A hockey team is convinced that the coin used to determine the order of play is weighted. The team captain steals this special coin and flips it 14 times to evaluate the hypothesis that the coin is weighted, and it shows up heads 12 times. Test this hypothesis (use alpha=.05).

1. What is the appropriate test?

2. State the null hypothesis:

3. State the alternative hypothesis:

4. Find the critical value:

5. Calculate the obtained statistic:

6. Make a decision:

7. What does your decision mean

Answers

Answer 1

Answer:

Since x= 12 (0.006461) does not fall in the critical region so we accept our null hypothesis and conclude that the coin is fair.

Step-by-step explanation:

Let p be the probability of heads in a single toss of the coin. Then our null hypothesis that the coin is fair will be formulated as

H0 :p 0.5   against   Ha: p ≠ 0.5

The significance level is approximately 0.05

The test statistic to be used is number of heads x.

Critical Region: First we compute the probabilities associated with X the number of heads using the binomial distribution

Heads (x)        Probability (X=x)                        Cumulative     Decumulative

0                        1/16384 (1)             0.000061     0.000061

1                         1/16384  (14)         0.00085             0.000911

2                       1/16384 (91)           0.00555             0.006461

3                       1/16384(364)         0.02222

4                       1/16384(1001)         0.0611

5                       1/16384(2002)       0.122188

6                        1/16384(3003)      0.1833

7                         1/16384(3432)      0.2095

8                        1/16384(3003)       0.1833

9                        1/16384(2002)       0.122188

10                       1/16384(1001)        0.0611

11                       1/16384(364)        0.02222

12                      1/16384(91)            0.00555                             0.006461

13                     1/16384(14)              0.00085                           0.000911

14                       1/16384(1)            0.000061                            0.000061

We use the cumulative and decumulative column as the critical region is composed of two portions of area ( probability) one in each tail of the distribution. If  alpha = 0.05 then alpha by 2 - 0.025 ( area in each tail).

We observe that P (X≤2) =   0.006461 > 0.025

and

P ( X≥12 ) = 0.006461 > 0.025

Therefore true significance level is

∝=  P (X≤0)+P ( X≥14 ) = 0.000061+0.000061= 0.000122

Hence critical region is (X≤0) and ( X≥14)

Computation x= 12

Since x= 12 (0.006461) does not fall in the critical region so we accept our null hypothesis and conclude that the coin is fair.


Related Questions

Which solution value satisfies the inequality equation x – 5 ≤ 14?

Answers

Answer:

Any value that has x less than or equal to 19 is a solution

Step-by-step explanation:

x – 5 ≤ 14

Add 5 to each side

x – 5+5 ≤ 14+5

x  ≤ 19

Any value that has x less than or equal to 19 is a solution

Answer:

[tex]\boxed{x\leq 19}[/tex]

Step-by-step explanation:

[tex]x-5\leq 14[/tex]

[tex]\sf Add \ 5 \ on \ both \ sides.[/tex]

[tex]x-5+5 \leq 14+5[/tex]

[tex]x\leq 19[/tex]

Can someone please help me ASAP:(

Answers

Answer:

3 =x

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

3x(x+1) = 4x*x

Divide each side by x

3(x+1) = 4x

Distribute

3x+3 = 4x

Subtract 3x from each side

3x-3x +3 = 4x-3x

3 =x

Find the sum of the first 30 terms in the sequence in #2. (Sequence is 16, 7, -2, …) Just need sum of first 30 solved :)

Answers

The sequence is arithmetic, since the forward difference between consecutive terms is -9.

7 - 16 = -9

-2 - 7 = -9

etc.

This means the sequence has the formula

[tex]a_n=16-9(n-1)=25-9n[/tex]

The sum of the first 30 terms is

[tex]\displaystyle\sum_{n=1}^{30}a_n=25\sum_{n=1}^{30}1-9\sum_{n=1}^{30}n[/tex]

Recall the formulas,

[tex]\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n[/tex]

[tex]\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2[/tex]

Then the sum we want is

[tex]\displaystyle\sum_{n=1}^{30}a_n=25\cdot30-\frac{9\cdot30\cdot31}2=\boxed{-3435}[/tex]

n a genetics experiment on​ peas, one sample of offspring contained 372 green peas and 35 yellow peas. Based on those​ results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3 4 that was​ expected?

