When the person jumps off the platform, traveling a horizontal distance of 1.00 m while falling a vertical distance of 0.500 m to the ground, the final speed of the platform is: 0.602 m/s
The momentum of the person right before he jumps off is given by [tex]P = m*v = 75 kg * 0 m/s = 0 Ns.[/tex]
After he jumps off, the momentum of the platform-person system must remain the same: P = m*v. So, the final velocity of the platform after the person jumps off is given by v = P/m.
Now, we just need to calculate the new momentum of the system after the person jumps off. For that, we can use the conservation of energy, which states that the total energy in a closed system remains constant:
Potential energy before = Potential energy after + Kinetic energy after mgh
[tex]= (1/2)mv^2 + (1/2)Mv^2[/tex]
where m is the mass of the person (75.0 kg), M is the mass of the platform (155 kg), h is the height (0.500 m), and v is the velocity of the platform after the person jumps off.
Solving this equation for v, we get:
[tex]v = sqrt(2gh/(m+M))[/tex]
[tex]v = sqrt(2*9.81*0.500/(75.0+155)) = 0.602 m/s[/tex]
Therefore, the final speed of the platform is 0.602 m/s.
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what are two characteristics of net forces that are balanced
Balanced net forces have equal and opposing forces that cancel each other out and provide a net force of zero, which does not alter the motion of an item.
An object's velocity remains constant and motion is unaltered when the net forces acting on it are balanced. This indicates that the thing is either stationary or moving continuously. When the forces exerted on an item are opposing in direction and of equal magnitude, they are said to be balanced forces. The forces in this situation cancel one another out, leaving a net force of zero. This can happen when one force is applied to an item and that object applies an equal and opposite force in the opposite direction to another object. It can also happen when two or more forces are applied in opposing directions and of equal magnitude. Understanding equilibrium and stability in physics requires a knowledge of the idea of balanced forces.
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what is the relationship between the velocity of a fluid and the size of the sediment that the fluid carries?
The relationship between the velocity of a fluid and the size of the sediment that the fluid carries is directly proportional.
Higher velocity fluids are capable of carrying larger sediments while lower-velocity fluids are capable of carrying smaller sediments. This is due to the fact that higher-velocity fluids have greater kinetic energy, which allows them to overcome the gravitational forces that hold larger sediments in place.
A fluid is a substance that is able to flow and take on the shape of the container it is placed in, with the ability to deform under applied shear stress. Examples of fluids include liquids and gases. In contrast, solids maintain their shape and volume under applied stress.
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a train moves from a train station at 30meter per second after 5 seconds its cover the distance of 100 m and the acceleration is ten meters per second square find the speed
The speed of a train that moves from a train station at 30 meters per second after 5 seconds and covers a distance of 100 m with an acceleration of ten meters per second square would be 80 m/s.
Speed of a trainWe can use the equation of motion to solve for the final velocity of the train:
v = u + at
where:
v = final velocityu = initial velocity = 30 m/sa = acceleration = 10 m/s^2t = time = 5 sSubstituting the values, we get:
v = 30 + 10(5)
v = 80 m/s
Therefore, the speed of the train after 5 seconds is 80 m/s.
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what is the current in a counductor if 3.15*10^18 electrons pass a given point in the conductor in 10 seconds
The current in a counductor if 3.15*10^18 electrons pass a given point in the conductor in 10 seconds is 0.0504 amperes
Current calculation.
The current in a conductor is defined as the rate at which electric charge flows through it. The unit of current is amperes (A), which is defined as coulombs per second. One coulomb is equal to the charge on 6.24 × 10^18 electrons.
Given that 3.15 × 10^18 electrons pass a given point in the conductor in 10 seconds, we can find the charge that flows through the point as follows:
Number of electrons = 3.15 × 10^18
Charge on one electron = 1.6 × 10^-19 coulombs
Total charge = Number of electrons × Charge on one electron
Total charge = 3.15 × 10^18 × 1.6 × 10^-19
Total charge = 0.504 coulombs
The current is the rate of flow of charge, so we can find it by dividing the total charge by the time taken:
Current = Total charge ÷ Time taken
Current = 0.504 coulombs ÷ 10 seconds
Current = 0.0504 amperes (A)
Therefore, the current in the conductor is 0.0504 amperes, or 50.4 milliamperes (mA).
