A Sociology instructor gives students points for each​ discussion-board post and points for each reply to a post. Ana wrote 6 posts and 8 replies and received 114 points. Jae wrote 5 posts and 4 replies and received 79 points. Determine how many points a discussion post is worth and how many points a reply is worth?

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Answer 1

Answer:

5 points per post and 2 points per replies


Related Questions

Choose the system of inequalities that best matches the graph below.

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Answer:

"D" is the correct answer

Step-by-step explanation:

Find the value of x. Round to the nearest tenth.

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36
i think. hope it helped sorrh if it’s wrong i’m not good at math

Can someone just check my answers please? Please let me know which questions are wrong. Thank you for your time.

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Well done
All of these are correct

Which shows the best estimate of the quotient of 4,346 ÷ 82?

between 50 and 60
between 60 and 70
between 500 and 600
between 600 and 700

Answers

Answer:

Between 50 and 60

Step-by-step explanation:

4,346/82 is 53 which is between 50 and 60.

Hope this helps!

An urn has 21 balls that are identical except that 8 are white, 7 are red, and 6 are blue. What is the probability that all are white if 3 are selected randomly without replacement?

Answers

Answer:

.0421

about 4.21%

Step-by-step explanation:

[tex]\frac{{8\choose3}}{{21\choose3}}=\frac{56}{1330}=.042105263[/tex]

9.
Find the area of the shaded region.
6
6
The exact area is A =
square units.

Answers

Answer:

8. 36

Step-by-step explanation:

8.

The diameter of the square is x=[tex]\sqrt{6^{2} +6^{2} }\\[/tex] = [tex]\sqrt{72}[/tex] = 6 [tex]\sqrt{2}[/tex]

The diameter of the square is the diameter of the circle, therefore the radius of the circle is r = 6 [tex]\sqrt{2}[/tex]/2 = 3[tex]\sqrt{2}[/tex]

The area of the shaded region, which is a circle is A= π[tex]r^{2}[/tex] =  π[tex](3\sqrt{2} )^{2}[/tex] = 36π

​=
The solution set is
​ 1/2(10x+16)-13=-3/5(15x-35)

Answers

Answer: 13/7 or as a decimal 1.857142857

How did i get the answer:

Step 1: Simplify both sides of the equation.

so 1/2 of 10 is 5, 1/2 of 16 is 8

-3/5 of 15 is -9 and -3/5 of -35 is POSITIVE 21

all together should look like 5x+8+−13=−9x+21

(now we have to combine like terms)

8+ -13= -5

5x -5 = -9x+21

Step 2: Add 9x to both sides

5x + 9x= 14x

14x -5 = 21

Step 3: Add 5 to both sides.

21+5= 26

14x=26

Step 4: Divide both sides by 14.

26/14= 1.85714286 or 13/7

The solution is x= 13/7

Which of the following is a polynomial?

Answers

Answer:

(D.) 3x^2 + 6x

Step-by-step explanation:

the other options aren't complete and some don't even create a parabola.

-32=?

it told me to write atlest 20 words so ignore this

Answers

Answer:

I don't think it's possible.

Question A cotton farmer produced 390 pounds per acre after 4 years of operating. After 9 years, he was producing 460 pounds per acre. Assuming that the production amount has been increasing linearly, estimate the production per acre 7 years after he started farming. Your answer should just be a numerical value. Do not include units in your answer. Provide your answer below:​

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Photo math should help you

PLSHELPASAPDFFFFFFFFFFFFFFFFFFFFFFFFFF

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im struggling with the same one

(a) Starting with the geometric series [infinity] xn n = 0 , find the sum of the series [infinity] nxn − 1 n = 1 , |x| < 1.

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Let f(x) be the sum of the geometric series,

[tex]f(x)=\displaystyle\frac1{1-x} = \sum_{n=0}^\infty x^n[/tex]

for |x| < 1. Then taking the derivative gives the desired sum,

[tex]f'(x)=\displaystyle\boxed{\dfrac1{(1-x)^2}} = \sum_{n=0}^\infty nx^{n-1} = \sum_{n=1}^\infty nx^{n-1}[/tex]

Ms. Ambrose paid $10 for 1.25 pounds of almonds. How much did the almonds cost per pound???

