A solution is made by mixing 34.5 g of sugar with 75.0 g of water. What is the mass percent of sugar in this solution?

Please explain and show work.

Answers

Answer 1

the mass percent of sugar in this solution is 46%.

Answer:

Solution given:

mass of solute=34.5g

mass of solvent=75g

mass percent=[tex]\frac{mass\:of\:solute}{mass\:of \:solvent}*100\%[/tex]

=[tex]\bold{\frac{34.5}{75.0}*100\%=46\%}[/tex]

Answer 2

We know that,

[tex]mass \: solute = \frac{mass \: of \: solute}{mass \: of \: solvent} [/tex]×100

[tex] \frac{34.5}{75.0} = 0.46[/tex]

hope it helps..


Related Questions

You prepare a solution by dissolving 25.3 g sucrose (C12H22O11) 705 mL of water. Calculate the molarity of the solution.

Answers

Answer:

0.105 M

Explanation:

First we convert 25.3 grams of sucrose into moles, using sucrose's molar mass:

Molar Mass of C₁₂H₂₂O₁₁ = 342.3 g/mol25.3 g C₁₂H₂₂O₁₁ ÷ 342.3 g/mol = 0.0739 mol C₁₂H₂₂O₁₁

Now we calculate the molarity of the solution, using the given volume and the calculated number of moles:

Converting 705 mL ⇒ 705 mL / 1000 = 0.705 LMolarity = 0.0739 mol / 0.705 L = 0.105 M

Carbonic anhydrase is strongly inhibited by the drug acetazolamide, which is used as a diuretic (i.e., to increase the production of urine) and to lower excessively high pressure in the eye (due to accumulation of intraocular fluid) in glaucoma.

a. True
b. False

Answers

Answer:

a. True

Explanation:

There is strong inhibition of Carbon Anhydrase by Aceta-zolamide Carbonic Anhydrase. The drug acetazolamide is used as diuretic which increase the urine production in human body. It lowers pressure in eye in glaucoma.

What kind of element is Phosphorus is

Answers

phosphorus is and non metal

Answer:

NON-METAL

Explanation:

Phosphorus is a non-metal that sits just below nitrogen in group 15 of the periodic table. This element exists in several forms, of which white and red are the best known.


0.28 M Ca(NO3)2
Express your answer using two significant figures.

Answers

Answer:

Mass=Moles × RFM

Mass= 0.28M× 164

Mass= 45.92 grammes

What is the molarity of a solution prepared by dissolving 12.0 g of potassium permanganate, KMnO4, in water to make 250.0 mL of solution

Answers

Answer:

Explanation:

Molecular weight of potassium permanganate is 158 g .

12 g = 12 g / 158 g moles

= .076 moles .

250 mL = .25 L .

Molarity of solution = moles dissolved / volume of solution

= .076 / .25 L

= .304 M .

Molarity of solution is .304 M.  

The molarity of a solution prepared by dissolving 12.0 g of potassium permanganate, KMnO4, in water to make 250.0 mL of solution will be 0.304 M. It can be calculated by using mole formula.

What is molarity ?

The amount of material in a given volume of the given solution has been measured in molarity (M). The moles of a particular solute per liter of a solution can be known as molarity. The molar solution of known concentration is indeed known as molarity.

What is mole?

A mole is just the quantity of a material that includes exactly 6.022 × [tex]10^{23}[/tex] of the particular chemical elementary entities.

Molecular weight potassium potassium permanganate = 12 g

Volume of the solution = 250mL = 25 L.

Calculation of mole:

Mole can be calculated by using the formula.

Mole = mass / molar mass

Mole = 12 g / 158 g

Mole = 0.076 mole.

Calculation of molarity:

Molarity can be calculated by using the molarity formula:

Molarity = moles of dissolved / volume of solution

Molarity = 0.076 / 0.25

Molarity = 0.304 M

Therefore, the molarity of the solution will be 0.304 M.

To know more about molarity and mole

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the pressure on a 205 mL volume of gas is decreased from 985 mm hg to 615 mm hg while constant temperature is maintained, What is the new volume of the gas?

Answers

The new volume of gas should be 328.33 mL

Answer:

[tex]\boxed {\boxed {\sf 328 \ mL}}[/tex]

Explanation:

The pressure on the gas changes, while the temperature remains constant, and we want to find the new volume. So, we will use Boyle's Law, which states there is an inverse relationship between the pressure on a gas and the volume of the gas. The formula is:

[tex]{P_1V_1}= P_2V_2[/tex]

The pressure of the gas is originally 985 mm Hg and the volume is 205 milliliters.

