A car is negotiating a flat curve of radius of 50.0 m with a speed of 20.0 m/s. The centripetal force provided by friction is 1.20 x 10^4 N. What is the mass of the car? (1,500 kg)

Answer:

117.72 N

Explanation:

The given parameters are;

The mass m₁ = 2.0 × 10³ kg

The mass m₂ = 4.4 × 10² kg

The mass of the man, m₃ = 6.0 × 10 kg

The condition of the interaction of the surfaces = Frictionless surfaces

The

The tension in the string = The downward force = The weight of (m₂ + m₃) = (m₂ + m₃) × g

Let a represent the acceleration of the connected masses due to the weight of m₂, and m₃, we have;

(m₁ + m₂ + m₃) × a = (m₂ + m₃) × g

∴ a = (m₂ + m₃) × g/(m₁ + m₂ + m₃)

Which gives;

a = (4.4 × 10²+ 6.0 × 10) × 9.81/(2.0 × 10³+ 4.4 × 10²+ 6.0 × 10) = 1.962

The downward acceleration, a = 1.962 m/s²

The apparent weight of the man = The mass of the man, m₃ × The acceleration, a

∴ The apparent weight of the man = 6.0×10 kg ×1.962 m/s² = 117.72 N

Answer:

a) the other components are zero, in the direction of one of the coordinate axes

b) the magnitude is less than the value of one of its components, it must occur when the vector is in some arbitrary direction

9) constant velocity the acceleration must necessarily be zero,

constant speed  can be accelerated since it may be changing the direction of the velocity vector

Explanation:

Vectors are quantities that have modulo (scalar) direction and sense.

a)  If in a vector its magnitude is equal to one d its components implies that the other components are zero, therefore the vector must be in the direction of one of the coordinate axes

b) if the magnitude is less than the value of one of its components, it must occur when the vector is in some arbitrary direction, other than the direction of the axes, that is

          R² = x² + y²

where R is the magnitude of the vector e x, and are the components

9) When a particle has a constant velocity, the acceleration must necessarily be zero,

         v = vo + a t

The bold letters indicate vectors If a = 0 implies that v = vo

If a particle has constant speed it can be accelerated since it may be changing the direction of the velocity vector, this type of acceleration has the name of centripetal acceleration

Explanation:

The change in momentum from an force within the system.

Answer:

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Explanation:

jdjdjdjdjfjofkd ruudoeksowkosksd and nkdeondjvndkxnfuvjfk

Answer:

La columna de aceite tendría una altura de 11,613 metros.

Explanation:

El modelo de Torricelli basa el cálculo de la presión atmosférica mediante el concepto de presión hidrostática, en donde la densidad del fluido ([tex]\rho[/tex]), en kilogramos por metro cúbico, es inversamente proporcional a la altura de la columna ([tex]h[/tex]), en metros, para una igual presión atmosférica ([tex]P[/tex]), en atmósferas. Entonces, podemos estimar la altura de la columna mediante el siguiente modelo:

[tex]\rho_{Hg}\cdot h_{Hg} = \rho_{o}\cdot h_{o}[/tex] (1)

Donde:

[tex]\rho_{Hg}[/tex] - Densidad del mercurio.

[tex]h_{Hg}[/tex] - Altura de la columna de mercurio.

[tex]\rho_{o}[/tex] - Densidad del aceite.

[tex]h_{o}[/tex] - Altura de la columna del aceite.

Si sabemos que [tex]\rho_{Hg} = 13600\,\frac{kg}{m^{3}}[/tex], [tex]h_{Hg} = 0,760\,m[/tex] y [tex]\rho_{o} = 890\,\frac{kg}{m^{3}}[/tex], entonces la altura de la columna del aceite es:

[tex]h_{o} = \left(\frac{\rho_{Hg}}{rho_{o}} \right)\cdot h_{Hg}[/tex]

[tex]h_{o} = \frac{13600\,\frac{kg}{m^{3}} }{890\,\frac{kg}{m^{3}} }\times (0,760\,m)[/tex]

[tex]h_{o} = 11,613\,m[/tex]

La columna de aceite tendría una altura de 11,613 metros.

