Answer:
it should be 3 so letter c
Step-by-step explanation:
I hope this help
If 5k = -25, then 5k - 1 = -25 - 1
Segment proof
Create a triangle ABC of your choice. Using GeoGebra tools, construct the angle bisectors of ∠A and ∠B. Mark the intersection point of the angle bisectors, and label it point D.
Create a line through point D perpendicular to .
Find the intersection of line segment and the perpendicular line, and label it point E. With point D as the center, create a circle passing through point E.
Measure and label the radius of the inscribed circle of ΔABC on the diagram.
Take a screenshot of your result, and paste it below.
The steps to create attached screenshot of the inscribed circle of triangle ΔABC using GeoGebra tools includes;
1) Clicking on the Geometry link, under Powerful Math Apps group
2) On the opened Geometry page click on the Polygon icon and follow the instructions that come up, which is Select all vertices and then the first vertex (selected) again (a second time)
3) Once the triangle is created, select the Angle Bisector icon, under the Construct group; A message will appear, asking to Select three points or two lines, select three vertex, of the triangle created with a mouse click, with the vertex A in the center, such as BAC, or CAB a straight line representing the angle bisector of angle ∠A is created
4) Repeat the above to create the angle bisector of angle ∠B
5) Click on the Point button under the Basic Tools group, then click on the intersection of the two angle bisectors created above, the point will be automatically labelled point D
6) Click on the Perpendicular Line, icon under the Construct group, then click on point D, and then the line AB to draw the perpendicular from D to AB
7) Click on the point Point icon and then the intersection point of the perpendicular from D and AB to label the point E
8) Click on the Circle with Center basic tool and then points D and E above, to create the inscribed circle of triangle ΔABC
9) Select the Segment tool, then select the center of the circle and a point
on the circumference. Click on the label, from the pop up options, select
the label option AA then change the label of the segment created to Radius
and select Show Label and Show Value. The inscribed circle of ΔABC created with GeoGebra tools is attached
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Answer:
Step-by-step explanation: from edmentum
What is the answer for 76 = -4b
Answer:
-19 = b
Step-by-step explanation:
76 = -4b
Divide each side by -4
76/-4 = 4-b/-4
-19 = b
Answer:
b = -19
Step-by-step explanation:
76 = -4b
shift -4 to the left hand side and when you shift -4 divides 76
76/-4 = b
-19 = b
hello i need help someone please!!
find the inverse of this relation
h(t) = -6t + 7
Answer:
73
Step-by-step explanation:
Answer:
[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]
Step-by-step explanation:
let y = h(t) and rearrange making t the subject
y = - 6t + 7 ( add 6t to both sides )
6t + y = 7 ( subtract y from both sides )
6t = 7 - y ( divide both sides by 6 )
t = [tex]\frac{7-y}{6}[/tex]
Change y back into terms of x with t = [tex]h^{-1}[/tex] (t)
[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]
f(x) =-x^2+x+13
find f(9)
Answer:
f(9) = - 59
Step-by-step explanation:
Substitute x = 9 into f(x) , that is
f(9) = - (9)² + 9 + 13
= - 81 + 22
= - 59
Answer:
-59
Step-by-step explanation:
f(x) =-x^2+x+13
Let x = 9
f(9) = - (9)^2 +9+13
= -81 +9+13
= -59
What is the solution set of { x | x <-5} n { x | x >5 }? Help needed!
Answer:
The Empty set............
Answer:
There is no solution for the intersection of these two sets, as they do not intersect! They don't have any numbers in common and thus form an empty set. The correct answer choice is option D. the empty set.
Step-by-step explanation:
The solution for { x | x <-5} is ---> x < -5
The solution for { x | x >5 } is ---> x > 5
If you placed the two sets on a number line close to each other, you would see that they do not intersect. Thus there is no solution for the intersection of set A and set B as defined in the given problem.
See the graph for better understanding. You see how there's an empty space or area between -5 and 5? Yeah, this is called the empty set which is option D from your answer choices.
The mean of 14 numbers is 49. Removing one of the numbers causes the mean to decrease to 43. What number was removed?
Answer:
126 was removed.
