A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is the number of 3-point questions and y is the number of 5-point questions, the system is shown represents this equation. x + y = 24 3x + 5y = 100

Scale factor used by Nancy for the model of an airplane = 1 : 14

Length of the tail of the airplane = 5.7 inches

Scale factor is defined by the expression,

Scale factor = [tex]\frac{\text{Dimension of the image}}{\text{Dimension of the original}}[/tex]

By substituting the dimension of the model in the expression,

[tex]\frac{1}{14}=\frac{5.7}{\text{Dimension of the original}}[/tex]

Dimension of the original plane = 14 × 5.7

                                                     = 79.80 inches

Therefore, length of the tail of the actual airplane will be 79.80 inches.

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Length of Actual airplane's tail is 79.8 inches or 6.65 ft

Given:

Scale model sample = 1 : 14

Length of model airplane's tail = 5.7 inches

Find:

Length of Actual airplane's tail

Computation:

Length of Actual airplane's tail = Length of model airplane's tail × Scale model sample

Length of Actual airplane's tail = 5.7 × 14

Length of Actual airplane's tail = 79.8 inches

Length of Actual airplane's tail = 79.8 inches or 6.65 ft

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Answer:

[tex]\frac{14}{19}[/tex]

First:

Convert any mixed numbers to fractions.

Then your initial equation becomes:

[tex]\frac{7}{4} \div \frac{19}{8}[/tex]

Applying the fractions formula for division:

[tex]= \frac{7 \times 8}{4 \times 19}[/tex]

[tex]= \frac{56}{76}[/tex]

Simplifying 56/76, the answer is:

[tex]\frac{14}{19}[/tex]

I hope this helps! :)

Answer:

the answer is 14/19

change the mixed numbers to improper fractions then that becomes 7/4 and 19/8 then multiply across 7x8=56 and 19x4=76 that gives you 56/76

Simplifying 56/76,=  14/19  

Answer:

3x^2+5x+2

Step-by-step explanation:

(3x^2)+(2x)+(3x)+(2)

3x^2+5x+2.

Answer:

3x²+5x+2

Step-by-step explanation:

(x+1)(3x+2)

(3x²)+(2x)+(3x)+(2)  

3x²+5x+2.

Answer:

a)

[tex] \frac{3.6}{1.5} = \frac{36}{15} = 2.4[/tex]

b)

[tex] \frac{42}{0.21} = \frac{4200}{21} = 200[/tex]

c)

[tex] \frac{200}{0.5} = \frac{2000}{5} = 400[/tex]

I hope I helped you^_^

Answer:  5*sqrt(5)

This is the same as sqrt(125).

It approximates to roughly 11.1803

=========================================================

Explanation:

Vector u is 5 units long as indicated by the notation ||u|| = 5. Some math books would say |u| = 5, and it's the same thing. The double bars are probably more fitting because it helps emphasize we're looking for the length of a vector and we're not using absolute value bars.

The second equation ||u|| = (1/2)*||v|| can be rewritten into ||v|| = 2*||u|| telling us that vector v is twice as long compared to vector u. Since vector u is 5 units long, that must mean vector v is 10 units long.

The two vectors are orthogonal, i.e. they are perpendicular. The vector u+v represents the diagonal of the rectangle as shown below in the attached image. Vector u is horizontal, v is vertical, and u+v is the diagonal. Technically we don't know where vector u is pointed along a compass (it may or may not be pointing directly east), but I find it's easier to have it set up like this. The answer will be the same regardless of where vector u is pointed. Rotations don't affect vector lengths.

We can see that vector u+v effectively breaks down component-wise into the horizontal component u and vertical component v (think of them as x and y components respectively).

Furthermore, note how there are two right triangles that form when we draw in the diagonal of the rectangle.

To find the length of vector u+v, we apply the pythagorean theorem.

a^2+b^2 = c^2

( ||u|| )^2 + ( ||v|| )^2 = ( ||u+v|| )^2

( 5 )^2 + ( 10 )^2 = x^2

25 + 100 = x^2

125 = x^2

x^2 = 125

x = sqrt(125)

x = sqrt(25*5)

x = sqrt(25)*sqrt(5)

x = 5*sqrt(5) is the length of vector u+v

In other words, ||u+v|| = 5*sqrt(5)

Keep in mind that this trick using the pythagorean theorem only works when vectors u and v are orthogonal. The process to find ||u+v|| for non-orthogonal vectors u,v is a bit more complicated.