Answers

Complete Question

In a genetics experiment on​ peas, one sample of offspring contained 372 green peas and 35 yellow peas. Based on those​ results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was​ expected?

Answer:

The  probability is  [tex]P(g) = 0.9140[/tex]

No it is not close to the probability expected

Step-by-step explanation:

From the question we are told that

    The sample size is  [tex]n = 372 + 35= 407[/tex]

      The  number of  green peas is  [tex]n_g = 372[/tex]

    The  number of  yellow  peas is  [tex]n_y = 35[/tex]

The  probability of getting an offspring pea that is green is mathematically represented as

         [tex]P(g) = \frac{n_g}{n}[/tex]

substituting values

         [tex]P(g) = \frac{372}{ 407}[/tex]

         [tex]P(g) = 0.9140[/tex]

The  expected probability is  [tex]\frac{3}{4} = 0.75[/tex]

But what we got is  [tex]P(g) = 0.9140[/tex]

So we can say that the value obtained is not equal to the expected value

find the value of each variable and the measure of each angle​

Answers

Answer:

Left angle = 60°

Top angle = 120°

Right angle = 60°

Step-by-step explanation:

Use what you know about angle relationships to set up equations you can solve for each variable.

The top top angle, for example, added to one of the other angles must equal 180° because they are supplementary.

You have two variables, so you need at least two equations (I made three but only used two).

The work is in my attachment, comment of you have questions.

A bag contains three red marbles, two green ones, one lavender one, two yellows, and two orange marbles. HINT [See Example 7.] How many sets of seven marbles include at least one yellow one but no green ones

Answers

Answer: 8

Step-by-step explanation:

Given: A bag contains three red marbles, two green ones, one lavender one, two yellows, and two orange marbles.

Total marbles other than green = 8

Total marbles other than green and yellow = 6

Then the number of sets of seven marbles include at least one yellow one but no green ones:-

[tex]^{2}C_1\times^{6}C_6+ ^2C_2\times^6C_5\\\\= 2\times 1+1\times6\\\\=2+6=8[/tex]

Number of sets of seven marbles include at least one yellow one but no green ones = 8

Policeman A and Policeman B hand out 70 speeding tickets in a month.
Policeman A hands out 4 times as many speeding tickets as Policeman B.
Policeman A handed out ? Speeding tickets.

Answers

Answer:

Policeman A = 56 tickets

Step-by-step explanation:

Policemen A + B = 70

If Policeman B hands out x no of tickets...

Then Policeman A hands out 4x no of tickets

meaning...

x + 4x = 70

5x = 70

x = 70/5

x = 14

Therefore Policeman A hands out..

4x = 4 × 14 = 56 tickets

A random sample of 10 single mothers was drawn from a Obstetrics Clinic. Their ages are as follows: 22 17 27 20 23 19 24 18 19 24 We want to determine at the 5% significance level that the population mean is not equal to 20. What is the rejection region?

Answers

Answer:

0.09

Step-by-step explanation:

Let x = ages of mother

x  :  22   17    27    20    23     19      24    18    19    24

N = 10

Mean = ∑x/N = 218/10 = 21.8

Difference in mean = 21.8 - 20 = 1.8

If significance level = 5% or 0.05

∴ Rejection region = 1.8 X 0.05 = 0.09

football team, won 35 out of 39 games over a period of 4 years. if they keep winning pace, predict how many games you would expect them to win over the next 78 football games

Answers

Answer:

70

Step-by-step explanation:

If the team continues with same pace, they expected wins as per previous ratio:

35/39*78 = 70

Expected wins 70 out of 78 games

I need help will rate you brainliest 10

Answers

Answer:

It is option A

Step-by-step explanation:

A is correct option

A European study of thousands of men found that the PSA screening for prostate cancer reduced the risk of a man’s dying from prostate cancer from 3.0 percent to 2.4 percent. "But it’s already a small risk. I don’t think a difference of less than 1 percent would be of practical importance," said Ed. Do you agree with Ed’s conclusion?

