Answer:
0.7513 = 75.13% probability that no more than 1 employee was over 50
Step-by-step explanation:
The employees are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
4 + 16 = 20 employees, which means that [tex]N = 20[/tex]
4 over 50, which means that [tex]k = 4[/tex]
5 were dismissed, which means that [tex]n = 5[/tex]
What is the probability that no more than 1 employee was over 50?
Probability of at most one over 50, which is:
[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 0) = h(0,20,5,4) = \frac{C_{4,0}*C_{16,5}}{C_{20,5}} = 0.2817[/tex]
[tex]P(X = 1) = h(1,20,5,4) = \frac{C_{4,1}*C_{16,4}}{C_{20,5}} = 0.4696[/tex]
Then
[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.2817 + 0.4696 = 0.7513[/tex]
0.7513 = 75.13% probability that no more than 1 employee was over 50
Find the solution of the differential equation that satisfies the given initial condition. (dP)/(dt)
Answer:
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
Step-by-step explanation:
Given
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]P(1) = 2[/tex]
Required
The solution
We have:
[tex]\frac{dP}{dt} = \sqrt{Pt[/tex]
[tex]\frac{dP}{dt} = (Pt)^\frac{1}{2}[/tex]
Split
[tex]\frac{dP}{dt} = P^\frac{1}{2} * t^\frac{1}{2}[/tex]
Divide both sides by [tex]P^\frac{1}{2}[/tex]
[tex]\frac{dP}{ P^\frac{1}{2}*dt} = t^\frac{1}{2}[/tex]
Multiply both sides by dt
[tex]\frac{dP}{ P^\frac{1}{2}} = t^\frac{1}{2} \cdot dt[/tex]
Integrate
[tex]\int \frac{dP}{ P^\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Rewrite as:
[tex]\int dP \cdot P^\frac{-1}{2} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the left hand side
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{-1}{2}+1} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]\frac{P^{\frac{-1}{2}+1}}{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
[tex]2P^{\frac{1}{2}} = \int t^\frac{1}{2} \cdot dt[/tex]
Integrate the right hand side
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{1}{2} +1 }}{\frac{1}{2} +1 } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{t^{\frac{3}{2}}}{\frac{3}{2} } + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex] ---- (1)
To solve for c, we first make c the subject
[tex]c = 2P^{\frac{1}{2}} - \frac{2}{3}t^\frac{3}{2}[/tex]
[tex]P(1) = 2[/tex] means
[tex]t = 1; P =2[/tex]
So:
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1^\frac{3}{2}[/tex]
[tex]c = 2*2^{\frac{1}{2}} - \frac{2}{3}*1[/tex]
[tex]c = 2\sqrt 2 - \frac{2}{3}[/tex]
So, we have:
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + c[/tex]
[tex]2P^{\frac{1}{2}} = \frac{2}{3}t^\frac{3}{2} + 2\sqrt 2 - \frac{2}{3}[/tex]
Divide through by 2
[tex]P^{\frac{1}{2}} = \frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3}[/tex]
Square both sides
[tex]P = (\frac{1}{3}t^\frac{3}{2} + \sqrt 2 - \frac{1}{3})^2[/tex]
This Bar Chart shows the number of DVDs sold at a local music store during one week.
Which measure(s) of central tendency can be used to determine the average number of DVDs sold each day?
A. the median
B. the mean
C. the mean and the median
D. the mode
Answer:
B. the mean
Step-by-step explanation:
According to the Bar Chart shown, the number of DVDs sold at a local music store during one week are displayed.
Therefore, the measure(s) of central tendency that can be used to determine the average number of DVDs sold each day is the mean.
This is because the mean is the sum total of the number of DVDs sold, divided by the number, which gives the average.
Answer:
The Mean
Step-by-step explanation:
I took the test
Graph the solution set to this Inequality.
