78950W the answer
Explanation:
A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor
A 75- kw, 3-, Y- connected, 50-Hz 440- V cylindrical synchronous motor operates at rated condition with 0.8 p.f leading. the motor efficiency excluding field and stator losses, is 95%and X=2.5ohms. calculate the mechanical power developed, the Armature current, back e.m.f, power angle and maximum or pull out torque of the motor
You find an unnamed fluid in the lab we will call Fluid A. Fluid A has a specific gravity of 1.65 and a dynamic viscosity of 210 centipoise [cP]. What is the kinematic viscosity of Fluid A, in units of stokes [St]
Answer:
1.2727 stokes
Explanation:
specific gravity of fluid A = 1.65
Dynamic viscosity = 210 centipoise
Calculate the kinematic viscosity of Fluid A
First step : determine the density of fluid A
Pa = Pw * Specific gravity = 1000 * 1.65 = 1650 kg/m^3
next : convert dynamic viscosity to kg/m-s
210 centipoise = 0.21 kg/m-s
Kinetic viscosity of Fluid A = dynamic viscosity / density of fluid A
= 0.21 / 1650 = 1.2727 * 10^-4 m^2/sec
Convert to stokes = 1.2727 stokes
The view factor for radiation emitted by surface 1 to surface 2 was calculated to be 0.4. The working area of surface 1 is 0.01 m2, the working area of surface 2 is 0.04 m2. What is the view factor for radiation emitted by surface 2 to surface 1?
Answer:
The view factor for radiation emitted by surface 2 to surface 1 is 0.1
Explanation:
Given
[tex]F_{12} = 0.4[/tex]
[tex]A_1 = 0.01m^2[/tex]
[tex]A_2 = 0.04m^2[/tex]
Required
Determine [tex]F_{21}[/tex]
To do this, we make use of the following equivalent ratio
[tex]A_1 * F_{12} = A_2 * F_{21}[/tex]
Make [tex]F_{21[/tex] the subject
[tex]F_{21} = \frac{A_1 * F_{12}}{ A_2}[/tex]
Substitute values into the equation
[tex]F_{21} = \frac{0.01m^2 * 0.4}{0.04m^2}[/tex]
[tex]F_{21} = \frac{0.01 * 0.4}{0.04}[/tex]
[tex]F_{21} = \frac{0.004}{0.04}[/tex]
[tex]F_{21} = 0.1[/tex]
Identify the best drying agent or process for each described purpose. Removal of small amounts of water from a polar solvent____. Removal of visible pockets of water from an organic solvent____. Storage of solvents or other materials in a desiccator_____.
Answer:
Calcium Chloride
Brine Wash
Drierite
Explanation:
Removal of small amounts of water from a polar solvent is Calcium Chloride
Removal of visible pockets of water from an organic solvent is Brine Wash
Storage of solvents or other materials in a desiccator is Drierite
Một máy nghiền bi thùng ngắn đường kính D = 1.6m, dài L = 2m dùng để nghiền VL. Kích thước đầu vào D1 = 20mm, sản phẩm sau nghiền có kết quả phân tích rây sau:
Số mesh
60/80
80/100
100/150
150/200
Khối lượng VL trên rây
0.1
0.3
2.5
0.1
Hỏi
1. Tính kích thước bi nghiền bi.
2. Tính số vòng quay tối ưu.
3. Tính năng suất (biết K1 = 1.01).
4. Tính số lượng bi cần nạp vào thùng. Biết hệ số chứa đầy φ = 0.25, hệ số rỗng = 0.65, ⍴bi = 8000 kg/m3
Answer:
bood ekogcd gcaerh is an American fbnuxc
Problem
In the clevis shown in Fig. find the minimum bolt diameter and the minimum thickness of each yoke that will support a load P= 14 kips without exceeding a shearing stress of 12 ksi and a bearing stress of 20 ksi
Answer:
In the clevis shown in Fig. 1-11b, find the minimum bolt diameter and the minimum thickness of each yoke that will support a load P = 14 kips without exceeding a shearing stress of 12 ksi and a bearing stress of 20 ksi.
