Step-by-step explanation:
Area of a square = s x s and this equals 10 x s
this is :
s^2 = 10 s divide both sides of the equation by 's'
s = 10 units ( or zero....but that makes no sense)
3) One piece of fencing is 71/8 feet long. How long will a fence be that is made up of 9 of these pieces?
Answer:
Step-by-step explanation:
71/8*9 which it 639/8 feet long
Line A has a gradient of -5. Line B is perpendicular to line A. a) What are the coordinates of the y-intercept of line B? b) What is the equation of line B? S Give your answer in the form y where m and c are integers or fractions written in their simplest form. mx + c,
The equation of line B is y = (1/5)x + 0, which can be simplified to y = (1/5)x.
What is equation?An equation is a statement that shows the equality between two expressions. It typically contains one or more variables and may involve mathematical operations such as addition, subtraction, multiplication, division, exponentiation, or roots. An equation can be solved by finding the value(s) of the variable(s) that make the equation true. Equations are used extensively in mathematics, science, engineering, and other fields to describe relationships between different quantities and to make predictions or solve problems.
Here,
Since line B is perpendicular to line A, the product of their gradients is -1. Therefore, the gradient of line B is 1/5.
a) To find the y-intercept of line B, we need to know a point on the line. Since we don't have one, we can use the fact that the y-intercept is the point where the line intersects the y-axis. To find this point, we can set x = 0 in the equation of line B:
y = (1/5)x + c
0 = (1/5)(0) + c
c = 0
Therefore, the y-intercept of line B is (0,0).
b) The equation of line B is y = (1/5)x + 0, which can be simplified to y = (1/5)x.
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Elouise finds a woodlouse that is 8 mm long. When she views it under the microscope it
appears 12 cm long.
What is the magnification?
Answer:
Step-by-step explanation:
This can be solved by taking X as the magnification
8*x = 12cm *10
x= 120/8
x= 30/2= 15
the magnification = 15 times
Tiana has a new beaded necklace. The necklace has 3 blue beads and 17 white beads. What percentage of the beads on Tiana's necklace are blue?
Therefore, 15% of the beads on Tiana's necklace are blue.
What is percentage?Percentage is a way of expressing a fraction or a proportion out of 100. It is denoted by the symbol "%". For example, if we say that 50% of the students in a class are girls, it means that 50 out of every 100 students are girls.
Percentage can be calculated by dividing the given quantity by the total and multiplying by 100. For example, if there are 20 girls out of a total of 40 students in a class, the percentage of girls in the class can be calculated as follows:
Percentage of girls = (number of girls / total number of students) x 100%
= (20 / 40) x 100%
= 50%
by the question.
Tiana's necklace has a total of 3 + 17 = 20 beads.
To find the percentage of blue beads, we need to divide the number of blue beads by the total number of beads and then multiply by 100 to get the percentage:
percentage of blue beads = (number of blue beads / total number of beads) x 100
percentage of blue beads = (3 / 20) x 100
percentage of blue beads = 15
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With respect to the average cost curves, the marginal cost curve: Intersects average total cost, average fixed cost, and average variable cost at their minimum point b. Intersects both average total cost and average variable cost at their minimum points Intersects average total cost where it is increasing and average variable cost where it is decreasing d. Intersects only average total cost at its minimum point
With respect to the average cost curves, the marginal cost curve: intersects both average total cost and average variable cost at their minimum points that is option B.
The fixed cost per unit of production is the average fixed cost (AFC). AFC will reduce consistently as output grows since total fixed costs stay constant. The variable cost per unit of production is known as the average variable cost (AVC). AVC generally declines until it reaches a minimum and then increases due to the growing and then lowering marginal returns to the variable input. The average total cost curve's (ATC) behaviour is determined by the behaviour of the AFC and AVC.
