Answer:
6s , 60mls
Explanation:
hope this helps love
Answer:
0m/s
Explanation:
When the object strikes the ground, it then becomes in uniform motion and when an object is in uniform motion, the velocity is 0
6. The electric force between two charged objects is influenced by
Answer:
the amount of each charge and the distance between them. ... Coulomb's law states the the electric force between two charges is proportional to the product of the two charges and inversally proportional to the square distance that separates their centers.
State two sources of EMF cell other than the chemical cell
Answers
Explanation:
A photodiode or solar cell may be considered as a source of emf, similar to a battery, resulting in an electrical voltage generated by charge separation driven by light rather than chemical reaction. Other devices that produce emf are fuel cells, thermocouples, and thermopiles.
Calculate the mass in grams of a toy car if a force of 2 N causes it to accelerate by 10 m/s2
Answer:
m=0.2kg=200g
Explanation:
F=2N, a=10m/s²
F=ma⇒ m=F/a=2/10=0.2kg=200g
Answer:
[tex]\boxed {\boxed {\sf 200 \ grams}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F=m*a[/tex]
The force is 2 Newtons and the acceleration is 10 meters per square second. First, we should convert the units of Newtons to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared. The force of 2 N equals 2 kg*m/s²
Substitute the known values into the formula.
F= 2 kg*m/s²a= 10 m/s²[tex]2 \ kg*m/s^2 = m * 10 \ m/s^2[/tex]
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 10 meters were second squared. The inverse of multiplication is division. Divide both sides by 10 m/s².
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}=\frac{ m* 10 m/s^2}{10 \ m/s^2}[/tex]
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}= m[/tex]
The units of meters per second squared cancel.
[tex]\frac { 2 \ kg}{10}= m[/tex]
[tex]0.2 \ kg =m[/tex]
Now, we must convert the mass to grams. There are 1000 grams in 1 kilogram. We can multiply the mass by 1000 or set up a ratio.
[tex]0.2 \ kg * \frac{1000 \ g}{1 \ kg}= 0.2 * 1000 \ g = 200 \ g[/tex]
The toy car's mass is 200 grams.
Compare the MKS, CGS & FPS system of units. which system of units are convenient to use? Justify your answer.
Answer: The system of unit which is most convenient for use is the MKS unit.
Explanation:
System of units is defined as the complete set of units which comprises of both the fundamental units and the derived units. The mass, length and time are considered to be the fundamental quantities and their units are called the fundamental units. The systems of unit which are in common use can be compared through their description below:
--> MKS system of unit: In this system of unit, the unit of length is in meter (m). The unit if mass is in kilogram (k). The unit of time is in seconds (s). Hence the name m.k.s system of unit.
--> CGS system of unit: In this system of unit, the unit of length is in centimeter (cm). The unit if mass is in grams (g). The unit of time is in seconds (s). Hence the name c.g.s. system of unit.
--> FPS system of unit: In this system of unit, the unit of length is in foot (Ft). The unit if mass is in pound (Lb). The unit of time is in seconds (s). Hence the name m.k.s system of unit.
The system of unit which is most CONVENIENT for use is the MKS unit. This is because of the introduction of the international system of units (S.I unit). This unit was endorsed by the International Standard Organisation (ISO) to form a logical and interconnected framework for all measurements in science and technology. The MKS system of unit was made the SI units enabling physical quantities to be represented by only one unit.
You slide a 325-N trunk up a 20.0° inclined
plane with a constant velocity by exerting a
force of 211 N parallel to the inclined plane.
a. What is the component of the trunk's
weight parallel to the plane?
b. What is the sum of your applied force, fric-
tion, and the parallel component of the
trunk's weight? Why?
C. What is the size and direction of the friction
force?
d. What is the coefficient of friction?
Answer:
A) 111 N
B) F_net = 0 N
C) 100 N, in the opposite direction of the motion.
D) μ = 0.3274
Explanation:
A) The component of the trunks weight acts parallel to the plane but in the vertical direction and so;
W = Fsin θ
W = 325 sin 20
W = 325 × 0.3420
W ≈ 111 N
B) We are told the trunk is moving with a constant velocity and for this reason the sun of the forces will equal to zero.
