Please help me anyone please and thank you

Answer:

The probability that Aaron goes to the gym on exactly one of the two days is 0.74

Step-by-step explanation:

Let P(Aaron goes to the gym on exactly one of the two days) be the probability that Aaron goes to the gym on exactly one of the two days.

Then

P(Aaron goes to the gym on exactly one of the two days) =

P(Aaron goes to the gym on Saturday and doesn't go on Sunday) +

P(Aaron doesn't go to the gym on Saturday and goes on Sunday)

P(Aaron goes to the gym on Saturday and doesn't go on Sunday) =

P(the probability that Aaron goes to the gym on Saturday)×P(If Aaron goes to the gym on Saturday the probability that he does not go on Sunday)=

0.8×0.7=0.56

Thus, P(Aaron doesn't go to the gym on Saturday and goes on Sunday) = P(The probability that Aaron doesn't go to the gym on Saturday)×P(if Aaron does not go to the gym on Saturday the probability he goes on Sunday)

=0.2×0.9=0.18

Then

P(Aaron goes to the gym on exactly one of the two days) =0.56 + 0.18 =0.74

Answer:

5

Step-by-step explanation:

because line AB divided the triangle into two equal halves

Answer:

42.78⁹, 137.22⁹.

Step-by-step explanation:

sine Ф=0.6792

Angle Ф in the first quadrant = 42.78 degrees.

The sine is also positive in the second quadrant so the second solutio is

180 - 42.78

= 137.33 degres.

Answer:

5, 12, 19, 26, 33

Step-by-step explanation:

Using the recursive rule and a₁ = 5 , then

a₂ = a₁ + 7 = 5 + 7 = 12

a₃ = a₂ + 7 = 12 + 7 = 19

a₄ = a₃ + 7 = 19 + 7 = 26

a₅ = a₄ + 7 = 26 + 7 = 33

The first 5 terms are 5, 12, 19, 26, 33

Answer:

[tex]{ \tt{ {x}^{2} - \frac{1}{ {x}^{2} } }} \\ = { \tt{ {(2 + \sqrt{5} )}^{2} - \frac{1}{ {(2 + \sqrt{5}) }^{2} } }} \\ = { \tt{ \frac{(2 + \sqrt{5} ) {}^{4} - 1}{ {(2 + \sqrt{5} )}^{2} } }} \\ = { \tt{ \frac{(9 + 4 \sqrt{5}) {}^{2} }{ {(9 + 4\sqrt{5}) }}}} \\ = { \tt{9 + 4 \sqrt{5} }}[/tex]

Answer:

[tex]8\sqrt{5}[/tex]

Step-by-step explanation:

[tex]x = 2 + \sqrt{5}\\\\ x^{2} = (2+ \sqrt{5})^{2} \\\\ \ \ \ \ = 2^{2}+2* \sqrt{5}*2+( \sqrt{5})^{2}\\\\[/tex]

 [tex]= 4 + 4 \sqrt{5}+5\\\\= 9+4 \sqrt{5}[/tex]

[tex]\frac{1}{x^{2}}=\frac{1}{9+4\sqrt{5}}\\\\=\frac{1*(9-4\sqrt{5}}{(9+4\sqrt{5})(9-4\sqrt{5})}\\\\=\frac{9-4\sqrt{5}}{9^{2}-(4\sqrt{5})^{2}}\\\\=\frac{9-4\sqrt{5}}{81-4^{2}(\sqrt{5})^{2}}\\\\=\frac{9-4\sqrt{5}}{81-16*5}\\\\=\frac{9-4\sqrt{5}}{81-80}\\\\=\frac{9-4\sqrt{5}}{1}\\\\=9-4\sqrt{5}[/tex]

[tex]x^{2}-\frac{1}{x^{2}}= 9 + 4\sqrt{5} -(9 - 4\sqrt{5})\\\\[/tex]

            [tex]= 9 + 4\sqrt{5} - 9 + 4\sqrt{5}\\\\= 9 - 9 + 4\sqrt{5} + 4\sqrt{5}\\\\= 8\sqrt{5}[/tex]

We have

(a + bx) / (a - bx) = (b + cx) / (b - cx)

==>   (a + bx) (b - cx) = (a - bx) (b + cx)

==>   ab + (b ² - ac) x - bcx ² = ab + (ac - b ²) x - bcx ²

==>   (b ² - ac) x = (ac - b ²) x

==>   b ² - ac = ac - b ²

==>   2b ² = 2ac

==>   b ² = ac … … … [1]

Similarly, you would find

(a + bx) / (a - bx) = (c + dx) / (c - dx)

==>   ad = bc … … … [2]

and

(b + cx) / (b - cx) = (c + dx) / (c - dx)

==>   c ² = bd … … … [3]

Now:

c ² = bd   ==>   b = c ² / d

b ² = ac   ==>   c = b ² / a

ad = bc   ==>   d = bc / a

and we find

d / c = (bc / a) / (b ² / a) = c / b

and

c / b = (b ² / a) / (c ² / d) = (b ² d) / (a c ²) = b / a

which is to say, the ratio between d and c is equal to the ratio between c and b, and also equal to the ratio between b and a. Therefore (a, b, c, d) are in a geometric progression.