-2x + 9 < 51 12
Answer:
X<-2551.5
Step-by-step explanation:
-2x<5112-9
-2x/-2<5103/-2
x<-2551.5
What angles can you construct using just a pair of compasses and a ruler?
Answer:
By using a pair of compasses and a ruler you can draw all angles
Can someone help me please! Thanks
Answer:
hello again.. I think you have a problem about figures
Step-by-step explanation:
please be brave when you try to solve..try to draw new lines to get angle and then look at the overall of shape.. the photo helps you good bye
Calculate the difference and enter it below
-6 - 12
Answer:
-18
Step-by-step explanation:
Answer: -18 is the difference
Step-by-step explanation:
Evaluate = -18
Solve the following inequality.
- 202-16
Which graph shows the correct solution?
Can anyone help me please? I've been trying for so long, but I can't figure out the answer to this problem. Picture attached. Thank you so much.
Answer:
C
Step-by-step explanation:
Start by simplifying what you can in each radicalfor example, the
∛(xy⁵)= y∛(xy²)
and
∛(x⁷y¹⁷)=x²y⁵∛(xy²)
So know our equation looks like
y∛(xy²)*x²y⁵∛(xy²)
Now because what's inside the radical is the same we can combine them
y⁶x²∛(xy²)²
distribute the square
so
∛(xy²)²= ∛(x²y⁴)= y∛(x²y)
and finally,
y⁶x²*y∛(x²y)= y⁷x²∛(x²y)
this is equal to option C
solve 5x^2-2=-12 by taking the square root
Answer:
[tex]x = \sqrt{-2} = 2i[/tex]
Step-by-step explanation:
[tex]5x^2-2=-12[/tex]
[tex]5x^2 =-10[/tex]
[tex]x^2 =-2[/tex]
[tex]x = \sqrt{-2} = 2i[/tex]
Gloria received a 4 percent raise and is now making $24,960 a year, what was her salary before the raise?
She gets a 4% raise so her new pay is 100% + 4% of her previous pay.
104% = 1.04 as a decimal.
Divide her new pay by 1.04:
24,960 / 1.04 = 24,000
Her previous pay was $24,000
How do you graph this helppp and explain
Answer:
bottom graph
Step-by-step explanation:
f(x) = |3q-6|
because you have absolute value there are 2 possibilities
y= +(3q-6) and y= -(3q-6)
to find where the graph intersects the x-axis make y=0 because there the y coordinate is 0, so we have...
3q-6 =0 and -3q+6 =0
3q= 6 and -3q =-6
q=2 and q=2
the bottom graph has the intersection with x-axis only at 2, so is the correct one
9514 1404 393
Answer:
bottom graph shown
Step-by-step explanation:
It can be helpful to rearrange the equation to either of the equivalent forms ...
f(x) = |3(x -2)|
or ...
f(x) = 3|x -2|
_____
The first of these forms represents a horizontal compression of the absolute value function by a factor of 3, then a right-shift by 2 units. This matches the bottom graph shown.
__
The second of these forms represents a horizontal right-shift by 2 units, and a vertical expansion by a factor of 3. This matches the bottom graph shown.
__
The attached graph shows the function given here along with the absolute value parent function.
_____
Additional comment
The transformations we're usually interested in are ...
g(x) = k·f(x) . . . . vertically scaled (stretched) by a factor of k
g(x) = f(kx) . . . . .horizontally compressed by a factor of k
g(x) = f(x) +k . . . shifted up by k units
g(x) = f(x -k) . . . . shifted right by k units
In many cases, as here, horizontal scaling and vertical scaling are indistinguishable as to which caused a given effect.
HELPPPP ME ASAP
If f(x) = x2, g(x) = 5x, and h(x) = x +4, find each value.
Find g[h(-2)]
9514 1404 393
Answer:
10
Step-by-step explanation:
Put the values where the arguments are and do the arithmetic.
g(h(-2)) = g(-2+4) = g(2) = 5(2)
g(h(-2)) = 10
on the provided graph, plot the points where the following function crosses the x-axis and the y-axis g(x) = -5^x + 5, what does the graph look like?