[tex]985 \ mm \ Hg * 205 \ mL = P_2V_2[/tex]

The pressure is decreased to 615 mm Hg, but the new volume is unknown.

[tex]985 \ mm \ Hg * 205 \ mL = 615 \ mm \ Hg * V_2[/tex]

We are solving for the new volume, so we must isolate the variable V₂. It is being multiplied by 615 millimeters of mercury.. The inverse of multiplication is division, so we divide both sides of the equation by 615 mm Hg.

[tex]\frac {985 \ mm \ Hg * 205 \ mL}{615 \ mm \ Hg} = \frac{615 \ mm \ Hg * V_2}{615 \ mm \ Hg}[/tex]

[tex]\frac {985 \ mm \ Hg * 205 \ mL}{615 \ mm \ Hg} = V_2[/tex]

The units of millimeters of mercury (mm Hg) cancel.

[tex]\frac {985 \ * 205 \ mL}{615 } = V_2[/tex]

[tex]\frac{201925 }{ 615} \ mL = V_2[/tex]

[tex]328.3333333 \ mL = V_2[/tex]

The original measurements have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 3 to the right in the tenths place tells us to leave the 8 in the ones place.

[tex]328 \ mL \approx V_2[/tex]

The new volume of the gas is approximately 328 milliliters.

Which technique is best suited to each application?

a. In the second week of a four week biochemistry experiement, you have 50 fractions collected from a gel filtration column to determine which fractions contain lactate dehydrogenase. You are given only 400 uL of 0.100 mg/mL lactate dehydrogenase to prepare your calibration curve. 96-well microplate
b. Your environmental lab has 2000 samples to be analyzed for trace ammonia by next week. discrete analyzer.
c. Twenty water samples must be analyzed for Cl-, NH3, PO3-, and So during each work shift. flow injection analysis colorimeter.
d. Your professor heard you will be hiking the Appalachian Trail next summer. She asks you to collect 100-mL water samples from the ten streams with the highest concentration of phosphate.

Answers

Answer:

a. discrete analyzer

b. 96 well microplate

c. flow injection analysis

d. colorimeter

Explanation:

96 well microplates are instruments designed for sample collection and throughput screening. If an environment lab has collected 2000 samples then 96 well microplate is best suited application. Discrete analyzer is automated chemical analyzer which performs test on samples kept in discrete cells. Flow injection analysis is approach used for chemical analysis. It injects a plug of sample into a flowing carrier stream. Colorimeter is a device which measures absorbance of wavelength of light by a specific solution.

A mixture of 1-heptyne, 2-heptyne, and 3-heptyne was hydrogenated in the presence of a palladium catalyst until hydrogen uptake ceased. How many seven-carbon hydrocarbons were produced

Answers

Answer:

four

Explanation:

Recall that the hydrogenation of 1-heptyne, 2-heptyne, and 3-heptyne  is an addition reaction. The hydrogen is added across the triple bond in the presence of palladium serving as the catalyst.

Note that 1-heptyne and 2-heptyne do not exist as geometric isomers hence they yield one corresponding hydrocarbon each. However, 3-heptyne exhibits geometric isomerism. As a result of this, 3-heptyne yields cis and trans products making a total of four seven-carbon hydrocarbons produced.

So, the number of seven carbon hydrocarbons produced is one.

1-heptyne, 2-heptyne, and 3-heptyne

Note that if there is excess hydrogen, then all triple bonds will be substituted by hydrogen  so  only  heptane is  formed, double bonds and tirple bonds disappear to

[tex]CH_3-(CH_2)_5-CH_3[/tex]

Learn More: https://brainly.com/question/15704986

______ drives the aminoacylation reaction hydrolysis of gtp hydrolysis of phosphate phosphorylation hydrolysis of pyrophosphate

Answers

Answer:

Hydrolysis of pyrophosphate

Explanation:

The hydrolysis of pyrophosphate into two molecules of inorganic phosphate (Pi) reaction which is highly energetic that drives the other two reactions. These two reactions highly exergonic reactions that take place inside the aminoacyl-tRNA synthetase which is specific for that amino acid. Exergonic reactions are the reactions that produce free energy that can be used in the next phases of reactions so we can say that  hydrolysis of pyrophosphate is responsible for the happening of aminoacylation reaction.

