A and B are two similar 2D shapes
A 12cm
B 15cm
The area of the shape A is 200cm^2.
Calculate the area of shape B

Answer:

The answer is 180 - 65

Step-by-step explanation:

We got 180, because that is the number of degree's in a line

so 180 - 65 is 115 degrees, that's your answer :)

Answer:

x = 7

Step-by-step explanation:

x + 5 = 12

Subtract 5 from both sides

5 - 5 cancels out

12 - 5 = 7

We're left with x = 7

Answer:

Not sure but I think it might be A

Step-by-step explanation:

Took the test

Answer:

Option B is answer.

Step-by-step explanation:

Hey there!

Given;

f(X) = X(X+5)(x-8)

According to the factor theorem, f(X) = 0;

Or, X(X+5)(x-8) = 0

Either;

x = 0

Or;

(x+5)= 0

X = -5

Or;

(x-8)= 0

x = 8.

Therefore, the zeros of the polynomial are: 0,-5,8.

Hope it helps!

Answer:

[tex]x=6[/tex]

Step-by-step explanation:

We want to solve the equation:

[tex]\displaystyle \log_6(2x-6)+\log_6x=2[/tex]

Recall the property:

[tex]\displaystyle \log_bx+\log_by=\log_b(xy)[/tex]

Hence:

[tex]\log_6(x(2x-6))=2[/tex]

Next, recall that by the definition of logarithms:

[tex]\displaystyle \log_b(a)=c\text{ if and only if } b^c=a[/tex]

Therefore:

[tex]6^2=x(2x-6)[/tex]

Solve for x. Simplify and distribute:

[tex]36=2x^2-6x[/tex]

We can divide both sides by two:

[tex]x^2-3x=18[/tex]

Subtract 18 from both sides:

[tex]x^2-3x-18=0[/tex]

Factor:

[tex](x-6)(x+3)=0[/tex]

Zero Product Property:

[tex]x-6=0\text{ or } x+3=0[/tex]

Solve for each case. Hence:

[tex]x=6\text{ or } x=-3[/tex]

Next, we must check the solutions for extraneous solutions. To do so, we can simply substitute the solutions back into the original equations and examine its validity.

Checking x = 6:

[tex]\displaystyle \begin{aligned} \log_{6}(2(6)-6)+\log_{6}6&\stackrel{?}{=} 2 \\ \\ \log_6(12-6)+(1)&\stackrel{?}{=}2 \\ \\ \log_6(6)+1&\stackrel{?}{=}2 \\ \\ 1+1=2&\stackrel{\checkmark}{=}2\end{aligned}[/tex]

Hence, x = 6 is indeed a solution.

Checking x = -3:

[tex]\displaystyle\begin{aligned} \log_6(2(-3)-6) + \underbrace{\log_6-3}_{\text{und.}} &\stackrel{?}{=} 2\\ \\ \end{aligned}[/tex]

Since the second term is undefined, x = -3 is not a solution.

Therefore, our only solution is x = 6.

Answer:

x = 6

Step-by-step explanation:

The given logarithmic equation is ,

[tex]\implies log_{6}(2x - 6) + log_{6}x = 2[/tex]

We can notice that the bases of both logarithm is same . So we can use a property of log as ,

[tex]\bf \to log_a b + log_a c = log_a {( ac)} [/tex]

So we can simplify the LHS and write it as ,

[tex]\implies log_{6} \{ x ( 2x - 6 )\} = 2 [/tex]

Now simplify out x(2x - 6 ) . We get ,

[tex]\implies log_6 ( 2x^2 - 6x ) = 2 [/tex]

Again , we know that ,

[tex]\bf \to log_a b = c , a^c = b [/tex]

Using this we have ,

[tex]\implies 2x^2 - 6x = 6^2 \\\\\implies 2x^2 - 6x -36 = 0 [/tex]

Now simplify the quadratic equation ,

[tex]\implies x^2 - 3x - 18 = 0 \\\\\implies x^2 -6x + 3x -18=0\\\\\implies x( x -6) +3( x - 6 ) = 0 \\\\\implies (x-6)(x+3) = 0 \\\\\implies x = 6 , -3 [/tex]

Since logarithms are not defined for negative numbers or zero , therefore ,

[tex]\implies 2x - 6 > 0 \\\\\implies x > 3 [/tex]

Therefore the equation is not defined at x = -3 . Hence the possible value of x is 6 .

[tex]\implies \underline{\underline{ x \quad = \quad 6 }}[/tex]

Answer:

prime number between 1 to7

The description of set P is the set of prime numbers less than or equal to 7 and the rule is {x | x is a prime number less than or equal to 7}

The set P is given as:

P = {2,3,5,7}

Note that the numbers are prime numbers.

