A car travels first 10 km in 20 minutes and another 10 km in 30 minutes. What is the average speed of the car in m/s?

Answer:

New force = 0.063 N

Explanation:

Given that,

The electric force between two charges is[tex]4.2\times 10^{-2}\ N[/tex]

The formula for the electric force is:

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

If the distance between the charges is doubled, r' = 2r and one of the charges is tripled, q₁' = 2q₁, q₂' = 3q₂

Put all the values,

[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{kq_1q_2}{r^2}}{\dfrac{kq_1'q_2'}{r'^2}}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{q_1\times q_2}{r^2}}{\dfrac{2q_1\times 3q_2}{(2r)^2}}\\\\\dfrac{F}{F'}=\dfrac{4}{6}=\dfrac{2}{3}\\\\F'=\dfrac{3\times 4.2\times 10^{-2}}{2}\\\\F'=0.063\ N[/tex]

So, the new force is 0.063 N.

Answer:

The force becomes 0.0315 N.

Explanation:

Force, F = 4.2 x 10^-2 N

When the distance is doubled, a charge is tripled, Let the force is F'.

The force between the two charges is

[tex]F = \frac{K qq'}{r^2}\\[/tex]

when, q' = 3 q' and r is 2 r so

[tex]F' = \frac{K 3qq'}{4r^2} = \frac{3 F}{4} = \frac {3\times 4.2\times 10^{-2}}{4}=0.0315 N[/tex]

Answer:

Data:

D = 2400 kg/m³

V = 0.20 m³

M = ?

∴ Density = [tex]\frac{Mass}{Volume}[/tex]

2400 kg/ = [tex]\frac{Mass}{0.2 m^{3} }[/tex]

Mass = 2400 kg/m³ × 0.20 m³

Mass = 480 kg (answer)

Answer:

Therefore, the mass of the block is 480 kg.

Answer:

1. 7.5 m

2. towards west side

explanation:

I hope it will help you

Explanation:

→ Volume of cone = πr² × h/3

Here,

→ Volume of cone = π(13)² × 27/3 cm³

→ Volume of cone = 169π × 9 cm³

→ Volume of cone = 1521π cm³

→ Volume of cone = 1521 × 22/7 cm³

→ Volume of cone = 33462/7 cm³

→ Volume of cone = 4780.28 cm³

Answer:

4,778.4 is correct

Explanation:

when you get the answer please tell me

Answer:

Correct option is C it decreases by a factor of 2

Answer: A - it increases by a factor of 4

Explanation:

Ohm's law is V = IR where V = potential difference, I = current, and R = resistance. Assuming that resistance stays constant (since the question mentioned no change in resistance), we only need to look at "V" and "I" in the equation V = IR.

"V" and "I" are directly proportional. In other words, whatever change happens to "V" will also occur to "I". Since "V" increases by a factor of 4, then "I" will also increase by a factor of 4.

You could also approach this problem by plugging in a change of 4 for the potential difference in the equation: V = I*R.

If we plug in 4V for V, we now have:

4V = I*R

Since the left side increases by a factor of 4, then the right side (only looking at current in this case) will also need to increase by a factor of 4 in order to have the right side stay equal to the left. Therefore, current will also increase by a factor of 4.

Answer:

ᴀꜱ ᴡᴀʀᴍ ᴀꜱ ꜱᴜɴ

ᴀꜱ ꜱɪʟʟʏ ᴀꜱ ꜰᴜɴ

ᴀꜱ ᴄᴏʟᴅ ❄️ ᴀꜱ ᴀ ᴛʀᴇᴇ

ᴀꜱ ꜱᴄᴀʀʏ ᴀꜱ ꜱᴇᴀ

ᴀꜱ ʜᴏᴛ ᴀꜱ ꜰɪʀᴇ

ᴀꜱ ᴄᴏʟᴅ ᴀꜱ ɪᴄᴇ

ꜱᴡᴇᴇᴛ ᴀꜱ ꜱᴜɢᴀʀ

ᴀɴᴅ ᴇᴠᴇʀʏᴛʜɪɴɢ ɴɪᴄᴇ

ᴀꜱ ᴏʟᴅ ᴀꜱ ᴛɪᴍᴇ ⌛

ᴀꜱ ꜱᴛʀᴀɪɢʜᴛ ᴀꜱ ʟɪɴᴇ ➖

ᴀꜱ ʀᴏʏᴀʟ ᴀꜱ ᴀ ᴀɴɢᴇʟ☺️

ᴀꜱ ʙᴜᴢᴢᴇᴅ ᴀꜱ ʙᴇᴇ

ᴀꜱ ꜱᴛᴇᴀʟᴛʜ ᴀꜱ ᴛɪɢᴇʀ

ꜱᴍᴏᴏᴛʜ ᴀꜱ ɢʟɪᴅᴇʀ

ᴘᴜʀᴇ ᴀꜱ ʜᴇᴀʀᴛ ❤️

ᴘᴜʀᴇ ᴀꜱ ɪ ᴡᴀɴɴᴀ ʙᴇ

Answer:

m=0.2kg=200g

Explanation:

F=2N, a=10m/s²

F=ma⇒ m=F/a=2/10=0.2kg=200g

Answer:

[tex]\boxed {\boxed {\sf 200 \ grams}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F=m*a[/tex]

The force is 2 Newtons and the acceleration is 10 meters per square second. First, we should convert the units of Newtons to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared. The force of 2 N equals 2 kg*m/s²

Substitute the known values into the formula.

[tex]2 \ kg*m/s^2 = m * 10 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 10 meters were second squared. The inverse of multiplication is division. Divide both sides by 10 m/s².

[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}=\frac{ m* 10 m/s^2}{10 \ m/s^2}[/tex]

[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}= m[/tex]

The units of meters per second squared cancel.

[tex]\frac { 2 \ kg}{10}= m[/tex]

[tex]0.2 \ kg =m[/tex]

Now, we must convert the mass to grams. There are 1000 grams in 1 kilogram. We can multiply the mass by 1000 or set up a ratio.

[tex]0.2 \ kg * \frac{1000 \ g}{1 \ kg}= 0.2 * 1000 \ g = 200 \ g[/tex]

The toy car's mass is 200 grams.

Answer:

Covalent bond.

Explanation:

There are 4 main types of bonds:

Covalent, ionic, metallic, and hydrogen.

Covalent bond: Involves the sharing of pairs of electrons, here the difference between the electronegativity of the atoms is not too large. Covalent bonds usually form an octet of electrons.

Ionic bond: This happens because the electrostatic attraction between the atoms whit very different electronegativities

Hydrogen bond: Electrostatic attractive force between an electronegative atom and a hydrogen atom covalently bonded to another electronegative atom.

Metallic bond: Type of bond that makes the metallic atoms to stay really tightly together. The atoms bond because of the electrostatic atractive force between conduction electrons and positively charged metal ions.

Now, in this case, we have the bond between Nitrogen (electronegativity = 2.0) and Hydrogen (electronegativity = 2.1)

So we can see that:

The elements are not metals, so we can discard metallic bond.

For a hydrogen bond, we need 3 atoms (one of which is hydrogen), here we have two, so we can discard this option.

Ionic bond needs different electronegativities, here the electronegativities are really close together, so the ionic bond can be discarded.

we can conclude that the bond will be a covalent bond.

Explanation:

125 is your answer........

Answer:

1.67 amperes

Explanation:

Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.

Mathematically, Ohm's law is given by the formula;

[tex] V = IR [/tex]  ......equation 1

Where;

Making I the subject of formula, we have;

[tex] I = \frac {V}{R} [/tex]  .....equation 2

Given the following data;

To find the current flowing through the battery, we would use eqn 2;

[tex] I = \frac {10}{6} [/tex]  

Current, I = 1.67 amperes

Answer:

1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds

Explanation:

so it would be 16.6666666667 meters per second

Answer:

False.

Explanation:

Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.

Answer:

Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.FALSE

Answer:

Pemain A

Explanation:

Mengingat data berikut;

Kecepatan pemain A = 12 m/s

Kecepatan pemain B = 36 km/h

Untuk menentukan siapa pelari tercepat di antara dua pemain;

Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.

Jadi, mari kita gunakan pengukuran umum meter per detik.

Konversi:

36 km/h = (36 * 1000)/(60 * 60)

36 km/h = 36000/3600

36 km/h = 10 m/s

Kecepatan pemain B = 10 m/s

Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.

Explanation:

A photodiode or solar cell may be considered as a source of emf, similar to a battery, resulting in an electrical voltage generated by charge separation driven by light rather than chemical reaction. Other devices that produce emf are fuel cells, thermocouples, and thermopiles.

