Answer:
-66
Step-by-step explanation:
There will be $66 left after the $12 spent on lunch. 66 + -66 = 0
The number could be -66 combined with the amount left in the account to make zero.
What are Arithmetic operations?Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.
Student has $78 in his checking account
Student spends $12 on lunch
Let, the number is x
78 + x - 12 = 0
x = - 66
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The altitude of an airplane is decreasing at a rate of 44 feet per second. What is the change in altitude of the airplane over a period of 34 seconds?
Answer:
1320 feet
Step-by-step explanation:
All we have to do is multiply the rate of change of altitude by the time it took the altitude to change.
The altitude of an airplane is decreasing at a rate of 44 feet per second. After 30 seconds, the change is altitude is:
44 * 30 = 1320 feet
The altitude of the airplane has changed by 1320 feet.
Solve the proportion.
3x / 10 = 9 / 4
Answer:
x =7.5
Step-by-step explanation:
We can use cross products to solve
3x / 10 = 9 / 4
3x*4 = 10*9
12x = 90
Divide each side by 12
12x/12 = 90/12
x =7.5
Which expression has the same value as the one below?
22+(-32)
○ 22+(-22)+(-10)
○22+(22)+(-10)
○22+(-22)+(10)
○22+0+32
Answer:
Option A
Step-by-step explanation:
22+(-32) is the same thing as 22-32.
[tex]22-32=-10[/tex]
Let's see if the given options are equal:Option A:
[tex]22+(-22)+(-10) \\22-22-10\leftarrow \text{Distribute -1 into the Parentheses.} \\0-10\\\boxed {-10}[/tex]
Option A's expression has the same value as the expression given.
Option B:
22+(22)+(-10)
[tex]22+22-10\\44-10\\\boxed {34}[/tex]
Option B's expression does not have the same value as the expression given.
Option C:
[tex]22+(-22)+(10)\\22-22+10\\0+10\\\boxed {10}[/tex]
Option C's expression does not have the same value as the expression given.
Option D:
[tex]22+0+32\\22+32\\\boxed{54}[/tex]
Option D's expression does not have the same value as the expression given.
The correct answer should be A: 22+(-22)+(-10).Answer:
the answer is A
hoped this helped
After 3 minutes, a submarine had descended to −320 feet. After 8 minutes, the submarine had descended to −420 feet. Assuming a linear function, write an equation in the form d(t)=mt+b that shows the depth, d(t), after t minutes.
Answer:
d(t) = -20t -260
Step-by-step explanation:
We are given two points ...
(t, d) = (3, -320) and (8, -420)
The 2-point form of the equation of a line can be useful when 2 points are given.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
Substituting the given points, we have ...
d(t) = (-420 -(-320))/(8 -3)(t -3) -320
d(t) = -20(t -3) -320
d(t) = -20t -260
BRAINLIEST ASAP! LENGTH OF AC?
Answer:
2.33 units
Step-by-step explanation:
[tex]\tan 25\degree =\frac{AC}{5}\\\\0.46630 = \frac{AC}{5}\\\\AC = 0.46630 \times 5\\AC =2.3315\\AC = 2.33 \: units[/tex]
Tia is planning a sailing party for her friends. The boat rental is $150 plus an
additional $15 per person. Tia has saved up $400 dollars. What is the
maximum number of people that can go sailing?
Identify the inequality to solve and the maximum number of people.
Answer:
16 people
Step-by-step explanation:
First subtract the cost of the rental from the amount of money:
$400-$150 = $250
Therefore Tia has $250 to spend for additional people. Then if each person is $15, divide the remaining amount of money by the amount of money per person:
$250/$15 = 16.67
Since you can't have 0.67 of a person she can have 16 people go with her.
