A volcanic eruption launches two rocks of different masses into the air. The first rock had a mass of 10 kilograms while the second rock had a mass of 20 kilograms.

At the eruption, both rocks accelerated at a rate of 600 m/s2. Which of the following statements is true regarding the eruption of the two rocks?
The amount of force applied to rock one was twice as much as the force applied to rock two during the eruption.
The amount of force applied to rock one was the same as the force applied to rock two during the eruption.
The amount of force applied to rock one was half the amount of force applied to rock two during the eruption.
The amount of force applied to the rocks is impossible to determine without knowing the inertia of the rocks.

Answers

Answer 1

Answer:

C. The amount of force applied to rock one was half the amount of force applied to rock two during the eruption.

Explanation:

A force is an agent which changes the state of an object well applied to it. Second Newton's law of motion state's that;

F = ma

where F is the force, m is the mass of the object and a is the acceleration of the object.

In the given question,

Mass of first rock = 10 kilograms

Mass of the second rock = 20 kilograms

Acceleration of the two rocks = 600 m/[tex]s^{2}[/tex]

Thus,

Force on the first rock = ma

                                    = 10 x 600

                                    = 6000 N

Force on the second rock = 20 x 600

                                   = 12000 N

Therefore, it can be observed that the amount of force applied to rock one was half the amount of force applied to rock two during the eruption.

Answer 2

The statement that is true regarding the eruptions of the two rocks is;

Option C; The amount of force applied to rock one was half the amount of force applied to rock two during the eruption.

We are given;

Mass of first rock; m1 = 10 kg

Mass of second rock; m2 = 20 kg

Acceleration of both rocks; a = 600 m/s²

The formula for Force applied is;

F = ma

Where;

m is mass

a is acceleration

Now;

Force applied on first rock; F1 = m1 × a

F1 = 10 × 600

F1 = 6000 N

Force applied on second rock; F2 = m2 × a

F2 = 20 × 600

F2 = 12000 N

We can see that the force applied to rock 1 was half the amount of force applied to rock 2.

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C. 7m
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Explanation:

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A car with a mass of 1600 kg is towing a trailer with a mass of 420 kg. The car
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1 point
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Answers

Answer:the same

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According to Newton's law, the force exerted by the bug and car is equal and opposite. Thus their acceleration decreases as mass increases. Therefore the acceleration of bug will be greater than that of the car.

What is acceleration?

Acceleration, in physics is the rate of change in velocity. Thus it has the unit m/s². Newton's second law of motion states that the force acting on a moving body is the product of its mass and acceleration.

Hence F=  m a indicates that the acceleration is in inverse proportionality with the mass. Thus a body with greater mass will have smaller acceleration but greater force.

According to third  law of motion, an action have an equal opposite reaction. Thus the force exerted by the bug on the car and the force exerted by the car on bug are equal and opposite where, the bug will have greater acceleration due to its less mass.

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What is the density of an object with a mass of 20 grams and a volume of 5 cm?

Answers

Answer:

4

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Divide mass(m) by volume(v), you get density(D)

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1. Which statement best describes the motion of the scooter? *
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2. What is the velocity of the scooter? *
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Answers

Answer:

HI

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its E

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b: alternative units of measurement
c : units of length and width
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Answers

Answer:

snoemw

Explanation:

Which pair of concurrent forces could produce a resultant force having a magnitude of 10. Newtons?

Answers

The pair of concurrent  forces will be of 5 N to make the magnitude of net force as 10 N.

Given data:

The magnitude of resultant force is, [tex]F_{net}=10 \;\rm N[/tex].

The given problem is based on the concept of concurrent forces which says that, If the forces applied to a body are such that their lines of action meet at a single point, then they are called concurrent forces.

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Thus, we conclude that the pair of concurrent forces will be of 5 N to make the magnitude of net force as 10 N.

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An object weighing 49 N is pushed across a floor by a force of 12 N. What is the acceleration of the object?

Answers

Answer:

Explanation:

Given parameters:

Weight of object  = 49N

Force applied = 12N

Unknown:

Acceleration of object  = ?

Solution:

The acceleration of the object is found by dividing the force by the weight;

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Answer:

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Explanation:

The factor that impact the amount of potential and kinetic energy should be explained below.

Factor impact the amount of energy:

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

To send a pulse of different speed, change the tension or stretch on the spring

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कृपया ब्रेनलिस्ट का उत्तर केवल 1more उत्तर देने का प्रयास करें।

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Electric power is to be generated by installing a hydraulic turbine-generator at a site 70 m below the free surface of a large water reservoir that can supply water at a rate of 1500 kg/s steadily. If the mechanical power output of the turbine is 800 kW and the electric power generation is 750 kW, determine the turbine efficiency and the combined turbine–generator efficiency of this plant. Neglect losses in the pipes.

Answers

Answer:

[tex]\eta_{turbine} = 0.777 = 77.7\%[/tex]

[tex]\eta_{combined} = 0.728 = 72.8\%[/tex]

Explanation:

First we calculate the power input to the turbine. The input power will be equal to the potential energy of water per unit time:

Input Power = [tex]P_{in} = \frac{Work}{Time} = \frac{Potential\ Energy\ of\ Water}{t} \\P_{in} = \frac{(mass)(g)(height)}{Time} = (mass flow rate)(g)(height)\\\\P_{in} = (1500\ kg/s)(9.81\ m/s^2)(70\ m)\\P_{in} = 1.03\ x\ 10^6\ W = 1030\ KW[/tex]

Now, for turbine efficiency:

[tex]\eta_{turbine} = \frac{Mechanical\ Power\ Out}{P_{in}}\\\\\eta_{turbine} = \frac{800\ KW}{1030\ KW}\\\\\eta_{turbine} = 0.777 = 77.7\%[/tex]

for generator efficiency:

[tex]\eta_{generator} = \frac{Power\ Generation}{Mechanical\ Power\ Out}\\\\ \eta_{generator} = \frac{750\ KW}{800\ KW}\\\\\eta_{turbine} = 0.9375 = 93.75\%[/tex]

Now, for combined efficiency:

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A stone takes 5.4 seconds to fall from the top of a cliff. The cliff is
meters high.
143
53
286
573

Answers

Answer:

143

Explanation:

Using one of the 3 fundamental equations in physics, y=vo*t+1/2gt^2, we can use this equation to find the total distance that was traveled.

Acceleration due to gravity is always 9.8m/s^2 and time is 5.4s, we also have no initial velocity.

Given this, we can plug in the known variables.

y=0t+1/2*9.8*5^2

simplify,

y=4.9*5.4^2

y=4.9*29.16

y=142.884m which we can round up to 143 meters

Final Answer: 143 meters

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