Given:

The ratio of 45-45-90 triangle is [tex]x:x:x\sqrt{2}[/tex].

The hypotenuse of the given isosceles right triangle is [tex]7\sqrt{2}[/tex].

To find:

The lengths of the other two sides of the given isosceles right triangle.

Solution:

Let [tex]l[/tex] be the lengths of the other two sides of the given isosceles right triangle.

From the given information if is clear that he ratio of equal side and hypotenuse is [tex]x:x\sqrt{2}[/tex]. So,

[tex]\dfrac{x}{x\sqrt{2}}=\dfrac{l}{7\sqrt{2}}[/tex]

[tex]\dfrac{1}{\sqrt{2}}=\dfrac{l}{7\sqrt{2}}[/tex]

[tex]\dfrac{7\sqrt{2}}{\sqrt{2}}=l[/tex]

[tex]7=l[/tex]

Therefore, the lengths of the other two sides of the given isosceles right triangle are 7 units.

Answer:

C: 2 × 10⁴

Step-by-step explanation:

We are told that the average net primary production in tropical rain forests each year is 8,900 kilocalories per square meter.

Thus;

P_net,average = 8900 Kcal/m²

We are also told that net primary production of a selected portion of a tropical rain forest in a given year is 1.8 × 10^(8) kilocalories.

Thus;

P_net = 1.8 × 10^(8) Kcal

To get the average, the formula is;

P_net,average = P_net/Area

Thus;

Area = P_net/P_net,average

Plugging in the relevant values;

Area = (1.8 × 10^(8))/8900

Area ≈ 2 × 10⁴ m²

Answer:

29

Step-by-step explanation:

all in all it is 180 so 61 + m (which is 90 because it is a right angle)=151

then 180-151=29

Answer:

what is that? I can't understand it.

Answer:

divide by 2

Step-by-step explanation:

to find x you must divide 8 by 2.

Answer:

you divide 8 by 2

Step-by-step explanation:

To isolate the variable, x you need to divide by 2 on both sides so it cancels out the 2 on 2x and will divide 8 by 2=4

Answer:

(-2,-2)

Step-by-step explanation:

x^2 + y^2 = 9

A circle has an equation of the form

(x-h)^2 + (y-k)^2 = r^2

where the center is at ( h,k) and the radius is r

The circle is centered at (0,0) and has a radius 3

The only point entirely within the circle must have points less than 3

(-2,-2)

Answer:

1/4

Step-by-step explanation:

a^2

Let a= 1/2

(1/2)^2

(1/4)

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{a^2}\\\\\mathsf{= \ (\dfrac{1}{2})^2}\\\\\mathsf{= \ \dfrac{1}{2}\times\dfrac{1}{2}}\\\\\mathsf{= \ \dfrac{1\times1}{2\times2}}\\\\\mathsf{= \ \bf \dfrac{1}{4}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Therefore, the ANSWER is: }\boxed{\mathsf{\bf \dfrac{1}{4}}}}}\huge\checkmark[/tex]

[tex]\huge\textsf{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

1 = 35p

6 = 35p×6

= 240p

Therefore, 6 bagels cost 240 p

Answer:

[tex]6(3f-15)=90[/tex]

[tex]3f=90/6+15=30[/tex]

[tex]f=10[/tex]

---------------------------

Hope it helps...

Have a great day!!

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{6(3f - 15) = 90^\circ}\\\\\huge\text{DISTRIBUTE}\\\\\mathsf{6(3f) + 6(-15) = 90^\circ}\\\\\mathsf{18f - 90 = 90^\circ}[/tex]

[tex]\text{NEW EQUATION: }\mathsf{18f - 90 = 90}[/tex]

[tex]\huge\text{ADD 90 to BOTH SIDES}[/tex]

[tex]\mathsf{18f - 90 + 90 = 90 + 90}[/tex]

[tex]\textsf{CANCEL out: -90 + 90 because that gives the number of 0}[/tex]

[tex]\textsf{KEEP: 90 + 90 because it helps solve for the f-value}[/tex]

[tex]\mathsf{90 + 90 = \bf 180}[/tex]

[tex]\huge\text{NEW EQUATION:\textsf{ 18f = 180}}[/tex]

[tex]\huge\text{DIVIDE 18 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{18f}{18}=\dfrac{180}{18}}[/tex]

[tex]\mathsf{CANCEL \ out: \dfrac{18}{18}\ because \ that \ gives \ the \ number \ of\ 1}[/tex]