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I think it’s 8 dollars because 10/1.25 is 8

Simplify the ratio.
2.25 to 0.5

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Answer:

9:2

Step-by-step explanation:

Diana adds either 2 or 5 to every whole number from 1 to 9. She wants to achieve as few different sums as
possible. What is the minimum number of different values she obtains?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9

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The answer is 7 because is the minimum

84 percent of students athletes attend a preseason meeting. If there are 175 students athletes how many attend the meeting

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Answer:

Total no. of students =175

percent of students athletes who attend a preseason meeting =84

No. of students who attend the meeting

= 84% of 175

=147

Ted buys wood to build his guitars. Find the number of blocks of mahogany that Ted can afford to buy if he wishes to spend a total of $5000 this month, mahogany costs $450 per block, and he has already bought 7 blocks of spruce at $200 each.

Answer choices:
7
8
11
10

Answers

Answer:

the answer is 8

Step-by-step explanation:

Total amount Ted wishes to spend this month is $5000.

Mahogany costs $450 per block, and he has already bought 7 blocks of spruce at $200 each.

So, money spent on spruce =  dollars

Money left after buying spruce =  dollars

Now as $450 will be spent on buying 1 block of mahogany.

So, $3600 will be spent

and then your answer will be 8

What is the slope of the line?

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5/5 using rise over run

(4 + 4i)/(5+4i) = divide

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Answer:

B.

Step-by-step explanation:

[tex] \frac{4 + 4i}{5 + 4i} [/tex]

Multiplying both numerator and denominator by (5 - 4i) , the conjugate of the denominator, i. e, (5 + 4i).

[tex] \frac{4 + 4i}{5 + 4i} \times \frac{5 - 4i}{5-4i} [/tex]

[tex] \frac{(4 + 4i)(5 - 4i)}{(5 + 4i)(5 - 4i)} [/tex]

Multiplying (4+4i) and (5-4i) using distributive propertyUsing the identity (a+b)(a-b)= a² - b² where 5 will act as a and 4i will act as b

[tex] \frac{20-16i+20i-16i^2}{(5) {}^{2} - (4i) {}^{2} } [/tex]

i² = -1

(combining like terms)

[tex] \frac{20+(-16i+20i)-(-16)}{25-(-16)} [/tex]

[tex] \frac{(20+16)+4i}{25+16} [/tex]

[tex] \frac{36+4i}{41} [/tex]

distributing the denominator

[tex] \frac{36}{41} + \frac{4}{41}i [/tex]

That is, option B.

Select the correct answer.
Which is the simplified form of the expression ?

Answers

Answer:

a)  b^5/12

Step-by-step explanation:

b^2/3 ÷ b^1/4    [if bases are the same then subtract the exponents]

2/3 - 1/4 = 5/12

which pair of fractions are equivalent? 2/3 and 12/9 20/40 and 45/ 55 20/40 and 4/8 5/5 and 25/50​

Answers

Answer:

[tex]\frac{20}{40} \ and \ \frac{4}{8} \ is \ equivalent[/tex]

Step-by-step explanation:

1.

[tex]\frac{2}{3} \ and \ \frac{12}{9} \\\\\frac{2}{3} \ and \ \frac{4}{3}\\\\Not \ equivalent[/tex]

2.

[tex]\frac{20}{40} \ and \ \frac{45}{55}\\\\\frac{1}{2} \ and \ \frac{9}{11}\\\\Not\ equivalent[/tex]

3.

[tex]\frac{20}{40} \ and \ \frac{4}{8}\\\\\frac{1}{2} \ and \ \frac{1}{2} \\\\Equivalent[/tex]

4.

[tex]\frac{5}{5} \ and \ \frac{25}{50} \\\\\frac{1}{1} \ and \ \frac{1}{2} \\\\not \ equivalent[/tex]

2/3 and 12/9 are not equivalent since 12/2 isn’t equal to 9/3.
➡️ 6 isn’t equal to 3.

20/40 and 45/55 are not equivalent since 45/20 isn’t equal to 55/40.
➡️ 2.25 isn’t equal to 1.375.