This means that the description of set P is the set of prime numbers less than or equal to 7

The rule form of the set would be:

P = {x | x is a prime number less than or equal to 7}

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Answer:

1/3 fraction of whole paint is used by mark

Step-by-step explanation:

Mark used  1/2 out of 3/2 cans.

[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}[/tex]

Answer:

34

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

Dilated pupils

Long periods of wakefulness

Loss of appetite

Overconfidence

Over-excitement

Paranoia

Runny nose or frequent sniffles

White powder around nostrils

Legal issues

Missing or being late to work

Financial problems

Mood swings

Irritability

Depression

Answer:

14

Step-by-step explanation:

[tex]4 \frac{1}{5} \times (1 \frac{1}{9} \times 3) \\\\= \frac{21}{5} \times ( \frac{10}{9} \times 3)\\\\=\frac{21}{5} \times( \frac{10}{3})\\\\= \frac{21 \times 10}{ 5 \times 3}\\\\=7 \times 2 \\\\= 14[/tex]

Answer:

to get the slope. take the change of y axis value divide by the change of x axis value

Step-by-step explanation:

We know that the sum of angle around a point is 180° . Therefore let the first angle be x then second will be x + 3 .

According to the Question ,

> x + x + 3 = 360°

> 2x = 357=

> x = 357°/2

> x = 178.5°

Answer:

x = 38°

y = 90°

Step-by-step explanation:

x is an inscribed angle, so, 78/2=39

y is an inscribed angle of which connects two endpoints of the diameter, so y = 90°

Answered by GAUTHMATH

Answer:

1

Step-by-step explanation:

64+32 =96 that'd how I got the answer

Answer:

[tex]{ \tt{8(2v + 8) = 96}} \\ { \tt{2v + 8 = 12}} \\ { \tt{2v = 4}} \\ { \bf{v = 2}}[/tex]

Answer:

1min = 0.25miles

5.25miles / 0.25miles = 25 = 25minutes

Step-by-step explanation:

Hope this is right I'm not the best at worded time/distance math questions.

9514 1404 393

Answer:

  0 ≤ t < 52.5 minutes

Step-by-step explanation:

Riko will be behind Yuto until her distance traveled matches his. That is, she will be behind for ...

  0.35t < 5.25 +0.25t

  0.10t < 5.25

  t < 52.5

Riko will be behind Yuto on the interval 0 ≤ t < 52.5 minutes.

_____

Additional comment

distance = speed × time

Here, time is measured from when Riko starts riding. In addition to the 5.25 miles that Yuto has already gone, his distance will be the product of his speed (0.25 mi/min) and the travel time (t min). Then Yuto's total distance is 5.25+0.25t miles. The speed×time product is also used to find Riko's distance traveled. In her case, it is 0.35t miles.

Answer:

% change in perimeter = 43. 44 %

% change in area = 16 %

Step-by-step explanation:

initial perimeter of the rectangle = 2(2p + p)

= 6p

initial area of the rectangle = 2p × p

= 2p²

therefore,

= 2p + 0.8p = 2.8 p

= p - 0.4p

= 0.6 p

= 3.4 p

= 1.68 p²

% change in perimeter

[tex] = \frac{6p - 3.4p}{6p} \times 100 \\ = \frac{2.6p}{6p} \times 100 \\ = 43.33\%[/tex]

% change in area

[tex] \frac{2 {p}^{2} - 1.68 {p}^{2} }{2 {p}^{2} } \times 100 \\ = \frac{0.32}{2} \times 100 \\ = 16\%[/tex]

Answer:

x = 63.9

Step-by-step explanation:

We have:

[tex]\frac{QR}{sin35}[/tex] = [tex]\frac{78}{sin90}[/tex]

=> QR × sin90 = 78 × sin35

=> QR × sin90 = 44.7

=> QR = 44.7

But, we also have: [tex]x^{2}[/tex] + [tex]QR^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] + [tex]44.7^{2}[/tex] = [tex]78^{2}[/tex] <=> [tex]x^{2}[/tex] = 6084 - 1998.09

=> [tex]x^{2}[/tex] = 4085.91

=> x = [tex]\sqrt{4085.91}[/tex] = 63.9211.. = 63.9

<3 Have a nice day!!

Answer:

x^4+4x^3+6x^2+7x+2

Answer:

2

Step-by-step explanation:

that is √ 14 which is 27 ×>44.2177

Answer:

$610.70

Step-by-step explanation:

[tex]a = pe^{rt}[/tex]

a = 500 [tex]e^{.05 * 4}[/tex]

a = $610.70

Answer:

a=1

b=-5

c=6

Step-by-step explanation:

ax^2+bx+c=0

Is the formula used for this question.

