Starting at the same spot on a circular track that is 80 meters in diameter, Hillary and Eugene run in opposite directions, at 300 meters per minute and 240 meters per minute, respectively. They run for 50 minutes. What distance separates Hillary and Eugene when they finish
Answer:
143.32 m
Step-by-step explanation:
Given the following :
Diameter of circular track = 80m
Hillary's speed = 300m per minute
Eugene's speed = 240m per minute
Run time = 50 minutes
Note: they both run in opposite direction.
Calculate the Circumference(C) of the circle :
C = 2πr or πd
Where r = radius ; d = diameter
Using C = πd
C = πd
C = π * 80
C = 251.327
Eugene's distance covered = (240 * 50) = 12000
Hillary's distance covered = (300 * 50) = 15000
Number turns :
Eugene = 12000/ 251.327 = 47.746561
Hillary = 15000/251.327 = 59.683201
Therefore ;
48 - 47.746561 = 0.253439
60 - 59.683201 = 0.316799
(0.253439+0.316799) = 0.570238
Distance which separates Eugene and Hillary when they finish :
0.570238 * 251.327 = 143.32 m
A pet store has m tanks of fish. Each tank has 35 fish. Using m, write an expression for the total number of fish in the store
Answer:
35m
Step-by-step explanation:
Each tank has 35 fish and the total fish tanks is m, so to find the total you will need to do 35*m.
This is an expression because it does not have anything it is equal to.
Expression: No equal sign
Equation:Equal Sign
Hope this helps!:)
In a right angled triangle ABC, ACB =30 and AC=10cm a. calculate BAC b. calculate line AB
Answer:
10 cm is the answer because 30÷3 angles
area of a parrollelogram with a base length of 2.9ft and a height of 5.5ft
Answer:
[tex] \boxed{15.95 \: {ft}^{2} }[/tex]Step-by-step explanation:
base length ( b ) = 2.9 ft
Height ( h ) = 5.5 ft
Let's find the area of parallelogram:
Area of parallelogram : [tex] \mathsf{ = b \times h}[/tex]
plug the values
⇒[tex] \mathsf{2.9 \times 5.5}[/tex]
Multiply
⇒[tex] \mathsf{15.95}[/tex] ft²
--------------------------------------------------------------------
Extra information:
Parallelogram
The quadrilateral in which opposites sides are parallel is called a parallelogram.
The opposite sides of a parallelogram are equal.The opposite angles of a parallelogram are equal.The diagonals of a parallelogram bisect each other.The area of a parallelogram = base × heightHope I helped!
Best regards!
There are a total of two hundred students and chaperones going on a
field trip. Each bus can hold 60 passengers. How many buses will be
used for the field trip? Explain why your answer is reasonable.
Answer:
4 bus is required for field trip to carry 200 passengers.
Step-by-step explanation:
Total no . of passengers = 200
let the be x bus required to carry 200 passengers
capacity of 1 bus = 60 passengers
capacity of x bus = 60*x passengers = 60x passengers
Thus,
60x = 200
x = 200/60 = 3 2/3
thus, 3.66 bus is required , but no. of bus cannot be in fraction hence we take integral value greater than 3.66 which is 4
Thus, 4 bus is required for field trip to carry 200 passenger.
**Yoxelt buys 4 1/ 2 gallons of soda. One-fourth of the soda he bought was Pepsi and the rest was Sprite. How many gallons of Pepsi did Yoxelt buy? Show all work below.
Answer:
1 1/8
Step-by-step explanation:
1/4 of 4 1/2 is Pepsi.
1/4 * 4 1/2 = (1/4) * 4 + (1/4) * (1/2) = 1 1/8
help..? why are there so many parentheses..?can you plz give a step by step on how to slove the equation?
Answer:
= -11
Step-by-step explanation:
-(-(11-22))
= -(-11+22)
= 11 - 22
= -11
BRAINLIEST, 5 STARS AND THANKS IF ANSWERED CORRECTLY.
A quadratic equation with a negative discriminant has a graph that..
A. touches the x-axis but does not cross it
B. opens downward and crosses the x-axis twice
C. crosses the x-axis twice.
D. never crosses the x-axis.
Answer:
never crosses the x-axis.