Thus; F_net = 0 N
C) Since the kinetic friction force needs to balance the component of the weight, the magnitude is;
F_f = 211 - 111 = 100 N
The direction will be in the opposite direction since it's against the motion.
D) From friction formula, we know that;
F_f = μW cos θ
100 = μ × 325 × cos 20
μ = 100/(325 × cos 20)
μ = 0.3274
Determine the force that the block of metal would exert when resting on a flat surface in Newtons
Answer:
normal force
tension force
and other example of force
1.10) For a fixed mass of gas at constant temperature, if the volume of the gas (V) increases to twice its original amount, the pressure of the gas (P) will be
A)2P
В )1/2 Р
C)P
D)4P
Answer:
B
Explanation:
According to boyle's law for a gas the pressure and volume are inversely proportional.this simply means when one increases the other one reduces and when the other one reduces the other increases.so in this case the volume increased to twice it original amount meaning the pressure will reduce to half the volume.
I hope this helps
Can someone please help a struggling physics student?
A Physics student is running an experiment to test the kinematic equations that she learned over the week. She is throwing a ball with an initial velocity of +12.0 m/s in the vertical direction. Assume that the ball is thrown from the ground (i.e., neglect the student's height)
a) What is the maximum height the ball will reach in the air? Express your answer in m
What is the the velocity of the ball when it hits the ground? Express your answer in m/s.
Later that day, the student decided to repeat the experiment. This time, the weather was a little rough outside and there was a strong wind blowing in the horizontal direction (see figure). As a result of the wind, the horizontal component of the ball's velocity is + 2.3 m/s throughout the time it is in air (pointing to the right).
b) Assuming that the student throws the ball with the same initial upwards velocity as in part a), what will be the maximum height that the ball with reach in the presence of wind? Express your answer in m.
What is the magnitude of the velocity of the ball when it hits the ground? Express your answer in m/s
What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).
What is the maximum height the ball will reach in the air?
Kinematics equation used:
[tex]v_f^2=v_i^2+2ad[/tex], where [tex]v_f[/tex] is final velocity, [tex]v_i[/tex] is initial velocity, [tex]a[/tex] is acceleration, and [tex]d[/tex] is distance travelled. From SI units, velocity should be in [tex]m/s[/tex], acceleration should be in [tex]m/s^2[/tex], and distance should be in [tex]m[/tex]We're given that the initial velocity is 12.0 m/s in the y-direction. At the maximum height, the vertical velocity of the ball will be 0 m/s, otherwise it would not be at maximum height. This is our final velocity.
The only acceleration in the system is acceleration due to gravity, which is approximately [tex]9.8\:\mathrm{ m/s^2}[/tex]. However, the acceleration is acting down, whereas the ball is moving up. To express its direction, acceleration should be plugged in as [tex]-9.8\:\mathrm{m/s^2}[/tex]. We have three variables, and we are solving for the fourth, which is distance travelled. This will be the maximum height of the ball.
Substitute [tex]v_i=12[/tex], [tex]v_f=0[/tex], [tex]a=-9.8[/tex] to solve for [tex]d[/tex]:
[tex]0^2=12^2+2(-9.8)(d),\\0=144-19.6d,\\-19.6d=-144,\\d=\frac{-144}{-19.6}=7.34693877551\approx \boxed{7.35\text{ m}}[/tex]
What is the velocity of the ball when it hits the ground?
This question tests a physics concept rather than a physics formula. The vertical velocity of the ball when it hits the ground is equal in magnitude but opposite in direction to the ball's initial vertical velocity. This is because the ball spends equal time travelling to its max height as it does travelling from max height to the ground (ball is accelerating from initial velocity to 0 and then from 0 to some velocity over the same distance and time). Since the ball has an initial vertical velocity of +12.0 m/s, its velocity when it hits the ground will be [tex]\boxed{-12.0\text{ m/s}}[/tex]. (The negative sign represents the direction. Because velocity is a vector, it is required.)
