Answer:
There will need to be 2 and 1/3 cups of flour according to the recipe
Step-by-step explanation:
Given the recipe, we can say that for each 2 and 2/3s cups of milk, one cup of flour is used. We can write this as ( 2 + 2/3) cups of milk / (1) cup of flour.
We can also write 2 + 2/3 as 2*(3/3) + 2/3 = 6/3 + 2/3 = 8/3, making our ratio
(8/3) / 1
The ratio stays the same, no matter how many cups of milk or flour are used. Therefore, (8/3) /1 = (4 + 2/3) / cups of flour
Writing our final cups of flour as c, we can say
(8/3) / 1 = (4+2/3) / c
(4+2/3)/c = (12/3 + 2/3) /c = (14/3) /c
(8/3)/1 = (14/3) /c
anything divided by 1 is equal to itself
(8/3) = (14/3)/c
multiply both sides by c to make the variable not a denominator
(8/3) * c = 14/3
multiply both sides by 3 to remove the denominators
8 * c = 14
divide both sides by 8 to isolate the c
c = 14/8 = 7/3 = 6/3 + 1/3 = 2 + 1/3
There will need to be 2 and 1/3 cups of flour according to the recipe
find x
2 ^30 divided by 8^9= 2x
Answer:
see below
Step-by-step explanation:
2^30
-------
8^9
Rewriting
8^9
2^3 ^ 9
We know a^b^c = a^(b*c)
2^(3*9) = 2^27
2^30
-------
2^27
We know a^b / a^c = a^(b-c)
2^(30-27) = 2^3
Assuming you mean 2^x
2^3 = 2^x
x=3
If you mean 2x
2^3 = 8
8 = 2x
Divide by 2
4 =x
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{\dfrac{2^{30}}{8^9}=2x}[/tex]
[tex]\mathsf{2^{30}}\\\mathsf{= \bf 1,073,741,824}\\\\\mathsf{8^9}\\\mathsf{= \bf 134,217,728}[/tex]
[tex]\mathsf{\rightarrow \dfrac{1,073,741,824}{134,217,728}= 2x}\\\\\\\mathsf{\dfrac{1,073,741,824}{134,217,728}= \bf 8}\\\\\\\mathsf{\rightarrow \ 8 = 2x}\\\\\\\\\large\textsf{TURN\ the\ EQUATION\ around}\\\\\\\mathsf{\rightarrow\ 2x = 8}\\\\\\\large\textsf{DIVIDE 2 to BOTH SIDES}\\\\\\\mathsf{\dfrac{2x}{2}=\dfrac{8}{2}}\\\\\\\large\textsf{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\textsf{ because it gives you 1}\\\\\\\large\textsf{KEEP: }\mathsf{\dfrac{8}{2}}\large\textsf{ because it gives you the answer of x}[/tex]
[tex]\mathsf{x = \dfrac{8}{2}}\\\\\\\mathsf{x = 8\div 2}\\\\\\\mathsf{x = \bf 4}\\\\\\\\\\\boxed{\boxed{\huge\text{Therefore, your answer is: \textsf{x = 4}}}}\huge\checkmark[/tex]
[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Find x (Round to the nearest tenth). PLS HURRY
Answer:
x = 28.4°
Step-by-step explanation:
The cos(x) = 15/17 ≈ 0.88
The acos(0.88) = 28.4°
a mean of μ = 78 points with σ = 9. She collects a sample mean of M = 84 for app users. What is the null hypothesis, in both words and symbols?
Answer:
M ≤ μ (=78)
Here μ denotes the means of the population
And, M denotes the sample mean
Step-by-step explanation:
The computation of the null hypothesis, in both words and symbols is given below:
Null Hypothesis(H0) is
M ≤ μ (=78)
This means that the study application does not improve the grades
Also
Alternative hypothesis (H1): M> μ
Here μ denotes the means of the population
And, M denotes the sample mean
In 4 years Craston's age will be the same as Terrins age is now. In 2 years, Terrin will be twice as old as craston. Find their ages now
Answer:2 and 6
Step-by-step explanation:
Given
In 4 years Craston's age will be the same as Terrins age is now
Suppose the present of Craston's and Terrins are [tex]x[/tex] and [tex]y[/tex] respectively
According to the question
[tex]\Rightarrow x+4=y\\\Rightarrow y-x=4\quad \ldots(i)[/tex]
In 2 years Terrin will be twice as old as craston
[tex]\Rightarrow (y+2)=2(x+2)\\\Rightarrow y-2x=4-2\\\Rightarrow y-2x=2\quad \ldots(ii)\\[/tex]
Solving (i) and (ii) we get
[tex]x=2,y=6[/tex]
Thus, the present age of Craston and Terrins are [tex]2[/tex] and [tex]6[/tex]
what is the simplification of 9^8 / 9^7?