Carbon monoxide, a product of combustion, is a toxic gas that has an extremely high affinity for hemoglobin (much higher than that of oxygen for hemoglobin); consequently, as soon as it dissolves in the liquid part of blood at low partial pressure, it diffuses quickly into red blood cells and binds to hemoglobin. In carbon monoxide (CO) poisoning, even with very low partial pressure of inspired CO, CO rapidly binds to hemoglobin (Hgb), leaving a lower fraction of oxygen binding sites on Hgb available to be occupied by oxygen. What would you expect to find if you measure the arterial PO2 of a person with CO poisoning

Answers

Answer:

Decreases.

Explanation:

The arterial PO2 of a person is decreasing because of carbonmonoxide poisoning due to higher affinity to hemoglobin than oxygen. The PO2 in the blood of arteries are used up by the cells and then there is higher concentration of  carbonmonoxide in the blood as compared to oxygen. Due to this higher amount of carbonmonoxide in the blood, many complications occur such as headache, dizziness, weakness, upset stomach, vomiting, chest pain, and confusion.

Which acid or base (along with its corresponding salt) should be used to generate a buffer solution with pH around 3.5

Answers

Answer:

Formic acid

Sodium formiate

Explanation:

To determine acid or base that can generate a buffer solution with pH around 3.5, we have to think in the acid whose pKa = pH.

Although we have to also think in buffer capacity, a measure which can cause a change of 1 pH unit in 1 L of solution.

Buffer capacity does not only depend on the concentration of its components but also of the relationship between that concentrations.

When pH = pKa, buffer capacity is maximum which means that the concentration of conjugated species is the same and the ability to oppose pH changes is maximum.

One example with pH = pKa or nearly if:

COOH⁻  + Na⁺ →  NaCOOH

HCOOH  +  H₂O  →  COOH⁻  + H₃O⁺     Ka: 1.8×10⁻⁴

pKa = 3.74

2) If a brick has a length of 13.77 cm, a width of 8.50 cm, and a height of 5.12 cm:
a) What is the volume of the brick?
b) If the brick has a mass of 895.3 g, what is its density?

Answers

Answer:

a. 599 cm³

b. 1.49 g/cm³

Explanation:

A. Volume

Volume is the amount of space an object occupies. Since this is a brick, the object is a rectangular prism. The formula for the volume of a rectangular prism is the product of length, width, and height.

[tex]V= l *w*h[/tex]

The brick's length (l) is 13.77 centimeters, the width (w) is 8.50 centimeters, and the height (h) is 5.12 centimeters. Substitute these values into the formula.

[tex]V= 13.77 \ cm * 8.50 \ cm * 5.12 \ cm[/tex]

Multiply the numbers together.

[tex]V= 117.045 \ cm^ 2* 5.12 \ cm[/tex]

[tex]V= 599.2704 \ cm^3[/tex]

The original measurements have at least 3 significant figures, so our answer must have 3. For the number we calculated, that is the ones place. The 2 in the tenths place tells us to leave the 9 in the ones place.

[tex]V \approx 599 \ cm^3[/tex]

[tex]\bold {The \ volume \ of \ the \ brick \ is \ approximately \ 599 \ cubic \ centimeters}}[/tex]

2. Density

Density is the amount of matter in a specified space. The formula for density is mass over volume.

[tex]d= \frac{m}{v}[/tex]

The mass of the brick is 895.3 grams and we just found the volume to be 599.2704 cubic centimeters. Substitute the values into the formula.

[tex]d= \frac{895.3 \ g}{599 \ cm^3}[/tex]

Divide.

[tex]d= 1.494657763 \ g/cm^3[/tex]

Round to three significant figures. For the number we calculated, that is the hundredth place. The 4 in the thousandth place tells us to leave the 9 in the hundredth place.

[tex]d \approx 1.49 \ g/cm^3[/tex]

[tex]\bold {The \ density\ of \ the \ brick \ is \ approximately \ 1.49 \ grams /cubic \ centimeters}}[/tex]

A 2.584 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of dioxygen, producing 5.874 g CO2 and 2.404 g H2O. What mass of oxygen is contained in the original sample?a. 0.7119 g.b. 0.8463 g.c. 0.29168 g.d. 0.1793 g.e. 0.6230 g.

