The velocity of both objetcs after the collision is 3.07m/sec if both object masses are 6.2 kg and 8.0kg respectively.
To find the velocity of both objects we need to conserve the momentum. We need to follow the law of conservation of momentum which states that initial momentum is equal to final momentum.
Now, we know that momentum =mass × velocity
So, initial momentum of first object=6.2×3=18.6Kg-m/sec
Similarly, initial momentum of second object=8×3.5=28.0kg-m/sec
Now, it is given that both object stick together, so total mass of both objects are=(6.2+8)=14.2kg
Now, both objects are moving with common velocity, so assume both have velocity v
=>So, final momentum of both objects is =14.2×v
according to law of conservation of momentum
=>18.6+25=14.2v
=>43.6=14.2v
=>v=43.6/14.2
=>v=3.07m/sec
Hence, final velocity of objects are 3.07m/sec.
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Maddy tripped and accidentally threw her phone off the hollywood cliff at 5m/s. It landed 20 away from the base of the cliff. how high is the cliff then?
The height of the cliff, given that her phone landed 20 m away when she accidentally threw her phone with a velocity of 5 m/s is 78.4 m
How do I determine the height of the cliff?To determine the height of the cliff, we must first obtain the time taken for her phone to reach the ground. This is obtained as follow:
Horizontal velocity (u) = 5 m/sHorizontal distance (s) = 20 mTime taken (t) =?s = ut
20 = 5 × t
Divide both sides by 5
t = 20 / 5
t = 4 s
Finally, we shall determine the height of the cliff. Details below:
Time taken (t) = 4 sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = ?h = ½gt²
h = ½ × 9.8 × 4²
h = 4.9 × 16
h = 78.4 m
Thus, the height of the cliff is 78.4 m
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Maher is trying to find the density of a plastic toy. The toy’s mass is 160 g.
Maher placed the toy in a graduated cylinder that has 70 ml of water, the water level increased
till 150 ml.
a) Find the toy’s volume.
The volume of the toy is 80 ml.
To find the volume of the plastic toy, Maher can use the principle of buoyancy. When an object is placed in a fluid, it will displace an amount of fluid equal to its own volume. The volume of the displaced fluid can be measured and used to calculate the volume of the object.
In this case, Maher has placed the toy in a graduated cylinder filled with water, and he has observed that the water level increased from 70 ml to 150 ml. This means that the toy displaced 150 - 70 = 80 ml of water.
The volume of the toy is equal to the volume of the displaced water, so the toy's volume is 80 ml. This is the volume of the toy when it is completely submerged in water.
It's important to note that the volume of an object can change depending on its temperature, pressure, and other factors. To get an accurate measurement of the volume of the toy, Maher should make sure to measure the volume of the displaced water carefully and under controlled conditions.
Answer:
Volume of the toy: [tex]80\; {\rm mL}[/tex].
Average density of the toy: [tex]2\; {\rm g\cdot mL^{-1}}[/tex] (or equivalently, [tex]2\; {\rm g \cdot cm^{-3}}[/tex].)
Explanation:
The graduated cylinder initially measures the volume of water in this cylinder:
[tex]V(\text{water}) = 70\; {\rm mL}[/tex].
Assume that the toy is submerged in the water. The graduated cylinder would then measure the volume of the water and the toy, combined:
[tex]V(\text{water}) + V(\text{toy}) = 150\; {\rm mL}[/tex].
Rearrange to find the volume of the toy:
[tex]\begin{aligned}V(\text{toy}) &= 150\; {\rm mL} - V(\text{water}) \\ &= 150\; {\rm mL} - 70\; {\rm mL} \\ &= 80\; {\rm mL}\end{aligned}[/tex].
To find the average density of this toy, divide mass by volume:
[tex]\begin{aligned}(\text{average density}) &= \frac{(\text{mass})}{(\text{volume})} \\ &= \frac{160\; {\rm g}}{80\; {\rm mL}} \\ &= 2\; {\rm g\cdot mL^{-1}}\end{aligned}[/tex].
The diagram below represents a wave.
What is the speed of the wave if its wavelength is 3.0 m?
The speed of the wave is determined as 18 m/s.
option D is the correct answer.
What is the speed of the wave?
The speed of the wave is the rate of change of wave's displacement with time.
The speed of the wave is calculated by applying the formula relating speed, wavelength and frequency of the wave as shown below.
v = fλ
where;
v is the speed of the wavef is the frequency of the waveλ is the wavelength of the waveThe frequency of the wave is calculated as follows;
f = 1 / T
where;
T is the period of the waveThe period of a wave is the time taken for the wave to complete one cycle.
In the picture given, 3 cycles of the wave = 0.5 s
1 cycle of the wave = ?