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As a wave moves through a medium, the individual particles of the medium move from source of the wave to another location some distance away.
True or False
Answer:
False: Generally, the particles move in a vertical direction, vibrating perpendicular to the propagation of the wave.
A ________ is a descriptive research activity representing a small-scale investigation of 10 to 30 subjects that are representative of the main study's defined target population but focus on a specific subcomponent of the main study.
Multiple Choice
median
pretest
pilot test
pilot study
mode
A d.pilot study is a descriptive research activity representing a small-scale investigation of 10 to 30 subjects that are representative of the main study's defined target population but focus on a specific subcomponent of the main study.
A pilot study is a small-scale study that is usually carried out before the main study or trial to test if the intended study design, data collection method(s), measurement instruments, and data analysis techniques are feasible and sufficient. This is also done to ensure that data is collected in a way that minimizes the risk of error in the main study.
Mode, the most frequently occurring value in a data set is referred to as the mode. It is frequently utilized with categorical or nominal data. Pretest, before the test, a pretest is given to test subjects to establish a baseline for their knowledge or capability. Median, in statistics, the median is a measure of central tendency that is used to split a dataset into two equal parts. It is used with continuous or ordinal data.
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a painter (of mass 68 kg) needs to reach out from a scaffolding to paint the side of a building, so he lays a plank across two bars of the scaffolding, and puts a heavy bucket of mass 29 kg directly over one of the bars (see figure). you can assume the plank is massless, and is long enough to reach to the other building. Otheexpertta.com If the bars are separated by distance 1 how far; d, from the bar on the the right can the painter walk before the plank starts to fall? Numeric A numeric value is expected and not an expression_
0.99. is the distance from the bar on the right the painter walk before the plank fell.
To solve the given problem, we have to use the principle of moments which states that a body is in rotational equilibrium if the sum of clockwise moments is equal to the sum of anti-clockwise moments.
Let the distance between the painter and the bar on the right be x.
Then the distance between the painter and the bar on the left is 1 − x.
We have to find the maximum value of x for which the plank does not tip over.
As the plank is in equilibrium, the net moment about any point should be zero.
Here we will take the moment about the bar on the left so the clockwise moment will be taken as positive and the anticlockwise moment as negative.
The moment due to the painter will be the product of the mass of the painter, the distance of the centre of gravity of the painter from the left bar which is (1−x)/2, and the acceleration due to gravity.
The moment due to the bucket of 29 kg will be the product of the mass of the bucket, the distance of the centre of gravity of the bucket from the left bar which is x, and the acceleration due to gravity.
The moment due to the plank is zero as the plank is massless and the plank's centre of gravity lies at the centre which is midway between the two bars.
The expression for the principle of moments is shown below:-
m1g (1 - x)/2 + m2g x = 0
where, m1 = mass of painter,
m2 = mass of bucket and
g = acceleration due to gravity
Substituting the given values we get:-
68 (9.8) (1 - x)/2 + 29 (9.8) x = 0
Simplifying the above equation, we get:-
333.4x + 330.4 = 0x = 0.99 m
a painter (of mass 68 kg) needs to reach out from a scaffolding to paint the side of a building, so he lays a plank across two bars of the scaffolding, and puts a heavy bucket of mass 29 kg directly over one of the bars (see figure).
you can assume the plank is massless, and is long enough to reach to the other building. f the bars are separated by distance 1 how far; d, from the bar on the the right can the painter walk before the plank starts to fall.
Thus, the painter can walk to a distance of 0.99 m from the right bar before the plank starts to fall.
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a 421 kg block is puled up a 4.54 degree incline by a constant force f of 3282 n. the coefficient of friction mu between the block and the plane is 0.47. how fast in m/s will the block be moving 6 seconds after the pull is applied?
The block will be moving at 3.97 m/s 6 seconds after the pull is applied.
Given Mass of the block, m = 421 kg, Inclined angle, θ = 4.54°, Force applied, F = 3282 N, Coefficient of friction, μ = 0.47, Time, t = 6 s
Using Newton's second law of motion, F - μmg sin θ = ma
Where,
m = Mass of the block
g = Acceleration due to gravity
a = Acceleration of the block
Substituting the given values,
3282 - 0.47 × 421 × 9.81 × sin 4.54° = 421 × a
a = 0.6614 m/s²
Using kinematic equations of motion,
v = u + at
Where,
u = Initial velocity
v = Final velocity
a = Acceleration
t = Time
Since the initial velocity is zero, the above equation becomes
v = at
Substituting the values,
v = 0.6614 m/s² × 6 s
v = 3.97 m/s
Therefore, the block will be moving at 3.97 m/s 6 seconds after the pull is applied.
