ABC is a straight angle.which equation can be used to find the measure of the unknown angle?

Answers

Answer 1

Answer:

Straight angles are all 180 degrees, so it must be an equation that equals 180. I hope that this helps! be saffffeee!

Answer 2

Answer:

140 x 180

Step-by-step explanation:


Related Questions

Secant TQ and tangent TR intersect at point T. Chord SR and chord PQ intersect at point V. Find the values of x and y. If necessary, round to the nearest tenth.

Answers

Answer:

x=4, y=9.6

Step-by-step explanation:

Using Theorem of Intersecting Secant and Tangent

[tex]TP X TQ=TR^2[/tex]

[tex]9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4[/tex]

Next, we apply Theorem of Intersecting Chords

SV X VR=PV X VQ

5 X y = x X 12

Recall: x=4

5y=4 X 12

5y=48

y=48/5=9.6

Therefore: x=4, y=9.6

PLEASE HELP!!!! NEED ANSWER ASAP

Answers

Answer:

X=25

Step-by-step explanation:

Since these 2 angles are vertically opposite angles so they are equal. (rule)

75°=(4x-25°)

75° + 25° = 4x

100=4x

X=100/4 = 25

___________

Hope this helps...

Find the volume of the figure

Answers

Answer:

450

Step-by-step explanation:

Find the surface area of the cylinder with a height of 4 and a radius of 9

Answers

Answer:

735.13268 units^2

Step-by-step explanation:

A=2πrh+2πr2=2·π·9·4+2·π·92≈735.13268

What is the distance between points A(13, 2) and B(7, 10)

Answers

Answer:

distance = sqrt((x2-x1)^2 + (y2-y1))

distance = sqrt((7-13)^2 + (10-2)^2)

distance = sqrt( -6^2 + 8^2)

distance = sqrt(36+64)

distance = 10

Step-by-step explanation:

Answer:

10 units

Step-by-step explanation:

d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]

d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]

d = [tex]\sqrt{36 + 64}[/tex]

d = [tex]\sqrt{100}[/tex]

d = 10 units

What is the slope of the line ?

Answers

Answer:

-3

Step-by-step explanation:

The leaning Tower of Pisa was completed in 1372 and makes 86 degree angle with the ground. The tower is 50 meters tall, measured vertically from the ground to the highest point. If you were to climb to the top then accidentally drop your keys, where would you start looking for them?



How far from the base of the tower would they land?



I made having no luck in figuring this out.

Answers

Answer:

The distance where the keys would drop from the base is 3.5m

Step-by-step explanation:

Height of the tower = 50m

Angle it makes to the ground = 86°

To solve this question, you have to understand that the tower isn't vertically upright and the height of the tower is different from the distance from the top of the tower to the ground.

The tower makes an angle 86° to the ground and that makes it not vertically straight because a vertically straight building is at 90° to the ground.

See attached document for better illustration.

The distance from where the keys drop to the base of the tower can be calculated using SOHCAHTOA

We have to use cosθ = adjacent / hypothenus

θ = 86°

Adjacent = ? = x

Hypothenus = 50m

Cos θ = x / hyp

Cos 86 = x / 50

X = 50 × cos 86

X = 50 × 0.06976

X = 3.488 = 3.5m

The distance where the keys would drop from the base of the tower is approximately 3.5m

Which expressions are equivalent to g+h+(j+k) Check all that apply

Answers

Answer:

g+h+(j+k)

Step-by-step explanation:

(g+h)+j+k

(g+k)+j+h

(g+j)+h+k

(k+h)+j+h

(j+h)+g+k

Answer:

1 and 3

Step-by-step explanation:

dont mind me this needed to be longer wait still needs no be longer

At the beginning of the month, Tim has $50. He mows 2 lawns and washes 1 car. Then, he buys two video games that cost $15 each and a sweatshirt that costs $35. How much money does Tim have left? (please put just your answer with the $)

Answers

Answer:

Tim has $50. 15+15=30-35=5

Tim has $5 left

1. If 5tanA=4, Find the value of (5sinA-3cosA)/(4cosA+5sinA)
2. Solve for θ, sinθ/(1+cosθ) + (1+cosθ)/sinθ =4, 0°<θ<90°
3. Prove that tan⁡〖θ-cot⁡θ 〗 = (〖2sin〗^2 θ-1)/sinθcosθ
4. Without using trigonometric tables ,show that
tan 10°tan15°tan75°tan80°=1
5. If x=acosθ-bsinθ and y=asinθ + bcosθ prove that x^2+y^2=a^2+b^2

Answers

Answer:

1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A))  = 1/8

2. θ = 30°

3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) +  cos²(θ) = 1

4. tan10°·tan15°·tan75°·tan80°= 1 from;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;

cos²θ + sin²θ = 1

Step-by-step explanation:

1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4

∴ 5·sin(A) = 4·cos(A)

Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;

Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;

(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8

Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8

2. For the equation as follows, we have

[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives

[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]

[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]

[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]

[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]

We place;

[tex]tan\frac{\theta}{2} = x[/tex]

