A student is given the equation N₂ + H₂ → NH3
2NH₂-
to balance. She answers with N₂ + 2H₂
Explain why her answer is not correct. Balance
the equation correctly.

Sodium ion, Na+ and chloride ion, Cl- are the spectator ions of the reaction of perchloric acid with sodium hydroxide. Therefore, options a and d are correct.

What are spectator ions?

Spectator ions are ions that do not undergo a chemical reaction in a chemical equation, and they are in solution in their original form. The balanced chemical equation for the reaction of perchloric acid with sodium hydroxide is:

HClO4(aq) + NaOH(aq) → NaClO4(aq) + H2O(l)

In the reaction above, sodium hydroxide reacts with perchloric acid to form sodium perchlorate and water. During the reaction, H+ and OH- ions combine to form water (H2O) and cancel each other out. This makes them spectator ions. Also, sodium and chloride ions are already present in their original form before and after the reaction. They remain the same, which makes them spectator ions. CO2 and O2 are not spectator ions in this reaction; hence, they are incorrect as possible options in this question.

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The likely magnitude of the equilibrium constant K for the combustion reaction 2H₂(g) + O₂(g) = 2H₂O(g) is 10^3.

The equilibrium constant K is a measure of the extent of a chemical reaction at equilibrium, and it is given by the ratio of the products to the reactants, with each species raised to a power equal to its stoichiometric coefficient. For the combustion reaction of hydrogen and oxygen, the equilibrium constant K can be calculated as,

K = ([H₂O]^2) / ([H₂]^2[O₂])

Since the combustion reaction of hydrogen and oxygen is highly exothermic, the products (water molecules) are favored at equilibrium. This means that the concentration of water molecules will be much higher than the concentrations of hydrogen and oxygen molecules, leading to a large value of K. In this case, the likely magnitude of the equilibrium constant K is 10^3, indicating that the combustion reaction is highly favored at equilibrium.

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According to the kinetic molecular theory, the particles of an ideal gas are separated by great distances, compared to there size. Hence option D is correct.

A large number of submicroscopic particles, including atoms and molecules, are used in the kinetic theory of gases, a theoretical model for characterizing the molecular composition of gases. The idea also states that atmospheric pressure is the result of particles colliding with each other and the walls of containers.

According to the kinetic hypothesis, gases are composed of many submicroscopic particles (atoms or molecules), all of which are in continuous random motion. The walls of the container and the fast moving particles that collide are constant and are separated by great distances, compared to there size.

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A catalyst will not have an impact on the position of equilibrium. Therefore option a is the correct answer.

Specifically, a catalyst is a substance that increases the rate of a chemical reaction without being consumed in the process. It does this by providing an alternative reaction pathway with a lower activation energy, which increases the reaction rate and therefore speeds up the rate at which equilibrium is achieved. The transition energy of the equilibrium is also lowered, meaning it will be easier for the reaction to move from the reactants to the products.

Therefore catalysts can alter the rate at which a reaction proceeds, but they cannot influence the position of equilibrium.

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The mass of 1 mole of solute dissolved to make the solution will be 40 g/mol (mass of 1 mole of solute).

To determine the mass of 1 mole of solute, we can use the molar mass of the solute. The formula for molar mass is:
Molar Mass = Mass of Solute ÷ Number of Moles

Let's use this formula to solve the problem:
Mass of Solute = 20 grams
Volume of Solution = 500 mL = 0.5 L
Concentration of Solution = 1 M
Number of Moles of Solute = Concentration × Volume = 1 M × 0.5 L = 0.5 mol

Now, we can use the molar mass formula to calculate the mass of 1 mole of solute:
Molar Mass = Mass of Solute ÷ Number of Moles
Molar Mass = 20 grams ÷ 0.5 mol
Molar Mass = 40 grams/mol

Therefore, the mass of 1 mole of solute is 40 grams.

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The Lewis acid is the one that accepts electrons from the donor atom. Option 'b' [tex]BCl_3[/tex] is the Lewis acid of the following options.  

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The answer of the following following questions are PbO(s) + PbS(s) → 2Pb(l) + SO2(g) and  2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g)

What is chemical reaction ?

A chemical reaction is a process in which one or more substances (reactants) are transformed into new substances (products) by the breaking and formation of chemical bonds. During a chemical reaction, the arrangement of atoms in the reactants is changed to form different molecules or compounds.

