A can do a piece of work in 10 days and B in 12 days.
With the help of C they can finish the work in 4 days. How
long will C take to do it alone?
a) 12 days b) 15 days c) 18 days d) 20 days​

Answers

Answer 1

Answer:

B. 15 days

Step-by-step explanation:

A=10=1/10 of the job

B=12=1/12 of the job

A+B+C=4=1/4 of the job

A+B

=1/10 + 1/12

=10+12/120

=22/120

=11/60

(A+B+C) - (A+B)

=1/4 - 11/60

=5 - 11/60

=4/60

=1/15

It would take C alone 15 days to finish the job


Related Questions

Write a function rule for the table
х
f(x)
0
3
1
4
2
5
3
6

Answers

Answer:

  f(x) = x +3

Step-by-step explanation:

The first differences for adjacent x-values are all 1, so this is a linear function. Because those differences are all 1, it is a linear function with a slope of 1. We observe that f(0) = 3, so that is the y-intercept.

__

The slope-intercept form of a linear function is ...

  y = mx + b . . . . . where m is the slope (1) and b is the y-intercept (3).

A suitable function rule is ...

  f(x) = x +3

Need to find the Domain and Range

Answers

Answer:

D: {x∈R | -2 ≤ x ≤ 2 }

R: {y∈R | 0 ≤ y ≤ 4 }

Step-by-step explanation:

The domain ranges between -2 and 2

The range ranges between 0 and 4

The expression (x-6)^2 is equivalent to

Answers

Answer:

2−12x+36

Step-by-step explanation:

Answer:

(x-6)² = (x-6)(x-6) = x² - 12x + 36

Step-by-step explanation:

An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each other. One airplane is 150 miles from the point and has a speed of 300 miles per hour. The other is 200 miles from the point and has a speed of 400 miles per hour.(a) At what rate is the distances between the planes decreasing?(b) How much time does the air traffic controller have to get one of the planes on a different flight path?

Answers

Answer:

The answer to this question can be defined as follows:

In option A, the answer is "- 357.14 miles per hour".  

In option B, the answer is "-0.98".

Step-by-step explanation:

Given:

[tex]\frac{dx}{dt} =- 300 \text{ miles per hour}[/tex]

[tex]\frac{dy}{dt} =- 400 \text{ miles per hour}[/tex]

find:

[tex]\frac{ds}{dt} =?[/tex] when

[tex]x= 150 \\y= 200\\s=x+y\\\\[/tex]

  [tex]= 150+200 \\\\=350[/tex]

[tex]\to s^2=x^2+y^2\\[/tex]

differentiate the above value:

[tex]\to 2s\frac{ds}{dt}= 2x \frac{dx}{dt}+2y \frac{dy}{dt}[/tex]

[tex]\to 2s\frac{ds}{dt}= 2(x \frac{dx}{dt}+y \frac{dy}{dt})\\\\\to \frac{ds}{dt}= \frac{(x \frac{dx}{dt}+y \frac{dy}{dt})}{s}\\\\[/tex]

        [tex]= \frac{(150 \times -300 +200 \times -400 )}{350}\\\\= \frac{-45000+ (-80000) }{350}\\\\= \frac{- 125000 }{350}\\\\= - 357.14 \ \text{miles per hour}[/tex]

In option B:

[tex]\to d=rt\\\\ \to t= \frac{d}{r}[/tex]

[tex]\to \ \ d= 350 \ \ \ \ \ \ r= -357.14\\[/tex]

[tex]\to t= - \frac{350}{357.14}\\\\\to t= - 0.98[/tex]

Two shaded identical rectangular decorative tiles are first placed (one each) at the top and at the base of a door frame for a hobbit's house, as shown in Figure 1. The distance from W to H is 45 inches. Then the same two tiles are rearranged at the top and at the base of the door frame, as shown in Figure 2. The distance from Y to Z is 37 inches. What is the height of the door frame, in inches?