Answer:
9
Step-by-step explanation:
We know that a^b / a^c = a^(b-c)
9^8 / 9^7
9^(8-7)
9^1
9
Sausages come in packets of 4. Bread rolls come in packets of 6. Colin wants to buy enough packs of sausages and rolls so that there are an equal number of sausages and rolls. What is the minimum number of sausages and rolls he needs to buy?
Answer:
12
Step-by-step explanation:
because it's true we need to know the full proce
there were 13 original states. there are now 50 . what fraction of the states are the original states
Answer:
13/50
Step-by-step explanation:
#of original states/# of states now
The fraction of the states are original states is [tex]\frac{13}{50}[/tex].
What is fraction?A numerical value that expresses a part of a whole is called a fraction.
According to the given question.
Number of original states before = 13
Number of original states now = 50
Therefore, the fraction of original states
= number of original states before/ number of original states now
=[tex]\frac{13}{50}[/tex]
Hence, the fraction of the states are original states is [tex]\frac{13}{50}[/tex].
Find out more information about fraction here:
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The length of a rectangular field is 6 metres longer than its width. If the area of the field is 72 square metres, What are the width and the length of the field?
Answer:
The length is 12metres, the width is 6metres
Step-by-step explanation:
Suppose the width is x, the length is x+6
The square is 72. The square of rectangular field is equal to product of length and width.
so x(x+6)=72
x^2+6x-72=0
a=1 b=6 c=-72
D= b^2-4ac= 6*6+288= 36+288= 324
sqrtD= 18
x1= (-b-sqrtD)/2a=(-6-18)/2= -12 (it is negative, but width is only positive. So this root doesn't match)
x2=(-b+sqrtD)/2a= (-6+18)/2= 12/2=6 - the width
The length is 6+6=12
Help fast pleaseeeeeeee
Answer:
Multiply 800 by 1.022^7 because 1.022^(n-1)
Step-by-step explanation:
Series and sequences.
PLEASE HELP ME ANSWER THIS QUESTION
Answer:
x = 0
y = -2
Step-by-step explanation:
2304.06 is written in expanded form
4 is unit place. So, 4 *10⁰ = 4 * 1 = 1 {Any integer to the power of 0 is 1}
x = 0
6 is hundredth place = 6 * 1/100 = 6*10⁻²
y= -2
The point slope formula (if possible) to write an equation of the line given the following information…we
The equation in point slope form is y - 6 = 2(x + 3)
This is from the general point slope template of [tex]y - y_1 = m(x - x_1)[/tex]
The m is the slope, which in this case is m = 2. The [tex](x_1,y_1)[/tex] is the point the line goes through. In this case, [tex]x_1 = -3 \text{ and } y_1 = 6[/tex]
If you were to solve that equation in bold for y, then you should get y = 2x+12 which is now in y = mx+b form, aka slope intercept form.
Land surveyors outlined a park as shown. What is the area of the park?
Answer:
70.875
Step-by-step explanation:
Area of park=Area of rectangle+Area of triangle
Area of park=13.5*4.8+(0.5)*(13.5)*0.9=70.875
How much cement is needed for a hole 0.4m wide and 1m long.
Answer:
its 80 meters longs
Step-by-step explanation:
if it is wrong just go look it up
Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. Round to the nearest tenths place.
I need help, please
Answer:
so you multiply the 13 by 12. Then divid 12 by 2 to get 6 as the radius then use a calculator and type in 2(PIE SYMBOL) R. R=radius then whatever number you get cut it in half then subtract it from 13x12.
[tex]3x + 9 = 12[/tex]
Solve for x
Answer:
x=1
Step-by-step explanation:
3x+9 = 12
Subtract 9 from each side
3x+9-9=12-9
3x = 3
Divide by 3
3x/3 = 3/3
x=1
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]x = 1[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Calculating the answer...}}\\\\3x + 9 = 12\\-------------\\\rightarrow 3x + 9 - 9 = 12 - 9\\\\\rightarrow 3x = 3\\\\\rightarrow \frac{3x=3}{3}\\\\\rightarrow \boxed{x=1}[/tex]
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
evaluate 2 tan 45 - tan 60
Answer:
2-\sqrt{3} \\
Step-by-step explanation:
2-\sqrt{3} \\
Picture Shown!
Find the image of the given point
under the given translation.
P(-5,7) T(x, y) = (x + 5, y - 4)
P' = ([?], [?])
Enter the number that belongs in
the green box.
Answer:
0'=(0,3)
Step-by-step explanation:
P'=(-5+5,7-5)=(0,3)
a shipping boox has the dimentsions what is the volume of the box in cubic yards
Answer: 1/32
Step-by-step explanation:
The angle of elevation to the top of the
school is 37° from where you are standing
11.2 m from the wall of the school. Find
the height of the school.
