a solid plastic cylinder of radius 2.33 cm and length 6.30 cm. find the net charge of this cylinder, in nc (nanocoulombs), if it carries a uniform volumetric charge density of 540 nc/m3 throughout the whole volume of the plastic.

Answers

Answer 1

The net charge of a solid plastic cylinder of radius 2.33 cm and length 6.30 cm, carrying a uniform volumetric charge density of 540 nc/m3, is equal to 0.0583 nC (nanocoulombs)


To determine the net charge of a cylinder, the formula Q =ρV has to be used where Q is the net charge, ρ is the uniform volumetric charge density, and V is the volume of the cylinder.

ρ is given as 540 nc/m³.

V is calculated using the formula

V = πr²h

where r is the radius and h is the length.

π is approximated to be 3.14.  

h is given as 6.30cm

r is 2.33cm

so the calculation for V becomes;

V = πr²h

V = 3.14 x 2.33² x 6.3

V = 108.02 cm³ or 108.02 x 10⁻⁶ m³.

Substitute the values of Q and V into the equation and solve for Q:

Q = ρVQ = 540 nc/m³ x 108.02 x 10⁻⁶ m³

Q = 0.0583 nc (to 3 decimal places)

Therefore the net charge of this cylinder, in nc (nanocoulombs) is 0.0583nc.

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Related Questions

in one cycle a heat engine absorbs 480 j from a high-temperature reservoir and expels 320 j to a low-temperature reservoir. if the efficiency of this engine is 56% of the efficiency of a carnot engine, what is the ratio of the low temperature to the high temperature in the carnot engine?

Answers

The ratio of the low temperature to high temperature of the Carnot engine is 2.38.

What is the efficiency of Carnot engine?

The efficiency of the Carnot engine can be defined as the ratio of network done per cycle by the engine to the heat energy absorbed by the engine per cycle by the working substance from the source.


Efficiency = 1 - (Tlow/Thigh)


Heat absorbed by engine = 480J

Heat expelled by engine = 320J

Efficiency of the engine = 56% of efficiency of Carnot engine

The ratio of low temperature to high temperature in the Carnot engine.

Let's assume the efficiency of the Carnot engine is 'ηc' = 1 - T₂/T₁

Where, T₂ = Low temperature and T₁ = High temperature

To calculate the efficiency of the engine given, η = (Q1 - Q2)/Q1

η = (480 - 320)/480

η = 160/480

η = 1/3

η = 33.33%

Now, η = 56% × ηc

0.56ηc = 1/3ηc = (1/3)/0.56 = 0.58

As we already know, ηc = 1 - T₂/T₁

T₂/T₁ = 1 - ηc

T₂/T₁ = 1 - 0.58

T₂/T₁ = 0.42

T₁/T₂ = 1/0.42

T₁/T₂ = 2.38

Therefore, the ratio of low temperature to high temperature in the given Carnot engine with an efficiency of 56% will be about 2.38.

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what's the correct answer. ​

Answers

The coordinated functions of the Nervous, Endocrine, and Reproductive systems are:

D. CerebrumN. Wernicke's AreaF. Occipital LobeH. HypothalamusJ. ThalamusH. HypothalamusC. CerebellumL. Superior ColliculusA. AmygdalaM. Pineal Gland

What are coordinated functions?

Coordinated functions refer to the integration and communication between different organs, systems, and tissues in the body to achieve a common goal or purpose. In biological terms, coordinated functions often involve multiple physiological systems working together to maintain homeostasis, respond to stimuli, or carry out complex behaviors or processes.

Examples of coordinated functions include the regulation of blood glucose levels by the pancreas and liver, the coordination of movement by the nervous and musculoskeletal systems, and the release of hormones by the endocrine system to control various physiological processes.

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The question is:

"COORDINATED FUNCTIONS OF THE NERVOUS, ENDOCRINE, AND REPRODUCTIVE SYSTEMS"

Directions: Identify the part of the brain that is involved in each situation below. Write only the letter of your answer.

A. Amygdala

B. Brocka's Area

C. Cerebellum

D. Cerebrum

E. Hippocampus

F. Occipital Lobe

G. Hippocampus

H. Hypothalamus

I. Inferior Colliculus.

J. Thalamus

K. Pons

L Superior Colliculus

M. Pineal Gland

N. Wernicke's Area

O. Pituitary Gland

1. "My heart tells me that you are the one. I love you so much!"

2. "IAOCEVOY! I don't know what that means. It's all Greek to me!"

3. "Chartreuse, Olive,Turquoise, and Mint are all shades of green."

4. "Janna always wakes up at 4 in the morning, regardless of whether she uses an alarm clock or not."

5. "I don't remember the way going to Myla's house. Can you accompany me there?"

6. Jenny's mother is about to give birth, she complains about contraction and pain usually when the baby is kicking

7. "Anthony is a very skilled dancer. He just won the school hip hop dance competition last week."

8. "As Nica was walking on the road she readily moved to the side for she heard an incoming ambulance"

9. "Elsa loves making faces whenever she talks to her friends."

10. "Ryan usually talks about how happy his high school days were to his grandchildren."

When Joselyn went to the store she bought 2.7kg of salt water taffy. What would Joselyn do to find out how many grams she bought?A. Divide by 1000B. Multiply by 1000C. Divide by 100D. Multiply by 100

Answers

At the shop, Joselyn purchased 2700 grammes of salt water taffy.

To convert kilograms (kg) to grams (g), Joselyn would need to multiply the weight in kilograms by 1000. This is because there are 1000 grams in 1 kilogram. Therefore, to find out how many grams of salt water taffy Joselyn bought, she would need to multiply 2.7kg by 1000.

The correct answer is (B) Multiply by 1000.

Multiplying 2.7kg by 1000 gives:

2.7kg x 1000 = 2700g

So Joselyn bought 2700 grams of salt water taffy at the store.

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the surface of the sun appears sharp in visible light because

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"The surface of the sun appears sharp in visible light because the photosphere is thin compared to the other layers in the sun."

Most of the electromagnetic energy that reaches the earth begins in the photosphere, the area of the sun that is visible to us. The photosphere is referred to as the sun's surface, despite the fact that it is a gaseous entity.

The gas in the photosphere appears to have a sharp surface, but in reality, it is heavier lower in the Sun and less dense higher up. It is more transparent the less thick it is. The area of the gas that is visible to us is where it has largely become translucent. About 300 km of this layer are deep.

The photosphere is the line separating the core of the Sun from its atmosphere. It is the part of the Sun's surface that is visible to us. The photosphere is not like a planet's surface; even if you could stand in the sun, you couldn't do so on the photosphere.

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