This can also be modeled by this inequality:
[tex]150 + 15x \leqslant 400[/tex]
AB=
Round your answer to the nearest hundredth.
pleaseee
Answer:
[tex]c = \frac{2}{0.42} [/tex]
Step-by-step explanation:
AB = c
[tex] \frac{a}{sin \: A} = \frac{c}{sin \: C} \\ \frac{2}{sin \: 25} = \frac{c}{sin \: 90} \\ \frac{2}{0.42} = \frac{c}{1} \\ 0.42 \: c = 2 \\ c = \frac{2}{0.42} [/tex]
Answer:
4.73
Step-by-step explanation:
100 POINTS
PLEASE PROVIDE STEPS
FIND FIRST DERIVATIVE AND SIMPLIFY ANSWER
Answer:
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
Step-by-step explanation:
h(x) = ln x / √(x² + 1)
You can either use quotient rule, or you can rewrite using negative exponents and use product rule.
h(x) = (ln x) (x² + 1)^(-½)
h'(x) = (ln x) (-½) (x² + 1)^(-³/₂) (2x) + (1/x) (x² + 1)^(-½)
h'(x) = (-x ln x) (x² + 1)^(-³/₂) + (1/x) (x² + 1)^(-½)
h'(x) = (x² + 1)^(-³/₂) (-x ln x + (1/x) (x² + 1))
h'(x) = (1/x) (x² + 1)^(-³/₂) (-x² ln x + x² + 1)
h'(x) = (-x² ln x + x² + 1) / (x (x² + 1)^(³/₂))
Solution:
h(x) = ln(x)/√x^2+1
h(x) = ln(x) * (x^2 + 1)^-1/2
h(x) = ln(x) * (-1/2) * (x^2 + 1)^-3/2 * 2x + 1/x * (x^2 + 1)^-1/2
h(x) = -x ln(x) * (x^2 + 1)^-3/2 + 1/x * (x^2 + 1)^-1/2
h(x) = (x^2 + 1)^-3/2 * (-x ln(x) + 1/x * (x^2 + 1))
h(x) = -x^2ln(x)+x^2+1/(x(x^2+1)^3/2)
Best of Luck!
Determine the number of solutions to a system of equation:
Please help
Answer:
Step-by-step explanation:
These equations are all written in slope-intercept form, so the question is relatively easy to answer. These rules apply.
if slopes are different: 1 solutionif slopes are the same and y-intercepts are different, 0 solutionsif slopes are the same and y-intercepts are the same, infinitely many1. y=-6x-2; y=-6x-2 --- infinitely many
2. y=0.5x+5; y=0.5x+1 --- zero
3. y=0.25x-2; y=5x-4 --- one
4. y=2x+3; y=4x-1 --- one
5. y=2x+1.5; y=2x+1.5 --- infinitely many
6. y=-x-3; y=-x+3 --- zero
_____
Slope-intercept form is ...
y = mx +b
m is the slope
b is the y-intercept
Answer:
Step-by-step explanation: 1. y=-6x-2; y=-6x-2 --- infinitely many
2. y=0.5x+5; y=0.5x+1 --- zero
3. y=0.25x-2; y=5x-4 --- one
4. y=2x+3; y=4x-1 --- one
5. y=2x+1.5; y=2x+1.5 --- infinitely many
6. y=-x-3; y=-x+3 --- zero
How far can a dog run into the woods?
Answer:
Half way
Step-by-step explanation:
Half way, because the dog can run all the way through the woods, but only half of the time he is going in, the rest of the time he is going out.
What is the amplitude of y=3sin(2x−1)+4?
Answer:
3
Step-by-step explanation:
Amplitude is the number in front of the sin or the number multiplied by the whole equation. In this case its 3
A movie theater decreased the size of its popcorn bags by 20%. If the old bags held 15 cups of popcorn, how much do the new bags hold
Answer:
Your answer will be [tex]12[/tex] cups of popcorn.
Step-by-step explanation:
To find out how much the new bags hold, you need to find out the discount.
[tex]\frac{20}{100 } = .2[/tex]
[tex]15 * .2 = 3[/tex]
We know that the discount is [tex]3[/tex].
To figure out how much the new bags hold, subtract by the old bags.
[tex]15 - 3 = 12[/tex]
The new bags hold 12 cups of popcorn.
The number of new contributors to a public radio station's annual fund drive over the last ten years is 63, 58, 61, 72, 98, 103, 121, 147, 163, 198 Using Microsoft Excel, develop a linear regression model that predicts the number of new contributors. Explain the slope of this model. Based on this model, how many new contributors would you predict for the following year?
Answer:
The number of potential members predicted in next year's estimate becomes 193. The further explanation is given below.
Step-by-step explanation:
The slope of the model,
m = 15.345
c = 24
After comparing with the equation,
⇒ [tex]y=mx+c[/tex]
we get,
⇒ [tex]=15.345x + 24[/tex]
The slope seems to be a positive value which also means that another always improves this as component decreases. Which ensures that perhaps the number of contributors rising as time went by.