Answer:
8.44 m
Step-by-step explanation:
SohCahToa is a good way to remember that Sin = opposite/hypotenuse, Cosine = adjacent/hypotenuse and Tangent = opposite/adjacent. In this case, we have to use tangent. So tan 37° = x/11.2. Multiply both sides by 11.2 and you get tan 37° × 11.2 = x; The height of the school is x so the height of the school is 8.44 m
A boat travels 12 km upstream and 40 km downstream in 8 hours. It can go 16 km upstream and 32 km downstream in the same time. Find the speed of the boat in still water and the speed of the stream.
the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h
Let's define the variables:
B = speed of the boat in still water.
S = speed of the stream.
When the boat travels downstream, the total speed of the boat will be equal to the sum of the speed of the stream and the speed of the boat in still water:
speed = B + S
When the boat goes downstream, the speed will be:
speed = B - S
Now, also remember the relation:
speed*time = distance.
The given information is:
In 8 hours the boat can:
go 12 km upstream and 40km downstream.
We now need to define another variable, T, as the time that the boat travels upstream.
Then we can write this as:
12km = (B - S)*T
If the boat travels T hours upstream, and travels for a total of 8 hours, then the amount of time that travels downstream is 8h - T, then we can write:
40km = (S + B)*(8h - T)
Similarly, when we have:
"it can go 16 km upstream and 32 km downstream in the same time."
we can define a new variable T', and write:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
Then we have a system of 4 equations:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
40km = (S + B)*(8h - T)
12km = (B - S)*T
And we need to solve this for S and B.
To do it, we need to isolate one of the variables in one of the equations.
Let's isolate T in the last equation:
T = 12km/(B - S)
now we can replace that in the third equation to get:
40km = (S + B)*(8h - 12km/(B - S))
So now we have 3 equations:
16km = (B - S)*T'
32km = (S + B)*(8h - T')
40km = (S + B)*(8h - 12km/(S - B))
Now we need to do the same thing, this time let's isolate T' in the first equation and replace it in the second one:
T' = 16km/(B - S)
Replacing it in the second equation we get:
32km = (S + B)*(8h - T')
32km = (S + B)*(8h - 16km/(B - S))
So now we have two equations:
40km = (S + B)*(8h - 12km/(B - S))
32km = (S + B)*(8h - 16km/(B - S))
Let's simplify these:
40km = 8h*(S + B) - 12km*(S + B)/(B - S)
32km = 8h*(S + B) - 16km*(S+ B)/(B - S)
Now we can multiply both equations by (B - S) to get:
40km*(S - B) = 8h*(S + B)*(B - S) - 12km*(S + B)
32km*(S - B) = 8h*(S + B)*(B - S) - 16km*(S+ B)
Let's keep simplifying this:
40km*(B - S) + 12km*(S + B) = 8h*(S + B)*(B - S)
32km*(B - S) + 16km*(S+ B) = 8h*(S + B)*(B - S)
Now we get:
52km*B - 28km*S = 8h*(S^2 + B^2)
48km*B - 16km*S = 8h*(S^2 + B^2)
Notice that the right side of these equations is the same thing, then we can write:
52km*B - 28km*S = 48km*B - 16km*S
(52km - 48km)*B = (28km - 18km)*S
4km*B = 10km*S
B = (10/4)*S
B = (5/2)*S
Now we can replace this in one of our two equations, let's use the first one:
48km*B - 16km*S = 8h*(S^2 + B^2)
48km*(5/2)*S - 16km*S = 8h*( S^2 + ( (5/2)*S)^2)
Now we can solve this for S
104km*S = 8h*( S^2 + 25/4*S^2)
104km*S = 8h*(29/4*S^2) = 48h*S^2
104km*S = 48h*S^2
dividing at both sides by S we get:
104km = 48h*S
104km/48h = S = 2.167 km/h
And using B = (5/2)*S
We can find the speed of the boat:
B = (5/2)*2.167 km/h = 5.418 km/h
Then:
the speed of the boat is 5.418 km/h and the speed of the stream is 2.167 km/h
If you want to learn more about this topic, you can read:
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The scores of players on a golf team are shown in the table. The team’s combined score was 0. What was Travis’s score?
Answer:here’s the table
Step-by-step explanation:
Celina -3
Jannie 3
Sami 1
Ted 4
Travis ??
