A line passes through the points (0,0) and (4,4). What is the equation of the line?

Answer:

18225 cm²

Step-by-step explanation:

Divide 540 by 4 to get the length of all sides

540/4 = 135

Square 135 to get the max possible size

135² = 18225

18225 cm²  is the greatest possible area for the quilt.

The measurement that expresses the size of a region on a plane or curved surface is called area. Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.

Given

Divide 540 by 4 to obtain the length of all sides

540/4 = 135

Square 135 to acquire the max possible size

135² = 18225

18225 cm²  is the greatest possible area for the quilt.        

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Answer:

x = -17

Step-by-step explanation:

7(2x + 3) = 12x - 13

Distribute

7*2x +7*3 = 12x-13

14x +21 = 12x-13

Subtract 12x from each side

14x-12x+21 = 12x-12x-13

2x+21 = -13

Subtract 21 from each side

2x+21-21 = -13-21

2x = -34

Divide by 2

2x/2 = -34/2

x = -17

Answer:

people who ordered a cold drink=

[tex]8+12+5=25[/tex]

people who ordered a large cold drink= 5

[tex]probability= \frac{5}{25}[/tex] [tex]=\frac{1}{5}[/tex]

[tex]=\frac{1}{5} \times100=20~\%[/tex]

[tex]Answer: 20\%[/tex]

-----------------------

Hope it helps...

Have a great day!!

The probability that the customer ordered a large given that he or she ordered a cold drink is 5%.

Probability is simply the possibility of getting an event. Or in other words, we are predicting the chance of getting an event.

The value of probability will be always in the range from 0 to 1.

Given the order of the first 100 customers in a coffee shop.

Number of customers who ordered a large which is also a cold drink = 5

Total number of customers = 100

Probability = Number of desired outcomes / Total number of outcomes

Substituting,

Probability = 5 / 100 = 0.05 = 5%

Hence the required percent is 5%.

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Answer:

[tex]y = -0.25x -1.5[/tex]

Step-by-step explanation:

Given

[tex](x,y) = \{(-12,1.5)(-1,-1.25),(5,-2.75),(8,-3.5)\}[/tex]

Required

The function rule (in slope intercept)

First, we calculate the slope (m) using:

[tex]m = \frac{y_2 -y_1}{x_2 - x_1}[/tex]

This gives:

[tex]m = \frac{-1.25 -1.5}{-1 - -12}[/tex]

[tex]m = \frac{-2.75}{11}[/tex]

[tex]m = -\frac{2.75}{11}[/tex]

[tex]m = -0.25[/tex]

The equation is then calculated using:

[tex]y = m(x - x_1) + y_1[/tex]

This gives:

[tex]y = -0.25(x - -12) + 1.5[/tex]

[tex]y = -0.25(x +12) + 1.5[/tex]

Open bracket

[tex]y = -0.25x -3 + 1.5[/tex]

[tex]y = -0.25x -1.5[/tex]

Answer:

2.4

Step-by-step explanation:

Took the assignment

Answer:

2.4 seconds is the correct answer.

Step-by-step explanation:

Just completed it.

Given set:- x - 7 > - 2

Solving It:-

x - 7 > - 2

x > -2 + 7 [Here '7' is greater than '-2' So Sign Changes To Positive]

x > 5

So Correct Solution Set Will Be

Option C= {x | x R, x > 5}

Given:

The tens digit of a two digit number is 5 greater the units digit.

If you subtract double the reversed number from it, the result is a fourth of the original number.

To find:

The original number.

Solution:

Let n be the two digit number and x be the unit digit. Then tens digit is (x+5) and the original number is:

[tex]n=(x+5)\times 10+x\times 1[/tex]

[tex]n=10x+50+x[/tex]

[tex]n=11x+50[/tex]

Reversed number is:

[tex]x\times 10+(x+5)\times 1=10x+x+5[/tex]

[tex]x\times 10+(x+5)\times 1=11x+5[/tex]

If you subtract double the reversed number from it, the result is a fourth of the original number.

[tex]11x+50-2(11x+5)=\dfrac{1}{4}(11x+50)[/tex]

[tex]11x+50-22x-10=\dfrac{1}{4}(11x+50)[/tex]

[tex]40-11x=\dfrac{1}{4}(11x+50)[/tex]

Multiply both sides by 4.

[tex]160-44x=11x+50[/tex]

[tex]160-50=11x+44x[/tex]

[tex]110=55x[/tex]

Divide both sides by 55.

