3. Which equation shows why nuclear fission can produce a large amount of energy from very little mass?

E= 1/2 mv ^2
E= m^2
E= c^2
E= mc^2

Answers

Answer 1

Answer:

E=mc^2 is correct answer, last one

Explanation:

Hope it will help you


Related Questions

3. Pretend you're a farmer and you want to grow more crops. You have three different
fertilizers to choose from. Design an experiment that will help you choose which
fertilizer is best.
a. What variables would you need to control in your experiment?
b. Which variable would you change to test the fertilizers?
C. What is the measurable data point for this experiment?
d. What would the procedure be for your experiment?

Answers

Answer:

A

Explanation:

Sodium combines with water to produce sodium hydroxide and hydrogen gas. Which word equation represents this violent reaction? O sodium hydroxide + water → Sodium + hydrogen O sodium + water → sodium hydroxide + hydrogen O sodium + hydrogen → sodium hydroxide + water O sodium + sodium hydroxide → Water + hydrogen​

Answers

The word equation that represents the violent reaction between sodium and water is as follows: sodium + watersodium hydroxide + hydrogen.

What is a chemical reaction?

A chemical reaction is the process, typically involving the breaking or making of interatomic bonds, in which one or more substances are changed into others.

According to this question, sodium (Na) and water (H2O) are involved in a chemical reaction to produce sodium hydroxide (NaOH) and hydrogen gas (H2).

Therefore, the word equation that represents the violent reaction between sodium and water is as follows: sodium + watersodium hydroxide + hydrogen

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A cup of coffee has 71 mL of coffee and 127 mL of water. What is the percent volume of the coffee solution?

Answers

Answer:

35.9%

Explanation:

The percent volume of the coffee solution can be calculated as follows:

% volume of coffee solution = volume of coffee/total volume of coffee solution × 100

According to this question, a cup of coffee has 71 mL of coffee and 127 mL of water. This means that, the total volume of coffee solution is;

71mL + 127mL = 198mL

% volume = 71/198 × 100

= 0.359 × 100

Percent volume of coffee solution = 35.9%

Given the reaction at equilibrium:
H2(g) + Cl2(g) → 2HCl(g) + heat
The equilibrium will shift to the right when there is an
increase in
A temperature
B pressure
C concentration of H2(g)
O concentration of HCl(g)

Answers

B IT IS B … thank me later.

An ionic substance is formed between a positively charged cation and a negatively charged anion. Ionic substances are generally formed from metal and nonmetal atoms with the metal atoms forming the cations and the nonmetal atoms forming the anions. Which of the following substances are ionic? Check all that apply. Check all that apply. AlCl3 MgI2 C2H5OH NH3

Answers

Answer:

Which of the following substances are ionic?

Check all that apply.

AlCl3

MgI2

C2H5OH

NH3

Explanation:

An ionic substance is formed between a positively charged cation and a negatively charged anion.

Ionic substances are generally formed from metal and nonmetal atoms with the metal atoms forming the cations and the nonmetal atoms forming the anions.

Among the given substances,

MgI2 is an ionic substance.

Since Mg is the metal atom. It forms a cation.

I is a  nonmetal atom. It forms anion.

Hence,

MgI2 is an ionic substance.

Though AlCl3 looks like an ionic substance it is a covalent compound.

This is due to the high polarizability of [tex]Al^3+[/tex] ion.

The remaining two compounds do not contain any metal atoms.

So, ethanol and NH3 are not ionic compounds.

Answer:

MgI2

The theoretical yield of NH3 is 945 grams. You conducted the experiment and only produced 598 grams.

Answers

Answer:

Given theoretical yield of NH3 is 945g.

The actual yield is 598g.

What is the %yield?

Explanation:

%yield of a chemical reaction can be calculated by using the formula:

[tex]%yield=\frac{actual yield}{theoretical yield} * 100[/tex][tex]\frac{actual yield}{theoretical yield} * 100[/tex]

Substitute the given values in this formula to get the %yield.

[tex]\frac{598g}{945g} * 100\\=63.3[/tex]

Hence, the %yield for the formation of ammonia is ---- 63.3.

The metal aluminum coils in an air conditioner conduct thermal energy from inside the house and release it outside the house. What can be said about the coils when they are accepting the heat inside the house?

Answers

Answer:

c

Explanation:

Answer:
B: They must be cooler than the air inside the house.