Answer: [tex]219.65\ \text{km}[/tex]

Explanation:

Given

Car drives 215 km east and then 45 km North

Displacement is East direction is

[tex]\Rightarrow \vec{r_1}=215\hat{i}[/tex]

Now, the displacement from that to 45 km North is given by

[tex]\Rightarrow \vec{r_{21}}=45\hat{j}[/tex]

Net displacement is [tex]\vec{r_2}[/tex]

[tex]\Rightarrow \vec{r_2}=\vec{r_1}+\vec{r_{21}}\\\Rightarrow \vec{r_2}=215\hat{i}+45\hat{j}[/tex]

Magnitude of the displacement is

 [tex]\Rightarrow \left | r_{2} \right |=\sqrt{\left ( 215 \right )^2+\left ( 45 \right )^2}\\\Rightarrow \left | r_{2} \right |=\sqrt{48250}\\\Rightarrow \left | r_{2} \right |=219.65\ \text{km}[/tex]

Answer:

7.8 N

Explanation:

Applying,

I = Ft................. Eqaution 1

Where I = Impulse on the egg test dummy, F = Force on the egg test dummy during the time interval, t = time interval

make F the subject of the equation

F = I/t.................. Equation 2

From the question,

Given: T = -0.39 N.s, t = 0.050 s

Substitute these vales into equation 2

F = -0.39/0.050

F = -7.8 N

Hence the force that act on the egg test dummy is 7.8 N

Answer:

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=health Is a type of thing that gives employment to the person working in firm

hope u understand

Explanation:

Answer:

2) zero acceleration

Explanation:

Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

Mathematically, the motion of an object is described in terms of time, distance, speed, velocity, position, displacement, acceleration, etc.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

Generally, an object is said to be in equilibrium when neither the energy possessed by the object not state of motion changes with respect to time. Thus, the vector sum of all the forces acting upon an object that's in equilibrium is zero.

In conclusion, an essential characteristic of an object in equilibrium is zero (0) acceleration because there's no change in its velocity with respect to time.

Answer:

B

Explanation:

Stress-strain diagram with 4 materials graphed. The graph with maximum yield strength is B.

Stress is defined as the force applied per unit area of cross-section. It is denoted by Sigma(σ). Its's unit is same as the pressure i.e. N/m².

Considering the stress-strain diagram shown here. Assumed all four material samples denoted as (A-D) were originally the same size and shape.

When a body is stretched by a tensile force, it stretches more and more until it reaches its elastic limit. There comes a point where the body no longer stretches. The change in stress is very less and the stress is greater at the yield point. The strength required up to the yield point is called as the yield strength. The body breaks while forming the neck of the bottle. This strength of any material is known as ultimate stress at break or ultimate tensile strength.

So, the material with the highest yield strength is B.

Thus, the correct option is B.

Learn more about Stress.

https://brainly.com/question/12871096

#SPJ5

Answer:

When fired from (1,3) the rocket will hit the target at (4,0)

When fired from (2, 2.5) the rocket will hit the target at (12,0)

When fired from (2.5, 2.4) the rocket will hit the target at [tex](\frac{35}{2},0)[/tex]

When fired from (4,2.25) the rocket will hit the target at (40,0)

Explanation:

All of the parts of the problem are solved in the same way, so let's start with the first point (1,3).

Let's assume that the rocket's trajectory will be a straight line, so what we need to do here is to find the equation of the line tangent to the trajectory of the airplane and then find the x-intercept of such a line.

In order to find the line tangent to the graph of the trajectory of the airplane, we need to start by finding the derivative of such a function:

[tex]y=2+\frac{1}{x}[/tex]

[tex]y=2+x^{-1}[/tex]

[tex]y'=-x^{-2}[/tex]

[tex]y'=-\frac{1}{x^{2}}[/tex]

so, we can substitute the x-value of the given point into the derivative, in this case x=1, so:

[tex]y'=-\frac{1}{x^{2}}[/tex]

[tex]y'=-\frac{1}{(1)^{2}}[/tex]

m=y'=-1

so we can now use this slope and the point-slope form of the line to find the equation of the line tangent to the trajectory of the airplane so we get:

[tex]y-y_{1}=m(x-x_{1})[/tex]

[tex]y-3=-1(x-1})[/tex]

[tex]y-3=-1x+1[/tex]

[tex]y=-x+1+3[/tex]

[tex]y=-x+4[/tex]

So we can now set y=0 so find the x-coordinate where the rocket hits the x-axis.