127-clevis-double-shear-bolt.gif
Solution 127
Hide Click here to show or hide the solution
127-fbd-clevis-double-shear-bolt.gifFor shearing of rivets (double shear)
P=τA
14=12[2(14πd2)]
d=0.8618in → diameter of bolt answer
For bearing of yoke:
P=σbAb
14=20[2(0.8618t)]
t=0.4061in → thickness of yoke answer
A stream of ethylene glycol vapor at its normal boiling point and 1atm flowing at a rate of 175 kg/min is to be condensed at constant pressure. The product stream from the condenser is liquid g lycol at the condensation temperature.
a. Calculate the rate at which heat must be transferred from the condenser (kW).
b. If heat were transferred at a lower rate than that calculated in part (A), what would the state of the product stream be? (Dedu ce as much as you can about the phase and the temperature of the stream.)
c. If heat were transferred at a higher rate than that calculated in part (A), what could you deduce about the state of the product stream?
Answer: hello attached below is the question properly written
a) 2670 Kw
b) product will be made up of vapor and liquid
c) Product will be a super cooled liquid
Explanation:
mass Flow rate ( m ) = 175 kg/min
pressure = 1 atm
molecular weight of ethylene glycol ( mw ) = 62.07 g/mol
enthalpy of vaporization ( ΔHv ) = 56.9 KJ/mol
Using values from the table 8.1 related to the question
a) Determine the rate at which heat must be transferred from condenser
Using values from the table 8.1 related to the question
ΔH = 2670 Kw
b) If heat is transferred at a lower temperature the product will be made up of vapor and liquid
c) If heat was transferred at a higher temperature the product will be a super cooled liquid
In a certain pressing operation, the metallic powder fed into the open die has a packing factor of 0.5. The pressing operation reduces the powders to 70% of their starting volume. In the subsequent sintering operation, shrinkage amounts to 10% on a volume basis. Given that these are the only factors that affect the structure of the finished part, determine its final porosity.
Answer:
0.2063
Explanation:
Given data:
packing factor = 0.5
percentage of reduction of powders = 70%
Calculate the final porosity
after sintering Bulk specific volume = 0.9 * 0.7 = 0.63
assuming true specific volume = 1
packing factor = 0.5 , bulk specific volume = 2
packing factor after pressing and sintering
= 1 / ( 2 * 0.63 ) = 0.7937
hence : porosity = 1 - packing factor
= 1 - 0.7937 = 0.2063
A copper block receives heat from two different sources: 5 kW from a source at 1500 K and 3 kW from a source at 1000 K. It loses heat to atmosphere at 300 K. Assuming the block to be at steady state, determine (a) the net rate of heat transfer in kW; (b) the rate of entropy generation in the system's universe
Answer:
a) Zero
b) the rate of entropy generation in the system's universe = ds/dt = 0.2603 KW/K
Explanation:
a) In steady state
Net rate of Heat transfer = net rate of heat gain - net rate of heat lost
Hence, the rate of heat transfer = 0
b) In steady state, entropy generated
ds/dt = - [ Qgain/Th1 + Qgain/Th2 - Qlost/300 K]
Substituting the given values, we get –
ds/dt = -[5/1500 + 3/1000 – (5+3)/300]
ds/dt = - [0.0033 + 0.003 -0.2666]
ds/dt = 0.2603 KW/K
thiết kế ic 555 và code để ic hoạt động
Answer:
here you go.
screenshot 2 should give you some basic idea
Request for proposal (RFP) is a type of document that contains the information and proposals mostly through the bidding process. This document is regarding the valuable assets, services, entity, commodity, etc.
Answer:
Answer to the following is as follows;
Explanation:
A request for proposal is a documentation that invites prospective contractors to submit business opportunities to an agency or corporation interested in procuring a commodities, product, or valuable resource through a bid procedure.
A request for proposal (RFP) is a commercial document that introduces a project, defines it, and invites eligible contractors to compete on its completion.
Just because I seen someone else ask but they didn't have enough information.
If a filesystem has a block size of 4096 bytes, this means that a file comprised of only one byte will still use 4096 bytes of storage. A file made up of 4097 bytes will use 4096*2=8192 bytes of storage. Knowing this, can you fill in the gaps in the calculate_storage function below, which calculates the total number of bytes needed to store a file of a given size?
