Answer:
6N
Explanation:
Given parameters:
Pressure applied by the woman = 300N/m²
Area = 0.02m²
Unknown:
Force applied = ?
Solution:
Pressure is the force per unit area on a body
Pressure = [tex]\frac{force}{area}[/tex]
Force = Pressure x area
Force = 300 x 0.02 = 6N
This man proposed that all matter was composed of atoms
Answer:
John Dalton
Explanation:
When dribbling you should?
a. Use both feet.
b.Use frequent small touches of the ball.
C.Protect the ball with your body.
D. All of the above.
Which statement is supported by the information in the diagram and table below?
Answer:
a
Explanation:
a
A man travels 25 kilometers in 15 minutes. A police officer stops him and
writes a ticket for speeding. The posted speed limit is 80 kilometers per
hour. Did the man exceed the posted speed limit?
Answer:
yes
Explanation:
cuz 15x2=30 30x2=60 60=1 hour, and the limited is 80 km per hour
15=25
15x4=60 25x4=100
so yes
he was going 100km per hour
Annie has 100 mL of honey. The honey has a mass of 145 g. What is the density of the honey?
Answer:
The answer is 1.45 g/mLExplanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question we have
[tex]density = \frac{145}{100} \\ [/tex]
We have the final answer as
1.45 g/mLHope this helps you
A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?
Answer:
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m
Explanation:
The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water
The net force, F acting on the body falling through the fluid is given as follows;
F = Weight force, W, from gravity - Drag force, D, from the fluid
F = W - D
Given that F = Mass, m × Acceleration, a, we have;
F = m × a
The acceleration, a = F/m = (W - D)/m
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.
how do the early efforts of women during the suffrage movement compare to the later years
The idea that women's liberation is also men's liberation arouses the awakening of feminism. In 1966 Frieden and other feminists founded the National Organization for Women. Then other women's organizations for equal rights were formed in the United States and Western Europe. These organizations sought to overturn discriminatory laws and practices that forced women to hold down their status, such as discrimination in matters of contract and property ownership, employment and wages, the treatment of wage income, and issues relating to sex and child-bearing. The growing feminist movement more broadly seeks to change social stereotypes that women are more vulnerable, passive and dependent, less rational and emotionally reactive than men. Feminism strives for greater freedom for women in the workplace and makes them financially and psychologically independent of men, if they wish. Feminists criticized society's general emphasis on women as objects of sexual desire and sought to raise women's awareness and expand their opportunities in order to achieve equality with men. Another objective of feminism is to promote women's participation in all areas of political decision-making and social life.
What is the speed of a car that
accelerates at a rate of 10 m/s2 for a
total of 25 seconds?
Answer:
250 m/sExplanation:
The speed of the car can be found by using the formula
v = a × twhere
a is the acceleration
v is the speed
t is the time
From the question we have
v = 10 × 25
We have the final answer as
250 m/sHope this helps you
hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N l need process
Answer:
735N
Explanation:
Weight is a measurement of force.
F = Force
m = mass
a = acceleration
F = m*a
F = 75kg*9.8m/s²
F = 735N
which theory is a famous for quantum physics
hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest
Answer:
A. Cue, White Ball, Blue Ball
Explanation:
Visualize in which order things are being hit
30.) We observe motion by using a *blank* of *blank*.
Answer:
Point of Reference
Explanation:
Which of the following is true regarding mixtures? a. One substance not combined with any other substances. b. Two or more substances physically mixed and can be separated. c. Two or more substances that are impossible to separate d. One substance that forms a compound alone.
Answer:
aerga
dggzsd
Explanation:
szsdrgzsedg
An object with a mass of 15 kg accelerates 10.0 m/s2 when an unknown force is applied to it. What is the
amount of the force
Answer:
f=mass × acceleration
=15×10
=150
Los satélites de televisión giran alrededor de la Tierra en una órbita de 42370 km de radio. a) ¿Cuánto vale la aceleración de la gravedad en esa órbita? (Resultado: g = 0,22 m/s2 ) b) ¿Cuánto pesará allí un satélite de 1200 kg? (Resultado: P = 264 N) Datos: G = 6,67 10-11 Nm2 /kg masa de la Tierra: 6 1024 kg
Answer:
(a) La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) Un satélite de 1,200 kg pesará allí 264 N.