[tex]-x+4=0[/tex]

and solve for x

x=4

so, when fired from (1,3) the rocket will hit the target at (4,0)

Now, let's calculate the coordinates where the rocket will hit the target if fired from (2, 2.5)

so, we can substitute the x-value of the given point into the derivative, in this case x=2, so:

[tex]y'=-\frac{1}{x^{2}}[/tex]

[tex]y'=-\frac{1}{(2)^{2}}[/tex]

[tex]m=y'=-\frac{1}{4}[/tex]

so we can now use this slope and the point-slope form of the line to find the equation of the line tangent to the trajectory of the airplane so we get:

[tex]y-y_{1}=m(x-x_{1})[/tex]

[tex]y-2.5=-\frac{1}{4}(x-2})[/tex]

[tex]y-2.5=-\frac{1}{4}x+\frac{1}{2}[/tex]

[tex]y=-\frac{1}{4}x+\frac{1}{2}+\frac{5}{2}[/tex]

[tex]y=-\frac{1}{4}x+3[/tex]

So we can now set y=0 so find the x-coordinate where the rocket hits the x-axis.

[tex]-\frac{1}{4}x+3=0[/tex]

and solve for x

x=12

so, when fired from (2, 2.5) the rocket will hit the target at (12,0)

Now, let's calculate the coordinates where the rocket will hit the target if fired from (2.5, 2.4)

so, we can substitute the x-value of the given point into the derivative, in this case x=2.5, so:

[tex]y'=-\frac{1}{x^{2}}[/tex]

[tex]y'=-\frac{1}{(2.5)^{2}}[/tex]

[tex]m=y'=-\frac{4}{25}[/tex]

so we can now use this slope and the point-slope form of the line to find the equation of the line tangent to the trajectory of the airplane so we get:

[tex]y-y_{1}=m(x-x_{1})[/tex]

[tex]y-2.4=-\frac{4}{25}(x-2.5})[/tex]

[tex]y-2.4=-\frac{4}{25}x+\frac{2}{5}[/tex]

[tex]y=-\frac{4}{25}x+\frac{2}{5}+2.4[/tex]

[tex]y=-\frac{4}{25}x+\frac{14}{5}[/tex]

So we can now set y=0 so find the x-coordinate where the rocket hits the x-axis.

[tex]-\frac{4}{25}x+\frac{14}{5}=0[/tex]

and solve for x

[tex]x=\frac{35}{20}[/tex]

so, when fired from (2.5, 2.4) the rocket will hit the target at [tex](\frac{35}{2},0)[/tex]

Now, let's calculate the coordinates where the rocket will hit the target if fired from (4, 2.25)

so, we can substitute the x-value of the given point into the derivative, in this case x=4, so:

[tex]y'=-\frac{1}{x^{2}}[/tex]

[tex]y'=-\frac{1}{(4)^{2}}[/tex]

[tex]m=y'=-\frac{1}{16}[/tex]

so we can now use this slope and the point-slope form of the line to find the equation of the line tangent to the trajectory of the airplane so we get:

[tex]y-y_{1}=m(x-x_{1})[/tex]

[tex]y-2.25=-\frac{1}{16}(x-4})[/tex]

[tex]y-2.25=-\frac{1}{16}x+\frac{1}{4}[/tex]

[tex]y=-\frac{1}{16}x+\frac{1}{4}+2.25[/tex]

[tex]y=-\frac{1}{16}x+\frac{5}{2}[/tex]

So we can now set y=0 so find the x-coordinate where the rocket hits the x-axis.

[tex]-\frac{1}{16}x+\frac{5}{2}=0[/tex]

and solve for x

[tex]x=40[/tex]

so, when fired from (4,2.25) the rocket will hit the target at (40,0)

I uploaded a graph that represents each case.

Answer:

Explanation:

(a)

In event A , one has to walk along diameter of the field from X to Y.

In this event , walk is along a straight line , both displacement and distance covered will be same.