Answer:
Following are the program to the given question:
def calculate_storage(filesize):#definging a method calculate_storage that takes filesize as a parameter
block_size = 4096#definging block_size that holds value
full_blocks = filesize//block_size#definging full_blocks that divides the value and hold integer part
partial_block_remainder = filesize%block_size#definging partial_block_remainder that holds remainder value
if partial_block_remainder > 0:#definging if that compare the value
return block_size*full_blocks+block_size#return value
return block_size*full_blocks#return value
print(calculate_storage(1)) # calling method by passing value
print(calculate_storage(4096)) # calling method by passing value
print(calculate_storage(4097)) # calling method by passing value
Output:
4096
4096
8192
Explanation:
In this code, a method "calculate_storage" is declared that holds a value "filesize" in its parameters, inside the method "block_size" is declared that holds an integer value, and defines "full_blocks and partial_block_remainder" variable that holds the quotient and remainder value and use it to check its value and return its calculated value. Outside the method, three print method is declared that calls the method and prints its return value.
A laminated steel ring is wound with 3000 turns. When the magnetism current varies between 7 and 9 A, the magnetic flux varies between 860 and 900Nwb, calculate the incremental inductance of the coil over this range of current variation
Answer:
60000 H
Explanation:
We are given;
Number of turns; N = 3000 turns
Change in flux = 900 - 860 = 40 Wb
Change in current = 9 - 7 = 2 A
Now, the formula for incremental inductance is given as:
L = N(Change in flux/Change in current) where;
N is Number of turns
Plugging in the relevant values, we have;
L = 3000(40/2)
L = 60000 H.
In a series circuit, there ______ for current to flow.
a.
are at least two paths
b.
are multiple paths
c.
is only 1 path
d.
are very small paths
Answer:
Option C = Only 1 path for current to flow.
hãy trình bày sự hiểu biết của bạn về đo dòng điện
Answer:
-Khái niệm:
Đo dòng điện là sử dụng các dụng cụ như ôm kê, vôn kế, ampe kế, tần số kế… để xác định các đại lượng vật lý của dòng điện
-Đo lường điện để làm gì?
Phát hiện hư hỏng sự cố trong mạch điện và các thiết bị vi mạch
Xác định các giá trị cần đo
Đánh giá chất lượng của các thiết bị sau sản xuất
Xác định thông số kỹ thuật của thiết bị
-Phân loại dụng cụ đo điện: Hiên nay có 2 phương pháp phân loại chính
a. Theo nguyên lý làm việc
Dụng cụ đo kiểu điện từ
Dụng cụ đo kiểu điện động
Dụng cụ đo kiểu cảm ứng
Dụng cụ đo kiểu từ điện
b. Theo đai lượng, giá trị cần đo
+Đo điện năng: Ví dụ công tơ điện
+Đo điện áp: Ví dụ: Vôn kế
+Đo dòng điện: Ví dụ: Ampe kế
+Đo công suất: Oát kế
+Đo điện trở: Ôm kế
Sai số khi đo: Khi đo lường luôn xảy ra các sai số
Sai số tương đối: Là tỷ lệ % của sự chênh lệch giữa giá trị đo được và giá trị thự
good housekeeping can increase production in a work place is it true or false
False, Good housekeeping eliminates accident and fire hazards. It also maintains safe, healthy work conditions; saves time, money, materials, space, and effort; improves productivity and quality; boosts morale; and reflects an image of a well-run, successful organization.
Hope it helps you❤️
16) Find the output of the following flowchart
Address
100
101
102
103
104
105
Value
1
2.
3
8
15
16
hi
Answer:80
Answer:
364 566 inches of class-6th from a
Please label the following statements as either True (T) or False (F).
(a) The true stress is higher than the engineering stress for a sample under tension.
(b) Creep test is carried out with a dynamic stress under elevated temperature.
Answer:
a. True
b. False
Explanation:
a. Since true stress, σ' = σ(1 + ε) where σ = engineering stress and ε = engineering strain.
Also under tension ε > 0, so, (1 + ε) > 1
Since (1 + ε) = σ'/σ > 1, ⇒ σ' > σ
So, the true stress is greater than the engineering stress.