So that the above is the right answer.
What is the right answer!???????
Answer:
dont know need points
Step-by-step explanation:
Answer:
What points are needed?
Solve this system of equations.
2x + 6y = −6,
4x − 3y = −12
What is the solution to the system of equations?
Answer:
x = -3 and y = 0
Step-by-step explanation:
It would be more direct to apply elimination in this problem, rather than substitution:
2x + 6y = -6 ⇒ 2x + 6y = -6 ⇒ 10x = - 30
+ 2(4x - 3y = -12) + 8x - 6y = -24
Now let us solve for x through simply algebra:
10x = -30,
x = -3
Substitute this value of x into the first equation to get the value of y:
2( -3 ) + 6y = -6,
-6 + 6y = -6,
6y = 0,
y = 0
Answer:
-3 and 0
Step-by-step explanation:
i hope this helps :)
in the first quarter of the game the Giants gained 5 yards lost 13 yards gained 2 yards gained 6 yards and unfortunately lost 12 yards in their final play
Answer:
They lost a total of -12 yards.
Step-by-step explanation:
Do the calculation.
5- 13= -8
-8 + 2 + 6= 0
0 - 12 = -12
Divide 45 minutes in the ratio 2:3
Answer: 18 minutes: 27 minutes
Here the steps see attachment
What’s the correct answer for this?
Answer:
c
Step-by-step explanation:
solve for x
4x+5(5x-39)=153
Answer:
x=12
Step-by-step explanation:
4x+5 (5x-39) = 153
4x + 25x - 195 = 153
29x - 195 = 153
29x = 348
x = 12
Example on worksheet (subtracting by adding up)
50-29?
29+20=49
49+1=50
20+1=21
50-29=21
My question is where did the 20 come from? can you help me understand this?
Answer:
(49 - 29) + 1 =(50 - 29)
Step-by-step explanation:
The 20 comes from the subtraction of 29 in both sides of the previous step equality. In the following, I transcript the complete procedure and I add the step that you need to understand why 20 appears (in bold numbers):
29+20=49
49+1=50
(49 - 29) + 1 =(50 - 29)
20+1=21
50-29=21
hence, it was only nesseraty to subtract 29
A 5000-seat theater has tickets for sale at $28 and $40. How many tickets should be sold at each price for a sellout performance to generate a total revenue of $153 comma 200?
Answer:
Let's denote:
x: number of ticket 28$
y: number of ticket 40$
Then, we have:
x + y =5000
28x + 40y = 153200
=> 28(5000 - y) + 40y = 153200
=> 12y = 153200 - 140000
=> 12y =13200
=> y = 1100 (ticket 40$)
=> x = 5000 - 1100 = 3900 (ticket 28$)
PLEASE HELP!!! WILL MARK AS BRAINLIEST!!!
A colony of 300 bacteria doubles in size every 22 minutes can be represented by the exponential function y=300(2)x. If you want to know how many bacteria will be present about 66 minutes, what should you plug in for x?
Answer:
[tex] y = 300 (2)^x[/tex]
Where x represent the number of period of times of 22 minutes. If we want to know the value of the population after 66 minutes we need to find the value of x on this way:
[tex] x = 66 minutes *\frac{1period}{22 minutes}= 3[/tex]
So then we need to replace the value of x =3 and we got:
[tex] y= 300 (2)^3 = 2400[/tex]
Step-by-step explanation:
For this case we have the following function:
[tex] y = 300 (2)^x[/tex]
Where x represent the number of period of times of 22 minutes. If we want to know the value of the population after 66 minutes we need to find the value of x on this way:
[tex] x = 66 minutes *\frac{1period}{22 minutes}= 3[/tex]
So then we need to replace the value of x =3 and we got:
[tex] y= 300 (2)^3 = 2400[/tex]
In the right triangle shown DF=EF=3. How long is DE?
Answer:
4.24
Step-by-step explanation:
To solve this, use the Pythagorean therom. A^2 + b^2 = C^2
in this case a = 3 and b = 3
so 9 + 9 = sqrt 18
4.24
Answer:3√(2)
Step-by-step explanation:
DF=3
EF=3
DE=√(3^2 + 3^2)
DE=√(3x3 + 3x3)
DE=√(9+9)
DE=√(18)
DE=√(2 x 9)
DE=√(2) x √(9)
DE=√(2) x 3
DE=3√(2)
A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed
According to the Empirical Rule, what percent of the data is in each of the following ranges? Round to the nearest tenth of a percent if necessary.