Explanation:

I got it right on edge!

what is the mass percentage for hydrogen

Answers

Answer:

The mass percent of hydrogen in hydrogen peroxide is 5.88

The mass percentage of hydrogen in water is 11.19 percent.

i need help answering this question on my homework, could anyone help?

Answers

The Hydrogen symbol is H,
but a hydrogen gas is H2
H2 is the answer

Un método de laboratorio para preparar O 2 (g) consiste en la descomposición de KCIO 3 (s): KCIO 3 (s)  KCI(s) + O 2 (g) a) ¿Cuántos moles de O 2 se producen cuando se descomponen 32,8 g de KCIO 3 ? b) ¿Cuántos gramos de KCIO 3 deben descomponerse para obtener 50 g de 02? c) ¿Cuántos gramos de KCI se forman al descomponerse KCIO 3 formándose 28,3 g de O2? 3. ¿Cuántos gramos de Ag 2 CO 3 deben haberse descompuesto si se obtuvieron 7511 g de Ag según la reacción: Ag 2 CO 3  Ag(s) + CO 2 (g) + O 2 (g)?

Answers

Answer:

2a. 0.401 moles de O2

b. 127.7g KClO3

c. 43.95g KCl

3. 9600g Ag2CO3 debieron haberse descompuesto

Explanation:

Basados en la reaccion:

2KCIO 3 (s) → 2KCI(s) + 3O 2

2 moles de KClO3 producen 3 moles de oxígeno:

a. 32.8g de KClO3 son:

Moles KClO3 -Masa molar: 122.55g/mol-

32.8g * (1mol / 122.55g) = 0.2676 moles KClO3

Moles O2:

0.2676 moles KClO3 * (3moles O2 / 2mol KClO3) =

0.401 moles de O2

b. 50g O2 son:

Moles O2 -Masa molar: 32g/mol-

50g O2 * (1mol/32g) = 1.5625 moles O2

Moles KClO3:

1.5625 moles O2 * (2mol KClO3 / 3mol O2) = 1.042 moles KClO3

Masa KClO3:

1.042 moles KClO3 * (122.55g/mol) =

127.7g KClO3

c. Las moles de O2 son:

28.3g O2 * (1mol / 32g) = 0.88 moles O2

Moles KCl:

0.88 moles O2 * (2mol KCl / 3mol O2) = 0.5896 moles KCl

Masa KCl -Masa molar: 74.55g/mol-

0.5896 moles KCl * (74,55g/mol) = 43.95g KCl

3. Basados en la reacción:

2Ag 2 CO 3 → 4Ag(s) + 2CO 2 (g) + O 2 (g)?

2 moles de Ag2CO3 reaccionan produciendo 4 moles de Ag. Las moles de Ag son:

Moles Ag -Masa molar: 107.8682g/mol-

7511g Ag * (1mol/107.8682g) = 69.63 moles Ag

Moles Ag2CO3:

69.63 moles Ag * (2moles Ag2CO3/4molesAg) = 34.82 moles Ag2CO3

Masa Ag2CO3-Masa molar: 275.7453g/mol-

34.82 moles Ag2CO3 * (275.7453g/mol) =

9600g Ag2CO3 debieron haberse descompuesto

Which of the following best summarizes what happens in a displacement reaction?
A
Two elements react to form a compound.
B
A compound breaks down into elements.
C
An element and a compound react to form a different element and compound.
D
An element and a compound react to form another compound.

Answers

Answer:

C

Explanation:

Here's an example of displacement reaction:

2 Al (s) + 3 CuSO4 (aq) -> 3 Cu (s) + Al2(SO4)3 (aq)

note that aluminium and copper are elements,

copper II sulphate and aluminium sulphate are compound

The statement that best describes displacement reaction is an element and a compound react to form a different element and compound. The correct option is C.

What is displacement reaction?

When a more reactionary element displaces, or continues to push out, a less reactive element from a compound containing the less reactive element, a displacement reaction occurs.

The less reactive element is now pure and uncombined following a displacement reaction.

A single-displacement reaction occurs when a more reactive element in a compound replaces a much less reactive element.

Metal displacement, hydrogen displacement, and halogen displacement are the three types of displacement reactions.

An element as well as a compound react to form a specific component and compound, according to the best description of displacement reaction.

Thus, the correct option is C.

