A small bag can hold 40 packets of crackers and a large bag can hold 90
packets of crackers. If the total number of bags exceeds 300 and the total
number of packets of crackers exceeds 1500, represent the situation using a
system of linear inequalities.

Answer:

the formula for the volume of a square pyramid is V=a^2*h/3

so if we just put in the data

12^2*10/3

144*10/3

480

so the answer is B

Hope This Helps!!!

Answer:

A.

Step-by-step explanation:

4y = 12x + 16

3x = y - 4

=>

y = 3x + 4

using that in the first equation

4(3x+4) = 12x + 16

12x + 16 = 12x + 16

=> both lines/equations are identical, so they have infinitely many solutions.

Answer:

6.9

Step-by-step explanation:

Cos ∆ = Adjacent/Hypotenuse

therefore x=12Cos55°

=6.88

=6.9 to the nearest tenth

Answer:

12

Step-by-step explanation:

the angles on top of a line (or below a line) sum up to 180 degrees, as a line stands in that regard for a flip from left to right - which is a half circle or 180 degrees.

therefore, the sum of both angles must be 180.

10x - 20 + 6x + 8 = 180

16x -12 = 180

16x = 192

x = 12

Answer:

48km hr this is the answer in your question.

Answer:

*Refer the graph

Step-by-step explanation:

Blue : y= cot 2A + tan 2A cot 2A-tan 2A

domain a ≠ kπ/4

Yellow : y= sec 4A

domain a ≠ π/8 + kπ/4

vertical intercept (0,1)

Answer:

About Points

S = (x,y)        searched point (it will be in the third quadrant )

M = (-2,0)      Midpoint | SP |

P = (3,5)        one end of the segment | SP |

You have to draw Cartesian.

we set in a point M and P. We both points by a simple and we extend it for the third quarter of the system. Compass measure the distance from the point M to the point P. From the point M we set a compass point S. Figure attached. Received point S = ( -7 , -5 ) . It sought a point that calculate .

We use the information that | SM | = | MP |

Answer : S = (-7,-5)

Step-by-step explanation:

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ P(\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad \underline{Q}(\stackrel{x_2}{x}~,~\stackrel{y_2}{y}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{x+3}{2}~~,~~\cfrac{y+3}{2} \right)=\stackrel{M}{(-2,0)}\implies \begin{cases} \cfrac{x+3}{2}=-2\\[1em] x+3=-4\\ \boxed{x = -7}\\[-0.5em] \hrulefill\\ \cfrac{y+3}{2}=0\\[1em] y+3=0\\ \boxed{y=-3} \end{cases}[/tex]

Answer:

[tex]\frac{5}{12}[/tex]

Step-by-step explanation:

Multiply straight across and reduce.

[tex]\frac{5}{8}[/tex] · [tex]\frac{2}{3}[/tex] = [tex]\frac{10}{24}[/tex] = [tex]\frac{5}{12}[/tex]

Answer:

30

Step-by-step explanation:

[tex]\frac{75}{100} = \frac{x}{40}\\\\Cross- multiply:\\\\\\75*40=100x[/tex]

3000 = 100x

x = 30

Another way:

75/100 is in reality 3/4

and 3/4 of 40 = 30

40/4 = 10

10 * 3 = 30

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

[tex]y=4x+6[/tex]

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope (also called the gradient) and b is the y-intercept (the value of y when x is 0)

1) Plug the gradient into the equation (b)

[tex]y=mx+b[/tex]

We're given that the gradient of the line is 4. Plug this into [tex]y=mx+b[/tex] as m:

[tex]y=4x+b[/tex]

2) Determine the y-intercept (b)

[tex]y=4x+b[/tex]

Plug in the given point (1,10) as (x,y) and solve for b

[tex]10=4(1)+b\\10=4+b[/tex]

Subtract 4 from both sides to isolate b

[tex]10-4=4+b-4\\6=b[/tex]

Therefore, the y-intercept of the line is 6. Plug this back into [tex]y=4x+b[/tex] as b:

[tex]y=4x+6[/tex]

I hope this helps!

answer = y = 4x + 6

y = mx + b

gradient = slope = m = 4

(1,10) = (x,y)

plug in the values

10 = 4 (1) + b

10 = 4 + b

b = 6

y = 4x + 6

Answer:

I only have the answer for B

Step-by-step explanation:

This is the answer: 1st blank: 7y

2nd blank: 9

3rd blank: 42xy

Answer:

if you look at carefully the left triangle has two same side. so left-angle of C is 180-130=50 degree 5x+5x+50=180 x=13 degree

Step-by-step explanation:

for right triangle again one angle is 50 degree and other is 6*13-(3)=75 degree so 75+50+(10y+5)=180 degree y=5 degree

Answer:

[tex]x=13\text{ and } y=5[/tex]

Step-by-step explanation:

First, notice that ∠BCD and ∠DCE form a linear pair. Linear pairs sum to 180°. Therefore:

[tex]m\angle BCD + m\angle DCE = 180[/tex]

And since we know that ∠BCD measures 130°:

[tex]m\angle DCE = 180-130=50^\circ[/tex]

And since ∠DCE and ∠BCA are vertical angles:

[tex]\displaystyle \angle DCE \cong \angle BCA[/tex]

Therefore, by definition:

[tex]m\angle DCE = m\angle BCA = 50^\circ[/tex]

Looking at the left triangle, we can see that BC and AC both have one tick mark. This means that they are congruent. Therefore, ΔABC is an isosceles triangle. The two base angles of an isosceles triangle are congruent. Hence:

[tex]m\angle A = m\angle B[/tex]

The interior angles of a triangle must total 180°. So:

