A city of Punjab has a 15 percent chance of wet weather on any given day. What is the probability that it will take a week for it three wet weather on 3 separate days? Also find its Standard Deviation

Answers

Answer 1

Answer:

The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447

Explanation:

Probability of wet weather = 0.15

Probability of not being a wet weather = 1-0.15

We are supposed to find probability that it will take a week for it three wet weather on 3 separate days

Total number of days in a week = 7

We will use binomial over here

n = 7

p =probability of failure = 0.15

q = probability of success=1-0.15

r=3

Formula :[tex]P(r=3)=^nC_r p^r q ^{n-r}[/tex]

[tex]P(r=3)=^{7}C_{3} (0.15)^3 (1-0.15)^{7-3}\\P(r=3)=\frac{7!}{3!(7-3)!} (0.15)^3 (1-0.15)^{7-3}\\P(r=3)=0.06166[/tex]

Standard deviation =[tex]\sqrt{n \times p \times q}[/tex]

Standard deviation =[tex]\sqrt{7 \times 0.15 \times (1-0.15)}[/tex]

Standard deviation =0.9447

Hence The probability that it will take a week for it three wet weather on 3 separate days is 0.06166 and its standard deviation is 0.9447


Related Questions

Consider a data set of 15 distinct measurements with mean A and median B , if the highest number were increased , what would be the effect on the median and mean?

Answers

Answer:

Mean would increase, median will stay the same.

Explanation:

If the highest numbers were to be increased, than the mean (average), would also increase, because you will be dividing a larger number into 15 parts.

However the median (middle number in a data set), will stay the same because if only the top few numbers get their value increased the middle value will still be the same.

Your academic calendar has been distracted by the global pandemic, such that, you are to teach your class from the house. Outline specific hardware and software and the various teaching and learning tools you will deploy to enable you continue to teach your pupils from home. Discuss four (4) ways you will use to reach all pupils who are living at a​

Answers

The correct answer to this open question is the following.

During this pandemic moments that students have to stay at home and taking classes, I would use the proper hardware to teach good video classes. Of course, a good computer or lap tot with modern hardware capacities such as "intel Pentium" or higher. A good and high-speed internet connection will help me to efficiently use all the tools and educational apps such as the one needed to teach video class. These are google meet and zoom.

I will use the following tools to reach all pupils. First, the classroom of Google to have all the homework information on one site. I would use Google Drive to store all the information and evidence of the semester. Another good tool is Canva, for the students to elaborate all their infographics needed to do homework. For better school presentations I would also use "gneally," a good presentation system that has room for a lot of animation.

B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of length 4. The number of binary code words, B(n), of length n, is shown above. If the length is increased from n to n+1, how many more binary code words will there be? The answer is 2^n, but I don't get how they got that answer. I would think 2^n+1 minus 2^n would be 2. Please help me! Thank you! ​

Answers

Answer:

The additional words is [tex]2^n[/tex]

Explanation:

Given

[tex]B(n) = 2^n[/tex]

Required

Determine the additional words; i.e. [tex]B(n + 1) - B(n)[/tex]

From the given parameters, we have that;

B is a function of n

Such that;

[tex]B(n) = 2^n[/tex]

To calculate [tex]B(n+1)[/tex], we simply substitute n + 1 for n

[tex]B(n) = 2^n[/tex]

[tex]B(n + 1) = 2^{n + 1}[/tex]

Applying laws of indices

[tex]B(n + 1) = 2^{n} * 2^1[/tex]

[tex]B(n + 1) = 2^{n} * 2[/tex]

[tex]B(n + 1) = 2(2^{n})[/tex]

Calculating Additional Binary Code;

[tex]B(n + 1) - B(n)[/tex]

Substitute values for B(n + 1) and B(n)

[tex]B(n + 1) - B(n) = 2(2^n) - 2^n[/tex]

Express [tex]2^n[/tex] as [tex]2^ n * 1[/tex]

[tex]B(n + 1) - B(n) = 2(2^n) - 2^n * 1[/tex]

Express 1 as [tex]2^0[/tex]

[tex]B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0[/tex]

Factorize

[tex]B(n + 1) - B(n) = 2^n(2 - 2^0)[/tex]

[tex]B(n + 1) - B(n) = 2^n(2 - 1)[/tex]

[tex]B(n + 1) - B(n) = 2^n(1)[/tex]

[tex]B(n + 1) - B(n) = 2^n[/tex]

Hence, the additional words is [tex]2^n[/tex]

Which of the following is an example of a parameter? 9047 out of 531,310 citizens voted in the special election for city council. Half of the receipts at the coffee shop include web address for giving feedback. 3.5% of the restaurant goers are given a survey to fill out. All of the members of the community watch group gave their availability to volunteer over the summer.

Answers

Answer:

All of the members of the community watch group gave their availability to volunteer over the summer.

Explanation:

In Statistics, a parameter can be defined as a fixed quantity which summarizes the characteristic of an entire population. Generally, a parameter gives a detailed description of a given population.

In this scenario, all of the members of the community watch group making known their availability to volunteer over the summer is an example of a parameter.

Another example of a parameter is, asking all tutors on brainly website what subject they love tutoring most and half of them said Mathematics; 50% of the total tutors loves Mathematics---this is a parameter.

Answer:

All of the members of the community watch group gave their availability to volunteer over the summer.

Explanation:

Got it right on the test.


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Answers

Answer:

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Explanation:

Actually, that is what you should do SECOND.

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Answer:

A

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Answers

Answer:

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Explanation:

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Answer:

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