Step-by-step explanation:
The total before division took place was
Total = mean * 14
mean = 49
Total = 49 * 14
Total = 685
Now you subtract x from the total
685 - x
And divide by 13 [one number is missing]
(685 - x)/13
and the result = 43
(685 - x ) / 13 = 43 Multiply both sides by 13
685 - x = 43 * 13
685 - x = 559 Subtract 685 from both sides
- x = - 126 Multiply by - 1
x = 126
Find the value of a. A. 57 B. 104 C. 26 D. 52
Answer:
Option D, 52
Answered by GAUTHMATH
2. Find the measure of angle J.
Working as a team, 8 mathletes can solve 20 problems in 10 minutes. At this same rate, how many mathletes are needed in order to solve 30 problems in 5 minutes?
Answer:
12 mathletes is needed to solve 30 problems in 5 minutes
Step-by-step explanation:
8 athletes can solve 20 problems in 10 minutes
30-20=10
now we need 10 more problems to be solved so
20/2=10. 8/2=4 so we need more 4 mathletes to solve all the problems
how do I simplify when there are fractions on fractions
Answer: y/y+x
Step-by-step explanation: Reduce the fraction at the bottom (1 - x/y) (1 + x/y) = 1 + x/y = simplify and you get y/y+x
Find the inverse of the given function. f(x) = 7x – 4
Hi there!
[tex]\large\boxed{y = \frac{x + 4}{7}}[/tex]
f(x) = 7x - 4
Rewrite f(x) with y:
y = 7x - 4
Swap the x and y variables:
x = 7y - 4
Solve for y:
x + 4 = 7y
y = (x + 4)/7
The hypotenuse of a right triangle measures nem and one of its legs measures o em.
Mnd the measure of the other leg. If necessary, round to the nearest tenth.
Sun
attempt to
Using Pythagorean theorem
[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]
[tex]\\ \sf\longmapsto P^2=11^2-9^2[/tex]
[tex]\\ \sf\longmapsto P^2=121-81[/tex]
[tex]\\ \sf\longmapsto P^2=40[/tex]
[tex]\\ \sf\longmapsto P=\sqrt{40}[/tex]
[tex]\\ \sf\longmapsto P=6.2cm[/tex]
Step-by-step explanation:
Given,
Hypotenuse = 11 cm
Base (One of the given leg) = 9 cm
Therefore,
According to Pythagoras Theorem,
[tex] {base}^{2} + {height}^{2} = {hypotenuse}^{2} [/tex]
[tex] = > {(9)}^{2} + {height}^{2} = {(11)}^{2} [/tex]
[tex] = > {height}^{2} = {(11)}^{2} - {(9)}^{2} [/tex]
[tex] = > {height}^{2} = 121 - 81[/tex]
[tex] = > {height}^{2} = 4 0[/tex]
[tex] = > height = \sqrt{40} [/tex]
=> height = 6.3245553203
When rounded to nearest tenth,
=> height = 6.3
Hence,
Required length of other leg is 6.3 (Ans)
A storeowner orders 25 calculators that cost $38 each. The storeowner can sell each calculator for $42. The storeowner sold 22 calculators to customers. He had to return 3 calculators that were never sold and pay a $2 charge for each returned calculator (although the initial cost is refunded). What is the storeowner's profit?
Answer:
Step-by-step explanation:
25*-30= -$750
Second: He sells 22 of those calculators for $35 each, so he is making money.
22*35= $770
Third: With the remaining three calculators, he must pay $2 each for returned calculators, so he is losing money again.
3*-2= -6
Add all the costs and sales together, and you get 770-750-6= $14 profit
However, the problem does not say if he gets his money back for the 3 returned calculators. In that case if he did, you would add the cost of each of those calculators to his profit. 30*3= 90
$90+$14= $104 profit
here u go
What is the value of x?
Answer:
x = 46
Step-by-step explanation:
Assuming DE is an angle bisector , then it divides the opposite side into segments that are proportional to the other 2 sides, that is
[tex]\frac{HD}{DG}[/tex] = [tex]\frac{EH}{EG}[/tex] , substitute values
[tex]\frac{x+4}{58}[/tex] = [tex]\frac{55}{63.8}[/tex] ( cross- multiply )
63.8(x + 4) = 3190 ( divide both sides by 63.8 )
x + 4 = 50 ( subtract 4 from both sides )
x = 46
Simplify
1)a³b⁴/ ab³
2)2 (x³ )²
3)3x*2x³ y²
Answer:
1) a³b⁴/ ab³ = a²b
2)2 (x³ )² = 2x^6
3)3x*2x³ y² = 6x⁴y²
The Vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).Find the length of each diagonal.Show me with the steps Please!
