A mother who is 35 years old has two sons, one of whom is twice as old as the other. In 3 years the sum of all their ages will be 59 years. How old are the boys at present ?

6x^2+4x+8

6x7^2+4x+8

blah  blah blah

ANSWER

330

pls say if im right

Answer:

Step-by-step explanation:

[tex]6x^2 +4x +8\\x =7\\\\6(7)^2 +4(7) +8\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:exponents}\:\left(7\right)^2\::\quad 49\\\\=6\cdot \:49+4\left(7\right)+8\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:6\cdot \:49\::\quad 294\\\\=294+4\left(7\right)+8\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:4\left(7\right)\::\quad 28\\\\=294+28+8\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:294+28+8\:\\:\quad 330[/tex]

In decimal form, this is equivalent to 1.25

=============================================

Work Shown:

The given equation 2x^2-10x+13 = 0 matches the form ax^2+bx+c = 0

We see that a = 2, b = -10, c = 13. Plug those values into the quadratic formula to solve for x.

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-10)\pm\sqrt{(-10)^2-4(2)(13)}}{2(2)}\\\\x = \frac{10\pm\sqrt{-4}}{4}\\\\x = \frac{10\pm2i}{4}\\\\x = \frac{2(5\pm i)}{2*2}\\\\x = \frac{5\pm i}{2}\\\\x = \frac{5}{2} \pm \frac{1}{2}i\\\\x = \frac{5}{2} + \frac{1}{2}i \ \text{ or } \ x = \frac{5}{2} - \frac{1}{2}i\\\\[/tex]

The two solutions are in the form [tex]a \pm bi[/tex] where a = 5/2 and b = 1/2

Therefore a*b = (5/2)*(1/2) = 5/4 = 1.25

Answer:

2^3×3^2=6^5​  equation is wrong because

2×2×2×3×3=72

6^5=6×6×6×6×6=36×36×6=7776

the two numbers are not equal

Mate, I think your question is wrong ! ;(

[tex]Corrected \\ Question...\\[/tex] (2^3)^2*(3^2)^3=6^5

The polynomial remainder theorem states that the remainder of the division of a polynomial [tex]P(x)[/tex] by [tex]x-a[/tex] is equal to [tex]P(a)[/tex].

Therefore

[tex]P(-2)=4\\2\cdot(-2)^3 - 4\cdot(-2)^2 + k\cdot(-2) + 10=4\\-16-16-2k=-6\\-2k=26\\k=-13[/tex]

Answer:

Step-by-step explanation:

$66,200  - the median selling price of a home in 1985

and the price increased by 30%:

66,200•30% = 66,200•0.3 = 19,860

66,200 + 19,860 = 86,060

$86,060 - the median selling price of a home in 1990

and the price increased by 15%

86,060•15% = 86,060•0.15 = 12,909

86,060 + 12,909 = 98,969

$98,969  - the median house price in Atlanta in 2005

Answer:

£0.79 add £1.69 add £1.00 equals £ 3. 4 8

Take away £4.00 and change is 52p

Step-by-step explanation:

An equation is formed of two equal expressions. The change that Chris would receive is $0.52.

An equation is formed when two equal expressions are equated together with the help of an equal sign '='. while an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

Given that Chris had $4 in cash. Also, he purchased coffee for $0.79, a bag of chips for $1.69 and a lottery ticket for $1.00. Therefore, the change he would receive is,

Change = Cash Chris has - Cost of coffee - Cost of chips - Cost of lottery

              = $4 - $0.79 - $1.69 - $1.00

              = $0.52

Hence, the change that Chris would receive is $0.52.

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Answer:

x1 = 0.64575

x2 = -4.64574

Step-by-step explanation:

Step 1: We want to rearrange the equation so all the variables are on one side

0 = -x² - 4x + 3

Step 2: We take out -1 in the first 2 terms so a = 1

0 = -(x² + 4x) + 3

Step 3: Force a square, take the 'b' value and divide it by 2 and square the result. Add it and subtract it from the inside of the brackets

b = 4

4/2 = 2

2² = 4

0 = -(x² + 4x + 4 - 4) + 3

Step 4: Move the -4 out remembering to apply the -

= -(x² + 4x + 4) + 4 + 3

Step 5: We notice is inside the brackets is a perfect square

0 = -(x + 2)² + 7

Therefore the vertex form of the equation is

y = -(x + 2)² + 7

Step 6: We want to solve the equation (find the x intercepts) so we set y to 0 and solve for x

