-5n-4(-7-4n)=36+7n

What is N?

Answer:

[tex]2(a + 1) \times (3a + 5)[/tex]

Step-by-step explanation:

[tex]6(a + 1 {)}^{2} + 4(a + 1)[/tex]

➡️ [tex]2(a + 1) \times (3(a + 1) + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 3 + 2)[/tex]

➡️ [tex]2(a + 1) \times (3a + 5)[/tex]

Answer:

The loss percentage is 37.5%

Step-by-step explanation:

Cost Price = 500 × 100/125 = 400

New selling price = Rs. 250 ⇒ Loss = 400 – 250 = 150

Loss percentage = 100 × 150/400 = 37.5%.

Answer:

96

Step-by-step explanation:

First, you find the area of RPQ using 1/2×base×height. That is, 1/2×6×8. And the answer is 24. Then you multiply 24 by 4 to get the area of all the sides excluding the base to get 96.

Answer:

Step-by-step explanation:

Answer:

Im not certain but I think 7.5% If you get another answer which is different trust them not me if u get one which is the same it should be correct

The interest rate was 7.5% when borrowing $600 for one year and paying $45.00 interest.

Simple interest is defined as interest paid on the original principal and calculated with the following formula:

S.I. = P × R × T, where P = Principal, R = Rate of Interest in % per annum, and T = Time, usually calculated as the number of years. The rate of interest is in percentage r% and is to be written as r/100.

We have been given data as:

Principal (P) = $600

Time (T) = 1 year

Simple interest = $45.00

⇒ Simple interest = P × R × T

Substitute the value of P, and T in the above formula, and solve for R

⇒ 45.00 = 600 × R × 1

⇒ 45.00 = 600R

⇒ R = 45.00/600

⇒ R = 0.075

⇒ R = 7.5/100

⇒ R = 7.5%

Therefore, the interest rate was 7.5%.

Learn more about the simple interest here:

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Answer:

Each child will receive eight fifths of the cupcakes.

5x=8 ; x represents how many cupcakes each child receives.

[tex]\frac{8}{5}[/tex]

Step-by-step explanation:

There are 8 cupcakes in total.

5 children.

Divide 8 by 5. [tex]\frac{8}{5}[/tex]

I hope this helps!

pls ❤ and mark brainliest pls!

Answer:

63

Step-by-step explanation:

6x + 3y - 9

x = 6

y = 9

6(6) + 3(9)

36 + 27

= 63

Answer:

y = 1/3mx + b

Step-by-step explanation:

x = 3(y - b)/m

~Multiply m to both sides

mx = -3b + 3y

~Add 3b to both sides

mx + 3b = 3y

~Divide everything by 3

1/3mx + b = y

y = 1/3mx + b

Best of Luck!

[tex]\\ \rm\longmapsto x=\dfrac{3(y-b)}{m}[/tex]

[tex]\\ \rm\longmapsto mx=3(y-b)[/tex]

[tex]\\ \rm\longmapsto mx=3y-3b[/tex]

[tex]\\ \rm\longmapsto 3y=mx+3b[/tex]

[tex]\\ \rm\longmapsto y=\dfrac{1}{3}mx+b[/tex]

Answer:

2400

which is not having any remainder as 2400÷60=40

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

6x+5=53

6x=48

6x/6=48/6

x=8

Answer:

153*10^3

Step-by-step explanation:

I assumed the first exponential number as 1

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{(3.4 \times 10^4)(4.5 \times 10^3)}}\\\huge\boxed{\mathsf{\rightarrow 3.4\times10^4 \times 4.5 \times 10^3}}[/tex]

[tex]\huge\boxed{\mathsf{10^4}}\\\huge\boxed{= 10\times10\times10\times10}\\\huge\boxed{= 100\times100}\\\huge\boxed{= 10,000}\\\\\\\huge\boxed{\mathsf{10^3}}\\\huge\boxed{=10\times10\times10}\\\huge\boxed{= 100\times10}\\\huge\boxed{= 1,000}[/tex]

[tex]\huge\boxed{\rightarrow\mathsf{3.4\times \bold{10,000} \times 4.5 \times \bold{1,000}}}}[/tex]

[tex]\huge\boxed{\mathsf{3.4\times10,000}}\\\huge\boxed{= 34,000}\\\\\\\huge\boxed{\mathsf{4.5\times1,000}}\\\huge\boxed{{= 4,500}}}[/tex]