Answer:
see image
Step-by-step explanation:
Put -3.0-3.45, -15, and -3.15 in order from least to greatest.
Answer:
-15 -3.45 -3.15 -3.0
Step-by-step explanation:
A plane flying horizontally at an altitude of 2 miles and a speed of 410 mi/h passes directly over a radar station. Find the rate at which the distance from the plane to the station is increasing when it is 5 miles away from the station.
Answer:
[tex]82\sqrt{21}\text{ or approximately 375.77 miles per hour}[/tex]
Step-by-step explanation:
Please refer to the diagram below. R is the radar station and x is the distance from the station to the plane.
We are given that the plane is flying horizontally at an altitude of two miles and at a speed of 410 mph. And we want to find the rate at which the distance from the plane to the station is increasing when it is five miles away from the station.
In other words, given da/dt = 410 and x = 5, find dx/dt.
From the Pythagorean Theorem:
[tex]a^2+4=x^2[/tex]
Implicitly differentiate both sides with respect to time t. Both a and x are functions of t. Hence:
[tex]\displaystyle 2a\frac{da}{dt}=2x\frac{dx}{dt}[/tex]
Simplify:
[tex]\displaystyle a\frac{da}{dt}=x\frac{dx}{dt}[/tex]
Find a when x = 5:
[tex]a=\sqrt{5^2-2^2}=\sqrt{21}[/tex]
Therefore, dx/dt when da/dt = 410, x = 5, and a = √(21) is:
[tex]\displaystyle \frac{dx}{dt}=\frac{(\sqrt{21})(410)}{5}=82\sqrt{21}\approx 375.77\text{ mph}[/tex]
The rate at which is distance from the plane to the radar station is increasing at a rate of approximately 375.77 miles per hour.
. a) In a group of 75 students, 20 liked football only, 30 liked cricket only and 18 did not like any of two games? (i) How many of them liked at least one game? (ii) Find the number of students who liked both the games. (iii) How many of them liked football? (iv) How many of them liked cricket? (v) Represent the result in a Venn diagram.
i)50
Steps
30+20=50
ii)7
Steps
75-(30+20)-18
=75-(50)-18
=7
iii)20
Steps
From the available data from the question
iv)30
Steps
From the available data from the questionl
v)From the attcged image file
What is 5.071 in words?
Answer:
Step-by-step explanation:
The number 5.071 written in english words is "five and seventy-one thousandths
A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression. How many people clicked on the banner ad
Answer:
300
Step-by-step explanation:
[tex] \frac{1.5}{100} = 20000 \\ 20000 \div 100 = 200 \\ 200 \times 1.5 = 300[/tex]
if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad
What is Percentage?percentage, a relative value indicating hundredth parts of any quantity.
A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression.
We need to find how many people clicked on the banner ad.
Let us find the value of 1.5% of 20000
Convert 1.5 % to decimal
1.5/100=0.015
Now multiply 0.015 with 20000
0.015×20000
300
Hence, if A banner ad created by Jonathan had CTR of 1.5% with 20,000 impression then 300 people clicked on the banner ad
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Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2
[tex]{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}[/tex]
[tex]\small\color{blak}{{\underline{\bold{ Find \:a X } } } }[/tex]
[tex]\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } } } \\ = 173 = 25x - 2 \\ = - 25x = - 2 - 173 \\ = - 25x - 175 \\ = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}[/tex]
[tex]\small\color{blak}{{\underline{\bold{ Find\:a\:m<QSR } } } }[/tex]
[tex]\small\color{blak}{{\underline{\bold{ 10(7)-2 } } } }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m<QSR=68°\:\:\:\: }}}}[/tex]
[tex]\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}[/tex]
The measure of angle QSR is 68 degrees.
What is substitution?Substitution means putting numbers in place of letters to calculate the value of an expression.