[tex]\mathsf{KEEP: \dfrac{180}{18} \ because \ that \ gives \ the\ f-value \ result}[/tex]

[tex]\mathsf{f = \dfrac{180}{18}}[/tex]

[tex]\huge\text{SOLVE ABOVE \& YOU HAVE THE RESULT}[/tex][tex]\huge\text{OF THE F-VALUE}[/tex]

[tex]\mathsf{\dfrac{180}{18}}[/tex]

[tex]\mathsf{= \bf 18}[/tex]

[tex]\boxed{\boxed{\huge\textsf{Therefore, your ANSWER is: \bf f = 10}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

- 22.5

Step-by-step explanation:

Substitute x = 3 into f(x) and x = 16 into h(x) , then

[tex]\frac{1}{2}[/tex] g(3) - h(16)

= [tex]\frac{1}{2}[/tex] × - 3(3)² - (2[tex]\sqrt{16}[/tex] + 1)

= [tex]\frac{1}{2}[/tex] × - 3(9) - (2(4) + 1)

= [tex]\frac{1}{2}[/tex] × - 27 - (8 + 1)

= - 13.5 - 9

= - 22.5

Answer:

p = 1

Step-by-step explanation:

7 = 8 - p

7 + p = 8

p = 8-7

p = 1

Answered by Gauthmath

For sinø = cosø, ø = 45°. Because it is right, it is also a right, isosceles  triangle

Answer:

Lines parallel to this line will have a slope of -1

Step-by-step explanation:

y = -x + 7

This line is in slope intercept form

y = mx+b where m is the slope

The slope is -1

Parallel lines have the same slope

Lines parallel to this line will have a slope of -1

Answer:

-1

Step-by-step explanation:

Parallel lines have the same slope

The equation y = -x + 7 has a slope of -1 meaning that a line parallel to it would also have a slope of -1

Answer:

0

Step-by-step explanation:

To calculate the slope or gradient we use this formula:

Slope = y2-y1/x2-x1

(-3,2) = (x1, y1)

(4,2) =  (x2, y2)

Slope = 2-2/4-(-3) = 0

Answer from Gauthmath

Answer:

[tex]we \: know \: that \: slope = \frac{y2 - y1}{x2 - x1} \\ = \frac{2 - 2}{4 - - 3} \\ = \frac{0}{7} = 0 \\ slope \: = 0 \\ thank \: you[/tex]

Answer:

The top answer is correct

Step-by-step explanation:

Vertical angles are formed when two lines meet each other at a point and they are always equal to each other. Their angles are also equal. In this problem number two has angles that do not match and number three also has different angles. Finally number four also has different angles and is not equal to each other. Leaving number one (the top answer) which looks to have the same angle, and is equal to each other.

Answer:

10 digress when converted to nearest digree

Answer:

a =2 5

b =50

Step-by-step explanation:

The value of x for the given equation [tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2 will be 2 so option (B) must be correct.

The exponent indicates the power to which a base number is raised to produce a given number called a logarithm.

In another word, a logarithm is a different way to denote any number.

Given the equation

[tex]log_{8}[/tex](16) + 2[tex]log_{8}[/tex](x) = 2

We know that,

xlogb = log[tex]b^{x}[/tex]

So,

2[tex]log_{8}[/tex](x) = logx²

For the same base

logA + logB = log(AB)

So,

[tex]log_{8}[/tex](16) + [tex]log_{8}[/tex](x)² = 2

[tex]log_{8}[/tex](16x²) = 2

We know that

[tex]log_{a}[/tex](b) = c ⇒ b = [tex]a^{c}[/tex]

so,

[tex]log_{8}[/tex](16x²) = 2 ⇒ 8² = 16x²

x = 2 hence x = 2 will be correct answer.

For more about logarithm

https://brainly.com/question/20785664

#SPJ2

Answer:

chemical

Step-by-step explanation:

Answer:

[tex]{ \tt{ \sqrt[3]{8} {}^{ \frac{1}{4} x} }} \\ = { \tt{ {8}^{( \frac{1}{4}x) \frac{1}{3} } }} \\ = { \tt{ {8}^{ \frac{1}{12} x} }} \\ = { \tt{ \sqrt[12]{8} {}^{x} }}[/tex]

Answer:

[tex]\sqrt[12]{8^{x} }[/tex]

Step-by-step explanation:

[tex]\sqrt[12]{8^{x} }[/tex]

Answer:

-3/5

Step-by-step explanation:

Pythagorean formula :

x^2 + y^2 = r^2

(-8)^2 + (-6)^2 = r^2

64 + 36 = 100

r^2 = 100

r= 10

sin is the y coordinate over the radius :

-6/10

-3/5

Answer:

https://www.dasd.org › 4444PDF

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