The given function is the same as y = 1x^2 + (-5x) + 6

Compare it to the form y = ax^2+bx+c, and we have the following:

a = 1

b = -5

c = 6

Answer:

in jh ynhtym

hunt ghb JBL iggmmjuu ki ju nu j

Answer:

12,-2

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

Let's find the first term in terms of p.

So an arithmetic sequence is a linear relation.

That means it will have the same slope no matter the pair of points used. We are given the slope, the common difference, is 2. We are going to use point (9, 3+3p) and (1, t(1)) along with m=2 to find t(1).

[t(1)-(3+3p)]/[1-9]=2

Simplify denominator

[t(1)-(3+3p)]/[-8]=2

Multiply both sides by -8

t(1)-(3+3p)=-16

Add (3+3p) on both sides

t(1)=-16+3+3p

Combine like terms

t(1)=-13+3p

This means we can find the next term by adding 2 this.

t(2)=-11+3p

Let's find the next term by adding 2 this.

t(3)=-9+3p

Finally we can find the 4th term by adding 2 to this

t(4)=-7+3p

We are given the sum of the first 4 terms is 2p-10. So we can write:

-13+3p+-11+3p+-9+3p+-7+3p=2p-10

Combine like terms on left

12p-40=2p-10

Subtract 2p on both sides

10p-40=-10

Add 40 on both sides

10p=30

Divide both sides by 10

p=3.

-----------------

Checking:

t(1)=-13+3p=-13+3(3)=-13+9=-4

t(2)=-11+3p=-11+3(3)=-11+9=-2

t(3)=-9+3p=-9+3(3)=-9+9=0

t(4)=-7+3p=-7+3(3)=-7+9=2

----sum of the first 4 is -4

And 2p-10 at p=3 gives 2(3)-10=6-10=-4

So this part checks out

In general, the pattern that those 4 terms I wrote out follow t(n)=(-13-2)+2n+3p. I know this because the 0th term would have been (-13-2)+3p and this part goes up by 2 each time. The plus 3p part doesn't change.

Anyways t(9)=(-13-2)+2(9)+3p=-15+18+3p=3+3p. And this part looks good too.

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3.

Answer:

-3,4 are the TWO integers whos product is -12 and whose sum is 1.

Step-by-step explanation:

-3×4=12

-3+4=1

Answer:

If U = { a, b, c, d, e, f, g, h} , find the complements of the following sets:(i) A = {a, b, c} (ii) B = {d, e, f, g} (iii) C = {a, c, e, g} (iv) D = { f, g, h, a}

Answer:

A= { a,b,c,d,e}

B= {d,e,f,g,h,i}

C= {a,e,i,o,u}

AuBuC = {a,b,c,d,e,f,g,h,i,o,u}

HAVE A NİCE DAY

Step-by-step explanation:

GREETİNGS FROM TURKEY ¯ツ

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

Answer:

Step-by-step explanation:

1 . ( n + 4 ) / ( 2m - 3 )

The gradient (slope) is

= ( change in y direction ) / ( change in x direction )

= ( n - (-4) ) / ( 2m - 3 )

= ( n + 4 ) / ( 2m - 3 )

2.

A line parallel to the x-axis will always have the equation of y = #. This is because all along that line, every value of x, y will still equal the same number. For example, a line parallel to the x-axis that crosses the y-axis at 2, will be y = 2. If it is in the negative range, it's the same concept, for example if it crossed the y-axis at -4, the equation would be y = -4.

Example - Computational Knowledge Engine

3.

To understand the slope of a line parallel to y axis, let us consider the figure given below.

1 . The gradient (slope) is ( n + 4 ) / ( 2m - 3 )

2. n = -4

3. m is not defined.

A line's slope is determined by how its y coordinate changes in relation to how its x coordinate changes. y and x are the net changes in the y and x coordinates, respectively. Therefore, it is possible to write the

change in y coordinate with respect to the change in x coordinate as,

m = Δy/Δx where, m is the slope

Given:

points (2m, n) and (3, -4).

1 . The gradient (slope) is

= ( change in y direction ) / ( change in x direction )

= ( n - (-4) ) / ( 2m - 3 )

= ( n + 4 ) / ( 2m - 3 )

2. A line parallel to the x-axis will always have the equation of y = x.

The line is therefore horizontal so gradient = 0

(n+4) / (2m-3)= 0

n = -4

(iii) Find the value of m if the line is parallel to the y-axis

(n+4) / (2m-3)= gradient

(n+4) / (2m-3)= 1

We know n = -4 from part (ii) then

(-4+4) /(2m-3)= 1

0/(2m-3) = 1

0 = 1 The 'm' vanishes

Hence, m is not defined.

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