Answers

Answer:

a. 0.7119 g

Explanation:

To solve this question we need to know that all carbon of the compound will react producing CO2 and all Hydrogen producing H2O.

Thus, we can find the mass of C and the mass of H and by difference regard to the 2.584g of the compound we can find the mass of oxygen as follows:

Moles CO2 = Moles C -Molar mass: 44.01g/mol-

5.874g CO2 * (1mol/44.01g) = 0.1335 moles CO2 = 0.1335 moles C

Mass C -Molar mass: 12.01g/mol-:

0.1335 moles C * (12.01g /mol) = 1.6030g C

Moles H2O -Molar mass: 18.01g/mol-

2.404gH2O * (1mol / 18.01g) = 0.1335 moles H2O * (2mol H / 1mol H2O) = 0.267 moles H

Mass H -Molar mass: 1g/mol-

0.267 moles H * (1g/mol) = 0.2670g H

Mass Oxygen =

Mass O = 2.584g compound - 1.6030g C - 0.2670g H

Mass O = 0.714g O ≈

a. 0.7119 g

Write a balanced half-reaction for the reduction of liquid water to gaseous hydrogen in basic aqueous solution. Be sure to add physical state symbols where appropriate.

Answers

Answer:

2 H₂O(l) + 2 e⁻ ⇒ H₂(g) + 2 OH⁻(aq)

Explanation:

Let's consider the unbalanced half-reaction for the reduction of liquid water to gaseous hydrogen in basic aqueous solution.

H₂O(l) ⇒ H₂(g)

First, we will perform the mass balance. We will balance oxygen atoms by multiplying H₂O by 2 and adding 2 OH⁻ to the right side.

2 H₂O(l) ⇒ H₂(g) + 2 OH⁻(aq)

Then, we perform the charge balance by adding 2 electrons to the left side.

2 H₂O(l) + 2 e⁻ ⇒ H₂(g) + 2 OH⁻(aq)

What element
is a basic element of life

Answers

There are four basic elements of life: Oxygen, hydrogen, nitrogen and phosphorus. These four elements are found in abundance in both the human body and in animals. There are other elements that compose the human body, but the four we've highlighted participate in all life processes

Answer:

Oxygen is the main element of life.

Explanation:

Because Oxygen allows us to breathe..

I hope this helps you!

XoXo Makayla

A mixture of hydrocarbons contains 38.3% hexane, C6H14, 13.9% octane, C8H18, and 47.8% decane, C10H22. The mixture is combusted in an excess of oxygen. What mass of CO2 is generated from the combustion of 19.3 kg of the mixture

Answers

Answer:

52.206 kg

Explanation:

From the given information:

Mass of hexane C6H14 = [tex]19.3*10^3 \ g \times \dfrac{38.3}{100}[/tex]

= 7391.9 g

Mass of octane C8H18 = [tex]19.3*10^3 \ g \times \dfrac{13.9}{100}[/tex]

= 2682.7 g

Mass of decane C10H22 = [tex]19.3*10^3 \ g \times \dfrac{47.8}{100}[/tex]

= 9225.4 g

However, recall that:

number of moles of an atom = mass/molar mass

For hexane, no of moles = 7391.9 g/86.18 g/mol

= 85.77 moles

For octane, no of moles = 2682.7 g/114.23 g/mol

= 23.49 moles

For decane, no of moles = 9225.4 g/142.29 g/mol

= 64.84 moles

Therefore:

number of moles of CO2 produced = (6 × 85.77)+(23.49)+(10×64.84) moles

= 1186.51 moles

Finally, the mass of CO2 produced is:

= 1186.51 mol × 44 g/mol

= 52206.44  g

= 52.206 kg

Can someone help me with problem 21.105? Many thanks!

Answers

the correct answer is 1 to the 3rd power

Write the precipitation reaction for silver sulfate in aqueous solution: (Use the lowest possible coefficients. Be sure to specify states such as (aq) or (s). If a box is not needed, leave it blank.)

Answers

Answer:

The balanced chemical reaction is :

[tex]2Ag^+(aq)+SO_4^{2-}(aq)\rightarrow Ag_2SO_4(s)[/tex]

Explanation:

The precipitation reaction is defined as a chemical reaction in which a solid substance is formed when two aqueous solutions of different compounds are allowed to react with each other.

When an aqueous solution of silver ion and sulfate ions are mixed together solid white precipitate of silver sulfate is formed.

