Answer:
b = 2 x .
(9+2x) (9-2x)
Step-by-step explanation:
Since both terms are perfect squares, factor using the difference of squares formula, a 2 − b 2 = ( a + b ) ( a − b )
Answer:
Step-by-step explanation:
81 - 4[tex]x^{2}[/tex]
notice how this is difference of squares, meaning you can simplify
(9-2x) (9+2x)
if the question is asking to find roots, then you just set this equal to 0, and that means that either 9-2x or 9+2x must be equal to 0.
9-2x = 0 9+2x = 0
9 = 2x 9 = -2x
x = 4.5 x = -4.5
Therefore the two roots of this equation are ±4.5
Compare the ordered pairs of the pre-image to the
image to answer these questions.
Is the dilation an enlargement or reduction?
The point of dilation is about what coordinate?
What is the scale factor?
Pre-image
Answer: Reduction
(0,0)
1/3
Step-by-step explanation:
Answer:
1-reduction
2-(0,0)
3-1/3
Step-by-step explanation:
If a < 0 then the graph opens_____
Answer:
down
Step-by-step explanation:
Assuming this is for a parabola
a>0 the graph opens up
a < 0 the graph opens down
( negative is a frown)
> means the line is curving downwards.
< means the line is curving upwards.
Assuming that this is a parabola, the inequality a > 0 means that the line is curving in a downward form. This inequality will also have a maximum.
Best of Luck!
d = 8 cm
h = 18 cm
What is the surface area of the cylinder
Answer:
144 (If multiplying)
Step-by-step explanation:
18x8=144.
What is the correct answer?
Answer:45
Step-by-step explanation:
Sin^-1= 5÷7
Find the height of a right cylinder with surface area 240π ft2 and radius 5 ft.
The height of the right cylinder is __
ft.
Answer:
h ≈ 2.64ft
Step-by-step explanation:
A = 2πrh + 2πr2
h= A /2πr﹣r = 240 /2·π·5﹣5 ≈ 2.63944ft
Kono Dio Da!!
Which expression is equivalent to (4 + 7(3 + 41)?
-16+37i
12-28i
16-37i
37+16i
Answer:
C
Step-by-step explanation:
If the product of two whole numbers is zero then one number will be (ii) If the product of two whole numbers is zero then both number will be zero (a) OnlyIcanbetrue(b)onlyiicanbetrue(c)Bothcanbetrue(d)botharefalse
Answer:
If the product of two numbers is zero, there are two possibilities, namely;
1. One of the numbers is zero.
2. Both of the numbers are zero.
Step-by-step explanation:
As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.
Therefore,
1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,
153, 000 * 0 = 0
2. If both of the numbers are zero, then the product of the two numbers is zero. For example,
0 * 0 = 0.
So we can say that both can be true.
The student body of 10 students want to elect a president, vice president, secretary, and treasurer.
A) Permutation
B) Combination
C) Circular permutation
Answer:
a
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
I am donating packages for Christmas drive. After the first week, I spent 126 to donate three children packages and 8 adult packages. After two weeks I spent 108 to donate six children packages and 4 adult packages. What is the price of each type of package
Answer:
Step-by-step explanation:
Let the price for children and adults package be represented with x and y respectively.
For the first week the sum of the package will be as follows:
3x+8y = 126
For the two weeks after:
6x+4y= 108
So, we will be having two equations
3x+8y = 126..... (1)
6x+4y= 108.......(2)
These are simultaneous equations
From equation 1
3x+8y = 126
3x = 126-8y
X = 126-8y/3 ............. (3)
Put equation 3 into 2
6 ( 126-8y)/3 +4y = 108
756-48y/3 +4y = 108
756-48y+12y/3 = 108
Cross multiplying
756-48y+12y= 108×3
756-48y+ 12y = 324
Collecting like terms
756-324 = 48y-12y
432= 36y
Divide both sides by 36
432/36 = 36y/36
y= 12
Substituting y into equation 1
3x+8= 126
3x+96=126
3x= 126-96
3x= 30
Divide both sides by 3
3x/3 = 30/3
x = 10
Hence for each of the packages for children and adults. It will be 10 and 12 respectively.
The combined weight of Maia and Vashti is 102.45kg. If Maia weighs 2.15kg more than Vashti, calculate Vashti's weight.
Answer:
50.32 I think
Step-by-step explanation:
52,13+50,32=102.45
BE5-3 Cha Company buys merchandise on account from Wirtz Company. The selling price of the goods is $780, and the cost of the goods is $470. Both companies use perpetual inventory systems. Journalize the transaction on the books of both companies.