Answer:
Step-by-step explanation:
-5
What are the solutions to the quadratic equation (5y + 6)2 = 24?
y = StartFraction negative 6 + 2 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction negative 6 minus 2 StartRoot 6 EndRoot Over 5 EndFraction
y = StartFraction negative 6 + 2 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction 6 minus 2 StartRoot 6 EndRoot Over 5 EndFraction
y = StartFraction negative 4 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction negative 8 StartRoot 6 EndRoot Over 5 EndFraction
y = StartFraction 4 StartRoot 6 EndRoot Over 5 EndFraction and y = StartFraction 8 StartRoot 6 EndRoot Over 5 EndFraction
there are two solutions:
a) y = [tex]\frac{-6+2\sqrt{6} }{5}[/tex]
b) [tex]y = \frac{-6-2\sqrt{6} }{5}[/tex]
Answer:
it's A
Step-by-step explanation:
Trust me I got the question right on the quiz
ate
at?
20) A triangular garden has sides that
1
5
6- 7
feet.
6
What is the perimeter of the garden?
Answer:
Since all the three sides of the triangle are of equal length, we can find the perimeter by multiplying the length of each side by 3. 20 + 20 + 20 = 3 × 20 = 60 cm.
Will Mark Brainlest helppp plss
Answer:
you can ask from it will be easy for you actually I don't know answern
Which is the graph of f(x)=x-1/x2-x-6
Answer:
answer of this question is A
Which expressions are equivalent to -f-5(2f-3)
Answer:
-11f +15
Step-by-step explanation:
-f-5(2f-3)
Distribute
-f -10f +15
Combine like terms
-11f +15
Answer:
B
Step-by-step explanation:
We apply distributive property first on the 2f thingie.
The negative 5 is applied on both the 2f and the negative 3 to get
-10f + 15 since two negatives equals a positive in math.
Then we subtract an "f" from the current data to get your answer since the original question was
-f -5 ( 2f - 3 )
So we get
-11f + 15 or B.
solve it please. Just wanted to check my drawing skill but please solve it
Answer:
Step-by-step explanation:
I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:
[tex]x-9=\sqrt{x}+3[/tex] then subtract 3 from both sides to get
[tex]x-12=\sqrt{x}[/tex] and then square both sides to get
[tex]x^2-24x+144=x[/tex] and get everything on one side to solve for x by factoring:
[tex]x^2-25x+144=0[/tex] and factor that however it is you have learned to factor second-degree polynomials to get that
x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:
[tex]\frac{16-9}{\sqrt{16}+3 }=1[/tex] If 16 is a solution, then this statement will be mathematically true.
[tex]\frac{7}{4+3}=1[/tex] and [tex]\frac{7}{7}=1[/tex] so 16 works. Let's try 9:
[tex]\frac{9-9}{\sqrt{9}+3 }=1[/tex] We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.
x = 16 is the only solution.
Answer:
x = 16
Step-by-step explanation:
[tex]\frac{x-9}{\sqrt{x}+3}=1[/tex]
Cross multiply,
x - 9 = √x + 3
Subtract 3 from both sides
x - 9 - 3 = √x
x - 12 = √x
Square both sides
(x -12)² = (√x)²
x² - 2 * x*12 + 12² = x
x² - 24x + 144 = x
x² - 24x + 144 - x = 0
x² - 25x + 144 = 0
Sum = -25
Product = 144
Factors = -9 , -16 {(-9)+(-16) = -25 & (-)*(-16) = 144}
x² - 25x + 144 = 0
x² - 16x - 9x + (-9)*(-16) = 0
x(x - 16) - 9(x - 16) = 0
(x - 16) (x - 9) = 0
x - 16 = 0 ; x - 9 = 0
x = 16 ; x = 9
x = 9 is an extraneous solution.
When we plug in 9 in the LHS of the equation,
LHS = [tex]\frac{9-9}{\sqrt{9}+3}[/tex]
[tex]= \frac{0}{3+3}[/tex]
= 0 ≠ RHS
So, x = 16 is the only solution
the sum of two numbers A and B is 25. if one fourth of A is 1 more than one third of B, find the number A.
Please help me fill in those couple blanks I’m really struggling
y = x^2 - 8x + 3
y - 3 = x^2 - 8x + 3 - 3
y - 3 = x^2 - 8x + ___
c = (8/2)^2 = 16
y - 3 + 16 = x^2 - 8x + 16
y + 13 = (x - 4)^2
y + 13 - 13 = (x - 4)^2 - 13
y = (x - 4)^2 - 13
Vertex: (4, -13)
Hope this helps!
Can someone please answer B (PICTURE)
Answer:
The question is asking for the perimeter. There are three ways to answer this depending on the assumptions though so I'll let you choose.
Assumptions are basically the different scenarios
1st scenario being the trim covers the carpet and the tile, they'd need 48m of trim (12+12+4+8+8+4)
2nd scenario in which the trim covers the carpet but not the tiled area, they'd need 44m of trim (12+12+4+8)
3rd scenario where the trim only covers the the tiled area, 4m of trim
(just 4 since the tile only touches 4m of the wall)
Hope this helps!
Step-by-step explanation:
trim is just the perimeter since it covers the base of the wall