Between
34 and 39
Less than
31.5
Between
29 and 36.5
Percentage
%
%
Answer:
a) [tex] z= \frac{34-34}{2.5}= 0[/tex]
[tex] z= \frac{39-34}{2.5}= 2[/tex]
And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
b) [tex] P(X<31.5) [/tex]
[tex] z= \frac{31.5-34}{2.5}= -1[/tex]
So one deviation below the mean we have: (100-68)/2 = 16%
c) [tex] z= \frac{29-34}{2.5}= -2[/tex]
[tex] z= \frac{36.5-34}{2.5}= 1[/tex]
For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Step-by-step explanation:
For this case we have a random variable with the following parameters:
[tex] X \sim N(\mu = 34, \sigma=2.5)[/tex]
From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.
We want to find the following probability:
[tex] P(34 < X<39)[/tex]
We can find the number of deviation from the mean with the z score formula:
[tex] z= \frac{X -\mu}{\sigma}[/tex]
And replacing we got
[tex] z= \frac{34-34}{2.5}= 0[/tex]
[tex] z= \frac{39-34}{2.5}= 2[/tex]
And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %
For the second case:
[tex] P(X<31.5) [/tex]
[tex] z= \frac{31.5-34}{2.5}= -1[/tex]
So one deviation below the mean we have: (100-68)/2 = 16%
For the third case:
[tex] P(29 < X<36.5)[/tex]
And replacing we got:
[tex] z= \frac{29-34}{2.5}= -2[/tex]
[tex] z= \frac{36.5-34}{2.5}= 1[/tex]
For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%
Two linear functions, f(x) and g(x), are combined by addition to form h(x). The same two linear functions are combined by multiplication to form j(x). Graphs of the resulting combined functions are shown. Which statements are true? Check all that apply. Graph A represents j(x). Graph A represents h(x). The y-intercepts for f(x) and g(x) can be 1 and 3. The y-intercepts for f(x) and g(x) can be 3 and 4. The rate of change of the sum of f(x) and g(x) is greater than that of either function.
Answer: this is the right answer Graph A represents j(x). The y-intercepts for f(x) and g(x) can be 1 and 3. And The rate of change of the sum of f(x) and g(x) is greater than that of either function. your welcome
Step-by-step explanation:
The rate of change of the sum of f(x) and g(x) is greater than that of either function.
How to determine the true statement?From the question, we have the following parameters:
h(x) = f(x) + g(x)j(x) = f(x) * g(x)The graphs of the functions are not given;
However, if all the functions are linear functions, then the slopes of the sum of functions f(x) and g(x) could be greater than the slopes of h(x) and j(x)
Hence, the true statement (by observation) is (c)
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A company that manufactures laptop batteries claims the mean battery life is 16 hours. Assuming the distribution of battery life is approximately normal, a consumer group will conduct a hypothesis test to investigate whether the battery life is less than 16 hours. The group selected a random sample of 14 of the batteries and found an average life of 15.6 hours with a standard deviation of 0.8 hour.
Which of the following is the correct test statistic for the hypothesis test?
A. t=15.6−160.8
B. t=16−15.60.8
C. t=15.6−160.813
D. t=15.6−160.814
E. t=16−15.60.814
Answer:
The correct test statistic for the hypothesis test is [tex]t = -1.87[/tex]
Step-by-step explanation:
The null hypothesis is:
[tex]H_{0} = 16[/tex]
The alternate hypotesis is:
[tex]H_{1} < 16[/tex]
The test statistic is:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.
In this question:
[tex]X = 15.6, \mu = 16, s = 0.8, n = 14[/tex]
So
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{15.6 - 16}{\frac{0.8}{\sqrt{14}}}[/tex]
[tex]t = -1.87[/tex]
The correct test statistic for the hypothesis test is [tex]t = -1.87[/tex]
Hypothesis test used to check the results of the experiments gives true for the meaningful results.. The correct test statistic for the hypothesis test is -1.871.
Given information-
The mean battery life of the laptop is 16 hours claimed by the company.
The random sample for the test is 14.
Average life of the batteries found out as 15.6 hours.
