A car with a mass of 1200kg is travelling at 72kmh^-1 when the driver sees a dog running across the street. He applies the brakes and 10 seconds later the car is moving at 18kkmh^-1.
A) Calculate the initial momentum of the car.
B) Calculate the final momentum of the car.
C) Calculate the change in momentum of the car.
D) Calculate the net force applied by the brakes of the car.
Answers
Please find attached photograph for your answer. Please do comment whether it is helpful or not.
Related Questions
1. Review the data collected in the lab and explain the movement of the cart relative to the reference point(starting point). Be sure to mention how far from the origin the cart gets in each time interval.
2. Review the data collected in the lab and determine the relationship between the position of the car relative to the reference point and the amount of time in each time interval in other words as time goes by how does the position change?
3. For this response he will show your work on calculating the speed of the car during the lab remember you are used to change and slope equation or (y^2-y^1)/(x^2-x^1).
Now let’s make connections to the data table the horizontal variable is the time which we will represent with t and the vertical variable is position which we will represent with an x using this we can rewrite the equation above to the following
(final position - initial position)/
(final time - initial time)
Answers
When the data of the position and time are available, the velocity which is the ratio of change in position to change in time which is the same as the slope of the graph of the data can be calculated. For the car, we have;
1. The car moves progressively further as the time interval increases
2. The relationship between the position of the car and the time interval is that the car moves approximately 0.02 units of distance for each change in time of 0.05
3. The speed of the car is 0.398
The reason for arriving at the above values are as follows:
1. From the given data, we have that the cart moves progressively further from the start for each time interval increase, such that the cart moves progressively further from the origin in each time interval increases
[tex]\begin{array}{|c|c|} \mathbf{ Time} & \mathbf{ Position}\\2.2&0.8963\\2.25& 0.9164\\2.3 & 0.9375\\2.35 & 0.9581\\2.4 & 0.9759\end{array}\right][/tex]
2. From the given data, we have;
At time t = 2.2, the position = 0.8963
At time t = 2.25, the position = 0.9164
The change in position for a change in time from 2.2 to 2.25 is, Δx = 0.9164 - 0.8963 = 0.0201
Similarly, for the change in time from 2.25 to 2.3, which is a change of 0.05 seconds, we have;
Δx = 0.9375 - 0.9164 = 0.0211
The next interval is 2.3 to 2.35, Δx = 0.9581 - 0.9375 = 0.0206
Therefore, the change in the distance from the origin increases by approximately 0.02 for each increase in tome by Δt = 0.05 seconds
3. The slope equation is presented as follows;
[tex]Slope = \dfrac{y_2 - y_1 }{x_2 - x_1}[/tex]
The speed of the car is given by the slope of the distance time graph, where;
The horizontal variable, x, is the time, t (x = t)
The vertical variable, y, is the position, x (y = x)
Based on the given assignment of the variables to the x, and y, variables, we have;
[tex]Slope = Speed = \dfrac{y_2 - y_1 }{x_2 - x_1} = \dfrac{x_2 -x_1}{t_2 - t_1} = \mathbf{\dfrac{Final \ position - Initial \ position }{Final \ time - Initial \ time}}[/tex]
Plugging in the values in the table, we have;
[tex]Speed = \dfrac{Final \ position - Initial \ position }{Final \ time - Initial \ time} = \mathbf{\dfrac{0.9759 - 0.8963 }{2.4 - 2.2}} = 0.398[/tex]
The speed of the car = 0.398
Learn more about distance time graph here:
https://brainly.com/question/11755354
https://brainly.com/question/17457755
urgent!!!
factor affecting for the depth which is exerted by the foot print of a bull and a man with same masses on a sand floor is,
1.The pressure exerted by the foot of bull is low
2.the pressure exerted by the foot of man is high
3.the area wich touches the sand foor human feet is less
4.the area wich touches the sand floor of 4 feet of the bull is less than the man.
please this is urgent....
Answers
The area which touches the sand floor of 4 feet of the bull is less than the man.
because the area of surface of contact is more in bull than in man. More is the area of contact, leads is the force or pressure affected.
which of the following are fundamental unit ?