Answer:
13 and 17 units
Step-by-step explanation:
explaination is in pic.
The length of the diagonals of the quadrilateral AC and BD are 13 units and 17 units respectively, as per length between two points.
What is the length between two points in a plane?The length between two given points (x₁, y₁) and (x₂, y₂) will be:
√[(x₂ - x₁)² + (y₂ - y₁)²] units
Given, the vertices of a quadrilateral are A(4,-3),B(7,10),C(-8,2)and D(-1,-5).
Therefore, the diagonals of the quadrilateral will be AC and BD.
The coordinates of the diagonal AC are (4, - 3) and (- 8, 2).
Now, the length of the diagonal AC will be:
= √[(-8 - 4)² + (2 - (- 3))²] units
= √[(- 12)² + (5)²] units
= √[144 + 25] units
= √(169) units
= 13 units (length can't be negative)
Similarly, the coordinates of the diagonal BD are (7, 10) and (- 1, - 5).
Now, the length of the diagonal BD will be:
= √[(-1 - 7)² + (- 5 - 10)²] units
= √[(- 8)² + (- 15)²] units
= √[64 + 225] units
= √(289) units
= 17 units (length can't be negative)
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Coordinates of C and D are (-14 , 6) and (x , 13) respectively.Given x is a positive integer and the distance CD is 25 units.Find the value of x.
Answer:
10
Step-by-step explanation:
1) The vector CD is equal to (X-(-14); 13-6)= (x+14; 7)
2) The module of the vector CD is equal to diatance CD=25. It is equal to
sqrt ((x+14)(x+14)+7*7) from the formula of module (with coordinates).
25= sqrt ((x+14)(x+14)+7*7)
625= (x+14)*(x+14)+49
625= x^2+28x+196+49
X^2+28X-380=0
a=1 b=28 c=-380
D= b*b-4ac= 28*28-4*1*(-380)= 784+1520= 2304
sqrt D= sqrt2304=48
x1= (-28-48)/2= -38
x2= (-28+48)/2= 10
But x1<0 it is negative and it is not suitable, x2>0 it is positive, so answer is 10.
Here are two fractions 3/10 and 5/7 work out which one is closer to a 1/2
Answer:
Therefore 3/10 is closer to ½
Step-by-step explanation:
We've to get the difference:
» with 3/10 :
[tex] \frac{1}{2} - \frac{3}{10} = { \boxed{\frac{1}{5} }}[/tex]
» with 5/7
[tex] | \frac{1}{2} - \frac{5}{7} | = { \boxed{ \frac{3}{14} }}[/tex]
but:
[tex] \frac{3}{14} > \frac{1}{5} [/tex]
Among both the given fractions, the one that is closer to a ½ is 3/10.
What is a fraction?A number that is stated as a quotient in mathematics, when the numerator and denominator are split in half. Both are integers in a straightforward fraction. In the numerator or denominator of a complex fraction is a fraction.
An element of a whole or, more broadly, any number of equal pieces, is represented by a fraction. When used in conversational English, a fraction indicates the number of components of a particular size, as in one-half, eight-fifths, and three-quarters.
A fraction is a number that represents a portion of a whole. In order to evaluate it, a whole is divided into a number of components. A correct fraction has a numerator that is lower than its denominator.
Required calculations are done with both the fractions,
1/2 - 3/10 = 1/5
1/2 - 5/7 = 3/14
3/14 ≥ 1/5
Therefore, among both the given fractions, the one that is closer to a ½ is 3/10.
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25 points, choices in photo
Which of the following accurately shows the first step when solving the following system of equations by substitution?
I would go with C as a first step
The correct answer is C (that is equating f(x) and g(x))
How to solve a quadratic and linear equation?A quadratic polynomial has highest degree 2 and a linear polynomial has highest degree 1.
In geometric sense, solving them means finding the point of intersection of curves:
In X-Y plane, these polynomials can be written as:
[tex]y=-x^{2} +2x+3\\y=-2x+3[/tex]
Taking the value of y from second equation and substituting it in first equation we get,
[tex]-x^{2} +2x+3=-2x+3[/tex]
Therefore, with the above procedure, we got the first step of solving the equations with the help of substitution.