Part B:**Since my initial answer exceeds the character limit, I've attached the first question to Part B as an image. Please refer to the attached image for the answer and explanation to the first question of Part B. Apologies for the inconvenience.**
What is the direction of the velocity of the ball when it hits the ground? Express your answer in terms of the angle (in degrees ) of the ball's velocity with respect to the horizontal direction (see figure).
This question uses a similar concept as the second question of Part A. The vertical velocity of the ball at launch is equal in magnitude but opposite in direction to the ball's final velocity. The horizontal component is equal in both magnitude and direction throughout the entire launch, since there are no horizontal forces acting on the system. Therefore, the angle below the horizontal of the ball's velocity when it hits the ground is equal to the angle of the ball to the horizontal at launch.
To find this, we need to use basic trigonometry for a right triangle. In any right triangle, the tangent/tan of an angle is equal to its opposite side divided by its adjacent side.
Let the angle to the horizontal at launch be [tex]\theta[/tex]. The angle's opposite side is represented by the vertical velocity at launch (12.0 m/s) and the angle's adjacent side is represented by the horizontal velocity at launch (2.3 m/s). Therefore, we have the following equation:
[tex]\tan \theta=\frac{12.0\text{m/s}}{2.3\text{ m/s}}[/tex]
Take the inverse tangent of both sides:
[tex]\arctan (\tan \theta)=\arctan (\frac{12.0}{2.3})[/tex]
Simplify using [tex]\arctan(\tan \theta)=\theta \text{ for }\theta \in (-90^{\circ}, 90^{\circ})[/tex]:
[tex]\theta=\arctan(\frac{12.3}{2.3}),\\\theta =79.14989537\approx \boxed{79.15^{\circ}}[/tex]
We can express our answer by saying that the direction of the velocity of the ball when it hits the ground is [tex]\boxed{\text{approximately }79.15^{\circ} \text{ below the horizontal}}[/tex] or [tex]\boxed{\text{approximately }-79.15^{\circ} \text{ to the horizontal}}[/tex].
A block of density 2400 km/m3 has a volume of 0.20 m3 what is it's mass
Answer:
Data:
D = 2400 kg/m³
V = 0.20 m³
M = ?
∴ Density = [tex]\frac{Mass}{Volume}[/tex]
2400 kg/ = [tex]\frac{Mass}{0.2 m^{3} }[/tex]
Mass = 2400 kg/m³ × 0.20 m³
Mass = 480 kg (answer)
Answer:
Therefore, the mass of the block is 480 kg.
A basketball is held over head at a height of 2.4 m. The ball is lobbed to a teammate at 8 m/s at an angle of 40'. If the ball is caught at the same height it was tossed at, how far away is the teammate?
Explanation:
since both the teammates are of the same height, their height won't matter. Because now the basketball won't cover any vertical distance.
We have to calculate its range the horizontal distance covered by it when tossed from one teammate to the other.
range can be calculated by the formula :-
[tex] \boxed{\mathfrak{range = \frac{ u {}^{2} \sin 2\theta }{g} }} [/tex]
u is the velocity during its take off and [tex]\theta[/tex] is the angle at which its thrown
Given that
u = 8m/ s [tex]\theta[/tex] = 40°calculating range using the above formula
[tex] = \frac{ {8}^{2} \sin2(40) }{10} [/tex]
[tex] = \frac{64 \times \sin(80) }{10} [/tex]
value of sin 80 = 0. 985
[tex] = \frac{64 \times 0.985}{10} [/tex]
[tex] = \frac{63.027}{10} [/tex]
[tex] = 6.3027[/tex]
Hence,
[tex] \mathfrak { \blue{the \: teammate \: is \: \red{\underline{6.3027 \: meters} }\: away } } [/tex]
sinong personalidad ang bumuo ng pangkat militar na tinawag na black shirts na nagsagawa ng pagpupulong ng mga grupong sosyalista at komunista
Answer:
Answer to the following answer is as follows;
Explanation:
In the northwestern city of Milan, Mussolini formed his nationalist regime in 1919. He organised black-shirted street warriors into teams. His "Blackshirts" raped and expelled socialists and communists from municipal administrations.