I.candela
II.ampere
III.mole
IV.all of these
Answers
Answer:
all of these very easy questions
A bicyclist is traveling at +25m/s when he begins to decelerate at -4m/s2. How fast is he traveling after 5 seconds
Answers
Answer:
+5m/s
Explanation:
When doing the math we figure out that e is going to be slowing down at -4m/s² for 5 seconds. In total he is slowing down -20m/s which we take from the total speed of +25m/s to get his current new speed.
Help PLEASE ITS DUE TODAY
Answers
Hi :)
The formula for velocity is
v = displacement / change in time
velocity = 100 m / 4 seconds
velocity = 25 m/s
The formula for velocity is
v = displacement / change in time
velocity = 100 m / 4 seconds
velocity = 25 m/s
đo cường độ dòng điện bằng dụng cụ gì
Answers
Answer:
Explanation:
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how to convert m/s to miles/seconds
Answers
Answer:
Divide by 1609
Explanation:
So to convert from m/s to m/s divide by 1609
what is the density of a 75 g block of wood measuring 12 cm x 8cm x 9cm
Answers
Answer:
density is equal to mass divided by volume (m/v)
volume: 12×8×9=864cm³
75÷864=0.09
Answer: 0.09g/cm³
what is the name of the chart that contain elements?
Answers
Answer:
Element Chart
Explanation:
It is a chart that provides many different elements.
Prove that the acceleration due to gravity is independent to the mass of the falling body.
Answers
Answer:
½mv²=mgh
g=½(V²/h)
Explanation:
When an object is held at a height, it posses gravitational potential energy which is mgh, where m= mass, h=height, g=acceleration due gravity
When the object is dropped, the potential energy will be converted to kinetic energy which is ½mv², where V=velocity at which the object moves.
V=∆h/t, ∆h is change in height with respect to time.
½mv²=mgh
Mass cancel out,
g=v²/2h
This implies that g does not depend or is not affected by mass. Hence heavy object and light object will reach the ground at the same time when dropped from the same height. When air resistance is negligible.
A snail at position 3 cm moves to position 20 cm in 8 seconds
What is it's velocity ?
What is it's displacement ?
Answers
Answer:
no worries
Explanation:
Leave it to me.
Answer:
17 cm
Because the equation you're using is ∆d=df
a car advertisement States that a certain car can accelerate from rest to70km/h in 7seconds find the car's average acceleration
Answers
Answer:
Acceleration is 2.78 m/s²
Explanation:
Since the car is from rest, initial velocity, u is zero.
from first newton's equation of motion:
[tex]{ \bf{v = u + at}} \\ [/tex]
v is final velocity
u is initial velocity
a is acceleration
t is time
70 km/h is (70 × 1000 ÷ 3600) m/s = 19.44 m/s
[tex]{ \sf{19.44 = 0 + (a \times 7)}} \\ { \sf{7a = 19.44 }} \\ { \sf{a = 2.78 \: {ms}^{ - 2} }}[/tex]
write the maximum number of electrons that can be accommodated in the s,p,d,f subshells
Answers
Answer:
S=2,P=6,D=10,F=14. The total number of electrons contained by s,p,d,f subshells is 32
???????.............please help:)
Answers
Answer:
It is:
0.00477
0.00000301
Un alumno menciona que al abrir la ventana de su casa sintió cómo el frío ingresaba a su cuerpo. Menciona cuál es la verdadera razón por la cual el niño tuvo la sensación de frío. *
a) Porque el aire tiene una temperatura menor que la de su cuerpo; por eso se propaga más rápido.
b) Porque la temperatura de su cuerpo, siente el aire frio que entra por la ventana.
c) Porque el calor de su cuerpo se propaga al medio ambiente, al ser la temperatura del niño mayor que la del aire exterior.
d) Porque la temperatura del aire es igual a la temperatura del cuerpo.
Answers
Answer:
My believe the answer is
A.) or B.)
Explanation:
Here is why I think A is the answer.
