A cube shaped box has a volume of 1 cube. Qhst is the area of one of its faces?

Answer:

24

Step-by-step explanation:

m=8x4 n=3x4 so that is the answer

Monique can choose 20 different sets of 3 of the books

The set of books she can select from the library is an illustration of combination (or selection)

The expression that represents combination is represented as:

[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]

Where:

So, we have:

[tex]^6C_3 = \frac{6!}{(6 - 3)!3!}[/tex]

Evaluate the differences

[tex]^6C_3 = \frac{6!}{3!3!}[/tex]

Evaluate the factorials

[tex]^6C_3 = \frac{720}{6 \times 6}[/tex]

Evaluate the products

[tex]^6C_3 = \frac{720}{36}[/tex]

Divide 720 by 36

[tex]^6C_3 = 20[/tex]

Hence, Monique can choose 20 different sets of 3 of the books

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Answer:

it is in fact 20 (for khan)

Step-by-step explanation:

credit goes to person above

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Answer:

Below.

Step-by-step explanation:

(a^2b - c)^2

= ​(a^2b - c)(a^2b - c)

= a^4b^2 - a^2bc - a^2bc + c^2

= a^4b^2 - 2a^2bc + c^2.

Answer:

16.7%

Step-by-step explanation:

Putting 1/6 into a calculator gives you 16.67, the question is asking to round the the nearest tenth, so 16.7%.

Answer:

Step-by-step explanation:

The Sydney Harbour Bridge is approximately 1200 metres long. A model of the bridge is built with a scale of 1:6000. What is the length of the model?

Pick one:

5cm

20cm

200cm

720cm

--------------------

scale = 1:6000

so

1200 : 6000 =  0.2m

0.2m = 20 cm

Answer:

20cm

Step-by-step explanation:

«A scale of 1:6000» means the model is smaller than the bridge by a factor of 6000. We can also make up a proportion [tex]\dfrac{1}{6000}=\dfrac{x}{1200}[/tex], where the left side is the scale, x is the model length, 1200 is the bridge length (in meters). So, finding x or just dividing 1200 by 6000, we get 0.2 meters. Provided 1 m = 100 cm, 0.2 m is 0.2 × 100 = 20 cm.

Step-by-step explanation:

5x - 6 = 3x + 2

5x - 3x = 2 + 6

2x = 8

x = 8/2

x = 4

Answer:

yes

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

126/3 = 42

Answer: x = 5, y = 6

Step-by-step explanation: took the quiz.

Answer:

Where's the Answer? There's No

Hello there!

Remember that equivalent fractions have the same value.

[tex]\frac{1}{2} , \frac{2}{24} ,\frac{3}{36}, \frac{4}{48}[/tex]

Hope this helps you!

~Just a felicitous girlie

#HaveASplendidDay

[tex]SilentNature :)[/tex]

Answer:

[tex]y=-\frac{5}{2}x+\frac{3}{2}[/tex]

Step-by-step explanation:

[tex]5x+2y=3\\\\2y=-5x+3\\\\y=-\frac{5}{2}x+\frac{3}{2}[/tex]

Answer:

Step-by-step explanation:

Slope-intercept from: y = mx + b

5x + 2y = 3

       2y = -5x + 3

Divide the whole equation by 2

[tex]\dfrac{2y}{2}=\dfrac{-5x}{2}+\dfrac{3}{2}\\\\y=\dfrac{-5}{2}x +\dfrac{3}{2}[/tex]

Answer:

She can fit 9 cubic feet of clothing in the two boxes.

Step-by-step explanation:

6 cubic feet + 3 cubic feet = 9 cubic feet.

-Lexi

Answer:

9 ft^3

Step-by-step explanation:

Add together the box capacities:  3 ft^3 + 6 ft^3 = 9 ft^3.

Maddie can pack a total of 9 ft^3 of clothing into these two boxes.

Answer:

20400

Step-by-step explanation:

its 2.03x10x10x10x10 so first ten: 20.4 and ten: 204 3rd ten: 2040 last ten :20400

Answer:

i think the answer should be 8

Step-by-step explanation:

Answer:

The kinetic energy of the car is 43,200 Joules.

