 150,000

It could be 1.5 ten thousands. 1.5 ten thousands is 15,000.

Answer:

x=29°

Step-by-step explanation:

as lines are parallel.

external alternate angles are equal.

7x-86=4x+1

7x-4x=1+86

3x=87

x=87/3=29

Answer:

The answer is

[tex] \frac{3}{x} = \frac{11}{10} - \frac{4}{5} \\ \frac{3}{x} = \frac{55 - 40}{50} \\ \frac{3}{x} = \frac{15}{50} \\ \frac{3}{x} = \frac{3}{10} \\ x = 10[/tex]

Answer:

130

Step-by-step explanation:

Answer:

11011000

Step-by-step explanation:

the binary equivalent of decimal number 216 is 11011000

[tex]\huge\sf\red{Answer}[/tex]

11011000

__________

Hopefully it helps

Answer:

Solution given:

Let there be a point P(x, y) equidistant from

A(-3, 2) and B(0,4),

so PA = PB,

[tex]\sqrt{(x+3)²+(y-2)²}=\sqrt{(x-0)²+(y-4)²}[/tex]

squaring both side

[tex](\sqrt{(x+3)²+(y-2)²})^{2}=(\sqrt{(x-0)²+(y-4)²})²[/tex]

x²+6x+9+y²-4y+4=x²+y²-8y+16

x²+6x+y²-4y-x²-y²+8y=16-4-9

6x-4y+8y=3

6x-4y=3 is a required locus

Actually:

A locus is a curve or other figure formed by all the points satisfying a particular equation of the relation between coordinates, or by a point, line, or surface moving according to mathematically defined conditions.

Answer:

Step-by-step explanation:

2/a = 1/b - 1/d

2d/a = d/b - 1

2d/a - d/b = -1

d(2/a - 1/b) = -1

d(2b-a)/(ab) = -1

d(a-2b)/(ab) = 1

d = ab/(a-2b)

Answer:

3m -2

Step-by-step explanation:

(10m – 6) – (7m – 4)

Distribute the minus sign

(10m – 6) – 7m + 4

Combine like terms

3m -2

Answer:

3/9

Step-by-step explanation:

P(G,G) = 1/3 × 1/3 = 1/9

P(B,B) = 1/9

P(Y,Y) = 1/9

P(same colour) 1/9 + 1/9 + 1/9 = 3/9

Answer:

[tex]3(2x+5)(x-3)[/tex]

Step-by-step explanation:

The given equation is:

[tex]6x^{2}-3x-45[/tex]

It can be solved by using middle term splitting.

So,

[tex]6x^{2}-3x-45=6x^2+15x-18x-45\\\\=3(2x+5)(x-3)[/tex]

So, the factors of [tex]6x^{2}-3x-45[/tex] are [tex]3(2x+5)(x-3)[/tex]

Answer:

x

Step-by-step explanation:

The cube root of x to the power of 3 is

( [tex]\sqrt[3]{x}[/tex] )³ = ( [tex]x^{\frac{1}{3} }[/tex] )³ = x

or

[tex]\sqrt[3]{x^3}[/tex] = x

Answer:

x = -1

Step-by-step explanation:

If you input -1 to both functions, you get 3.

Answer:

1 / sqrt(3)

Step-by-step explanation:

tan(o) = sin(o) / cos(o)

sin(o) is the vertical distance from the x-axis. and that is in this basic circle the y-coordinate of the point.

cos(o) is the horizontal distance from the y-axis. that is the x-coordinate of the point.

so,

tan(o) = (1/2) / (sqrt(3)/2) = (2×1) / (2×sqrt(3)) = 1/sqrt(3)

the answer is 1024 because 7²+25²=b²

factor out the square which gives you

(7+25)²=b²

32²=b²

squaring 32 gives 1024

Answer:

24 units

Step-by-step explanation:

i just took the quiz

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\dfrac{(9 \times5) 2}{3}}[/tex]

[tex]\huge\boxed{9 \times 5 = \bf 45}[/tex]

[tex]\huge\boxed{ = \dfrac{45(2)}{3}}[/tex]

[tex]\huge\boxed{45(2) = \bf 90}[/tex]

[tex]\huge\boxed{= \dfrac{90}{3}} \\\\\huge\boxed{= \dfrac{90\div3}{3\div3}}\\\\\huge\boxed{= \dfrac{30}{1}}[/tex]

[tex]\huge\boxed{= \bf 30}[/tex]

[tex]\huge\boxed{\rm{Answer: 30}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

30

Step-by-step explanation:

Multiply 9 and 5 to get 45.

Multiply 45 and 2 to get 90.

Divide 90 by 3 to get 30.

Answer:

Y = 2x + 5

Step-by-step explanation:

2x is your slope and 5 is your y intercept.

The formula for this is: y = mx + b

B.

the solution is in the picture

Answer:

The height of the school building is approximately 21.06 meters

Step-by-step explanation:

The method of Geometry Tyler is using to determine the height of his school building is through the property that similar triangles have a common ratio of corresponding their sides

The given parameters for the triangle formed by Tyler and the mirror are;

The distance from Tyler's eyes to the ground = 1.15 meters

The horizontal distance between Tyler and the mirror at X = 0.8 m

The parameters of the triangle formed by the height, h, of the school building and the mirror at X are;

The horizontal distance between the school building and the mirror = 14.65 m

The height of the school building = h

Therefore, we have;

[tex]\dfrac{The \ distance \ from \ Tyler's \ eyes \ to \ the \ ground}{The \ height \ of the \ school \ building} =\dfrac{Tyler's \ horizontal \ distance \ from \ mirror }{The \ building \ to \ mirror \ horizontal \ distance }[/tex]Therefore;

[tex]\dfrac{1.15 \, m}{h} = \dfrac{0.8 \ m}{14.65 \ m}[/tex]

[tex]h = \dfrac{1.15 \, m \times 14.65 \, m }{0.8 \, m} = 21.059375 \ m[/tex]

The height of the school building h to the nearest hundredth meter ≈ 21.06 m.

Answer:

A

Step-by-step explanation:

Have a great summer :)