Step-by-step explanation:
A quadratic equation with a negative discriminant has a graph that - never crosses the x-axis.
Answer:
The graph of a quadratic equation that has a negative discriminant is the one that never intersect x-axis. The graph of a quadratic equation that has a zero discriminant is the one that intersect x-axis at only one point. To be clearer, it can be seen in the attached image.
Step-by-step explanation:
Answer D
Which of the following lists of three numbers could form the side lengths of a triangle? A. 10, 20, 30 B. 122, 257, 137 C. 8.6, 12.2, 2.7 D. 1/2, 1/5, 1/6
Answer:
Step-by-step explanation:
The triangle inequality theorem states that the sum of any two sides of a triangle os greater than the third side.
■■■■■■■■■■■■■■■■■■■■■■■■■■
First triangle:
Let a,b and c be the sides of the triangle:
● a = 10
● b = 20
● c = 30
Now let's apply the theorem.
● a+b = 10+20=30
That's equal to the third side (c=30)
●b+c = 50
That's greater than a.
● a+c = 40
That's greater than b.
These aren't the sides of a triangel since the first inequality isn't verified.
■■■■■■■■■■■■■■■■■■■■■■■■■
Second triangle:
● a = 122
● b = 257
● c = 137
Let's apply the theorem.
● a+b = 379
That's greater than c
● a+c = 259
That's greater than b
● b+c = 394
That's greater than a
So 122,257 and 137 can be sides of a triangle.
■■■■■■■■■■■■■■■■■■■■■■■■■■
The third triangle:
● a = 8.6
● b = 12.2
● c = 2.7
Let's apply the theorem:
● a+b = 20.8
That's greater than c
● b+c = 14.9
That's greater than a
● a+c = 11.3
That isn't greater than b
So theses sides aren't the sides of triangle.
■■■■■■■■■■■■■■■■■■■■■■■■■■
● a = 1/2
● b = 1/5
● c = 1/6
Let's apply the theorem.
● a+b = 7/10
That's greater than c
● a+c = 2/3
That's greater than b
● b+c = 11/30
That isn't greater than a
So these can't be the sides of a triangle.
Lenny is competing with his cousin, Jasper, in an indoor rock-climbing contest. At the start of the climb, Lenny makes his way 5 ¼ feet up the wall, while Jasper climbs 9 ¾ feet. How much farther did Jasper climb than Lenny?
Answer:
[tex]4\frac{1}{2}[/tex] feet further.
Step-by-step explanation:
Since these are mixed numbers that are both in fourths, we can easily subtract the two numbers. However, I find it easier if we first convert both mixed numbers into improper fractions.
[tex]5\frac{1}{4} = \frac{5\cdot4+1}{4} = \frac{21}{4}[/tex]
[tex]9\frac{3}{4} = \frac{9\cdot4+3}{4} = \frac{39}{4}[/tex]
Now we can subtract the numerators:
[tex]\frac{39}{4} - \frac{21}{4} = \frac{39-21}{4} = \frac{18}{4}[/tex]
[tex]\frac{18}{4}[/tex] simplifies down to [tex]\frac{9}{2}[/tex].
Converting [tex]\frac{9}{2}[/tex] to a mixed number is easy - 2 goes into 9 4 times (8) with one remainder so:
[tex]4\frac{1}{2}[/tex] .
Hope this helped!
solve for x 5(x+1)=4(x+8)
Answer:
x=27
Step-by-step explanation:
expanding the above expression we get
5x+5=4x+32
grouping numbers with coefficient of x at the left side and constant at the right side we get
5x-4x=32-5
x=27
HELP!!!
The solutions to (x + 3)^2- 4=0 are x = -1 and x = -5
True or false
Answer:
False
Step-by-step explanation:
We can simplify this equation and then solve for x.
[tex](x+3)^3-4=0\\\\x^2+6x+9-4=0\\\\x^2+6x+5=0\\\\(x+2)(x+3)=0\\\\x=-3\\x=-2[/tex]
As you can see, the solutions are not x=-1 and x=-5.
Therefore, the answer is false.