[tex]\huge\boxed{\mathsf{\rightarrow\bf 34,000\times4,500}}\\\huge\boxed{\rightarrow\mathsf{ORIGINAL \ ANSWER: \frak {153,000,000}}}}[/tex]

[tex]\huge\boxed{\textsf{Your answer: }\mathsf{153\times10^6}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

Step-by-step explanation:

1. Approach

One is given the following information:

[tex]cos(2\theta)=-\frac{2}{5}[/tex]

One can rewrite this as:

[tex]cos(2\theta)=-0.4[/tex]

Also note, the problem says that the angle ([tex]2\theta[/tex]) is found in the third quadrant.

Using the trigonometric identities ([tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]) and ([tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]) one can solve for the values of ([tex]cos(\theta)[/tex]) and ([tex]sin(\theta)[/tex]). After doing so one can use another trigonometric identity ([tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]).  Substitute the given information into the ratio and simplify.

2. Solve for [tex](cos(\theta))[/tex]

Use the following identity to solve for ([tex]cos(\theta)[/tex]) when given the value ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

Substitute the given information in and solve for ([tex]cos(\theta)[/tex]).

[tex]cos(2\theta)=2(cos^2(\theta))-1[/tex]

[tex]-0.4=2(cos^2(\theta))-1[/tex]

Inverse operations,

[tex]-0.4=2(cos^2(\theta))-1[/tex]

[tex]0.6=2(cos^2(\theta))[/tex]

[tex]0.3=cos^2(\theta)[/tex]

[tex]\sqrt{0.3}=cos(\theta)[/tex]

Since this angle is found in the third quadrant its value is actually:

[tex]cos(\theta)=-\sqrt{0.3}[/tex]

3. Solve for [tex](sin(\theta))[/tex]

Use the other identity to solve for the value of ([tex]sin(\theta)[/tex]) when given the value of ([tex]cos(2\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

Substitute the given information in and solve for ([tex]sin(\theta)[/tex]).

[tex]cos(2\theta)=1-2(sin^2(\theta))[/tex]

[tex]-0.4=1-2(sin^2(\theta))[/tex]

Inverse operations,

[tex]-0.4=1-2(sin^2(\theta))[/tex]

[tex]-1.4=-2(sin^2(\theta))[/tex]

[tex]0.7=sin^2(\theta)[/tex]

[tex]\sqrt{0.7}=sin(\theta)[/tex]

Since this angle is found in the third quadrant, its value is actually:

[tex]sin(\theta)=-\sqrt{0.7}[/tex]

4. Solve for [tex](tan(\theta))[/tex]

One can use the following identity to solve for [tex](tan(\theta))[/tex];

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

Substitute the values on just solved for and simplify,

[tex]tan(\theta)=\frac{sin(\theta)}{cos(\theta)}[/tex]

[tex]tan(\theta)=\frac{-\sqrt{0.7}}{-\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{0.7}}{\sqrt{0.3}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

Rationalize the denominator,

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}}}{\sqrt{\frac{3}{10}}}*\frac{\sqrt{\frac{3}{`0}}}{\sqrt{\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{7}{10}*\frac{3}{10}}}{\sqrt{\frac{3}{10}*\frac{3}{10}}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{\frac{21}{100}}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\frac{\sqrt{21}}{10}}{\frac{3}{10}}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{10}*\frac{10}{3}[/tex]

[tex]tan(\theta)=\frac{\sqrt{21}}{3}[/tex]

-8/10,-12/15,-16/20,-20/25,-24/30,etc.

The number sets that apply to -4/5 is the fractions.

Fractions represent the parts of a whole or collection of objects.

A fraction has two parts. The number on the top of the line is called the numerator and the number on the top of the line is called the denominator.

Now the given number is,

-4/5

-4/5 is a fraction. A fraction has two components numerator and denominator. This can positive or negative. Other example of fractions include 1/2,3/2,-5/2,-1/3.

The numbers who are not fractions are 0, 3, 6, 7.7.

Thus, the number sets that apply to -4/5 is the fractions.

To learn more about fractions:

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Answer:

a= 11.55

Step-by-step explanation:

If the answer is 8.45, then the variable equals the difference of 20 minus the answer, 8.45

Hope this helps!