Answers

Answer:

41 inches

Step-by-step explanation:

Let the point at the top of the door on the left be x

Wx + xH = 45

Let the point at the top of the door  on the right be c

Yc + cZ = 37

We know the door is

xH +  plus the width of the tile

The width of the tile is Yc

xH + Yc

On the right door

cZ +  the height of the tile

cZ + Wx

Add the two doors together

xH + Yc + cZ + Wx = 2 times the height of the door

Rewriting

xH +  Wx +  Yc + cZ = 2 times the height of the door

45+ 37 = 2 times the door height

82 = 2 times the door height

Divide by 2

41 = door height

when the point ( k, 3 ) lies on each of these lines, find the value of k y= 3x+1 , y= 4x-2 , y=1/2x - 1 and 2x+3y=4

Answers

Answer:

see explanation

Step-by-step explanation:

Since (k, 3) lies on each of the lines, the point satisfies the equations.

Substitute x = k, y = 3 into each and solve for k

y = 3x + 1

3 = 3k + 1 ( subtract 1 from both sides )

2 = 3k ( divide both sides by 3 )

k = [tex]\frac{2}{3}[/tex]

-------------------------------------------------------

y = 4x - 2

3 = 4k - 2 ( add 2 to both sides )

5 = 4k ( divide both sides by 4 )

k = [tex]\frac{5}{4}[/tex]

--------------------------------------------------------

y = [tex]\frac{1}{2}[/tex] x

3 = [tex]\frac{1}{2}[/tex] k ( multiply both sides by 2 to clear the fraction )

k = 6

---------------------------------------------------------

2x + 3y = 4

2k + 3(3) = 4

2k + 9 = 4 ( subtract 9 from both sides )

2k = - 5 ( divide both sides by 2 )

k = - [tex]\frac{5}{2}[/tex]

Parabolic microphones are used for field audio during sports events. The microphones are manufactured such that the equation of their cross section is x=1/34y^2, in inches. The feedhorn part of the microphone is located at the focus

a. How far is the feedhorn from the edge of the parabolic surface of the microphone?

b. What is the diameter of the microphone? Explain your reasoning

c. If the diameter is increased by 5 inches, what is the new equation of the cross section of the microphone?​

Answers

Answer:

a. 8.5 in.

b. 34 in

c. x = 1/39 x^2.

Step-by-step explanation:

Part a.

x = 1/34 y^2

y^2 = 34x

Comparing with y^2 = 4px where p is the focus:

4p = 34

p = 8.5 in.

Part b.

The diameter = 4p = 34 in.

Part c.

Diameter = 4p = 34 + 5 = 39 in

The new equation is x = 1/39 x^2.

The marketing department at Quality Home Improvement Center (QHIC) uses simple linear regression analysis to predict home upkeep expenditure on the basis of home value. Predictions of home upkeep expenditures are used to help determine which homes should be sent advertising brochures promoting QHIC's products and services.

Answers

Full question :

The Tasty Sub Shop Case:

A business entrepreneur uses simple linear regression analysis to predict the yearly revenue for a potential restaurant site on the basis of the number of residents living near the site. The entrepreneur then uses the prediction to assess the profitability of the potential restaurant site.

And

The QHIC Case:

The marketing department at Quality Home Improvement Center (QHIC) uses simple linear regression analysis to predict home upkeep expenditure on the basis of home value. Predictions of home upkeep expenditures are used to help determine which homes should be sent advertising brochures promoting QHIC’s products and services.

Discuss the difference in the type of prediction in both cases and provide rational of the reasons that these predictions were used.

Answer and explanation:

In the first case, The Tasty Sub Shop Case, the entrepreneur aims to utlilize the predicted values from his regression analysis in ascertaining profit of his potential business. He does this using the values from number of residents in the area(independent variables) to predict the revenue for his business(dependent variables). His predictions using the number of residents in the area are largely because the residents in the area are his target consumers and are the ones to buy food from his restaurant and increase his revenue.