The balanced chemical reaction is written as:

[tex]2Ag^+(aq)+SO_4^{2-}(aq)\rightarrow Ag_2SO_4(s)[/tex]

The tabulated data show the rate constant of a reaction measured at several different temperatures. Use an Arrhenius plot to determine the activation barrier and frequency factor for the reaction.

Temperature (K) Rate Constant (1/s)
300 0.0134
310 0.0407
320 0.114
330 0.303
340 0.757

Required:
Use an Arrhenius plot to determine the activation barrier for the reaction.

Answers

Answer:

e−(Ea/RT): the fraction of the molecules present in a gas which have energies equal to or in excess of activation energy at a particular temperature

from kinatic point of view explain the change from solid to liquied based on the effect of change of tempreture.​

Answers

Answer:

Temperature affects the kinetic energy in a gas the most, followed by a comparable liquid, and then a comparable solid. The higher the temperature, the higher the average kinetic energy, but the magnitude of this difference depends on the amount of motion intrinsically present within these phases.

Explanation:

Liquids have more kinetic energy than solids. When a substance increases in temperature, heat is being added, and its particles are gaining kinetic energy. Because of their close proximity to one another, liquid and solid particles experience intermolecular forces. These forces keep particles close together.

Calculate the boiling point of a 3.5 % solution (by weight) of sodium chloride in water.
Kb of H2O = 0.512 oC/M

Answers

Answer: The boiling point of the solution is [tex]101.02^oC[/tex]

Explanation:

We are given:

3.5 % (by weight) NaCl

This means that 3.5 g of NaCl is present in 100 g of solution

Mass of solvent = Mass of solution - Mass of solute

Mass of solvent (water) = (100 - 3.5) g = 96.5 g

Elevation in the boiling point is defined as the difference between the boiling point of the solution and the boiling point of the pure solvent.

The expression for the calculation of elevation in boiling point is:

[tex]\text{Boiling point of solution}-\text{boiling point of pure solvent}=i\times K_b\times m[/tex]

OR

[tex]\text{Boiling point of solution}-\text{Boiling point of pure solvent}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}[/tex] ......(1)

where,

Boiling point of pure solvent (water) = [tex]100^oC[/tex]

Boiling point of solution = ?

i = Vant Hoff factor = 2 (for NaCl)

[tex]K_b[/tex] = Boiling point elevation constant = [tex]0.512^oC/m[/tex]

[tex]m_{solute}[/tex] = Given mass of solute (NaCl) = 3.5 g

[tex]M_{solute}[/tex] = Molar mass of solute (NaCl) = 36.5 g/mol

[tex]w_{solvent}[/tex] = Mass of solvent (water) = 96.5 g

Putting values in equation 1, we get:

[tex]\text{Boiling point of solution}-(100)=2\times 0.512\times \frac{3.5\times 1000}{36.5\times 96.5}\\\\\text{Boiling point of solution}=(1.02+100)^oC\\\\\text{Boiling point of solution}=101.02^oC[/tex]

Hence, the boiling point of the solution is [tex]101.02^oC[/tex]

What is the molecular geometry of CIO3F as predicted by the VSEPR model?

Multiple Choice
trigonal pyramidal
square planar
square pyramidal
tetrahedral
octahedral

Answers

Explanation:

since there are no lone pairs on the central atom, the shape will be tetrahedral

If a 520 mg sample of technetium-99 is used for diagnostic procedure, how much of Tc-99 remains after 30.0h? Half life of Tc-99 is 6.0 hours.

Answers

16.25 mg
I have attached an image of the half life formula.
In this problem, N0 would be 520, since that is the initial amount.
t = 30.0 Hours
t 1/2 = 6.0 hours
Now plug everything into the equation. You get 16.25 mg. No

g Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing carbon dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of of acetylene. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Answers

Answer:

3.0 mol CO₂

Explanation:

Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing carbon dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of 1.5 moles of acetylene. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Step 1: Write the balanced combustion reaction

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(g)

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of C₂H₂ to CO₂ is 1:2.