The marginal cost is the cost added to the overall cost of producing one extra unit of output. MC initially falls until it hits a minimum and then increases. When both AVC and ATC are at their minimal points, MC equals both. Also, when AVC and ATC are dropping, MC is lower; when they are growing, it is higher.Initially, the marginal cost of manufacturing is lower than the average cost of preceding units. When MC falls below AVC, the average falls. The average cost will reduce as long as the marginal cost is smaller than the average cost.When MC surpasses ATC, the marginal cost of manufacturing one more extra unit exceeds the average cost.Learn more about Marginal cost curve:
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Complete question:
With respect to the average cost curves, the marginal cost curve:
A) Intersects average total cost, average fixed cost, and average variable cost at their minimum point
B) Intersects both average total cost and average variable cost at their minimum points
C) Intersects average total cost where it is increasing and average variable cost where it is decreasing
D) Intersects only average total cost at its minimum point
find the area of a quadrilateral ABCD in each case.
The area of the quadrilateral ABCD for this case is of 4 square units.
How to obtain the area of the quadrilateral ABCD?The quadrilateral ABCD in the context of this problem represents a diamond, hence it's area is given by half the product of the diagonal lengths of the diamond.
The lengths for each diagonal of the diamond are given as follows:
Diagonal AC = 2 - 0 = 2.Diagonal BD = 4 - 0 = 4.The product of the diagonal lengths is given as follows:
AC x BD = 2 x 4 = 8 square units.
Hence half the product of these diagonal lengths, representing the area of the quadrilateral, is given as follows:
0.5 x 8 square units = 4 square units.
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Suppose you roll a special 37-sided die. What is the probability that one of the following numbers is rolled? 35 | 25 | 33 | 9 | 19 Probability = (Round to 4 decimal places) License Points possible: 1 This is attempt 1 of 2.
Answer:
5/37
Step-by-step explanation:
There are 37 possible outcomes when rolling a 37-sided die, so the probability of rolling any one specific number is 1/37.
To find the probability of rolling any of the given numbers (35, 25, 33, 9, or 19), we need to add the probabilities of rolling each individual number.
Probability of rolling 35: 1/37
Probability of rolling 25: 1/37
Probability of rolling 33: 1/37
Probability of rolling 9: 1/37
Probability of rolling 19: 1/37
The probability of rolling any one of these numbers is the sum of these probabilities:
1/37 + 1/37 + 1/37 + 1/37 + 1/37 = 5/37
So the probability of rolling any of the given numbers is 5/37, which is approximately 0.1351 when rounded to four decimal places.
Sarah is a healthy baby who was exclusively breast-fed for her first 12 months. Which of the following is most likely a description of her weights (at 3, 6, 9, and 12 months of age) as percentiles of the CDC growth chart reference population? 85th percentile at 3 months; 85th percentile at 6 months; 9oth percentile at 9 months; 95th percentile at 12 months 75th percentile at 3 months; 40th percentile at 6 months; 25th percentile at 9 months; 25th percentile at 12 months 30th percentile at 3 months; 50th percentile at 6 months; 70th percentile at 9 months; 80th percentile at 12 months 25th percentile at 3 months; 25th percentile at 6 months; 25th percentile at 9 months; 25th percentile at 12 months
The 12 months of age) as percentiles of the CDC growth chart reference population.
The most likely description of Sarah's weights (at 3, 6, 9, and 12 months of age) as percentiles of the CDC growth chart reference population is: 85th percentile at 3 months; 85th percentile at 6 months; 90th percentile at 9 months; 95th percentile at 12 months.What is percentile in statistics?In statistics, a percentile is a value below which a specific percentage of observations in a group falls. It is used to split up data into segments that represent an equal proportion of the entire group, resulting in a data set split into 100 equal portions, with each portion representing one percentage point. Sarah's weight is in the 85th percentile at 3 months, 85th percentile at 6 months, 90th percentile at 9 months, and 95th percentile at 12 months is a most likely description of her weights (at 3, 6, 9, and 12 months of age) as percentiles of the CDC growth chart reference population.
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based on historical data, it takes students an average of 48 minutes with a standard deviation of 15 minutes to complete the unit 5 test. what is the probability that your class of 20 students will have a mean completion time greater than 60 minutes on the unit 5 test?
Using central limit theorem, the probability that the class of 20 students will have a mean completion time greater than 60 minutes on the unit 5 test is 0.00017332
What is the probability that your class of 20 students will have a mean completion time greater than 60 minutes on the unit 5 test?We can use the Central Limit Theorem (CLT) to approximate the distribution of the sample mean completion time for the class. According to CLT, the distribution of the sample mean is approximately normal, with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.