According to the given question.
m ∠TSQ = 15x
m ∠TSR = 173 degrees
m ∠QSR = 10x -2
Since,
m ∠TSR = m ∠TSQ + ∠QSR
Substitute the value of m ∠TSR, m ∠TSQ and m ∠QSR in the above expression.
⇒ [tex]173 = 15x + 10x - 2[/tex]
⇒ [tex]173 = 25x - 2[/tex]
⇒ [tex]175 = 25x[/tex]
⇒ [tex]x = \frac{175}{25}[/tex]
⇒ [tex]x = 7[/tex]
Again, for finding the value of angle QSR substitute the value of x in 10x - 2.
Therefore,
m ∠QSR = 10(7) - 2
⇒ m ∠QSR = 70 - 2
⇒ m ∠QSR = 68 degrees
Hence, the measure of angle QSR is 68 degrees.
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Where does the graph of f(x)=2√-x+2 start?
A. (−2,0)
B. (2,0)
C. (0,2)
D. (0,−2)
Evaluate double integral of f(u,v)=∬dudv over region R where R is bounded by v^2-nu=0 , v^2-(n+1)u=0 and uv=n,uv=(n+1). Sketch neat graph and shade the bounded region. Clearly mention the points of intersection. Reverse the order of integration then evaluate. Where n is 100.
Answer:
5670272728262728227627
Which law would you use to simplify the expression?
Answer:
A. quotient of Powers
Step-by-step explanation:
hope it helps
Answer:
A. Quotient of powers
Step-by-step explanation:
Hope it helps
1. Find the exact value of sin( a−B), given that sin a=−4/5 and cos B=12/13, with a in quadrant III and B in quadrant IV.
2. Find all real numbers in the interval [0,2pi) that satisfy the equation.
3sec^2 x tan x =4tan x
3. Simplify the following trigonometric expressions, using identities as needed:
sin(x)/1−cos(x) + 1−cos(x)/sin(x)
(1) Recall that
sin(x - y) = sin(x) cos(y) - cos(x) sin(y)
sin²(x) + cos²(x) = 1
Given that α lies in the third quadrant, and β lies in the fourth quadrant, we expect to have
• sin(α) < 0 and cos(α) < 0
• sin(β) < 0 and cos(β) > 0
Solve for cos(α) and sin(β) :
cos(α) = -√(1 - sin²(α)) = -3/5
sin(β) = -√(1 - cos²(β)) = -5/13
Then
sin(α - β) = sin(α) cos(β) - cos(α) sin(β) = (-4/5) (12/13) - (-3/5) (-5/13)
==> sin(α - β) = -63/65
(2) In the second identity listed above, multiplying through both sides by 1/cos²(x) gives another identity,
sin²(x)/cos²(x) + cos²(x)/cos²(x) = 1/cos²(x)
==> tan²(x) + 1 = sec²(x)
Rewrite the equation as
3 sec²(x) tan(x) = 4 tan(x)
3 (tan²(x) + 1) tan(x) = 4 tan(x)
3 tan³(x) + 3 tan(x) = 4 tan(x)
3 tan³(x) - tan(x) = 0
tan(x) (3 tan²(x) - 1) = 0
Solve for x :
tan(x) = 0 or 3 tan²(x) - 1 = 0
tan(x) = 0 or tan²(x) = 1/3
tan(x) = 0 or tan(x) = ±√(1/3)
x = arctan(0) + nπ or x = arctan(1/√3) + nπ or x = arctan(-1/√3) + nπ
x = nπ or x = π/6 + nπ or x = -π/6 + nπ
where n is any integer. In the interval [0, 2π), we get the solutions
x = 0, π/6, 5π/6, π, 7π/6, 11π/6
(3) You only need to rewrite the first term:
[tex]\dfrac{\sin(x)}{1-\cos(x)} \times \dfrac{1+\cos(x)}{1+\cos(x)} = \dfrac{\sin(x)(1+\cos(x))}{1-\cos^2(x)} = \dfrac{\sin(x)(1+\cos(x)}{\sin^2(x)} = \dfrac{1+\cos(x)}{\sin(x)}[/tex]
Then
[tex]\dfrac{\sin(x)}{1-\cos(x)}+\dfrac{1-\cos(x)}{\sin(x)} = \dfrac{1+\cos(x)+1-\cos(x)}{\sin(x)}=\dfrac2{\sin(x)}[/tex]
Name some real-life situations where graphing could be useful. Discuss your ideas. Name some real-life situations where finding the coordinates of the midpoint of a line segment could be useful.