In a chemical reaction, the reactants are transformed into products through the rearrangement of atoms, but the total number of atoms remains the same. This is known as the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction.

(a)

Step 1: Roasting of galena in oxygen gas:

PbS(s) + 3O2(g) → PbO(s) + 2SO2(g)

Step 2: Heating the metal oxide with more galena:

PbO(s) + PbS(s) → 2Pb(l) + SO2(g)

(b) Overall balanced equation for the process:

2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g)

Note: The state of the reactants and products has been indicated in the equations, with (s) representing a solid, (g) representing a gas, and (l) representing a liquid.

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Photorespiration is a process which occurs in plants when there is not enough CO2 available for photosynthesis, resulting in the hydrolysis of ATP.

During photorespiration, oxygen is consumed and carbon dioxide is produced.

The light reactions of photosynthesis produce NADPH and ATP, and when cyclic electron flow is disrupted due to a mutation, the production of NADPH will be reduced.

Without NADPH, the Calvin cycle will not proceed, resulting in the production of glycolic acid, which is further broken down to form glycine, ammonia and carbon dioxide.

This process results in the hydrolysis of ATP and the consumption of oxygen, with the production of carbon dioxide as a by-product.

Photorespiration results in the hydrolysis of ATP, the consumption of oxygen and the production of carbon dioxide.

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Amino acids as acidic, basic, neutral polar, or neutral nonpolar are

Part A: NH₂: Basic, CH₃: Neutral nonpolar, CH₃: Neutral nonpolar, CH: Neutral nonpolar, NH₂: Basic, CH₂: Neutral nonpolar, H,N-C-coo: Acidic

Part B: OH: Neutral polar, CH₂: Neutral nonpolar, HON-C-COO: Acidic, H,N-C-COO: Acidic.

Acidic amino acids: These amino acids have a carboxyl group (COOH) in their side chain, which makes them acidic. They can donate a hydrogen ion (H+) and have a negative charge at physiological pH.

Basic amino acids: These amino acids contain an amino group (NH2 or NH3+) in their side chain, which makes them basic. They can accept a hydrogen ion (H+) and have a positive charge at physiological pH.

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If 1.04 g of chlorine gas occupies a volume of 872 ml at constant temperature and pressure, 2.08 g of chlorine gas would occupy 436 ml.

The given data for the question is:

Since the temperature and pressure are constant, we can use the formula,

Therefore, Initial Volume/Final Volume = Initial mass/Final mass

Where,

Initial Mass of Chlorine = Final Mass of ChlorineInitial Volume/V2 = 1.04/2.08

Final Volume = 872/2 = 436 ml

Thus, the final volume of the chlorine gas is 436 ml when the initial mass is 1.04g and the final mass is 2.08g at constant temperature and pressure.

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The concentration of ammonia in the solvent rises, the solubility of AgCl increases. Thus, in the solvent aqueous ammonia, AgCl is most soluble.

AgCl is most soluble in aqueous ammonia. AgCl is a chemical compound that is formed when silver nitrate and hydrochloric acid are combined. It is a white solid that is moderately soluble in water.

The solubility of AgCl in various solvents, such as water, ethanol, and aqueous ammonia, has been studied. AgCl is most soluble in aqueous ammonia.

When AgCl is dissolved in aqueous ammonia, a complex ion called the diammine silver(I) cation, [Ag(NH3)2]+, is formed. The AgCl crystal structure is disrupted by the presence of ammonia molecules, resulting in increased solubility. Here is the equation for the dissolution of AgCl in aqueous ammonia:

AgCl(s) + 2NH3(aq) → [Ag(NH3)2]+(aq) + Cl−(aq)

The solubility of AgCl in aqueous ammonia is temperature-dependent. As the temperature increases, the solubility of AgCl in aqueous ammonia increases. As the temperature decreases, the solubility of AgCl in aqueous ammonia decreases.

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Menthol, like methanol, occurs naturally and has several isomers. One structural characteristic of menthol that is responsible for it having enantiomers is that it has a chiral center.

Chiral centers are atoms with four different substituents attached to them, and they are a type of stereocenter. Menthol has a chiral center, which means it has two possible enantiomers.

Enantiomers are molecules that are mirror images of each other and cannot be superimposed on one another.