Distance = displacement = 1 km.

option ii is correct .

(b )

radius of circular track r = 0.5 km

length of track = circumference = 2π r

= 2 x 3.14 x .5 = 3.14 km

Length of running in event B is 15.7 km

No of rounds = 15.7 / 3.14 = 5

option iii is correct .

( c )

speed = length of race / time

time = length of race / speed

= 15. 7 km / 3.14 km /h

= 5 hours .

option iv is correct option.

(d)

In event C , length of race is 25.12 km

speed = length of race / time taken

= 25.12 km  / 4 hour

= 6.28 km/h .

Option i is correct.

Answer:

(a) (ii)

(b) (iv)

(c) (i)

(d) (i)

Explanation:

diameter, XY = 1 km

Event A- Fast walking along the diameter of the field.

Event B- A 15.7 km running race along the circular track.

Event C- A 25.12 km cycling race along the circular track.

(a) When athletes walked from X to Y , the distance is equal to the displacement which is equal to the diameter = 1 km.  

Option (ii).

(b) distance = 15.7 km

distance traveled by one round = 3.14 x 1 = 3.14 km

So, the number of round complete in B = 1.57/3.14 = 0.5

option (iv).

(c)If Pihu ran at an average speed of 3.14 km/h during Event B, then she would finish the race in

time, t = 1.57/3.14 = 0.5 hours

option (i)

(d) What should the average speed of cyclist Yousef be, so that he can complete Event C in 4hours?

Distance = 25.12 km

time , t = 4 hours

Speed = 25.12 / 4 = 6.28 km/h

Option (i)

Answer:

here it is...

Explanation:

The friction between the two surfaces is because of the interlocking of the irregularities of the two surfaces. During sliding, contact points do not get enough time to get interlocked properly. Therefore, less friction. ... This explains why sliding friction is less than static friction.

Answer:

1. These lines are addressed to Duke.

2. These lines show that Shylock is not willing to forgive the debt a merchant owes him, nor is he willing to justify why he demands that debt be paid, even if it seems cruel.

3. He swore by the Holy Sabbath, which is a holy day for him, who is a Jew. He swore he would get the debt money or a piece of the debtor's flesh.

Explanation:

The lines shown in the question above refer to "The Merchant of Venice" written by Shakespeare. In this story we are introduced to Antonio, a commercial who is very prejudiced against Jews, but when he needs money, he borrows from another merchant, Shylock, who is Jewish. Shylock agrees to lend money to Antonio, but determines the date that this money must be returned, in addition, Shylock states that he will lend the money if Antonio agrees that if this money is not paid by the specified date, Antonio will have to pay with half a kilo of flesh from his own body. Antonio agrees, but doesn't pay the money so Shylock goes after the flesh of Antonio's body and Duke tries to intervene because he thinks this is too cruel. At this point, Shylock speaks the lines shown in the question above, showing that he is not willing to change his mind.

Answer:

155mEq/L Cl-

Explanation:

A Ringer’s solution contains the following concentrations of cations: 146 mEq/L of Na+, 5 mEq/L of K+, and 4 mEq/L of Ca2+.

As Cl- is the only counterion of those cations:

For Na, the molecule is NaCl and the mEq/L of Cl- = mEq of Na+. The Cl- of the first ion is 146mEq/L Cl-

For K+, The molecule is KCl, mEq Cl- = 5mEq/L Cl-

And, for Ca2+, The molecule is CaCl2 but the equivalents of Ca2+ = Equivalents of Cl- = 4mEq/L Cl-

The total concentration of Cl- are:

146 + 5 + 4 =

Answer:

Say the full question I can't understand what it is

Answer:

a ) Its wavelength decreases

Explanation:

When a ray enters into air from glass slab its wavelength decreases.

Answer:

If 2 objects have the same mass, then which object has a larger volume will have a smaller density

Explanation:

Because density is the object's mass divided by volume

Group of answer choices.

A. Energy is absorbed in the reaction.

B. Energy is released in the reaction.

C. There is no transfer of energy in the reaction.

D. Energy is lost in the reaction.

Answer:

B. Energy is released in the reaction.

Explanation:

A chemical reaction can be defined as a chemical process which typically involves the transformation or rearrangement of the atomic, ionic or molecular structure of an element through the breakdown and formation of chemical bonds to produce a new compound or substance.