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Fe2O3 (s) + CO (g) -> Fe(s) + CO2 (g) (unbalanced)
1.Calculate the number of grams of CO that can react with 0.150kg of Fe2O3
2. Calculate the number of grams of Fe and the number of grams of CO2 formed
when 0.150 kg of Fe2O3 reacts

Answers

Answer:

1. 78.9g of CO

2. 104.9g Fe and 124.0g CO2

Explanation:

Based on the balanced reaction:

Fe2O3 (s) + 3CO (g) -> 2Fe(s) + 3CO2 (g)

1 mole of Fe2O3 reacts with 3 moles of CO to produce 2 moles of Fe and 3 of CO2

1. The moles of 0.150kg = 150g of Fe2O3 -Molar mass: are:

150g * (1mol / 159.69g) = 0.9393 moles Fe2O3

Moles CO:

0.9393 moles Fe2O3 * (3mol CO / 1mol Fe2O3) = 2.818 moles CO

Mass CO -Molar mass: 28.01g/mol-:

2.818 moles CO * (28.01g/mol) = 78.9g of CO

2. The moles of Fe produced are:

0.9393 moles Fe2O3 * (2mol Fe / 1mol Fe2O3) = 1.8786 moles Fe

Mass Fe -Molar mass: 55.845g/mol-:

1.8786 moles Fe * (55.845g/mol) = 104.9g Fe

The moles of CO2 produced are:

0.9393 moles Fe2O3 * (3mol CO2 / 1mol Fe2O3) = 2.818moles CO2

Mass CO2 -Molar mass: 44.01g/mol-:

2.818moles CO2 * (44.01g/mol) = 124.0g CO2

What are the coefficients needed to balance this chemical reaction to show that matter is conserved?

Answers

The answer is B I had took that last year

Elvis eats a peanut butter sandwich for lunch. Peanut butter contains a lot of protein, and bread is mostly starch. Elvis plans to go for a run later this afternoon. He is breathing normally. What does he need from the food he ate and the air he breathes so that he can go on his run? How do Elvis' body systems work together to get the molecules he needs into his cells? How do his cells use these molecules to release energy for his body to run?

Answers

Answer:

hi

Explanation:

please help bbg'sssss

Answers

Answer:

Explanation:

from the way the trees look, i would say A: Wind from the sky, it seems B: Clouds and in the distance C:Precipitation(rain)

Dos moléculas de Clorato de Potasio en estado sólido, al aplicarle calor se descompone en dos moléculas de Cloruro de Potasio en estado sólido y tres moléculas diatómicas de Oxígeno en estado gaseoso ¿como se representan?

Answers

Answer:

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

Explanation:

Una ecuación de reacción química es una representación simbólica de lo que sucede en un recipiente de reacción.

Al escribir la ecuación de reacción química para una reacción particular, se utilizan los símbolos químicos de todas las especies involucradas.

Por la reacción. en el cual dos moléculas de Clorato de Potasio en estado sólido, al aplicar calor se descompone en dos moléculas de Cloruro de Potasio en estado sólido y tres moléculas diatómicas de Oxígeno en estado gaseoso, la ecuación de reacción se escribe así;

2KClO3 (s) -------> 2KCl (s) + 3O2 (g)

La regla para escribir ecuaciones de reacción química balanceada es que el número de átomos de cada elemento en el lado derecho de la ecuación de reacción debe ser el mismo que el número b de átomos del mismo elemento en el lado izquierdo de la ecuación de reacción.

Si realizamos un conteo de átomos simple en ambos lados de la ecuación de reacción, la regla se cumple

What is the number of Co2 in a 220 gram

Answers

I believe that the number for Co2 in 220 grams is 5

2HCl → H2 + Cl2
Is synthesis?

Answers

Answer:

It's decomposition

explanation:

PPE 15. What variables are you manipulating in this exercise? Identify a symbol to represent each variable.​

Answers

can you provide a picture ?

What happens to the electric force between two particles if the distance
between them is doubled?

Answers

Answer:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion become weaker, decreasing to one-fourth of the original value. ...The size of the force is proportional to the value of each charge.

WILL GIVE BRAINLIEST - A solution has a [H3O+] of 1 × 10−3 M. What is the [OH−] of the solution?
11 M
14 M
1 × 10−14 M
1 × 10−11 M

Answers

Answer:

The answer is 1 x 10 - 11 M.  :))

Write a balanced equation state the reaction type, and perform the requested stoichiometry: Carbon and hydrogen combine to form
methane. How many grams of carbon would be needed to react with 30.2 grams of hydrogen?