Answer:
True
Step-by-step explanation:
Given
(x + 3)² - 4 = 0 ( add 4 to both sides )
(x + 3)² = 4 ( take the square root of both sides )
x + 3 = ± [tex]\sqrt{4}[/tex] = ± 2 ( subtract 3 from both sides )
x = - 3 ± 2
Thus
x = - 3 - 2 = - 5
x = - 3 + 2 = - 1
What is negative 14 minus 5
Answer:
-19
Step-by-step explanation:
(-14)
-5
-------
14+5=19
add the negative
-19
the area of a trapezium is 14.7cmsquare. if the parallel sides are 5.3cm and 3.1cm long,find the perpendicular distance between them
The perpendicular distance of the trapezoid is 3.5 cm
How to determine the perpendicular distance?The given parameters are:
Parallel sides = 5.3 cm and 3.1 cmArea = 14.7 square cmThe area of a trapezoid is:
Area = 0.5 * (Sum of parallel sides) * perpendicular distance
So, we have:
14.7 = 0.5 *(5.3 + 3.1) * perpendicular distance
Evaluate
Perpendicular distance = 3.5
Hence, the perpendicular distance of the trapezoid is 3.5 cm
Read more about area at:
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What property is demonstrated here? (3x-5) x 4 = 3 x (-5 x 4) A) commutative property of addition B) associative property of multiplication C) commutative property of multiplication D) associative property of addition (haven't learned this yet so I have no clue)
Answer:
B) Associative Property of Multiplication
Step-by-step explanation:
*if it's wrong idk how, but I apologise*
PLEASE HELPP on THIS PICTURE FOR ONE OF MY QUESTIONS
Answer:
Linear pair postulate
Step-by-step explanation:
The Linear Pair Postulate states: "If two angles form a linear pair, then the angles are supplementary; that is, the sum of their measures is 180 degrees
A linear pair of angles is such that the sum of angles is 180 degrees.
prove that (3-4sin^2)(1-3tan^2)=(3-tan^2)(4cos^2-3)
Answer:
Proof in the explanation.
Step-by-step explanation:
I expanded both sides as a first step. (You may use foil here if you wish and if you use that term.)
This means we want to show the following:
[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]
[tex]=12\cos^2(\theta)-9-4\cos^2(\theta)\tan^2(\theta)+3\tan^2(\theta)[/tex].
After this I played with only the left hand side to get it to match the right hand side.
One of the first things I notice we had sine squared's on left side and no sine squared's on the other. I wanted this out. I see there were cosine squared's on the right. Thus, I began with Pythagorean Theorem here.
[tex]3-9\tan^2(\theta)-4\sin^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]
[tex]3-9\tan^2(\theta)-4(1-\cos^2(\theta))+12\sin^2(\theta)\tan^2(\theta)[tex]
Distribute:
[tex]3-9\tan^2(\theta)-4+4\cos^2(\theta)+12\sin^2(\theta)\tan^2(\theta)[/tex]
Combine like terms and reorder left side to organize it based on right side:
[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
After doing this, I since that on the left we had products of sine squared and tangent squared but on the right we had products of cosine squared and tangent squared. This problem could easily be fixed with Pythagorean Theorem again.
[tex]4\cos^2(\theta)-1+12\sin^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+12(1-\cos^2(\theta))\tan^2(\theta)-9\tan^2(\theta)[/tex]
Distribute:
[tex]4\cos^2(\theta)-1+12\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
Combined like terms while keeping the same organization as the right:
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
We do not have the same amount of the mentioned products in the previous step on both sides. So I rewrote this term as a sum. I did this as follows:
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-12\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
Here, I decide to use the following identity [tex]\cos\theta)\tan(\theta)=\sin(\theta)[/tex]. The reason for this is because I certainly didn't need those extra products of cosine squared and tangent squared as I didn't have them on the right side.
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\cos^2(\theta)\tan^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]
We are again back at having sine squared's on this side and only cosine squared's on the other. We will use Pythagorean Theorem again here.
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8\sin^2(\theta)-9\tan^2(\theta)[/tex]
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8(1-\cos^2(\theta))-9\tan^2(\theta)[/tex]
Distribute:
[tex]4\cos^2(\theta)-1+3\tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)-8+8\cos^2(\theta)-9\tan^2(\theta)[/tex]
Combine like terms:
[tex]12\cos^2(\theta)-9+3tan^2(\theta)-4\cos^2(\theta)\tan^2(\theta)[/tex]
Reorder again to fit right side:
[tex]12\cos^2(\theta)-9+4\cos^2(\theta)\tan(\theta)+3\tan^2(\theta)[/tex]
This does match the other side.