In this case, the population mean is given as 48 minutes, the population standard deviation is given as 15 minutes, and the sample size is 20. Therefore, the mean of the sample mean completion time is also 48 minutes, and the standard deviation of the sample mean completion time is 15/√20 ≈ 3.3541 minutes.
To find the probability that the class mean completion time is greater than 60 minutes, we can standardize the distribution of the sample mean completion time using the z-score formula:
z = (x - μ) / (σ / √n)
where x is the value we want to find the probability for (in this case, x = 60), μ is the population mean, σ is the population standard deviation, and n is the sample size.
Plugging in the values, we get:
z = (60 - 48) / (15 / √20) = 3.5777
Using a standard normal distribution table (or calculator), we can find the probability that a z-score is greater than 3.5777.
P = 0.00017332
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use a direct proof to show that every odd integer is the difference of two squares. [hint: find the difference of the squares of k 1 and k where k is a positive integer.]
Yes, every odd integer can be written as the difference of two squares.
To prove this, let k be a positive integer. Then the difference of the squares of k+1 and k is (k+1)² - k² = (k+1)(k+1) - k(k) = k² + 2k + 1 - k² = 2k + 1, which is an odd integer. Thus, every odd integer can be written as the difference of two squares.
To prove this, we first chose a positive integer, k. We then found the difference of the squares of k+1 and k to be (k+1)² - k² = (k+1)(k+1) - k(k) = k² + 2k + 1 - k² = 2k + 1. Since 2k + 1 is an odd integer, it follows that every odd integer is the difference of two squares.
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Calculate (3.7 x 10¹⁴) + (9 × 10¹²) Give your answer in standard index form.
Answer:3.79*10^14
Step-by-step explanation:
370000000000000+9000000000000=379000000000000
=3.79 x 10^14
Answer:
(3.79×10^14)
Step-by-step explanation:
sjskakakzks
find the smallest positive integer $n$ so that \[\renewcommand{\arraystretch}{1.5} \begin{pmatrix} -\frac{\sqrt{2}}{2}
The smallest positive integer n so that,
$$\renewcommand{\arraystretch}{1.5} \begin{pmatrix} -\frac{\sqrt{2}}{2} \frac{1}{n} \\ \frac{\sqrt{2}}{2} \frac{1}{n} \end{pmatrix}$$is a column matrix that contains integers,
we can write it as follows. $$\begin{pmatrix} -\frac{\sqrt{2}}{2} \frac{1}{n} \\ \frac{\sqrt{2}}{2} \frac{1}{n} \end{pmatrix} = \begin{pmatrix} -\frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \end{pmatrix} \frac{1}{n}.$$Since n has to be an integer, we have to find the smallest positive integer n for which the right-hand side is a column matrix containing integers. Since the left-hand side has a factor of 1/n, we can see that the smallest value of n must be a divisor of the denominator of the left-hand side. The denominator of the left-hand side is $\sqrt{2}/2$. If we multiply this by 100, we get 70.710678.
Therefore, the smallest positive integer n that satisfies the equation is the smallest divisor of 70.710678. This is 2, and it gives us the column matrix $$\begin{pmatrix} -\frac{1}{\sqrt{2}} \\ \frac{1}{\sqrt{2}} \end{pmatrix}.$$Therefore, the smallest positive integer n is 2.
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Show that, the sum of an infinite arithmetic progressive sequence with a positive common difference
is +∞
Answer:
Show that, the sum of an infinite arithmetic progressive sequence with a positive common difference
is +∞
Step-by-step explanation:
To show that the sum of an infinite arithmetic progressive sequence with a positive common difference is +∞, we can use the formula for the sum of the first n terms of an arithmetic sequence:
Sn = n/2 [2a + (n-1)d]
where a is the first term, d is the common difference, and n is the number of terms in the sequence.
Now, if we let n approach infinity, the sum of the first n terms of the sequence will also approach infinity. This can be seen by looking at the term (n-1)d in the formula, which grows without bound as n becomes larger and larger.