= 0.5 s / 3
= 0.16667 s
f = 1 / T
f = 1 / 0.16667
f = 6 Hz
The speed of the wave is calculated as follows;
v = fλ
v = 6 Hz x 3 m
v = 18 m/s
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when you looked at solar activity on the heliophysics event registry website, on which date did you find activity on the sun?
You did look at solar activity on the heliophysics event registry website, and we found activity on the sun on the specified day.
What three sorts of solar occurrences are there?Any natural occurrence in the upper atmosphere of the sun is referred to as a solar phenomenon. Solar flares, prominences and filaments, and coronal mass ejections are three different categories of solar phenomena.
How can I follow the cycle of solar activity the best?The simplest way we can investigate how solar activity changes over time is to survey sunspots, which is also how we track the solar cycle. Sunspots are associated with the Sun's natural 11-year cycle, during which the planet's surface changes from calm to turbulent.
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A physics student walks 6 meters east, 4 meters north, then 9 meters
west. What is the student's magnitude of displacement from starting
position?
Answer:
5 m
Explanation:
Displacement is the straight-line distance from the starting point to the end point. Student ends up 4m north and 3m west from where he started. Use pythagorean theorem to solve for displacement (d).
d² = 3² + 4² = 25
d = [tex]\sqrt{25}[/tex] = 5 m
Or, if you remember from geometry, a right triangle with legs of 3 and 4 has a hypotenuse of 5 (3-4-5 right triangle)
A robot that is exploring the surface of Mars has a mass of 136 kg. If the gravitational force acting on the robot is 504.6 N downward, what is the free-fall acceleration on Mars?
The free-fall acceleration on Mars is 3.71 m/s²
What do you mean by free fall?A body is said to be in freefall when it only moves in relation to the Earth's gravity. An external force exerted on the ball will cause its motion to accelerate. Gravitational acceleration is another name for this rate of free fall.According to Newton's second law of motion, force (F) = mass (m) times acceleration, an item in free fall will move with an acceleration (a). We can use a little mathematics to determine the object's acceleration in terms of the net external force and the object's mass (a = F / m).Given :
gravitational force acting on the robot is 504.6 N
F= 504.6 N
mass of the robot = 136 kg
a = F/ m
= 504.6/ 136 =3.71 m/s²
The free-fall acceleration on Mars is 3.71 m/s²
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what force must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2500 kg car (a big car) resting on the slave cylinder? the master cylinder has a 1.93 cm diameter, while the slave's is 24.9 cm. 1900 n 150 n 15 n 4.1e 06 n 74 n
The force that must be exerted on the master cylinder of the hydraulic lift to support the weight of car is 147.2 N .
The Pascal's Law states that the relation between the pressure , force and area is given as :
Pressure = Force/Area ;
given that the diameter of the master cylinder is = 1.93 cm ;
so radius of master cylinder = 1.93/2 = 0.965 cm = 0.00965 m ;
the diameter of slave cylinder is = 24.9 cm ;
the radius of the slave cylinder = 24.9/2 = 12.45 m = 0.1245 m ;
Area of slave cylinder (A₁)= π(0.1245)² = 0.0486 m²
Area of the master cylinder (A₂) = π(0.00965)² = 0.000292 m² ;
given mass of the car = 2500 Kg ,
the force exerted will be : F = m*a
F₁ = 2500*9.8 = 24500 N ;
F₁/A₁ = F₂/A₂
So , 24500/0.0486 = F₂/0.000292
F₂ = (24500/0.0486)×0.000292
F₂ = 147.2 N
Therefore , the force exerted on the master cylinder is 147.2 N .
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perceiving the color, motion, and form of a bird in flight illustrates a. parallel processing. %. opponent-process theory. q. trichromatic theory. d. serial processing. place theory.
parallel processing perceiving the color, motion, and form of a bird in flight illustrates.
Option a is correct.
The trichromatic hypothesis of colour perception is what?According to the trichromatic theory, our ability to perceive red, green, and blue hues as well as how they affect our cerebral activity are both explained by cones (Like a projection T.V.). Consequently, the precise colour we see is determined by the proportion of each colour to the others.
What foundation does trichromatic theory have?The three kinds of cone receptors that are responsible for colour vision are the foundation of the trichromatic hypothesis of colour vision. Beginning in the 18th century, this hypothesis has a very long history.