In the other case, the marketing department in QHIC utilizes the predicted values in determining their customers who need to be aware of their products. They get the predicted values(home upkeep expenditure and dependent variable) by plotting their relationship with home value(independent variable) and then use predicted values of home upkeep expenditures in determining their customers who they will market their products to. They do this because predicting home upkeep expenditures will enable them determine what homes can afford or will need their products and services.

one utilizes his predictions at ascertaining profit while the other uses his predictions in determining potential customer base to market products to. The first case is making a revenue/ profitability prediction while the other is making a market prediction


2x + 3y = 40
5x + 2y = 30​

Answers

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A) Let's solve for x.  [tex]2x + 3y = 40[/tex]

Step 1: Add -3y to both sides.

[tex]2x + 3y + -3y = 40 + -3y[/tex]

[tex]2x = -3y + 40[/tex]

Step 2: Divide both sides by 2.

[tex]\frac{2x}{2} = \frac{-3y + 40}{2}[/tex]

[tex]x = \frac{-3}{2} y + 20[/tex]

Answer : [tex]\frac{-3}{2} y + 20[/tex]

~~~~~~~~~~~~~~~~~

B) Let's solve for x. [tex]5x + 2y = 30[/tex]

Step 1: Add -2y to both sides.

[tex]5x + 2y + -2y = 30 + -2y[/tex]

[tex]5x = -2y + 30[/tex]

Step 2: Divide both sides by 5.

[tex]\frac{5x}{5} = \frac{-2y + 30}{5}[/tex]

[tex]x = \frac{-2}{5} y + 6[/tex]

Answer : [tex]\frac{-2}{5} y + 6[/tex]

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Hope this helped you.

Could you maybe give brainliest..?

❀*May*❀

I think I found it
X=10/11
Y=140/11

For all x, 5-3(x-4)=?

Answers

Answer:

the answer that i find is 17-3x

Find the missing the side of the triangle A. 130−−−√ m B. 179−−−√ m C. 42–√ m D. 211−−−√ m

Answers

Answer:

The answer is option A

Step-by-step explanation:

Since the triangle is a right angled triangle we can use the Pythagoras theorem to find the missing side

Using the Pythagoras theorem

That's

[tex] {a}^{2} = {b}^{2} + {c}^{2} [/tex]

From the question

x is the hypotenuse or the longest side of the triangle

Substituting the values into the above formula we have

[tex] {x}^{2} = {9}^{2} + {7}^{2} [/tex]

[tex] {x}^{2} = 81 + 49[/tex]

[tex] {x}^{2} = 130[/tex]

Find the square root of both sides

We have the final answer as

x = √130 m

Hope this helps you

A movie theater conducted a survey to see what customers preferred at the concession stand. The theater asked every fifth person who entered the movie theater every Friday for a month what his or her favorite movie snack was. Were the results of the survey valid? A. No, because the theater did not survey everyone in the theater. B. Yes, because the theater only surveyed children. C. Yes, because the theater surveyed a random sample. D. No, because the theater did not use a random sample.

Answers

Answer:

A) No because the theater did not survey everyone in the theater.

Answer:

Yes, because the theater surveyed a random sample.

Step-by-step explanation:

The survey is valid because there was a random sample. They surveyed every fifth person, so there was a variety of age groups, genders, and preferences included in the sample. Therefore, the correct answer is yes, because the theater surveyed a random sample.

Write each expression using a positive exponent. ("/" means division)("^" means to the power of) 9^-4