In other words, as we add more and more terms to the sequence, each term gets larger by a fixed amount (the common difference d), and so the sum of the sequence increases without bound. Therefore, the sum of an infinite arithmetic progressive sequence with a positive common difference is +∞.
What is the gradient of the line segment between the points 2,4 and 4,6
Answer:
1
Step-by-step explanation:
Given values are:
x1 y1=(2,4)
x2 y2=( 4,6)
slop=(6-4)divide (4-2)=1
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what types of inferences will we make about population parameters? (select all that apply) causation estimation implied testing regression
The types of inferences that will be made about population parameters are causation, estimation, and regression on the basis of relationship.
What are the types of inferences?Causation is the process of showing the cause-and-effect relationship between two variables. In this case, one variable influences the other variable. This type of inference is significant when making decisions because it helps us understand how a change in one variable leads to a change in another variable.
Estimation: In statistical analysis, estimation refers to determining the possible value of an unknown population parameter. It is impossible to calculate the population parameters directly, and hence we use sample statistics to estimate them.
Regression analysis is the statistical technique used to identify the relationship between two variables. It involves estimating the coefficients of the model that best fit the data.
This type of inference helps us predict the value of a dependent variable based on an independent variable.
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Suppose an angle has a measure of 140 degrees a. If a circle is centered at the vertex of the angle, then the arc subtended by the angle's rays is______ times as long as 1/360th of the circumference of the circle. b. A circle is centered at the vertex of the angle, and 1/360th of the circumference is 0.06 cm long. What is the length of the arc subtended by the angle's rays? _______ cmc. Another circle is centered at the vertex of the angle. The arc subtended by the angle's rays is 70 cm long. - 1/360th of the circumference of the circle is _____ cm long. - Therefore the circumference of the circle is _______ cm
If an angle of measurement of 140° then; a circle is centered at the vertex of the angle, then the arc subtended by the angle's rays is 0.0233 cm times as long as 1/360th of the circumference of the circle. Also if a circle is centered at the vertex of the angle, and 1/360th of the circumference is 0.06 cm long then length of the arc subtended by the angle's rays 8.4 cm. Another circle is centered at the vertex of the angle then arc subtended by the angle's rays is 70 cm long,Therefore the circumference of the circle is 180 cm.
a.) To find the fraction of the circle's circumference subtended by the angle's rays, we divide the angle measure by 360 degrees:
fraction of circle's circumference = 140/360
Simplifying this fraction, we get:
fraction of circle's circumference = 7/18
To find the length of the arc subtended by the angle's rays, we multiply the fraction of the circle's circumference by the circumference of the circle. Let's call the circumference of the circle "C":
length of arc = (7/18)*C
We're also told that the length of 1/360th of the circumference is equal to 0.06 cm. So, we can write:
(1/360)*C = 0.06
Multiplying both sides by 360, we get:
C = 360*0.06 = 21.6 cm
Now, we can substitute this value of C into the expression for the length of the arc:
length of arc = (7/18)*C
length of arc = (7/18)*(21.6)
length of arc = 8.4 cm (rounded to one decimal place)
Therefore, the length of the arc subtended by the angle's rays is 8.4 cm.
b.) We're given that 1/360th of the circumference of the circle is 0.06 cm long. To find the length of the arc subtended by the angle's rays, we need to multiply 140/360 by 0.06:
length of arc = (140/360)*0.06
length of arc = 0.0233 cm (rounded to four decimal places)
Therefore, the length of the arc subtended by the angle's rays is approximately 0.0233 cm.
c.) We're told that the length of the arc subtended by the angle's rays is 70 cm. To find the circumference of the circle, we need to find the length of 1/360th of the circumference first. We can do this by dividing 70 by 1/360:
(1/360)*C = 70
Multiplying both sides by 360, we get:
C = 70*360 = 25,200 cm
Therefore, the circumference of the circle is 25,200 cm. We can also verify this by dividing the length of the arc by the fraction of the circumference subtended by the angle's rays:
length of arc = (7/18)*C
C = (18/7)*length of arc
C = (18/7)*70
C = 180 cm (rounded to one decimal place)
This is a different value than we got earlier, so we need to check our calculations. It turns out that the previous calculation was incorrect - we made a mistake when multiplying 7/18 by 21.6. The correct calculation gives us:
length of arc = (7/18)*C
length of arc = (7/18)*(21.6)
length of arc = 8.4 cm (rounded to one decimal place)
Now, we can calculate the circumference of the circle:
length of arc = (7/18)C
C = (18/7) *length of arc
C = (18/7) *70
C = 180 cm (rounded to one decimal place)
Therefore, the circumference of the circle is 180 cm.
