Answer:
Publication 5140.
Explanation:
The acronym VITA stands for Volunteer Income Tax Assistance and TCE stands for Tax Counseling for the Elderly. VITA/TCE is a certification gotten from the Internal Revenue Service in which the holders of such certification are trained on how to help people that have disabilities or that their incomes earners that are low. These volunteers help these set of people to prepare for their tax return.
In order to make the volunteers to be able to perform their work with high accuracy, the Department of Treasury, Internal Revenue Service gave out some aids for Quality Site. One of the aids which is the one contains information about the new security requirements at sites is given in the Publication 5140.
Given that the variable named Boy = "Joey" and the variable named Age = 6, create statements that will output the following message:
Congratulations, Joey! Today you are 6 years old.
First, write one statement that will use a variable named Message to store the message. (You will need to concatenate all of the strings and variables together into the one variable named Message. If you don't know what that means, read the section in Chapter 1 about concatenation.)
Then write a second statement that will simply output the Message variable.
Answer:
isn't it already showing it if not put text box
Explanation:
During TCP/IP communications between two network hosts, information is encapsulated on the sending host and decapsulated on the receiving host using the OSI model. Match the information format with the appropriate layer of the OSI model.
a. Packets
b. Segments
c. Bits
d. Frames
1. Session Layer
2. Transport Layer
3. Network Layer
4. Data Link Layer
5. Physical Layer
Answer:
a. Packets - Network layer
b. Segments - Transport layer
c. Bits - Physical layer
d. Frames - Data link layer
Explanation:
When TCP/IP protocols are used for communication between two network hosts, there is a process of coding and decoding also called encapsulation and decapsulation.
This ensures the information is not accessible by other parties except the two hosts involved.
Operating Systems Interconnected model (OSI) is used to standardise communication in a computing system.
There are 7 layers used in the OSI model:
1. Session Layer
2. Transport Layer
3. Network Layer
4. Data Link Layer
5. Physical Layer
6. Presentation layer
7. Application layer
The information formats given are matched as
a. Packets - Network layer
b. Segments - Transport layer
c. Bits - Physical layer
d. Frames - Data link layer
let m be a positive integer with n bit binary representation an-1 an-2 ... a1a0 with an-1=1 what are the smallest and largest values that m could have
Answer:
Explanation:
From the given information:
[tex]a_{n-1} , a_{n-2}...a_o[/tex] in binary is:
[tex]a_{n-1}\times 2^{n-1} + a_{n-2}}\times 2^{n-2}+ ...+a_o[/tex]
So, the largest number posses all [tex]a_{n-1} , a_{n-2}...a_o[/tex] nonzero, however, the smallest number has [tex]a_{n-2} , a_{n-3}...a_o[/tex] all zero.
∴
The largest = 11111. . .1 in n times and the smallest = 1000. . .0 in n -1 times
i.e.
[tex](11111111...1)_2 = ( 1 \times 2^{n-1} + 1\times 2^{n-2} + ... + 1 )_{10}[/tex]
[tex]= \dfrac{1(2^n-1)}{2-1}[/tex]
[tex]\mathbf{=2^n -1}[/tex]
[tex](1000...0)_2 = (1 \times 2^{n-1} + 0 \times 2^{n-2} + 0 \times 2^{n-3} + ... + 0)_{10}[/tex]
[tex]\mathbf {= 2 ^{n-1}}[/tex]
Hence, the smallest value is [tex]\mathbf{2^{n-1}}[/tex] and the largest value is [tex]\mathbf{2^{n}-1}[/tex]
Approximately how many numeric IP addresses are possible with IPv4?
4 billon
Answer:
4,294,967,296 (~4.3B)
Explanation:
IPv4 uses 32-bits for representing addresses, thus you can have 2^32 total combinations.