Step 3: Calculate the moles of CO₂ produced from 1.5 moles of C₂H₂

1.5 mol C₂H₂ × 2 mol CO₂/1 mol C₂H₂ = 3.0 mol CO₂

The following list of properties is most descriptive of a(n) ______________. Low melting point, non-conductor of electric current. Group of answer choices

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete but the completed question is below;

"The following list of properties is most descriptive of a(n) ______

1. High melting point, conductor of electricity when dissolved in water

2. Low melting point, non-conductor of electric current

3. Malleable, ductile, insoluble in water.

The choices for all 3 are: a) metallic solid b) molecular solid c) ionic solid d) all of these e) none of these f) more than one of these"

1. Ionic solid: Ionic solids are solids that have ionic/electrovalent bonds holding it's constituent molecules together. These bonds are strong bonds that involve the transfer of electrons from one constituent atom (the metal) to another constituent atom (the nonmetal). This strong bond causes the solid to have a high melting and boiling point. Also, when dissolved in water, the constituent atoms (involved in the electron transfer) dissociate to form ions (become charged) and thus easily carry electric charges (i.e conduct electricity).

Examples are Sodium Chloride and Potassium Iodide

2. Molecular solids: These are solids whose constituent molecules are held together by a weak bond/force known as Van der Waal forces. This forces are easily broken down when subjected to heat and thus the molecular solids have a low melting point. Also, these solids do not have carriers of heat or electric charges in them and are thus non-conductors of electric current.

Examples are Ice (frozen water) and sucrose

3. Metallic solids: These of solids made from constituent metal atoms only. The nuclei of these constituent metal atoms have the ability to move past one another without disrupting there metallic bonding; it is for this reason they are malleable and ductile. There constituent atoms however do not dissociate in water and are thus insoluble in water.

Examples are aluminium and copper crystal.


3. At 35 C, a sample of gas has a volume of 256 ml and a pressure of 720.torr. What would the volume
be if the temperature were changed to 22 C and the pressure to 1.25 atmospheres

Answers

Answer:

The volume will be 185.83 mL.

Explanation:

Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases. Gay-Lussac's law can be expressed mathematically as follows:

[tex]\frac{P}{T} =k[/tex]

Where P = pressure, T = temperature, k = Constant

Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. Boyle's law is expressed mathematically as:

P*V=k

Where P = pressure, V = volume, k = Constant

Finally, Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is kept at a constant pressure. For a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .

In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

[tex]\frac{V}{T} =k[/tex]

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

[tex]\frac{P*V}{T} =k[/tex]

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

[tex]\frac{P1*V1}{T1} =\frac{P2*V2}{T2}[/tex]

In this case:

P1= 720 torr V1= 256 mLT1= 35 C= 308 K (being 0 C= 273 K)P2= 1.25 atm= 950 torr (being 1 atm= 760 torr)V2= ?T2= 22 C= 295 K

Replacing:

[tex]\frac{720 torr*256 mL}{308 K} =\frac{950 torr*V2}{295 K}[/tex]

Solving:

[tex]V2= \frac{295K}{950 torr} *\frac{720 torr*256 mL}{308 K}[/tex]

V2= 185.83 mL

The volume will be 185.83 mL.

How must the hydrogen in an acid be attached (ionically or covalently) to be an acid?

Answers

Answer:

Search it online it will help

what would happen if the number of protons and electrons in the Atom did change

Answers

When you change the number of protons in an atom, you will change the atom from one element to a different element. Sometimes, when you add a proton to an element, the element will become radioactive. If you change the number of electrons in an atom, you will get an ion of the element.

What’s the IUPAC name
O
||
CH3CH2CH2CH2COCH3

Answers

Answer:

Methyl pentanoate.

Explanation:

Hello there!

In this case, according to the given information, we can see the correct structure will be:

                             O

                              ||

CH3CH2CH2CH2COCH3

Which matches with the structure of an ester due to the -COO- functional group. In such a case, the first part of the name is in function of the right side of the ester, in this case, methyl, followed by the left side, pentanoate, as it has five carbon atoms and is an ester (similar to an inorganic salt, but organic) and therefore, the name will be methyl pentanoate.

Regards!

To what volume should you dilute 55 mL of 12 M stock HNO3 solution to obtain a 0.145 HNO3 solution?

Answers

Answer:

4552 mL

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 55 mL

Molarity of stock solution (M₁) = 12 M

Molarity of diluted solution (M₂) = 0.145 M

Volume of diluted solution (V₂) =?

The volume of the diluted solution can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

12 × 55 = 0.145 × V₂

660 = 0.145 × V₂

Divide both side by 0.145

V₂ = 660 / 0.145

V₂ ≈ 4552 mL

Thus, the volume of the diluted solution is 4552 mL

Other Questions
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