Also, If an angle of measurement of 140° then; a circle is centered at the vertex of the angle, then the arc subtended by the angle's rays is 0.0233 cm times as long as 1/360th of the circumference of the circle.
b. A circle is centered at the vertex of the angle, and 1/360th of the circumference is 0.06 cm long.The length of the arc subtended by the angle's rays 8.4 cm
c. Another circle is centered at the vertex of the angle.
The arc subtended by the angle's rays is 70 cm long,Therefore the circumference of the circle is 180 cm.
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Write down the smallest possible answer.
The answer of the given factor and multiplication term for the positive integers are 3.
What about integers?Positive, negative, and zero digit whole numbers are all included in the category of integers. They can be stated without any fractional or decimal components and are a subset of the real numbers. On a number line, integers can be visualized as positive numbers to the right of zero and negative numbers to the left.
Define Multiplication term:In mathematics, a multiplication term is a mathematical expression that involves the multiplication of two or more factors. The factors can be numbers, variables, or a combination of both. Multiplication terms are commonly represented using the multiplication symbol "×" or the dot "." symbol.
For example, in the expression 2x × 3y, the multiplication term is 2x × 3y, which involves the multiplication of the factors 2x and 3y.
According to the given information:If you want to find the smallest possible value of the given term we have that,The smallest factor of 15 is 1.
The smallest multiple of 3 is 3so, the smallest answer is 1x3 = 3.
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Use the equation, 8^2x = 32^x+3, to complete the following problems.
(a) Rewrite the equation using the same base.
(b) Solve for x. Write your answer in simplest form.
Given: ,8^2x= 32^x+3
a: (2³)^2x = (2⁵)^x+3
b: Solving, we get
2^6x = 2^5x+15
Since bases are same, we have
=>6x=5x+15
=> x = 15
A train leaves the station traveling north at 85 km/h. Another train leaves at the same time and travels south at 95 km/h. How long will it take before the trains are 990 km apart
First before two trains were [tex]990[/tex] kilometers apart, it will require [tex]5.5[/tex] hours.
What is the mathematical formula for train?Train speed is calculated as total distance traveled divided by travel time. The time it takes for two trains to pass each other is equal to (a+b) / (x+y) if the lengths of the trains, say a or b, are known and they are going at speeds of y and x, respectively.
What fuels trains use?Typically, a locomotive fueled by electricity or diesel powers trains. If there are several route networks, complicated signaling methods are used. One of the quickest forms of land transportation is rail.
[tex]distance = rate * time[/tex]
distance between trains [tex]= (85 km/h) * t + (95 km/h) * t[/tex]
distance between trains [tex]= (85 + 95) km/h * t[/tex]
distance between trains [tex]= 180 km/h * t[/tex]
Now, we can set up an equation to solve for the time it takes for the trains to be [tex]990[/tex] km apart:
[tex]180 km/h * t = 990 km[/tex]
[tex]t = 990 km / 180 km/h[/tex]
[tex]t = 5.5[/tex] hours
Therefore, it will take [tex]5.5[/tex] hours before the two trains are [tex]990[/tex] km apart.
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4x 2 +6x−13=3x 2 to the nearest tenth.
The solutions to the equation are x = -4 and x = 1.
What is quadratic formula?The quadratic formula, which is often employed in the disciplines of mathematics, physics, engineering, and other sciences, is a potent tool for resolving quadratic problems. We must first get the values of a, b, and c from the quadratic equation in order to apply the quadratic formula. To get the answers for x, we then enter these values as substitutes in the formula and simplify.
The given equation is 4x² + 6x - 13 = 3x².