Explanation:
(a) Cada punto del espacio tiene un valor del campo proporcional a la función, siguiendo el modelo de gravitación de Newton:
[tex]g=G*\frac{m}{r^{2} }[/tex]
donde m será masa, r la distancia entre los objetos y G la constante de gravitación universal, cuyo valor es [tex]G=6.672*10^{-11}\frac{N*m^{2} }{kg }[/tex]
En este caso:
m= 6*10²⁴ kgr=42,370 km= 42,370,000 mReemplazando:
[tex]g=6.672*10^{-11}\frac{N*m^{2} }{kg }*\frac{6*10^{24}kg }{(42,370,000 m)^{2} }[/tex]
Resolviendo, obtenes:
g= 0.22 [tex]\frac{m}{s^{2} }[/tex]
La aceleración de la gravedad en esa órbita es 0.22 [tex]\frac{m}{s^{2} }[/tex]
(b) La ley fundamental de la dinámica o segunda ley de Newton expresa que la fuerza neta que es aplicada sobre un cuerpo es proporcional a la aceleración que adquiere en su trayectoria. Esto se expresa matemáticamente como:
F= m*a
en donde F es fuerza neta , m la masa y a la aceleración.
El peso es la fuerza que ejerce la gravedad sobre una masa, por lo que se obtiene de manera análoga a la fuerza:
P=m*g
En este caso la masa m tiene un valor de 1,200 kg y la gravedad g un valor de 0.22 [tex]\frac{m}{s^{2} }[/tex].
Reemplazando:
P=1,200 kg*0.22 [tex]\frac{m}{s^{2} }[/tex]
Resolviendo:
P= 264 N
Un satélite de 1,200 kg pesará allí 264 N.
The mass of the sun is 1.9891030 kg and the mass of the Earth is 5.9721024kg. If the Earth’s acceleration toward the sun is 0.0059 m/s/s, what is the sun’s acceleration toward the Earth?
Answer:
this is the answer according to my calculations
Explanation:
0.001.9
Device A has a current of 0.4 A and a resistance of 3 Ω. Device B has a current of 0.6 A and a resistance of 3Ω. Which device would be more energy efficient?
Your answer would be Device A.
Answer:
Device A because it would use more voltage :D
Explanation:
PLZ EXPLAIN THE EQUATION AND I WILL GIVE BRAINLIST You are out and about in the country and your father sees a rock that he really wants in the yard. Now you must get the very heavy rock into the back of a truck. The truck bed is 3 feet off the ground. Your father pulls out a 5-foot plank and begins to set up a ramp. At the same time, you (who know about mechanical advantage!) have found a plank that is 8 feet long, and you show it to your father. Which plank will give you the most mechanical advantage? Calculate the MA for each plank
Answer:
The 8 foot long plank
Explanation: hope this helps :)
A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is decreasing at a rate of 3.1m/s2.
What is the student's mass?
What is the net force on the student?
What value does the scale read?
Answer:
1) The mass of the student is approximately 73.39 kg
2) The net force on the student is approximately 947.523 N
3) The value the scale will read is approximately 96.59 kg
Explanation:
The given parameters are;
The weight of the student = 720 N
The speed at which the elevator is decreasing = 3.1 m/s²
1) The weight of the student = The mass of the student × The acceleration due to gravity
The acceleration due to gravity is a constant = 9.81 m/s²
Substituting the known values gives;
720 N = The mass of the student × 9.81 m/s²
∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg
2) The forces acting on the student are;
i) The force of gravity which is the weight of the student acting downwards
ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student
The net force, [tex]F_{net}[/tex] = The weight of the student + The inertia force of the slowing elevator
∴ The net force, [tex]F_{net}[/tex] = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N
3) The scale will read the mass of the student as follows;
Mass reading of student on the scale = Force on scale/9.81
∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg
The value the scale will read = 96.59 kg.
The mass of student is, 73.46 kg.
The net force acting on the student is 942.72 N.
The reading of the scale is 96.70 kg
Given data:
The weight of student is, W = 720 N.
The magnitude of acceleration is, [tex]a = 3.1 \;\rm m/s^{2}[/tex].
The standard expression for the weight is,
[tex]W =mg[/tex]
Here, g is the gravitational acceleration. And m is the mass of student.
Solving as,
[tex]W =mg\\\\720 = m \times 9.8\\\\m = 73.46 \;\rm kg[/tex]
Thus, the mass of student is, 73.46 kg.
Since, the force of gravity which is the weight of the student acting downwards . The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student. Then the net force is,
[tex]F_{net} = W+(ma)[/tex]
Solving as,
[tex]F_{net} = 720+(73.46 \times 3.1)\\\\F_{net}=947.72 \;\rm N[/tex]
Thus, we can conclude that the net force acting on the student is 942.72 N.
The reading of the scale is given as,
[tex]reading=\dfrac{F_{net}}{g}[/tex]
Solving as,
[tex]reading = \dfrac{947.72}{9.8}\\\\reading=96.70 \;\rm kg[/tex]
Thus, we can conclude the reading of the scale is 96.70 kg.
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3. Four projectiles, A, B, C, and D, were launched from, and returned to, level ground.
The data table below shows the initial horizontal speed, initial vertical speed, and
time of flight for each projectile.
Data Table
Projectile Initial Horizontal Speed (m/s) Initial Vertical Speed (m/s) Time of Flight (s)
A
40.0
29.4
6.00
B
60.0
19.6
4.00
С
50.0
24.5
5.00
D
80.0
19.6
4.00
Which projectile traveled the greatest horizontal distance? [Neglect friction.]
Answer is D
Taking the test rn and found out the answer
The projectile D traveled the greatest horizontal distance.
What is projectile motion?Projectile motion is a form of motion experienced by an object or particle that is projected near the Earth's surface and moves along a curved path under the action of gravity only.
What is projectile horizontal distance?Horizontal range of a projectile is the horizontal distance travelled by the projectile between launch and the landing points.
The projectile horizontal distance is depend on horizontal speed and time in air.
In all these four projectile, projectile D has maximum horizontal speed and time in air.
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can someone help rn please!! thank you sm!!
A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 53.9 m/s2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall.
Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant free-fall acceleration equal to 9.80 m/s2 .
Answer:
maximum height reach by rockect =970.2metre
Explanation:
Write an equation of the line in slope-intercept form.
Please explain.
Answer:
y = [tex]-\frac{1}{4}[/tex]x + 3
Explanation:
The equation of a straight line is given as:
y = mx + c
y and x are the coordinates
m is the slope
c is the y -intercept
The y-intercept = 3;
Slope = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]
x₁ = 0
x₂ = 4
y₁ = 3
y₂ = 2
Slope = [tex]\frac{2-3}{4 -0 }[/tex] = [tex]-\frac{1}{4}[/tex]
y = mx + c
y = [tex]-\frac{1}{4}[/tex]x + 3
when a car suddenly stops,the objects in the backseat are thrown forward.this is explained by-
A.Newton's first law of motion
B.Newton's second law of motion
C.Newton's third law of motion
D.the universal law of gravitation
Answer:law of interia(1st law)
Explanation:
Amanda studies a waveform. She labels parts of the waveform using variables (P,Q,R, and S), as shown in the image.
Which label part represents the wavelength
Answer:
Q
Explanation:
To know which symbol defines the wavelength, we must know the definition of wavelength.
Wavelength can be defined as the distance between two successive crests (i.e the highest part) or troughs (the lowest part) of a wave.