Answer:

[tex]1\frac{1}{4}[/tex] cups

Step-by-step explanation:

3/4=3/5

3/4*1/3=3/5*1/3

1/4 = 1/5

1/4*5=1/5*5

5/4=5/5

5/4= 1 and 1/4 cups

Hope this helped! Please mark brainliest :)

~~ SUMMER ~~

Answer:

rs140

Step-by-step explanation:

I=P×T×R/100

1400×2×5/100

2800×5/100

14000/100

140

Step-by-step explanation:

Principle(p)= 1400

time= 2 year

rate= 5%

interest= p×t×r/100

= 1400×2×5/100

= 14000/100

=140

Answer:

4x-2y =42 is the required equation

Step-by-step explanation:

given equation is,

4x-2y -7=0---------eqn1

parallel equation of given equation is

4x -2y+k =0-------eqn 2

now passing it through (9,-3), we get,

4×9 + 2×3 +k = 0

or,36+6+k =0

or,42+k =0

or, k= -42

putting the value of k in eqn2

4x-2y - 42=0

4x-2y = 42

Answer:

18 ft

Step-by-step explanation:

The circumference of a circle is given by

C = 2 * pi *r

113.04 = 2 ( 3.14) * r

113.04 = 6.28 r

Divide each side by 6.28

113.04/6.28 = 6.28r/6.28

18 =r

Answer:

2. ☑ A [tex]\displaystyle f(x) = tan\:\frac{1}{2}x[/tex]

☐ B [tex]\displaystyle f(x) = tan\:2x[/tex]

☐ C x = [tex]\displaystyle 2tan\:x[/tex]

1. ☐ A [tex]\displaystyle \frac{\pi}{2}[/tex]

☐ B [tex]\displaystyle \pi[/tex]

☑ C [tex]\displaystyle 2\pi[/tex]

Explanation:

[tex]\displaystyle \boxed{f(x) = -cot\:(\frac{1}{2}x - \frac{\pi}{2})} \\ \\ y = Acot(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\pi} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

OR

[tex]\displaystyle y = Atan(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{\pi}{B} \hookrightarrow \boxed{2\pi} \hookrightarrow \frac{\pi}{\frac{1}{2}} \\ Amplitude \hookrightarrow N/A[/tex]

Here is all the information you will need. Now, what you need to know is that ALL tangent, secant, cosecant, and cotangent functions have NO amplitudes. Also, keep in mind that although this IS the tangent graph, if you plan on writing your equation as a function of cotangent, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = cot\:\frac{1}{2}x,[/tex] in which you need to replase "tangent" with "cotangent", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the tangent graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cotangent graph [photograph on the right] is shifted [tex]\displaystyle \pi\:units[/tex] to the left, which means that in order to match the tangent graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \pi\:units,[/tex] which means the C-term will be positive, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\pi} = \frac{\frac{\pi}{2}}{\frac{1}{2}},[/tex] but we are NOT YET DONE. Although we shifted the graph back into position, remember, cotangent is graphed in REVERCE, so we need to insert a negative in front of the amplitude term, and with that, the cotangent graph of the tangent graph, accourding to the horisontal shift, is [tex]\displaystyle y = -cot\:(\frac{1}{2}x - \frac{\pi}{2}).[/tex] Now, with all that being said, we can move forward. To find the period in this case, you need to take a look at the distanse between each vertical asymptote. Now, accourding to this graph, the vertical asymptotes are [tex]\displaystyle -\pi = x\:and\:\pi = x.[/tex] From here, you will then find the distanse between these asymptotes by simply perfourming the operation of Deduction, and doing that will give you [tex]\displaystyle \boxed{2\pi} = \pi + \pi.[/tex] So, the period of this function is [tex]\displaystyle 2\pi.[/tex] Now, you will instantly get the jist of the horisontal shift by looking at the above formula. Just keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must pay cloce attention to what is given to you inside those parentheses. Finally, the midline is the centre of your graph, also known as the vertical shift, which in this case is at [tex]\displaystyle y = 0.[/tex]

Well, that just about wraps it up. Now that everything has been explained, you should understand it better. If you still have questions, do not hesitate to comment any you have.

I am delighted to assist you at any time.