Answers

Answer:

C + 2H2 = CH4

Given 30.2g of H2

Find the Moles

Mole =Mass/Molar Mass

Molar Mass of H2 = 1x2 = 2g/mol

Mole = 30.2/2

= 15.1moles of Hydrogen gas.

Now from the balanced equation of Reaction above...

1mole of Carbon reacts completely with 2moles of Hydrogen gas.

"x" moles of carbon with react with 15.1moles of Hydrogen

x = 15.1/2

=7.55moles of carbon.

We now have moles of carbon.

To find mass

Mole =Mass/Molar Mass

Mass = Mole x Molar Mass

Molar mass of carbon = 12g/mol

Mass = 7.55 x 12

Mass = 90.6g of carbon is needed.

What are the two functional group present in the molecule

Answers

Answer:

carboxyl group (COOH) and amines

Explanation:

The two functional group present in the shown molecule are carboxylic acid group and amine group.

What are functional groups?

Functional group is defined as a substituent or group of toms or an atom which causes chemical reactions.Each functional group will react similarly regardless to the parent carbon chain to which it is attached.This helps in prediction of chemical reactions.

The reactivity of functional group can be enhanced by making modifications in the functional group .Atoms present in functional groups are linked to each other by means of covalent bonds.They are named along with organic compounds according to IUPAC nomenclature.

Functional group inter conversion is also possible by retro -synthesis.In some cases , functional groups can be charged molecules.

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Which sublevel contains valance electrons in an atom of magnesium (mg)?

A. 2s

B. 2p

C. 3s

D. 3p

Answers

The answer is B
The answer is B
The correct answer is B!!

Which of the following is not an amphoteric substance?
a) lead(II) oxide
b) aluminum hydroxide
C) iron(ill) oxide
d) zinc oxide

Answers

Sắt oxit

Explanation:

The correct formula for finding the relative velocity of an object is:
Vac= vah-vыс
Valc = ab + b c
Vad = ab + b c
b c = ab + b c

Answers

Answer:

va/c = v a/b + v b/c

Explanation:

This is the correct formula for relative velocity

A sample of oxygen gas has volume 150.0 mL, at 0.947 atm, what will be the volume of the gas at 750.12 mm of Hg if temperature remain constant.

Answers

Answer:

143.9 mL

Explanation:

Applying,

PV = P'V'................. Equation 1

Where P = Initial pressure, V = Initial Volume, P' = Final pressure, V' = Final volume.

Make V' The subject of equation 1

V' = PV/P'............. Equation 2

From the question,

Given: P = 0.947 atm, V = 150 mL, P' = 750.12 mm of Hg = (750.12/760) = 0.987 atm,

Substitute these values  into equation 2

V' = (0.947×150)/0.987

V' = 143.9 mL

Does a reaction involving an acid and a base have to take place in a water environment? Justify your answer.

Answers

Answer:

Yes, because the water solvent is better

Explanation:

Hope this helps

1. Ecosystems are composed of biotic and abiotic factors. Which of the following
represent only an abiotic factor in an ecosystem that could have an effect on
the ecosystem?
a. rivers with more dams
b. wood being taken for manufacturing
c. waste not being used by fungi
d. decomposers only taking nutrients from plants

Answers

Answer:

wood being taken for manufacturing



What is the volume of a 0.25 M MgCl2 solution that contains 0.75 moles of MgCl2?

Answers

Answer:

The volume of the solution is 3 L.

Explanation:

Molarity is a measure of the concentration of that substance that indicates the number of moles per unit volume. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution.

[tex]Molarity=\frac{number of moles of solute}{solution}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}=M[/tex]

In this case:

Molarity= 0.25 Mnumber of moles of solute= 0.75 molesvolume= ?

Replacing in the definition of molarity:

[tex]0.25 M=\frac{0.75 moles}{volume}[/tex]

volume*0.25 M= 0.75 moles

[tex]volume=\frac{0.75 moles}{0.25 M}[/tex]

volume= 3 L

The volume of the solution is 3 L.