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if the true stress - true plastic strain curve can be described by the hollomon equation , obtain the true strain at the onset of necking in terms of hollomon equation parameters
The true strain at the onset of necking can be obtained from the Hollomon equation as follows: true strain = (K/S)^(1/n).
Here, K is the strength coefficient, S is the stress, and n is the strain hardening exponent. Thus, given the values of these parameters, we can calculate the true strain at the onset of necking.
The Hollomon equation is a mathematical expression for the true stress-true strain curve that relates the true stress to the true strain in a material. It is expressed as follows: true stress = K(true strain)^n. Here, K is the strength coefficient and n is the strain hardening exponent.
The true strain at the onset of necking is the strain at which the material starts to deform plastically instead of elastically. This can be obtained from the Hollomon equation by rearranging it to the form true strain = (K/S)^(1/n). Thus, given the values of the parameters K, S, and n, we can calculate the true strain at the onset of necking.
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A car speeds up at a constant rate pf 4 m/s?. An identical car takes a right turn with 4 m radius at constant speed of 8 m/s. Which of the following statements is correct? A. The car speeding up experiences the greater net force. B. The car speeding up experiences zero net force. C. The car that is turning experiences the greater net force. D. The car that is turning experiences no net force.
The correct answer is the car that is turning experiences no net force.
What is a net force?A net force is the sum of all forces acting on an object, taking into account their magnitude and direction. If an object is not in equilibrium, it experiences a net force, which causes it to accelerate. In physics, a net force, often known as unbalanced force, is defined as the total sum of all forces that act on an object. If the forces acting on an object are balanced, meaning they are the same size but opposite in direction, the object will maintain a constant speed with no acceleration.
In this scenario, the car speeding up experiences the greater acceleration. The car that is turning, on the other hand, experiences no net force since the force acting on the car, the centripetal force, is equal to the force required to maintain its motion.
Therefore, the answer is option D. The car that is turning experiences no net force.
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which of the following best describes bedded gypsum and halite? a. varieties of coal b. varieties of calcium carbonate evaporites; c. chemical sedimentary rocks d. detrital sedimentary rocks
Bedded gypsum and halite are chemical sedimentary rocks. These rocks are formed through the chemical precipitation of minerals from solution.
Chemical sedimentary rocks are formed when minerals dissolve in water and then precipitate, forming layers of solid sediment. The most frequent minerals are halite, gypsum, and limestone. Some of these rocks are deposited as evaporites or are formed by alteration of previously deposited chemical sediments. These rocks are made up of mineral grains that are the result of a chemical reaction.
Halite, gypsum, and other minerals are examples of this type of rock. They're usually made up of a single mineral type or a combination of two or more minerals that have been deposited from water or other fluids. These rocks are formed through processes such as precipitation, evaporation, and alteration of minerals by water or other fluids. Halite and gypsum are the two most common minerals found in this type of rock.
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What is the length of the x-component of the vector shown below?
The length of the x-component of the vector is approximately 48.55 units.
What is the length of the x-component of the vector?To find the length of the x-component of the vector, we need to use trigonometry.
We can use the angle and the magnitude (length) of the vector to find the x-component using the formula:
x-component = magnitude x cos(angle)
Plugging in the values given, we get:
x-component = 52 units x cos(21⁰)
x-component = 52 units x 0.9336
Multiplying these two numbers, we get:
x-component ≈ 48.55 units
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an electromagnetic wave is transporting energy in the positive y direction. at one point and one instant the magnetic field is in the positive x direction. the electric field at that point and instant points in the
Energy is being transported in the positive y direction by an electromagnetic wave. The magnetic field is in the positive x direction at one spot and one moment. At that precise moment, the electric field is oriented in the "negative z" direction.