0 = -(x + 2)² + 7

-7 = -(x + 2)²

7 = (x + 2)²

[tex] \sqrt{7 } = x + 2 [/tex]

[tex]x = \sqrt{7} - 2[/tex]

1st Solution:

x = +2.64575 - 2

x = 0.64575

2nd Solution:

x = -2.64575 - 2

x = -4.64574

Answer:

19 x 97 = 1843

Answer:

10

Step-by-step explanation:

m + 2p

2 + 2(4)

= 2 + 8

= 10

Answer:

10

Step-by-step explanation:

m +2p;

let m = 2, and p = 4​

2+2*4

2+8

10

Answer:

81

Step-by-step explanation:

First find the amount decrease

90 * 10 %

90 * .10

9

90 decreased by 9

90 -9

81

Answer:

81

Step-by-step explanation:

Turn into decimal.

10% = 0.1

Multiply

90 * 0.1 = 9

Subtract

90 - 9 = 81

Best of Luck!

Answer:

11/12

Step-by-step explanation:

The product of One-fourth times three and two-thirds will be 1 / 2.

Multiplication is the process of determining the product of two or more numbers in mathematics. A product, or an expression that specifies factors to be multiplied, is what happens when you multiply two numbers in mathematics.

Given that, the numbers are one-fourth times three and two-thirds. The product of the numbers will be calculated as,

Product =  ( 1 / 4 ) x ( 3 ) x ( 2 / 3 )

Product = 6 / 12

Product = 1 / 2

Therefore, the product of One-fourth times three and two-thirds will be 1 / 2.

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Answer:

42.5 units²

Explenation:

The area of the square on the left is 5×5=25.

At the top you do 12-5=7 to find the length of the tringle.

Than it is 7×5=35 than this divided by two, so 17.5.

You add both areas 25+17.5=42.5

Answer:

42.5 square units

Step-by-step explanation:

Separate shape into a square and a triangle

Calculate the area of the square (5*5=25 square units)

Calculate the are of the triangle (7*5/2=35/2= 17.5 square units)

Add together (17.5+25=42.5 square units)

Answer:

Step-by-step explanation:

If the password for a certain safe is indicated by multiplying (x^2-16)/(x-1) with 1 / ((x ^ 2 + 6x + 8) / (x ^ 2 + 2x-3))

Simplify the expression in its lowest term first

[tex]= \dfrac{x^2-16}{x-1} * \dfrac{1}{\dfrac{x ^ 2 + 6x + 8}{x ^ 2 + 2x-3} } \\\\= \dfrac{x^2-16}{x-1} * }{\dfrac{x ^ 2 + 2x - 3}{x ^ 2 + 6x + 8} }\\\\= \dfrac{ (x+4)(x-4)}{x-1} * \dfrac{(x+3)(x-1)}{(x+4)(x+2)}\\\\= \dfrac{x-4}{1} * \dfrac{x+3}{x+2}\\[/tex]

If the value of x = 9, to get the numeric value of the password, we will substitute x = 9 into the resulting function as shown;

[tex]= \dfrac{x-4}{1} * \dfrac{x+3}{x+2}\\\\= \dfrac{9-4}{1} * \dfrac{9+3}{9+2}\\\\= \frac{5}{1} * \frac{12}{11}\\\\= \frac{60}{11}\\ \\= 5.455[/tex]

Hence the numeric value of the password is 5.455

Answer:

I will assume that ABCD is a parallelogram.

1. In a parallelogram, opposite sides are congruent so 3x = 18 which means x = 6.

2. The diagonals of a parallelogram bisect each other so BE is half of BD, therefore, BD = 7.5.

3. Consecutive angles of a parallelogram are supplementary so m∠ADC = 180° - 135° = 45°.

4. Consecutive angles of parallelograms are supplementary so 2x + 10 + 135 = 180 → 2x + 145 = 180 → 2x = 35 → x = 17.5°.

5.  Again, the diagonals bisect each other so -6 + 8v = 9v - 10 → v = 4.

6. DA || BC so ∠DAC and ∠ACB are (congruent) alternate interior angles, therefore, m∠DAC = 37°.

7. The area of a parallelogram is base * height; we know base = 18 and height = 21 u so area = 378 u.

Answer:

52°

Step-by-step explanation:

360 - 33 - 165 - 20 - 90 = x

x = 52

Answer:

Step-by-step explanation:

Let's find the size of angle x

The angle in a complete turn add up to 360°

[tex] \mathsf{x + 20 + 165 + 33 + 90 = 360}[/tex]

Add the numbers

[tex] \mathsf{x + 308 = 360}[/tex]

Move constant to R.H.S and change it's sign

[tex] \mathsf{x = 360 - 308}[/tex]

Calculate the difference

[tex] \mathsf{x = 52}[/tex] °

Hope I helped!