The proof is done.
Note: Reordering was done by commutative property.
Solve logs (8 - 3x) = log20 for x.
A. X = 14
B. X = -13
C.x = -8
D. X= -4
Answer:
x = -4
Step-by-step explanation:
logs (8 - 3x) = log20
Since we are taking the log on each side
log a = log b then a = b
8 -3x = 20
Subtract 8 from each side
8 -3x-8 =20 -8
-3x = 12
Divide by -3
-3x/-3 = 12/-3
x = -4
Answer:
[tex] \boxed{\sf x = -4} [/tex]
Step-by-step explanation:
[tex] \sf Solve \: for \: x \: over \: the \: r eal \: numbers:[/tex]
[tex] \sf \implies log(8 - 3x) = log 20[/tex]
[tex] \sf Cancel \: logarithms \: by \: taking \: exp \: of \: both \: sides:[/tex]
[tex] \sf \implies 8 - 3x = 20[/tex]
[tex] \sf Subtract \: 8 \: from \: both \: sides:[/tex]
[tex] \sf \implies 8 - 3x - 8 = 20 - 8 [/tex]
[tex] \sf \implies - 3x = 12 [/tex]
[tex] \sf Divide \: both \: sides \: by \: - 3:[/tex]
[tex] \sf \implies \frac{-3x}{-3} = \frac{12}{-3} [/tex]
[tex] \sf \implies x = - 4[/tex]
i need help please i give 5 stars ;(
Answer:
D. [tex]\sqrt{\frac{2*2*2*2*3}{5*5*7} }[/tex]
Step-by-step explanation:
48 divided by 2 is 24. Insert the 2.
24 divided by 2 is 12. Insert the 2.
12 divided by 2 is 6. Insert the 2.
6 divided by 2 is 3. Insert the 2 and 3:
[tex]48=2*2*2*2*3[/tex]
175 divided by 5 is 35. Insert the 5.
35 divided by 5 is 7. Insert the 5 and 7:
[tex]175=5*5*7[/tex]
:Done
For the function F(x)= 1/x-2 whose graph is shown below, what is the relative value of F(x) when the value of x is close to 2?
Answer:
10,000
Step-by-step explanation:
What are the domain and range of the real-valued function f(x)=2/(x+5)?
Answer:
Domain is all real numbers, x ≠ -5
Range is all real numbers, y ≠ 0
Step-by-step explanation:
what is the radical of 5√72 PLZ HELP!
Answer: Exact Form: 30√2
Decimal Form:42.42640687…
Step-by-step explanation: Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.
I hope this helped :)
Answer:
30√2
Step-by-step explanation:
The radical portion of the given expression is √72.
__
Perhaps you want the simplest form of your expression. Factor out the perfect squares from under the radical.
[tex]5\sqrt{72}=5\sqrt{36}\sqrt{2}=5\cdot 6\sqrt{2}=\boxed{30\sqrt{2}}[/tex]
Given the right triangle below, if AB = 4 and BC = 4, find AC.
A
B
C
AC will be 4√2 when AB = 4 and BC = 4, in the given right triangle.
What is Pythagoras' Theorem?According to Pythagoras' Theorem, in a right triangle, the square of the length of the longest side, that is, the hypotenuse, that is, the side opposite to the right angle is equal to the sum of the squares of the lengths of the other two sides.
How to solve the question?In the question, we are given a right triangle, with sides AB = 4 and BC = 4.
We are asked to find AC.
To find AC, we will use the Pythagoras theorem, according to which, we can write:
AC² = AB² + BC²
or, AC² = 4² + 4²,
or, AC² = 16 + 16,
or, AC² = 32,
or, AC = √32,
or, AC = √(16 * 2) = 4√2.
Therefore, AC will be 4√2 when AB = 4 and BC = 4, in the given right triangle.
Learn more about Pythagoras' Theorem at
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Point E is on line segment DF. Given DE=9 and DF=11, determine the length EF.