If we use the process of elimination, it would look like this,
a) Porque el aire tiene una temperatura menor que la de su cuerpo; por eso se propaga más rápido.
This makes sense because we all know in winter the weather is very cold and freezing.
b) Porque la temperatura de su cuerpo, siente el aire frio que entra por la ventana.
I feel like this answer is the question, but it could also be an answer, sorry, I'm a little uncertain.
c) Porque el calor de su cuerpo se propaga al medio ambiente, al ser la temperatura del niño mayor que la del aire exterior.
This answer has nothing to do with the question, plus it is very false, our body heat is not enough to overcome the very cold temperature from outside.
d) Porque la temperatura del aire es igual a la temperatura del cuerpo.
This is false because again our body heat is not even compared to the freezing cold temperatures from the winter.
Well, have a nice rest of the day!ba baiii!
47) Which of the following types of energy is the kind that an object gains when it is raised to a higher point on a
hill than when it started?
A)
B)
Kinetic Energy
Chemical Energy
Mechanical Energy
Gravitational Potential Energy
Answers
Answer:
kinetic
Explanation:
kinetic energy is powered by motion or gravity the steeper the hill is the faster a ball will roll
According to the graph the acceleration of the object is ?
A) Constant
B) decreasing
C) increasing
D) zero
Answers
Answer:
your answer is (B) decreasing
I hope it's helps you
A bullet fired from a pistol travelled 50 metres to the target in 0.08s. What was its speed?
Answers
Its speed is 4m/s
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The acceleration of a particle is given by a = c1 + c2v, where a is in millimeters per second squared, the velocity v is in millimeters per second, and c1 and c2 are constants. If the particle position and velocity at t = 0 are s0 and v0, respectively, determine expressions for the position s of the particle in terms of the velocity v and time t.
Answers
The expression for the position of the particle in terms of velocity and time is given as, s = vt
The given expression:
[tex]a = c_1 + c_2v[/tex]the unit of a = mm/s²the velocity, v = mm/sc₁ and c₂ are constantthe position of the particle at time, t = 0, is s₀ and v₀To find:
The expression for the position s of the particle in terms of the velocity v and time tDetermine the value of the constants from second equation of motion given as:
[tex]s = vt + \frac{1}{2}at^2\\\\substitute \ the \ given \ value \ of \ a\\\\s = vt + \frac{1}{2}(c_1 + c_2v)t^2\\\\s = vt + \frac{1}{2} c_1 t^2 + \frac{1}{2} c_2vt^2\\\\divide \ through\ by \ t^2\\\\\frac{s}{t^2} = \frac{v}{t} + \frac{1}{2} c_1 + \frac{1}{2} c_2v\\\\multiply \ through \ by \ 2\\\\\frac{2s}{t^2} = \frac{2v}{t} + c_1 + c_2v\\\\when \ t = 0\\\\0 = 0 +c_1 + c_2v\\\\c_1 + c_2v = 0\\\\from \ the \ original \ equation;\\\\s = vt + \frac{1}{2} (c_1 + c_2v)t^2\\\\[/tex]
[tex]s = vt + \frac{1}{2}(0)^2\\\\s = vt[/tex]
Thus, the expression for the position of the particle in terms of velocity and time is given as, s = vt
Learn more here: https://brainly.com/question/22935373
5 reasons why people should use electricity wisely
Answers
Answer:
1. heating
2. entertainment
3. cooling
4.educational purpose
5.comfort
A playground merry-go-round spins about its axis with negligible friction. A child moves from the center of the merry-go-round to the rim. For this system, indicate which of the following quantities change.
A. Potential energy
B. Angular momentum
C. Mass
D. Moment of inertia
E. Angular speed
F. Rotational kinetic energy
Answers
Answer:
B
Explanation:
In this process on merry go round there is not any external torque so angular momentum will be conserve. Mass is always conserved.