Answers

Answer:

[tex]\frac{1}{9^4}[/tex].

Step-by-step explanation:

[tex]9^{-4}[/tex]

= [tex]\frac{1}{9^4}[/tex]

= [tex]\frac{1}{9 * 9 * 9 * 9}[/tex]

= [tex]\frac{1}{81 * 81}[/tex]

= [tex]\frac{1}{6561}[/tex]

= 0.0001524157903.

Hope this helps!

What is the volume of this rectangular prism?
3 cm
cm
1
cm

Answers

Answer:

.75cm³

Step-by-step explanation:

To find the volume of a shape like this it is,

base×height×width.

In this case it is .5×.5×3=.75cm³

Answer:

3/4 or 0.75

Step-by-step explanation:

Length times width times height:

1/2 * 1/2 * 3

= 3/4

The ratio of two numbers is 2:3 and the sum of their cubes is 945,what are the two numbers. let the 1st no be=2x and 2nd=3x (2x)^3 + (3x)^3=945

Answers

Answer:

        The first number is 6,  the second number is 9

Step-by-step explanation:

a:b = 2:3

a = 2x    - first number

b = 3x   - second number

a³ + b³  =  945

[tex](2x)^3 + (3x)^3=945\\\\8x^3 +27x^3=945\\\\35x^3 = 945\\\\x^3=945:35\\\\x^3=27\\\\ x^3=3^3\\\\x=3\\\\\\a=2\cdot3 = 6\\\\b=3\cdot3=9[/tex]

What is the answer??

c — 10 ≥ 15

Answers

Answer:

Step-by-step explanation:

c - 10  ≥  15 =

c  ≥ = 15 + 10

c  ≥ = 25

c  = 26 ( or numbers above 26)

If everybody on the team scores 6 points, and the team has a total of 42 points, how many people are on the team? 6 p = 42 7 p = 42 6 + p = 42 42 - p = 6

Answers

Answer: 7 people

Explanation:

6p = 42
P = 42/6
P = 7

If everybody on the team scores 6 points, and the team has a total of 42 points, the people that are on the team are 7 people.

What is addition?

The addition is one of the four basic mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.

The addition is a method of merging items and counting them as a single, large group. In mathematics, addition is the process of joining two or more integers.

The process of adding two or more numbers together to get their sum is known as an addition. The addition is a fundamental arithmetic operation that is used to compute the sum of two or more numbers. For instance, 7

+ 7 = 14.

6p = 42

P = 42/6

P = 7

Therefore, the people that are on the team are 7 people.

To learn more about addition, refer to the link:

https://brainly.com/question/29560851

#SPJ2

The office building is 111ft high. About how tall is this in meters.?

Answers

Answer:

Hey there!

11 meters is about 36 feet tall.

Let me know if this helps :)

Answer:

you answer is :33.8328

Check whether 301 is a term of the list of numbers 5, 11, 17, 23, . . .

Answers

Answer:

not a term

Step-by-step explanation:

There is a common difference between consecutive terms in the sequence, that is

d = 11- 5 = 17 - 11 = 23 - 17 = 6

This indicate the sequence is arithmetic with n th term

[tex]a_{n}[/tex] = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 5 and d = 6, thus

[tex]a_{n}[/tex] = 5 + 6(n - 1) = 5 + 6n - 6 = 6n - 1

Equate this to 301 and solve for n

6n - 1 = 301 ( add 1 to both sides )

6n = 302 ( divide both sides by 6 )

n = 50.333....

Since n is not an integer value then 301 is not a term in this sequence.

According to data from the U.S. Department of Education, the average cost y of tuition and fees at public four-year institutions in year x is approximated by the equation where x = 0 corresponds to 1990. If this model continues to be accurate, during what year will tuition and fees reach $4000?

Answers

Answer:

Graphing Calculator

Step-by-step explanation:

when simplifying the expression y=(2x(x-3)(x-3))/(x-1)(x-3) do all of the x-3 s get cancelled or just one in the numerator and one in the denominator?​

Answers

Answer:

x-3 is cancelled and just one remains in numerator.

One hundred people, ages 11-15, were randomly surveyed to find their opinion of their favorite leisure time activity. Sixty-four percent of them said they liked to spend time watching TV. If there are 1500 students in your school, about how many of them would you predict would enjoy watching t.v. A.2343 B.960 C.640 D.500

Answers

Answer:

If there are 1500 students in your school then 960 students would enjoy watching TV

Step-by-step explanation:

Step 1: We know that 64% of kids aged from 11 to 15 enjoy watching TV and there is 1500 students in your school

Step 2: We now want to find 64% of 1500, we can rewrite 64% as 0.64. We multiple 1500 by 0.64 to find out how many students enjoy watching TV

0.64 x 1500 = # of students who like watching TV

960 = # of students who like watching TV

Therefore out of 1500 students, 960 would enjoy watching TV

Simplify 6 to the second power

Answers

Answer:

36

Step-by-step explanation:

[tex]6^2 =6\times 6\\\\= 36[/tex]

ux=x+y/k, solve for x

Answers

Answer:

x = y/( ku-1)

Step-by-step explanation:

Here in this question, we are asked to solve for x.

we have;

Ux = x+ u/ k

cross multiply;

k * Ux = x + y

kUx = x + y

kUx- x = y

x(KU-1) = y

x = y/( ku-1)

Solve for x : 2^(x-5) . 5^(x-4) = 5​

Answers

Answer:

x = 5

Step-by-step explanation:

Notice that there is also a base 5 on the right hand side of the equation, therefore, let's move [tex]5^{x-4}[/tex] to the right by dividing both sides by it. and then re-writing the right hand side as 5 to a power:

[tex]2^{x-5}\,*\,5^{x-4}=5\\2^{x-5}=5/5^{x-4}\\2^{x-5}=5\,*\,5^{4-x}\\2^{x-5}=5^{5-x}[/tex]

Now apply log to both sides in order to lower the exponents (where the unknown resides):

[tex](x-5)\,log(2)=(5-x)\,log(5)[/tex]

Notice that when x = 5, this equation is true because it makes it the identity: 0 = 0

So, let's now examine what would be the solution of x is different from 5, and we can divide by (x - 5) both sides of the equation:

[tex]log(2)=\frac{5-x}{x-5} \,log(5)\\log(2)=-1\,\,log(5)\\log(2)=-log(5)[/tex]

which is an absurd because log(2) is [tex]\neq[/tex] from log(5)

Therefore our only solution is x=5

Answer:

if decimal  no solution

if multiply x =5

Step-by-step explanation:

If this is a decimal point

2^(x-5) . 5^(x-4) = 5

Rewriting .5 as 2 ^-1

2^(x-5)  2 ^ -1 ^(x-4) = 5

We know that a^ b^c = a^( b*c)

2^(x-5)  2 ^(-1*(x-4)) = 5

2^(x-5)  2 ^(-x+4) = 5

We know a^ b * a^ c = a^ ( b+c)

2^(x-5 +-x+4) = 5

2^(-1) = 5

This is not true so there is no solution

If it is multiply

2^(x-5)  * 5 ^(x-4) = 5

Divide each side by 5

2^(x-5)  * 5 ^(x-4) * 5^-1 = 5/5

We know that a^ b * a^c = a^ ( b+c)

2^(x-5)  * 5 ^(x-4 -1)  = 1

2^(x-5)  * 5 ^(x-5)  = 1

The exponents are the same, so we can multiply the bases

a^b * c*b = (ac) ^b

(2*5) ^ (x-5) = 1

10^ (x-5) = 1

We know that 1 = 10^0

10^ (x-5) = 10 ^0

The bases are the same so the exponents are the same

x-5 = 0

x=5

Simplify the expression a-2b, when a=1.4 - 2x and b=-0.2x + 1.7 *

Answers

Answer:

a-2b= -1.6x-2.0

Step-by-step explanation:

[tex]a=1.4-2x\\b=-0.2x+1.7\\a-2b= (1.4-2x)-2(-0.2x+1.7)\\a-2b= 1.4-2x+0.4x-3.4\\a-2b=-1.6x-2.0\\[/tex]

{By, substituting the values of a and b in a-2b , we can find the value of a-2b}

