45x7
what is 45x7
cause I dont know anymore

Answer:

130

Step-by-step explanation:

Answer:

You told me to resolve this question

Answer:

what answer

Step-by-step explanation:

?????????????

Answer:

20 three-point scores

61/3=20 R1

Answer:

7

Step-by-step explanation:

61 divided by 8 = 7 remainder 5

you can do 7 3's and 7 5's which would make 7x3 = 21  +  7 x 5 = 35  21 + 35 = 56

61 - 56  = 5 (add 1 to the amount of 5's)

7 3's and 8 5's

Answer:

6^3

Step-by-step explanation:

3 × 3 × 3 × 3 × 3 × 3=729

6^3=216

3 × 3 × 3 × 3 × 3 × 3=729

3^6=729

Hope this helps :)

3 × 3 × 3 × 3 × 3 × 3

63

9 × 9 × 9

36

Answer: the answer is in the attachment.

Answer:

Hope this helps :)

Step-by-step explanation:

i guess you have copied the wrong question.. it should be somewhat like if tan theta + sec theta = p then find tge value of sin theta...

secθ+tanθ=P

⇒(secθ+tanθ)² = P²

⇒sec² θ+tan² θ+2tanθsecθ=P²

⇒2tan²θ + 1 + 2 sinθ/cos θ = P²

⇒2 sin²θ+ cos²θ+ 2 sinθ total by cos²θ = P²

Applying componendo and dividendo

=> 2sin²θ+ cos²θ+ 2sinθ- cos²θ/ 2sin²θ+ cos²θ+ 2sinθ- cos²θ = p²-1 / p²+1

⇒2sinθ(sinθ+1)/ 2(sinθ+1) = p²-1 / p²+1

=> sinθ = p²-1/ p²+1

Answer:

Answer# 1: A. 26

Answer# 2: A. 25

1. What is m + 5n where m = 1 and n = 5?

Substitute 1 for "m" and 5 for "n":

[tex]\sf (1)+5(5)[/tex]

Multiply 5*5 =25

[tex](1)+25[/tex]

Add :

[tex]\sf 26[/tex]

____________________

2. What is 5m + 5n where m = 10 and n = -5?

Substitute 10 for "m" and -5 for "n".

[tex]\sf 5\left(10\right)\:+\:5\left(-5\right)[/tex]

Multiply 5 * 10= 50

[tex]\sf 50+5\left(-5\right)[/tex]

Multiply 5 * -5 = -25

[tex]\sf 50-25[/tex]

Subtract:

[tex]\sf 25[/tex]

___________________________________

Answer:

6 cm for both sides

Step-by-step explanation:

1. 3/7 = 72/x

By cross multiplication we get :

➟ 3x = 72 × 7

➟ x = 72 × 7/3

➟ x = 24 × 7

➟ x = 168

2. m/8 = 8/20

By cross multiplication we get :

➟ 20m = 8 × 8

➟ 20m = 64

➟ m = 64/20

➟ m = 16/5

Answer:

It is b

Step-by-step explanation: Because only one that makes sense

Answer:

chu papi

Step-by-step explanation:

Let

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = a_0 + a_1x + a_2x^2 + \cdots[/tex]

Differentiating twice gives

[tex]\displaystyle y'(x) = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1) a_{n+1} x^n = a_1 + 2a_2x + 3a_3x^2 + \cdots[/tex]

[tex]\displaystyle y''(x) = \sum_{n=2}^\infty n (n-1) a_nx^{n-2} = \sum_{n=0}^\infty (n+2) (n+1) a_{n+2} x^n[/tex]

When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.

Substitute these into the given differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1) a_{n+2} x^n - \sum_{n=0}^\infty a_nx^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1) a_{n+2} - a_n\bigg) x^n = 0[/tex]

Then the coefficients in the power series solution are governed by the recurrence relation,

[tex]\begin{cases}a_0 = y(0) \\ a_1 = y'(0) \\\\ a_{n+2} = \dfrac{a_n}{(n+2)(n+1)} & \text{for }n\ge0\end{cases}[/tex]

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.

• If n is even, then n = 2k for some integer k ≥ 0. Then

[tex]k=0 \implies n=0 \implies a_0 = a_0[/tex]

[tex]k=1 \implies n=2 \implies a_2 = \dfrac{a_0}{2\cdot1}[/tex]

[tex]k=2 \implies n=4 \implies a_4 = \dfrac{a_2}{4\cdot3} = \dfrac{a_0}{4\cdot3\cdot2\cdot1}[/tex]

[tex]k=3 \implies n=6 \implies a_6 = \dfrac{a_4}{6\cdot5} = \dfrac{a_0}{6\cdot5\cdot4\cdot3\cdot2\cdot1}[/tex]

It should be easy enough to see that

[tex]a_{n=2k} = \dfrac{a_0}{(2k)!}[/tex]

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then

[tex]k = 0 \implies n=1 \implies a_1 = a_1[/tex]

[tex]k = 1 \implies n=3 \implies a_3 = \dfrac{a_1}{3\cdot2}[/tex]

[tex]k = 2 \implies n=5 \implies a_5 = \dfrac{a_3}{5\cdot4} = \dfrac{a_1}{5\cdot4\cdot3\cdot2}[/tex]

[tex]k=3 \implies n=7 \implies a_7=\dfrac{a_5}{7\cdot6} = \dfrac{a_1}{7\cdot6\cdot5\cdot4\cdot3\cdot2}[/tex]

so that

[tex]a_{n=2k+1} = \dfrac{a_1}{(2k+1)!}[/tex]

So, the overall series solution is

[tex]\displaystyle y(x) = \sum_{n=0}^\infty a_nx^n = \sum_{k=0}^\infty \left(a_{2k}x^{2k} + a_{2k+1}x^{2k+1}\right)[/tex]

[tex]\boxed{\displaystyle y(x) = a_0 \sum_{k=0}^\infty \frac{x^{2k}}{(2k)!} + a_1 \sum_{k=0}^\infty \frac{x^{2k+1}}{(2k+1)!}}[/tex]

Using the z-distribution, it is found that the p-value for this test is of 0.0375.

At the null hypothesis, it is tested if the expenses are the same as the national average, that is, of $5,423. Hence:

[tex]H_0: \mu = 5423[/tex]

At the alternative hypothesis, it is tested if it is higher, hence:

[tex]H_1: \mu > 5423[/tex]

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

The parameters are:

For this problem, the values of the parameters are: [tex]\overline{x} = 5516, \mu = 5423, \sigma = 979, n = 352[/tex]

The value of the test statistic is:

[tex]z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{5516 - 5423}{\frac{979}{\sqrt{352}}}[/tex]

[tex]z = 1.78[/tex]

The p-value is the probability of finding a sample mean above $5,516, which is 1 subtracted by the p-value of z = 1.78.

1 - 0.9625 = 0.0375

Hence, the p-value for this test is of 0.0375.

A similar problem is given at https://brainly.com/question/25549474

Answer:

wa

at you ım prenses

Step-by-step explanation:

you ind soluk

Answer:

66

forty-four times 1.5 equals 66

Answer:

1386

Step-by-step explanation:

V=πr²*h

V=22/7*7²*9

V=1386

Answer:

four times a number less 10 is equall to 16 ia not

Answer:

proportion of ratio will be used

Answer:

C. 1 4/10 + 9/10 + 6/10

got it right

Answer:

Step-by-step explanation:

5 / 6 = 0.83333333...

0.833333...•100 = 83.333333...

83.3%

Answer:

You can do this type of questions with inverse proportion.

_

%83,3

If the given equation is

[tex]27^{\frac13} = 9^{14} + 3^{x + 1}[/tex]

first simplify the left side using the fact that 27 = 3³:

[tex]27^{\frac13} = (3^3)^{\frac13} = 3^{\frac33} = 3^1 = 3[/tex]

and on the right side, 9 = 3²:

[tex]9^{14} = (3^2)^{14} = 3^{2\times14} = 3^{28}[/tex]

So we have

[tex]3 = 3^{28} + 3^{x + 1}[/tex]

Next,

[tex]3^{x+1} = 3^x \times 3^1 = 3 \times 3^x[/tex]

so that

[tex]3 = 3^{28} + 3 \cdot 3^x[/tex]

and dividing both side by 3 gives

[tex]1 = 3^{27} + 3^x[/tex]

Isolate 3ˣ :

[tex]3^x = 1 - 3^{27}[/tex]

Solve for x by taking the base-3 logarithm of both sides:

[tex]\log_3(3^x) = \log_3(1-3^{27})[/tex]

[tex]x \log_3(3) = \log_3(1-3^{27})[/tex]

[tex]\boxed{x = \log_3(1-3^{27})}[/tex]

Answer:

0.00706666666

Step-by-step explanation:

Answer:

about 20 cents

Step-by-step explanation:

#Shop A

Pack of 70pens:-

[tex]\\ \sf\longmapsto 7(2.30)=16.10[/tex]

#2

Pack of 70

[tex]\\ \sf\longmapsto 14(1.60)=20.80[/tex]

But you get half price

Difference:-

[tex]\\ \sf\longmapsto 16.10-10.40=5.70\£[/tex]

Answer:

(6,-2)

Step-by-step explanation:

Answer:

if she pays the bank back it would be 25 but if she just deposited 85 then she has 85 in the bank

Step-by-step explanation:

Answer:

Step-by-step explanation:

I am sorry but please give detailed question