So, the statement is true
b. Creep is a time-dependent deformation under certain applied load.
Creep occurs at high temperatures under different types of stress.
But, Creep test is carried out at constant high temperature and constant stress.
This statement is false.
An assembly line has 3 fail safe sensors and one emergency shutdown switch.The line should keep moving unless any of the following conditions arise:
(1) If the emergency switch is pressed
(2) If the senor1 and sensor2 are activated at the same time.
(3) If sensor 2 and sensor3 are activated at the same time.
(4) If all the sensors are activated at the same time
Suppose a combinational circuit for above case is to be implemented only with NAND Gates. How many minimum number of 2 input NAND gates are required.
Answer:
1 NAND gate
Explanation:
The minimum number of 2 input NAND gates that can be used to implement the combinational circuit = 1
The only true combinations conditions that can produce a false result ( i.e. condition/result different from the expected result as stated in the question )
Sensor 2 activated + Emergency switch pressed = False ( Line will keep moving )
R-134a is throttled in a line flowing at 25oC, 750 kPa with negligible kinetic energy to a pressure of 165 kPa. Find the exit temperature and the ratio of the exit pipe diameter to that of the inlet pipe (Dex/Din) so that the velocity stays constant.
Solution :
For R-134a, we are given :
[tex]$T_i = 25^\circ C$[/tex]
[tex]$P_i=750 \ kPa$[/tex]
[tex]$P_e=165 \ kPa$[/tex]
Now we have one inlet and one exit flow, no work and no heat transfer. The energy equation is :
[tex]$h_e+\frac{1}{2}.v_e^2= h_i+\frac{1}{2}.v_i^2 $[/tex]
We also know that the gas is throttled and there is no change in the kinetic energy.
So, [tex]$v_e=v_i$[/tex]
Now from the energy equation above, we can see that the inlet and the exit enthalpies are also the same. Therefore,
[tex]$h_i=h_e$[/tex]
From the saturated R-134a table, corresponding to [tex]P_e = 165 \ kPa[/tex], we can find the exit saturation temperature.
[tex]$T_e=-15^\circ C$[/tex]
From the saturated R-134a table, corresponding to [tex]P_e = 165 \ kPa[/tex], we can find the specific enthalpies :
[tex]$h_f = 180.19 \ kJ/kg$[/tex]
[tex]$h_{fg} = 209 \ kJ/kg$[/tex]
Calculating the exit flow quality factor,
[tex]$x_e=\frac{h_e-h_f}{h_{fg}}$[/tex]
[tex]$=\frac{234.59-180.19}{209}$[/tex]
= 0.26
From the saturated R-134a table, corresponding to [tex]P_e = 165 \ kPa[/tex], we can find the specific volumes :
[tex]$v_f = 0.00746 \ m^3/kg$[/tex]
[tex]$v_{fg} = 0.11932 \ m^3/kg$[/tex]
Calculating the exit specific volume :
[tex]$v_e=v_f+x_e(v_{fg})$[/tex]
= 0.000746 + 0.26 (0.11932)
= 0.0318 [tex]m^3/kg[/tex]
The mass flow is equal to :
[tex]$\dot{m} = A_i . \frac{v}{v_i}$[/tex]
[tex]$=A_e . \frac{v}{v_e}$[/tex]
So, [tex]$\frac{A_e}{A_i}=\frac{v_e}{v_i}$[/tex]
Therefore, the ratio of the exit pipe and the inlet pipe diameter is equal to
[tex]$\frac{D_e}{D_i}=\sqrt{\frac{A_e}{A_i}}$[/tex]
[tex]$\frac{D_e}{D_i}=\sqrt{\frac{v_e}{v_i}}$[/tex]
[tex]$\frac{D_e}{D_i}=\sqrt{\frac{0.0318}{0.000829}}$[/tex]
[tex]$\frac{D_e}{D_i}=6.19$[/tex]
Here are the city gas mileages for 13 different midsized cars in 2008. 16, 15, 22, 21, 24, 19, 20, 20, 21, 27 , 18 , 21 , 48 What is the minimum ?
Answer:
Minimum city gas mileage is 15
Explanation:
Minimum city gas mileage among 13 different car sizes in 2008 is 15.
If the two 304-stainless-steel carriage bolts of the clamp each have a diameter of 10 mmmm, and they hold the cylinder snug with negligible force against the rigid jaws, determine the temperature at which the average normal stress in either the magnesium or the steel first becomes 12.0 MPaMPa .
Answer: hello some data related to your question is missing attached below is the missing data
answer:
T2 = 265°C
Explanation:
First step : calculate sum of vertical forces
∑ y = 0
Fmg - 2(0.5 Fst ) = 0
∴Fmg = ( 12 * 10^6 ) ( 2 * π/4 (0.01)^2 )
= 1884.96 N
Also determine the Compatibility equation in order to determine the change in Temperature
ΔT = 250°C
therefore Temperature at which average normal stress becomes 12.0 MPa
ΔT = T2 - T1
250°C = T2 - 15°C
T2 = 250 + 15 = 265°C
attached below is the detailed solution
The mean of 10 numbers is 9, then the sum (total) of these numbers will be
Answer:
90
Explanation:
mean is basically taking the sum of all numbers and then dividing the sum with the number of all given numbers..
here, the mean is 9, total numbers are 10.. so the sum will be 9 multiplied by 10, that is 90.
If the mean of 10 numbers is 9, then the sum (total) of these numbers will be 90. The correct option is D.
What is mean?The mean is the average of a set of variables in mathematics and statistics. The mean can be calculated in a variety of ways, including the simple arithmetic mean (add the numbers and divide the total by the number of observations), geometric mean, and harmonic mean. Mean is denoted by a small m.
To calculate mean: Arrange the data items in ascending order from least to greatest. If the number of points is odd, the median is the data point in the middle of the list. If the number of data points in the list is even, the median is the average of two middle data points.
Mean = total sum of the numbers/total numbers
9 = total sum of the numbers / 10
The sum of the terms = 9 x 10 = 90
90 = total sum of the numbers
Therefore, the correct option is D. 90
To learn more about the mean, refer to the link:
https://brainly.com/question/28670966
#SPJ2
The question is incomplete. Your most probably complete question is given below:
A. 9. B. 0.9. C. 70. D. 90
When a voltage (v=353 sin (251t+30) is applied to two elements impedance a current (i =7.07 cos 251 t) is passing. Find the nature and the value of the elements and the circuit power
Answer:
A.C. voltage, V= V0 sin ωt As,t = πω = 12.2πω = 12T, therefore, first half cycle (T/2). Hence, average value of AC voltage, Eav = 2V0π.list 3 appliances each of the following
soil
waste
Answer:
soil>>Slop sink
>Urinal
>water closet
khái niệm về môi trường nhiệt nóng và môi trường nhiện lạnh ?
ảnh hưởng của môi trường và môi trường nhiệt lạnh đến con người như thế nào ?
Theo em môi trường nào gây nguy hiểm hơn đối với con người ? Vì sao ?
Explanation:
उह्ह्नमजज्ल्ह्ह्बनुतनकुहक्जो
nơi nào có điện tích thì xung quanh điện tích đó có :
Explanation:
sory sorry sorry sorrysorrysorry
8. The operation of a TXV is controlled by the
O A. thermostatic spring.
O B. temperature bulb.
O C. external pressure of the evaporator.
O D. modulating valve.
find the volume of the pond with the following dimension length 40m breadth 10m height 1.2m depth 0.9m express in both meters and feet
Answer:
The volume for this is 29.7
Explanation:
Trust me on this I'm an expert
A circuit diagram for a lighting circuit is shown in Figure 6.
Figure 6
230 V AC
A
RL1
+
B T 12 V
04
4
Explain the function of the relay RL1 in the lighting circuit shown in Figure 6.
[2 marks)
Answer:
is there a picture of the figure?
1. What is the maximum value of the linear density in a crystalline solid (linear density defined as the fraction of the line length occupied by atoms, assumed as spheres and only counted it their center is on the line)?
2. What family of directions has the highest linear density in the FCC system?
3. What family of directions has the highest linear density in the BCC system?
4. What family of planes has the highest planar density in the FCC system?
5. What family of planes has the highest planar density in the BCC system?
6. What family of planes has the highest planar density in the HCP sytem?