∴ x² - 4·x + 1 = 0

Factorizing we have

(x - (2 - √3))·(x - (2 + √3))

Therefore, tan(θ/2) = (2 - √3) or (2 + √3)

Solving, we have;

θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)

Which gives, θ/2 = 15° or 75°

Hence, θ = 30° or 150°

Since 0° < θ < 90°, therefore, θ = 30°

3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)

Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)

∴  tan(θ) - 1/tan(θ) = (sin²(θ) -  cos²(θ))/(cos(θ)×sin(θ))...........(1)

From sin²(θ) +  cos²(θ) = 1, we have;

cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;

(sin²(θ) -  (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

Therefore;

tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))

4. tan10°·tan15°·tan75°·tan80°= 1

Here we have since;

sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]

cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]

Then;

tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°

tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]

Which gives;

[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]

[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]

[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]

[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]

5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ

∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²

= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ

= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ

= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ

= (a² + b²)·cos²θ + (a² + b²)·sin²θ

= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have

= (a² + b²)×1 = a² + b²

The expression two square root of three minus square root of 27 is equivalent to

Answers

Answer:

-0.954(rounded)

Step-by-step explanation:

first write it in number form

√2(3)-√27

the exact form will be 3√2-3√27 = -0.954(rounded)

It’s rounded to 0.954

mean median and mode of 14, 10, 12, 15, and 13​

Answers

Answer:

mean= 12.8

median=13

mode=there is no mode

Step-by-step explanation:

mean/average=14+10+12+15+ 13​=64/5=12.8

median=10,12,13,14,15=13

mode= is the number that repeats more often. = there is no mode

Margo can purchase tile at a store for $0.89 per tile and rent a tile saw for $45. At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile. How many tiles must she buy for the cost to be the same at both stores?


Margo must buy ____ tiles for the cost to be the same at both stores.

Answers

Answer:

She must buy 90 tiles for the cost to be the same at both stores

Step-by-step explanation:

Let x be the no. of tiles bought for the cost to be the same at both stores

Margo can purchase tile at a store for $0.89 per tile at shop 1

Cost of x tiles =0.89x

She rent a tile saw for $45.

So, total cost at Store 1 = 0.89x+45

At another store she can borrow the tile saw for free if she buys tiles there for $1.39 per tile.

So, cost of 1 tile = 1.39

Cost of x tiles = 1.39x

ATQ

0.89x+45=1.39x

45=1.39x-0.89x

45=0.5x

[tex]\frac{45}{0.5}=x[/tex]

90=x

Hence She must buy 90 tiles for the cost to be the same at both stores

Four students spoke to the Home and School parents for a total of 2/3 hour. Each student spoke for the same amount of time. How long did each student speak?

Answers

creo que la respuesta el 10 minutos, porque dice "horas" pero no dice a cuantas horas equivale :)      espero que te aya adudado auque sea un poquito

Please help me now I will mark you brainliest

Answers

Answer:

Out side the circle

Step-by-step explanation:

This is because the center is 0 and if the point 6, square root seven is on the circle that mean that as far as the circle goes on each side.

If 3x and 71/x are two prime numbers V x equivalent to R, then number of x so that 3x + 71/x = 10 is/ are

Answers

Answer:

x = 5/3

Step-by-step explanation:

Guven two prime numbers to be 31/x and 71/x, if their sum is 10 as given;

3x + 71/x = 10 then to find the value of x, the following steps must be taken;

Step 1

Find the LCM of the given equation;

3x + 71/x = 10

[tex]\frac{3x^{2}+71 }{x} =10\\[/tex]

Step 2:

Cross multiplying;

[tex]3x^{2} +71=10x\\3x^{2} -10x+71 =0\\[/tex]

Using the general formula to get the value of x;

x = -b±√b²-4ac/2a

a=3, b=-10, c=71

= 10±√(-10)²-4(3)(71)/2(3)

= 10±√100-852/6

= 10±√-752/6

= 10±27.4i/6

= 10+27.4i/6 or 10-27.4i/6

x = 5/3+27.4i/6 or 5/3-27.4i/6

Since the values of x are real values then, our answer will be the real part of the complex number gotten.

x = 5/3

If the product of two whole numbers is zero then one number will be (ii) If the product of two whole numbers is zero then both number will be zero (a) OnlyIcanbetrue(b)onlyiicanbetrue(c)Bothcanbetrue(d)botharefalse

Answers

Answer:

If the product of two numbers is zero, there are two possibilities, namely;

1. One of the numbers is zero.

2. Both of the numbers are zero.

Step-by-step explanation:

As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.

Therefore,

1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,

153, 000 * 0 = 0

2.  If both of the numbers are zero, then the product of the two numbers is zero. For example,

0 * 0 = 0.

So we can say that both can be true.

What is the correct answer?

Answers

Answer:45

Step-by-step explanation:

Sin^-1= 5÷7

The student body of 10 students want to elect a president, vice president, secretary, and treasurer.


