3kg of water at 80degree celcius is added to 8 kg of water at 25 degree celcius. find the temperature of final mixture provided there is no loss of heat in the surrounding. the specific heat capacity is 4200j/kg​

Answer:

4 kg

Explanation:

F (force) = 22.0 N

m (mass) = ? (in Kg)

a (acceleration) = 5.5 m/s²

We apply the data to the Resultant Force formula, we have:

f=ma

22=m x 5.5

5.5m=22

m=22/5.5

m=4kg

Answer:

[tex]\boxed {\boxed {\sf 4 \ kilograms}}[/tex]

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

[tex]F= m*a[/tex]

The bowling ball was pushed with a force of 22.0 Newtons and the acceleration was 5.5 meters per second squared.

1 Newton is equal to 1 kilogram meter per second squared. Therefore, the force of 22.0 N is equal to 22 kg*m/s² (we do this conversion so we can easily cancel the units later).

Substitute the values into the formula.

[tex]22.0 \ kg*m/s^2 = m * 5.5 \ m/s^2[/tex]

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 5.5 meters per second squared. The inverse of multiplication is division, so we divide both sides by 5.5 m/s²

[tex]\frac { 22.0 \ kg*m/s^2}{5.5 \ m/s^2} = \frac{m * 5.5 \ m/s^2}{5.5 \ m/s^2}[/tex]

[tex]\frac { 22.0 \ kg*m/s^2}{5.5 \ m/s^2}=m[/tex]

The units of meters per second squared (m/s²) cancel.

[tex]\frac { 22.0 \ kg}{5.5 }=m[/tex]

[tex]4 \ kg =m[/tex]

The mass of the bowling ball is 4 kilograms.

Answer:

You did not include the picture but I found a similar question that I can explain and you can then use to answer yours.

The middle scale is in hundreds. The arrow here is pointing to 100 so the mass of the object is more than 100g but less than 200g.

The highest scale is in 10s. The arrow is pointing to 0. This means that the object weighs more than 100 but less than 110 g. If the arrow was pointing to 10 then the object would weigh more than 110g.

The bottommost scale is in 1s. Notice how the scale is pointing to 5.7 grams. The object is therefore 105.7 grams.

Look for the option closest to this because the 105.7g might be rounded up.

You will then find 105.65g as your answer.

Answer:433.0 g

Explanation:i’m not 100% sure

Answer:

Explanation:

hi

Answer:

Length in times = 0.75 times

Explanation:

Given:

Length of Euler buckling load = 160 cm

Equivalent load length = 120 cm

Find:

Length in times

Computation:

Length in times = Equivalent load length / Length of Euler buckling load

Length in times = 120 / 160

Length in times = 12 / 16

Length in times = 3 / 4

Length in times = 0.75 times

Answer:

Mass, m = 146.72 kilograms

Explanation:

Given the following data;

Kinetic energy = 190 J

Velocity = 2.59 m/s

To find the combined mass of the girl and her bike;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = ½mv²

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

190 = ½*m*2.59

Cross-multiplying, we have:

380 = 2.59m

Mass, m = 380/2.59

Mass, m = 146.72 kilograms

Answer:

R = 40 cm

Explanation:

From the formulae of magnification:

[tex]\frac{q}{p}=\frac{image\ height}{object\ height}\\\\\frac{q}{10\ cm} = \frac{4\ cm}{2\ cm}\\\\q = (10\ cm)(2)\\\\q = 20\ cm[/tex]

where,

q = image distance from mirror

p = object distance from mirror

Using thin lens formula:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\frac{1}{f}=\frac{1}{10\ cm}+\frac{1}{-20\ cm}\\\\\frac{1}{f} = 0.05\\\\f = 20\ cm[/tex]

q is negative for the virtual image.

Now, the radius of the spherical mirror is double the focal length (f):

R = 2f

R = 2(20 cm)

R = 40 cm

Pedaling forward over the bike with the increase in your applied force would decrease your acceleration. Thus, option B is correct.

Acceleration is define as the rate at which velocity changes with time, in terms of both speed and direction. The equation for acceleration is:

a=F/m

where, a = acceleration,

F = force applied

m =  mass of the object

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object.

As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Therefore, if you are pedaling forward on your bike then a increase in your applied force would decrease your acceleration. Thus, option B is correct.

Learn more about acceleration here:

https://brainly.com/question/980919

#SPJ5

Answer:

I just did it. A is right.

Explanation:

If the boat's speed is s, and the river's speed is r, and the boat is traveling east (0 degrees),

(0,r) + (s cos297,s sin297) = (6,0)

now just solve for r and s.

Pls mark me as brainliest

Answer:

The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

Explanation:

Strain is defined mathematically as follows .

strain = Δ L/ L

Δ L is change in length of a wire when some force is applied on it to stretch it along its length and L is original length of a wire .

Stress is The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

Answer:

The elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

Explanation:

Every object has some elastic and inelastic properties.

The strain is defined as the ratio of change in dimensions to the original dimensions.

There are three types of strains:

1. Longitudinal strain

2. Volumetric strain

3. Shear strain

So, it is defined as elongation (or change in length) of a specimen divided by the original length, sometimes referred to as percent elongation.

Answer:

t = 0.4 s

Explanation:

Given that,

The speed of sound on steel is about 5000 m/s.

A friend of yours, 2000 m away, strikes a railroad track which you have your ear on.

We need to find the time after she strikes it will the sound arrive. Let the time is t. We know that,

Speed = distance/time

So,

[tex]t=\dfrac{d}{v}\\\\t=\dfrac{2000}{5000}\\\\t=0.4\ s[/tex]

So, the required time is 0.4 seconds.

Answer:

Work = F X D

Explanation:

Work (J) equals Force (N) multiplied by Distance (M)

Answer:

Here's your answer: The wheelbarrow's wheel and axle help the wheelbarrow to move without friction thus making it easier to push or pull. That's why it will be easier to lift a load in wheel barrow of the load is transferred towards the wheel.

Explanation:

Answer:

Explanation:

The wheel barrows wheel and axle helps the wheelbarrow to move without friction this making it easier to push or pull.thats why it will be easier to lift a load in a wheelbarrow if it's transferred towards the wheel..

Hope it helps

Answer:

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

Explanation:

Although The Photon ( sunshine from the sun's surface ) heating up the student standing on the Earth's surface and the neutrinos discovered by the other student inside the gold mine are both formed in the Sun's core.

The difference between both are

The photon takes millions of years to reach the Surface of the sun while the Neutrinos travelling at the speed of light reaches the surface of the sun in approximately 2 seconds

The Photon is million year old while the neutrino is just some minutes old as observed by the student .

Answer:

80 °C

Explanation:

The heat transfer parameters for the water and copper container are;

Mass of the copper container, m₁ = 84 g

Mass of the water in the container, m₂ = 84 g

Initial temperature of the water in the container, T₂ = 20°C

Mass of the hot water added, m₃ = 46 g

Initial temperature of the hot water, T₃ = 200°C

Specific heat capacity of water, c₂ = 4,200 J·kg⁻¹·°C⁻¹

Specific heat capacity of copper, c₁ = 400 J·kg⁻¹·C⁻¹

The formula for the specific heat, ΔQ = m·c·ΔT

The heat lost by the hot water = The heat gained by the container the and the cold water

The formula for the specific heat of the mixture is presented as follows;

m₃ × c₃ × (T₃ - T)  = m₁ × c₁ × (T - T₁) + m₂ × c₂ × (T - T₂)

Where T represents the final temperature of the water

Therefore, by plugging in the values, we get;

46 × 4200 × (200 - T) = 84 × 400 × (T - 20) + 84 × 4200 × (T - 20)

38640000 - 193200·T = 386400·T - 7728000

38640000 + 7728000 = 46368000 = 386400·T + 193200·T = 579,600·T

∴ T = 46368000/579,600 = 80

The final temperature of the water, T = 80°C

Answer:

the emf of the cell can be determined by measuring the voltage across the cell using a voltmeter and the current in the circuit using an ammeter for various resistances.

Answer:

C

Explanation:

When light transitions from the air to the water the light bends due to refraction. The refractive index is related to the speed of light in both air and water. The Wikipedia article on Refraction does and excellent job of explaining this.

Answer:

The correct option is C. A picture of a straw in a glass of water showing the shift in position of the straw due to the water.

Explanation:

Hope this helps you. Have a nice day ahead( ; ^_^

Answer:

According to this direction of force is perpendicular to the direction of current and magnetic field. Therefore force is opposite to electron into the paper at 90°.

Answer:

Explanation:

What you forgot to include is the mass of the earth, which is 5.98 × 10²⁴ kg. NOW we can do the problem:

[tex]F=\frac{Gm_1m_2}{r^2}[/tex] where m1 and m2 are the masses of the objects experiencing this force of gravity, F. G is the universal gravitational constant. Filling in:

[tex]2.00*10^{20}=\frac{(6.67*10^{-11})(7.34*10^{22})(5.98*10^{24})}{r^2}[/tex]

We are going to rearrange and solve for r before we do any math on this thing:

[tex]r=\sqrt{\frac{(6.67*10^{-11})(7.34*10^{22})(5.98*10^{24})}{2.00*10^{20}} }[/tex] and when we plug all that mess into our calculators we will do it just like that and then round to 3 significant digits at the very end.

Doing all of that gives us that

r = 3.83 × 10⁸ m

magnitude is area. hope it helps.

Answer:

72.98 km

Explanation:

Her displacement is simply the distance from her final position to her initial position.

Now, I've drawn and attached a triangle diagram to depict this her movement.

Point O is her initial starting point.

Point A is the first point she gets to after travelling north while point B is the final point after travelling north east.

From the triangle, the displacement will be the distance OB which is denoted by x and can be solved from cosine rule.

Thus;

x² = 62² + 26² - 2(62 × 26)cos 120

x² = 4520 + 806

x² = 5326

x = √5326

x = 72.98 km

Answer:

The beat frequency is 5.5 Hz.

Explanation:

f = 110 Hz, T = 600 N , T' = 540 N

let the frequency is f'.

[tex]\frac{f'}{f}=\sqrt\frac{T'}{T}\\\\\frac{f'}{f}=\sqrt\frac{540}{600}\\\\\frac{f'}{f}=0.95\\\\f'= 104.5 Hz[/tex]

So, the beat frequency is f - f' = 110 - 104.5 = 5.5 Hz

Answer:

8m/s^2

Explanation:

Acceleration=initial velocity-final velocity/time

initial velocity(u) is 32 final velocity (v) is 96

therefore

a=96-32/8

a=8m/s squared

hope it helps

Answer:

The final displacement of the car is 140 meters.

Explanation:

The final displacement of the car ([tex]s[/tex]), in meters, is the sum of the change in displacement associated with each part of the journey, which is derived from the following kinematic formulas:

[tex]s = s_{1} + s_{2}[/tex] (1)

[tex]s_{1} = \frac{1}{2}\cdot a_{1}\cdot t_{1}^{2}[/tex] (2)

[tex]v_{o,2} = a_{1}\cdot t_{1}[/tex] (3)

[tex]s_{2} = v_{o,2} + \frac{1}{2}\cdot a_{2}\cdot t_{2}^{2}[/tex] (4)

Where:

[tex]s_{1}[/tex] - Traveled distance of the first part, in meters.

[tex]s_{2}[/tex] - Traveled distance of the second part, in meters.

[tex]a_{1}[/tex] - Acceleration in the first part, in meters per square second.

[tex]a_{2}[/tex] - Acceleration in the second part, in meters per square second.

[tex]v_{o,2}[/tex] - Initial speed of the car in the second part, in meters per second.

[tex]t_{1}[/tex] - Time taken in the first part, in seconds.

[tex]t_{2}[/tex] - Time taken in the second part, in seconds.

If we know that [tex]a_{1} = 0.8\,\frac{m}{s^{2}}[/tex], [tex]t_{1} = 10\,s[/tex], [tex]a_{2} = 0.4\,\frac{m}{s^{2}}[/tex] and [tex]t_{2} = 10\,s[/tex], then the distance traveled by the car is:

By (2):

[tex]s_{1} = \frac{1}{2}\cdot \left(0.8\,\frac{m}{s^{2}} \right)\cdot(10\,s)^{2}[/tex]

[tex]s_{1} = 40\,m[/tex]

By (3):

[tex]v_{o,2} = \left(0.8\,\frac{m}{s^{2}} \right)\cdot (10\,s)[/tex]

[tex]v_{o,2} = 8\,\frac{m}{s}[/tex]

By (4):

[tex]s_{2} = \left(8\,\frac{m}{s} \right)\cdot (10\,s) + \frac{1}{2}\cdot \left(0.4\,\frac{m}{s^{2}} \right)\cdot (10\,s)^{2}[/tex]

[tex]s_{2} = 100\,m[/tex]

By (1):

[tex]s = 140\,m[/tex]

The final displacement of the car is 140 meters.

The options missing are;

A. Make only a few changes to the manipulated variable.

B. Identify any biases about the answer to the scientific question.

C. Include as many details as possible when writing the conclusion.

D. Share her ideas through peer review.

Answer:

B. Identify any biases about the answer to the scientific question.

Explanation:

Since the question is asking what can be done to improve the quality of the results, it means what can the scientist do to make sure that the result answers the question properly and has little or no biases.

Thus, looking at the options, the only one that comes close to actually improving on the quality of the results before finalizing is option B where the scientist is to identify any biases.

Answer:

[tex] \implies U = \dfrac{kq}{r} [/tex]

[tex]\implies U = \dfrac{9 \times {10}^{9} \times 1}{1} [/tex]

[tex]\implies U = 9 \times {10}^{9} \: J[/tex]

We have that absolute potential difference ,due of point charge of 1C at a distance of 1 m is given by

[tex]\rho=9x10 ^{10}J[/tex]

From the question we are told that

point charge of 1C at a distance of 1 m

Generally the equation for the Electrostatic potential energy  is mathematically given as

[tex]\rho=\frac{kq_1q_2}{r}[/tex]

Where k is a constant

[tex]k=9*10^9Nm^2/c^2[/tex]

Therefore

[tex]\rho=\frac{(9*10^9)1*10^(-6)*1*10^{-6}}{1}[/tex]

[tex]\rho=9x10 ^{10}J[/tex]

For more information on this visit

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Answer:

A stellar core greater than 3 solar masses

Explanation:

The process of the evolution of a star in which the star changes form with time, includes phases of evolution which are determined by the mass of the core of the star, which involves a process of conversion of elements and the contraction of the star

Where the mass of the core of the star is more than the mass of three Suns, (3 solar masses) the contraction of the star continues, due to the gravitational force being larger than the pressure exerted by neutron, such that the star collapses to a black hole

Therefore, the search for black holes involves searching for a stellar core greater than 3 solar masses.