Answer:
In the books of Wirtz, the selling party, the required entries are
Debit Accounts receivable $780
Credit Revenue $780
Being entries to recognize sales revenue on account
Debit Cost of sales $470
Credit Inventory $470
Being entries to recognize the cost of items sold
In the books of Cha Company
Debit Inventory $780
Credit Accounts payable $780
Being entries to record cost of inventory purchased
Step-by-step explanation:
When a company makes a sale, the effect of such sale is dual in the books of the company being that the company would first recognize revenue and then recognize the cost of items sold.
To recognize revenue,
Debit Cash/Accounts receivable
Credit Revenue
To record the cost of the item sold
Debit Cost of sales
Credit Inventory
For the party that makes the purchase
Debit Inventory
Credit Cash/Accounts payable
Can you please help me with this question please i will give you. a Brainiest
Answer:
q < 5
Step-by-step explanation:
GEOMETRY DESPERATE HELP
==========================================================
Explanation:
The center is at (0,2). So (h,k) = (0,2) leads to h = 0 and k = 2.
The radius is 2 units, meaning r = 2.
Plug h = 0, k = 2, r = 2 into the formula below and simplify
[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-0)^2 + (y-2)^2 = 2^2\\\\x^2 + (y-2)^2 = 4[/tex]
Which expressions are equivalent to g+h+(j+k) Check all that apply
Answer:
g+h+(j+k)
Step-by-step explanation:
(g+h)+j+k
(g+k)+j+h
(g+j)+h+k
(k+h)+j+h
(j+h)+g+k
Answer:
1 and 3
Step-by-step explanation:
dont mind me this needed to be longer wait still needs no be longer
At the beginning of the month, Tim has $50. He mows 2 lawns and washes 1 car. Then, he buys two video games that cost $15 each and a sweatshirt that costs $35. How much money does Tim have left? (please put just your answer with the $)
Answer:
Tim has $50. 15+15=30-35=5
Tim has $5 left
The expression two square root of three minus square root of 27 is equivalent to
Answer:
-0.954(rounded)
Step-by-step explanation:
first write it in number form
√2(3)-√27
the exact form will be 3√2-3√27 = -0.954(rounded)
Una escalera está apoyada sobre la fachada de un edificio. Si la escalera mide 10 m de longitud y el pie de la escalera está a 5 m de la pared, ¿a qué altura de la pared llega la escalera? Expresa el resultado con radicales extrayendo todos los factores posibles.
Answer:
8.66 meters
Step-by-step explanation:
Assuming that the building is completely straight, a right angle is formed and therefore a right triangle.
Thanks to this we can calculate the height at which the ladder reaches the wall using the Pythagorean theorem, this height being one of the legs.
We have to:
c ^ 2 = a ^ 2 + b ^ 2
c = 10
a = 5
replacing
b ^ 2 = 10 ^ 2 - 5 ^ 2
b ^ 2 = 75
b = 8.66
that is to say that the height at which the ladder reaches the wall is 8.66 meters
Need help ASAP, marking first as brainliest. Rlly appreciate it.
Answer:
Choose answers B and D
Step-by-step explanation:
Answer:
Choose answers B and D.
Step-by-step explanation:
What is the distance between points A(13, 2) and B(7, 10)
Answer:
distance = sqrt((x2-x1)^2 + (y2-y1))
distance = sqrt((7-13)^2 + (10-2)^2)
distance = sqrt( -6^2 + 8^2)
distance = sqrt(36+64)
distance = 10
Step-by-step explanation:
Answer:
10 units
Step-by-step explanation:
d = [tex]\sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]
d = [tex]\sqrt{(13 - 7)^2 + (2 - 10)^2}[/tex]
d = [tex]\sqrt{(6)^2 + (-8)^2}[/tex]
d = [tex]\sqrt{36 + 64}[/tex]
d = [tex]\sqrt{100}[/tex]
d = 10 units
How do I solve this problem? I need to find the volume of this composite figure.
Step-by-step explanation:
V = (12*4*5) + (2*3*5) + (5*3*5) + (12*4*5)
V = 240 + 30 + 75 + 240
V = 585 cm^3
Solve for x. 2x + 3 =9
Answer:
x=3
Step-by-step explanation:
- 3 on both sides
2x=6
divide by 2 on both sides
x=3
Answer:
x = 3
Step-by-step explanation:
[tex]2x+3=9[/tex]
Subtract 3.
[tex]2x=9-3\\2x=6[/tex]
Divide by 2.
[tex]x=\frac{6}{2}\\ x=3[/tex]
Divya’s recipe calls for 3.25 pounds of beef, 0.65 pounds of onions, 0.2
pounds of potatoes, 0.15 pounds of tomatoes, and 0.33 pounds of asparagus.
How much will Divya pay for all the ingredients in the recipe? Show your work.