20/40 and 4/8 are equivalent since 20/4=40/8
➡️ 5=5


5/5 and 25/50 are not equivalent since 25/5 isn’t equal to 50/5.
➡️ 1 isn’t equal to 10

A raffle has a grand prize of a European cruise valued at $10000 with a second prize of a Rocky Point vacation valued at $700. If each ticket costs $4 and 11000 tickets are sold, what are the expected winnings for a ticket buyer?

Answers

Answer:

- 3.027

Step-by-step explanation:

First price = 10000 ; second price = 700

Number of tickets sold = 11000

Ticket cost = $4

Probability that a ticket wins grand price = 1 / 11000

Probability that a ticket wins second price = 1 / 11000

X ____ 10000 _____ 700

P(x) ___ 1 / 11000 ___ 1/11000

Expected winning for a ticket buyer :

E(X) = Σx*p(x)

E(X) = (1/11000 * 10000) + (1/11000 * 700) - ticket cost

E(X) = 0.9090909 + 0.0636363 - 4

E(X) = - 3.0272728

E(X) = - 3.027

Using the graph below, if f(x) = 4, find x.

Answers

3 I think is the answer

You are given the following information about x and y.
x y Independent Dependent Variable Variable 15 5 12 7 10 9 7 11
The least squares estimate of b 0 equals ______.
a. 16.41176
b. â1.3
c. 21.4
d. â7.647

Answers

Answer:

[tex]b_0 = 16.471[/tex]

Step-by-step explanation:

Given

[tex]\begin{array}{ccccc}x & {15} & {12} & {10} & {7} \ \\ y & {5} & {7} & {9} & {11} \ \end{array}[/tex]

Required

The least square estimate [tex]b_0[/tex]

Calculate the mean of x

[tex]\bar x = \frac{\sum x}{n}[/tex]

[tex]\bar x = \frac{15+12+10+7}{4} =\frac{44}{4} = 11[/tex]

Calculate the mean of y

[tex]\bar y = \frac{\sum y}{n}[/tex]

[tex]\bar y = \frac{5+7+9+11}{4} =\frac{32}{4} = 8[/tex]

Calculate [tex]\sum(x - \bar x) * (y - \bar y)[/tex]

[tex]\sum(x - \bar x) = (15 - 11) * (5 - 8)+ (12 - 11) * (7 - 8) + (10 - 11) * (9 - 8)+ (7 - 11) * (11 - 8)[/tex]

[tex]\sum(x - \bar x) = -26[/tex]

Calculate [tex]\sum(x - \bar x)^2[/tex]

[tex]\sum(x - \bar x)^2 = (15 - 11)^2 + (12 - 11)^2 + (10 - 11)^2 + (7 - 11)^2[/tex]

[tex]\sum(x - \bar x)^2 = 34[/tex]

So:

[tex]b = \frac{\sum(x - \bar x) * (y - \bar y)}{\sum(x - \bar x)^2}[/tex]

[tex]b = \frac{-26}{34}[/tex]

[tex]b_0 = y - bx[/tex]

[tex]b_0 = 5 - \frac{-26}{34}*15[/tex]

[tex]b_0 = 5 + \frac{26*15}{34}[/tex]

[tex]b_0 = 5 + \frac{390}{34}[/tex]

Take LCM

[tex]b_0 = \frac{34*5+ 390}{34}[/tex]

[tex]b_0 = \frac{560}{34}[/tex]

[tex]b_0 = 16.471[/tex]

Four complex numbers lie at the vertices of a square in the complex plane.
Three of the numbers are 1 + 2i, -2 + i and -1 – 2i. What is the fourth
number?

Answers

9514 1404 393

Answer:

  2 -i

Step-by-step explanation:

The two diagonals have the same center point. Here, it is ...

  (1 +2) +(-1 -2i) = 0 +0i

The fourth point is found by reflecting the 2nd point across the origin:

  p4 = -p2 = -(-2 +i) = 2 -i . . . . . fourth corner of the square

Help ASAP!! A triangle has side lengths of 11in, 15in, and 20in. Find the angle measures of the triangle. Round decimal answers to the nearest tenth. Someone help pls.