Answers

Answer:

Following are the answer to this question:

Step-by-step explanation:

In the given statement, we don't agree with Ed’s conclusion, because it is not relevant simply since it is not statistically significant. The reduction of prostate cancer is the death risk, which is highly significant even if it decreases significantly. It can also be something statistically important without becoming important.

Given g(x) = -x - 2, find g(3).

Answers

Answer:

g(3) = -5

Step-by-step explanation:

g(3) is basically the value of g(x) when x = 3. Therefore, g(3) = -3 - 2 = -5.

Answer:

[tex] \boxed{\sf g(3) = -5} [/tex]

Given:

g(x) = -x - 2

To Find:

g(3) i.e. g(x) where x = 3

Step-by-step explanation:

[tex]\sf Evaluate \ -x - 2 \ where \ x = 3:[/tex]

[tex] \sf \implies - x - 2 = - 3 - 2[/tex]

[tex] \sf - 3 - 2 = - (3 + 2) : [/tex]

[tex] \sf \implies - (3 + 2)[/tex]

[tex] \sf 3 + 2 = 5 : [/tex]

[tex] \sf \implies - 5[/tex]

A simple random sample of 60 households in city 1 is taken. In the sample, there are 45 households that decorate their houses with lights for the holidays. A simple random sample of 50 households is also taken from the neighboring city 2. In the sample, there are 40 households that decorate their houses. What is a 95% confidence interval for the difference in population proportions of households that decorate their houses with lights for the holidays

Answers

Answer:

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

Step-by-step explanation:

We formulate the null and alternative hypotheses as

H0: p1= p2 there is no difference in population proportions of households that decorate their houses with lights for the holidays

against Ha : p1≠ p2  (claim)  ( two sided)

The significance level is set at ∝= 0.05

The critical value for two tailed test at alpha=0.05 is ± 1.96

or Z∝= 0.05/2= ± 1.96

The test statistic is

Z = p1-p2/√pq(1/n1 +1/n2)

p1= proportions of households  decorating in city 1  = 45/60=0.75

p2= proportions of households  decorating in city 2 = 40/50= 0.8

p = the common proportion on the assumption that the two proportion are same.

p =   [tex]\frac{n_1p_1 +n_2p_2}{n_1+n_2}[/tex]

Calculating

p =60 (0.75) + 50 (0.8) / 110

p=  45+ 40/110= 85/110 = 0.772

so  q = 1-p= 1- 0.772= 0.227

Putting the values in the test statistic and calculating

z= 0.75- 0.8/ √0.772*0.227( 1/60 + 1/50)

z= -0.05/√ 0.175244 ( 110/300)

z= -0.05/0.25348

z= -0.197

The calculated value of z = - 0.197  falls in the critical region therefore we reject the null hypothesis and conclude that  at  the 5% significance level there is significant difference in population proportions of households that decorate their houses with lights for the holidays

how much would it cost to buy 100 shares in ODX group Inc and 300 shares

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The cost to buy 100 shares in ODX group Inc and 300 shares   peer Comms Lts is  

         [tex]C = \$ 775[/tex]

Step-by-step explanation:

   From the chat we that the cost of 100  ODX shares is  [tex]\$175[/tex]

    The cost of 100 peer Comms Lts  is  [tex]\$ 200[/tex]

Hence the cost 300 peer Comms Lts  is  [tex]k = 3 * 200 = \$ 600[/tex]

Now  the cost of  100 shares in ODX group Inc and 300 shares of  peer Comms Lts  is mathematically evaluated as

           [tex]C = 175 + 600[/tex]

           [tex]C = \$ 775[/tex]

 

 

The cost to buy 100 shares in ODX group Inc and 300 shares in peer comm LTD is $775.

Given in question the graph here is missing.

We have to calculate the total cost of 100 shares in ODX group Inc and 300 shares in peer comms limited in year 5.

From the graph it is clear that, the x axis shows the no. of year and y axis shows the cost of 100 shares for each type.

From graph, the cost of 100 shares of ODX group in year 5 is $175.

And the cost of 100 shares of peer comm Ltd in year 5 is $ 200.

So the total cost of 300 shares of  peer comm Ltd in 5 year is $([tex]200\times3[/tex]) or $600.

Now final cost of 100 shares in ODX group Inc and 300 share in peer comm Ltd is [tex]($600+$175)[/tex] dollars.