The Blackshirts, originally known as the Squadrismo, were formed in 1919 by a group of dissatisfied former soldiers.
True or false: Ultimate tensile strength increases as the thickness of a solid material sample increases.
True
False
Answer:
False.
Explanation:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.
Answer:
Tensile strength should remain constant, regardless of thickness. For larger cross sections, it can slightly increase because the atoms in the center become more constricted and therefore less responsive to the applied stress.FALSE
79. A skater glides along a circular path of radius 5.00 m in clockwise direction. When he coasts around one-half of the circle, starting from the west point, find (a) the magnitude of his displacement vector and (b) how far he actually skated. (c) What is the magnitude of his displacement vector when he skates all the way around the circle and comes back to the west point
The current in a light bulb is 2 A. How long does it take for a total charge of 4 C to pass a point in the wire
Answer:
2min
Explanation:
i think it will be clear from photo
Answer: The formula for current is charge/time
so here we have to change subject so we are asked to look for time
Explanation: so it would be T=Q/I
T=4/2
T=2s
hope this helpss
C is not less than 0
Hai vận động viên chạy trên cùng 1 đoạn đường, vận động
viên A chạy với vận tốc 12 m/s vận động viên B chạy với vận tốc 36
km/h. Hỏi vận động viên nào chạy nhanh hơn?
Answer:
Pemain A
Explanation:
Mengingat data berikut;
Kecepatan pemain A = 12 m/s
Kecepatan pemain B = 36 km/h
Untuk menentukan siapa pelari tercepat di antara dua pemain;
Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.
Jadi, mari kita gunakan pengukuran umum meter per detik.
Konversi:
36 km/h = (36 * 1000)/(60 * 60)
36 km/h = 36000/3600
36 km/h = 10 m/s
Kecepatan pemain B = 10 m/s
Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.
The potential difference across a resistor increases by a factor of 4. How
does the current change? (Ohm's law: V = IR)
A it increases by a factor of 4
B it decreases by a factor of 4
C it increases by a factor of 2
D it decreases by a factor of 2
Answer:
Correct option is C it decreases by a factor of 2
Answer: A - it increases by a factor of 4
Explanation:
Ohm's law is V = IR where V = potential difference, I = current, and R = resistance. Assuming that resistance stays constant (since the question mentioned no change in resistance), we only need to look at "V" and "I" in the equation V = IR.
"V" and "I" are directly proportional. In other words, whatever change happens to "V" will also occur to "I". Since "V" increases by a factor of 4, then "I" will also increase by a factor of 4.
You could also approach this problem by plugging in a change of 4 for the potential difference in the equation: V = I*R.
If we plug in 4V for V, we now have:
4V = I*R
Since the left side increases by a factor of 4, then the right side (only looking at current in this case) will also need to increase by a factor of 4 in order to have the right side stay equal to the left. Therefore, current will also increase by a factor of 4.
what means 10² what we call this
we call it as well as 100 . so easey
Answer:
10 squared
Explanation:
10 squared
In Depth:
Let have a square that has a side length of 10.
A square four sides are equal and if we find the area of a squared, our formula is
[tex] {s}^{2} [/tex]
Our in this instance,
[tex] {10}^{2} [/tex]
or we call it
[tex]10 \: \: squared[/tex]
The pressure at the ice point for a constant-volume gas thermometer is 4.81 x 10^4 Pa. While that at the steam point is 6.48 x 10^4 Pa.
What pressure would the thermometer indicate at 50°c?
when you get the answer please tell me
Convert 60 km/ hr into m/s
Answer:
1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds
Explanation:
so it would be 16.6666666667 meters per second
Why are simple everyday actions considered
thermodynamic reactions?
they transform energy
they destroy energy
they create energy
Answer:
They transform energy
Explanation:
thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy
A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the school is _________ m? The direction of the student's displacement, relative to the school is ______?
Answer:
1. 7.5 m
2. towards west side
explanation:
I hope it will help you
If the electric force between two charges is 4.2 × 10-2 N, what would the new force be if the distance between the charges is doubled and the charge on one of the charges is tripled?