Basically, there are two (2) main types of chemical reaction and these include;

I. Endothermic reaction: it's a chemical reaction in which heat is absorbed

II. Exothermic reaction: it's a chemical reaction in which heat is liberated into the environment.

In Chemistry, all chemical equation must follow or be in accordance with the Law of Conservation of Mass, which states that mass can neither be created nor destroyed by either a physical transformation or a chemical reaction but transformed from one form to another in an isolated (closed) system.

Generally, energy is released in a chemical reaction when the energy of the products is less than the energy of the reactants and it is referred to as an exothermic reaction.

However, when the energy of the products is greater than the energy of the reactants, energy is absorbed and it is referred to as an endothermic reaction.

Answer:

Explanation:

The negative only matters reallly if you are dealing with a 2d system. I could even define down as positive and up as negative. However, usually you are taught that down is negative. It really doesn't matter because a force is a force. It is only given a direction relative to another force or vector direction.

Answer:

A. So that you can see if the answer to a problem makes physical sense.

Explanation:

Science can be defined as a branch of intellectual and practical study which systematically observe a body of fact in relation to the structure and behavior of non-living and living organisms (animals, plants and humans) in the natural world through experiments.

An experiment can be defined as an investigation which typically involves the process of manipulating an independent variable (the cause) in order to be able to determine or measure the dependent variable (the effect).

This ultimately implies that, an experiment can be used by scientists to show or demonstrate how a condition causes or gives rise to another i.e cause and effect, influence, behavior, etc in a sample.

Measurements refers to the process which typically involves the process of identifying and determining the dimensions of a physical object. The dimensions include important parameters such as width, height, length, area, volume, circumference etc.

In Science, making rough estimates of physical quantities is useful so that you can see if the answer to a problem makes physical sense.

For example, you could make a rough estimate of a storage tank and deductively determine whether or not it's in tandem with its physical size in reality.

Answer:

Explanation:

W = FΔx so filling in:

12 = F(30) so

F = .4N

Answer:

499.73 m

Explanation:

We'll begin by calculating the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 25 °C

Final temperature (T₂) = –20° C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = –20 – 25

ΔT = –45 °C

Finally, we shall determine the length on a cold day at –20° C. This can be obtained as follow:

Length at 25°C (L₁) = 500 m

Coefficient of linear expansion (α) = 12×10¯⁶ /°C

Change in temperature (ΔT) = –45 °C

Length at –20 °C (L₂) =?

α = L₂ – L₁ / L₁ΔT

12×10¯⁶ = L₂ – 500 / (500 × –45)

12×10¯⁶ = L₂ – 500 / –22500

Cross multiply

L₂ – 500 = 12×10¯⁶ × –22500

L₂ – 500 = –0.27

Collect like terms

L₂ = –0.27 + 500

L₂ = 499.73 m

Therefore, the length on a cold day at –20° C is 499.73 m.

C. The Uniformity of Cosmic Background Radiation

Answer:

Pemain A

Explanation:

Mengingat data berikut;

Kecepatan pemain A = 12 m/s

Kecepatan pemain B = 36 km/h

Untuk menentukan siapa pelari tercepat di antara dua pemain;

Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.

Jadi, mari kita gunakan pengukuran umum meter per detik.

Konversi:

36 km/h = (36 * 1000)/(60 * 60)

36 km/h = 36000/3600

36 km/h = 10 m/s

Kecepatan pemain B = 10 m/s

Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.

Answer:

physical measurement comprises the measurement of objects, things, etc. and is concerned with the measurement of height, weight, length, size, volume etc.

Answer:

Cannot be determined from the given information

Explanation:

Given the following data;

Velocity = 24 m/s

Period = 3 seconds

To find the amplitude of the wave;

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

x is displacement of the wave measured in meters.

A is the amplitude.

ω is the angular frequency measured in rad/s.

t is the time period measured in seconds.

ϕ is the phase angle.

Hence, the information provided in this exercise isn't sufficient to find the amplitude of the waveform.

However, the given parameters can be used to calculate the frequency and wavelength of the wave.