2. A force of 20N acts on a particle of mass 2 Kg and displaces it by 5m at an angle 30°. What is the work done? a) 40J ) b) 50 J c) 100J
Answers
Mass is not required
Force=F=20NAngle=30°Displacement=s=5m[tex]\\ \rm\longmapsto W=Fscos\Theta[/tex]
[tex]\\ \rm\longmapsto W=20(5)cos30[/tex]
[tex]\\ \rm\longmapsto W=100\times \dfrac{\sqrt{3}}{2}[/tex]
[tex]\\ \rm\longmapsto W=50\sqrt{3}J[/tex]
Answer:
[tex]we \: have \\ w = fs \cos( \alpha ) \\ f = 20n \\ m = 2kg \\ s = 5m \\ \alpha = 30 \\ \\ then \: w = 20 \times 5 \times \cos(30) \\ 100 \cos(30) \\ = 100 \frac{ \sqrt{3} }{2} \\ = 50 \sqrt{3} \\ = 86.6 \: joule\\ thank \: yo[/tex]
A still object has a mass of 25kg, what would be the Weight? What would be the Normal Force?
Answers
[tex]\\ \rm\longmapsto Force=Mass(Acceleration)[/tex]
[tex]\\ \rm\longmapsto Force=25(10)[/tex]
[tex]\\ \rm\longmapsto Force=250N[/tex]
Please answer these, I’m willing to give plenty of points.
Does a person with a family history of a breast cancer have a higher chance of developing breast cancer during her life?
IV:_________
DV:__________
Hypothesis:__________
Does grass grow faster under shade of a tree or in direct sunlight?
IV:_______
DV:_______
Hypothesis:_________
Observation: students do not eat very much of their food in the lunchroom.
Question: will students eat more food in lunch room if more fresh fruit and vegetables are used?
IV:_________
DV:__________
Hypothesis:_______
Observation: my dog won’t stop barking whenever someone rings the doorbell.
Question: will my dog bark less when the doorbell rings if he exercises for an hour everyday?
IV:_____
DV:_______
Hypothesis:________
Create your own question.
Observation:___________
Question:_____________
IV:________
DV:_________
Hypothesis:____________
Please send help before school starts!!!!!
Answers
Answer:
IV family history of breast cancer or not.
DV chance of developing breast cancer. Hypothesis Someone with a family history of breast cancer will have a higher chance of developing it.
IV: Where the grass is placed: tree shade or direct sunlight.
Dv:The grasses growth rate
Hypothesis: Grass will grow faster in direct sunlight as opposed to tree shade
IV: Fresh veggies and fruit or not
Dv: how much the students eat: will they eat more or less?
Hypothesis The students will eat more in the lunchroom when Fresh veggies and fruits are served.
IV: The dog exercise everyday for 1 hour or not.
DV: The dogs barking: less or more.
Hypothesis: The dog will bark less when someone rings the doorbell if he exercises for 1 hour every day.
Explanation:
Observation When I wish my face before bed, I get less breakouts in the morning.
Question Does nightly face washing prevent morning breakouts?
IV Washing face at night or not
Dv How much breakouts in the morning.
Hypothesis Washing your face nightly decreases the occurrence of morning breakouts.
on the way to school the bus speeds from 20 m/s to 36 m/s in 4 seconds. what distance does the bus cover in this time frame
Answers
Answer:
d=s
t
d=36
4
d=10m/s
Explanation:
distance is equal to speed over t therefore 36 divide by 4 is 10
Someone decode this please
My friend sended this he said it was a bit horror but yeah i need help with this
Answers
Answer:
what is it for
Explanation:
Divergent plate boundaries are when plates
collide
move past each other
move apart
Answers
Explanation:
Move past each other.
Have a good day.
The elevators in the John Hancock building in Chicago move 783 ft in 33 s. What is this speed in miles per hour?
Answers
Answer:
16.18 mph
Explanation:
the speed of elevators =
(783×3600)/(33×5280) =
2,818,800/174,240 = 16.18 mph
pls give me an answer
Answers
Answer:
IV what is it's potential energy at the maximum height
Record the length of the line shown in centimeters.
7.30
7.12
7.3
7.28
Please help will be marked most brainlist !!
Answers
Zooming I. On the image the red line is just short of the 3rd line past the 7 so it is not 7.3 but just a little under.
Answer: 7.28