Answer:
mapping an area
Step-by-step explanation:
One situation and probably the most common is mapping an area. Graphs are great for dividing a geographical location into various sections and creating a model representation of the area. The graph itself allows for specific directions to be shared using the x and y coordinates on the graph. The same applies for finding the midpoint of a line segment. For example, this is useful if you were trying to find a place to meetup with a friend that is an equal distance from where you are and from where your friend is currently located. Therefore, allowing you to meetup at the midpoint.
Does the expression represents a positive or negative 3(-2 1/3)
Answer:
Positive
Step-by-step explanation:
This is an equation, with distribution in it. The number on the outside is positive, and the one inside is negative. Furthermore, since the number on the outside is larger than the one inside, the outcome will be positive.
Answer:
positive
Step-by-step explanation:
when both positive and negative will multiply then will makes negatives. so negative is correct option.
HELP AGAIN sorry
What is the measure of ∠AOB?
The measure of angle ∠AOB is 180°. The correct option from the following is (A).
A turn's angle is quantified using degrees or °. A full turn encompasses 360°. A protractor can be used to determine the size of an angle. The term "acute" refers to an angle smaller than 90°. Obtuse refers to an angle between 90° and 180°. Reflex is an angle larger than 180 degrees. Right angles have an angle of exactly 90 degrees.
A quadrilateral is an enclosed form created by uniting four points, any three of which cannot be collinear. A quadrilateral is a polygon that has four sides, four angles, and four vertices. Let us study more about quadrilaterals' shapes, their characteristics, and the various kinds of quadrilaterals, as well as some examples of quadrilaterals.
For the given quadrilateral, the sum of angles is:
∠A + ∠O + ∠B = ∠AOB
60° + 60° + 60° = 180°
Hence, the correct option is (A).
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Solve for x in the triangle. Round your answer to the nearest tenth.
Answer:
7.3 units
Step-by-step explanation:
Hi there!
We're given an angle and one leg of this right triangle and we must solve for the other leg. Given this circumstance, we can use the tangent ratio:
[tex]tan\theta=\frac{opposite}{adjacent}[/tex]
Plug in all values
[tex]tan39=\frac{x}{9}\\9*tan39=x\\7.3=x[/tex]
Therefore, the value of x when rounded to the nearest tenth is 7.3 units.
I hope this helps!
Please help me i will give you brainlest
Answer:
a speaker receive credibility is a combination of competence trustworthiness and caring
prove that
[tex]2 \tan30 \div 1 + tan ^{2} 30 = sin60[/tex]
prove that
.
Step-by-step explanation:
2tan 30° / 1 + tan² 30° =
2(⅓√3) /1 + (⅓√3)² =
⅔√3 / 1+ ⅓ =
⅔√3 / 4/3 =
2/4 √3 =
½√3 = sin 60° (proven)
With a.b.c=1 and a+b+c=1
Prove that:
Answer:
HOPE IT HELPS PLZ MARK ME BRAINLIEST
Step-by-step explanation:
abc=1
⟹c=1/ab
1/(1+a+1/b)+1/(1+b+1/c)+1/(1+c+1/a)
=1/(1+a+1/b)+1/(1+b+ab)+1/(1+1/ab+1/a)
=b/(1+b+ab)+1/(1+b+ab)+ab/(1+b+ab)
=1+b+ab/(1+b+ab)
=1