The beef price is $10.65
Onions price is $2.49
Potatoes are $3.29
Tomatoes are $8.45
Asparagus is $4.99
3.25 pounds of beef is 3.25 * 10.65 = 34.61
0.65 pounds of onions is 0.65 * 2.49 = 1.62
0.2 pounds of potatoes is 0.2 * 3.29 = 0.66
0.15 pounds of tomatoes is 0.15 * 8.45 = 1.27
0.33 pounds of asparagus is 0.33 * 4.99 = 1.65
Adding these up we get 34.61 + 1.62 + 0.66 + 1.27 + 1.65
This is equal to 39.81
A recipe is mixture of ingredients.
Divya will pay $39.81 for all the ingredients in the recipe.
The beef price is $10.65 per pound
So, price of 3.25 pounds of beef is , [tex]3.25 * 10.65 = 34.61[/tex]
Onions price is $2.49 per pound
So, price of 0.65 pounds of onions is, [tex]0.65 * 2.49 = 1.62[/tex]
Potatoes are $3.29 per pound
So, price of 0.2 pounds of potatoes is , [tex]0.2 * 3.29 = 0.66[/tex]
Tomatoes price are $8.45 per pound.
So, price of 0.15 pounds of tomatoes is , [tex]0.15 * 8.45 = 1.27[/tex]
Asparagus price is $4.99 per pound.
So, price 0.33 pounds of asparagus is , [tex]0.33 * 4.99 = 1.65[/tex]
Hence, total amount paid by Divya is,
[tex]=34.61 + 1.62 + 0.66 + 1.27 + 1.65=39.81[/tex]
Thus, Divya will pay $39.81 for all the ingredients in the recipe.
Learn more:
https://brainly.com/question/18994792
Find the volume of the figure
Answer:
450
Step-by-step explanation:
Four students spoke to the Home and School parents for a total of 2/3 hour. Each student spoke for the same amount of time. How long did each student speak?
creo que la respuesta el 10 minutos, porque dice "horas" pero no dice a cuantas horas equivale :) espero que te aya adudado auque sea un poquito
PLEASE HELP!!!! NEED ANSWER ASAP
Answer:
X=25
Step-by-step explanation:
Since these 2 angles are vertically opposite angles so they are equal. (rule)
75°=(4x-25°)
75° + 25° = 4x
100=4x
X=100/4 = 25
___________
Hope this helps...
Whats the answer plz??
Answer:
C
Step-by-step explanation:
Absolute Value is the distance from 0, so when you have -|22| that means its the absolute value of 22 then add the negative sign so that means it's further from 0 than |-22|.
I hope this will help.
Secant TQ and tangent TR intersect at point T. Chord SR and chord PQ intersect at point V. Find the values of x and y. If necessary, round to the nearest tenth.
Answer:
x=4, y=9.6
Step-by-step explanation:
Using Theorem of Intersecting Secant and Tangent
[tex]TP X TQ=TR^2[/tex]
[tex]9(9+12+x)=15^2\\9(21+x)=225\\189+9x=225\\9x=225-189\\9x=36\\x=4[/tex]
Next, we apply Theorem of Intersecting Chords
SV X VR=PV X VQ
5 X y = x X 12
Recall: x=4
5y=4 X 12
5y=48
y=48/5=9.6
Therefore: x=4, y=9.6
PLZ HELP I ONLY HAVE 11 points left and I need help with this question plz :( It's URGENT
Answer:
16 units
Step-by-step explanation:
The y intercept is when the x value is 0
f(0) = 2(0)+8 = 8
The y intercept of f(x) is 8
g(0) = -8
The y intercept of g(x) is -8
The distance between f(0) and g(0)
8 - -8 = 8+8 = 16
how much money does ron have each month
Answer:
after paying all expenses Ron will have $10 leftover each month.