[tex]\dfrac{110}{55}=x[/tex]

[tex]2=x[/tex]

The unit digit is 2. So, the tens digit is [tex]2+5=7[/tex].

Therefore, the original number is 72.

Answer:

[tex]\frac{16}{45}x-\frac{11}{12}[/tex]

Step-by-step explanation:

We are given that an expression

[tex]\frac{2}{5}(1/3x-15/8)-\frac{1}{3}(1/2-2/3x)[/tex]

We have to find the equivalent expression.

[tex]\frac{2}{5}(\frac{1}{3}x-\frac{15}{8})-\frac{1}{3}(\frac{1}{2}-\frac{2}{3}x)[/tex]

[tex]\frac{2}{5}\times \frac{1}{3}x-\frac{2}{5}\times \frac{15}{8}-\frac{1}{3}\times \frac{1}{2}-\frac{1}{3}\times (-\frac{2}{3}x)[/tex]

Using the the property

[tex]a\cdot (c-b)=a\cdot c-a\cdot b[/tex]

[tex]\frac{2}{5}(1/3x-15/8)-\frac{1}{3}(1/2-2/3x)[/tex]

[tex]=\frac{2}{15}x-\frac{3}{4}-\frac{1}{6}+\frac{2}{9}x[/tex]

[tex]=\frac{6x+10x}{45}+\frac{-9-2}{12}[/tex]

[tex]=\frac{16}{45}x-\frac{11}{12}[/tex]

[tex]\frac{2}{5}(1/3x-15/8)-\frac{1}{3}(1/2-2/3x)=\frac{16}{45}x-\frac{11}{12}[/tex]

Answer: Becomes four times

Step-by-step explanation:

Given

Speed is doubled for a moving object

Suppose initial speed is u

Increased speed is 2u

Kinetic Energy is given by

[tex]\Rightarrow K=0.5mu^2[/tex]

When speed is doubled

[tex]\Rightarrow K'=0.5m(2u)^2\\\Rightarrow K'=(0.5mu^2)\times 4\\\Rightarrow K'=4K[/tex]

Kinetic energy becomes four times

Answer:

hope it helps plz mark me brainliest!

Step-by-step explanation:

4x² - 3, x less than/equal to 0

Step-by-step explanation:

y = (-1/2)[(x+3)^½]

(x+3)^½ = -2y

Square both sides,

(x+3) = (-2y)²

x+3 = 4y²

x = 4y²-3

Interswitch x and y

Inverse is 4x²-3

Domain of inverse is the range of f.

The range of f is less than/equal to 0

Because at x = -3, f(x) = 0

For x > -3, f(x) is negative

Domain of inverse is x less than/equal to 0

Answer:

They sold 162 vanilla cones.

Step-by-step explanation:

429-105=324

324/2=162

162+105=267 (chocolate)

267(chocolate)+162(vanilla)=429(total)

Answer:

[tex]y = -4x^2 + 8x + 192[/tex]

Step-by-step explanation:

Hi there!

Standard form: [tex]y=ax^2+bx+c[/tex]

[tex]y = -4(x + 6)(x - 8)[/tex]

Use the distributive property to multiply (x+6) and (x-8)

[tex]y = -4(x(x - 8) + 6(x - 8))\\y = -4(x^2 - 8x + 6x - 48)\\y = -4(x^2 - 2x - 48)[/tex]

Multiply the parentheses by -4

[tex]y = -4x^2 + 8x + 192[/tex]

I hope this helps!

Step-by-step explanation:

Increase in dollars

19/100 x 472.000 = $89,670

and the current value house is $472,000 + $89,670 = $561,680

Answer:

it should be 3

Step-by-step explanation:

I hope this help

Answer:

A.15/8

Step-by-step explanation:

the answer is 15/8

Answer:

D.

[tex]{ \tt{ \cos( \theta) = \frac{adjacent}{hypotenuse} }} \\ \\ { \tt{ \cos( \theta) = \frac{8}{ \sqrt{ {15}^{2} + {8}^{2} } } }} \\ \\ { \tt{ \cos( \theta) = \frac{8}{ \sqrt{289} } }} \\ \\ { \tt{ \cos( \theta) = \frac{8}{17} }}[/tex]

Answer:

The right solution is "0.5545".