A) Permutation

B) Combination

C) Circular permutation

Answers

Answer:

a

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Jamal and Cleo mow lawns together, Jamal can mow an average lawn in 60 minutes by
himself. Cleo would take 90 minutes for the same job. How long would it take both of
them together to mow one (1) lawn

Answers

60+90= 150
Hope this helps

BE5-3 Cha Company buys merchandise on account from Wirtz Company. The selling price of the goods is $780, and the cost of the goods is $470. Both companies use perpetual inventory systems. Journalize the transaction on the books of both companies.

Answers

Answer:

In the books of Wirtz, the selling party, the required entries are

Debit Accounts receivable $780

Credit Revenue $780

Being entries to recognize sales revenue on account

Debit Cost of sales $470

Credit Inventory  $470

Being entries to recognize the cost of items sold

In the books of Cha Company

Debit Inventory $780

Credit Accounts payable  $780

Being entries to record cost of inventory purchased

Step-by-step explanation:

When a company makes a sale, the effect of such sale is dual in the books of the company being that the company would first recognize revenue and then recognize the cost of items sold.

To recognize revenue,

Debit Cash/Accounts receivable

Credit Revenue

To record the cost of the item sold

Debit Cost of sales

Credit Inventory

For the party that makes the purchase

Debit Inventory

Credit Cash/Accounts payable

solve the equation 18=n-18

n=_____​

Answers

Answer:

36

Step-by-step explanation:

Josh is making a rectangular-shaped picture frame. The length of the frame is to be 5 inches more than twice the width. Which equation models the area, A, of the frame in terms of the width, w?

Answers

Answer:

A=2x^2+5x

Step-by-step explanation:

length of frame = 2x+5

width of frame = x

A=lw

A=(2x+5)x

A=2x^2+5x

Find the height of a right cylinder with surface area 240π ft2 and radius 5 ft.

The height of the right cylinder is __
ft.

Answers

Answer:

h ≈ 2.64ft

Step-by-step explanation:

A = 2πrh + 2πr2

h= A /2πr﹣r = 240 /2·π·5﹣5 ≈ 2.63944ft

Kono Dio Da!!

Compare the ordered pairs of the pre-image to the
image to answer these questions.
Is the dilation an enlargement or reduction?
The point of dilation is about what coordinate?
What is the scale factor?
Pre-image

Answers

Answer: Reduction

(0,0)

1/3

Step-by-step explanation:

Answer:

1-reduction

2-(0,0)

3-1/3

Step-by-step explanation:

The combined weight of Maia and Vashti is 102.45kg. If Maia weighs 2.15kg more than Vashti, calculate Vashti's weight.





Answers

Answer:

50.32 I think

Step-by-step explanation:

52,13+50,32=102.45

Vashti’s weight is 50.15kg Hope this helped!

how much money does ron have each month

Answers

Answer:

after paying all expenses Ron will have $10 leftover each month.

Answer:

10 on edge

Step-by-step explanation:

Which number is composite ??? A.11 B.5 C.9 D.2

Answers

Answer:

the correct answer is 9

Divya’s recipe calls for 3.25 pounds of beef, 0.65 pounds of onions, 0.2
pounds of potatoes, 0.15 pounds of tomatoes, and 0.33 pounds of asparagus.

How much will Divya pay for all the ingredients in the recipe? Show your work.

Answers

The beef price is $10.65

Onions price is $2.49

Potatoes are $3.29

Tomatoes are $8.45

Asparagus is $4.99

3.25 pounds of beef is          3.25 * 10.65 =  34.61

0.65 pounds of onions is      0.65 * 2.49   =  1.62

0.2 pounds of potatoes is     0.2 * 3.29     =  0.66

0.15 pounds of tomatoes is   0.15 * 8.45   =  1.27

0.33 pounds of asparagus is 0.33 * 4.99  =  1.65

Adding these up we get 34.61 + 1.62 + 0.66 + 1.27 + 1.65

This is equal to 39.81

                                           

A recipe is mixture of ingredients.

Divya will pay $39.81 for all the ingredients in the recipe.

The beef price is $10.65 per pound

So, price of 3.25 pounds of beef is ,  [tex]3.25 * 10.65 = 34.61[/tex]

Onions price is $2.49 per pound

So, price of 0.65 pounds of onions is,  [tex]0.65 * 2.49 = 1.62[/tex]

Potatoes are $3.29 per pound

So, price of 0.2 pounds of potatoes is ,  [tex]0.2 * 3.29 = 0.66[/tex]

Tomatoes price are $8.45 per pound.

So, price of 0.15 pounds of tomatoes is  , [tex]0.15 * 8.45 = 1.27[/tex]

Asparagus price is $4.99 per pound.

So, price 0.33 pounds of asparagus is , [tex]0.33 * 4.99 = 1.65[/tex]

Hence, total amount paid by Divya is,

             [tex]=34.61 + 1.62 + 0.66 + 1.27 + 1.65=39.81[/tex]

Thus, Divya will pay $39.81 for all the ingredients in the recipe.

Learn more:

https://brainly.com/question/18994792

what is a=1/4 b if b is the subject?

Answers

Answer:

b = 4a

Step-by-step explanation:

Given

a = [tex]\frac{1}{4}[/tex] b

Multiply both sides by 4 to clear the fraction

4a = b

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