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Which of the following numbers are solutions of the sentence x-3 < 2?
I -3
II 0
III 2
IV 5
O ll only
O III only
O I and III only
O I, II, and III only
O I, II, III, and IV
Answer:
O I, II, and III only
Step-by-step explanation:
x-3 < 2
Add 3 to each side
x-3+3< 2+5
x<5
-3 is less than 5
0 is less than 5
2 is less than 5
5 is not less than 5
I , II , II are true
PLEASE HELP DUE IN 15 MNUTES MARKING BRAINLIEST AND 15 POINTS YOU DONT HAVE TO EXPLAIN MUCH
Answer:
see below
Step-by-step explanation:
11a -2(x^2 -3)
Distribute
-2*x^2 -2(-3)
-2x^2 +6
11b 2x(x+4)
Distribute
2x*x +2x*4
2x^2 +8x
12 The perimeter is the sum of all sides
The top is equal to the bottom and the left side is equal to the right
x-10 + x+20+x-10+x+20
Combine like terms
4x +20
solve the inequality and graph the solution
-5-7x < -40
Answer:
x > 5
Step-by-step explanation:
-5-7x < -40
Add 5 to each side
-5+5-7x < -40+5
-7x < -35
Divide by -7, remembering to flip the inequality
-7x/-7 > -35/-7
x > 5
Open circle at 5, going to the right
Round 4746.13662611 to the nearest whole number.
Answer:
4746
Step-by-step explanation:
Is 3584 a term of the series 7+14+28+56........?
(please answer if you know; this is the question from geometric series:- General progression)
(full steps and process required)
(No spam answers or else you'll be reported )
Answer:
yes it is the 10th term in the series
Step-by-step explanation:
The nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁ [tex](r)^{n-1}[/tex]
where a₁ is the first term and r the common ratio
Here a₁ = 7 and r = [tex]\frac{a_{2} }{a_{1} }[/tex] = [tex]\frac{14}{7}[/tex] = 2 , then
[tex]a_{n}[/tex] = 7 [tex](2)^{n-1}[/tex]
Equate [tex]a_{n}[/tex] to 3584 and solve for n
7 [tex](2)^{n-1}[/tex] = 3584 ( divide both sides by 7 )
[tex]2^{n-1}[/tex] = 512 , that is
[tex]2^{n-1}[/tex] = [tex]2^{9}[/tex]
Since the bases on both sides are equal, both 2 , then equate the exponents
n - 1 = 9 ( add 1 to both sides )
n = 10
3584 is the 10th term in the series
Express 3 objects as a percentage of 1 dozen
show working.
Answer:
25%
Step-by-step explanation:
1 dozen = 12
3 out of 12
3/12
Simplify
1/4
Multiply top and bottom by 25 to get a denominator of 100
25/100
25%
The area of a rectangle is the product of its length and width. Both length and width are whole numbers. A rectangular poster has an area of 88 square inches. The width of the poster is greater than 10 inches and is prime.
Answer: a rectangular poster has an area of 260 square inches.the width of the poster is greater than 10 inches and is a prime number
Step-by-step explanation: a rectangular poster has an area of 260 square inches.the width of the poster is greater than 10 inches and is a prime number.what is the width
What is the slope of a line that passes through the points (-2, 4) and (-6, 12)?
Answer:-3\2
Step-by-step explanation:
slope is difference y axis by x axis
4-12/-2+6=-6/4=-3\2
I need help plz anyone I don't understand this at all.
Answer:
jejejjejejr
Step-by-step explanation:
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What will be the first term of a geometric series which has its sum 280, common ratio 3 and the last term 189 ?
Answer:
b1=7
Step-by-step explanation:
If we deal with geometric series, we should use the formulas for it. If there is the last term, it is not infinite geometric series. The sum of geometric series which isn't infinite is equal to b1(r^n-1)/(r-1) where b1 is the first term and r is the common ratio.
So 280= b1(3^n-1)/(3-1)
560= b1(3^n-1)
560= b1*3^n-b1
Then express bn=b1*r^(n-1)
189= b1*3^(n-1)
189= b1*3^n*1/3
567= b1*3^n when
560= b1*3^n-b1
560=567-b1
b1=7