Rearranging the equation we have:
x² + 6x - 13 = 0
The quadratic formula is given as:
x = (-b ± √(b² - 4ac)) / 2a
Substituting the values of a = 1, b = 6, and c = -13.
x = (-6 ± √(6² - 4(1)(-13))) / 2(1)
x = (-6 ± √(100)) / 2
x = (-6 ± 10) / 2
x = -8/2 or x = 2/2
x = -4 or x = 1
Hence, the solutions to the equation are x = -4 and x = 1
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Put these numbers in order, from least to greatest. If you get stuck, consider using the number line. 3.5, -1, 4.8, -1.5, -0.5, -4.2, 0.5, -2.1, -3.5
The numbers are as follows, going from lowest to highest:
-4.2, -3.5, -2.1, -1.5, -1, -0.5, 0.5, 3.5, 4.8.
How are numbers on a number line determined?We must compare and organize these numbers from least to greatest in order to put them in numerical order. The two smallest figures, which are -4.2 and -3.5, can be used as a starting point. Afterwards, we add the remaining numbers to the list in ascending order of least to largest after comparing them to these two. We arrive at the list above after continuing this approach.
Visualizing these numbers in order can alternatively be done by using a number line. In the number line, we can mark each number and arrange them in ascending order from left to right. We can see from the number line that the least number is -4.2.
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what is -0.33333333333 as a fraction
Answer:
-1/3
Step-by-step explanation:
Answer:
-1/3
Step-by-step explanation:
use the ka values for weak acids to identify the best components for preparing buffer solutions with the given ph values. name formula ka phosphoric acid h3po4 7.5 x 10-3 acetic acid ch3cooh 1.8 x 10-5 formic acid hcooh 1.8 x 10-4
To prepare a buffer solution with a given pH, we need to choose a weak acid and its conjugate base, such that the pKa of the weak acid is close to the desired pH.
The pKa is related to the Ka value as follows:
pKa = -log(Ka)
So, for each of the weak acids given, we can calculate the pKa:
Phosphoric acid (H3PO4): Ka = 7.5 x 10^-3, so pKa = -log(7.5 x 10^-3) = 2.12
Acetic acid (CH3COOH): Ka = 1.8 x 10^-5, so pKa = -log(1.8 x 10^-5) = 4.74
Formic acid (HCOOH): Ka = 1.8 x 10^-4, so pKa = -log(1.8 x 10^-4) = 3.74
Now, let's consider the desired pH values and choose the best components for buffer solutions:
For a pH of 2.5, the best choice would be phosphoric acid (pKa = 2.12).
For a pH of 4.5, the best choice would be formic acid (pKa = 3.74) or a mixture of acetic acid and acetate ion (CH3COOH/CH3COO-, pKa = 4.76).
For a pH of 6.5, the best choice would be a mixture of acetic acid and acetate ion (CH3COOH/CH3COO-, pKa = 4.76).
Note that a buffer solution can be prepared by mixing a weak acid and its conjugate base in roughly equal amounts, so the appropriate salt can be added to the acid to form the buffer solution. For example, to prepare an acetate buffer, one could mix acetic acid with sodium acetate.
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two fifths of 60 is what number
Answer:
I hope this helps please rate my answer
Step-by-step explanation:
2/5×60
2×12=24
Is this a compound?
First, Gabriel planted the geraniums in a clay pot, and then he placed the pot on a sunny windowsill in his kitchen
A. YES
B. NO
Answer:
yes it is right now you can write it
Most people can roll their tongues, but many can’t. The ability to roll the tongue is genetically determined. Suppose we are interested in determining what proportion of students can roll their tongues. We test a simple random sample of 400 students and find that 317 can roll their tongues. The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is closest to
0.008.
0.02.
0.03.
0.04.
0.208.
The proportion of students who can roll their tongues will be estimated and the margin of error for a 95 percent confidence interval for the true proportion of tongue rollers among students will be determined. There were 317 tongue rollers out of a sample of 400 students.
As a result, the sample proportion is 317/400 = 0.7925.
We'll compute the margin of error next. The margin of error (E) for a 95 percent confidence interval is:
E = zα/2 * sqrt[p(1 - p) / n]
where zα/2 is the z-score that corresponds to the level of confidence α/2, p is the sample proportion, and n is the sample size.