Considering the diagram given above, Q shows the distance between two successive crests (i.e the highest part) of the wave. Therefore, Q is the wavelength of the wave given in the diagram above.
Calculate the density of a rock that has a mass of 32 grams and a volume of
4.5 mL.
Answer:
85.2ml
Explanation:
Unit 2 kinetic energy mastery test
Answer: kinetic energy is Energy of motion.
Explanation:
Which is the balanced equation for Sg + O2 → SO2?
OS: + 016 — 8S02
O S₂ + O₂S₃ + O₂
O S8+ O₂S₂O₂
O Sg + 802 8S02
The balanced equation for S(g) + O₂ → SO₂ is as follows: S₈ + 8O₂ → 8SO₂ (option C).
What is a balanced equation?A balanced equation is a chemical equation in which the number of atoms of each element on both sides of the equation are the same.
This means that the number of the atoms involved in the reactants side is equal to the number of atoms in the products side.
Balancing chemical equations involves the addition of stoichiometric coefficients to the reactants and products.
According to this question, sulfur reacts with oxygen gas to produce sulfur dioxide as follows:
S₈ + O₂ → SO₂
The balanced chemical equation is as follows:
S₈ + 8O₂ → 8SO₂
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On the moon, the gravity is 1/6 that of Earth. While on the moon, Buzz Aldrin carried on his back a support system that would weigh over 1760 N on Earth. a) What did the backpack weigh on the moon? b) What was its mass on the moon? please show the work
Answer:
a) 293.[tex]\bar 3[/tex] N
b) Approximately 179.41 kg
Explanation:
The given parameters are;
The gravity (gravitational acceleration) on the moon = 1/6 × The gravity on Earth
The weight of the support system Buzz Aldrin carries = 1760 N
a) Given that the weight of the support system on Earth = Mass of the support system, m × Gravity, g (Acceleration due to gravity) = m·g
The weight of the support system on Earth = m·g
We have;
The gravity on the moon = 1/6 × g
∴ The weight of the support system on the moon = Mass of the support system, m × 1/6 × g = m·g/6
∴ The weight on the of the support system on the moon = m·g/6 = 1/6 × m·g = 1/6 × m·g = 1/6 × The weight of the support system on Earth
The weight on the of the support system on the moon = 1/6 × 1760 N = 880/3 N = 293.[tex]\bar 3[/tex] N
b) The mass, m, of the support system on the moon = The mass, m, of the support system on Earth
The mass, m, of the support system on Earth = Weight of the support system/(Gravity(acceleration due to gravity))
∴ The mass, m, of the support system on Earth = 1760/9.81 ≈ 179.41 kg
∴ The mass, m, of the support system on the moon ≈ 179.41 kg.
1. Which elements would likely have similar properties: two elements in the same group, or two elements in the same period?
2. Fill in the table below with the correct classification of element.
Left side:
Right side:
Zigzag line:
3. Use the periodic table to answer this question: Are the properties of rubidium (Rb) more like those of cesium (Cs) or those of strontium (Sr)? Explain your answer.
4. Use the periodic table at the bottom of the page to identify the elements in the following compounds:
PBS:
KBr:
Rao:
5. Use the periodic table to determine whether each element is a metal or a nonmetal:
Sodium (Na):
Krypton (Kr):
Phosphorus (P):
Answer:
3. Cs, they are in the same group, mainly sharing characteristics.
Explanation:
The elements in the same group have similar properties. The properties of rubidium is similar to those of strontium because, both are in second group.
What are groups in periodic table ?In periodic table, all elements are classified into different periods and groups. The vertical columns in the table is called groups and the horizontal rows are called periods.
The elements in a group have same number of valence electrons and similar chemical and physical properties. For example rubidium and strontium are second group elements and they show similarity in properties.
The elements in the compound, PbS are lead and sulphur and that in KBr are potassium and bromine. Elements in RaO are radium and oxygen. Among the given elements sodium is a metal and krypton and phosphorus are non metals or gases.
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