If 50.0 g of KCl reacts with 50.0 g of O2 to produce KClO3 according to the following equation, how many grams of KClO3 will be formed? Word and Formula equation.

If 50.0 G Of KCl Reacts With 50.0 G Of O2 To Produce KClO3 According To The Following Equation, How Many

Answers

Answer 1

Answer:

A. 82.2g of KClO3

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3

C. Formula equation:

2KCl + 3O2 —> 2KClO3

Explanation:

The balanced equation for the reaction. This is given below:

2KCl + 3O2 —> 2KClO3

Next, we shall determine the masses of KCl and O2 that reacted and the mass of KClO3 produced from the balanced equation. This is illustrated below:

Molar Mass of KCl = 39 + 35.5 = 74.5g/mol

Mass of KCl from the balanced equation = 2 x 74.5 = 149g

Molar Mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Molar Mass of KClO3 = 39 + 35.5 + (16x3) = 122.5g/mol

Mass of KClO3 from the balanced equation = 2 x 122.5 = 245g

Summary:

From the balanced equation above:

149g of KCl reacted.

96g of O2 reacted.

245g of KCl were produced.

Next, we shall determine the limiting reactant. This is illustrated below:

From the balanced equation above,

149g of KCl reacted with 96g of O2.

Therefore, 50g of KCl will react with = (50 x 96)/149 = 32.21g of O2.

Since a lesser mass of O2 ( i.e 32.21g) than what was given (i.e 50g) is needed to react completely with 50g of KCl, therefore, KCl is the limiting reactant and O2 is the excess reactant.

A. Determination of the mass of KClO3 produced from the reaction.

In this case the limiting reactant will be used.

From the balanced equation above,

149g of KCl reacted To produce 245g of KClO3.

Therefore, 50g of KCl will react to produce = (50 x 245)/149 = 82.2g of KClO3.

Therefore, 82.2g of KClO3 is produced from the reaction.

B. Word equation:

50g of KCl react with 50g of O2 to produce 82.2g of KClO3.

C. Formula equation:

2KCl + 3O2 —> 2KClO3

Answer 2

The mass of [tex]\rm KClO_3[/tex] produced has been 82.1085 g.

The word equation for the reaction has been: 50 gram potassium chloride reacts with 50 g oxygen to give 82.1085 g potassium chlorate.

The formula equation has been, [tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex].

The balanced chemical equation for the reaction has been given as:

[tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex]

Computation for Mass of Potassium chlorate:

From the balanced chemical equation, 2 moles of KCl reacts with 3 moles of oxygen to give 2 moles of [tex]\rm KClO_3[/tex].

The moles of reactants have been given as:

[tex]\rm Moles=\dfrac{mass}{molar\;mass}[/tex]

The moles of 50 g KCl has been given as:

[tex]\rm Moles\;KCl=\dfrac{50}{74.55} \\Moles\;KCl=0.67\;mol[/tex]

The moles of KCl available has been 0.67 mol.

The moles of 50 g [tex]\rm O_2[/tex] has been given as:

[tex]\rm Moles\;O_2=\dfrac{50}{32}\\Moles\;O_2=1.5625\;mol[/tex]

The moles of 50 g [tex]\rm O_2[/tex] has been 1.5625 mol.

From the balanced equation, for 2 moles KCl, 3 moles oxygen has been required. For 0.67 mol KCl, oxygen required has been:

[tex]\rm 2\;mole\;KCl=3\;moles\;O_2\\0.67\;mol\;KCl=\dfrac{3}{2}\;\times\;0.67\;mol\;O_2\\0.67\;mol\;KCl=1.005\;mol\;O_2[/tex]

The available moles of oxygen has been 1.5625 mol. Thus, oxygen has been excess reactant and KCl has been limiting reactant.

The moles of [tex]\rm KClO_3[/tex] produced has been given as:

[tex]\rm 2\;mol\;KCl=2\;mol\;KClO_3\\0.67\;mol\;KCl=\dfrac{2}{2}\;\times\;0.67\;mol\;KClO_3\\0.67\;mol\;KCl=0.67\;mol\;KClO_3[/tex]

The moles of [tex]\rm KClO_3[/tex] produced has been 0.67 mol.

The mass of [tex]\rm KClO_3[/tex] produced has been:

[tex]\rm Mass=Moles\;\times\;molar\;mass\\Mass\;KCl=0.67\;\times\;122.55\;\\Mass\;of\;KCl=82.1085\;g[/tex]

The mass of [tex]\rm KClO_3[/tex] produced has been 82.1085 g.

The word equation for the reaction has been:

50 gram potassium chloride reacts with 50 g oxygen to give 82.1085 g potassium chlorate.

The formula equation has been, [tex]\rm 2\;KCl\;+\;3\;O_2\;\rightarrow\;2\;KClO_3[/tex].

For more information about chemical equation, refer to the link:

https://brainly.com/question/13350862


Related Questions

The specific heat of iron is 0.107 cal/g x oC. How much heat is transferred when a 24.7 kg iron ingot is cooled from 880 oC to 13 oC?

Answers

Answer:

heat = 229139.43 cal

Explanation:

given data

specific heat of iron is 0.107 cal/g-°C     C = 0.4494 J/g°C;

Mass of iron = 24.7 kg = 24700 g

temperature T1 = 880°C

temperature T2 = 13°C

solution

we know that Heat lost that is express as

heat loss = mcΔT      .........................1

here m is the mass and c is specific heat capacity of iron and ΔT is the change in temperature

so here change in the temperature is = 880°C - 13°C

change in the temperature = 867°C

so put here value and we get

heat  = 24700 × 0.107 cal/g-°C × 867°C

heat = 229139.43 cal

Review the following chemical equation: Find the molar ratio between C6H6 to
carbon dioxide, CO2. 2C6H6 + 1502 YEILDS 6H20 - 12C02

Answers

Answer:

[tex]\frac{1}{6}[/tex]

Explanation:

Molar ratio is defined as the ratio of number of moles of reactants or products in a balanced chemical equation.

In this balanced equation, the number of C6H6 molecules react to form 12 CO2 molecules.

Thus, the molar ratio between C6H6 to  carbon will be equal to 2 moles of  C6H6 divided by 12 moles of CO2

[tex]\frac{2}{12}\\\frac{1}{6}[/tex]

what are the possible values for standard temperature and pressure

Answers

Answer:

0 °C and 1 Atm,

Explanation:

Standard Temperature and Pressure. Standard temperature is equal to 0 °C, which is 273.15 K.

Standard Pressure is 1 Atm, 101.3kPa or 760 mmHg or torr

How is a lithium atom (Li) different from a lithium ion (Li+)?

Li has fewer electrons than Li+
Li has more electrons than Li+
Li has fewer protons than Li+
Li has more protons than Li+

Answers

Answer:

Li has fewer protons than Li+

Li has fewer electrons than Li+

the combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110kg of carbon dioxide what is the limittinf reacrant?

Answers

Answer:

Propane

Explanation:

From the question given, we were told that 0.1240 kg of propane reacted with excess oxygen to produce 0.3110kg of carbon dioxide.

Since the reaction took place in the presence of excess oxygen, therefore, propane is the limiting reactant as all of it is used up in the presence of excess oxygen.

Answer:

The limiting reactant is propane, C₃H₈ and the percentage yield is 83.77%

Explanation:

Mass of propane = 0.1240 kg = 124 g

Mass of carbon dioxide = 0.3110 kg = 311 g

Molar mass of propane = 44.1 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Number of moles of propane = 124/44.1 = 2.812 moles

Number of moles of carbon dioxide = 311/44.01 = 7.067 moles

Equation for the reaction

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Hence 1 mole of propane ideally yields 3 moles of CO₂

Hence, 2.812 moles of propane will yield 3×2.812 moles = 8.44 moles of CO₂

Since, oxygen is in excess, therefore, the limiting reactant = Propane, C₃H₈

The percentage yield = 7.067/8.44× 100 = 83.77%.


(b) Which peak, the one at 365 nm or the one at 435 nm, results from the absorption of
photons with the greater energy? Justify your answer.
(c) Based on the diagram above, is the forward reaction endothermic or exothermic? Justify
your answer in terms of Le Châtelier's principle.

Answers

Answer:

365nm and Exothermic reaction

Explanation:

b) The Einstein Planck's equation states that

E = hf where E is the energy of a photon

                     h  is the Planck's constant

                     f  is the frequency

But Frequency f = c/λ  where c  is the speed of light

                                                  λ  is the wavelength

Therefore Energy E = hc/λ

From the above equation we see that the Energy of a photon is indirectly proportional to its wavelength

Hence as the wavelength increases from 365nm to 435nm, the energy of the photons decreases

Therefore, a photon will wavelength 365nm would have a higher energy than one will wavelength of 435nm.

c) From the diagram we observe the following:

At high temperatures,   HPR⁺ occurs at a higher concentration than at low temperatures.

At low temperatures, more of PR⁻ is formed than at high temperatures

The equation of the reaction is

HPR⁺ (aq) ⁺ ⇆ H⁺ + PR⁻(aq)      

Le Chartelier's principle states that when an external constraint such as a change in concentration, pressure or temperature is placed on a system in equilibrium, the system acts in such a way as to oppose the change.

Hence a decrease in temperature on the side of reactant, HPR would force the equilibrium to the side of the products, PR in other to accommodate the change

The forward reaction, which produces more of the product PR⁻ is exothermic because  the at low temperatures, the the forward reaction is favoured and equilibrium shifts to the right.

How many atoms are there in 2 moles of helium?

Answers

Answer:

1 mole Of Helium = Weight of Helium/4Weight of Helium = 1*4 = 4 grams 1 mole of Helium contains 6.023*10²³ ( Avogadro number) atoms. Number of moles of in 4 grams of Hydrogen 4 grams is = given weight / molecular weight of Hydrogen (H₂) = 4/2 =2 Number of atoms/molecules in 2 moles of Hydrogen is (2*6.023*10²³) atoms. = 12.046*10²³ atoms.

(Hope this helps)

The number of atoms in 2 moles of helium is 1.204×10²⁴ atoms

From Avogadro's hypothesis,

1 mole of any substance = 6.02×10²³ atoms

Thus,

1 mole of helium = 6.02×10²³ atoms

With the above information in mind, we can obtain the number of atoms in 2 moles of helium as follow:

1 mole of helium = 6.02×10²³ atoms

Therefore,

2 moles of helium = 2 × 6.02×10²³ atoms

2 moles of helium = 1.204×10²⁴ atoms

Thus, we can conclude that 2 moles of helium contains 1.204×10²⁴ atoms

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modern vacuum techniques make it possible to reach a pressure of 1.00 * 10 ^ -10 mm Hg in a laboratory system. what volume in milliliters would 1.00 * 10 ^ 6 molecules of gas occupy at this pressure and standard temp?​

Answers

Answer:

around 0.283

Explanation:

What is the percent yield of C when 35 g CS₂ are reacted and produce 36.4 g C. * LABEL THE LIMITING REACTANT IN YOUR WORK.* Use the following balanced chemical equation to solve the problem: CS₂ + 4 CO --> 5 C + 2 SO₂ *

Answers

Answer:

Limiting reactant is CS2

% yield = 131.8 %

Explanation:

Using the alanced equation given, Mole ratio of C to CS2 is 1 : 5.

That is, for every 1 mole of CS2 used, 5 moles of Carbon is produced.

35g of CS2 --- [tex]\frac{35}{76.14}[/tex] moles

= 0.4597 moles

⇒ mass of C produced = 5 × 0.4597 × 12 g/mol

= 27.6 g of C.

Percentage yield (%) = [tex]\frac{actual- yield}{theoretical- yield}[/tex]

= [tex]\frac{36.4}{27.6} * 100[/tex] =131.9%

What is El Nino and La Nina explained? Please help fast

Answers

Answer:

el nino: the boy

la nina: the girl

Explanation:

Answer:

el nino is dinosour la nino is fishcat

Explanation:

Katie throws a 3 kilogram ball fast at a speed of 15 meters what is the momentum of the ball katie threw

Answers

Answer:

Hey!

Your answer is 45kg.m/s

Explanation:

Using the formula P=M x V

(p=momentum...M=mass...V=velocity)

We do M x V

15 x 3

Which gives us an answer of 45kg.m/s!

HOPE THIS HELPS!!

PLEASE HELP :"( DUE NOW!!

What is the equation for the equilibrium constant for this equation?


CO+3H2⇌CH4+H2O



[H2O][H2]/[CH4][CO]



[CO][H2]3/[CH4][H2O]



[CH4][H2O]/[CO][H2]3



[CH]4[H2O]/[H2]3

Answers

Answer:

The correct answer is  

[CH4][H2O]/[CO][H2]3

Option 3 is correct

Explanation:

Step 1: Data given

For the equation aA + bB ⇆ cC + dD

The equilibrium constant is [C]^c * [D]^d / [A]^a*[B]^b

Step 2: Calculate the equilibrium constant Kc

CO+3H2⇌CH4+H2O

Kc = [H2O][CH4] / [CO][H2]³

The correct answer is  

[CH4][H2O]/[CO][H2]3

Option 3 is correct

________________ substances have an equal amount of H+ and OH- ions in solution.

Answers

A neutral solution will have H+ ions equal to OH- ions. I think this should be the answer hhhh

Answer:

Water, and other neutral

Explanation:

That means those substances have pH = 7.

When the amount of H+ is more than the amount of OH- in solution, the substance is acidic ( eg.: Lemon juice ). pH < 7

When the amount of H+ is less than the amount of OH- in solution, the substance is basic ( eg.: Baking soda ). pH > 7

How many total atoms from Carbon are present on the reactant side?
20 points
2CH2+202
O2+HC4
5
2
1
3

Answers

Answer:

2 carbon atoms/molecules are present on the reactant side.

hope it helps!

Use the information provided in the table to determine the Kb for acetate ion, the conjugate base of acetic acid. 1.8 × 10-19 5.6 × 10-10 2.8 × 10-9 1.8 × 1010

Answers

Answer:

B. 5.6 × 10^-10

Explanation:

The Kb for the acetate ion can be obtained from; Kb = [CH3COOH] [OH-]/[CH3COO-]

The Kb of acetate ion

The term Kb refers to the base dissociation constant of a substance. We know that the Kb for the acetate ion can be obtained from;

Kb = [CH3COOH] [OH-]/[CH3COO-]

The numerical value of the Kb can be obtaned if we have the concentrations of the various species in the equation above.

Learn more about Kb: https://brainly.com/question/19165803

#SPJ2

please helpppppppppp

Select the TRUE statements about the carbon cycle

The carbon cycle is the process in which carbon travels from the atmosphere into organisms and the Earth and then back into the atmosphere.
Plants take carbon dioxide from the air and use it to make food.
Animals eat food and the carbon is stored in their bodies or released during cellular respiration.
Water (H2O) is cycled around the Earth

Answers

the carbon cycle is the process in which carbon travels from the atmosphere into organisms and the earth and then back into the atmosphere

The oxidation number of bromine in bromine gas is _____. A. 0 B. +1 C. –1 D. –2

Answers

Answer:

the answer is 0

The answer to the question is

A. 0


Which is usually associated with a slower reaction rate?
A. using a whole solid in the reactants
B. adding heat energy to the reactants
C. adding food coloring to the reactants
D. using a strong solution of the reactants

Answers

A. Using a whole solid in the reactants
using a whole solid in the reactants

How much NaOH (in grams) is needed to prepare 463 mL of solution with a pH of 10.020?

Answers

Answer: [tex]1.94\times 10^{-3}g[/tex] of NaOH

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

[tex]pH=-\log [H^+][/tex]

Putting in the values:

[tex]10.020=-\log[H^+][/tex]

[tex][H^+]=9.55\times 10^{-11}[/tex]

[tex][H^+][OH^-]=10^{-14}[/tex]

[tex][OH^-]=\frac{10^{-14}}{9.55\times 10^{-11}}=1.05\times 10^{-4}M[/tex]

[tex]NaOH\rightarrow Na^++OH^-[/tex]

[tex]Molarity=\frac{moles\times 1000}{\text {Volume in ml}}[/tex]

[tex]1.05\times 10^{-4}M=\frac{moles\times 1000}{463ml}[/tex]

moles = [tex]4.86\times 10^{-5}[/tex]

Mass of [tex]NaOH=moles\times {\text {Molar mass}}=4.86\times 10^{-5}\times 40=1.94\times 10^{-3}g[/tex]

Thus [tex]1.94\times 10^{-3}g[/tex] of NaOH is needed to prepare 463 mL of solution with a pH of 10.020

when the surface of a mirror curves inward, like the inside of a bowl, it is called a ____.
A) plane mirror
B) convex mirror
C) concave mirror
D) diffuse mirror

Answers

Answer:

C

Explanation:

The answer is always C

Answer:C. Concave mirror

Explanation:

When the surface of a mirror curves inward, like the inside of a bowl, it is called c. Concave mirror.

Create a Element #Brainliest Challenge

Rules- It must Have Atomic mass and Number and it's Fictional name you created

For Fun Add #GoGenius​

Answers

Answer:

NeHe

Explanation:

Atomic Mass: 24.182302

Number: 18

I don't know, I just made it up.

how does the sun light affect earths climate

Answers

Answer:

The Sun powers life on Earth; it helps keep the planet warm enough for us to survive. It also influences Earth’s climate: We know subtle changes in Earth’s orbit around the Sun are responsible for the comings and goings of the past ice ages. But the warming we’ve seen over the last few decades is too rapid to be linked to changes in Earth’s orbit, and too large to be caused by solar activity

Explanation:

What is the correct answer? Please

Answers

Answer:

c

Explanation:

How could you determine if a car door is made of a material, such as plastic?

Answers

Answer:Most cars have the visible outer panel, and supporting structure, made from steel. Some use aluminium, at least one series-produced model had magnesium doors, and there are also doors where the visible parts are plastic or fiberglass, with some sort of metal inside for strength.

Explanation:

Answer:

Most cars have the visible outer panel, and supporting structure, made from steel. Some use aluminium, at least one series-produced model had magnesium doors, and there are also doors where the visible parts are plastic or fiberglass, with some sort of metal inside for strength.

balancing equations

Answers

Answer:

4. 1HCL + 1NAOH- I NACL+1H2O

Explanation:

there is 2 hydrogens on the left side of the equation, balancing out to the other side of the equation. everything else would be balanced out too

Balance the following equation by adding the correct mole numbers.
P⁴+Cl²->PCl³​

Answers

Hey there!

P₄ + Cl₂ → PCl₃

First, let's balance Cl.

There are 2 on the left, and 3 on the right.

To balance this, let's put a coefficient of 3 in front of Cl₂ and a coefficient of 2 in front of PCl₃.

P₄ + 3Cl₂ → 2PCl₃

Now we have 6 on the left and 6 on the right.

Next, let's balance P.

There are 4 on the left and 2 on the right.

Let's change the coefficient in front of PCl₃ from 2 to 4.

P₄ + 3Cl₂ → 4PCl₃

There are now 4 P on each side.

However, now Cl is unbalanced, with 6 on the left and 12 on the right.

We can change the coefficient in front of Cl₂ from 3 to 6.

P₄ + 6Cl₂ → 4PCl₃

So now, we have 4 P on each side and 12 C on each side.

This is our final balanced equation.

Hope this helps!

Answer:

1:1

Explanation:

Took test

Which formula represents an isomer of CH3−CH2−COOH?


CH3−CO−O−CH3


CH3−CO−CO−CH3


CH3−C−OH−CH3

CH3−CH2−CO2−CH3

Answers

Answer:

CH3−CO−O−CH3

Explanation:

i just took the test

Relate dark matter to the development of the universe after the Big Bang. In 3-5 sentences, speculate on how the development of the universe would have been different if there had been no dark matter. In your answer, use the term structures.

Please answer this and ill mark you as brainliest

Answers

Answer:

Dark matter also called baronic matter is the matter that makes up 27% of the universe.

In 1933 it was determined as that mass that cannot be seen, that is, the non-visible mass of outer space.

Dark matter also plays a central role in the formation of structures and the evolution of galaxies and has measurable effects on the anisotropy of cosmic microwave background radiation. The composition of this matter is unknown today.

The dark matter component has considerably more mass than the "visible" component of the Universe.

Explanation:

There are certain researchers who say that the appearance of dark matter was before the appearance of the big bang.

A relevant fact of this matter is that dark matter exerts gravity, and that gravity affects the movements of objects.

Despite the fact that nothing is known about its origin, astronomers have amply demonstrated that dark matter plays a determining role in the formation of galaxies and galactic clusters, which could not maintain their cohesion without its existence, but many doubt that it is the remainder / remnant or product of a big bang.

What is the answer ?

Answers

Answer:

b

Explanation:

Electromagnetic waves are waves that have no medium to travel whereas mechanical waves need a medium for its transmission.

ASAP NEED HELP PLSSS
A gas occupying a volume of 3.75L at a pressure of 0.980 arm is allowed to expand at constant temperature until its pressure reaches 0.641 atm. What is the final volume of the sample?

Answers

Answer:

Volume = 5.73L

Explanation:

Data;

V1 = 3.75L

P1 = 0.980atm

P2 = 0.641atm

V2 = ?

This question involves the use of Boyle's law, which states that, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

Mathematically,

V = kP, k = PV

P1V1 = P2V2 =P3V3=........=PnVn

P1V1 = P2V2

V2 = (P1 * V1) / P2

V2 = (0.980 × 3.75) / 0.641

V2 = 5.73L

The final volume of the gas is 5.73L

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