Step-by-step explanation:

According to the question,

The probability of having 6 or 7 males will be:

= [tex]P(6 \ males)+ P(7 \ males)[/tex]

= [tex]\frac{15_C_6\times 13_C_6}{28_C_{12}} + \frac{15_C_7\times 13_C_5}{28_C_{12}}[/tex]

= [tex]\frac{5005\times 1716+6435\times 1287}{30421755}[/tex]

= [tex]\frac{16870425}{30421755}[/tex]

= [tex]0.5545[/tex]

Answer:

x=136

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Given the three integrals, we want to determine which integrals necessarily have the same value.

We can let the first integral be itself.

For the second integral, we can perform a u-substitution. Let u = x + a. Then:

[tex]\displaystyle du = dx[/tex]

Changing our limits of integration:

[tex]u_1=(0)+a=a \text{ and } u_2 = (b+a)+a = b+2a[/tex]

Thus, the second integral becomes:

[tex]\displaystyle \int_{0}^{b+a}f(x+a)\, dx = \int_a^{b+2a} f(u)\, du[/tex]

For the third integral, we can also perform a u-substitution. Let u = x + c. Then:

[tex]\displaystyle du = dx[/tex]

And changing our limits of integration:

[tex]\displaystyle u_1=(a-c)+c=a \text{ and } u_2=(b-c)+c=b[/tex]

Thus, our third integral becomes:

[tex]\displaystyle \int_{a-c}^{b-c}f(x+c)\, dx = \int_{a}^{b} f(u)\, du[/tex]

Since the only difference between f(x) and f(u) is the variable and both the first and third integral have the same limits of integration, our answer is B.

Answer:

total balls = 18 .... 3/x = 1/6

blue = 10 ... 18-(5+3) = 10

p of green = 5/18 = .277

Step-by-step explanation:

Answer:

730.88

Step-by-step explanation:

Area of the entire circle = pi * r^2

r = 16

Area = 3.14 * 16^2

Area = 803.84

1/4 of the circle contains the shaded area. It's area = 1/4 * 803.84

Area of 1/4 circle =

200.96

the area of the triangle

Area = 1/2 AG * G?

AG and G? are equal

Area = 1/2 * 16^2

Area = 128

Area of 1/4 circle - area of the triangle = area of the shaded portion

shaded portion = 200.95 - 128

Shaded Portion = 72.96

So the area of the unshaded part

unshaded = 803.84 - 72.96

Unshaded = 730.88

Answer: SSS Similarity Theorem (Choice A)

This is because we have three pairs of corresponding sides that form the same ratio, as shown by the given equation PQ/ST = QR/TU = RS/US.

That equation is basically the shorthand version of PQ/ST = QR/TU and QR/TU = RS/US combined together as one.

The question is incomplete. The complete question is :

A school in Delhi has its own flag, which is rectangular and divided into 4 rows and 6 columns. The word ‘SCHOOL’ is inscribed in the first row, ‘FLAG’ in the fourth row, and a  purple colored rhombus is in the middle, as shown in the given figure.

Based on this picture of the school flag, answer the following questions:  

(a) What fraction of the flag has the purple rhombus?

Solution :

From the figure, the total number of squares in the flag of 4 rows and 6 columns are : 4 x 6 = 24 blocks

The purple colored rhombus is made on the half of the 4 blocks.

i.e. [tex]$\frac{1}{2} \times 4 = 2\ \text{blocks}$[/tex]

Therefore, the fraction of the flag that has the purple rhombus is :

[tex]$=\frac{2}{24}$[/tex]

[tex]$=\frac{1}{12}$[/tex]

Answer:

Step-by-step explanation:

There are 2 very distinct and important things that we need to know before completing the problem. First is that we are given that the cos of an angle is 1/3 (adjacent/hypotenuse) and it is in the first quadrant. We also need to know that the identity for sin2θ = 2sinθcosθ.