The two enantiomers of menthol are (1R,2S,5R)-(−)-menthol and (1S,2R,5S)-(+)-menthol. They have identical physical and chemical properties, except for their interaction with polarized light. This is due to the fact that they rotate plane-polarized light in opposite directions.

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Answer:

I hope it's helpful

Explanation:

2 mol of Al2O3 = 4 mol of Al

13 mol of Al2O3 =? (13/2)*4 = 26 mol

The H-alpha line at 656.28 nm, the H-beta line at 486.14 nm, the H-gamma line at 434.05 nm, the H-delta line at 410.17 nm, and the H-epsilon line at 397.00 nm are some of the most noticeable Fraunhofer lines in the sun's spectrum.

The Balmer series of hydrogen, which gave rise to these lines, is honored in their namesake.

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The H-alpha line at 656.28 nm, the H-beta line at 486.14 nm, the H-gamma line at 434.05 nm, the H-delta line at 410.17 nm, and the H-epsilon line at 397.00 nm are some of the most noticeable Fraunhofer lines in the sun's spectrum.

The Balmer series of hydrogen, which gave rise to these lines, is honored in their namesake.

The emission of light from the sun's surface, which is subsequently filtered via the sun's atmosphere, produces the sun's spectrum. Hydrogen, helium, calcium, iron, and other elements are among those found in the sun's atmosphere.

Some of the light emitted by the surface of the sun is absorbed by these substances as it travels through the atmosphere, producing dark absorption lines in the spectrum.

Each element has its own set of energy levels that map to particular light wavelengths that can be absorbed.

The photons in the light may be absorbed when light with these particular wavelengths travels through the element, elevating the electrons' energy levels.

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The order of oxyacids in decreasing acid strength is:

This order of  oxyacids is based on the number of oxygen atoms bonded to the central atom (in this case, Cl or Br) and the strength of the bond between the central atom and the oxygen atoms. The more oxygen atoms that are bonded to the central atom, the stronger the acid. Additionally, the strength of the bond between the central atom and the oxygen atoms increases as the electronegativity difference between the two atoms increases, making the acid stronger. HClO3 has the most oxygen atoms and the strongest bond, making it the strongest acid, while HBrO has the fewest oxygen atoms and the weakest bond, making it the weakest acid.

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Answer:

a) Methanoic acid can be prepared from methanol through oxidation using potassium permanganate and sulfuric acid. The reaction proceeds as follows:

CH3OH + 2[O] → HCOOH + H2O

b) Methanal (formaldehyde) can be prepared from methanol through oxidation using potassium dichromate and sulfuric acid. The reaction proceeds as follows:

CH3OH + [O] → CH2O + H2O

c) Butanone can be prepared from 2-butanol through oxidation using Jones reagent (CrO3/H2SO4) or pyridinium chlorochromate. The reaction proceeds as follows:

CH3CH(OH)CH2CH3 + [O] → CH3COCH2CH3 + H2O

d) Pentanal can be prepared from 1-pentanol through oxidation using potassium permanganate and sulfuric acid. The reaction proceeds as follows:

CH3(CH2)3CH2OH + 3[O] → CH3(CH2)3CHO + 3H2O

e) Hexanoic acid can be prepared from 1-hexanol through oxidation using potassium permanganate and sulfuric acid. The reaction proceeds as follows:

CH3(CH2)4CH2OH + 4[O] → CH3(CH2)4COOH + 4H2O

f) Hexanal can be prepared from 1-hexanol through oxidation using pyridinium chlorochromate. The reaction proceeds as follows:

CH3(CH2)4CH2OH + [O] → CH3(CH2)5CHO + H2O

g) Hexan-3-one can be prepared from 3-hexanol through oxidation using Jones reagent (CrO3/H2SO4) or pyridinium chlorochromate. The reaction proceeds as follows:

CH3(CH2)4CH(OH)CH3 + [O] → CH3(CH2)3COCH3 + H2O

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The reaction in which two compounds exchange their ions to form two new compounds is called decomposition reaction. Option (a) is correct.

Decomposition reaction is defined as a reaction in which a compound breaks down into two or more simpler substances. The general form of the decomposition reaction can be written as,

            AB → A+B.

This type of reaction require an input of energy in the form of heat, light, or electricity. It occurs when one reactant breaks down into two or more products. Some examples of decomposition reactions involves the breakdown of hydrogen peroxide to water and oxygen and the breakdown of water to hydrogen and oxygen. This is called the the process or effect of simplifying a single chemical entity into two or more fragments. This reaction is usually regarded and defined as the exact opposite of chemical synthesis .

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The entropy of methanol vapor at 800 K is calculated to be 185.4 J/(K mol).

The standard molar entropy (S°) is the entropy of one mole of a substance in its normal state (solid, liquid, or gas) at a standard pressure of 1 bar.

Standard molar entropy of liquid methanol

S° of liquid methanol = 126.8 J/(K mol)

Standard molar entropy of gaseous methanol

The standard molar entropy of gaseous methanol (CH₃OH) can be calculated as follows:

S° of gaseous CH₃OH = S° of liquid CH₃OH + R × ln (P2/P1)

Where, P1 = 1 bar (standard pressure) P2 = vapor pressure of CH₃OH at 298.15 K = 98.8 kPa

R = gas constant = 8.314 J/(K mol)

S° of gaseous CH₃OH = 126.8 J/(K mol) + 8.314 J/(K mol) × ln (98.8 kPa/1 bar)

S° of gaseous CH₃OH = 185.4 J/(K mol)

The entropy of methanol vapor at 800K

The change in entropy of vaporization of methanol can be calculated as follows: ΔSvap = ΔHvap/T

Where, ΔHvap = enthalpy of vaporization = 35.2 kJ/mol

T = temperature = 800 K (in Kelvin)

Convert ΔHvap from kJ/mol to J/mol by multiplying by 1000.

ΔSvap = (35.2 × 1000 J/mol)/800 K

ΔSvap = 44.0 J/(K mol)

Therefore, the entropy of methanol vapor at 800 K is 44.0 J/(K mol).

The experimental value of the standard molar entropy of gaseous methanol at 298.15 K is 239.8 J/(K mol).

The calculated value of the standard molar entropy of gaseous methanol at 298.15 K is 185.4 J/(K mol).

Therefore, the calculated value is less than the experimental value.

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4974.9 kJ of energy are released during the interaction between 162.5 g of O2 and 216.7 g of NH3.

The given chemical equation shows the reaction between ammonia (NH3) and oxygen (O2) to form nitrogen monoxide (NO) and water (H2O). The enthalpy change (ΔH) for this reaction is -1225.6 kJ per mole of O2 consumed.

To determine the energy given off by the reaction between 162.5 g of O2 and 216.7 g of NH3, we need to first determine the limiting reactant. This is the reactant that is completely consumed in the reaction and limits the amount of product formed.

To find the limiting reactant, we need to calculate the number of moles of each reactant. The molar mass of O2 is 32.00 g/mol, so 162.5 g of O2 is equivalent to 5.078 moles of O2. The molar mass of NH3 is 17.03 g/mol, so 216.7 g of NH3 is equivalent to 12.71 moles of NH3.

The stoichiometric ratio of O2 to NH3 is 5:4, meaning that for every 5 moles of O2 consumed, 4 moles of NH3 are required. From the above calculations, we can see that there is excess NH3 in this reaction since only 4.063 moles of O2 are required to react with 3.250 moles of NH3.

Therefore, the amount of O2 that reacts is 4.063 moles, and the energy given off by the reaction is:

ΔH = (-1225.6 kJ/mol) x (4.063 mol) = -4974.9 kJ

Therefore, the reaction between 162.5 g of O2 and 216.7 g of NH3 gives off 4974.9 kJ of energy.

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Answer: 3.85%

Explanation: To calculate the volume percentage of ethanol in the mixture, we need to determine the total volume of the mixture first.

Total volume = volume of ethanol + volume of water

Total volume = 10 ml + 250 ml

Total volume = 260 ml

Now, we can calculate the volume percentage of ethanol in the mixture using the following formula:

Volume percentage of ethanol = (volume of ethanol ÷ total volume) x 100%

Plugging in the values, we get:

Volume percentage of ethanol = (10 ml ÷ 260 ml) x 100%

Volume percentage of ethanol = 3.85%

Therefore, the volume percentage of ethanol in the mixture is 3.85%.

The correct sequence of steps in the formation of an action potential is as follows: 4. a graded depolarization brings an excited membrane to threshold potential, 6. voltage-gated Na+ channel activation occurs, 7. Na+ enter the cell and depolarization occurs, 1. voltage-gated Na+ channels are inactivated, 2. voltage-gated K+ channels open and K+ move out of the cell, 3. voltage-gated Na+ channels regain their normal properties, and 5. a temporary hyperpolarization occurs.
Explanation: Action potential is generated when a neuron sends information down an axon, away from the cell body. The steps involved in the formation of an action potential are:Graded depolarization occurs, which brings an excited membrane to threshold potential.Na+ enters the cell and depolarization occurs.Voltage-gated Na+ channel activation occurs.Voltage-gated Na+ channels are inactivated.Voltage-gated K+ channels open and K+ move out of the cell.A temporary hyperpolarization occurs.Voltage-gated Na+ channels regain their normal properties, which complete the cycle.Action potential is a result of ions moving in and out of the cell membrane, which changes the voltage difference between the inside and outside of the cell membrane. Action potential, therefore, involves the sequential opening and closing of different types of voltage-gated ion channels, including sodium (Na+) and potassium (K+) channels.

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To estimate the system pressure and vapor-phase mole fraction when x1 = 0.8, we can use the 1-parameter Margules equation.

This equation assumes that the vapor-liquid equilibrium is a linear relationship between the mole fraction of each component.

Since the given experiment gives us three points, we can use linear interpolation to estimate the parameters of the Margules equation.

From the given experiment, we know the values for x1, y1, and P when x1 = 0.0, 0.2, and 1.0 respectively. Therefore, we can calculate the slope and y-intercept of the Margules equation as follows:

Slope = (P2 - P1)/(y2 - y1) = (68.23 - 41.02)/(0.51 - 0.0) = 68.23

y-intercept = P1 - (slope * y1) = 41.02 - (68.23 * 0.0) = 41.02

Using these values and the x1 value of 0.8, we can then estimate the system pressure and vapor-phase mole fraction as follows:

System Pressure = (slope * 0.8) + y-intercept = (68.23 * 0.8) + 41.02 = 78.2 kPa

Vapor-phase Mole Fraction = (System Pressure - y-intercept) / slope = (78.2 - 41.02) / 68.23 = 0.80

Therefore, the estimated system pressure and vapor-phase mole fraction when x1 = 0.8 is 78.2 kPa and 0.80 respectively.

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The last solution is the correct answer to this question. The atomic number of an element remains the same when γ-radiation is emitted.

Gamma radiation (γ-radiation) is a form of electromagnetic radiation that does not carry any charge or atomic mass. Therefore, it does not directly affect the atomic number (Z) or mass number (A) of an atom.

The atomic number of an element represents the number of protons in the nucleus of an atom. When a radioactive decay occurs, the nucleus of the atom changes, which may result in a change in the number of protons. However, γ-radiation is not a type of radioactive decay that results in a change in the number of protons or atomic number of an element.

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Answer:

oxygen friend

Explanation:

It is generally believed that the Earth's atmosphere did not contain oxygen until around 2500 million years ago (Mya) when oxygen-evolving photosynthetic bacteria arose. At around 800–500 Mya, the oxygen concentration increased sharply to reach the 21% we have today. So, it seems highly likely that life arose as anaerobic organisms, which then evolved to tolerate oxygen and finally, to use it as a terminal acceptor for the energy-producing oxidative processes in the respiration of aerobic bacteria and mitochondria in eukaryotic cells. The respiratory processes employed by typical aerobic organisms today have a wide range of mechanisms to deal with the troublesome side effects of living with a high oxygen concentration.

Vinyl chloride (CH2=CHCl) is most likely the initial substance required to prepare the product after treatment with heated hydrochloric acid. A hydrochlorination procedure creates 1,2-dichloroethane as a byproduct by adding HCl across the vinyl chloride double bond.

Alkenes frequently undergo the hydrochlorination process, in which HCl is added across the double bond to produce a chloroalkane byproduct. In this instance, a vinyl chloride, which possesses a double bond between the carbon and chlorine atoms, is most likely the beginning substance. Warm HCl fractures the double bond, allowing the H and Cl atoms to add across the carbon atoms to create 1,2-dichloroethane as a byproduct. This response can be modelled as:

CH2 = CHCl + HCl ClCH2CH2Cl

All in all, this is a straightforward reaction that can be performed on a small scale in a lab or on a larger scale in industry to make 1,2-dichloroethane, which is utilised as a solvent and in the creation of vinyl chloride monomer.