Best regards!

Answer:

Below

Step-by-step explanation:

● 11 + 4(x+ 2y + 4)

● 11 + 4x + 8y + 16

● 27 + 4x + 8y

Answer:

m = -9

Step-by-step explanation:

2m-10=44+8m

Subtract 2m from each side

2m-2m-10=44+8m-2m

-10 = 44+6m

Subtract 44 from each side

-10-44 = 44-44+6m

-54 = 6m

Divide by 6

-54/6 = 6m/6

-9 = m

Answer:

solve by solving the salvation for equation don't be a slave get educated from what's gave

Answer:

[tex]\boxed{\sf QS = 98}[/tex]

Step-by-step explanation:

QP = PS   [Diagonals are bisected(Divided into two equal parts) by the other diagonal of parallelogram]

So,

3x - 11 = 2x + 9

3x - 2x = 9 + 11

x = 20

Now,

QS = QP + PS

QS = 3x-11+2x+9

QS = 3(20)-11+2(20)+9

QS = 60 - 11 + 40 + 9

QS = 49 + 49

QS = 98

Answer:  QS=98

Step-by-step explanation: diagonals are bisected by the other diagonal parallelogram

Answer:

2

Step-by-step explanation:

Remember, a radical is the same thing as an exponent, but as a fraction. Therefore, instead of taking the 12th of the root, you can put [tex]8^4[/tex] to the 12th power like this: [tex](8^4)^{\frac{1}{12} }[/tex]

The two exponents can multiply together, so now it'll be [tex]8^{\frac{4}{12} }[/tex] which is [tex]8^{\frac{1}{3} }[/tex] when reduced

[tex]8^{\frac{1}{3} }[/tex] is the same thing as [tex]\sqrt[3]{8}[/tex]

Now, think about which number, when multiplied by itself 3 times is equal to 8... that number is 2--your answer

Answer:

2

Step-by-step explanation:

make it simple.. use a scientific calculator.

= ¹²√8⁴

= ¹²√4096

= 2

Answer:

196 degrees

Step-by-step explanation:

360-164=196 degrees

the arch CDF=2*82=164

so the arch CGF =360-164=196 degrees

square ?

although this statement doesn't make any sense.

Answer:

Square!

Step-by-step explanation:

A rectangle is a parallelogram with all its interior angles being 90 degrees. A rhombus is a parallelogram with all its sides equal. This means that for a rectangle to be a rhombus, its sides must be equal. When this is satisfied, we have a square.

Hope helped.. If yes mark me BRAINLIEST

TYSM!

Answer:

  40

Step-by-step explanation:

Angles ABO, BAO, and AOB are the angles of isosceles triangle AOB. The angles at A and B are equal, so we have ...

  AOB +2ABO = 180° . . . . . sum of angles in the triangle

  100° +2ABO = 180° . . . . . . use the given value

  50° +ABO = 90°  . . . . . . . . divide by 2; next, subtract 50°

  ∠ABO = 40°

Answer:

She spend[tex]\frac{7}{24}[/tex] more on erasers than rulers.

Step-by-step explanation:

We are given that Isabelle bought some stationery.

Fraction of pencil = [tex]\frac{1}{3}[/tex]

Remaining stationary =[tex]1-\frac{1}{3}=\frac{2}{3}[/tex]

5/8 of the remainder were erasers

So, part of eraser in stationary=[tex]\frac{5}{8} \times \frac{2}{3}=\frac{5}{12}[/tex]

Remaining stationary(rulers)=[tex]\frac{2}{3}-\frac{5}{12}=\frac{1}{4}[/tex]

Cost of ruler = $0.50

Cost of [tex]\frac{1}{4}[/tex]rulers =[tex]0.50 \times \frac{1}{4}=\frac{1}{8}[/tex]

Cost of eraser=$1

Cost of [tex]\frac{5}{12}[/tex] eraser=[tex]\frac{5}{12}[/tex]

Difference in cost of eraser and rulers =[tex]\frac{5}{12}-\frac{1}{8}=\frac{7}{24}[/tex]

Hence She spend[tex]\frac{7}{24}[/tex] more on erasers than rulers.