Answer:
10 on edge
Step-by-step explanation:
1. If 5tanA=4, Find the value of (5sinA-3cosA)/(4cosA+5sinA)
2. Solve for θ, sinθ/(1+cosθ) + (1+cosθ)/sinθ =4, 0°<θ<90°
3. Prove that tan〖θ-cotθ 〗 = (〖2sin〗^2 θ-1)/sinθcosθ
4. Without using trigonometric tables ,show that
tan 10°tan15°tan75°tan80°=1
5. If x=acosθ-bsinθ and y=asinθ + bcosθ prove that x^2+y^2=a^2+b^2
Answer:
1. (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8
2. θ = 30°
3. tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))
from tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ) and sin²(θ) + cos²(θ) = 1
4. tan10°·tan15°·tan75°·tan80°= 1 from;
sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]
cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]
5. x² + y² = a² + b² where x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ from;
cos²θ + sin²θ = 1
Step-by-step explanation:
1. Here we have 5·tan(A) = 5·sin(A)/cos(A) = 4
∴ 5·sin(A) = 4·cos(A)
Hence to find the value of (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) we have;
Substituting the value for 5·sin(A) = 4·cos(A) into the above equation in both the numerator and denominator we have;
(4·cos(A) - 3·cos(A)/(4·cos(A) + 4·cos(A)) = cos(A)/(8·cos(A)) = 1/8
Therefore, (5·sin(A) - 3·cos(A)/(4·cos(A) + 5·sin(A)) = 1/8
2. For the equation as follows, we have
[tex]\frac{sin \theta}{1 + cos \theta} + \frac{1 + cos \theta}{sin \theta} = 4[/tex] this gives
[tex]\frac{2sin (\theta/2) cos (\theta/2) }{2 cos^2 (\theta/2)} + \frac{2 cos^2 (\theta/2)}{2sin (\theta/2) cos (\theta/2) } = 4[/tex]
[tex]tan\frac{\theta}{2} + \frac{1}{tan\frac{\theta}{2} } = 4[/tex]
[tex]tan^2\frac{\theta}{2} + 1 = 4\times tan\frac{\theta}{2}[/tex]
[tex]tan^2\frac{\theta}{2} - 4\cdot tan\frac{\theta}{2} + 1 = 0[/tex]
We place;
[tex]tan\frac{\theta}{2} = x[/tex]
∴ x² - 4·x + 1 = 0
Factorizing we have
(x - (2 - √3))·(x - (2 + √3))
Therefore, tan(θ/2) = (2 - √3) or (2 + √3)
Solving, we have;
θ/2 = tan⁻¹(2 - √3) or tan⁻¹(2 + √3)
Which gives, θ/2 = 15° or 75°
Hence, θ = 30° or 150°
Since 0° < θ < 90°, therefore, θ = 30°
3. We have tan(θ) - cot(θ) = tan(θ) - 1/tan(θ)
Hence, tan(θ) - 1/tan(θ) = sin(θ)/cos(θ) - cos(θ)/sin(θ)
∴ tan(θ) - 1/tan(θ) = (sin²(θ) - cos²(θ))/(cos(θ)×sin(θ))...........(1)
From sin²(θ) + cos²(θ) = 1, we have;
cos²(θ) = 1 - sin²(θ), substituting the value of sin²(θ) in the equation (1) above, we have;
(sin²(θ) - (1 - sin²(θ)))/(cos(θ)×sin(θ)) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))
Therefore;
tan(θ) - cot(θ) = (2·sin²(θ) -1)/((cos(θ)×sin(θ))
4. tan10°·tan15°·tan75°·tan80°= 1
Here we have since;
sin(α)·sin(β) = 1/2[cos(α - β) - cos(α + β)]
cos(α)·cos(β) = 1/2[cos(α - β) + cos(α + β)]
Then;
tan 10°·tan15°·tan75°·tan80° = tan 10°·tan80°·tan15°·tan75°
tan 10°·tan80°·tan15°·tan75° = [tex]\frac{sin(10^{\circ})}{cos(10^{\circ})} \times \frac{sin(80^{\circ})}{cos(80^{\circ})} \times \frac{sin(15^{\circ})}{cos(15^{\circ})} \times \frac{sin(75^{\circ})}{cos(75^{\circ})}[/tex]
Which gives;
[tex]\frac{sin(10^{\circ}) \cdot sin(80^{\circ})}{cos(10^{\circ})\cdot cos(80^{\circ})} \times \frac{sin(15^{\circ}) \cdot sin(75^{\circ})}{cos(15^{\circ})\cdot cos(75^{\circ})}[/tex]
[tex]=\frac{1/2[cos(80 - 10) - cos(80 + 10)]}{1/2[cos(80 - 10) + cos(80 + 10)]} \times \frac{1/2[cos(75 - 15) - cos(75 + 15)]}{1/2[cos(75 - 15) + cos(75 + 15)]}[/tex]
[tex]=\frac{1/2[cos(70) - cos(90)]}{1/2[cos(70) + cos(90)]} \times \frac{1/2[cos(60) - cos(90)]}{1/2[cos(60) + cos(90)]}[/tex]
[tex]=\frac{[cos(70)]}{[cos(70) ]} \times \frac{[cos(60)]}{[cos(60) ]} =1[/tex]
5. If x = a·cosθ - b·sinθ and y = a·sinθ + b·cosθ
∴ x² + y² = (a·cosθ - b·sinθ)² + (a·sinθ + b·cosθ)²
= a²·cos²θ - 2·a·cosθ·b·sinθ +b²·sin²θ + a²·sin²θ + 2·a·sinθ·b·cosθ + b²·cos²θ
= a²·cos²θ + b²·sin²θ + a²·sin²θ + b²·cos²θ
= a²·cos²θ + b²·cos²θ + b²·sin²θ + a²·sin²θ
= (a² + b²)·cos²θ + (a² + b²)·sin²θ
= (a² + b²)·(cos²θ + sin²θ) since cos²θ + sin²θ = 1, we have
= (a² + b²)×1 = a² + b²