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explsin that arts and craft make life beautiful and elegent and help to build a beautiful. pls answer correctly A sample of oxygen gas has volume 150.0 mL, at 0.947 atm, what will be the volume of the gas at 750.12 mm of Hg if temperature remain constant. The reporting of net cash provided or used by operating activities that lists the major items of operating cash receipts, such as receipts from customers, and subtracts the major items of operating cash disbursements, such as cash paid for merchandise, is referred to as the: Choose all options that apply.Which of the following can result from uncontrolled hypertension?a) Peripheral vascular diseaseb) Chronic lung diseasec) Colorectal cancerd) Heart attacke) Stroke The publication of Unsafe at Any Speed resulted inthe widespread use of which feature on automobiles?A tinted glassB power steering seat beltsD antilock brakes Find the area of this circle. 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What price did C pay Enunciado del ejercicio n 1Se lanza un cuerpo verticalmente hacia abajo con una velocidad inicial de 7 m/s.a) Cul ser su velocidad luego de haber descendido 3 s?b) Qu distancia habr descendido en esos 3 s?c) Cul ser su velocidad despus de haber descendido 14 m?d) Si el cuerpo se lanz desde una altura de 200 m, en cunto tiempo alcanzar el suelo?e) Con qu velocidad lo har?Usar g = 10 m/sDesarrolloDatos:v0 = 7 m/st = 3 sy = 200 mh = 14 mFrmulas:(1) vf = v0 + gt(2) y = v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 2Se lanza un cuerpo verticalmente hacia arriba con una velocidad inicial de 100 m/s, luego de 4 s de efectuado el lanzamiento su velocidad es de 60 m/s.a) Cul es la altura mxima alcanzada?b) En qu tiempo recorre el mvil esa distancia?c) Cunto tarda en volver al punto de partida desde que se lo lanzo?d) Cunto tarda en alcanzar alturas de 300 m y 600 m?Usar g = 10 m/sDesarrolloDatos:v0 = 100 m/svf = 60 m/st = 4 sy1 = 300 my2 = 600 mFrmulas:(1) vf = v0 + gt(2) y = v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 3Un observador situado a 40 m de altura ve pasar un cuerpo hacia arriba con una cierta velocidad y al cabo de 10 s lo ve pasar hacia abajo, con una velocidad igual en mdulo pero de distinto sentido.a) Cul fue la velocidad inicial del mvil?b) Cul fue la altura mxima alcanzada?Usar g = 10 m/sDesarrolloDatos:t = 10 sy = 40 mFrmulas:(1) vf = v0 + gt(2) y = y0 + v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 4Desde un 5 piso de un edificio se arroja una piedra verticalmente hacia arriba con una velocidad de 90 km/h, cunto tardar en llegar a la altura mxima?Usar g = 10 m/sDesarrolloDatos:v0 = 90 km/hv0 = 25 m/sFrmulas:(1) vf = v0 + gt(2) y = v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 5Un auto choca a 60 km/h contra una pared slida, desde qu altura habra que dejarlo caer para producir el mismo efecto?Usar g = 10 m/sDesarrolloDatos:vf = 60 km/hvf = 16,67 m/sv0 = 0 m/sFrmulas:(1) vf = v0 + gt(2) y = v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 6Se lanza una pelota hacia arriba y se recoge a los 2 s, calcular:a) Con qu velocidad fue lanzada?b) Qu altura alcanz?Usar g = 10 m/sDesarrolloDatos:t = 2 sFrmulas:(1) vf = v0 + gt(2) y = v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 7Se lanza una pelota de tenis hacia abajo desde una torre con una velocidad de 5 m/s.a) Qu velocidad tendr la pelota al cabo de 7 s?b) Qu espacio habr recorrido en ese tiempo?Usar g = 10 m/sDesarrolloDatos:v0 = 5 m/st = 7 sFrmulas:(1) vf = v0 + gt(2) y = v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 8Se lanza un cuerpo verticalmente hacia arriba con una velocidad de 60 km/h, se desea saber la altura mxima alcanzada, la velocidad que posee al cabo de 4 s y 30 s, la altura alcanzada a los 8 s, el tiempo total que se encuentra en el aire.DesarrolloDatos:v0 = 60 km/h = (60 km/h)(1.000 m/km)(1 h/3.600 s) = 16,67 m/st1 = 4 st2 = 30 st3 = 8 sUsar g = 10 m/sFrmulas:(1) vf = v0 + gt(2) y = v0t + gt(3) vf - v0 = 2ghEnunciado del ejercicio n 9Se dispara verticalmente hacia arriba un objeto desde una altura de 60 m y se observa que emplea 10 s en llegar al suelo. 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