The given electromagnetic wave is transporting energy in the positive y direction. At one point and one instant, the magnetic field is in the positive x direction. Now we have to find the direction of the electric field at that point and instant. According to the right-hand rule, when the magnetic field is directed towards the positive x-axis, the electric field will be directed downwards along the negative z-axis. Therefore, the electric field at that point and instant points in the negative z direction.
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The tires of a car make 95 revolutions as the car reduces its speed uniformly 95 km/h to 55 km/h. The tires have a diameter of 0.80 m. (a) what was the angular acceleration of the tires? If the car continues to decelerate at this rate, (b) how much more time is required for it to stop, and (c) how far does it go?
(a) Angular acceleration of the tyres= 7.3 rad/s^2
(b) Time required to stop= 8.9 s
(c) Distance travelled= 492.5 m
The angular acceleration of the tires can be calculated by using the following equation:
Angular acceleration = (Change in angular velocity)/(time).
Using the given information, we can calculate the angular acceleration as follows:
Angular velocity = (95 revolutions)/(95 km/h)
Time = (95 km/h - 55 km/h)/(95 km/h)
Angular acceleration = (95 revolutions)/(Time x 0.80 m)
Angular acceleration = 7.3 rad/s^2
For part b, the amount of time required for the car to stop can be calculated as follows:
Time = (55 km/h)/(7.3 rad/s^2 x 0.80 m)
Time = 8.9 s
For part c, the distance the car travels can be calculated as follows:
Distance = (55 km/h x 8.9 s)
Distance = 492.5 m
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Suppose two protostars form at the same time, one with a mass of 0.5 msun and the other with a mass of 15 msun . Which of the following statements are true?
[Select ALL answers that are true in alphabetical order]
A) The 10MSun protostar will have a smaller change in surface temperature during this phase than the 0.5MSun protostar.
B) The 10MSun protostar will reach the main sequence cooler and fainter than the 0.5MSun protostar.
C) The 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage.
D) The 10MSun protostar will have a smaller change in luminosity during the sequence shown than the 0.5MSun protostar.
E) The 10MSun protostar will be much more luminous than the 0.5MSun protostar.
The two protostars form at the same time, the 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage, and 10MSun will be much more luminous than the 0.5MSun protostar. Thus, options C and E are correct.
More massive stars have shorter lifetimes because they burn through their nuclear fuel more quickly.
Therefore, the 10MSun star will end its main-sequence life before the 0.5MSun star even completes its protostar stage. Thus, option C is correct.
The luminosity of a star depends on its mass.
More massive stars have higher luminosities than less massive stars. Therefore, option E is correct.
Thus, options C and E are correct.
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a bullet is shot into a wood block. the bullet becomes embedded in the block, and they move off the ledge and land on the ground. the mass of the bullet is 2 g. the mass of the block is 98 g. the ledge height is 5 m. the block lands 10 m horizontally from the ledge. determine the initial speed of the bullet. let me see your literal equations first.
The initial speed of the bullet before being shot will be 1107 meters per second.
What are the given values?The mass of the bullet is given as 2 g. The mass of the block is given as 98 g. The height of the ledge is given as 5 m. The distance travelled by the block is given as 10 m.
We can use conservation of energy to find the initial velocity of the bullet. Conservation of energy: The work done on the block-bullet system is zero. Therefore, the initial potential energy of the block-bullet system is equal to the final kinetic energy of the block-bullet system. Potential energy of block-bullet system = Kinetic energy of block-bullet system
Initial potential energy = mgh
Final kinetic energy = (1/2)mv²
So, mgh = (1/2)mv²
where, m = total mass (mass of bullet + mass of block), h = height from where the block and bullet fall, v = final velocity
Let's calculate the total mass of the system:
m = mass of bullet + mass of block = 2 g + 98 g = 100 g = 0.1 kg
Let's substitute the values in the equation: 0.1 kg × 9.8 m/s² × 5 m = (1/2) × 0.1 kg × v²
v = 22.14 m/s
We can use conservation of momentum to confirm our result.
Conservation of momentum: Initial momentum = final momentum
0 = (m bullet × v bullet ) + (m block × v block ) (as the bullet gets embedded into the block, they both move with the same velocity)
v = (m bullet × v bullet )/(m bullet + m block )
Substituting the values:
v = (2 g × v bullet ) / (2 g + 98 g) = 0.02 v bullet / 1.00 = 0.02 v bullet
v bullet = 50 × v = 50 × 22.14 = 1107 m/s
Therefore, the initial speed of the bullet is 1107 m/s.