Answer:

see attachement

Step-by-step explanation:

Answer:

x=13, 16(x-1)

Step-by-step explanation:

For 38, you have to first divide both sides by 2.

This becomes, x-6=7

Add 6 to both sides

x=13.

For 40. You can can distribute the 8.

This makes it 16x-16.

With this you can than, factor out the 16.

16(x-1).

Answer:

Step-by-step explanation:

38.

[tex]2(x - 6) = 14\\\\\mathrm{Divide\:both\:sides\:by\:}2\\\\\frac{2\left(x-6\right)}{2}=\frac{14}{2}\\\mathrm{Simplify}\\x-6=7\\\mathrm{Add\:}6\mathrm{\:to\:both\:sides}\\\\x-6+6=7+6\\\\x=13[/tex]

40.

[tex]8(2x - 2)\\\mathrm{Apply\:the\:distributive\:law}:\\\quad \:a\left(b-c\right)=ab-ac\\\\a=8,\:b=2x,\:c=2\\\\=8\times \:2x-8\times \:2\\\\=16x-16[/tex]

Answer:

Step-by-step explanation:

[tex]6\sqrt{x-2}+4<28\\6\sqrt{x-2}<28-4\\\sqrt{x-2}<\frac{24}{6}\\\sqrt{x-2}<4\\\\x-2 <16\\x<16-2\\x<14x-2 \geq 0\\x\geq 2\\so~2 \leq x < 14[/tex]

Answer:

[tex]b = 10[/tex]

Step-by-step explanation:

We can use the cross products property and solve for b.

[tex]\frac{5}{6} = \frac{b}{12}\\\\\\b=(12\cdot5)\div6\\b=60\div6\\b=10[/tex]

Hope this helped!

Answer:

The answer is b=10

Step-by-step explanation:

All you need to do is think 12/6 is what, the answer would be 2, then you would multiply the numerator by 2, which would be 5*2 which is 10.

Thank you, Hope this helps you.

Answer:

Hey There!! The answer to this is: 32+10x-(21+12x) We are given that:

Amount MIkayla has in here piggy bank initially = $32

Money earned by Mikayla per week = $10

Money earned by Mikayla in x weeks = 10x

Total money MIkayla has after x weeks = 32+10x

Amount Jessica has in here piggy bank initially = $21

Money earned by Jessica per week = $12

Money earned by Jessica in x weeks = 12x

Total money Jessica has after x weeks = 21+12x

Comparing,

In order to compare, we subtract the money earned by Jessica from that earned by MIkalya,

The final expression would be:

32+10x-(21+12x

Hope It Helped!~ ♡

ItsNobody~ ☆

Answer:

1

4

5

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

Square root of 100 is 10

Answer:

10

Step-by-step explanation:

The square root of 100 is written as 2√100=√100=±10.

So it is 10.  Also, 10 times 10 equals 100, so it checks out.

A square root is just two of the same numbers added together to equal a specific number.

Answer:

The triangle is a scalene triangle that has all three sides having different lengths

Step-by-step explanation:

The given vertices (and their coordinates) of the triangle are;

A(-1, 3)

B(-3, 5)

C(3, 2)

The equation for finding the lengths of a segment, l, given the coordinates, x, y is presented as follows;

[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]

For segment AB, when, (x₁, y₁) = A(-1, 3) and (x₂, y₂) = B(-3, 5),  we have;

[tex]l = \sqrt{\left (5-3 \right )^{2}+\left (-3-(-1) \right )^{2}} = 2\cdot\sqrt{2}[/tex]

Length of segment AB = 2·√2

For segment AC, when, (x₁, y₁) = A(-1, 3) and (x₂, y₂) = C(3, 2),  we have;

[tex]l = \sqrt{\left (2-3 \right )^{2}+\left (3-(-1) \right )^{2}} = \sqrt{17}[/tex]

Length of segment AC = √17

For segment BC, when, (x₁, y₁) = B(-3, 5) and (x₂, y₂) = C(3, 2),  we have;

[tex]l = \sqrt{\left (2-5 \right )^{2}+\left (3-(-3) \right )^{2}} = 3 \cdot \sqrt{5}[/tex]

Length of segment AC = 3·√5

The triangle is a scalene triangle that has all three sides having different lengths.