We already know cos θ = 1/3, so we need now find the sin θ. The sin ratio is the side opposite the angle over the hypotenuse, and the side we are missing is the side opposite the angle (we do not need to know the angle; it's irrelevant). Set up a right triangle in the first quadrant and label the base with a 1 (because the base is the side adjacent to the angle), and the hypotenuse with a 3. Find the third side using Pythagorean's Theorem:

[tex]3^2=1^2+y^2[/tex] which simplifies to

[tex]9=1+y^2[/tex] and

[tex]y^2=8[/tex] so

[tex]y=\sqrt{8}=2\sqrt{2}[/tex] so that's the missing side. Now we can easily determine that

[tex]sin\theta=\frac{2\sqrt{2} }{3}[/tex]

Now we have everything we need to fill in the identity for sin2θ:

[tex]2sin\theta cos\theta=2(\frac{2\sqrt{2} }{3})(\frac{1}{3})[/tex] and multiply all of that together to get

[tex]2sin\theta cos\theta=\frac{4\sqrt{2} }{9}[/tex]

Answer:

[tex] \rm\displaystyle 4\cos( \theta) \cos \left( {2\theta} \right) \cos \left( {4 \theta } \right) [/tex]

Step-by-step explanation:

I assume the question want us to rewrite cosθ+cos3θ+cos5θ+cos7θ by using Sum-to-Product Formula and note that it's not an equation therefore θ can never be specified

===========================

so we want to rewrite cosθ+cos3θ+cos5θ+cos7θ by using Sum-to-Product Formula the good news is that the number of the function of the given expression is even so there's a way to do so, rewrite the expression in parentheses notation:

[tex] \rm\displaystyle \left( \cos( \theta) + \cos(3 \theta) \right) + \left(\cos(5 \theta) + \cos(7 \theta) \right)[/tex]

recall that,Sum-to-Product Formula of cos function:

[tex] \rm \boxed{\displaystyle \cos( \alpha ) + \cos( \beta ) = 2 \cos \left( \frac{ \alpha + \beta }{2} \right) \cos \left( \frac{ \alpha - \beta }{2} \right) }[/tex]

notice that we have two pair of function with which we can apply the formula thus do so,

[tex] \rm\displaystyle \left( 2\cos \left( \frac{ \theta + 3 \theta}{2} \right)\cos \left( \frac{ \theta - 3 \theta}{2} \right) \right) + \left(2\cos \left( \frac{5 \theta + 7 \theta}{2} \right) \cos \left( \frac{5 \theta - 7 \theta}{2} \right) \right)[/tex]

simplify addition:

[tex] \rm\displaystyle \left( 2\cos \left( \frac{4 \theta}{2} \right)\cos \left( \frac{ - 2\theta }{2} \right) \right) + \left(2\cos \left( \frac{12 \theta }{2} \right) \cos \left( \frac{ - 2 \theta}{2} \right) \right)[/tex]

simplify division:

[tex] \rm\displaystyle \left( 2\cos \left( {2 \theta} \right)\cos \left( { - \theta } \right) \right) + \left(2\cos \left( {6 \theta } \right) \cos \left( { - \theta} \right) \right)[/tex]

By Opposite Angle Identities we acquire:

[tex] \rm\displaystyle \left( 2\cos \left( {2 \theta} \right)\cos \left( { \theta } \right) \right) + \left(2\cos \left( {6 \theta } \right) \cos \left( { \theta} \right) \right)[/tex]

factor out 2cosθ:

[tex] \rm\displaystyle 2 \cos( \theta) (\cos \left( {2 \theta} \right) + \cos \left( {6 \theta } \right) )[/tex]

once again apply Sum-to-Product Formula which yields:

[tex] \rm\displaystyle 2 \cos( \theta) (2\cos \left( {4\theta} \right) \cos \left( {2 \theta } \right) )[/tex]

distribute:

[tex] \rm\displaystyle 4\cos( \theta) \cos \left( {2\theta} \right) \cos \left( {4 \theta } \right) [/tex]

and we're done!

Answer:

y=4x-7

Step-by-step explanation:

here,

the equation of straight line in slope intercept form is;

y=mx+c

( m= slope

c= y-intercept )

soo..

the question has asked for slope 4 i.e. m=4

and y- intercept -7 i.e. c= -7

now.

the required equation is

y= 4x-7

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Answer:

D. linear; y = - 1/2x + 2

Step-by-step explanation:

As the values of x increase by 1, the values of y decrease by 0.5. This means that we have a negative linear relationship of 1/2. In other words, the slope is -1/2. Our y-intercept is 2 since when x = 0, y = 2. So, D is the correct choice.

Answer:

FG ≈ FL (Both are hypotenuse, supposed to be equal in order to the congruency to become HL)

Answered by GAUTHMATH

Answer:

B

Step-by-step explanation:

At - infinity, the function will tend to 0 and at +infinity, the function will tend to +infinity. Those are the two extremas of the function and extremas define the range. Range is all positive real number