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A 12100 kg railroad car is coasting on a level, frictionless track at a speed of 19.0 m/s when a 4790 kg load is dropped onto it.
If the load is initially at rest, find the new speed of the car and the % change of the kinetic energy.
Hint 1: If the load is dropped into the car, it is like the car is "colliding� with a stationary load. If the load is stuck in the car, can they have different final velocities from one another?
The percent change in the kinetic energy of the system is [(0.5*(12100 + 4790)*1722) - 5.58 x 106] / (5.58 x 106) x 100% = 4.41%.
The 12100 kg railroad car is initially travelling at a speed of 19.0 m/s and has a kinetic energy of KE = 0.5*12100*1902 = 5.58 x 106 Joules. The 4790 kg load is dropped onto the car from rest, so its initial kinetic energy is 0.
When the load is dropped onto the car, the two objects collide and their velocities after the collision will be equal. Therefore, the final speed of both the railroad car and the load will be v = (12100*19 + 4790*0) / (12100 + 4790) = 17.2 m/s. The percent change in the kinetic energy of the system is [(0.5*(12100 + 4790)*1722) - 5.58 x 106] / (5.58 x 106) x 100% = 4.41%.
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A plane has an airspeed of 200 mph. The pilot wishes to reach a destination 900 mi due east, but a wind is blowing at 20. 0 mph in the direction 60. 0 ∘ north of east
The plane's heading is 4.61 degrees south of east, which is the direction the pilot needs to steer the plane in order to reach her objective and the trip takes 1.83 hours.
The airspeed of 200 mph can be broken down into its x and y components as follows: Vx = 200 mph * cos (0°) = 200 mph Vy = 200 mph * sin (0°) = 0 mph To solve this problem, we can break down the velocity vectors into their x and y components: The airspeed of 200 mph can be broken down into its x and y components as follows: Vx = 200 [tex]mph * cos (0°) = 200 mph Vy = 200 mph * sin (0°) = 0 mph[/tex]
The wind velocity of 20.0 mph at an angle of 60.0° north of east can be broken down into its x and y components as follows:[tex]Vwx = 20.0 mph * cos(60.0°) = 10.0 mph Vwy = 20.0 mph * sin(60.0°)[/tex] = 17.3 mph The resultant velocity vector is the vector sum of the airspeed and the wind velocity: Vrx = Vx + Vwx = 200 mph + 10.0 mph = 210 mpm Vry = Vy + Vwy = 0 mph + 17.3 mph = 17.3 mph
The speed of the plane relative to the ground is the magnitude of the resultant velocity vector:[tex]|Vr| = sqrt (Vrx^2 + Vry^2) = sqrt ((210 mph) ^2 + (17.3 mph) ^2) ≈ 211[/tex]mph The direction of the plane's velocity relative to the ground is given by the angle that the resultant velocity vector makes with due east:[tex]θ = atan(Vry / Vrx) = atan(17.3 mph / 210 mph) ≈[/tex] 4.7° north of east
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Complete question is :
A Plane Has An Airspeed Of 200 Mph. The Pilot Wishes To Reach Adestination 600 Mi Due East, But A Wind Is Blowing At 50 Mph In Thedirection 30o North Of Eastpart Ain What Direction Must The Pilot Head The Plane In Order To Reachher Destination? (2sig Figs)Part Bhow Long Will The Trip Take?(2 Sig Figs)Thanks!
a plane has an airspeed of 200 mph. the pilot wishes to reach adestination 600 mi due east, but a wind is blowing at 50 mph in thedirection 30o north of east
part A
in what direction must the pilot head the plane in order to reachher destination?
part B
how long will the trip take?
where are pisa and boston in relation to the moon when they have high tides?
The locations of Pisa and Boston in relation to the Moon have no bearing on the times of high tides. High tides are caused by the gravitational pull of the Moon on the Earth's oceans. The Moon's gravitational pull causes the oceans to bulge out towards the Moon, resulting in the two high tides per day.
The two high tides occur about 12 hours and 24 minutes apart, and the location of the Moon in the sky is always changing. During full moon and new moon, when the Moon is in alignment with the Sun, the gravitational pull of both celestial bodies is at its strongest, resulting in higher high tides.