Answer:

2min

Explanation:

i think it will be clear from photo

Answer: The formula for current is charge/time

so here we have to change subject so we are asked to look for time  

Explanation: so it would be T=Q/I

T=4/2

T=2s

hope this helpss

Answer:

An artificial satellites revolves around the earth under the influence of its gravitational force. So it does not require any energy to revolve around energy.

or maybe god:)))(

Answer:

They transform energy

Explanation:

thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy

Answer:

A) 111 N

B) F_net = 0 N

C) 100 N, in the opposite direction of the motion.

D) μ = 0.3274

Explanation:

A) The component of the trunks weight acts parallel to the plane but in the vertical direction and so;

W = Fsin θ

W = 325 sin 20

W = 325 × 0.3420

W ≈ 111 N

B) We are told the trunk is moving with a constant velocity and for this reason the sun of the forces will equal to zero.

Thus; F_net = 0 N

C) Since the kinetic friction force needs to balance the component of the weight, the magnitude is;

F_f = 211 - 111 = 100 N

The direction will be in the opposite direction since it's against the motion.

D) From friction formula, we know that;

F_f = μW cos θ

100 = μ × 325 × cos 20

μ = 100/(325 × cos 20)

μ = 0.3274

Answer:

Answer to the following answer is as follows;

Explanation:

In the northwestern city of Milan, Mussolini formed his nationalist regime in 1919. He organised black-shirted street warriors into teams. His "Blackshirts" raped and expelled socialists and communists from municipal administrations.

The Blackshirts, originally known as the Squadrismo, were formed in 1919 by a group of dissatisfied former soldiers.

Answer:

A. moving with uniform velocity.

Explanation:

Was this hepfull

Answer:

A

Explanation:

Equilibrium is a state in which opposing forces or influences are balanced hence A being correct

Answer:

Acceleration of this electron: [tex]-5.60 \times 10^{15}\; \rm m \cdot s^{-2}[/tex].

Time taken: approximately [tex]9.39 \times 10^{-9}\; \rm s[/tex].

Explanation:

Apply the SUVAT equation that does not involve time:

[tex]v^{2} - u^{2} = 2\, a \, x[/tex].

Equivalently:

[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x}\end{aligned}[/tex].

By this equation, the acceleration of this electron would be:

[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x} \\ &= \frac{(7.72 \times 10^{7}\; \rm m \cdot s^{-1})^{2} - (2.46 \times 10^{7} \; \rm m \cdot s^{-1})^{2}}{2 \times 0.478\; \rm m} \\ &\approx -5.60 \times 10^{15}\; \rm m \cdot s^{-2}\end{aligned}[/tex].

The speed of this electron has changed from [tex]u = 7.72 \times 10^{7}\; \rm m\cdot s^{-1}[/tex] to [tex]v = 2.46 \times 10^{7}\; \rm m \cdot s^{-1}[/tex]. Calculate the time required to achieve this change at a rate of [tex]a \approx -5.60 \times 10^{15}\; \rm m\cdot s^{-2}[/tex]:

[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{2.46\times 10^{7}\; \rm m \cdot s^{-1} - 7.72 \times 10^{7}\; \rm m\cdot s^{-1}}{-5.60 \times 10^{15}\; \rm m\cdot s^{-2}} \\ &\approx 9.39 \times 10^{-9}\; \rm s\end{aligned}[/tex].

Answer:

B

Explanation:

According to boyle's law for a gas the pressure and volume are inversely proportional.this simply means when one increases the other one reduces and when the other one reduces the other increases.so in this case the volume increased to twice it original amount meaning the pressure will reduce to half the volume.

I hope this helps

Answer:

normal force

tension force

and other example of force

Answer:

Use the formula ∆H = m x s x ∆T to solve.

Explanation:

Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.

Answer:

30.5mm

Explanation:

There are 300 pages, so to find the number of pages we do 0.1mm*300 to get 30mm. There are two covers in the book (the front and the back). 0.25mm*2 = 0.5mm. To determine the total thickness of the book we do 30mm+0.5mm to get a total of 30.5mm

Your answer is 30.5mm.

Answer:

15.5mm

Explanation:

there are 150 pages(one page has 2 sides so 300/2 = 150) and 2 covers

page's thickness is 0.1mm, cover's thickness is 0.25

so books thickness = 150*0.1+0.25*2 = 15.5mm

What is the maximum height the ball will reach in the air?