Answer:
New force = 0.063 N
Explanation:
Given that,
The electric force between two charges is[tex]4.2\times 10^{-2}\ N[/tex]
The formula for the electric force is:
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
If the distance between the charges is doubled, r' = 2r and one of the charges is tripled, q₁' = 2q₁, q₂' = 3q₂
Put all the values,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{kq_1q_2}{r^2}}{\dfrac{kq_1'q_2'}{r'^2}}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{q_1\times q_2}{r^2}}{\dfrac{2q_1\times 3q_2}{(2r)^2}}\\\\\dfrac{F}{F'}=\dfrac{4}{6}=\dfrac{2}{3}\\\\F'=\dfrac{3\times 4.2\times 10^{-2}}{2}\\\\F'=0.063\ N[/tex]
So, the new force is 0.063 N.
Answer:
The force becomes 0.0315 N.
Explanation:
Force, F = 4.2 x 10^-2 N
When the distance is doubled, a charge is tripled, Let the force is F'.
The force between the two charges is
[tex]F = \frac{K qq'}{r^2}\\[/tex]
when, q' = 3 q' and r is 2 r so
[tex]F' = \frac{K 3qq'}{4r^2} = \frac{3 F}{4} = \frac {3\times 4.2\times 10^{-2}}{4}=0.0315 N[/tex]
satellite does not need any energy to revolve around the earth why
Answer:
An artificial satellites revolves around the earth under the influence of its gravitational force. So it does not require any energy to revolve around energy.
or maybe god:)))(
định luất bảo toàn động lực chỉ đúng trong trường hợp nào
Answer:
ᴀꜱ ᴡᴀʀᴍ ᴀꜱ ꜱᴜɴ
ᴀꜱ ꜱɪʟʟʏ ᴀꜱ ꜰᴜɴ
ᴀꜱ ᴄᴏʟᴅ ❄️ ᴀꜱ ᴀ ᴛʀᴇᴇ
ᴀꜱ ꜱᴄᴀʀʏ ᴀꜱ ꜱᴇᴀ
ᴀꜱ ʜᴏᴛ ᴀꜱ ꜰɪʀᴇ
ᴀꜱ ᴄᴏʟᴅ ᴀꜱ ɪᴄᴇ
ꜱᴡᴇᴇᴛ ᴀꜱ ꜱᴜɢᴀʀ
ᴀɴᴅ ᴇᴠᴇʀʏᴛʜɪɴɢ ɴɪᴄᴇ
ᴀꜱ ᴏʟᴅ ᴀꜱ ᴛɪᴍᴇ ⌛
ᴀꜱ ꜱᴛʀᴀɪɢʜᴛ ᴀꜱ ʟɪɴᴇ ➖
ᴀꜱ ʀᴏʏᴀʟ ᴀꜱ ᴀ ᴀɴɢᴇʟ☺️
ᴀꜱ ʙᴜᴢᴢᴇᴅ ᴀꜱ ʙᴇᴇ
ᴀꜱ ꜱᴛᴇᴀʟᴛʜ ᴀꜱ ᴛɪɢᴇʀ
ꜱᴍᴏᴏᴛʜ ᴀꜱ ɢʟɪᴅᴇʀ
ᴘᴜʀᴇ ᴀꜱ ʜᴇᴀʀᴛ ❤️
ᴘᴜʀᴇ ᴀꜱ ɪ ᴡᴀɴɴᴀ ʙᴇ
prepare for the module exam,
Question 1
1 pts
If a 6 ohm wire is connected to a 10 volt battery, what will the current be?
O 6 amperes
O ,67 amperes
O 1.67 amperes
60 amperes
Answer:
1.67 amperes
Explanation:
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
[tex] V = IR [/tex] ......equation 1
Where;
V represents voltage measured in voltage.I represents current measured in amperes.R represents resistance measured in ohms.Making I the subject of formula, we have;
[tex] I = \frac {V}{R} [/tex] .....equation 2
Given the following data;
Voltage = 10 VoltsResistance = 6 OhmsTo find the current flowing through the battery, we would use eqn 2;
[tex] I = \frac {10}{6} [/tex]
Current, I = 1.67 amperes
An electron travelling at 7.72 x 107 m/s [E] enters a force field that reduces its velocity to 2.46 x 107 m/s [E]. The acceleration is constant. The displacement during the acceleration is 0.478 m [E]. Determine (a) the electron’s acceleration (b) the time interval over which the acceleration occurs.