Answer:

a) 16/25

b)3/2

Step-by-step explanation:

all explaination is in picturw below

Answer:

$17.25

Step-by-step explanation:

The tip is 15% of $15.00, or 0.15 * 15 = $2.25

We add that to the meal's cost, which is $15.00

15.00 + 2.25 = 17.25

Answer:

Below,...

Step-by-step explanation:

Your equation:

[tex]\frac{63}{7-(2*3)} =\frac{63}{7-6} =\frac{63}{1}=63[/tex]

Hope it helps,... Chow,...!

AB = AD [Given]

BC = CD [Given]

AC = AC [Same line segment]

So, ΔABC ≅ ΔADC [By SSS congruence criteria]

So, ∠ABC = ∠ADC [CPCT (Corresponding parts of congruent triangles)]

Hence, proved.

Answer:

I hope it will help U.

Answer:

After 5 seconds

Step-by-step explanation:

One is given the following expression to model to the flight path of a ball:

[tex]h=-16t^2+80t[/tex]

In this problem, one is asked to find the time at which the ball lands on the ground. The easiest way to do so is to factor the expression. Take out factors that both terms have in common. The one will set the equation equal to zero, as this is the height at which one wants to find the time for. Finally, use the zero product property to solve. The zero product property states that any number times zero equals zero. Apply these ideas to the given function:

[tex]h=-16t^2+80t[/tex]

Factor the expression; both terms have a common factor of (-16t):

[tex]h=-16t^2+80t[/tex]

[tex]h=-16t(t-5)[/tex]

Set the equation equal to zero to solve for when the ball has a height of zero or rather lands on the ground:

[tex]h=-16t(t-5)[/tex]

[tex]0=-16t(t-5)[/tex]

Now use the zero product property, this states that any number times zero equals zero. Set each of the factors equal to zero, and solve to find the value of (t) for which the factor will equal zero:

[tex]0=-16t(t-5)[/tex]

[tex]0=-16t[/tex]                          [tex]t - 5 =0[/tex]

Solve for the value (t) using inverse operations,

[tex]0=-16t[/tex]                            [tex]t - 5 =0[/tex]

(divide by (-16)                   (add (5))

[tex]0=t[/tex]                                     [tex]t=5[/tex]

As one can see, the ball started on the ground, therefore at (0) seconds, its height was (0). Then, after (5) seconds the ball landed on the ground, therefore, after (5) seconds its height was again (0).

Answer:45 ish

Step-by-step explanation:

Answer:

Below.

Step-by-step explanation:

I cant draw you a picture but it will be one right triangle inside the other where the vertical tower will be one leg common to 2 triangles and the base of the 2 triangles will be x and x+10 metres.

Tan 30 = h/ (x + 10)

tan 45 = h/x        where h is the height of the tower.

From the second equation  x = h / tan45

Substituting in the first equation;

tan30 = h / (h/tan45 + 10

Tan 30 = 1/ √3 and tan 45 = 1 so

1/ 1.732 = h/ (h + 10)

0.5774 = h/(h + 10)

h = 0.5774h + 57.74

0.4226 h = 57.74

h = 136.6 m to nearest tenth.

Answer:

5(x+4)

Step-by-step explanation:

It's basically asking for the sum of a number and four to be multiplied by 5. Since the sum is made up of the unknown number and four, you'd put four and the unknown number in parenthesis while putting five on the outside, making it 5(x+4).

Step-by-step explanation:

[tex]thank \: you[/tex]

Answer:

i have no idea that's why I need ur help

Answer:

6  19 /24

Step-by-step explanation:

find the lcd and add

Answer:

C

Step-by-step explanation:

Squaring is multiplying a number by itself

Examples:

2 x 2 = 4

3 x 3 = 9

4 x 4 = 16

etc.

[tex]\\ \rm\Rrightarrow 11+7x=-17[/tex]

[tex]\\ \rm\Rrightarrow 7x=-7-11[/tex]

[tex]\\ \rm\Rrightarrow 7x=-28[/tex]

[tex]\\ \rm\Rrightarrow x=\dfrac{-28}{7}[/tex]

[tex]\\ \rm\Rrightarrow x=-4[/tex]

Answer: x = -4

Step-by-step explanation:

Given equation

11 + 7x = -17

Subtract 11 on both sides

11 + 7x - 11 = -17 - 11

7x = -28

Divide 7 on both sides

7x / 7 = -28 / 7

[tex]\boxed{x=-4}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

purple.orang.blue.yellow and green

purple.orang.blue.yellow and green