The location of Pisa and Boston has no effect on high tide times, but they may experience higher tides due to local geography. If Pisa or Boston are near the ocean, their local geography may cause the tide to be higher or lower than normal. Additionally, weather conditions can also have an effect on local tide levels.
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A survey was conducted at local colleges around Madison, Wisconsin to find out the average height of a college student. Of 692 students surveyed, 421 replied that they were over 6 feet tall. What is the standard error? Answer choices are rounded to the hundredths place.
A survey was conducted at local colleges around Madison where 692 students were surveyed, and 421 replied that they were over 6 feet tall showing a standard error of 0.0084 in the average height of a college student.
The standard error is given by the formula given below:
[tex]$$SE= {s}/{\sqrt{n}}$$[/tex]
Where s is the standard deviation,
n is the sample size.
Now let us find out the standard deviation by using the formula given below:
[tex]$$s=\sqrt{\frac{(421-271.17)^2+(271.17-270)^2}{692-1}}$$[/tex]
After calculating we get that the standard deviation s is equal to $0.2208$.
Now let us plug the value of the standard deviation s and sample size n into the formula for standard error:
[tex]$$SE={s}/{\sqrt{n}}$$[/tex]
On substituting the respective values, we get [tex]$$SE={0.2208}/{\sqrt{692}}$$[/tex]
On solving, we get that the standard error is equal to 0.0084
Therefore, the standard error is 0.0084.
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upslope fog hugging the mountain surface occurs when: question 12 options: a. air warms because of decreasing atmospheric pressure
b. eventually air cools to the dew-point temperature air warms because of decreasing atmospheric pressure
c. eventually air warms to the dew-point temperature air cools because of increasing atmospheric pressure
d. eventually air cools to the dew-point temperature air cools because of decreasing atmospheric pressure
e. eventually air cools to the dew-point temperature
A decrease in atmospheric pressure eventually causes air to cool to the dew-point temperature.
How does surface-hugging upslope fog on mountains occur?Fog on an upward slope forms adiabatically. The process through which ascending air cools and sinking air warms is known as adiabatic cooling. The air rises and cools as wet breezes blow in the direction of a mountain. The dew point temperature is reached as a result of the rising air cooling.
Upslope fog: what is it?This type happens when air is lifted by sloping terrain and is adiabatically cooled to its dew point and saturation. Depending on the observer's frame of reference, upslope fog can be seen as either a stratus cloud or a fog.
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which of the following actions will cause the relative humidity of an air parcel to increase? select all that apply
a. Keep the parcel’s temperature constant and increase the parcel’s dew point
b. Decrease the parcels temperature and increasethe parcels dew point
c. Keep the parcel’s temperature constant and keep the parcels dew point constant
d. Increase the parcels temperature and increase the parcels dew point
e. Keep the parcels dew point constant and increase the parcels temperature
The relative humidity of an air parcel will increase if any of the following actions are taken:
Keep the parcel’s temperature constant and increase the parcel’s dew pointDecrease the temperature of the parcel and increase the parcels dew pointIncrease the temperature of the parcel and increase the parcels dew pointKeep the parcels dew point constant and increase the temperature of the parcelWhat is relative humidity?To understand this further, we can look at the formula for relative humidity, which is the amount of water vapor in the air divided by the amount of water vapor that can exist at a particular temperature. When the temperature is kept constant and the dew point increases, the amount of water vapor in the air increases, resulting in an increase in relative humidity.
The followings are the given options and the actions they will take that will cause the relative humidity of an air parcel to increase:
Option A: Keep the parcel's temperature constant and increase the parcel's dew point. This action would increase the RH of the air parcel because it will increase the quantity of water vapor in the air parcel. As the parcel's temperature is constant, the ability of the air to hold water vapor also remains constant.
Option B: Decrease the parcel's temperature and increase the parcel's dew point. This action would also increase the RH of the air parcel. As the temperature of the parcel decreases, the amount of moisture that the air can contain also decreases. When the dew point is raised, the quantity of water vapor in the air parcel rises relative to the amount it can carry.
Option C: Keep the parcel's temperature constant and keep the parcel's dew point constant. In this case, there will be no increase in RH because the quantity of water vapor in the air parcel will remain the same as the ability of the air to hold water vapor remains constant.
