Answer:
What evidence supports their claim.
Explanation:
In the end, all that really matters in an experiment, is what scientific evidence supports the claim being made.
Answer:
What evidence supports their claim.
Explanation:
Ok I am done waiting for an answer for 5 hours can somebody PLEASE PLEASE PLEASE help me TIMED ASSESMENT HERE!!!! PLEASE
A graph titled Speed as a Function of Time with horizontal axis time (seconds) and vertical axis speed (meters per second). A straight orange line labeled A starts at 0 seconds 4 meters per second and runs to 6 seconds 7 meters. A straight blue line labeled B starts at 0 seconds 4 meters and upward to 6 seconds 4 meters. A straight green line starts at 0 seconds 4 meters and runs to 4 seconds 0 meters.
Use the graph of speed versus time to answer the questions about acceleration.
Which of the cars is speeding up?
Which of the cars is slowing down?
Which of the cars is maintaining a constant speed?
Answer:
Explanation:
I'm going to assume that all the givens are in m/s. If I am correct, The orange line is speeding up. It is going from 4 m/s to 7 m/s. Its slant is from lower left to upper right. It is increasing in speed.
The green line is slowing down. It is going from 4 to 0 m/s. It's slant is from upper left to lower right.
The blue line is horizontal. It is neither slowing down or speeding up.
Answer:
sorry for being very very very late, but here is your answer)
car speed A
car slow down C
car constant speed B
hope this helped!!!!
What is the steady state rate of heat flow through a pane of glass that is 40.0 cm by 30.0 cm with a thickness of 4.00 mm when the outside temperature of the glass is −10.0℃ and its inside temperature is 25.0℃? The thermal conductivity of glass is 0.105 W/(m⋅K); the specific heat of glass is 0.180 cal/(g⋅℃); and 1 cal = 4.190 J.
Answer:
110.25 watt/s
Explanation:
The rate of heat transfer is given by the formula
R = k*A(T1 - T2) / d, where
k = thermal conductivity, 0.105 (W/(m*K)
d = thickness, 4 mm = 0.004 m
T1 = inside temperature, 25° C
T2 = outside temperatures, -10° C
A = area 0.3 * 0.4 = 0.12 m²
Now, applying the given data to the formula, we have
Rate = 0.105 * 0.12 (25 - -10) / 0.004
Rate = 0.105 * 0.12(35) / 0.004
Rate = 0.105 * 4.2 / 0.004
Rate = 0.441 / 0.004
Rate = 110.25 Watt/s
Therefore, the steady state rate of heat flow is 110.25 watt/s
In an open circuit like the picture
A. the light bulb will produce light
B. a resistor controls the flow of current
C. the light bulb will be off
D. current will flow
In an open circuit like the picture the light bulb will be off. So, option (C) is correct.
What is electric circuit?Electric circuit is a way for current to flow through electricity. An electric circuit consists of a source of energy for the charged particles that make up the current, like a battery or generator; sources of current-using equipment, like lamps, electric motors, or computers; and the connecting wires or transmission lines.
Ohm's law and Kirchhoff's rules are two of the fundamental mathematical laws that define how electric circuits function.
In the given diagram, the circuit is open. So, no current passes through it and the light bulb will be off. Hence, option (C) is correct.
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A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.
what is the name of this element?
Answer:
fluorine is the right answer of this question
What are Newton’s 3 laws of motion?
Answer: It states that for every action, there is an equal and opposite reaction.
I hope this helps, and Happy Holidays! :)
When will the Social Security fund dry up at its current level?
A.
2022
B.
2027
C.
2042
D.
2097
E.
2117
Answer:
C. 2042
Explanation:
trust me I know the answer
In 2042 the Social Security fund will dry up at its current level. The correct option is C.
The answer is not entirely clear, as projections can vary depending on various economic and demographic factors. However, based on the 2021 Social Security Trustees Report, the projected depletion date for the Social Security Trust Fund is 2034. This means that at the current rate of payouts and contributions, the Trust Fund will only be able to pay out about 78% of scheduled benefits after 2034.
Therefore, the closest option to the projected depletion date of the Social Security Trust Fund is C. 2042. However, it is important to note that this projection may change as economic and demographic factors change over time.
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*
If a rock falls for 3 seconds off of a bridge, how far will the rock fall?
-30 m
-45m
-60m
-75m
If an atom contains 13 protons, then it has (2.4)a.13 electrons. b. 26 electrons. c. 13 neutrons. d.26 neutrons.