Hence the cost to buy 100 shares in ODX group Inc and 300 shares in peer comm LTD is $775.

For more details on graph follow the link:

https://brainly.com/question/14375099

What does it mean when the resulting temperature is above 0 on the number line? What does it mean when a temperature is below 0?

Answers

Answer:

It means that above 0 degrees Celsius the water does not freeze, whereas 0 degrees are freezing teperatures of water.

Step-by-step explanation:

Water freezes at 0 degrees Celsius, but the freezing temperature can be lowered  by adding salt to the water. A student discovered that adding half a cup of salt to  a gallon of water lowers its freezing temperature by 7 degrees Celsius. What is  the freezing temperature of the gallon of salt water?

0° - 7° = -7°

My town has two cell phone providers. The provider Don’tTalkMuch charge is $80 per month plus 1 dollar per hour the provider TalkLots charges $20 per month plus 4 dollars per hour how much do you have to use your phone in a month in order for Don’tTalkMuch’s much is a deal to be better for you?

Answers

Answer:

The author have to use his/her phone less than 20 hours in a month in order for Don’tTalkMuch's is a deal to be better than TalkLots's is.

Step-by-step explanation:

Call X is the number of hours that the author uses on monthly basis.

Total bill value if the author uses Don’tTalkMuch service is $80 + $1 X.

Total bill value if the author uses TalkLots service is $20 + $4X

The total fees between 2 providers equal as:

$80 + $1 X = $20 + $4X => 3X = $60 => X = 20

Hence: The author have to use his/her phone less than 20 hours in a month in order for Don’tTalkMuch's is a deal to be better than TalkLots's is.

what are the comparison symbols for 5/6 and 2/5, 4/10 and 7/8, and 3/12 and 1/4

Answer like this: Example

=
<
>

Answers

Answer:

5/6 > 2/44/10 < 7/83/12 = 1/4

Step-by-step explanation:

The comparison will be the same if you subtract the right side and compare to zero:

  a/b ?? c/d . . . . . . . using ?? for the unknown comparison symbol

  a/b - c/d ?? 0 . . . . subtract the fraction on the right

  (ad -bc)/bd ?? 0 . . . combine the two fractions

  ad - bc ?? 0 . . . . . . multiply by bd to make the job easier

__

5/6 and 2/5

  5(5) -6(2) = 25 -12 > 0   ⇒   5/6 > 2/5

4/10 and 7/8

  4(8) -10(7) = 48 - 70 < 0   ⇒   4/10 < 7/8

3/12 and 1/4

  3(4) -12(1) = 0   ⇒   3/12 = 1/4

_____

Of course, you can use your calculator (or your memory) to change each of these to a decimal equivalent. The comparison should be easy at that point.

  0.833 > 0.400

  0.400 < 0.875

  0.250 = 0.250

please solution this question now .thank you very much​

Answers

Answer:

  5/2

Step-by-step explanation:

Let u = sin(t). Then this is the integral ...

  [tex]\displaystyle\int_0^{\frac{\pi}{2}}{5u}\,du=\left.\dfrac{5u^2}{2}\right|_0^{\frac{\pi}{2}}=\dfrac{5}{2}(\sin(\frac{\pi}{2})^2-\sin(0)^2)=\dfrac{5}{2}(1-0)=\boxed{\dfrac{5}{2}}[/tex]

sasha has some pennies nickels and dimes in her pocket. the number of coins is 18 the expression is 0.01p+0.05n+0.10d represents the value of the coins which is 1.08 she has twice as many dimes as pennies. How many of each coin does Sasha have

Answers

Answer:

3 pennies, 9 nickels, and 6 dimes

Step-by-step explanation:

We have three conditions:

(1)         p +        n +        d = 18

(2) 0.01p + 0.05n + 0.10d = 1.08

(3)                                   d = 2p

Multiply (2) by 100 and rearrange (3) to get a standard array.

(4)      p +   n +     d =   18

(5)      p + 5n + 10d = 108

(6)  -2p          +     d =    0

Subtract (4) from (5). This gives

(4)      p +   n +   d =  18

(7)            4n + 9d = 90

(6)  -2p          +   d =   0

Multiply (4) by 2 and add to (6). This gives

(4) p +   n +    d =  18

(7)        4n + 9d = 90

(8)        2n + 3d = 36

Double (8) and subtract from (7). This gives

(4)      p +   n +   d = 18

(7)            4n + 9d = 90

(9)                    3d = 18

Divide (9) by 3. This gives

(10) d = 6

Substitute (10) into (7). This gives

4n + 9(6) = 90

4n +   54 = 90

4n           = 36

(11) n       =    9

Substitute (10) and (11) into (4). This gives

p + 9 + 6 = 18

p +      15 = 18

p              =  3

Sasha has 3 pennies, 9 nickels, and 6 dimes.

How many solutions does the following equation have?
-5(z+1)=-2z+10
Choose 1 answer:
A: No solutions
B: Exactly one solution
C: Infinitely many solutions

Answers

Answer:

B

Step-by-step explanation:

-5z +1 = -2z +10

-3z = 9

z=9/-3

Z= -3

Answer:

the answer is exactly one solution

Step-by-step explanation:

this is the answer because i just took this question on khan academy and the one solution is z = -5 for the equation

Write all the factors of 32
Matj
Answer

Answers

The factors of a number are all the whole integers that can be multiplied to get that number. The factors for 32 are:

1 * 32

2 * 16

4 * 8

1, 2, 4, 8, 16, and 32

Answer: 1, 2, 4, 8, 16, and 32.

Step-by-step explanation:

Factors are what we can multiply to get the number.

Factors of 32:

1 x 32=32

2 x 16=32

4 x 8=32

Therefore, the factors of 32 are 1, 2, 4, 8, 16, and 32.

Which option is correct and how would one solve for it?

Answers

Answer:

28

Step-by-step explanation:

We need to find the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex]

We know that,

[tex]\Sigma n^2=\dfrac{n(n+1)(2n+1)}{6}[/tex]

Here, n = 3

So,

[tex]\Sigma n^2=\dfrac{3(3+1)(2(3)+1)}{6}\\\\\Sigma n^2=14[/tex]

So,

[tex]\Sigma_{x=0}^3\ 2x^2=2\times 14\\\\=28[/tex]

So, the value of [tex]\Sigma_{x=0}^3\ 2x^2[/tex] is 28. Hence, the correct option is (d).

Find the measure of the remote exterior angle. mZx = (4n – 18)º
m2y = (n+9)°
m2z = (151 – 5n)º
y
Х
Z

Answers

Answer:

71°

Step-by-step explanation:

The sum of two interior angles in a triangle is equal to an exterior angle

m<x + m<y = m<z

4n - 18 + n + 9 = 151 - 5n

5n - 9 = 151 - 5n add like terms

10n = 160

n = 16

Since m<z = 151 - 5n we replace n with 16 and 151 - 5×16 = 71

Answer:

A. 71

Step-by-step explanation:

x + y = z

4n - 18 + n + 9 = 151 - 5n

5n - 9 = 151 - 5n

10n = 160

n = 16

Z = 151 - 5(16) = 71

A line passes through (-5, -3) and is parallel to -3x - 7y = 10. The equation of the line in slope-intercept form is _____

Answers

Answer:

-3x - 7y = 36

Step-by-step explanation:

The given line -3x - 7y = 10 has an infinite number of parallel lines, all of the form -3x - 7y = C.

If we want the equation of a line parallel to -3x - 7y = 10 that passes through (-5, -3), we substitute -5 for x in -3x - 7y = 10 and substitute -3 for y in -3x - 7y = 10:

-3(-5) - 7(-3) = C, or

15  + 21 = C, or C = 36

Then the desired equation is -3x - 7y = 36.

Given the following computer printout for a set of sample data, which one of the following represents the value of the Interquartile Range?
Descriptive Statistics: Cycle Time
Variable N Mean StDev Variance Minimum Q1 Median Q3 Maximum
Cycle Time 52 31.808 5.333 28.436 21.700 27.825 31.000 36.075 44.000
A. 22.3
B. 3.175
C. 5.075
D. 8.25

Answers

Answer: D. 8.25

Step-by-step explanation: A data set can be divided into 4 equal parts, called Quartile. A quartile divides the data into three points:

Lower quartile: Q1;Median: Q2;Upper quartile: Q3;

Interquartile Range (IQR) is a measure of variability based on data divided into quartiles or the measure of where the bulk of the values are.

To calculate interquartile range:

IQR = Q3 - Q1

The table shows Q1 = 27.825 and Q3 = 36.075, then

IQR = 36.075 - 27.825

IQR = 8.25

The value of interquartile range is 8.25.

What number is the opposite of -3?
Explain your reasoning

Answers

The answer is 3

Answer Explanation:

helpppppppppppppppppppppppppppp give bralienst

Answers

Answer:

Brainliest! Hope I helped!

Step-by-step explanation:

you know its greater than 1cm and less than 2cm,

1 and 7hundreths cm is = 1.07 cm

thats not right because you know it is greater than that for sure!

so the only answer left is 1.7 cm

You answer is 1.7 cm

another way...

read the ruler and see the answer

Answer:

1.7 cm.

Step-by-step explanation:

The midpoint of 1 - 2 is 5 so count the lines after 5 and you get .7 to add to one cm.

Hope this helps, have a good day :)

George's height is 1.75 meters and Martha's height is 160 centimeters. How much taller is George than Martha in millimeters?

Answers

Converting 1.75 meters to mm :
1.75*100*10=1750 mm
Converting 160 cm to mm:
160*10=1600 mm
George=1750mm
Martha=1600mm
George-Martha = 150 mm
George is 150 mm taller than Martha

George should be 150 mm taller than Martha.

Calculation of the height in millimeters:

Since George's height is 1.75 meters and Martha's height is 160 centimeters.

So here we convert the meters to mm

So,

[tex]= 1.75\times 100\\\[/tex]

= 1750 mm

Now 160 cm to mm

So,

[tex]= 160\times 10[/tex]

= 1,600 mm

So, the difference should be

= 1,750 - 1,600

= 150 mm

Therefore, George should be 150 mm taller than Martha.

Learn more about height here: https://brainly.com/question/15810288

What is the simplified form of the following expression? 2 StartRoot 18 EndRoot + 3 StartRoot 2 EndRoot + StartRoot 162 EndRoot 6 StartRoot 2 EndRoot 18 StartRoot 2 EndRoot 30 StartRoot 2 EndRoot 36 StartRoot 2 EndRoot

Answers

Answer:

[tex]18\sqrt2[/tex]

Step-by-step explanation:

To simplify:

[tex]2 \sqrt{18}+ 3 \sqrt2+ \sqrt{162 }[/tex]

First of all, let us write 18 and 162 as product of prime factors:

[tex]18 = 2 \times \underline{3 \times 3}\\162 = 2 \times \underline{3 \times 3} \times \underline{3 \times 3}[/tex]

The pairs are underlined as above.

While taking roots, only one of the numbers from the pairs will be chosen.

Now, taking square roots.

[tex]\sqrt{18} =3 \sqrt2[/tex]

[tex]162 = 3 \times 3 \times \sqrt 2 = 9 \sqrt2[/tex]

So, the given expression becomes:

[tex]2 \sqrt{18}+ 3 \sqrt2+ \sqrt{162 } = 2 \times 3\sqrt2 + 3\sqrt2 +9\sqrt2\\\Rightarrow 6\sqrt2 + 3\sqrt2 +9\sqrt2\\\Rightarrow \sqrt2(6+3+9)\\\Rightarrow \bold{18\sqrt2}[/tex]

So, the answer is:

[tex]18\sqrt2[/tex] or 18 StartRoot 2 EndRoot

Answer:

its B. 18 sqrt(2)

Step-by-step explanation:

just took test

Consider the function f(x) = x2. Which of the following functions shifts f(x)
downward 5 units and to the right 3 units?
A)f(x) = (x + 3)2 - 5
B) f(x) = (x - 3)2 - 5
C) f(x) = (x - 5)2 - 3
D) f(x) = (x - 5)2 + 3

Answers

Answer:

f(x) = (x - 3)² - 5

Step-by-step explanation:

equate equation to 0

(x - 3)² = 0

take the square root on both sides

x - 3 = 0

add 3

x = 3

If x = 3 then you are moving to 3 units to the right.

- 5 means you are going downward 5 units.

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