Answers

Answer:

<A = 47.7°

<B = 99.4°

<C = 32.9

Step-by-step explanation:

When given the measurements of all three sides, you can calculate the angles using the Cosine Law.

c² = a² + b² - 2ab cos C

(based on Pythagorean Theorem)

If we say: a = 15

b = 20

c = 11

11² = 15² + 20² - 2(15)(20) cos C

121 = 625 - 2(15)(20) cos C

121 = 625 - 600 cos C

⁻504 = ⁻600 cos C

cos⁻¹ (504 ÷ 600) = C

< C = 32.9°

a² = b² + c² - 2bc cos A

15² = 20² + 11² - 2(20)(11) cos A

225 = 521 - 2(20)(11) cos A

225 = 521 - 440 cos A

⁻296 = ⁻440 cos A

cos⁻¹ (296 ÷ 440) = A

<A = 47.7°

Then, since we know the sum of all three angles of a triangle equals 180°:

180° - 32.9° - 47.7° = 99.4°

<B = 99.4°

Find the surface area and volume of the solid given the figure below

Answers

Answer:

Volume - 582.8848178 cm cubed

Step-by-step explanation:

Volume - to fine the volume start with the cone...

The formula is 1/3 pi r^2h

so for this problem it would be

1/3 * 3.14 * 26.01 * 11.2

so your answer would be...

305.061213 cm cubed

Your next step is to find the volume of the dome. to do that the formula is (4/3 pi r^3)/2

so for this problem it would be

(4/3 * 3.14 * 132.651)/2

so your answer would be...

277.8236048 cm cubed

Finally you add together those 2 volumes and get 582.8848178 cm cubed as your final answer.

What is the solution to the linear equation?
-12 + 3b - 1 = -5 - b

Answers

Answer:

b=2

Step-by-step explanation:

b = 2

Rearrange:
3b - 13 = -b - 5

Eliminate b from right side:
3b - 13 + b = -b - 5 + b

4b - 13 = -5

Eliminate 13 on the left:
4b - 13 + 13 = -5 + 13

4b = 8

Simplify:
8 / 4 = 2

b = 2

it's tooooo easy who wants brain list​

Answers

Answer:

1) Isosceles

2) Acute

3) Right angled

4( Obtuse

5) Equilateral

1)isoceles
2)Acute
3) right angled
4)obtuse
5)Equilateral

Determine whether the following propositions are true or false:
(a) 5 is an odd number and 3 is a negative number.
(b) 5 is an odd number or 3 is a negative number.
(c) 8 is an odd number or 4 is not an odd number.
(d) 6 is an even number and 7 is odd or negative.
(e) It is not true that either 7 is an odd number or 8 is an even number (or both).

Answers

Answer:

a) false

b) true

c) true

d) true

e) false

Step-by-step explanation:

In a statement of the type:

p ∧ q

where ∧ means "and"

The statement is true only if both p and q are true

the statement is false if p, q, or both, are false.

and in the case of:

p ∨ q

where ∨ means "or"

The statement is true if at least one of p or q (or both) are true.

The statement is false if both are false.

Now that we know that, let's solve the problem:

a) "5 is an odd number and 3 is a negative number."

Here we have:

p = 5 is an odd number

We know that this is true

q = 3 is a negative number

This is false.

then the complete statement is false.

b) "5 is an odd number or 3 is a negative number."

here we have:

p = 5 is an odd number.

this is true

q = 3 is a negative number

because in this case we have an "or", with only p being true, the whole statement is true.

c) "8 is an odd number or 4 is not an odd number."

p = 8 is an odd number  (this is false)

q = 4 is not an odd number  (this is true, 4 is a even number)

Again, we have an "or", so we need only one true proposition, then the statement is true.

d) "6 is an even number and 7 is odd or negative."

p = 6 is an even number  (true)

q = 7 is odd or negative  (notice that we have an or, and 7 is odd is true, so this proposition is true)

Then both propositions are true, then the statement is true.

e) "It is not true that either 7 is an odd number or 8 is an even number (or both)."

This is most complex, this will be true if at least one of the propositions is false.

but:

7 is an odd number is true

8 is an even number is true.

Then both statements are true, which means that the statement is false.

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