3^2 dived (-4+5)^2-11+2^3 hope you can answer

Answer:

what can i help u with

Step-by-step explanation:

I really can't help u with that sorry i am bad at math

5 by 3

3rd one

there we have to find hypotenuse.

Answer:

+- 5/3

Step-by-step explanation:

When we construct a right triangle with legs with length 3 and 4. The hypoteneuse must 5. Since tan(x) = opp/adj = 4/3 and sec(x) = hyp/adj,

We get the answer to be 5/3. Now there is a +- there because if we use the unit circle, if we take the point (-3, -4), we get tan(x) = (-4/-3) = 4/3. However, the hypoteneuse for sec(x) is always positive so sec(x) = 5/-3 = -5/3.

That is why there are two solutions, one with the terminal arm in Q3 and one in Q1. But that's the explanation using the unit circle.

Answer:

here I'm confused that whether the selling price is Rs.9,200 or Rs.9.200

any ways you can take the help of below procedure

Step-by-step explanation:

here,

let marked price be X

discount(d)=20%

VAT=15%

SP with VAT= 9200

now,

SP without VAT= SP - VAT of SP

= 9200-15/100 ×9200

= 9200- 1380

=Rs. 1380

again,

SP= MP - D of MP

or,7820= x- 20/100 × x

or, 7820× 100 = 100x- 20x

or,782000=80x

or, 782000/80=X

or, X= 9775.

hence MP is Rs 9775

Answer:

5.2561

step by step explanation:

using BODMAS, multiplication comes before addition.

Therefore,

[tex] \sqrt{1.13 + (2.84 \times 9.33)} [/tex]

[tex] \sqrt{1.13 + 26.4971} [/tex]

[tex] \sqrt{27.6272} [/tex]

Therefore the answer is

5.2561

Answer:

x = 9

Step-by-step explanation:

When doing these types of problems, the main goal is to get the variable by itself. Its kind of hard to explain with words so I will just use numbers.

15x + 14 = 149

(Subtract 14 on both sides. Remember, when you do something (Like subtracting, adding, etc.) on one side you have to do it to the other.)

15x + 14 = 149

       -14 =  -14

---------------------------

15x = 135

(Divide 15 on both sides. Since we need to use inverse operation to cancel the 15 out, we would divide 15 on both sides.)

15x/15 = 135/15

x = 9

Hope this helps :)

Answer:

Step-by-step explanation:

[tex]\sf 15x + 14 = 149[/tex]

[tex]\sf 15x+14-14=149-14[/tex]

[tex]\sf 15x=135[/tex]

[tex]\sf \cfrac{15x}{15}=\cfrac{135}{15}[/tex]

[tex]\sf x=9[/tex]

Answer:

Not enough infomation, you need to provide #12

Step-by-step explanation:

Answer: x = 2 and y = -4

x + 2y = -6

x = -6-2y

Putting this in value of x in

6x + 2y = 4

6(-6-2y) + 2y = 4

-36-12y+2y = 4

-10y = 4+36

y = 40/(-10)

y = -4

Now putting this value of y in

x + 2y = -6

x + 2(-4) = -6

x -8 = -6

x = -6+8

x = 2

Therefore x = 2 and y = -4

If we put these values we can check this

x + 2y = -6

2 + 2(-4) = -6

2 -8 = -6

-6 = -6

please click thanks and mark brainliest if you like :)

Answer:

line of symmetry is : x=2

Step-by-step explanation:

Answer:

Thus, the required line of symmetry is x = 2.

Step-by-step explanation:

Answer:

A) 3

B)60

C)4

Step-by-step explanation:

y = kx

36 = 12k

A)k=3

~~~~~~~~~~

b) 60

12*5

c) 4  

12/3

Area of a square is side^2

Diagonal of a square is sqrt(2) x side

Using this rewrite the area formula as :

1/2 x diagonal^2

Area = 1/2 x 40^2 = 800

Area = 800 m^2

Answer = b) 800m^2

Hi there!

[tex]\large\boxed{102^o}[/tex]

Using the triangle exterior angle theorem, we know that:

∠4 = the other two angles of the triangle combined (both are given)

Thus:

∠4 = 51 + 51 = 102°

Angle 4 is an outside angle.

An outside angle of a triangle is equal to the sum of the two opposite inside angles.

The two opposite inside angles to angle 4 are shown as 51 and 51

Angle 4 = 51 + 51

Angle 4 = 102 degrees.

Answer:

Step-by-step explanation:

6. Yes: these two angles are opposite 2 equal line.

7. No: We don't know that AC bisects <JAD

8. No: We don't know that JCA or DCA are right angles.

9. Yes. Both angles have AC in common. JD is a straight line which has 180 degrees. AC intersects a JD and creates 2 angles. We know their total but not their equality.

10. Yes. They are given as equal.

Not everything you see is true just because it looks that way.

Answer:

Let's call the length of the field "l", and the width of the field "w".

If the area of the field is 72 square meters, then we have:

l x w = 72

And if the length is 6 meters longer than the width, we have:

l = w+6

So looking at the first equation (l x w = 72), we can substitute the l for a w+6.

And we obtain:

(w+6) x (w) = 72

Which simplifies to w^2 + 6w = 72.

This quadratic equation is pretty easy to solve, you just need to factor it.

w^2 + 6w - 72 = 0

(w-6)(w+12)

This leaves the roots of the  quadratic equation to be 6 and -12, but in this case, a width of -12 wouldn't make sense.

So, the width of the rectangular field is 6, and the length of the field is 12.

Let me know if this helps!

Answer:

we assume one side is x and other side must be x+6 and when we multiple it together we can find x²+6x =72

Step-by-step explanation:

one side is 6 and. other is 12 so the lenght= 12 the width=6

Answer:

360cm³

Step-by-step explanation:

Volume of a triangular prism = Base area * Height of prism

Height of prism = 15cm

Base area = 1/2 * 6 * 8

Base area = 24cm²

Volume of the prism = 15 * 24

Volume of the prism = 360cm³

​

The derivative of a function f(x) is defined as

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h[/tex]

For f(x) = 3x ² + 4, we have

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x+h)^2+4) - (3x^2+4)}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{(3(x^2+2xh+h^2) - 3x^2}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}\frac{6xh+3h^2}h[/tex]

[tex]f'(x)=\displaystyle\lim_{h\to0}(6x+3h) = \boxed{6x}[/tex]

Answer:

37

Step-by-step explanation:

360 -(110+110+66) = 74

74/2 = 37

Answer: Choice A (both are smiley faces)

This is because the reflection doesn't flip the faces upside down or anything (instead it does a left-right swap in a way). This is why both faces are smiley faces.

Answer:

-2/3

Step-by-step explanation:

The slope is -2/3 because the slope formula, y2-y1/x2-x1

[tex]\huge\text{Hey there!}[/tex]

[tex]\boxed{\huge\boxed{\mathsf{Formula: m = \dfrac{y_2- y_1}{x_2- x_1}}}}[/tex]

[tex]\boxed{\huge\boxed{\mathsf{m = \dfrac{14 -10}{-18 - (-12)}}}}\\\\\\\huge\textsf{14 - 10 = \bf \boxed{\bf 4}}\\\\\\\huge\textsf{-18 - (-12)}\\\huge\textsf{= -18 + 12}\\\huge\textsf{= \bf -6}\\\\\boxed{\huge\boxed{\mathsf{m = \dfrac{4}{-6}}}}[/tex]

[tex]\boxed{\huge{\boxed{\mathsf{m = \dfrac{4\div2}{-6\div2}}}}}\\\\\huge\boxed{\mathsf{4\div2 = \bf 2}}\\\huge\boxed{\mathsf{-6\div2 = \bf -3}}\\\\\\\boxed{\boxed{\huge\boxed{\mathsf{\star m = \bf \dfrac{2}{-3}\star}}}}[/tex]

[tex]\boxed{\boxed{\huge \boxed{\mathsf{Answer: }\frak{\dfrac{2}{-3}}}}}\huge\checkmark[/tex]

[tex]\huge\boxed{\frak{Good\ luck\ on\ your\ assignment\ \& \ enjoy \your \ day!}}[/tex]

~[tex]\rm{Amphitrite1040:)}[/tex]

Xochitl needs to pay $8.50 to buy 3 pounds of cherries.

The expression for the cost to buy p pounds of cherries would be

$(4p - 3.50)

An equation is written in the form of variables and constants separated by the operation of multiplication and division,

An equation states that terms in different forms on both sides of the equality sign are equal.

Multiplication and division do not separate the terms of an equation.

Given, The price per pound of the cherries is $4 per pound and she has a coupon for $3.50 off the final amount.

Therefore, The cost of 3 pounds of cherries before the discount would be,

= $(3×4).

= $12.

And after the discount, it would be $(12 - 3.50).

= $8.50.

An expression for the cost to buy p pounds of cherries would be,

= $(4p - 3.50)

learn more about equations here :

https://brainly.com/question/29657992

#SPJ2

Answer:

5

Step-by-step explanation:

8-1-(18-2)÷8

PEMDAS says parentheses first

8-1-16÷8

Then divide

8-1-2

Then subtract from left to right

7-2

5

Answer:

Step-by-step explanation:

If the account grows steadily, this is a linear representation, where the constant, steady growth translates to the slope of a line.

I assume you're supposed to find the limit as n approaches infinity, not x.

You have

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5.3^n+1}{2.4^n+2} = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-\left(\dfrac{5.3}{5.3}\right)^n+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}} \\\\ = \lim_{n\to\infty}\frac{\left(\dfrac4{5.3}\right)^n-1+\dfrac1{5.3^n}}{\left(\dfrac{2.4}{5.3}\right)^n+\dfrac2{5.3^n}}[/tex]

For |x| < 1, we have lim |x|ⁿ = 0 as n goes to infinity. Then each exponential term converges to 0, which leaves us with -1/0. This means the limit is negative infinity.

On the other hand, perhaps you meant to write

[tex]\displaystyle \lim_{n\to\infty}\frac{4^n-5\times3^n+1}{2\times4^n+2}[/tex]

The same algebraic manipulation gives us

[tex]\displaystyle\lim_{n\to\infty}\frac{\left(\dfrac44\right)^n-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2\left(\dfrac44\right)^n+\dfrac2{4^n}} = \lim_{n\to\infty}\frac{1-5\left(\dfrac34\right)^n+\dfrac1{4^n}}{2+\dfrac2{4^n}}[/tex]

Again the exponential terms converge to 0, but this time we're left with the limit 1/2.

Answer:

[tex]A=2044[/tex]

Step-by-step explanation:

Note that [tex]x\in\mathbb{W}[/tex] denotes that [tex]x[/tex] is a whole number.

By definition, consecutive numbers follow each other when we count up (e.g. 1, 2, 3).

Let's consider our conditions:

Since B is a multiple of 5, the ones digit of B must be either 0 or 5. However, notice that the number before it, A, needs to be a multiple of 4. The ones digit of a number preceding a ones digit of 0 is 9. There are no multiples of 4 that have a ones digit of 9 and therefore the ones digit of B must be 5.

Because of this, we've identified that the ones digit of A, B, and C must be 4, 5, and 6 respectively.

We can continue making progress by trying to identify the smallest possible whole number greater than 2,000 with a units digit of 6 that is divisible by 6. Notice that:

[tex]2000=2\mod6[/tex]

Therefore, [tex]2000-2=1998[/tex] must be divisible by 6. To achieve a units digit of 6, we need to add a number with a units digit of 8 to 1,998 (since 8+8 has a units digit of 6).

The smallest multiple of 6 that has a units digit of 8 is 18. Check to see if this works:

[tex]C=1998+18=2016[/tex]

Following the conditions given in the problem, the following must be true:

[tex]A\in \mathbb{W},\\B\in \mathbb{W},\\C\in \mathbb{W},\\A+1=B=C-1,\\A=0\mod 4,\\B=0\mod 5,\\C=0\mod 6,[/tex]

For [tex]C=2016[/tex], we have [tex]B=2015[/tex] and [tex]A=2014[/tex]:

[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2014\neq 0\mod 6, \times\\B=2015=0\mod 5,\checkmark\\C=2016=0\mod 6\checkmark\\[/tex]

Not all conditions are met, hence this does not work. The next multiple of 6 that has a units digit of 8 is 48. Adding 48 to 1,998, we get [tex]C=1998+48=2046[/tex].

For [tex]C=2046[/tex], we have [tex]B=2045[/tex] and [tex]A=2044[/tex]. Checking to see if this works:

[tex]A\in \mathbb{W},\checkmark\\B\in \mathbb{W},\checkmark\\C\in \mathbb{W},\checkmark\\A+1=B=C-1,\checkmark\\A=2044=0\mod 4,\checkmark\\B=2045=0\mod 5,\checkmark\\C=2046=0\mod 6\checkmark[/tex]

All conditions are met and therefore our answer is [tex]\boxed{2,044}[/tex]

Answer:

a + b = 5.30

a + b = 7

No

Step-by-step explanation:

Expressing the information as system of linear equation :

Let apples = a, oranges = b

If $5.30 is charged for one apple and one orange, then we have ;

a + b = 5.30 - - - (1)

If $14 is charged for 2 apples and 2 oranges, then we have ;

2a + 2b = 14 - - - - (2)

a + b = 7

Since both equations gives varying combined cost for equal amount of the fruit, then a unique cost cannot be obtained for each fruit from the systems of equation using simultaneous equation process.

From (1)

a = 5.30 - b

Put a = 5.30 - b in (2)

2(5.30 - b) + 2b = 14

10.6 - 2b + 2b = 14

10.6 = 14 - - - - - (variables cancels out).

Answer:No the System has no solution

Step-by-step explanation:

a right angle can have at least 2

Answer:

x=- 31/3

Step-by-step explanation:

distribute 5(2x+3)-4x=-4+3x(x-4)

10x+15-4x=-4+3(x-4)

combine like terms

distribute

Answer:

Step-by-step explanation:

Find the slope of the line

(x₁ , y₁) = (6 , 8)   & (x₂ , y₂) = (0 , 5)

[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{5-8}{0-6}\\\\=\frac{-3}{-6}\\\\=\frac{1}{2}[/tex]

m = 1/2  ;(x₁ , y₁) = (6 , 8)

y - y₁ = m(x - x₁)

[tex]y - 8 = \frac{1}{2}(x - 6)\\\\y - 8 =\frac{1}{2}x -\frac{1}{2}*6\\\\y - 8 =\frac{1}{2}x- 3\\\\y = \frac{1}{2}x - 3 + 8\\\\y = \frac{1}{2}x + 5[/tex]

Answer:

[tex] 3x + y = 2 [/tex]

Step-by-step explanation:

[tex] y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1) [/tex]

[tex] y - 5 = \dfrac{-7 - 5}{3 - (-1)}(x - (-1)) [/tex]

[tex] y - 5 = \dfrac{-12}{4}(x + 1) [/tex]

[tex] y - 5 = -3(x + 1) [/tex]

[tex] y - 5 = -3x - 3 [/tex]

[tex] 3x + y = 2 [/tex]