Answer:
A, 13 electrons.
Explanation:
The number of protons is equal to the number of electrons.
A truck pushes a pile of dirt horizontally on a frictionless road with a net force of
20
N
20N20, start text, N, end text for
15.0
m
15.0m15, point, 0, start text, m, end text.
How much kinetic energy does the dirt gain?
Answer:
300 JoulesExplanation:
This is a common question on Khan Academy's "Calculating change in kinetic energy from a force" practice exercises. (AP Physics 1)
The simplest method to use is the following: [tex]W = F * d * cos(theta)[/tex], where W represents work (joules), F represents force (newtons), d represents distance (meters), and theta represents the angle of the force that's being applied.In this scenario, the force being applied is horizontal, so we can remove the [tex]cos(theta)[/tex] from our equation.So, our equation is now: [tex]W = F * d[/tex]. This would mean that [tex]W = 20 * 15[/tex], which is equal to [tex]300[/tex]. Our answer is 300 joules. (this value is positive and not negative because kinetic energy is being GAINED, not LOST)Here's the real question without all the formatting:
A truck pushes a pile of dirt horizontally on a frictionless road with a net force of 20 N for 15.0 m. How much kinetic energy does the dirt gain?A truck pushes a pile of dirt in the horizontal direction with a force of 20 N to a distance of 15 m then the kinetic energy of the dirt is 300 J.
What is work?In physics, the term "work" refers to the measurement of energy transfer that takes place when an item is moved over a distance by an externally applied, at least a portion of which is applied inside the direction of the displacement.
The duration of the path is multiplied by the component of a force acting along the path to calculate work if the forces are constant. The work W is theoretically equivalent to the pressure f times the range d, or W = fd, to represent this idea. Work is done when a force is applied at an angle of to a displacement, or W = fd cos.
The work done, [tex]W = Force * Displacement[/tex]
W = 15× 20
W = 300 J
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Two identical cylindrical vessels with their bases at the same level each contain a liquid of density 0.980 g/cm3. The area of each base is 4.85 cm2, but in one vessel the liquid height is 0.954 m and in the other it is 1.58 m. Find the work done by the gravitational force in equalizing the levels when the two vessels are connected.
Answer:
Explanation:
Potential energy of vessel with liquid upto height .954 m
= mgh where m is mass , h is height of CG of the liquid and g is acceleration due to gravity
mass = volume x density
= cross sectional area x height x density
potential energy = cross sectional area x height x density x g x height / 2
because CG lies at depth of half the height .
= 4.85 x 10⁻⁴ x .954 x 980 x .954/2 x 9.8
= 2.12 J .
Potential energy of vessel with liquid upto height 1.58 m
= 4.85 x 10⁻⁴ x 1.58 x 980 x 1.58/2 x 9.8
= 5.8 J
Total energy = 2.12 + 5.8 = 7.92 J
when the level becomes equal , common height becomes
(1.58 + .954 )/ 2 = 1.267 m
potential energy of liquid in two cylinders = 2 x 4.85 x 10⁻⁴ x 1.267 x 980 x 1.267/2 x 9.8
= 7.477 J
Work done by gravitational force
= 7.92 - 7.477 = .443 J
Why are doorknobs placed at the edge of a door rather than in the center
Answer: so it can reach the frame
Explanation:
Answer:
To increase force on the door
One of two 25-year-old identical twins begins a trip on a spaceship traveling at 0.8 c while her twin remains on Earth. The twin on Earth tracks her twin's trip for 10 years. After ten years, what age is the twin on the spaceship according to the twin on Earth?
a. 41.7 years old.
b. 35 years old.
c. 31 years old.
d. 37.5 years old.
When a object is electrically charged, ____ have been added or removed.
A) Neutrons
B) Electrons
C)Protons
Answer:
B, electrons.
Explanation:
An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.
what is mean by combination reaction ?
[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]
Those reaction in which two or more substances combine to form a one new substance are called Combination reaction
In this reaction, We can add :
Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.[tex] \underline{\green{\large \sf For\: example :}} [/tex]
[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]
In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.
g A communication system operating at a power of 510 W produces electromagnetic radiation with a wavelength of 10.5 cm . Calculate the number of photons produced by the system per minute.