Answer:
Acceleration of this electron: [tex]-5.60 \times 10^{15}\; \rm m \cdot s^{-2}[/tex].
Time taken: approximately [tex]9.39 \times 10^{-9}\; \rm s[/tex].
Explanation:
Let [tex]u[/tex] denote the velocity of this electron before the change.Let [tex]v[/tex] denote the velocity of this electron after the change.Let [tex]x[/tex] denote the displacement.Let [tex]a[/tex] denote the acceleration.Let [tex]t[/tex] denote the time taken.Apply the SUVAT equation that does not involve time:
[tex]v^{2} - u^{2} = 2\, a \, x[/tex].
Equivalently:
[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x}\end{aligned}[/tex].
By this equation, the acceleration of this electron would be:
[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x} \\ &= \frac{(7.72 \times 10^{7}\; \rm m \cdot s^{-1})^{2} - (2.46 \times 10^{7} \; \rm m \cdot s^{-1})^{2}}{2 \times 0.478\; \rm m} \\ &\approx -5.60 \times 10^{15}\; \rm m \cdot s^{-2}\end{aligned}[/tex].
The speed of this electron has changed from [tex]u = 7.72 \times 10^{7}\; \rm m\cdot s^{-1}[/tex] to [tex]v = 2.46 \times 10^{7}\; \rm m \cdot s^{-1}[/tex]. Calculate the time required to achieve this change at a rate of [tex]a \approx -5.60 \times 10^{15}\; \rm m\cdot s^{-2}[/tex]:
[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{2.46\times 10^{7}\; \rm m \cdot s^{-1} - 7.72 \times 10^{7}\; \rm m\cdot s^{-1}}{-5.60 \times 10^{15}\; \rm m\cdot s^{-2}} \\ &\approx 9.39 \times 10^{-9}\; \rm s\end{aligned}[/tex].
What does the m stand for in the enthalpy equation?
Answer:
Use the formula ∆H = m x s x ∆T to solve.
Explanation:
Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.
4. A body in motion is said to be in equilibrium when it is
A moving with uniform velocity.
B at rest.
C accelerated by a force.
D moving in an indefinite path.
Answer:
A. moving with uniform velocity.
Explanation:
Was this hepfull
Answer:
A
Explanation:
Equilibrium is a state in which opposing forces or influences are balanced hence A being correct
Question 12 of 15
If nitrogen, which has an electronegativity of 2.0, bonds with hydrogen, which
has an electronegativity of 2.1, the bond between the two atoms will be
classified as a(n)
covalent bond.
Answer here
SUBMIT
Answer:
Covalent bond.
Explanation:
There are 4 main types of bonds:
Covalent, ionic, metallic, and hydrogen.
Covalent bond: Involves the sharing of pairs of electrons, here the difference between the electronegativity of the atoms is not too large. Covalent bonds usually form an octet of electrons.
Ionic bond: This happens because the electrostatic attraction between the atoms whit very different electronegativities
Hydrogen bond: Electrostatic attractive force between an electronegative atom and a hydrogen atom covalently bonded to another electronegative atom.
Metallic bond: Type of bond that makes the metallic atoms to stay really tightly together. The atoms bond because of the electrostatic atractive force between conduction electrons and positively charged metal ions.
Now, in this case, we have the bond between Nitrogen (electronegativity = 2.0) and Hydrogen (electronegativity = 2.1)
So we can see that:
The elements are not metals, so we can discard metallic bond.
For a hydrogen bond, we need 3 atoms (one of which is hydrogen), here we have two, so we can discard this option.
Ionic bond needs different electronegativities, here the electronegativities are really close together, so the ionic bond can be discarded.
we can conclude that the bond will be a covalent bond.