Option D: Increase the parcel's temperature and increase the parcel's dew point. Increasing the parcel's temperature will raise the ability of the air to hold water vapor, but it will not increase the amount of water vapor in the air parcel. As a result, the RH of the air parcel will decrease.
Option E: Keep the parcel's dew point constant and increase the parcel's temperature. This action will also decrease the RH of the air parcel as it will increase the amount of moisture that the air can hold. Thus, the relative humidity will decrease.
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hydroelectric dams generate electricity by question 20 options: a. using the energy of the river to produce steam. b. using run-of-the-river systems, in which turbines are placed into the natural water flow. c. water impoundment, in which dam operators control the rate of water flow to turbines. d. using generators that are placed on the bottom of a river. e. converting the kinetic energy of the water impounded behind a dam into potential energy.
Hydroelectric dams generate electricity through water impoundment, in which dam operators control the rate of water flow to turbines.
c is the correct option.
Hydroelectric dams are dams used to produce electricity. The movement of water drives turbines, which power generators that generate electricity.
The movement of water, generated by gravity, is what drives turbines. Hydroelectric dams are the most widely used renewable energy source, accounting for approximately 16% of global electricity production.
Hydroelectric dams generate electricity through water impoundment, in which dam operators control the rate of water flow to turbines.
This is the process of using turbines that are powered by the movement of water that has been dammed to generate electricity.
Turbines are powered by water that has been dammed to generate electricity, which is then sent to a power station to be used.
The electricity generated from hydroelectric dams is clean and safe, making it an important part of the renewable energy mix. They are also an essential part of the global infrastructure because they provide reliable, low-cost power.
They also assist in the management of rivers, flood control, and irrigation systems in various parts of the world.
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a cliff diver drops from rest to the water below. how many seconds does it take for the driver to go from 0 mi/h to 60 mi/h? (for comparison, it takes about 3.5 s to 4.0 s for a powerful car to go from 0 to 60 mi/h.)
It takes about 2.73 seconds for the cliff diver to reach a speed of 60 mph (88 ft/s or 27 m/s) if we assume no air resistance. In reality, air resistance would slow down the diver and increase the time required to reach this speed. The given speed in mph is required to be converted into fps to solve the problem.
We know,1 mile = 5280 feet1 hour = 3600 secondsTherefore,1 mile/hour = 5280/3600 = 1.467 feet/second (approx)So, 60 miles/hour = 60 * 1.467 = 88.02 feet/secondGiven, a cliff diver drops from rest to the water below.We know, initial velocity, u = 0 ft/sFinal velocity, v = 88.02 ft/sTime, t = ?We have,Acceleration due to gravity, g = 32 ft/s²We can use the kinematic equation,v = u + atto find the time taken by the driver to go from 0 to 60 miles/hour.We have,u = 0 ft/st = ?v = 88.02 ft/sg = 32 ft/s²v = u + at88.02 = 0 + 32tt = v/a= 88.02/32= 2.75 seconds (approx)Therefore, the cliff driver takes about 2.75 seconds to go from 0 miles/hour to 60 miles/hour while jumping from rest to the water below.
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A bitmap image is provided in two different resolutions. Image 1 has a resolution of 1500 x 1225. Image 2 has a resolution of 500 x 350. Which of the following statements is true when the sizes of both the files are increased by 25 percent?
Image 1 is sharper than image 2 and has a larger file size than image 2.
The true statement is "Image 1st is sharper than Image 2nd and has a larger file size than Image 2nd"
What is a bitmap image?A bitmap image is a type of digital image that is made up of pixels, which are small squares of color that form an image.
Bitmap image also known as raster images.
Explain image resolution?Image resolution refers to the number of pixels contained in a digital image, typically measured as the number of pixels per inch (PPI) or dots per inch (DPI). The resolution of an image determines the level of detail and clarity that can be seen in the image.
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Critically discuss why the environment in most communities continue to be dirty amidst the existence of local government structures
Explanation:
# Unmanaged population distribution
# lack of sanitation programs
# lack of awareness programs
# lack of implementation of policies and rules
# carelessness of people and government
# Unmanaged waste disposal
Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods a)Find the moment of inertia of the system about an axis through the center of the square, perpendicular to its plane (an axis through point O). b)Find the moment of inertia of the system about an axis bisecting two opposite sides of the square (an axis along the line AB). c)Find the moment of inertia of the system about an axis that passes through the centers of the upper left and lower right spheres and through point O.