Answer:
The value is [tex]N = 2.69 *10^{26} \ photons[/tex]
Explanation:
From the question we are told that
The power is [tex]P = 510 \ W[/tex]
The wavelength is [tex]\lambda = 10.5 \ cm = 0.105 \ m[/tex]
Gnerally the number of photon produced is mathematically represented as
[tex]N = \frac{P * \lambda }{ h * c }[/tex]
Here [tex]h[/tex] is the Planck's constant with a value [tex]h = 6.62607015 * 10^{-34} J \cdot s[/tex]
c is the speed of light with value [tex]c = 3.0*10^{8 } \ m/s[/tex]
So
[tex]N = \frac{ 510 * 0.105 }{ 6.62607015 * 10^{-34} * 3.0 *10^{8} }[/tex]
=> [tex]N = 2.69 *10^{26} \ photons[/tex]
What will most likely happen with bar magnets aligned NS NS
Answer:
repel
Explanation:
A uniform hollow spherical ball of mass 1.75 kg and radius 40.0 cm rolls without slipping up a ramp that rises at 30.0° above the horizontal. The speed of the ball at the base of the ramp is 2.63 m/s. While the ball is moving up the ramp, find (a) the acceleration (magnitude and direction) of its center of mass and (b) the friction force (magnitude and direction) acting on it due to the surface of the ramp.
Answer:
2.94 m/s²
3.43 N
Explanation:
To start with, the combination of rotational and translational kinetic energy can be converted to gravity potential energy. So, we will apply this in solving our question.
PE = KE
mgh = ½mv² + ½Iω²
Moment of inertia of a hollow sphere
I = ⅔mr²
We also know that,
ω = v/r, so if we substitute for ω and I, we have
mgh = ½mv² + ½(⅔mr²)(v/r)², simplifying
gh = ½v² + ½(⅔r²)(v/r)², simplifying further
gh = ½v² + ⅓v², adding up
gh = (5/6)v², making h subject of formula
h = 5v²/6g
Now, we substitute for v and g to have
h = 5(2.63)² / 6(9.81)
h = 34.585 / 58.86
h = 0.588 m
To get the distance that the ball rolls on the ramp before stopping, we say
d = 0.588 / sin30.0
d = 0.588 / 0.5
d = 1.176 m
so acceleration is
a = (2.63² - 0²) / 2(1.176)
a = 6.917 - 0 / 2.352
a = 2.94 m/s
B
Neglecting friction, the sphere acts like a point mass and tends to rise.
mgh = ½mv², simplifying
h = v²/2g
h = 2.63² / 2(9.81)
h = 6.917 / 19.62
h = 0.353 m
The work done by the friction force is the same as the rotational kinetic energy of the sphere, so we say
U = KEr
Fd = ½Iω²
Fd = ½(⅔mr²)(v/r)²
Fd = ⅓mv²
F = mv²/3d
where d is the actual distance up the slope the sphere did roll.
The average friction force is thus
F = 1.75(2.63)² / 3(1.176)
F = 1.75 * 6.917 / 3.528
F = 12.1 / 3.528
F = 3.43 N
A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kinetic frictional force is equal to 70 N. Calculate the acceleration of the piano for an applied force of 100 N.
Answer:
a = 0.1 m/s²
Explanation:
If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:[tex]F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)[/tex]
By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:[tex]F_{net} = m* a = 300 Kg * a = 30 N (2)[/tex]
Solving for a:[tex]a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)[/tex]
Bob Beamon's 1968 Olympic long jump set a world record which remains unbroken to this day. This amazing jump resulted from an initial velocity of 9.5 m/s at an angle of 40 degrees from the horizontal.
1. Calculate the initial horizontal velocity (V_ix) to two significant figures:
2. Calculate the initial vertical velocity (V_iy) to two significant figures:
3. Calculate the time needed to reach the highest point of the jump (t_1/2) to two significant figures:
4. Calculate the total time (t_TOT) needed to complete the jump to two significant figures:
5. Calculate the maximum height (h) reached during the jump to two significant figures:
6. Calculate the range (total horizontal distance) of his jump to two significant figures:
Please answer today! Thanks!
Answer:
1.) 7.3 m/s 2.) 6.1 m/s
Explanation:
To calculate the initial horizontal velocity with just degrees and velocity alone is pretty simple. The formula is Velocity*cos(degrees)
eg 9.5*cos(40)
2. To calculate the initial vertical velocity with just degrees and velocity alone is pretty simple. The formula Velocity*sin(degrees)
eg 9.5*sin(40)
WILL MARK BRAINLIEST JUST PLEASE HELP
Answer:
40N in either direction is the answer
Two clear but non-mixing liquids each of depth 15 cm are placed together in a glass container. The liquids have refractive indices of 1.75 and 1.33. What is the apparent depth of the combination when viewed from above?
