A walking path across a park is represented by the equation y=-3x - 6. A new path will be built perpendicular to this path. The paths will intersect at the point (-3,3). Identify the equation that represents the new path 10- 20 10​

A Walking Path Across A Park Is Represented By The Equation Y=-3x - 6. A New Path Will Be Built Perpendicular

Answers

Answer 1

The equation of the new path would be y=1/3x+4.

Explanation

If two lines are perpendicular, their slopes are negative reciprocals of each other.  The original equation is written in slope-intercept form, y=mx+b, where m is the slope.  In this equation, m=-3=-3/1.

In the new equation, the slope would be the opposite sign and flipped; this means it would be 1/3.

We can use the point given, the slope and slope-intercept form to write the equation of the new line:

y=mx+b

3=1/3(-3)+b

3=1/3(-3/1)+b

3=(-3/3)+b

3=-1+b

Add 1 to both sides:

3+1=-1+b+1

4=b

This makes the equation y=1/3x+4.

Answer 2

Answer:

B

Step-by-step explanation:

> if the lines are perpendicular then their slopes are negative reciprocal so

y=mx+b , is the general form where is m = slope

y= -3x -4, old path has slope m= -3

y= (1/3)x +b , is the new path with slope m=(1/3)

>if the paths intersect at (-3,3) then this point is on the new path as well

y= (1/3)x +b, now substitute x= -3, and y=3 to find b

3 = (1/3)(-3)+b , divide -3/3

3= -1 +b, add 1 to both sides

4 = b

>the equation of the new path is

y= (1/3)x +4


Related Questions

can someone help me out

Answers

5.6 cm sry if i got it wrong

Given: The equation of a parabola is x2 = 8y.

Step 3: Where does the directrix for the given parabola lie? Enter the equation for the directrix line. Use your keyboard and the keypad to enter your answer. Then click Done.

Answers

Answer:

x=-2

Step-by-step explanation:

Answer:

Since a = 2, the equation for the directrix line will be y = −2.

Step-by-step explanation:

What is the axis of symmetry for y = 3x^2 + x - 2

Answers

Axis of Symmetry:
x= -1/6

pls pls pls pls help

Answers

Step-by-step explanation:

[tex]s = \pi \times {r}^{2} = \pi \times {6}^{2} = 36\pi[/tex]

[tex]h = 18 \times \sin(60) = 9 \sqrt{3} [/tex]

[tex]v = s \times h = 36\pi \times 9 \sqrt{3} = 324 \sqrt{3} \pi[/tex]

Emily puts away basketballs after the gym class. there are 15 basketballs, and each rack holds 4 basketballs. how many racks does Emily completely fill? How many basketballs are left?

Answers

Emily would completely fill 3 racks of baskets balls and she would have 3 basketballs left over.

4(number of basketballs each rack can hold) multiplied by 3 is equal to 12. Meaning 12 of the 15 basketballs will be able to go on a rack, and there would be 3 left over.(subtract 15-12 and you will get 3)

Answer:

emily fills 3 racks

3 basketballs are Left!

Step-by-step explanation:

15/4 = 3.3

A. -5x+4y=-20
B. -5x-4y=-20
C. -5x+4y=0
D. 5x+4y=-20

Answers

A is the answer because, when graphing, we use y= mx + b
So the first step is to change the equation into that.
We know m = the slope and b = the y-intercept

So,
m = y1-y2/x1-x2 ( I decided to use the intercepts)

The rest is on the paper, and sorry I wasn't neat with my working

Triangle Q R S is shown. Line R Q extends through point P. Angle Q S R is 35 degrees. Angle S R Q is 58 degrees. Exterior angle S Q P is x degrees. What is the value of x?

Answers

The triangle is missing and so i have attached it.

Answer:

x = 93°

Step-by-step explanation:

From the triangle attached, we can say that;

<SQP + <SQR = 180°

This is because sum of angles on a straight line equals 180°.