[tex]m\angle A + m\angle B +m\angle BCA = 180[/tex]

Substitute in known values:

[tex]m\angle A + m\angle A+ (50)=180[/tex]

Simplify:

[tex]2m\angle A=130[/tex]

Divide both sides by two:

[tex]m\angle A = 65[/tex]

Substitute:

[tex](5x)=65[/tex]

Therefore:

[tex]x=13[/tex]

Similarly, for the triangle on the right, we can write that:

[tex]m\angle D + m\angle E + m\angle DCE = 180[/tex]

Substitute:

[tex](10y+5)+(6x-3)+(50)=180[/tex]

Combine like terms:

[tex]10y+6x+52=180[/tex]

Since we determined that x = 13:

[tex]10y+6(13)+52=180[/tex]

Simplify:

[tex]10y+130=180[/tex]

Therefore:

[tex]10y=50[/tex]

And by dividing both sides by 10:

[tex]y=5[/tex]

Answer:

18.29

Step-by-step explanation:

32000 ÷ 35 ÷ 50 = 18.2857143

Answer:

dssadsasdsa

Step-by-step explanation:

ignore this need points for alt

Answer:

a)4

Step-by-step explanation:

(a+b)²=43 eqn 1

(a²+b²)=35 eqn 2

solving eqn 2 by putting the value of (a+b)² by eqn 1

hope it helps

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as [tex]x + 2y\geq 1200[/tex].​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are [tex]\$600[/tex] a term.

So, the fees for [tex]x[/tex] day students are [tex]\$600x[/tex] a term.

The fees for a boarding student are [tex]\$1200[/tex] a term.

The fees for [tex]y[/tex] boarding student are [tex]\$1200y[/tex] a term.

Total fees for [tex]x[/tex] day students and [tex]y[/tex] boarding student is:

[tex]\text{Total fees}=600x+1200y[/tex]

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

[tex]600x+1200y\geq 720000[/tex]

[tex]600(x+2y)\geq 720000[/tex]

Divide both sides by 600.

[tex]\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}[/tex]

[tex]x+2y\geq 1200[/tex]

Hence proved.

Answer:

20km is in 12.5miles

Step-by-step explanation:

5miles= 8km

12.5miles=xkm

12.5÷5miles=2.5miles

2.5miles/km

2.5×8km=20km

1.4

2.8

3.7 by 10

*Others do by your self*

Step-by-step explanation:

1. 3×4/3= 4

2.⅖×20=8

3.6/5×7/18=7/15

4.10/7×9/5=18/7= 2 4/7. Mixed Fraction

5.4/15×25/8=5/6

6.6×¾= 9/2= 4 1/2. Mixed Fraction

Answer:

9

Step-by-step explanation:

f(2)=(2+1)^2

(3)^2

(9)

Answer:

[tex]40\ cm^3[/tex]

Step-by-step explanation:

Let the actual volume is V.

The measured volume of an object is 46 cubic cm  which was 15% high from the actual volume.

According to the given condition,

[tex]V+\dfrac{15V}{100}=46\\\\\dfrac{115V}{100}=46\\\\V=\dfrac{4600}{115}\\\\V=40\ cm^3[/tex]

So, the actual volume was [tex]40\ cm^3[/tex].

Answer:

=x4y2z2−2x3y3z+2x3yz3+x2y4−4x2y2z2+x2z4+2xy3z−2xyz3+y2z2

Make me brainliest

Answer:

x2y-x2z-xy2+xz2+y2z-yz2

step by step

step.1

Equation at the end of step 1:(((x2)•(y-z)(+((y2)•(z-x)))+z2•(x-y)

step2

Equation at the end of step2

(((x2)•(yz))+yz•(z-x))+z2•(x-y)

step.3

equation at the end of step 3.

(x2•(y-z)+y2•(z-x))+z2•(x-y)

step4

trying to factor by pulling out:

factoring: x2y-x2z-xy2+xz2+y2z-yz2

thought fully split the expression at hand into groups,each group having two terms:

group1: y2z-yz2

group 2: x2y-x2z

group 3: xz2-yz2

pull out from each groups separately:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:(x-y)•(z2)

looking for common sub-expressions:

group 1:(x-z)•(-y2)

group 2:(y-z)•(x2)

group 3:( x-y)•(z2)

bad news !! factoring by pulling out fails:

The groups have no common factor and cannot be added up to form a multiplication.

final result:

x2y-x2z-xy2+xz2+y2z-yz2

Answer: 19/3

Step-by-step explanation:

[tex]4x+3-x-5=30-3x\\\\3x-8=30-3x\\\\6x-8=30\\\\6x=38\\\\x=\frac{19}{3}[/tex]

Answer:

(x+3)^2=5

Step-by-step explanation:

x^2-4x+4=2x

x^2-6x+4=0

x^2-6x+9-5=0

(x-3)^2-5=0

(x-3)^2=5

Answer:

The interest for the two years is Rs 51.

Step-by-step explanation:

Rate, R = 4 %

Compound interest for 1 year = Rs 25

Let the sum is P.

For first year,

[tex]A = P \left ( 1+\frac{R}{100} \right )^1\\\\A = P(1+0.04)\\\\A - P = 0.04 P\\\\0.04 P = 25\\\\P= Rs625[/tex]

For 2 year

[tex]A = P \left ( 1+\frac{R}{100} \right )^2\\\\A = 625(1+0.04)^2\\\\A = 676\\[/tex]

Interest is

Interest = Rs 676 - Rs 625 = Rs 51

Answer:

(x - 6)² + (y + 7)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (6, - 7 ) and r = 4 , then

(x - 6)² + (y - (- 7) )² = 4² , that is

(x - 6)² + (y + 7)² = 16