The moment of inertia of the system for the three situations are 0.026667 kg m2,0.04 kg m2,0.013333 kg .
Four small spheres, each of which you can regard as a point of mass 0.200 kg, are arranged in a square 0.400 m on a side and connected by light rods
a) The moment of inertia of the system about an axis
through the center of the square,
perpendicular to its plane (an axis through point O) is equal to
4 x 0.200 kg x (0.400 m)2/12
= 0.026667 kg m2.
b) The moment of inertia of the system about an axis
bisecting two opposite sides of the square (an axis along the line AB) is equal to
4 x 0.200 kg x (0.400 m)2/8
= 0.04 kg m2.
c) The moment of inertia of the system about an axis
that passes through the centers of the upper left and lower right spheres and
through point O is equal to
2 x 0.200 kg x (0.400 m)2/12
= 0.013333 kg m2.
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when the air is in geostrophic balance, it flows _______ to isobars _________ the boundary layer.
When the air is in geostrophic balance, it flows parallel to isobars and above the boundary layer.
Geostrophic balance is a state of balance between the pressure gradient force and the Coriolis force, where the pressure gradient force is directed from higher to lower pressure, and the Coriolis force is perpendicular to the direction of motion. In this state, the wind flows parallel to the isobars, with the pressure gradient force and the Coriolis force balancing each other out.
The boundary layer is the layer of air near the Earth's surface where friction between the air and the surface slows down the wind and causes it to flow in a more complex manner, with the wind direction changing with height. However, in the geostrophic flow regime, the wind flow is typically above the boundary layer and thus not affected by surface friction.
Therefore, in geostrophic balance, the wind flows parallel to isobars and above the boundary layer, with little to no effect from the Earth's surface.
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water flows through a pipe with a cross-sectional area of 0.002 m2 at a mass flow rate of 4 kg/s. the density of water is 1 000 kg/m3. determine its average velocity. multiple choice question. 0.02 m/s 2 m/s 200 m/s 20 m/s 0.2 m/s
The average velocity of water flowing through a pipe with a cross-sectional area of 0.002 m² at a mass flow rate of 4 kg/s is 2 m/s.
What is the formula for average velocity?The formula for average velocity is:
v = Q / A
Where:
v is the average velocityQ is the volume flow rateA is the cross-sectional area of the pipeThe formula for volume flow rate is:
Q = m / ρ
Where:
m is the mass flow rateρ is the density of the fluidSubstituting the values:
v = Q / Av = (m / ρ) / Av = m / (ρA)Given that the cross-sectional area of the pipe is 0.002 m², the mass flow rate is 4 kg/s, and the density of water is 1000 kg/m³, the average velocity is:
v = 4 / (1000 × 0.002)v = 2 m/sTherefore, the average velocity of water flowing through a pipe with a cross-sectional area of 0.002 m² at a mass flow rate of 4 kg/s is 2 m/s.
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2.1 [2] As more resistors are added in series, the equivalent resistance of the circuit approaches infinity. In contrast, as more resistors are added in parallel, the equivalent resistance a. approaches infinity b. approaches zero c. becomes zero d. approaches 1 Ω
2.2 [2] Kirchhoff's loop rule is equivalent to which of the following principles? a. conservation of charge b. conservation of energy c. conservation of mass d. conservation of force
2.1 As more resistors are added in parallel, the equivalent resistance approaches zero
2.2 Kirchhoff's loop rule is equivalent to the conservation of energy principle.
As more resistors are added in series, the equivalent resistance of the circuit approaches infinity. In contrast, as more resistors are added in parallel, the equivalent resistance approaches zero. This statement is TRUE. The equivalent resistance, Req, of a parallel combination of resistors is less than any of the resistors in the combination, while for a series combination it is equal to the sum of the resistances.
Kirchhoff's loop rule is equivalent to the conservation of energy principle. Kirchhoff's loop rule or Kirchhoff's voltage law (KVL) is a result of the conservation of energy principle. The principle of conservation of energy states that energy can neither be created nor destroyed, it can only be transformed from one form to another. In a closed loop, the total energy gained is equal to the total energy lost, according to the principle of conservation of energy.
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