Secondly, we know that sum of angles in a triangle also equals 180°.

Thus;

<SQR + <QSR + <SRQ = 180

From the attached triangle, we see that;

<QSR = 35°

<SRQ = 58°

Thus;

<SQR + 35° + 58° = 180°

<SQR + 93° = 180°

<SQR = 180° - 93°

<SQR = 87°

From earlier on, we saw that;

<SQP + <SQR = 180°

Plugging in <SQR = 87°, we have;

<SQP + 87° = 180°

<SQP = 180° - 87°

<SQP = 93°

We are told in the question that <SQP is denoted by x.

Thus;

x = 93°

Answer:

The value of x is answer D: 93

help please tries 2 times

Answers

Answer:

(2,1)

Step-by-step explanation:

2x - 2y = 2

5x + 2y = 12

again just add them in this case

7x = 14

x = 2

4 - 2y = 2

-2y = -2

y = 1

Given an arithmetic progression 17,13,9,..... find the number of terms required so that its sum is - 33 .

Answers

Answer:

11 terms.

Step-by-step explanation:

We are given the arithmetic sequence:

17, 13, 9, ...

And we want to find the number of terms required such that the sum is -33.

Recall that the sum of an arithmetic series is given by:

[tex]\displaystyle S = \frac{k}{2}\left( a + x_k\right)[/tex]

Where k is the number of terms, a is the first term, and x_k is the last term.

The desired sum is -33. The first term is 17 as well. Thus:

[tex]\displaystyle (-33) = \frac{k}{2} \left( (17) +x_k\right)[/tex]

Simplify:

[tex]-66 = k(17 + x_k)[/tex]

We can write a direct formula to find the last term x_k. The direct formula of an arithmetic sequence has the form:

[tex]x_ n = a + d(n-1)[/tex]

Where a is the initial term and d is the common difference.

The initial term is 17 and the common difference is -4. Hence:

[tex]\displaystyle x_n = 17 - 4(n-1)[/tex]

Then the last term is given by:

[tex]x_k = 17 - 4(k-1)[/tex]

Substitute:

[tex]\displaystyle -66 = k\left( 17 + \left( 17 - 4(k-1)\right)\right)[/tex]

Solve for k:

[tex]\displaystyle \begin{aligned} -66 &= k(17 + (17 - 4k + 4)) \\ -66 &= k(38 -4k) \\ -66 &= -4k^2 + 38k \\ 4k^2 -38k -66 &= 0 \\ 2k^2 - 19k -33 &= 0 \\ (k-11)(2k+3) &= 0 \\ k-11&= 0 \text{ or } 2k+3 = 0 \\ \\ k &= 11 \text{ or } k = -\frac{3}{2}\end{aligned}[/tex]

Since we cannot have a negative amount of terms, we can ignore the second solution.

Therefore, the given sequence must have 11 terms such that it sums to -33.

Answer:

Here is 2 methods

Step-by-step explanation:

1) we use excel to find n=11 for lasy students

2) mathematical method

[tex]u_1=17\\u_2=13=17+(2-1)*(-4)\\u_3=9=17+(3-1)*(-4)\\\\\\\boxed{u_n=17+(n-1)*(-4)}\\\\\\\displaystyle s_n=\sum_{i=1}^nu_i\\=\sum_{i=1}^n(17+(i-1)*(-4))\\\\\\=(\sum_{i=1}^n 17) + (-4)*\sum_{i=1}^n (i) +4*\sum_{i=1}^n (1)\\\\\\=17*n+4*n-4*\frac{n*(n+1)}{2} \\\\\\=21n-2n^2-2n\\\\\\=-2n^2+19n\\\\=-33\\\\\\\Longrightarrow\ 2n^2-19n-33=0[/tex]

[tex]\Delta=19^2+4*2*33=625=25^2\\\\n=\dfrac{19-25}{4} =-1.5\ (excluded)\ or\ n=\dfrac{19+25}{4}=11\\\\[/tex]

A giant pie is created in an attempt to break a world record for baking. The pie is shown below:

What is the area of the slice of pie that was cut, rounded to the nearest hundredth?