If a and b are acute angles such that tan (a+b)= 1.73 and tan(a-b) =1/1.73, find a and b

Answers

[tex] \LARGE{ \underline{ \boxed{ \orange{ \rm{Solution:)}}}}}[/tex]

Given,

tan (a + b) = 1.73 [tex]\approx[/tex] √3tan (a - b) = 1 / 1.83 [tex]\approx[/tex] 1 / √3

To find:

Value of a and b in degrees....?

Solution:

☃️ Refer to the trigonometric table....

Then, proceeding

⇛ tan 60 ° = √3

⇛ tan 60° = tan (a + b)

⇛ 60° = a + b

Flipping it,

⇛ a + b = 60° --------(1)

And,

⇛ tan 30° = 1 / √3

⇛ tan 30° = tan (a - b)

⇛ 30° = a - b

Flipping it,

⇛ a - b = 30° ---------(2)

Now adding eq.(1) and eq.(2),

⇛ a + b + a - b = 60° + 30°

⇛ 2a = 90°

⇛ a = 90° / 2

⇛ a = 45°

Putting value of a in eq.(1),

⇛ 45° + b = 60°

⇛ b = 15°

☄ So, Our Required answers:

a = 45°b = 15°

━━━━━━━━━━━━━━━━━━━━

[tex] \frac{ {9x}^{2} - {(x}^{2} - 4) {}^{2} }{4 + 3x - {x}^{2} } [/tex]
pls help me need help asap

Answers

Answer:

[tex] { x^2+3x-4} [/tex]

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

[tex] \frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} } [/tex]

= [tex]\frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}[/tex]

= [tex] \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)} [/tex]

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= [tex] { (x-1)(x+4)} [/tex]

= [tex] { x^2+3x-4} [/tex]

Answer:

The answer is

x² + 3x - 4

Step-by-step explanation:

[tex] \frac{9 {x}^{2} - ( { {x}^{2} - 4})^{2} }{4 + 3x - {x}^{2} } [/tex]

To solve the expression first factorize both the numerator and the denominator

For the numerator

9x² - ( x² - 4)²

Expand the terms in the bracket using the formula

( a - b)² = a² - 2ab + b²

(x² - 4) = x⁴ - 8x² + 16

So we have

9x² - (x⁴ - 8x² + 16)

9x² - x⁴ + 8x² - 16

- x⁴ + 17x² - 16

Factorize

that's

(x² - 16)(-x² + 1)

Using the formula

a² - b² = ( a + b)(a - b)

We have

(x² - 16)(-x² + 1) = (x + 4)(x - 4)( 1 - x)(1 + x)

For the denominator

- x² + 3x + 4

Write 3x as a difference

- x² + 4x - x + 4

Factorize

That's

- ( x - 4)(x + 1)

So we now have

[tex] \frac{(x + 4)(x - 4)( 1 - x)(1 + x)}{ - (x - 4)(x + 1)} [/tex]

Simplify

[tex] \frac{ - (x + 4)(1 - x)(1 + x)}{x + 1} [/tex]

Reduce the expression by x + 1

That's

-( x + 4)( 1 - x)

Multiply the terms

We have the final answer as

x² + 3x - 4

Hope this helps you

Please help me Tramserran mam...​

Answers

Answer:  see proof below

Step-by-step explanation:

Use the following when solving the proof...

Double Angle Identity: cos2A = 1 - 2sin²B

Pythagorean Identity: cos²A + sin²A = 1

note that A can be replaced with B

Proof from LHS → RHS

Given:                            cos²A + sin²A · cos2B

Double Angle Identity: cos²A + sin²A(1 - 2sin²B)

Distribute:                      cos²A + sin²A - 2sin²A·sin²B

Pythagorean Identity:                        1 - 2sin²A·sin²B

Pythagorean Identity:   cos²B + sin²B - 2sin²A·sin²B

Factor:                           cos²A + sin²B(1 - 2sin²A)

Double Angle Identity: cos²B + sin²B · cos2A

cos²B + sin²B · cos2A = cos²B + sin²B · cos2A  [tex]\checkmark[/tex]

the sum of 35 and one fifth part of itself is added to the sum of one seventh of 11 and 8​

Answers

Answer:

313/7

Step-by-step explanation:

Here, we are interested in turning the wordings of the statement to numeric values.

We take it one at a time.

Sum of 35 and 1/5(35) = 35 + 7 = 42

This is added to 1/7(11 + 8)

= 1/7(19) = 19/7

So we have;

42 + 19/7 = (294 + 19)/7 = 313/7

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