Answer: Line EF=2
Step-by-step explanation: 11 minus 9 is equal to 2. So line EF is equal to 2.
URGENTT PLEASE ANSWER
Answer:
Step 2
Step-by-step explanation:
9 was added to both sided so the equation would remain equal and the 9 would be cancelled out on the left side.
Using a table of values, determine the solution to the equation below to the nearest fourth of a unit. 2^x=1-3^x
Answer:
Option (1)
Step-by-step explanation:
Given equation is,
[tex]2^x=1-3^x[/tex]
To determine the solution of the equation we will substitute the values of 'x' given in the options,
Option (1)
For x = -0.75
[tex]2^{-0.75}=1-3^{-0.75}[/tex]
0.59 = 1 - 0.44
0.59 = 0.56
Since, values on both the sides are approximately same.
Therefore, x = -0.75 will be the answer.
Option (2)
For x = -1.25
[tex]2^{-1.25}=1-3^{-1.25}[/tex]
0.42 = 1 - 0.25
0.42 = 0.75
Which is not true.
Therefore, x = -1.25 is not the answer.
Option (3)
For x = 0.75
[tex]2^{0.75}=1-3^{0.75}[/tex]
1.68 = 1 - 2.28
1.68 = -1.28
Which is not true.
Therefore, x = 0.75 is not the answer.
Option (4)
For x = 1.25
[tex]2^{1.25}=1-3^{1.25}[/tex]
2.38 = 1 - 3.95
2.38 = -2.95
It's not true.
Therefore, x = 1.25 is not the answer.
Barry has been watching the geese that live in his neighborhood. The number of geese changes each week. n f(n) 1 56 2 28 3 14 4 7 Which function best shows the relationship between n and f(n)? f(n) = 28(0.5)n f(n) = 56(0.5)n−1 f(n) = 56(0.5)n f(n) = 112(0.5)n−1
Answer:
B. f(n) = 56(0.5)^n-1
Step-by-step explanation:
First, You have to find out the starting population, if you look at the problem you see the population starts at 56
f(x) = 56
Second, you know that the population goes down 50% each week so it has a decay of 0.5
f(x) = 56(0.5)
Third, you need to add the exponent of n to make it exponential. But, if you just add n then the the population would be 28 on week 1 which is incorrect. To fix that you make the exponent n-1 so when you are on week 1 it doesn't become 28 but it stays on 56, and on week 2 it's 28, ect
f(x) = 56(0.5)^n-1
The row-echelon form of the augmented matrix of a system of equations is given.Find the solution of the system
Answer:
x = 9/4
y = 3/5
z = 2/3
w = -9/5
Step-by-step explanation:
Technically, the matrix is in reduced row echelon form. If there are zeros above and below the ones, it is RREF. If there are zeros only below the ones, then it's REF.
Since it is in RREF, the augmented numbers to the right of the bar are already your solutions. Simply label the variables.
10. RP3-M
Jeanette purchased a concert ticket on a web site. The original price of the ticket was $75.
She used a coupon code to receive a 20% discount. The website applied a 10% service fee
to the discounted price. Jeannette's ticket was less than the original price by what percent?
Answer:
Jeannette's ticket was less than the original pice by 30%
Step-by-step explanation:
original price = $75
percentage discount = 20% of original price = 20% of $75
discounted price = [tex]\frac{20}{100} \times\ 75\ =\ 15[/tex]
discounted price = $15
website service fee = 10% of original price
website service fee = [tex]\frac{10}{100}\times 75 = \$7.5[/tex]
New discounted price = discount price + website service fee
= 15 + 7.5 = $22.5
Next, let us calculate what percentage of the original price that will give the new discount price.
Let the percentage of the original price = x%
x% of 75 = $22.5
[tex]\frac{x}{100} \times\ 75\ = 22.5\\\\\frac{75x}{100} = 22.5\\\\75x = 2250\\\\x = \frac{2250}{75} \\\\x = 30[/tex]
Therefore, Jeannette's ticket was less than the original pice by 30%
Which expression is equivalent to (–2)(a + 6)?
A. –2a + 6
B. 2a + 12
C. –2a – 12
D. –2a + 12
The answer is option c.