Answers

Answer:

Area of the slice of pie = 22.09 ft²

Step-by-step explanation:

Area of the slice of pie = Area of the sector of the circle with the central angle 45°

Area of the sector = [tex]\frac{\theta}{360^{\circ}}(\pi r^{2} )[/tex] [Here, r = radius of the circle]

                              = [tex]\frac{45^{\circ}}{360^{\circ}}(\pi )(\frac{15}{2})^2[/tex]

                              = 22.09 ft²

Area of the slice of pie = 22.09 ft²

Answer:

22.08ft^2

Step-by-step explanation:

A = πr^2(x/360) d = 15

Since r is half of diameter this means that r = 15/2 =7.5

so Lets use the Area of Sector formua

A =3.14(7.5)^2 (45/360)

A =3.14(56.25) (45/360)

A = 176.625 (45/360)

A = 176.625 (0.125)

A = 22.078125

rounded to the nearest 10th would make it 22.08

Product of the zeroes of polynomial 3x²-2x-4 is ? No spam ❌ Want accurate answers ✔ No spa.

full explain​

Answers

9514 1404 393

Answer:

  -4/3

Step-by-step explanation:

Quadratic ax² +bx +c can be written in factored form as ...

  a(x -p)(x -q)

for zeros p and q. The expanded form of this is ...

  ax² -a(p+q)x +apq

Then the ratio of the constant term to the leading coefficient is ...

  c/a = (apq)/a = pq . . . . the product of the zeros

For your quadratic, the ratio c/a is -4/3, the product of the zeros.

_____

Additional comment

You will notice that the sum of zeros is ...

  -b/a = -(-a(p+q))/a = p+q

Answer:

[tex] \green{ \boxed{ \bf \: product \: of \: the \: zeros \: = - \frac{4}{3} }}[/tex]

Step-by-step explanation:

We know that,

[tex] \sf \: if \: \alpha \: and \: \beta \: \: are \: the \: zeroes \: of \: the \: \\ \sf \: polynomial \: \: \: \pink{a {x}^{2} + bx + c }\: \: \: \: then \\ \\ \small{ \sf \: product \: of \: zeroes \: \: \: \alpha \beta = \frac{constant \: term}{coefficient \: of \: {x}^{2} } } \\ \\ \sf \implies \: \pink{ \boxed{\alpha \beta = \frac{c}{a} }}[/tex]

Given that, the polynomial is :

[tex] \bf \: 3 {x}^{2} - 2x - 4[/tex]

so,

constant term c = - 4coefficient of x^2 = 3

[tex] \sf \: so \: product \: of \: zeroes \: \: = \frac{ - 4}{3} = - \frac{4}{3} [/tex]

which inequality is represented on the number line shown?

Answers

Answer: A x> -2

Step-by-step explanation:

After 10 years, Hamid's account earned $900 in interest. If the interest rate (in decimal form) is 0.08, how much did Hamid initially invest? Without substitution, solve the formula chosen in the previous step for the unknown variable in terms of the known variable(s).

Answers

Answer:

Hamid initially invested $1,125.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

[tex]E = P*I*t[/tex]

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After 10 years, Hamid's account earned $900 in interest.

This means that [tex]t = 10, E = 900[/tex]

Interest rate of 0.08:

This means that [tex]I = 0.08[/tex]

How much did Hamid initially invest?

We have to find P. So

[tex]E = P*I*t[/tex]

[tex]900 = P*0.08*10[/tex]

[tex]P = \frac{900}{0.8}[/tex]

[tex]P = 1125[/tex]

Hamid initially invested $1,125.

The polygons in each pair are similar. Find the missing side length.

Answers

Answer:

12

Step-by-step explanation:

We can say that two polygons are similar to each other if both of the polygons have the same shape and their corresponding sides are in the same proportion, hence the ratio of their corresponding sides are equal to each other.

As we can see from the problem since both of the polygons are similar, hence the ratio of their corresponding sides are in the same proportion, therefore let x represent the missing length, hence:

[tex]\frac{x}{15} =\frac{32}{40} =\frac{32}{40} \\\\\frac{x}{15} =\frac{32}{40} \\\\x=\frac{32*15}{40} \\\\x=12[/tex]

32
Two forces one is 10N and other is 6N act on a body The directions are unknown the resultant force on the body is
a. between 4 and 16N
b. more than 6N I
c. more than 1ON
d between 6 and 16N

Answers

If Forces are acting on opposite direction

[tex]\\ \rm\hookrightarrow F_{net}=F_2-F_1[/tex]

[tex]\\ \rm\hookrightarrow F_{net}=10-6[/tex]

[tex]\\ \rm\hookrightarrow F_{net}=4N[/tex]

If both acting on same direction

[tex]\\ \rm\hookrightarrow F_{net}=F_1+F_2[/tex]

[tex]\\ \rm\hookrightarrow F_{net}=10+6[/tex]

[tex]\\ \rm\hookrightarrow F_{net}=16N[/tex]

Hence

[tex]\boxed{\sf 4N\leqslant F_{net}\leqslant 16N}[/tex]

Helpo pleasssse
On my hw I have a parabola that opens down with its vertex at (-3,-6)......
For the range would I say that {yER | y > -6} OR {yER | y < -6} ????
I'm just confused from the negative numbers

Answers

Answer: The range is  [tex]\{y \in \mathbb{R}\ | \ y \le -6\}[/tex]

Explanation:

The parabola opens down, forming a "frowny face" in a way (just without the eyes). Or you can think of it as a hill or mountain. This means that the vertex (-3,-6) is at the top of that mountain. It's the highest point of that parabola.

The range is the set of all possible y values. We see that y = -6 is the largest it can get. So y = -6 or y is smaller than this. We would then write [tex]y \le -6[/tex] to describe all the possible y values.

Therefore, the range is [tex]\{y \in \mathbb{R}\ | \ y \le -6\}[/tex]

This translates to "y is a real number such that y is -6 or smaller".

So the second answer you wrote is close, but you forgot the "or equal to" portion of the inequality sign.

See below for a visual example of what's going on.

how many degrees does a unit angle measure a 10° B 90° c 180 degrees d 100 degrees​

Answers

Ksbujbtskbzbiz kshg

Sjhhzjz

can i get some help solving this

Answers

Answer:

A =147 cm^2

Step-by-step explanation:

A = pi r^2

The radius is 7 and let pi = 3

A = 3*7^2

A = 3*49

A =147

The expression 13.25×5+6.5 gives the total cost in dollars of renting a bicycle and helmet for 5 days. The fee for the helmet does not depend upon the number of days.

Answers

Answer:

13.25×5+13, cost per day with a helmet.

Step-by-step explanation:

Numerical Expressions • Practice

Answer:

13.25×5+13, Per day without a helmet

Step-by-step explanation:

It took francisco 60 minutes to walk from his house to his grandmother’s house. what is 60 written as a product of factors greater than 1? each factor can have only 1 and itself as factors.

Answers

Answer:

2 × 2 × 3 × 5

Step-by-step explanation:

Given that,

The number = 60

To find,

Factors of 60 greater than 1 = ?

Procedure:

As we know,

Any of various numbers multiplied together to form a whole.

To find the factors of a number, we will have to do its prime factorization.

So,

The prime factorization of 60:

1 * 2 * 2 * 3 * 5 = 60

Since the factors greater than 1 are asked, the factors would be;

2 * 2 * 3 * 5

Thus, 2 * 2 * 3 * 5 is the correct answer.

y=8200(0.96)^x growth or decay find

Answers

Answer:

This would be a .04 or 4% decay.....

for every "time unit" (x in this case) you will be multiplying

the amount by .96 ... in other words if you started with one dollar

the results would be 96 cents... after two "time" steps you would have

only 92 cents (.96 *.96)

Step-by-step explanation:

b) 2x (x - y) + 3y (x - y)​

Answers

Use distributive law

[tex]\boxed{\sf a(b+c)=ab+ac}[/tex]

Now

[tex]\\ \sf\longmapsto 2x(x-y)+3y(x-y)[/tex]

[tex]\\ \sf\longmapsto 2x^2-2xy+3xy-3y^2[/tex]

[tex]\\ \sf\longmapsto 2x^2-3y^2-2xy+3x^2[/tex]

[tex]\\ \sf\longmapsto 2x^2-3y^2+xy[/tex]

Taking common

Answer: 2x (x-y) + 3y (x-y)

             = ( x-y ) ( 2x-3y )

I really need this answered!

Answers

Answer:

Its AA similaroty theorem

Suppose that d varies jointly with r and t, and d = 110 when r = 55 and t = 2. Find r when d = 40 and t = 3.

Answers

Answer:

r = 13.33

Step-by-step explanation:

d = k*r*t

Where,

k = constant of proportionality

d = 110 when r = 55 and t = 2

d = k*r*t

110 = k * 55 * 2

110 = 110k

k = 110/110

k = 1

Find r when d = 40 and t = 3

d = k*r*t

40 = 1 * r * 3

40 = 3r

r = 40/3

= 13.333333333333

Approximately,

r = 13.33

A walker has travelled 9 km along a trail. If he has completed 80% of the trail, how much further does he still have to go?

Answers

Answer:

2.25 km to go

Step-by-step explanation:

In order to get this answer, you have to figure out how many km 10% is, 0.1125. Then multiply that by the remaining 20% because he already finished 80% of the trail. So, 0.1125 x 20 = 2.25.

Hope this helps! :)

sin x = 4/5, cos x = 2/5 find the value of tan x​

Answers

Answer:

2 is the answer . the explanation is in the attachment .

A person walks on average 4000 steps per day. If one step is about 2 feet long, how much would the average person walk per week? HELP

Answers

Answer:

56000 ft

Step-by-step explanation:

4000 steps a day.

7 days in a week.

2 ft per step

so, we calculate how many steps in a week

4000 × 7 = 28000

and then we calculate the distance by saying each of these steps is 2 ft

so,

28000 × 2 = 56000 ft

as a little extra thought :

there are 5280 ft in a mile.

so, the person walks

56000 / 5280 miles = 10.61 miles

in a week.

Find the values of x and y.

Answers

Answer:

I think it's 43 and 43 degrees. I just subtracted 180-94, got 86, and divided it so yea.

Can someone help me on this please

Answers

I’m pretty sure it would be K because it is a constant with units of dollars per square foot.
Hope this helps :D

please ans this question pleaseee​

Answers

Answer:

[tex]{ \tt{ \tan {}^{4} \theta + { \sec }^{2} \theta }} \\ { \tt{ = ({ \tan }^{2} \theta ){}^{2} + { \sec }^{2} \theta }} \\ = { \tt{ {-(1 - { \sec }^{2} \theta) }^{2} + { \sec }^{2} \theta }} \\ { \tt{ = -(1 - 2 { \sec }^{2} \theta + { \sec }^{4} \theta) + { \sec}^{2} \theta}} \\ { \tt{ = -(1 - { \sec }^{2} \theta) + { \sec }^{4} \theta}} \\ { \tt{ = -{ \tan}^{2} \theta + { \sec }^{4} \theta }} \\ = { \tt{ { \sec}^{4} \theta - { \tan }^{2} \theta}} \\ { \bf{hence \: proved}}[/tex]

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