Select the correct answer.

Factor the given expression.

x2 + 16x + 64


A.
(x + 16)(x + 4)
B.
(x + 4)2
C.
(x + 8)(x − 8)
D.
(x + 8)2

Pls help will give brainliest if the answer it right

Answers

Answer 1

Answer: Factors are the numbers and/or variables between your transactions (division, multiplication, addition, and subtraction signs). So the answer would be x2, 16x, and 64.

Step-by-step explanation:

You welcome

Can I get brainliest when sun else answers?


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Answer: 16pi

Step-by-step explanation:

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Answers

Step-by-step explanation:

For a quadratic equation to have no real roots, the discriminant b² - 4ac must be negative.

For px² + 8x + 2 = 0,

We have a = p, b = 8 and c = 2.

=> (8)² - 4(p)(2) < 0

=> 64 - 8p < 0

=> 8p > 64

=> p > 8

Hence the range for p is p > 8.

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Answers

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the y-intercept, b, is 7

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Answer:

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Answer:

Line 1: Undefined

Line 2: -4/3

Line 3: 4/3

Line 4: Undefined

Line 5: 7/3

Line 6: -7/3

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Line 8: 0

Line 9: Undefined

Line 11: 0

Line 10 & 12: Undefined

Step-by-step explanation:

Use the slope formula (you can just search up the slope formula)

Also, always remember that a vertical line's slope will be undefined and a horizontal line's slope will be 0 (zero).

I hope this helps!

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

C(t) is the actual value of the function at time t

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answer:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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heyyy wanna help mee

Answers

Answer: Only j = 2

============================================

Explanation:

Let's solve for j

[tex]\frac{96}{j} \ge 40\\\\96 \ge 40j\\\\\frac{96}{40} \ge j\\\\2.4 \ge j\\\\j \le 2.4[/tex]

In the second step, I multiplied both sides by j. If j is a positive number, then the inequality sign will not flip. All of the answer choices are positive numbers, so we don't have to worry about the inequality sign flipping.

The last step shows that j = 2.4 or j < 2.4

So j is 2.4 or smaller.

Of the list given to us, only j = 2 fits the description, since something like j = 8 is not 2.4 or smaller.

---------------------------

If j = 2, then,

[tex]\frac{96}{j} \ge 40\\\\\frac{96}{2} \ge 40\\\\48 \ge 40\\\\[/tex]

which is a true statement since 48 is larger than 40. This shows that j = 2 is a solution.

Something like j = 8 does not work because

[tex]\frac{96}{j} \ge 40\\\\\frac{96}{8} \ge 40\\\\12 \ge 40\\\\[/tex]

which is false because 12 is not equal to 40 or larger than 40. This means j = 8 is not a solution. You should find that j = 12 and j = 3 lead to similar false statements.

Of the list given, j = 2 is the only solution.

Answer:[tex]\boxed{\boxed{\sf{j=2}}}[/tex]Solution Steps:

______________________________

1.) Solve using j = 12:Plug in 12: [tex]\frac{96}{12}[/tex] ≥ [tex]40[/tex]Divide 96 by 12: [tex]=8[/tex] Compare: [tex]8[/tex] ≥ [tex]40[/tex]

So this is False.

2.) Solve using j = 8:Plug in 8: [tex]\frac{96}{8}[/tex] ≥ [tex]40[/tex]Divide 96 by 8: [tex]=12[/tex] Compare: [tex]12[/tex] ≥ [tex]40[/tex]

So this is False.

3.) Solve using j = 2:Plug in 2: [tex]\frac{96}{2}[/tex] ≥ [tex]40[/tex] Divide 96 by 2: [tex]=48[/tex]Compare: [tex]48[/tex] ≥ [tex]40[/tex]

So this is True.

4.) Solve using j = 3:Plug in 3: [tex]\frac{96}{3}[/tex] ≥ [tex]40[/tex]Divide 96 by 3: [tex]=32[/tex] Compare: [tex]32[/tex] ≥ [tex]40[/tex]

So this is False.

______________________________

state if polygons are similar

Answers

Yes polygons are similar just not the same size
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