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To neutralize 50.0 mL of 0.80 M NaOH, 200 mL of 0.20 M HCl are needed.

When sodium hydroxide (NaOH) and hydrochloric acid (HCl) are mixed, sodium chloride (NaCl) and water (H2O) are the results. The chemical formula for the neutralizing reaction is as follows:NaOH+HClNaCl+H2O.

We must apply the following balanced chemical equation for the neutralization reaction to calculate how much HCl is needed to neutralize 50.0 mL of 0.80 M NaOH:

HCl + NaOH NaCl + H2O

One mole of HCl interacts with one mole of NaOH to form one mole of NaCl and one mole of water, as shown by the equation.

Let's first determine the quantity of NaOH in moles.

Moles of NaOH = volume (in liters) x molarity

Moles of NaOH = 50.0 mL x (1 L/1000 mL) x 0.80 M

Moles of NaOH = 0.040 moles

moles of HCl = volume (in liters) x molarity

0.040 moles = volume (in liters) x 0.20 M

Volume (in liters) = 0.040 moles / 0.20 M

Volume (in liters) = 0.20 L

Finally, we can convert the volume from liters to milliliters:

Volume (in milliliters) = 0.20 L x (1000 mL/1 L)

Volume (in milliliters) = 200 mL

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An atom is the smallest unit of an element which retains the chemical properties of the particular element. An ion, on the other hand, is a charged particle that forms when an atom gains or loses electrons.

Subatomic particles include protons, neutrons and electrons.

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The correct Lewis structure for the OH⁻ ion consists of an oxygen atom that has two lone pairs of electrons and one bonded pair of electrons. Therefore, the correct option is C.

The OH⁻ ion is a negatively charged polyatomic ion, and it is composed of an oxygen atom (O) and a hydrogen atom (H). The valence electrons present in these two atoms are given as follows: H atom: 1 valence electron and O atom: 6 valence electrons.

Hence, the total number of valence electrons in the OH⁻ ion is: 1 + 6 + 1 = 8. Now, let's follow the below steps to draw the Lewis structure for the OH⁻ ion: Step 1: Determine the central atom. In the OH⁻ ion, the oxygen atom is the central atom.

Step 2: Connect the atoms using single bonds. In the OH⁻ ion, the hydrogen atom is connected to the oxygen atom via a single bond.

Step 3: Add lone pairs of electrons around each atom. According to the octet rule, the oxygen atom should have eight electrons around it. Out of the eight valence electrons, two electrons are in the bond, and the remaining six electrons are added as two lone pairs of electrons. The hydrogen atom has two valence electrons, and it has no electrons left to add to complete its octet. So, the final Lewis structure for the OH- ion is as follows: 

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Dream car: 2022 Tesla Model S; Second car: 2022 Toyota Camry

To calculate the amount spent on gas in one year for each car, we need to multiply the number of gallons of gas used in one year by the price per gallon.

For the dream car: 426.9 gallons x $3.00/gallon = $1280.70 spent on gas in one year.

For the second car: 500 gallons x $3.00/gallon = $1500 spent on gas in one year.

Therefore, you would spend $1280.70 on gas for the dream car and $1500 on gas for the second car in one year.

The Tesla Model S is an electric car, so it does not have miles per gallon on the highway.

The Toyota Camry has a highway mpg of 39.

Balanced equation for the combustion of octane: 2C8H18 + 25O2 → 16CO2 + 18H2O

The first car (Tesla Model S) uses no gasoline, so it does not use any gallons of gas in one year.

Converting 1 gallon to mL: 1 gallon = 3785.4 mL

Assuming you drive the Toyota Camry 15,000 miles in one year and get 39 mpg on the highway: 15,000 miles ÷ 39 miles per gallon = 384.6 gallons

Converting gallons to mL: 384.6 gallons x 3785.4 mL/gallon = 1,455,047.64 mL

The second car (Toyota Camry) uses 384.6 gallons of gas in one year.

Converting gallons to mL for the second car: 384.6 gallons x 3785.4 mL/gallon = 1,455,047.64 mL

The Tesla Model S is more efficient in terms of gas use since it uses no gasoline.

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