A. 19.8 cm.
B. 23.1 cm.
C. 9.9 cm.
D. None of these are correct.
Answer:
A. 19.8 cm.
Explanation:
The apparent depth of the combination is
As it mentioned that the two clear but non-mixing liquid having depth of 15 cm that placed in a glass container together
Also the refractive indices would be 1.75 and 1.33
Based on the above information
As we know that
Refractive indices = real depth ÷ apparent depth
1.33 ÷ 1.75 = 15 ÷ apparent depth
So, it would be 19.736842 cm
Now the combination of apparent depth would be
= ( 19.736842 + 15) ÷ (1.75)
= 19.8 cm
hence, the correct option is A.
(35) Calculate the total charge of all the electrons in a copper plate of mass 3.0g,
atomic number z = 29 and atomic mass 63.5g/mol. (Avogadro's no.- 6.02x1023
atoms, e = 1.6x10-1°C)
Given :
A copper plate of mass 3.0g.
Atomic number, z = 29.
Atomic mass, M.M = 63.5 g/mol.
Avogadro's number, [tex]N_a = 6.02\times 10^{23}\ atoms[/tex].
Charge on electron, [tex]e = 1.6\times 10^{-19}\ C[/tex].
To Find :
The total charge of all the electrons.
Solution :
Moles of copper,
[tex]m = \dfrac{3}{63.5}\ moles\\\\m = 0.047 \ moles[/tex]
Number of atoms in 0.047 moles of copper :
[tex]n = 0.047\times 6.02\times 10^{23}\\\\n = 2.83\times 10^{22} \ atoms[/tex]
Since, there are 29 electrons on each atoms.
So, total charge is :
[tex]C = 2.83\times 10^{22}\times 29\times 1.6\times 10^{-19}\ C\\\\C = 131312\ C\\\\C = 1.31 \times 10^5\ C[/tex]
Hence, this is the required solution.
Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal. How long is it in the air?
Given :
Brandon hits a golf ball with an initial velocity of 30 m/s at an angle of 30 above the horizontal.
To Find :
How long is it in the air.
Solution :
We know, the formula of time of flight is :
[tex]T = \dfrac{2usin\ \theta}{g}\\\\T = \dfrac{2\times 30\times sin\ 30^o}{9.8}\\\\T = 3.06\ seconds[/tex]
Therefore, the ball is in air for 3.06 seconds.
The maximum electric field strength in air is 3.0 Mv/m . Stronger electric fields ionize the air and create a spark. What is the maximum power that can be delivered by a 1.5cm diameter laser beam propagating through air?
Answer:
The value is [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]
Explanation:
From the question we are told that
The maximized electric field strength is [tex]E = 3.0 \ MV/m = 3.0 *10^{6} \ V/m[/tex]
The diameter is [tex]d = 1.5\ cm = 0.015 \ m[/tex]
Generally the cross -sectional area is mathematically represented as
=> [tex]A = \frac{\pi * d^2 }{4}[/tex]
=> [tex]A = \frac{3.142 * 0.015^2 }{4}[/tex]
=> [tex]A = 0.0001767 \ m^2[/tex]
Generally the maximum power is mathematically represented as
[tex]P_{max} = \frac{E_{max}^2}{ 2 * \mu_o * c } * A[/tex]
Here c is the speed of light with value [tex]c = 3.0 *10^{8} \ m/s[/tex]
[tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4 \pi *10^{-7} \ H/m[/tex]
[tex]P_{max} = \frac{ (3.0 *10^{6})^2}{ 2 * (4 \pi *10^{-7}) * 3.0 *10^{8} } * 0.0001767[/tex]
=> [tex]P_{max} = 2.11 * 10^{6} \ W[/tex]
The maximum power that can be delivered by a laser beam propagating through air is equal to [tex]2.11 \times 10^6\;Watts[/tex]
Given the following data:
Electric field strength in air = 3.0 Mv/m = [tex]3 \times 10^6\;v/m[/tex]Diameter = 1.5 cm to m = 0.015 meter.Radius = [tex]\frac{Diameter}{2} = \frac{0.015}{2} = 0.0075\;meter[/tex]
Scientific data:
Permeability of free space = [tex]1.25663706 \times 10^{-6}\;H/m[/tex]Speed of light = [tex]3 \times 10^8\;m/s[/tex]To determine the maximum power that can be delivered by a laser beam propagating through air:
First of all, we would solve for the area of the laser beam as follows:
[tex]Area = \pi r^2\\\\Area = 3.142 \times 0.0075^2\\\\Area = 3.142 \times 0.00005625\\\\Area = 1.77 \times 10^{-4}\;m^2[/tex]
Now, we can determine the maximum power that can be delivered by a laser beam:
Mathematically, maximum power is given by the formula:
[tex]P_{max} = \frac{AE_{max}^2}{2 \mu_o c}[/tex]
Substituting the given parameters into the formula, we have;
[tex]P_{max} = \frac{1.77 \times 10^{-4} \;\times \;(3 \times 10^6)^2}{2 \;\times \;1.25663706 \times 10^{-6} \; \times \;3 \times 10^8}\\\\P_{max} = \frac{1.77 \times 10^{-4} \;\times \;9 \times 10^{12}}{753.982236}\\\\P_{max} = \frac{1593000000}{753.982236}\\\\P_{max} = 2.11 \times 10^6\;Watts[/tex]
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how large amount of energy is produced during the fission of uranium
Answer:
answer is a very large amount of energy is produced from a very small mass
Explanation:
nuclear energy is produced either by fusion or fission the former is fusion of lighter atoms into heavier elements while the letter is the splitting of a heavier atom into lighter atoms. both produce tremendous amount of energy fusion causes compassion of mass wild fission reduces it. and produce it. fusion does not produce radioactive particles while fission does (alpha and beta particles and neutrons)
TRUE/FALSE, the scientific question is written like “I wonder if [dependent variable] is affected by [independent variable].”
An aluminum baking sheet with a mass of 225 g absorbs 2.4 x 104 J from an oven. If its temperature was initially 25 C, what will its new temperature be?
Answer:
The value is [tex]T_2 =416.9 \ K[/tex]
Explanation:
From the question we are told that
The mass of the aluminum baking sheet is [tex]m = 225 \ g = 0.225 \ kg[/tex]
The energy absorbed is [tex]E = 2.4 *10^{4} \ J[/tex]
The initial temperature is [tex]T_1 = 25 ^oC = 25 + 273 = 298 \ K[/tex]
Generally the heat absorbed is mathematically represented as
[tex]Q = m * c_a * [T_2 - T_1][/tex]
Here [tex]c_a[/tex] is the specific heat capacity of aluminum with value [tex]c_a = 897 \ J / kg \cdot K[/tex]
So
[tex]2.4 *10^{4 } =0.225 * 897 * [ T_ 2- 298][/tex]
=> [tex]T_2 - 298 = 118.915[/tex]
=> [tex]T_2 =416.9 \ K[/tex]
A car jack works when a mechanic uses a force 3.8 N, on a small piston of radius 10 cm. What force can he exert on a larger piston of radius 0.22 m?
Answer:
18.392 N
Explanation:
Given that,
Smaller force acting on the car, F₁ = 3.8 N
Radius of smaller radius, r₁ = 10 cm = 0.1 m
The radius of the larger piston, r₂ = 0.22 m
We need to find the force exerted on the larger piston. Let it is F₂.
Using the relation,
[tex]\dfrac{F_1}{F_2}=\dfrac{A_1}{A_2}\\\\\dfrac{F_1}{F_2}=\dfrac{\pi r_1^2}{\pi r_2^2}\\\\\dfrac{F_1}{F_2}=\dfrac{r_1^2}{r_2^2}\\\\F_2=\dfrac{F_1r_2^2}{r_1^2}\\\\F_2=\dfrac{3.8\times (0.22)^2}{(0.1)^2}\\\\F_2=18.392\ N[/tex]
Hence, the force exerted on the larger piston is 18.392 N.
A stone dropped from a bridge strikes the water 5.6 seconds later. What is the final velocity in meters/s?
A) 179.78 meters/s
B) 5.71 meters/s
C) 1.75 meters/s
D) 54.88 meters/s
Answer: 54.88 meters/s
Explanation:
The final velocity will be calculated by using the formula:
v = u + at
where,
v = final velocity
u = initial velocity = 0
a = 9.8
t = 5.6
Therefore, we slot the value back into the formula. This will be:
v = u + at
v = 0 + (9.8 × 5.6)
v = 0 + 54.88
v = 54.88 meters per second
Therefore, the final velocity is 54.88m/s