The deviation for this result is 0.8 hours.
What is hypothesis test?Hypothesis test used to check the results of the experiments gives true for the meaningful results.
As the mean battery life of the laptop is 16 hours claimed by the company.The null hypothesis for the given problem is,
[tex]H_o\mu=16[/tex]
As average life of the batteries found out as 15.6 hours. Thus the alternate hypothesis for the given problem is,
[tex]H_1\mu<16[/tex]
One sample t test can be found using the below formula,
[tex]t=\dfrac{\overline x -\mu_o}{\dfrac{s}{\sqrt{n} } }[/tex]
Here, [tex]\overline x[/tex] is mean value, [tex]n[/tex] is the number of random sample and [tex]s[/tex] is the deviation.
Put the values,
[tex]t=\dfrac{15.6 -16}{\dfrac{0.8}{\sqrt{14} } }\\t=-1.871[/tex]
Thus the correct test statistic for the hypothesis test is -1.871.
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A bag contains 3 red marbles and 6 blue marbles. A second bag contains 6 green marbles and 4 yellow marbles. You choose a marble from bag A and then a marble from bag B, what would be the probability of selecting one blue marble and one yellow marble?
Answer:
4/15
Step-by-step explanation:
Bag A
3 red marbles and 6 blue marbles. = 9 marbles
P(blue) = blue/total =6/9 = 2/3
Bag B
6 green marbles and 4 yellow marbles. = 10 marbles
P(yellow) = yellow/total=4/10 = 2/5
P(blue,yellow) = 2/3 * 2/5 = 4/15
what kind of novel is nutshell?
Answer:
i dont know what is it
den
Giving brainliest for CORRECT awnser.
Answer:
64
Step-by-step explanation:
x^2 +16x+c
Take the coefficient of x
16
Divide by 2
16/2 =8
Square it
8^2 = 64
This is c
Answer:
c = 64
Step-by-step explanation:
The value for c is A. 64. That comes from the process of completing the square where you take half the linear term, square it, and add it in. Our linear term is 16. Half of 16 is 8, and 8 squared is 64.
Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet. Random samples of sales receipts were studied for mail-order sales and internet sales, with the total purchase being recorded for each sale. A random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75. A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25. Using this data, find the 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases. Assume that the population variances are not equal and that the two populations are normally distributed. Step 1 of 3 : Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Answer:
80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ([tex]\mu_1-\mu_2[/tex]) is [-9.132 , 23.332].
Step-by-step explanation:
We are given that a random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75.
A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25.
Firstly, the Pivotal quantity for 80% confidence interval for the difference between population means is given by;
P.Q. = [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] ~ [tex]t__n__1-_n__2-2[/tex]
where, [tex]\bar X_1[/tex] = sample mean sales receipts for mail-order sales = $81.70
[tex]\bar X_2[/tex] = sample mean sales receipts for internet sales = $74.60
[tex]s_1[/tex] = sample standard deviation for mail-order sales = $18.75
[tex]s_2[/tex] = sample standard deviation for internet sales = $28.25
[tex]n_1[/tex] = size of sales receipts for mail-order sales = 7
[tex]n_2[/tex] = size of sales receipts for internet sales = 11
Also, [tex]s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(7-1)\times 18.75^{2} +(11-1)\times 28.25^{2} }{7+11-2} }[/tex] = 25.11
Here for constructing 80% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.
So, 80% confidence interval for the difference between population means, ([tex]\mu_1-\mu_2[/tex]) is ;
P(-1.337 < [tex]t_1_6[/tex] < 1.337) = 0.80 {As the critical value of t at 16 degree
of freedom are -1.337 & 1.337 with P = 10%}
P(-1.337 < [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] < 1.337) = 0.80
P( [tex]-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] < [tex]{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}[/tex] < [tex]1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] ) = 0.80
P( [tex](\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] < ([tex]\mu_1-\mu_2[/tex]) < [tex](\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] ) = 0.80
80% confidence interval for ([tex]\mu_1-\mu_2[/tex]) =
[ [tex](\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] , [tex](\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }[/tex] ]
= [ [tex](81.70-74.60)-1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }[/tex] , [tex](81.70-74.60)+1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }[/tex] ]
= [-9.132 , 23.332]
Therefore, 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ([tex]\mu_1-\mu_2[/tex]) is [-9.132 , 23.332].