Kinematics equation used:

We're given that the initial velocity is 12.0 m/s in the y-direction. At the maximum height, the vertical velocity of the ball will be 0 m/s, otherwise it would not be at maximum height. This is our final velocity.

The only acceleration in the system is acceleration due to gravity, which is approximately [tex]9.8\:\mathrm{ m/s^2}[/tex]. However, the acceleration is acting down, whereas the ball is moving up. To express its direction, acceleration should be plugged in as [tex]-9.8\:\mathrm{m/s^2}[/tex]. We have three variables, and we are solving for the fourth, which is distance travelled. This will be the maximum height of the ball.

Substitute [tex]v_i=12[/tex], [tex]v_f=0[/tex], [tex]a=-9.8[/tex] to solve for [tex]d[/tex]:

[tex]0^2=12^2+2(-9.8)(d),\\0=144-19.6d,\\-19.6d=-144,\\d=\frac{-144}{-19.6}=7.34693877551\approx \boxed{7.35\text{ m}}[/tex]

What is the velocity of the ball when it hits the ground?

This question tests a physics concept rather than a physics formula. The vertical velocity of the ball when it hits the ground is equal in magnitude but opposite in direction to the ball's initial vertical velocity. This is because the ball spends equal time travelling to its max height as it does travelling from max height to the ground (ball is accelerating from initial velocity to 0 and then from 0 to some velocity over the same distance and time). Since the ball has an initial vertical velocity of +12.0 m/s, its velocity when it hits the ground will be [tex]\boxed{-12.0\text{ m/s}}[/tex]. (The negative sign represents the direction. Because velocity is a vector, it is required.)

**Since my initial answer exceeds the character limit, I've attached the first question to Part B as an image. Please refer to the attached image for the answer and explanation to the first question of Part B. Apologies for the inconvenience.**

What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).

This question uses a similar concept as the second question of Part A. The vertical velocity of the ball at launch is equal in magnitude but opposite in direction to the ball's final velocity. The horizontal component is equal in both magnitude and direction throughout the entire launch, since there are no horizontal forces acting on the system. Therefore, the angle below the horizontal of the ball's velocity when it hits the ground is equal to the angle of the ball to the horizontal at launch.

To find this, we need to use basic trigonometry for a right triangle. In any right triangle, the tangent/tan of an angle is equal to its opposite side divided by its adjacent side.

Let the angle to the horizontal at launch be [tex]\theta[/tex]. The angle's opposite side is represented by the vertical velocity at launch (12.0 m/s) and the angle's adjacent side is represented by the horizontal velocity at launch (2.3 m/s). Therefore, we have the following equation:

[tex]\tan \theta=\frac{12.0\text{m/s}}{2.3\text{ m/s}}[/tex]

Take the inverse tangent of both sides:

[tex]\arctan (\tan \theta)=\arctan (\frac{12.0}{2.3})[/tex]

Simplify using [tex]\arctan(\tan \theta)=\theta \text{ for }\theta \in (-90^{\circ}, 90^{\circ})[/tex]:

[tex]\theta=\arctan(\frac{12.3}{2.3}),\\\theta =79.14989537\approx \boxed{79.15^{\circ}}[/tex]

We can express our answer by saying that the direction of the velocity of the ball when it hits the ground is [tex]\boxed{\text{approximately }79.15^{\circ} \text{ below the horizontal}}[/tex] or [tex]\boxed{\text{approximately }-79.15^{\circ} \text{ to the horizontal}}[/tex].

Explanation:

since both the teammates are of the same height, their height won't matter. Because now the basketball won't cover any vertical distance.

We have to calculate its range the horizontal distance covered by it when tossed from one teammate to the other.

range can be calculated by the formula :-

[tex] \boxed{\mathfrak{range = \frac{ u {}^{2} \sin 2\theta }{g} }} [/tex]

u is the velocity during its take off and [tex]\theta[/tex] is the angle at which its thrown

Given that

calculating range using the above formula

[tex] = \frac{ {8}^{2} \sin2(40) }{10} [/tex]

[tex] = \frac{64 \times \sin(80) }{10} [/tex]

value of sin 80 = 0. 985

[tex] = \frac{64 \times 0.985}{10} [/tex]

[tex] = \frac{63.027}{10} [/tex]

[tex] = 6.3027[/tex]

Hence,

[tex] \mathfrak { \blue{the \: teammate \: is \: \red{\underline{6.3027 \: meters} }\: away } } [/tex]