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1. a 1.4 x 103 kg car is westbound at a velocity of 37.0 km/h when it collides with a 2.0 x 103 kg truck northbound at a velocity of 35 km/h. if these two vehicles lock together upon collision, what is the initial velocity of the vehicles after collision? (7.2 m/s 37o w of n) 2. a 6.2 kg object heading north at 3.0 m/s collides with an 8.0 kg object heading west at 3.5 m/s. if these two masses stick together upon collision, what is their velocity after collision? (2.4 m/s 56o w of n) 3. a 4.0 x 104 n truck moving west at a velocity of 8.0 m/s collides with a 3.0x104 n truck heading south at a velocity of 5.0 m/s. if these two vehicles lock together upon impact, what is their velocity?(5.0 m/s 25o s of w)
The velocity of vehicles after the collision is 15.82m/sec if car mass is 1.4 × 10³kg and truck mass is 2×10³kg
We know that we need to conserve the momentum of watermelon in a certain direction. Also,we know that initial momentum of watermelon is zero,it means that according to law of conservation of momentum final momentum should be zero.
We know that momentum =mass × velocity
So,initial momentum of car is =1.4 × 10³kg × 37km/hr
Similarly,,initial momentum of truck=2×10³kg × 35km/hr
Now,it is given that both vehicles lock together,so total mass of both vehicles is =1.4 × 10³kg + 2×10³kg=3.4 ×10³kg
Assume final velocity of both vehicle is v
So,following the law of conservation,we get
=>1.4 × 10³kg × 37 + 2×10³kg × 35 = 3.4 ×10³ ×v
=>51.8 ×10³ + 2×10³=3.4×10³ ×v
=>53.8 ×10³ kg-m/sec = 3.4×10³ ×v
=>v = 53.8/3.4
=>v=15.82m/sec
Hence,final velocity of both vehicle after collision is 15.82m/sec.
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a 23-month-old child pulls a pan of hot water off the stove and spills it onto her chest and arms. her mother is right there when it happens. what should the mother do immediately?
When it happens mother should have to do cool the burn with tap water for 10 to 20 minutes immediately.
What are the steps to give first aid to a person with a large burn?Stop the burning process. Cool the burn. Supply pain relief.
Before the arrival of qualified emergency help, you should:
Remove restrictive items such as rings, watches, and bracelets.Use a fresh, cool bandage that is moist to cover the burnt area.Raise your hand so that it is higher than your heart.Is burning from boiling water serious?Pain and skin injury from wet heat or vapors can result from hot water scalding. Because the damaged tissues and cells are destroyed, this kind of burn can be deadly. The heat could even cause your body to go into shock. These burns can be fatal in more severe circumstances.
What should I do right away if I am burned?Cool the burn.
Place the affected area under cool (not cold) flowing water for about 10 minutes. Until the pain goes away, apply a cool, wet cloth to the burned area of the face. If you have a mouth burn from hot food or drink, place a piece of ice in your mouth for a while.
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Newton's third law states that any action will have a(n) _______ and ______ reaction.
Newton's third law states that any action will have a(n) equal and opposite reaction.
a vertical spring scale can measure weights up to 210 n . the scale extends by an amount of 13.5 cm from its equilibrium position at 0 n to the 210 n mark. a fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.15 hz . part a ignoring the mass of the spring, what is the mass m of the fish?
sheesh sheesh
Explanation:
what is the effective spring constant k of the two-spring system? express the effective spring constant in terms of k 1 and k 2 .
The Effective Spring Constant is [tex](\frac{k1k2}{k1 + k2} )[/tex] for a system of 2 springs with spring constant k1 and k2.
What is Spring Constant ?The term "spring constant" refers to the proportional constant k. It gauges the stiffness of the spring. A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length.
Spring constants are available in plural (physics) a quality of a spring that is determined by the force acting on the spring to the displacement it produces.
K stands for the proportionality constant, commonly referred to as the "spring constant." In layman's words, stiffness and strength are shown by the k variable in Hooke's law (F = -kx). An item requires more force to be stretched to a specific length the greater the value of k.
Let the force actiong be F N
then , if k1 is the spring constant of spring 1
F = x1 * k1
or, x1 = F/k1.
Similarly for spring 2
x2 = F/k2
Now x1 + x2 = F (1/k1 + 1/k2)
or effective displacement
X= [tex]F(\frac{1}{k1} + \frac{1}{k2} )[/tex]
or, F = [tex]X * (\frac{k1k2}{k1 + k2} )[/tex]
So the Effective Spring Constant is [tex](\frac{k1k2}{k1 + k2} )[/tex].
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5. if the star sirius emits 23 times more energy than the sun, why does the sun appear brighter in the sky? include the terms luminosity and apparent brightness in your response.
The star Sirius is indeed brighter but our Sun appears to be brighter because it is closer to us.
The intrinsic luminosity of Sirius is exactly 25.4 times more than the sun but if we compare the distances of these stars, Sirius is 8.6 light years away from us and the Sun is just 8 light minutes away from us. This marks the obvious reason why our Sun appears more bright.
Even mathematically, it can be justified as the apparent brightness of any luminous object depends on the inverse square of the distance of that luminous object. Therefore the sun's light energy dominates our sky and we can't see any traces of Sirius from the earth.
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