Answer:

30

Step-by-step explanation:

Another way to group the factor would be 3(2×5)

2 times 5 is 10 and then 10 times 3 is 30 so therefore, your answer is 30

Answer:

-15

Step-by-step explanation:

17+2a=-13

2a=-30

a=-15

Answer:

r = 6

Step-by-step explanation:

– 36 – 4r = -2(-6 + 6r)

+36               +36

----------------------------------

-4r = -12r + 48

+12r     +12r

----------------------------------

8r = 48

/8     /8

----------------------------------

r = 6

Answer:

r = 6

Step-by-step explanation:

– 36 – 4r = -2(-6 + 6r)

-36 - 4r = 12 - 12r

-48 - 4r = -12r

-48 = -8r

r = 6

Answer:

x is equal to 6√3

Step-by-step explanation:

[tex] - \frac{2}{3} \sqrt{5} . \: { \boxed{x}}. \: \sqrt{7} = - 4 \sqrt{105} \\ \\ - \frac{2}{3} \sqrt{5} .{ \boxed{x}}. \sqrt{7} = - 4( \sqrt{3} \times \sqrt{5} \times \sqrt{7} ) \\ \\ - \frac{2}{3} x = - 4 \sqrt{3} \\ \\ x = \frac{12 \sqrt{3} }{2} \\ \\ x = 6 \sqrt{3} [/tex]

Answer:

5+h/n+3

Step-by-step explanation:

5+h is numerator

and n+3 is denominator

so you make it a fraction to get the quotient which is 5+h/n+3

Equations are represented with the = sign. It means both sides of the equation are equal. [tex]11=t+11.5-t[/tex] has no solution

Given that:

[tex]11=t+11.5-t[/tex]

Start by collecting like terms

[tex]11-11.5=t-t[/tex]

Evaluate like terms

[tex]-0.5 = 0[/tex]

-0.5 is not equal to 0.

Hence, the equation has no solution

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Answer:

$31,598.33

Step-by-step explanation:

she worked 4+5=9 days.

due the total average we need the total of sales and divide it by the length of the observation period (9 days).

how much did she sell in total on the first 4 days ?

well, the average times 4 = 32130×4 = $128520

how much did she sell in total during the following 5 days ?

31173×5 = $155865

so, the daily average is

($128520 + $155865) / 9 =$284385 / 9 = $31,598.33

Answer:

2/12 the answer

Answer:

The correct answer is A.

Step-by-step explanation:

Step-by-step explanation:

[tex] \frac{1}{ \sqrt{2} + 1 } [/tex]

(On Rationalizing )

[tex] = \frac{1}{ \sqrt{2} + 1} \times \frac{ \sqrt{2} - 1}{ \sqrt{2} - 1 } [/tex]

[tex] = \frac{ \sqrt{2} - 1 }{( { \sqrt{2} )}^{2} - {(1)}^{2} } [/tex]

[tex] = \frac{ \sqrt{2} - 1}{2 - 1} [/tex]

[tex] = \frac{ \sqrt{2} - 1}{1} [/tex]

[tex] = \sqrt{2} - 1(ans)[/tex]

Step-by-step explanation:

[tex]here \: b \: is \: the \: mid \: point \\ so \: ab = bc \\ 10x - 17 = 6x + 11 \\ x \: terms \: togather \\ 10x - 6x = 11 + 17 \\ 4x = 28 \\ x = \frac{28}{4} \\ x = 7 \\ thank \: you[/tex]

Answer:

C. 640π cubic units

Answer:

D

Step-by-step explanation:

x + 5 > 11

is the same as

x > 6

and because it is ">" and not ">=", the solution point is not included.

therefore the right graph is D and not C. an empty little circle means "excluded", while a filled, black circle means "included".

Answer:

90 degrees

Step-by-step explanation:

Answer:

probability

Step-by-step explanation:

do some division to calculate the probality of landing on a blue 1/3 and add up the numbers.

Answer:

rational

Step-by-step explanation:

if a number can be written as a fraction,  where p and q are integers and q is a non-zero number

Answer:

vdffdersewsesdfdresweseseseeerswesdsfd

Step-by-step explanation:

reterersesdvbvfdderereerereeeewwqwewereddddscdcvvbvfddewww

Answer:

A. b2 – 4ac = 0

Step-by-step explanation:

Hey user☺☺

Option a is correct

Because the graph has only one solution.

As the graph touches the x-axis at one point that means that it will have only one solution for x. But we know that a quadratic equation has two solutions. So the graph will have two equal solution and therefore the discriminant will be 0.

Hope this will help☺☺

Answer:

A. (16-12)

Step-by-step explanation:

16-12

Answer

=4