Step-by-step explanation:

KE = (1/2)mv^2

KE = (1/2)(600 kg)(12 m/s)^2

KE = (1/2)(600 kg)(144 m^2/s^2)

KE = 43,200 kg*m^2/s^2 = 43,200 Joules

Answer:

Step-by-step explanation:

KE= 1/2mv^2

KE = 1/2(600) 12^2

KE = 300 * 144 = 43200J

Answer:

1000

Step-by-step explanation:

15 = 15/100 x a

a = 150 ÷ 15/100

a = 150 x 100/15

a = 1000

Answer:

i think it is 49:9

Step-by-step explanation:

because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9

Answer:

28:12

Step-by-step explanation:

Multiply both 7 and 3 by 4 and you get the ratio 28:12.

Answer:

Step-by-step explanation:

Given,

Sum of parallel sides of the trapezium = 10 cm

Distance between or Height of the trapezium = 2 cm

As we know,

Area of a trapezium

[tex] = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height[/tex]

Therefore,

Area of the given trapezium will be,

[tex] = \frac{1}{2} \times 10 \: cm \times 2 \: cm[/tex]

= 1 × 10 cm × 1 cm

[tex] = 10 {cm}^{2} [/tex]

Hence,

The Area of the trapezium is 10 sq.cm (Ans)

Given :

To Find :

Solution :

We know that,

[tex]{ \qquad \: \pmb{ \dfrac{1}{2} \times (sum \: of \: the \: parallel \: sides) \times height} = \pmb{Area_{(trapezium)}}}[/tex]

Now, Substituting the given values in the formula :

[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times 10\: \times 2 \: = {Area_{(trapezium)}}}}}[/tex]

[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times 20 = {Area_{(trapezium)}}}}}[/tex]

[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{20}{2} = {Area_{(trapezium)}}}}}[/tex]

[tex]\qquad { \dashrightarrow \: { \sf{ 10 = {Area_{(trapezium)}}}}}[/tex]

⠀

Hence,

Answer:

705.3 repeated I don't know if that's what you want but

3 times of 705.33 and 2 subtracted is equal to 2114.

Simplification in mathematical terms is a process to convert a long mathematical expression in simple and easy form.

Given that,

2 less than 3 times a number equal to 2114.

Let the required number is x.

According to given condition,

3x - 2 = 2114

3x = 2114 + 2

3x = 2116

x = 2116 / 3

x = 705.33

The required number is 705.33.

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√54/3, √13, 6, 8, 26/3

Answer:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x

Answer:

the first option

Step-by-step explanation:

Answer:

1.) x = 2

2.) x = 5

3.) x = 9

4.) x = 0

Step-by-step explanation:

1.) -3x - 8 = -14

-3x = -6

x = 2

2.) 4x - 6 = 14

4x = 20

x = 5

3.) -3 - 3x = -30

-3x = -27

x = 9

4.) -5x + 5 = 5

-5x = 0

x = 0

Anwser 6720 ways different

Step-by-step explanation:

In this case, we must calculate the different ways using the permutation formula:

nPr = n! / (n - r)!

where n is the total number of people and r would come being the group of person that you want to put together the groups, therefore n = 8 and r = 5

replacing:

8P5 = 8! / (8 - 5)!

8P5 = 6720

That is to say that there are 6720 ways different winning groups are possible

Answer:

If we divide twice the qualifier of Jose by 4 it results in less than 8. What is Jose's highest grade?

Step-by-step explanation:

[tex]f(x) = 7x - 6[/tex]

[tex] \: [/tex]

Inverse

[tex]y = 7x - 6[/tex]

[tex]x = 7y - 6[/tex]

[tex]x + 6 = 7y[/tex]

[tex]y = \frac{x + 6}{7} [/tex]

[tex] {f}^{ - 1} (x) = \frac{x + 6}{7} [/tex]

Answer:

-5x+2

Step-by-step explanation:

1. Multiply number 2 and 2=4 so it is

4-5x-2

2. Combine like terms

-5x+4-2

3. Subtract the numbers

-5x+2

Answer:

x3 + 2x2 − 29x + 20

Step-by-step explanation:

x(x2+6x−5)−4(x2+6x−5)

x3+6x2−5x−4(x2+6x−5)

x3+6x2−5x−4x2−24x+20

x3+2x2−5x−24x+20

x3 + 2x2 − 29x + 20