E = 1.96 * sqrt[0.7925 * (1 - 0.7925) / 400]E
= 1.96 * sqrt[0.7925 * 0.2075 / 400]E
= 1.96 * sqrt(0.00040875)E
= 1.96 * 0.0202E
= 0.0395
The margin of error is approximately 0.04 or 4 percent. Hence, the correct option is 0.04.
The margin of error for a 95% confidence interval for the true proportion of tongue rollers among students is closest to 0.04
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help, please!
how do i complete the cumulative frequency table?
This procedure is repeated for each interval until the overall frequency of 35 is reached.
what is frequency distribution?A data summary called a frequency distribution displays the frequency, or amount of occurrences, of each value or range of values in a data set. It is frequently displayed as a table or graph, with the values enumerated along one axis and the frequencies of those values listed along the other. The pattern or shape of a data collection can be described using frequency distributions, which can also be used to spot outliers or other unusual values. They can also shed light on the data's central trend and variability.
given
To complete a cumulative frequency table:
Class interval Frequency Cumulative frequency
0-10 5 5
10-20 8 13
20-30 12 25
30-40 7 32
40-50 3 35
Total 35 35
The number of the first class interval is 5.
For the second interval, we multiply the total frequency of 5 plus the frequency of 8 to get 13.
This procedure is repeated for each interval until the overall frequency of 35 is reached.
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The missing value in the cumulative table is 36.
The missing value in the cumulative table can be determined by examining the frequencies given in the table. Let's analyze the frequencies step by step:
1. The frequency for scores less than 145 is given as 16.
2. The frequency for scores less than 150 is given as 26.
3. The frequency for scores less than 155 is given as 36.
4. The frequency for scores less than 160 is not explicitly given in the table, but we can determine it by subtracting the frequency for scores less than 155 (36) from the frequency for scores less than 150 (26).
This gives us a value of [tex]26 - 36 = -10.[/tex]
Since a frequency cannot be negative, we can conclude that there is an error in the given table. The cumulative frequency for scores less than 160 should be 36 instead of -10.
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a factory was manufacturing products with a defective rate of 7.5%. if a customer purchases 3 of the products , what is the probability of getting at least one that is defective
If a customer purchases 3 of the products, the probability of getting at least one that is defective is 38.59%.
How to determine the probabilityIn order to determine the probability of getting at least one defective product if a customer purchases three products with a defective rate of 7.5%, we can use the concept of complementary probability.
The probability of getting at least one defective product can be calculated as the complement of the probability of getting none defective products.
So, the probability of getting no defective products is:
P(none defective) = (1 - 0.075)³ = 0.6141
Therefore, the probability of getting at least one defective product is:
P(at least one defective) = 1 - P(none defective) = 1 - 0.6141 = 0.3859 or 38.59%
.So, the probability of getting at least one that is defective is 38.59%.
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Who ever helps me, Get 100 points
Step-by-step explanation:
a) Area=144m²
side²= 144
side=12m
b) perimeter=32m
4×side=32
side=32/4
side=8m
A random sample of size 64 is to be used to test the null hypothesis that for a certian age group
the mean score on an achievement test (the mean of a normal population with sigma square (variance)variancesigma square= 256) is
less than or equal to 40 against the alternative that it is greater than 40. If the null hypothesis
is to be rejected if and only if the mean of the random sample exceeds 43.5, nd
(a) the probabilities of type I errors when\mu=37, 38, 39, and 40;
(b) the probabilities of type II errors when\mu= 41, 42, 43, 44, 45, 46, 47, and 48.
Also plot the power function of this test criterion.
Answer:
A random sample of size 64 is used to test the null hypothesis that for certain age group the mean score on an achievement test is less than or equal to 40 against the alternative that it is greater than 40. The scores are assumed to be normally distributed with variance 0? 256 _ Consider the hypotheses Ha: L <40 versus HA Lt > 40 and suppose the null hypothesis is to be rejected if and only if the sample mean X exceeds 43.5. What is the size of this test? Compute the probability of type Il error at L = 42
Step-by-step explanation: